The driver of a car applies the brakes for 4.0 s.As a result an average force of 7500N is exerted in the car to slow it down.What is the change in momentum of the car.

Final answer:

Division and subtraction are not associative operations, meaning that the grouping of numbers can affect the outcome of these operations.

Explanation:

An operation is considered associative if a change in the grouping of the elements does not change the result of the operation. For example, in addition, (a + b) + c = a + (b + c). This means that addition is associative. Similarly, multiplication is associative as well: (a × b) × c = a × (b × c).

Division and subtraction are operations that are not associative. The expression (a - b) - c does not necessarily equal a - (b - c), and similarly, (a / b) / c is not the same as a / (b / c). These operations cannot be regrouped without potentially changing the outcome.

Therefore, the answer to the question is C. division and subtraction are operations that are not associative.

The final velocity of the candy is 57.7 m/s

Explanation:

The motion of the candy is a free fall motion, since it is subjected only to the force of gravity, so it is a uniformly accelerated motion and therefore we can use the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity

s is the vertical displacement

In this problem, we have:

u = 0 (the candy is dropped from rest)

s = 170 m (the vertical displacement is the height of thr monument)

Solving for v, we find the velocity of the candy as it hits the  ground:

[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(170)}=57.7 m/s[/tex]

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Answer:

D. 0.29

Explanation:

The power is 833.3 W

Explanation:

First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:

[tex]W=(mg)h[/tex]

where

mg = 1250 N is the weight of the barbell

h = 2 m is the change in height

Substituting,

[tex]W=(1250)(2)=2500 J[/tex]

Now we can calculate the power, which is equal to the work done per unit time:

[tex]P=\frac{W}{t}[/tex]

where

W = 2500 J is the work done

t = 3 s is the time taken

Substituting,

[tex]P=\frac{2500}{3}=833.3 W[/tex]

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D

The exact location of electrons in electron shells of atoms cannot be exactly ascertained. This is why VSPER atomic models represent the position of electrons (s, p, d, & f) using the probability of where they would most be expected to be found.

Explanation:

This is because merely observing electrons changes their behavior. Remember that to observe something one has to shine light on it so it bounces back to the eye. Due to the negligible mass of electrons, mere photons of light will change their direction of movement, spin or other behaviors/properties.

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Answer:

6

8

6

on edge

Explanation:

Answer:

13 to 19 years old

Explanation:

Because these 6 years there is the word TEEN 13, 14, 15, 16, 17, 18, and 19. but in 20 there is no teen.

PLEASE MARK AS BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

The acceleration of the ball after leaving the hand is [tex]9.8 m/s^2[/tex] downward

Explanation:

In order to find the acceleration of the ball during its motion, we have to study which forces are acting on it.

After the ball leaves the hand, if we neglect air resistance, there is only one force acting on the ball: the force of gravity, whose magnitude is

[tex]F=mg[/tex]

where m is the mass of the ball and g is the acceleration of gravity ([tex]g=9.8 m/s^2[/tex]), acting in the downward direction.

According to Newton's second law, the acceleration of the ball is given by

[tex]a=\frac{\sum F}{m}[/tex]

where

[tex]\sum F[/tex] is the net force acting on the ball

After the ball leaves the hand, the only force acting on it is the force of gravity, so we can substitute (mg) into the previous equation:

[tex]a=\frac{mg}{m}=g=9.8 m/s^2[/tex]

This means that the acceleration of the ball remains [tex]9.8 m/s^2[/tex] downward for the entire motion, after leaving the hand.

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Final answer:

The acceleration of the ball after it is thrown upward is a constant 9.8 m/s^2 downward due to gravity.

Explanation:

After you throw a ball upward with a speed of 14m/s, the acceleration of the ball after it leaves your hand is determined by the force of gravity. Regardless of the initial speed given to the ball, once it is not in contact with your hand, there is no longer any force being applied to it in the upward direction. Therefore, the only force acting on it is the force of gravity pulling it back toward the Earth's surface.

This force causes the ball to have a constant downward acceleration of approximately 9.8 m/s2, which is the standard acceleration due to gravity near the Earth's surface (often represented by the symbol g).

900 grams of lead can be added max to the tin so that it does not sink.

Explanation:

According to the Archimedes principle, an object will not sink in a medium until the density of the object exceeds the density of the medium.

The medium we have is water.

The density of medium(water) is given as ρ° = 1 g/cm³

Density of an object is simply its mass contained per unit volume.

Density = mass/volume

Volume of the tin = v = 1000 cm³

Mass of the tin = m = 100 g

Mass of lead that can be added without sinking = x

Total mass after adding lead in the tin = Mt = m + x

Total density after lead is added to the tin is given as:

ρt = (m+x)/v

Now, according to Archimedes principle, lead can be added to the tin until the density of tin is equal to the density of water.

ρt = ρ°

Mt/v = ρ°

(m + x)/v = ρ°

⇒ (100 + x)/1000 = 1

⇒ 100 + x = 1000

⇒ x = 1000 - 100

x = 900 g

Keyword: Archimedes principle

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The force of gravity causes a volleyball to accelerate downwards when it rises in the air.

Initially, as the ball rises, gravity slows down its vertical velocity until it comes to a stop at its maximum height and then starts descending back to the ground due to the force of gravity.

Answer:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward towards the center of rotation.

Explanation:

Definition of centripetal force:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward towards the center of rotation.

Example of centripetal force

A string on the end of which a stone is whirled about exerts a centripetal force on the stone.

The diagram is shown below

Where

The centripetal forces acting towards the centre C that is [tex]\vec {AC}[/tex]

and the direction is from A to C.

And the stone is moving in a circular motion with center as C.

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

[tex]F=mg[/tex] (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance [tex]r[/tex] from the centre of the Earth is given by

[tex]g=\frac{GM}{r^2}[/tex]

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

[tex]F=\frac{GMm}{r^2}[/tex]

When the astronaut is on the Earth's surface, [tex]r=R[/tex] (where R is the Earth's radius), so his weight is

[tex]F=\frac{GMm}{R^2}=640 N[/tex]

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

[tex]r'=3R+R=4R[/tex]

Therefore, the new weight is

[tex]F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}[/tex]

Which means that his weight has decreased by a factor 16: therefore, the new weight is

[tex]F'=\frac{640}{16}=40 N[/tex]

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Final answer:

The gravitational force on the astronaut 3 times farther from the Earth's surface than the radius would be 40 N, as at this distance the gravitational force is reduced to 1/16th of its original value.

Explanation:

The question asks: If an astronaut weighs 640 N on the earth's surface, what is the gravitation force between him and the earth if he is 3 times the distance from the Earth's surface? This requires understanding of Newton's law of universal gravitation, which can be expressed as F = G(m1m2)/r², where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.

As the astronaut moves to a distance 3 times farther from the surface of the Earth, the distance (r) from the center of the Earth becomes 4r, because the initial distance from the surface to the center of the Earth (the radius of the Earth, or 1r) is included. According to the inverse-square law, if the distance increases by a factor of n, the force decreases by a factor of n2. Thus, at 3 times the distance from the surface, or 4 times the radius of the Earth, the gravitational force becomes 1/16th of what it was at the surface.

Therefore, the new gravitational force is 640 N / 16 = 40 N.

Answer:

The work done by you, W = 9800 J

Explanation:

Given data,

The displacement of the car, S = 5 m

Let the mass of the car be, m = 2000 kg

Let the coefficient of static friction be 0

Hence, no frictional force is acting on the tire and ground.

Let, you push down the car to provide more friction, μₓ = 0.1 (you can change the value)

In order to provide the static friction, you push down the car is equal to the static friction force,

                                      Fₓ =  μₓ · η

Where,

                                 η - normal force acting on the car (mg)

Substituting the values,

                                   Fₓ = 0.1 x 2000 x 9.8

                                       = 1960 N  

Therefore work done,

                                   W = Fₓ x S

                                        = 1960 N x 5 m

                                        = 9800 J

Hence, the work done by you, W = 9800 J

Answer:

The distance the hiker walked is, d = 13 km

The displacement of the hiker is, S = 9.4 km

Explanation:

Given data,

The displacement of towards east, d₁ = 1 km

The displacement of towards north, d₂ = 2 km

The displacement of towards east, d₃ = 4 km

The displacement of towards north, d₄ = 6 km

The total distance the hiker walked

                           d = d₁ + d₂ + d₃ + d₄

                              = 1 + 2 + 4 + 6

                              = 13 km

The distance the hiker walked is, d = 13 km

The resultant displacement of the hiker, S

                                S = √( A² + B² + 2 A B cosФ)

Where,

                         A = d₁ + d₃ = 5 km

                         B = d₂ + d₄ = 8 km

                         Ф = angle between A and B = 90°

Substituting in the displacement equation

                          S = √( 5² + 8²)

                              = 9.4 km

Hence, the displacement of the hiker is, S = 9.4 km

Particle A orbits the nucleus, and Particle B is located in the nucleus.

Explanation:

The atoms consists of three types of particle:

- Proton: it is located in the nucleus of the atom, its mass is approximately [tex]1.67\cdot 10^{-27}kg[/tex], and its charge is [tex]+e=1.6\cdot 10^{-19}C[/tex] (positive charge)

- Neutron: it is also located in the nucleus of the atom, its mass is similar to that of the proton, and it has no electric charge

- Electron: it orbits around the nucleus, it is much lighter than the proton and the neutron (mass: [tex]9.11\cdot 10^{-31}kg[/tex]), and it is negatively charged ([tex]q=-e=-1.6\cdot 10^{-19}C[/tex])

Looking at the definitions above, and since we know that particle A has very little mass in comparison to particle B (so, particle A must be an electron), we can only conclude the following:

Particle A orbits the nucleus, and Particle B is located in the nucleus.

In fact, we cannot determine whether particle B is a proton or a neutron, since we don't know anything about its charge.

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Answer: the correct answer would be Particle A orbits the nucleus, and Particle B is located in the nucleus. I think Particle A represents the electrons while B represents protons and neutrons.

Explanation:

Answer:

2 m/s

Explanation:

In Physics, a reference direction denotes a clear direction related to motion. Options A, B, and C are valid reference directions, but '2 E' (option D) is not a clear reference direction.

In the context of Physics, a reference direction is an established direction, such as north, south, east, west, up, down, left, or right, used to describe the direction of a vector. These are often used in assessments of motion to delineate the path of an object. In your question, 'A. +', 'B. S', and 'C. down' can be considered as reference directions where '+' denotes a positive direction, 'S' represents South, and 'down' indicates a downward direction. However, 'D. 2 E' does not fit the criteria for a reference direction as '2 E' does not represent an established direction. Instead, it seems like a combination of a numeric value '2' and a directional reference 'E' (possibly East), but as a whole, it is not itself a clear direction.

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1) The ball's speed is 3 m/s

2) The final speed of the raft is 0.6 m/s

3) The collision is inelastic

Explanation:

1)

The momentum of an object is given by

[tex]p=mv[/tex]

where

p is the momentum

m is the mass of the object

v is its velocity

For the ball in this problem we have:

p = 12 kg m/s

m = 4 kg

Solving for v, we find its velocity (and so its speed):

[tex]v=\frac{p}{m}=\frac{12}{4}=3 m/s[/tex]

2)

We can solve this part by applying the law of conservation of momentum: in fact, the total momentum of an isolated system (=no external forces) must be conserved. Therefore we can write:

[tex]p_i = p_f[/tex] (1)

where

[tex]p_i = 0[/tex] is the total initial momentum (the swimmer and the raft are at rest at the beginning)

[tex]p_f = mv + MV[/tex] is the total final momentum, where

m = 75 kg is the mass of the swimmer

M = 500 kg is the mass of the raft

v = 4 m/s is the final velocity of the swimmer

V is the final velocity of the raft

And substituting into (1) we find:

[tex]0=mv+MV\\V=-\frac{mv}{M}=-\frac{(75)(4)}{500}=-0.6 m/s[/tex]

Where the negative sign indicates that the raft moves in the opposite direction to the swimmer: so, the speed of the raft is 0.6 m/s.

3)

In a collision between two objects, if the system is isolated the total momentum of the system is always conserved during the collision. However, this is not true for the total kinetic energy: in fact, due to the presence of internal frictions, part of the kinetic energy can be converted into thermal energy or other forms of energy.

Therefore, there are two types of collision:

- Elastic collision: in an elastic collision, also the total kinetic energy of the objects is conserved

- Inelastic collision: in an inelastic collision, the total kinetic energy is not conserved. The most extreme case is the perfectly inelastic collision, in which the two objects stick together after the collision, and in this case there is the maximum loss of kinetic energy.

Since in this problem the two objects stick together, the collision is inelastic.

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Final answer:

The appearance of a ship's top first as it approaches the horizon shows the Earth's curvature, as the lower parts disappear first due to the spherical shape.

Explanation:

When a ship comes into view on the horizon, the top appears before the rest of the ship, demonstrating that the Earth is spherical. This is because as the ship sails away from an observer, the curvature of the Earth causes the lower parts of the ship to disappear from view first, much like it would drop behind a hill. This phenomenon, which mariners like Columbus would have been familiar with, is a direct consequence of the Earth's spherical shape.

The higher masts of the ship remain visible for a while longer because they are the last to dip below the horizon as the ship follows the Earth's curvature. This effect proves that the Earth is not flat because if it were, the entire ship would simply appear smaller but would stay in full view as it moves away.

Moreover, the use of lookouts in the ship's mastheads also illustrates the Earth's curvature. On a spherical Earth, lookouts posted higher up can see further over the horizon than those at deck level. Conversely, if the Earth were flat, there would be little to no advantage of having lookouts at higher positions.

The mechanical advantage of the pulley is 3.56

Explanation:

The Mechanical Advantage (MA) of a pulley system is given by

[tex]MA=\frac{Load}{Effort}[/tex]

where

Load is the weight of the object lifted

Effort is the force applied in input

For the pulley in this problem, we have:

Effort = 55 N

While the load is the weight of the box of mass m = 20.0 kg:

[tex]Load = mg = (20.0 kg)(9.8 m/s^2)=196 N[/tex]

Substittuing, we find the MA of the pulley:

[tex]MA=\frac{196}{55}=3.56[/tex]

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Answer:

R=50 meters

Explanation:

We'll use the Pythagoras's theorem

[tex]R^2=a^2+b^2[/tex]

A right triangle with legs of a=40 m and b=30 m has an hypotenuse of

[tex]R^2=30^2+40^2=900+1600[/tex]

[tex]R=\sqrt{2500} =50[/tex]

[tex]R=50\ meters[/tex]

Answer:

b 50

Explanation:

just did it

The angle of incidence in glass is [tex]34.7^{\circ}[/tex]

Explanation:

We can solve this problem by applying Snell's law of refraction, which states that:

[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]

where

[tex]n_1, n_2[/tex] are the index of refraction of the first and second medium, respectively

[tex]\theta_1, \theta_2[/tex] are the angle of incidence and refraction, respectively

In this problem we have:

[tex]n_1 = 1.52[/tex] is the index of refraction of the first medium (glass)

[tex]n_2 = 1.00[/tex] is the index of refraction of the second medium (air)

[tex]\theta_2 =60^{\circ}[/tex] is the angle of refraction in glass

Solving for [tex]\theta_i[/tex], we find the angle of incidence:

[tex]\theta_1 = sin^{-1} (\frac{n_2 sin \theta_2}{n_1})=\sin^{-1}(\frac{(1.00)(sin 60^{\circ})}{1.52})=34.7^{\circ}[/tex]

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Final answer:

Using Snell's Law and the given indices of refraction for crown glass and air, as well as the angle of refraction in air, the angle of incidence within the crown glass is calculated to be approximately 41.14°.

Explanation:

To find the angle of incidence in glass when a ray of light exits the glass into air with a known angle of refraction, we use Snell's Law, which states that n1
*sin(θ1) = n2
*sin(θ2), where n1 and n2 are the refractive indices of the glass and air respectively, and θ1 and θ2 are the angles of incidence and refraction respectively. Given that the refractive index of crown glass is 1.52 (n1 = 1.52) and air is 1.00 (n2 = 1.00), with an angle of refraction of 60° in air (θ2 = 60°), we can rearrange Snell's Law to solve for the angle of incidence (θ1).

First, we plug in our known values:
1.52
*sin(θ1) = 1.00
*sin(60°)

Calculating the sine of 60 degrees and dividing by the refractive index of crown glass gives us the sine of the angle of incidence:

sin(θ1) = (1.00/1.52)
* sin(60°)

sin(θ1) ≈ 0.657

Using the inverse sine function, we find:

θ1 ≈ sin^−1(0.657)

θ1 ≈ 41.14°

Therefore, the angle of incidence in the crown glass is approximately 41.14°.

The final velocity of the rock is 19.8 m/s

Explanation:

The motion of the rock is a free fall motion (subjected only to the force of gravity), with constant acceleration [tex]g=9.8 m/s^2[/tex] towards the ground. Therefore, we can use the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the vertical displacement

For the rock in this problem,

u = 0 (initial velocity is zero)

[tex]a=g=9.8 m/s^2[/tex]

s = 20 m (height of the cliff)

Solving for v,

[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(20)}=19.8 m/s[/tex]

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Answer:

Explanation:

       A object dropped from a plane from a certain height will follow a parabolic trajectory because it has a horizontal velocity equal to plane's velocity.

       So, if supplies are to be dropped from a plane from a height of 160 m, let us calculate the time it takes to reach the ground.

       [tex]H=\frac{1}{2}gt^{2}\\160=\frac{1}{2}\times10\times t^{2}\\t=\sqrt{32}=4\sqrt{2}\text{ }sec[/tex]

       So, in this time, the supply moves a horizontal distance of [tex](4\sqrt{2}\text{ }sec)\times(45\text{ }\frac{m}{sec})=180\sqrt{2}\text{ }m=254.56\text{ }m[/tex].

∴ The supply must be dropped when the plane is 255 m away.

Answer:

The speed of the block after it has moved 3M if the surface in contact have a coefficient of kinetic friction of 0.15​  is 1.7s m/sec

Explanation:

Given:

mass of the block = 6.0 kg

Force with which the block is pulled = 12 N

Kinetic friction \mu= 0.15

Distance travelled  s = 3 m

To Find:

speed of the block after it has moved 3 metres =?

Solution :

W know that the friction formula is

[tex]f_k = \mu m g[/tex]

Substituting the values,

[tex]f_k = (0.15)(6)(10)[/tex]

[tex]f_k= 9 N[/tex]

Now Acceleration is Given by

[tex]a=\frac{F -f_k}{m}[/tex]

[tex]a=\frac{12 - 9}{60}[/tex]

[tex]a=\frac{3}{6}[/tex]

a= 0.5 [tex]m/s^2[/tex]

Initial velocity is u = 0

Also we know that,

[tex]v^2 - u^2=2as[/tex]

So the equation becomes

[tex]v^2 =2as[/tex]

[tex]v=\sqrt{2as}[/tex]

Substituting the values,

[tex]v=\sqrt{2as}[/tex]

[tex]v=\sqrt{2(0.5)(3)}[/tex]

[tex]v= \sqrt{3}[/tex]

v= 1.73 m/s

Answer:

μ = 0.535

Explanation:

On a level floor, normal force = weight.

N = W

Friction force = normal force × coefficient of friction.

F = Nμ

Substitute:

F = Wμ

83 = 155μ

μ = 0.535

Round as needed.

Answer:

Mass 1

Explanation:

Take any set of points of the masses:

Let's say the masses in the acceleration 4 m/s (because it represents the points more clearer)

Force = mass × acceleration.

But we need to know the mass if force and acceleration is given.

So,

Mass = Force ÷ acceleration

Now back to the set of points

mass = force ÷ acceleration

For mass 1,

mass = 8 ÷ 4

mass = 2

For mass 2,

mass = 4 ÷ 4

mass = 1

For mass 3,

mass = 2 ÷ 4

mass = 1/2

As you can see from the results, mass 1 definitely has the largest.

Now that you have read through here and think, "we might as well depend on the graph". You are correct but sometimes you should not rely on the graph.

Answer:

Mass 1

Explanation:

I have done the test.

Answer:

2100 J

Explanation:

Work = force × distance

W = Fd

W = (140 N) (15 m)

W = 2100 J

Answer:

[tex]\displaystyle 2100\:J[/tex]

Explanation:

[tex]\displaystyle FD = W → 2100 = [15][140][/tex]

Force by Distance

I am joyous to assist you anytime.

Answer:

I think D.

Injured cells stimulate pain, swelling, redness, and heat- which initiates bradykinin-which stimulates the release of histamine- which increases neutrophils and macrophages- leads to phagocytosis of foreign invaders.

Answer:

Injured cells stimulate bradykinin- which initiates the release of histamine- which causes pain, swelling, redness, & heat- increases neutrophils & macrophages- leads to phagocytosis of foreign invaders

Explanation:

Took the test

An beta particle is a fast-moving electron.

An alpha particle and a helium nucleus are the same thing . . . a package composed of two protons and two neutrons.

An positron is a particle with the same mass as an electron but a positive charge.