Chemistry College

The element germanium was once an important component
oftransistors. It can be made by heating the ore germanite
withhydrogen chloride, distilling of the germanium chloride to
theoxide to the metal.
When 1.00g germanite as treated this way, the germanium
presentedwas completely converted into 0.177g of a chloride
containing 33.9%by mass of germanium.
a) Calculate the percentage of germanium in germatite.

Answers

Answer 1

Answer:

The percentage of germanium in germatite is 6.0003%.

Explanation:

Mass of an ore of germanite = 1.00 grams

Mass of germanium chloride = 0.177 grams

Percentage of germanium in germanium chloride = 33.9%

Let the mass of germanium present in germanium chloride be x.

Percentage of an element in a compound:

[tex]\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100[/tex]

[tex]33.9\%=\frac{x}{0.177 grams}\times 100[/tex]

x = 0.060003 grams

Percentage of germanium in an ore of germanite:

[tex]=\frac{0.060003 gram}{1 gram}\times 100=6.0003\%[/tex]

The percentage of germanium in germatite is 6.0003%.

Related Questions

Draw a bond-line structure for each of the following compounds: 2.55 a) CH2-CHCH2C(CH3)3 (b) (CH3CH2)2CHCH2CH2OH (d) CH3CH2OCH2CH2OCH2CH3 (c) CH COCH2CH(CH3)2 (f) (CH3)2C=CHCH3 (e) (CH3CH2)3CBr

Answers

Answer:

See attachment

Explanation:

Bond-line structures are representations of molecules, where lines are drawn to represent the bonds between carbon atoms or between carbon atoms and heteroatoms (atoms other than C or H). Hydrogen atoms are not represented. Heteroatoms are indicated by their symbol but carbon atoms are not. Carbon atoms are located at the intersection of two lines.

A single bond is represented by one parallel line, a double bond by two parallel lines, and a triple bond by three parallel lines.

For (c), the formula is assumed to CH₃COCH₂CH(CH₃)₂

Final answer:

The question asks for bond-line structures of various compounds which are simplified drawings of molecules with the endpoints and intersections of each line representing carbon atoms and hydrogen atoms are understood to be filling any remaining free bonds, not represented in the diagram. An example is provided.

Explanation:

The question asks for bond-line structures of various compounds. A bond-line structure (also known as a line-angle diagram or skeletal formula) is a type of molecular structural formula that simplifies and reduces the drawing of a molecule to its basics, without including non-carbon and non-hydrogen atoms, or any multiple bonds. The endpoints and intersections of each line are carbon atoms and hydrogen atoms are understood to be filling any remaining free bonds, not represented in the diagram.

For example, for compound (CH₃CH₂)₂CHCH₂CH₂OH), the bond-line structure would look like a series of zig-zag lines, representing the carbon backbone of the molecule, with an OH group attached to the end. The CH₃ and CH₂ groups are understood without being explicitly drawn. The same principle applies to all the specified compounds. Due to the textual limitations of this platform, it's not possible to sketch the structures in the response.

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Which of the following choices has the compounds correctly arranged in order of increasing solubility in water? (least soluble to most soluble) Which of the following choices has the compounds correctly arranged in order of increasing solubility in water? (least soluble to most soluble) LiF < NaNO3 < CHCl3 CH3OH < CH4 < LiF CH4 < NaNO3 < CHCl3 CCl4 < CHCl3 < NaNO3 CH3OH < Cl4 < CHCl3

Answers

Answer: Option (d) is the correct answer.

Explanation:

As it is known that like dissolves like. So, water being a polar compound is able to dissolve only polar compounds.

Hence, a compound that is ionic or polar in nature will readily dissolve in water. Whereas non-polar compounds will be insoluble in water.

As [tex]CCl_{4}[/tex] is a non-polar compound. Hence, it is insoluble in water.

On the other hand, [tex]CHCl_{3}[/tex] is a polar compound due to difference in electronegativity of chlorine and carbon atom there will be development of partial charges. Hence, there will be dipole-dipole forces existing between them.

Whereas [tex]NaNO_{3}[/tex] is an ionic compound and it will readily dissociate into ions when dissolved in water. Also, there will be ion-dipole interactions between sodium and nitrate ions.

Hence, [tex]NaNO_{3}[/tex] will readily dissolve in water.

Thus, we can conclude that the compounds correctly arranged in order of increasing solubility in water are [tex]CCl_{4}[/tex] < [tex]CHCl_{3}[/tex] < [tex]NaNO_{3}[/tex].

Final answer:

The correct order of compounds from least soluble to most soluble in water is CH4 < NaNO3 < CHCl3. CH4 is nonpolar and doesn't dissolve well in water, NaNO3 is an ionic compound and readily soluble, and CHCl3 is more soluble than CH4 but less than NaNO3 due to its polar bonds.

Explanation:

Looking at your options, the correct arrangement of compounds in order of increasing solubility in water from least to most soluble is CH4 < NaNO3 < CHCl3. The solubility of a compound in water depends on its molecular structure. CH4 (Methane) is a nonpolar compound and therefore, it doesn't dissolve well in water, a polar solvent.

On the other hand, NaNO3 (Sodium nitrate) is an ionic compound and can dissociate into its ions in water, making it highly soluble. CHCl3 (Chloroform) is a polar compound due to the presence of polar C-Cl and C-H bonds, and it is more soluble in water than CH4 but less soluble than NaNO3.

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