The distance from the centroid of a triangle to its vertices are 16cm, 17cm, and 18cm. What is the length of the shortest median

Answer:

0.44

Step-by-step explanation:

The total numbers drawn = 300

Out those 146 are odd and 154 are even.

The number 8 was drawn = 22 times

So, the number of times an even number other than 8 = 154 -22 = 132

The experimental probability = The number of favorable outcomes ÷ The number of possible outcomes.

The experimental probability of an even number other than 8 being generated = [tex]\frac{132}{300}[/tex]

Simplify the above fraction to decimal, we get

= 0.44

Therefore, the answer is 0.44

Answer:

  y(x) = e^(-2x +3)

Step-by-step explanation:

The graphed line has a "y-intercept" of 3 and a slope of -2, so its equation is ...

  ln(y) = -2x +3

Taking antilogs, we get ...

  y(x) = e^(-2x +3)

Answer:

b) 0.2464

c) 0.0580

d) 0.2952

Step-by-step explanation:

Probability of those that purchased regular gas = 88% = 0.88

2% purchased mid grade gas

10% purchased premium gad

Given that a driver bought regular gas, 28% paid with credit card

Given that a driver bought mid grade gas, 34% paid with credit card

Given that a driver bought premium gas, 42% paid with credit card

Let R represent drivers that bought regular gas

Let M represent drivers that bought mid grade gas

Let P represent drivers that bought premium gas

Let C represent credit card payment

Let NC represent non-credit card payment

Pr(R) = 88% = 0.88

Pr(M) = 2% = 0.02

Pr(P) = 10% = 0.10

Pr(C|R) = 28%= 0.28

Pr(C|M) = 34%= 0.34

Pr(C|P) = 42%= 0.42

Pr(NC|R) = 1 - 0.28= 0.72

Pr(NC|M) = 1 - 0.34 = 0.66

Pr(NC|P) = 1 - 0.42 = 0.58

Using multiplication rule

Pr(AnB) = Pr(A) * Pr(B|A) = Pr(B) * Pr(A|B)

Using conditional probability,

P(B|A) = Pr(AnB) / Pr(A)

Pr(CnR) = Pr(R) * Pr(C|R)

= 0.88*0.28

= 0.2464

Pr(CnM) = Pr(M) * Pr(C|M)

= 0.02*0.34

= 0.0068

Pr(CnP) = Pr(P) * Pr(C|P)

= 0.10*0.42

= 0.0420

b) the probability that an automobile driver filled with regular gasoline AND paid with a credit card =

Pr(CnR)

= 0.2464

c) the probability that an automobile driver filled with premium gasoline AND did NOT pay with a credit card = Pr(P n NC) = Pr(NC|P) * Pr(P)

= 0.58 * 0.10

= 0.0580

d) The probability of those that paid with credit card is given as

Pr(CnR) + Pr(CnM) + Pr(CnP)

= 0.2464 + 0.0068 + 0.042

= 0.2952

This problem involves calculating different probabilities pertaining to customers' selection of gas type and payment method. These probabilities are found by multiplying corresponding probabilities together for intersecting events, and adding different possibilities together for compound events.

The subject of this question is probability, used in Mathematics. Let's solve each part step-by-step:

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Answer:

4.95

Step-by-step explanation:

You take the 4.50 and multiply it by 1.10 and it equals 4.95. Also I did it and I got it right.

The total price of the pastry is $4.95.

price of the pastry = $4.50

sales tax = 10%

The sales tax on the pastry is 10% of the price of the pastry.

Tax on pastry = price of the pastry x percentage of sales tax

                       [tex]= \$4.50 \times 10\%\\= 4.5\times \dfrac{10}{100}\\= 4.50 \times 0.1\\= 0.45[/tex]          

therefore, the tax on the pastry will be $0.45

Total price of the pastry =  Price of the pastry + tax on the pastry

                                        =   $4.50 + $0.45

                                        =  $4.95

Hence, the total price of the pastry is $4.95.

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Answer:

Step-by-step explanation:

Since the mutual fund is the lower yield vehicle, only the minimum should be invested there.

The investments and returns should be ...

  mutual fund: $9000, return = 6% × $9000 = $540

  CD: $71000, return = 8% × $71000 = $5680

The maximum return is ...

  $540 +5680 = $6220

To maximize the return, we need to find the amount to be invested in CDs and the mutual fund. The amount to be invested in CDs is $53,333.33 and the amount to be invested in the mutual fund is $26,666.67. The maximum return is $5,333.33.

To maximize the return, we need to find the amount to be invested in CDs and the mutual fund. Let's assume the amount invested in the mutual fund is x dollars. Since the investor requires at least twice as much to be invested in CDs, the amount invested in CDs will be 2x dollars. The total investment amount is $80,000, so we can write the equation: x + 2x = $80,000. Simplifying the equation, we have 3x = $80,000. Dividing both sides by 3, we get x = $26,666.67 (rounded to two decimal places).

The amount to be invested in CDs is 2 times x, which is $53,333.33 (rounded to two decimal places). Therefore, the maximum return can be calculated by multiplying the amount invested in CDs and the mutual fund by their respective interest rates and adding them. The return from the CDs would be 8% of $53,333.33 and the return from the mutual fund would be 6% of $26,666.67. Calculating the returns and adding them, we get the maximum return as $5,333.33 (rounded to two decimal places).

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For this case we must find the solution set of the given inequalities:

Inequality 1:

[tex]3 (2x + 1)> 21[/tex]

Applying distributive property on the left side of inequality:

[tex]6x + 3> 21[/tex]

Subtracting 3 from both sides of the inequality:

[tex]6x> 21-3\\6x> 18[/tex]

Dividing by 6 on both sides of the inequality:

[tex]x> \frac {18} {6}\\x> 3[/tex]

Thus, the solution is given by all the values of "x" greater than 3.

Inequality 2:

[tex]4x + 3 <3x + 7[/tex]

Subtracting 3x from both sides of the inequality:

[tex]4x-3x + 3 <7\\x + 3 <7[/tex]

Subtracting 3 from both sides of the inequality:

[tex]x <7-3\\x <4[/tex]

Thus, the solution is given by all values of x less than 4.

The solution set is given by the union of the two solutions, that is, all real numbers.

Answer:

All real numbers

Answer:

From three condition the it is proved that Δ ABC and  Δ DEF are similar Triangles .  

Step-by-step explanation:

Given as :

To Proof : Triangle Δ ABC and Triangle Δ DEF are similar

There are three methods for two Triangles to be similar

A ) SAS  i.e side angle side

B ) AA i.e angle angle

C ) SSS i.e side side side

Now,

A) If two triangle have a pair of equal corresponding angles and sides are proportional then triangle are similar

So, If in  Δ ABC and  Δ DEF

∠ B = ∠ E

and , [tex]\dfrac{AB}{DE}[/tex] =  [tex]\dfrac{BC}{EF}[/tex]

Then Δ ABC  [tex]\sim[/tex] Δ DEF

I.e SAS   similarity

B ) If two triangles have equal corresponding angles , then triangles are similar .

So, If in  Δ ABC and  Δ DEF

∠ B = ∠ E   and   ∠ A = ∠ D

Then Δ ABC  [tex]\sim[/tex] Δ DEF

I.e AA similarity

C ) If two triangles have three pairs of corresponding sides proportional then triangles are similar .

So, If in  Δ ABC and  Δ DEF

[tex]\dfrac{AB}{DE}[/tex] =  [tex]\dfrac{BC}{EF}[/tex] = [tex]\dfrac{AC}{DF}[/tex]

Then Δ ABC  [tex]\sim[/tex] Δ DEF

I.e SSS similarity

Hence From three condition the it is proved that Δ ABC and  Δ DEF are similar Triangles .   answer

Answer: Neither

Step-by-step explanation:

Got it wrong bc of the person it top of me but yea

Answer:

B) x + y = 3

Step-by-step explanation:

This is a specific way to give details without a detailed written explanation of the function. There will be NO exponents when trying to find out information about something:

[tex]\displaystyle x + y = 3 → y = -x + 3[/tex]

I am joyous to assist you anytime.

The optimal mixture to compose the desired fertilizer can be obtained using 17 lbs of Brand X, 6 lbs of Brand Y, and 8 lbs of Brand Z.

To solve this problem, let us denote X as the amount of brand X, Y as the amount of brand Y, and Z as the amount of brand Z. Since brand X contains equal parts of fertilizers B and C, and the optimal nutrients contain 13 lbs of B and 4 lbs of C, we can say that X = 13 lbs + 4 lbs = 17 lbs.

Brand Y contains one part of A and two parts of B. As we know from the problem that we need 5 lbs of A and 13 lbs of B, we get the equation Y = 5/3 lbs + 13/3 lbs = 6 lbs of Y. This equation is derived from the fact that for every 3 lbs of Y, you get 1.lb of A and 2 lbs of B.

Lastly, brand Z contains two parts of A, five parts of B, and four parts of C. So, Z could be calculated by the combined remainder of A, B and C i.e. (5 - 5/3 lbs) of A, (13 - 13 lbs) of B, and (4 - 4 lbs) of C which will get you approximately 8 lbs of brand Z.

So, you would need roughly 17 lbs of brand X, 6 lbs of brand Y, and 8 lbs of brand Z to create the desired fertilizer mixture.

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Answer:

[tex]\displaystyle \iint_S {\text{curl \bold{F}} \cdot} \, dS = \boxed{\bold{0}}[/tex]

General Formulas and Concepts:

Calculus

Integration Rule [Reverse Power Rule]:

[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:

[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:

[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:

[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Methods: U-Substitution + U-Solve

Multivariable Calculus

Partial Derivatives

Triple Integrals

Cylindrical Coordinate Conversions:

Integral Conversion [Cylindrical Coordinates]:

[tex]\displaystyle \iiint_T {f(r, \theta, z)} \, dV = \iiint_T {f(r, \theta, z)r} \, dz \, dr \, d\theta[/tex]

Vector Calculus

Surface Area Differential:

[tex]\displaystyle dS = \textbf{n} \cdot d\sigma[/tex]

Del (Operator):

[tex]\displaystyle \nabla = \hat{\i} \frac{\partial}{\partial x} + \hat{\j} \frac{\partial}{\partial y} + \hat{\text{k}} \frac{\partial}{\partial z}[/tex]

Stokes’ Theorem:

[tex]\displaystyle \oint_C {\textbf{F} \cdot } \, d\textbf{r} = \iint_S {\big( \nabla \times \textbf{F} \big) \cdot \textbf{n}} \, d\sigma[/tex]

Divergence Theorem:

[tex]\displaystyle \iint_S {\big( \nabla \times \textbf{F} \big) \cdot \textbf{n}} \, d\sigma = \iiint_D {\nabla \cdot \textbf{F}} \, dV[/tex]

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle \textbf{F} (x, y, z) = x^2z^2 \hat{\i} + y^2z^2 \hat{\j} + xyz \hat{\text{k}}[/tex]

[tex]\displaystyle \text{Region:} \left \{ {{\text{Paraboloid:} \ z = x^2 + y^2} \atop {\text{Cylinder:} \ x^2 + y^2 = 16}} \right[/tex]

Step 2: Integrate Pt. 1

Step 3: Integrate Pt. 2

Convert region from rectangular coordinates to cylindrical coordinates.

[tex]\displaystyle \text{Region:} \left \{ {{\text{Paraboloid:} \ z = x^2 + y^2} \atop {\text{Cylinder:} \ x^2 + y^2 = 16}} \right \rightarrow \left \{ {{\text{Paraboloid:} \ z = r^2} \atop {\text{Cylinder:} \ r^2 = 16}} \right[/tex]

Identifying limits, we have the bounds:

[tex]\displaystyle \left\{ \begin{array}{ccc} 0 \leq z \leq r^2 \\ 0 \leq r \leq 4 \\ 0 \leq \theta \leq 2 \pi \end{array}[/tex]

Step 4: Integrate Pt. 3

We evaluate the Stokes' Divergence Theorem Integral using basic integration techniques listed under "Calculus".

[tex]\displaystyle \begin{aligned}\iint_S {\text{curl } \textbf{F} \cdot} \, dS & = \int\limits^{2 \pi}_0 \int\limits^4_0 \int\limits^{r^2}_0 {r \bigg( 2z^2r \cos \theta + 2z^2r \sin \theta +r^2 \cos \theta \sin \theta \bigg)} \, dz \, dr \, d\theta \\& = \frac{1}{3} \int\limits^{2 \pi}_0 \int\limits^4_0 {zr^2 \bigg[ 2z^2 \big( \cos \theta + \sin \theta \big) + 3r \sin \theta \cos \theta \bigg] \bigg| \limits^{z = r^2}_{z = 0}} \, dr \, d\theta \\\end{aligned}[/tex]

[tex]\displaystyle \begin{aligned}\iint_S {\text{curl } \textbf{F} \cdot} \, dS & = \frac{1}{3} \int\limits^{2 \pi}_0 \int\limits^4_0 {r^5 \bigg[ 2r^3 \big( \cos \theta + \sin \theta \big) + 3 \sin \theta \cos \theta \bigg]} \, dr \, d\theta \\& = \frac{1}{54} \int\limits^{2 \pi}_0 {r^6 \bigg[ 4r^3 \big( \cos \theta + \sin \theta \big) + 9 \sin \theta \cos \theta \bigg] \bigg| \limits^{r = 4}_{r = 0}} \, d\theta \\\end{aligned}[/tex]

[tex]\displaystyle \begin{aligned}\iint_S {\text{curl } \textbf{F} \cdot} \, dS & = \frac{2048}{27} \int\limits^{2 \pi}_0 {\cos \theta \Big( 9 \sin \theta + 256 \Big) + 256 \sin \theta} \, d\theta \\& = \frac{-1024}{243} \bigg[ 4608 \cos \theta - \bigg( 9 \sin \theta + 256 \bigg)^2 \bigg] \bigg| \limits^{\theta = 2 \pi}_{\theta = 0} \\& = \boxed{\bold{0}}\end{aligned}[/tex]

∴ we have calculated the Stokes' Theorem integral with the given region and function using the Divergence Theorem.

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Topic: Multivariable Calculus

The Stokes' theorem is applied to convert a surface integral of a curl of a vector into a line integral. This is done by identifying the curl of the given vector field F and setting up the limits of the integral based on given bounds. The integral is then evaluated.

Stokes' theorem is used in vector calculus to simplify certain types of surface integrals. It transforms a surface integral of a curl of a vector field into a line integral. F(x, y, z) = x2z2i + y2z2j + xyzk, here, is the given vector field. The surface S is the part of the paraboloid that lies within the cylinder x² + y² = 16. The theorem is used to evaluate the integral S curl F · dS, by treating the surface integral as a line integral. The line integral can be easier to evaluate. The exact process involves identifying the curl of F, setting up the bounds of the integral based on the restrictions given, and then computing the integral.

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Answer:

Step-by-step explanation:

|t − 56|= 3 states that the temperature, t, can be as low as (56-3)°F, or 53°F, and as high as (56+3)°F, or 59°F.

On a number line, plot a dark dot at both 53°F and 59°F, and then connect these two dots with a solid line.

The maximum and minimum values of temperature are 59°F and  53°F respectively.

A difference between two values indicates whether one is smaller, larger, or basically not similar to the other.

A mathematical phrase in which the sides are not equal is referred to as being unequal. In essence, a comparison of any two values reveals whether one is less than, larger than, or equal to the value on the opposite side of the equation.

Given the inequality

|t − 56|= 3

Now,

Taking positive value ;

t - 56 = 3

t = 59

Now taking negative value

-(t-56) = 3

t = -3 + 56 =  53

Hence "The maximum and minimum values of temperature are 59°F and  53°F respectively".

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Answer:

It is significant because when they migrate from one place to other it becomes a source of genetic diversity between them and other population.

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Just by looking at the chart the answer concludes the correct equation for the graph hope this helps CORRECT ME IF I'M WRONG

ps: is that you on your profile picture?

Answer:

A

Step-by-step explanation:

1.9

A

Answer:

Step-by-step explanation:

We have four equations here.  Let's actually solve them, using factoring if possible and some other method if factoring is not possible.

A)  x^2 + 5x + 4 factors into (x + 1)(x + 4), but x^2 + 5x - 4 does not.

B)  x^2 + 6x + 9 factors into (x + 3)^2.

C) x^2 + 3x - 4 factors into (x + 4)(x - 1).

D) x^2 - x - 6 factors into (x - 3)(x + 2)

x^2 + 5x - 4 = 0 can be solved, but not by factoring.

Answer:

she will need to dance for 26 hours

Step-by-step explanation:

500=15(26)+110

Answer:

26 hours

Step-by-step explanation:

One group will donate $15 per hour, while the other is offering a flat sum of $110. She wants $500, so we can set up the equation

15x + 110 = 500 (with x being the number of hours Traci dances). You subtract 110 from 500 to isolate the variable with its coefficient, resulting in

15x = 390 . Then, dividing 390 by 15 to get x by itself, the answer of 26 hours is found.

Answer:

a) There are no evidence that Calvin is correct.

b) There are evidence that Calvin is correct.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 1 ounce

Sample size, n = 23

First, we design the null and the alternate hypothesis

[tex]H_{0}: \mu = 1\text{ ounce}\\H_A: \mu < 1\text{ ounce}[/tex]

P-value =  0.086

a) Significance level = 5% = 0.05

Since

P-value > Significance level

We fail to reject the null hypothesis and accept it. Thus, the chips bag contain one ounce of product. Thus, there are no evidence that Calvin is correct.

b) Significance level = 10% = 0.10

Since

P-value < Significance level

We reject the null hypothesis and accept the alternate hypothesis. Thus, the chips bag contain less than one ounce of product. Thus, there are evidence that Calvin is correct.

Answer: 50 tissue boxes

Step-by-step explanation:

The students want to make care packages for unhoused people for winter season.

They would like to put 5 boxes of tissues into each care package.

If they have 450 boxes pack, to determine how many tissue boxes that they need to complete the boxes, we will divide the total number of boxes pack that they have by the number of tissues that will go into one pack. It becomes

450/9 = 50

Answer:

8 bathroom jobs and 9 kitchen jobs

Step-by-step explanation:

B=60

K=20

8*60=480

9*20=180

that would give harry 660 dollars in a week. HOWEVER- we have to make sure that its equal to or less than 15 hours of work.

8*1h= 8 hours in bathroom

9*45m=6.75hr in kitchen

8 hours+6.75 hours=14.75hr 14.75 hr<15hr so it works.

Answer:

a) 125 < 128

b) The maximum probability that all 130 women are with college degree is 130 < 128 (this is not possible)

The minimum probability that none of the 130 women are college holders = 0 < 128 (this is possible)

Step-by-step explanation:

Total number of employees = 255

If the probability is less than 1/2 that the employee selected will be a woman who has college degree, we have

Women with college degree < 255/2

< 128

a) if 130 of the company employee do not have college degree, we consider that all the college degree holders are women.

The women with college degree = 255 - 130

= 125

Therefore; 125 < 128 ( this is possible)

b) If 125 of the company employees are men, the number of women = 250 -125

= 130 women

The maximum probability that all 130 women are with college degree is 130 < 128 (this is not possible)

The minimum probability that none of the 130 women are college holders = 0 < 128 (this is possible)

Answer: The estimated margin of error = 0.5 centimeter

The sample mean = 4.3 centimeters

Step-by-step explanation:

The confidence interval for population  mean is given by :-

[tex]\overline{x}\pm E[/tex]

or [tex](\overline{x}-E,\ \overline{x}+E)[/tex]

, where [tex]\overline{x}[/tex] = sample mean.

E = Margin of error .

The given confidence interval : (3.8,4.8 )

Lower limit : [tex]\overline{x}-E=3.8[/tex]                (1)

Upper limit =  [tex]\overline{x}+E=4.8[/tex]                (2)

Eliminate equation (1) from (2) , we get

[tex]2E=1.0\\\\\Rightarrow\ E=\dfrac{1}{2}=0.5[/tex]

⇒ The estimated margin of error = 0.5 centimeter

Add (1) and (2) ,we get

[tex]2\overline{x}-E=8.6\\\\\Rightarrow\ \overline{x}=\dfrac{8.6}{2}=4.3[/tex]  

⇒ The sample mean = 4.3 centimeters

Answer:

Step-by-step explanation:

Lines p and line r are parallel. This actually means that they will extend continuously without meeting at a point.

Let us assign an alphabet to an angle to make it easy for reference. The diagram is shown in the attached photo

From the photo,

Angle T is equal to 34 degrees. This is because angle T and 34 degrees are corresponding angles.

Angle G = angle T. This is because angle T is vertically opposite to angle G. Therefore

G = 34 degrees

Answer:

  C)  28√17

Step-by-step explanation:

The perimeter is twice the sum of the two given side lengths, so is ...

  P = 2(L +W) = 2(2√153 +4√68)

  = 2(6√17 +8√17) = 2(14√17)

  P = 28√17 . . . . . matches choice C

_____

This is about simplifying radicals. The applicable rules are ...

  √(ab) = (√a)(√b)

  √(a²) = |a|

__

  153 = 9×17, so √153 = (√9)(√17) = 3√17

  68 = 4×17, so √68 = (√4)(√17) = 2√17

_____

Comment on the problem presentation

It would help if there were actually radicals in the radical expressions. We had to guess based on the spacing and the answer choices.

In any event, this problem can be worked with a calculator. Find the perimeter (≈115.45) and see which answer matches that. (That's what I did in order to verify my understanding of what the radical expressions were.)

Answer

The answer

it is y ≥ -2|x + 1| + 3

since the -2 or A controls the negative or positive of an absolute value graph its negative so it's down.

| x+1| if it's like that then you must reverse the sign so it is -1

and for the +3 that controls your vertical line meaning up or down. & in this case it went up so its +3

Answer:

Null hypothesis: [tex]\mu \leq 15[/tex]

Alternative Hypothesis: [tex]\mu >15[/tex]

We have enough evidence to reject the null hypothesis at 10% level of significance.

Step-by-step explanation:

1) Data given

n =44, representing the sample size

[tex]\bar X=15.6ft[/tex] represent the sample mean for the length of great white sharks

[tex]s=2.5ft[/tex] represent the sample standard deviation for the  length of great white sharks

[tex]\alpha =0.1[/tex] significance level for the test

2) Formulas to use

On this case we are intereste on the sample mean for the  length of great white sharks, and based on the paragraph the hypothesis are given by:

Null hypothesis: [tex]\mu \leq 15[/tex]

Alternative Hypothesis: [tex]\mu >15[/tex]

since we have n>30 but we don't know the population deviation [tex]\sigma[/tex] so we will can use the t approximation. The sample mean have the following distribution

[tex]\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})[/tex]

Based on this the statistic to check the hypothesis would be given by:

[tex]t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}[/tex]

Replacing the values given we have:

[tex]t_{calc}=\frac{15.6-15}{\frac{2.5}{\sqrt{44}}}=1.592[/tex]

We can calculate the degrees of freedom with:

[tex]df=n-1=44-1=43[/tex]

With [tex]\alpha[/tex] and the degrees of freedom we can calculate the critical value, since [tex]\alpha=0.1[/tex] we need a value from the t distribution with 43 degrees of freedom that accumulates 0.1 of the area on the right or 0.9 of the area on the left.

We can use excel, a calculator or a table for this, calculating this value we got:

[tex]t_{(43,critc)}=1.302[/tex]

Since our calculatesd value was [tex]t_{calc}=1.592>t_{crit}[/tex], we can reject the null hypothesis at 0.1 level of significance.

Other way in order to have a criterion for reject or don't reject the null hypothesis is calculating the p value, on this case based on the alternative hypothesis the p value would be given by:

[tex]p_v=P(t_{(43)}>1.592)=0.0594[/tex]

So then [tex]p_v <\alpha[/tex] so we have enough evidence to reject the null hypothesis at 10% level of significance.

Answer:

12

Step-by-step explanation:

x=(-10×1+23×2)÷(2+1)=36/3=12

Final answer:

The coordinate that divides the line segment from -10 at J to 23 at K in the ratio of 2 to 1 is C) 12.

Explanation:

The coordinate that divides the line segment from -10 at J to 23 at K in the ratio of 2 to 1 is 12.

To find this coordinate, we can use the concept of a section formula. Let the ratio be m:n. The coordinate divided is [tex](\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n})[/tex]. Substituting the values, we get [tex](\frac{2 ( 23) + 1 ( -10)}{2+1}, \frac{2 (0) + 1 ( 2)}{2+1})[/tex] = (12, 0).

Therefore, the required coordinate that divides the line segment in the ratio of 2 to 1 is C) 12.

Answer:

r=68.64 m

Step-by-step explanation:

Given that

Weight ,wt= 14100 N

mass m = 1410 kg             ( g = 10 m/s²)

Friction force = Weight

Fr= 14100 N

v= 26.2 m/s

Lets take radius of the curve =  r

To balance the truck ,radial force should be equal to the friction force

[tex]\dfrac{mv^2}{r}=Fr[/tex]

mv² = Fr x r

1410 x 26.2² = 14100 x r

r=68.64 m

Therefore radius of the curve will be 68.64 m

Answer - r=68.64 m

The minimum safe curve radius that the truck could negotiate at 26.2 m/s in good driving conditions is approximately 78.94 meters. This relies on the principles of centripetal force and friction, and requires converting the weight of the truck into its mass. The resulting radius ensures that the centripetal force, provided by the friction between the tires and the road, is enough to keep the truck on its path.

The subject of this question is related to Centripetal Force and Friction in physics. Centripetal force is the net force on an object moving in a circular path and it points towards the center of the circular path. This force keeps the object moving along this path and is provided by the frictional force between the truck's tires and the road.

In this case, if friction equates to the weight of the truck (14100 N), it will be the centripetal force. The equation for centripetal force is given by:

where Fc is the centripetal force, m is the mass of the object, v is the velocity of the object and r is the radius of the circular path. We can arrange this formula to calculate the safe curve radius(r) the truck can negotiate:

However, in this case, the mass of the truck is given as a force (Weight = 14100 N). So first we need to convert this weight into mass. We can do this by using the formula: Weight = mass (m) × acceleration due to gravity (g). Here, g = 9.8 m/s²:

Now we can substitute m = 1438.78 kg, v = 26.2 m/s and Fc = 14100 N into our radius equation to find the minimum safe curve radius for the truck:

So, the minimum safe curve radius that the truck could negotiate at 26.2 m/s in good driving conditions is approximately 78.94 meters.

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Answer:

The two coaches will charge the same amount of money after working for 11 hours

Step-by-step explanation:

Let us assume for m hours, they both will charge same amount.

For COACH A:

The initial Fee = $ 6,925

The per hour fee  = $450

So, the fees in m hours = m x ( Per hour fees) = m x ($450)  = 450 m

So, the total fees of Coach A in m hours = Initial Fee + fee for m hours

                                                                  = $ 6,925  + 450 m  

⇒ The total fees of Coach A in m hours  = $ 6,925  + 450 m ....  (1)

For COACH B:

The initial Fee = $ 5,000

The per hour fee  = $725

So, the fees in m hours = m x ( Per hour fees) = m x ($725)  = 725  m

So, the total fees of Coach B in m hours = Initial Fee + fee for m hours

                                                                  = $ 5,000  + 725 m  

⇒ The total fees of Coach B in m hours  =$ 5,000  + 725 m ....  (2)

Now, for m hours , they both charge the SAME AMOUNT fees

⇒$ 6,925  + 450 m  = $ 5,000  + 725 m    ( from (1) and (2))

or, 6925 - 5000 = 725 m - 450 m

or, 1925 = 175 m

or,m = 1925 / 175 = 11

or, m = 11

Hence, the two coaches will charge the same amount of money after working for 11 hours.

Answer:

  7 feet

Step-by-step explanation:

Assuming the dimensions are integers, we can look at the factors of 28:

  28 = 1·28 = 2·14 = 4·7

The last pair differs by 3, so can be the solution to the problem.

The length of the rectangle is 7 feet.

Answer:

the answer is (-4,2)

Step-by-step explanation:

Answer:

Step-by-step explanation:

the answer is (-4,2)