The equation for density is mass divivded by volume.an increase in denstiy can result from all of following expect??

Answer:

The correct answer is option (i), amplifies sound vibrations

Explanation:

Cochlea is part of the inner ear that is responsible for receiving the sound vibrations. The received sound vibration is then converted into nerve impulses which are then send  to the brain for interpretation. Cochlea amplifies the sound so that they can be easily detected even by a damaged ear and it is also able to stimulate the hearing nerve directly.

The cochlea amplifies sound vibrations.

The cochlea is a spiral, hollow, conical chamber inside the human ears which is made up of a bone.

Cochlea is  present inside the inner ear its function is to receive the sound vibrations.

The received sound vibration is then converted into nerve impulses which are then send  to the brain for interpretation.

Cochlea amplifies the sound so that they can be easily detected even by a damaged ear and it is also able to stimulate the hearing nerve directly.

Hence The cochlea amplifies sound vibrations.

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Answer:

Metal

Explanation:

If a material is a good conductor of electricity, it is a metal, therefore the correct answer is option A.

The elements of the periodic tables that behave as metal, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.

Metals are very good conductors of heat and electricity while on the other hand nonmetals are very poor conductors of heat and electricity.

Metalloids are semiconducting materials that behave as the intermediate behavior between metal and nonmetal.

Thus, If a material is a good conductor of electricity, it is a metal, therefore the correct answer is option A.

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Orbittal is referred to the region around the nucleus occupied by the electrons.

This can be defined as a small, dense region consisting of protons and neutrons and is usually located at the center of an atom.

The electrons are present around the nucleus in a region which is referred to as orbittal and are actively involved in  chemical reactions.

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The examples of kinetic energy is ceiling fan and washing machine.

The examples of potential energy is stretched rubber band and electric battery.

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.

The gravitational potential energy of an item, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are examples of common types of potential energy.

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The correct answer is D. The force between the two charges will be 4 times as strong if the distance is divided by 2.

According to Coulomb's Law, the electric force (F) between two point charges is directly proportional to the product of the magnitudes of the charges (q1 and q2) and inversely proportional to the square of the distance (r) between them. Mathematically, this is expressed as:

[tex]\[ F = k \frac{|q_1 q_2|}{r^2} \][/tex]

where [tex]\( k \)[/tex] is Coulomb's constant ([tex]\( k = 8.988 \times 10^9 \, \text{N m}^2/\text{C}^2 \)[/tex]).

If the distance [tex]\( r \)[/tex] is divided by 2, the new distance becomes [tex]\( r' = \frac{r}{2} \)[/tex]. The new force [tex]\( F' \)[/tex] can be calculated by substituting [tex]\( r' \)[/tex] into Coulomb's Law:

[tex]\[ F' = k \frac{|q_1 q_2|}{(r')^2} = k \frac{|q_1 q_2|}{\left(\frac{r}{2}\right)^2} = k \frac{|q_1 q_2|}{\frac{r^2}{4}} = k \frac{4 |q_1 q_2|}{r^2} = 4 \left(k \frac{|q_1 q_2|}{r^2}\right) \][/tex]

[tex]\[ F' = 4F \][/tex]

Thus, the force between the two charges is 4 times stronger when the distance between them is halved. This is because the force is inversely proportional to the square of the distance, so reducing the distance by a factor of 2 results in a force that is [tex]\( 2^2 = 4 \)[/tex] times stronger.

Explanation:

1. Mechanical advantage of a pulley system, m = 2

Mechanical advantage of a machine is defined as the ratio of load to the effort force i.e.

[tex]m=\dfrac{F_L}{F_E}[/tex]

Here, [tex]F_L=2000\ lb[/tex]

[tex]F_E=\dfrac{F_L}{m}[/tex]

[tex]F_E=\dfrac{2000\ lb}{2}[/tex]

[tex]F_E=1000\ lb[/tex]

Hence, 1000 lb effort will be needed to move the car.

2. Mechanical advantage of a pulley system, m = 2,000,000

Value of load, [tex]F_L=2000\ lb[/tex]

Mechanical advantage, [tex]m=\dfrac{F_L}{F_E}[/tex]

[tex]F_E=\dfrac{F_L}{m}[/tex]

[tex]F_E=\dfrac{2000\ lb}{2000000}[/tex]

[tex]F_E=0.001\ lb[/tex]

Hence, 0.001 lb effort would be needed to move the car.

Answer:

to absorb heat flow from air molecules circuling around the refrigerant tubing

Explanation:

I know this is correct because I just had this question and this was the correct answer.

Here we have to calculate the pressure difference between two ends of the tube.

The diametre of tube [d] =1.90 mm

we know that  1 mm=[tex]10^{-3}[/tex]

The radius of tube [r]=0.95 mm i.e 0.00095 m

The length of the tube [l]=9.40 cm i.e 0.0940 m

The coefficient of visocity of the oil [tex][\eta][/tex] =0.20 pa.s

The rate of flow of oil [tex][\frac{dv}{dt} ]=6.4mL/min[/tex]

we know that 1 mL=[tex]10^{-3} L=10^{-6}m^{3}[/tex]  [1L=[tex]10^{-3} m^{3} ][/tex]

     Hence 6.4mL/m^3= [tex]1.067*10^{-7}[/tex] m^3/s

we know that [tex]\frac{dv}{dt} =\frac{\pi pr^4}{8\eta l}[/tex]

Hence [tex]p=\frac{dv}{dt} *8\eta l*\frac{1}{\pi r^4}[/tex]

        ⇒ [tex]p=1.067*10^{-7} *8*0.20*0.0940 *\frac{1}{ 3.14*[0.00095]^4}[/tex] pa

        ⇒ P=6.274630973*[tex]10^{3}[/tex] pa

Answer:

If the resistance in both resistors is doubled, then voltage gets doubled.

Explanation:

It is given that, A circuit consists of a battery and two resistors connected in parallel.

In parallel combination of resistors the potential difference remains the same while the current divides. The equivalent resistance is given by :

[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}[/tex]      

Initial condition, Let R₁ = R₂ = R

So, [tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R}+\dfrac{1}{R}[/tex]

[tex]{R_{eq}=\dfrac{R}{2}[/tex]  

Using Ohm's law,          

[tex]V=IR_{eq}=\dfrac{IR}{2}[/tex]...............(1)

Final condition, If the resistance in both resistors is doubled, and the current is kept constant.

So, [tex]\dfrac{1}{R'_{eq}}=\dfrac{1}{2R}+\dfrac{1}{2R}[/tex]      

[tex]{R'_{eq}=R[/tex]  

Voltage, [tex]V'=IR'_{eq}=IR[/tex]............(2)

From equation (1) and (2),

[tex]V'=2V[/tex]

So, the new voltage gets doubled. Hence, this is the required solution.    

The image distance and magnification is mathematically given as

Question Parameter(s):

An object is placed 20.0 cm from the front of

a converging lens of focal length 10.0 cm.

Generally, the equation for the lens equation   is mathematically given as

1 / i + 1 / o = 1 / f

Therefore

i = o f / (o - f)

i1 = 30 * 15.2 / (30 - 15.2)

i1= 30.8 cm

Therefore

i2 = 9.4 * 15.2 / (9.4 - 15.2)

i2= - 24.6 cm

In conclusion, magnification

M = m1 * m2

M= (-30.8 / 30) * (24.6 / 9.4)

M= -2.69

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Answer: Total Force = [tex]9.56*10^{17}[/tex]

Explanation:

Line points are:  Sun - Venus - Earth - Jupiter - Saturn

Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This means:

[tex]F=G\frac{m_{1} m_{2}}{r^{2} }[/tex]

Where,

G is the gravitational constant,

m1 and m2 are the masses of the objects,

and r is the distance between the centers of their masses.

So, if G value is [tex]6.674*10^{-11}  [\frac{m^{3}}{kg*s^{2}}][/tex], then we replace the equation with the corresponding values:

[tex]F=6.674*10^{-11} (-\frac{0.815ME^{2}}{(4.2*10^{10})^{2}} + \frac{318ME^{2}}{(6.28*10^{11})^{2}} + \frac{95.1ME^{2}}{(1.28*10^{12})^{2}})[/tex]

To get the distances we subtract the distances between the sun and earth and the distances between the other planets and the sun.

The answer is : the complete cycle of venus' phases. This is the observation of Galileo that refuted ptolemy's epicycles. . Using his telescope, Galileo found that Venus went through phases, just like our Moon. But, the nature of these phases could only be explained by Venus going around the Sun, not the Earth.

Galileo's observations that refuted Ptolemy's epicycles were the complete cycle of Venus' phases and the revolution of Jupiter's moons. These observations showed that these bodies were orbiting the Sun and Jupiter respectively, not the Earth as Ptolemy's model suggested.

The observation Galileo made that refuted Ptolemy's epicycles was the complete cycle of Venus' phases. Ptolemy's model suggested that all planets revolved in small circles, or 'epicycles', around a point that in turn orbited Earth. However, Galileo's observation showed that Venus goes through a set of phases similar to the Moon's, which could only occur if Venus orbits the Sun, not Earth. This discovery was incompatible with Ptolemy's model which largely placed Earth as the center of the universe. Galileo's discovery of the revolution of Jupiter's moons around it, instead of Earth, also offered further proof against Ptolemy's model.

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The statement which best describes how heat flows is that the heat generally flows from a warmer object to a colder object. Therefore, the correct option is A.

The mechanism of heat flow significantly describes the transfer of heat energy or enthalpy from one object to another. It is transferred through the process of conduction, convection, and radiation.

The object that is warmer in appearance may accumulate heat in enough amounts. This leads to an increase in its temperature and energy, While the mechanism of heat transfer generally initiates this warmer object to a colder object by conduction.

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a. The puck's average acceleration is equal to -1.2 [tex]m/s^2[/tex].

b. The coefficient of kinetic friction between the puck and the ice is 0.122.

Given the following data:

a. To find the puck's average acceleration:

Mathematically, acceleration is given by the formula;

[tex]Acceleration = \frac{V_f\; - \;V_i}{t}[/tex]

Where:  

[tex]Acceleration = \frac{6\; - \;12}{5}\\\\Acceleration = \frac{-6}{5}[/tex]

Average acceleration = -1.2 [tex]m/s^2[/tex]

b. To find the coefficient of kinetic friction between the puck and the ice:

The frictional force acting between the puck and the ice is given by the formula;

[tex]F = uN = -umg\\\\F = -umg\\\\\frac{F}{m} = -ug[/tex]....equation 1.

But, [tex]a = \frac{F}{m}[/tex]   ....equation 2.

We know that acceleration due to gravity (g) of an object is equal to 9.8 meter per seconds square.

[tex]a = -ug\\\\u = \frac{-a}{g}\\\\u = \frac{-(-1.2)}{9.8} \\\\u = \frac{1.2}{9.8}[/tex]

Coefficient of kinetic friction, u = 0.122

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Answer: Option (a) is the correct answer.

Explanation:

Momentum is defined as the ability or tendency of an object to continue moving.

Also, momentum is the product of mass and velocity. It can be shown as follows.

                      p = m × v

where,     p = momentum

               m = mass

               v = velocity

Thus, we can conclude that out of the given options, the formula p = mv show the relationship between momentum, mass, and velocity.

Answer:

A,D,F

Explanation:

(-6C₆) / x⁷ newton; it is an attractive force.  

Given:

The potential energy of a pair of hydrogen atoms separated by a large distance x is given by [tex]\boxed{ \ U(x) = - \frac{C_6}{x^6} \ }[/tex], where C₆ is a positive constant.  

Question:

The Process:

Let us rewrite the potential energy of the pair of the hydrogen atom:

[tex]\boxed{ \ U(x) = - \frac{C_6}{x^6} \ }[/tex]

The component of a conservative force in a particular direction, equals the negative of the derivative of the corresponding potential energy, properly concerning a displacement in that direction.

For one-dimensional motion, say along the x-axis, the relationship between force and potential energy is as follows:

[tex]\boxed{ \ \overrightarrow{F} = F_x \hat{i} = - \frac{\delta U}{\delta x} \hat{i} \ }[/tex]

Let us determine the force.

[tex]\boxed{ \ F_x \hat{i} = - \frac{\delta}{\delta x} \Big( - \frac{C_6}{x^6} \Big) \ \hat{i} \ }[/tex]

[tex]\boxed{ \ F_x \hat{i} = - (- C_6) \frac{\delta}{\delta x} \Big( \frac{1}{x^6} \Big) \ \hat{i} \ }[/tex]

[tex]\boxed{ \ F_x \hat{i} = C_6 \frac{\delta}{\delta x} (x^{-6}) \ \hat{i}} \ }[/tex]

[tex]\boxed{ \ F_x \hat{i} = (C_6)(-6)x^{-7} \ \hat{i} \ }[/tex]

Thus, we get: [tex]\boxed{\boxed{ \ F_x = - \frac{6C_6}{x^7} \ \hat{i} \ }}[/tex]

From the data problem above, we know that C₆ is a positive constant. Hence, Fₓ is positive when x is negative and vice versa. Thus Fₓ is always directed toward the origin. Besides, a negative sign means that an attractive force occurs.

In essence, the directions are toward the origin, since this is the potential energy for a restoring force.

_ _ _ _ _ _ _ _ _ _

Notes:

We know that the difference of potential energy from point 1 to point 2 as the negative of the work done:  

[tex]\boxed{ \ \Delta U_{12} = U_2 - U_1 = - W_{12} \ }[/tex]

The work done by the given force as the particle moves from coordinate x to (x + d x) in one dimension is  

[tex]\boxed{ \ dW = \overrightarrow{F} \cdot d \vec{r} \ } \rightarrow \boxed{ \ \overrightarrow{F} = \frac{dW}{d \vec{r}} \ }[/tex]

Therefore, for motion along a straight line, a conservative force  is the negative derivative of its associated potential energy function, i.e.,

[tex]\boxed{ \ \overrightarrow{F} = F_x \hat{i} = - \frac{\delta U}{\delta x} \hat{i} \ }[/tex]

_ _ _ _ _ _ _ _ _ _

Conservative force : force that does work independent of path.

To lift a 12 kg pail at a constant speed over a distance of 10 meters in 5 seconds, Jill requires a power of 235.44 W. This is calculated using the weight of the pail, the distance lifted, and the time taken.

To determine how much power is required to lift a 12 kg pail straight up at a constant speed over a distance of 10 meters in 5 seconds, we can follow these steps:

1. Calculate the force needed: Since the pail is moving at a constant speed, the force needed to lift it is equal to its weight.

The weight (force due to gravity) is given by:

2. Calculate the work done: Work done in lifting the pail can be calculated as:

3. Calculate the power required: Power is the rate at which work is done. It can be calculated as:

Therefore, the power required to lift the pail at a constant speed over the specified distance in the given time is 235.44 W.

The force constant of the spring is roughly0.171 kN/ m. The contraction  needed for the spring's implicit energy to equal0.0078 J is roughly0.381 cm.

To calculate the force constant of the spring( k), we use the formula for the implicit energy of a compressed or stretched spring, which is U = 1/2 k x2. Rearranging this formula to  break for k gives k =  2U/ x2. Substituting U = 0.0025 J and x = 0.54 cm( or0.0054 m) into the formula yields k = ( 2  J)/(0.0054 m) 2. Calculating this, we find k = 171.296 N/ m or  roughly0.171 kN/m.

For part( b), when seeking the  contraction  needed to produce a implicit energy of0.0078 J, we start from the formula U = 1/2 k x2 again. fitting the implicit energy U = 0.0078 J and the  preliminarily calculated force constant k = 171.296 N/ m into the formula and  working for x delivers x = sqrt(2 extasteriskcentered0.0078 J)/171.296 N/ m). This results in an x value of roughly0.00381 m or0.381 cm.