Answer:
The answer on edgenuity for dividing fractions is -3 on the assignment good luck!
Step-by-step explanation:
The heights of fully grown English oak (also known as Brown oak) trees are normally distributed with a mean of 95 feet and a standard deviation of 10 feet. What proportion of fully grown English oak trees are taller than 110 feet?
Final answer:
Using the z-score calculation and the standard normal distribution, approximately 6.68% of fully grown English oak trees are taller than 110 feet.
Explanation:
To find the proportion of fully grown English oak trees taller than 110 feet, given that the heights are normally distributed with a mean of 95 feet and a standard deviation of 10 feet, we first calculate the z-score for a height of 110 feet. The z-score is calculated using the formula: z = (X - μ) / σ, where X is the value of interest (110 feet), μ is the mean (95 feet), and σ is the standard deviation (10 feet).
By substituting the given values: z = (110 - 95) / 10 = 1.5. This z-score represents the number of standard deviations 110 feet is above the mean. To find the proportion of trees taller than 110 feet, we consult the standard normal distribution table or use a calculator that provides the area to the right of the z-score, which corresponds to the proportion we seek.
The standard normal distribution table or a calculator shows that the proportion of the area under the curve to the right of a z-score of 1.5 is approximately 0.0668.
Thus, about 6.68% of fully grown English oak trees are taller than 110 feet.
A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 20 miles per gallon of gas. During one particular week, the two cars went a combined total of 2025 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of the two cars that week?
bonnie had 6 bags of 6 gel pens. she wanted to give the same number of gel pens to 9 friends. how many gel pens did each friend get?
In a bag of 25 m&ms, each piece is equally likely to be red, green, orange, blue, or brown, independent of the color of any other piece. find the the pmf of r, the number of red pieces. what is the probability a bag has no red m&ms?
To find the probability mass function (pmf) of the number of red M&Ms in a bag, use the binomial distribution formula. The probability a bag has no red M&Ms is calculated by raising (4/5) to the 25th power, as per the binomial distribution with a success probability of 1/5 and 25 trials.
Explanation:The question involves finding the probability mass function (pmf) of the number of red M&Ms in a bag of 25 M&Ms where each M&M has an equal chance of being one of five colors.
To determine the pmf of the number of red M&Ms, which we'll call r, we can use the binomial distribution, since each M&M is an independent Bernoulli trial with two outcomes (red or not red), and each M&M has the same probability of being red.
The probability of getting a red M&M is 1/5, so the pmf of r for k red M&Ms in a bag of 25 is given by P(r=k) = (25 choose k) × (1/5)^k × (4/5)^(25-k).
To find the probability that a bag has no red M&Ms, we set k to 0 in the pmf formula: P(r=0) = (25 choose 0) × (1/5)⁰ × (4/5)²⁵. This simplifies to (4/5)²⁵, since any number to the zero power is 1 and (25 choose 0) is also 1.
Is the figure on the right congruent to the sample figure? Explain.
What is the volume of the figure below if a = 3.9 units, b = 5.7 units, and c = 3 units?
A.157.95 cubic units
B.351.351 cubic units
C.124.605 cubic units
D.113.49 cubic units
Please help and explain questions 20-22
Find the orbital period (in years) of an asteroid whose average distance from the sun is 10 au.
The orbital period (in years) of an asteroid whose average distance from the sun is 10 AU is 212314723 years.
What is Orbital period ?
Orbital period of a body is the the time taken by a body to cover one circular path around the central object under whose influence it is following circular path.
Given is a asteroid moving around the sun.
Mean distance from the Sun [x] = 10 AU = 1.496 x 10¹² m.
Assume that the time period of the asteroid is T.
The formula to calculate the orbital period around the sun is -
T²/ R³ = 4π²/GM[s]
Where -
R is the mean distance from sun.
G is the universal Gravitation constant.
M[s] is the mass of Sun.
Substituting the values, we get -
T² = (1.496 x 10¹² x 4 x 3.14 x 3.14)/(6.673 x 10⁻¹¹ x 1.98 x 10³⁰)
T² = (59 x 10¹²)/(13.2 x 10⁻¹⁹)
T² = 4.45 x 10 x 10³⁰
T² = 44.5 x 10³⁰
T = √44.5 x √10³⁰
T = 6.7 x 10¹⁵ seconds
In years, the time period will be -
T = 212314723 years (approx.)
Therefore, the orbital period (in years) of an asteroid whose average distance from the sun is 10 AU is 212314723 years.
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If a particular utility burned 5.40 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide was emitted?
Evaluate these quantities.
a.−17 mod 2
b.144 mod 7
c.−101 mod 13
d.199 mod 19
The modulo operator determines the remainder of a division operation. For the given expressions, the results are a. 1, b. 4, c. 2, d. 6
Explanation:The question is asking to evaluate several expressions using the modulo operation. Modulo is a mathematical operation that finds the remainder or signed remainder of a division, after one number is divided by another (called the modulus). Here's how we can solve each:
a. −17 mod 2 = 1 (Because when -17 is divided by 2, the remainder is 1) b. 144 mod 7 = 4 (Because when 144 is divided by 7, the remainder is 4) c. −101 mod 13 = 2 (Because when -101 is divided by 13, the remainder is 2) d. 199 mod 19 = 6 (Because when 199 is divided by 19, remainder is 6)Learn more about Modulo Operation here:https://brainly.com/question/36617304
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An American car company has designed a new high fuel efficiency vehicle that is rated at 55 miles per gallon. The company plans to export the car to Europe and must advertise the fuel efficiency in SI units. What is the fuel usage rate in kilometers per liter?
A basketball player makes 40% of his shots from the free throw line. suppose that each of his shots can be considered independent and that he throws 3 shots. let x = the number of shots that he makes. what is the probability that he makes 2 shots or less?
Using the binomial distribution, it is found that there is a 0.936 = 93.6% probability that he makes 2 shots or less.
-------------------
For each throw, there are only two possible outcomes. Either the player makes it, or he misses it. The probability of making a throw is independent of any other throw, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.In this question:
The player makes 40% of the shots, thus [tex]p = 0.4[/tex]3 shots, thus [tex]n = 3[/tex]The probability of making 2 or less is the probability that he does not make all of them, that is:
[tex]P(X < 3) = 1 - P(X = 3)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{3,3}.(0.4)^{3}.(0.6)^{0} = 0.064[/tex]
[tex]P(X < 3) = 1 - P(X = 3) = 1 - 0.064 = 0.936[/tex]
0.936 = 93.6% probability that he makes 2 shots or less.
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What is the solution to the system of equations graphed below
Answer:
Option C is correct
(1, 5)
Step-by-step explanation:
A system of equations contains two or more than two linear equations that divide two or more unknowns.
To find a solution for the system of equations,
we must find a value from the graph that is true for all equations in the given system.
We know that:
If the graphs of the equations intersect,
then there is one solution that is true for both equations.
Given the graph.
There are two lines
Equation of Blue line : y = -x+6
Equation of Red line = y = 2x+3
Since, the graph of two lines y = -x+6 and y = 2x+3 intersects which means there is one solution that satisfies the both equation.
Therefore, the solution to the system of equations graphed is, (1, 5)
Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.
By applying Fermat's Little Theorem, we can find the least positive residue of [tex]2^{1000000[/tex] modulo 17. Using the repeated squaring method, we calculate that [tex]2^{16[/tex] is congruent to 1 modulo 17. Therefore, [tex]2^{1000000[/tex] is also congruent to 1 modulo 17.
Fermat's Little Theorem states that if p is a prime number and a is any positive integer that is not divisible by p, then a raised to the power of p-1 is congruent to 1 modulo p. In this case, we need to find the least positive residue of 2 raised to the power of 1000000 modulo 17.
First, we need to find the value of 2 raised to the power of 16 modulo 17, since 17 is a prime number. Using the repeated squaring method, we can calculate:
[tex]2^2[/tex] = 4 (mod 17)
[tex]2^4[/tex] = [tex](2^2)^2[/tex] = [tex]4^2[/tex] = 16 (mod 17)
[tex]2^8[/tex] = [tex](2^4)^2[/tex] = [tex]16^2[/tex] = 1 (mod 17)
[tex]2^{16[/tex] = [tex](2^8)^2[/tex] = [tex]1^2[/tex] = 1 (mod 17)
Now, we can find the value of [tex]2^{1000000[/tex] modulo 17 using the fact that [tex]2^{16[/tex] is congruent to 1 modulo 17:
[tex]2^{1000000[/tex] = [tex](2^{16})^{62500[/tex] x [tex]2^0[/tex] = [tex]1^{62500[/tex] x 1 = 1 (mod 17)
Therefore, the least positive residue of [tex]2^{1000000[/tex] modulo 17 is 1.
Help with this math question
The given inequality is:
|-8x+24| \leq 16
This inequality can be divided in two parts as:
a) -16 \leq -8x +24
b) -8x + 24 \leq 16
Solving part a:
-16 \leq -8x+24 \\ \\ -40 \leq -8x \\ \\ 5 \geq x \\ or \\ x \leq 5
Solving part b:
-8x+24 \leq 16 \\ \\ -8x \leq -8 \\ \\ x \geq 1
Therefore, the solution to the given inequality is x \leq 5 and x \geq 1. Combining both the ranges we get the solution: 1 \leq x \leq 5.
In interval notation, this solution can be expressed as [1,5
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write the equation of the line with the following chracteristics
perpendicular to y=1/2x+3 through (9,1)
5(×-4)+3×-9×=6-(2×+5)+8×
Find the sum of the first 30 terms of the sequence. a_(n)=4n+1
based only on the information given in the diagram, which congruence theorems or postulates could be given as reasons why ΔLMN ≈ΔOPQ?
Check all that apply.
A. LL
B. LA
C. SAS
D. HL
E. ASA
F. AAS
HL congruence theorems or postulates used to prove ΔLMN ≈ΔOPQ.
What is Congruency?Congruent figures have sides that are the same length and angles that are the same measurement. In other words, congruent figures are those in which one figure superimposes another.
If two line segments have the same length, they are said to be congruent. If two angles have the same measure, they are said to be congruent. If the matching sides and angles of two triangles are equal, they are said to be congruent.
We have two Triangles as ΔLMN and ΔOPQ
As, per the figure both triangles are Right angles Triangle.
Also, LM = OP
MN = PQ
LN = OQ
and, the hypotenuse of both triangles also Equal.
Thus, both triangle are Congruent using HL theorem.
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What is the area of this triangle? A=bh2
A 24 in²
B 30 in²
C 48 in²
D 96 in²
Answer:
a 24
Step-by-step explanation:
On average how many words can 400 turtles type in 400 minutes?
Steven has 14 steel balls of equal weight. If he puts 9 of them in one pan of a pan balance and the rest along with a weight of 20 grams in the other pan, the pans balance each other. What is the weight of one steel ball?
Answer:
Step-by-step explanation:
A certain car costs $11,595 before taxes are added. Taxes are $860 and license tags cost $95. What is the overall tax rate (to the nearest tenth)?
0.8%
7.4%
8.2%
12.1%
Answer:
8.2%
Step-by-step explanation:
o-ware
14m+m+17m−9m if m=30
Answer:
690
Step-by-step explanation:
Put 30 where m is in the expression and do the arithmetic. Or, simpify the expression first, then do the same.
14·30 +30 +17·30 -9·30 = 420 +30 +510 -270 = 690
Simplifying first, you have ...
14m +m +17m -9m = m(14 +1 +17 -9) = 23m
23·30 = 690
To solve the equation 14m + m + 17m - 9m when m=30, substitute the value of m in the equation and follow order or operations. The result is 960.
Explanation:To solve for the given problem involving the variable m, simply substitute the value of m into the equation. The equation given is 14m + m + 17m - 9m. Substituting 30 for m in the equation gives us: 14(30) + 30 + 17(30) - 9(30). To solve this, use the order of operations principle, which states that multiplication and division should be performed before addition and subtraction.
First, perform the multiplication: 420 + 30 + 510 - 270. Next, add and subtract from left to right: 960. Thus, if m = 30, then 14m + m + 17m - 9m = 960.
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Which is the next term in this pattern ?
January, February, April, July,___
-August
-November
-October
-December
are you able to classify polygons by their sides and angles
Polygons can be classified by their sides and angles using formulas and definitions like regular polygons with equal sides and angles.
Polygons can be classified by their sides and angles. A regular polygon has equal sides and equal angles, such as an equilateral triangle or a square. The sum of interior angles in any polygon can be calculated using the formula 180 * (n - 2) degrees where n is the number of sides.
ANSWER FAST 20 PTS
What is the measure of T?
ABCD RSTU
125°
110°
100°
60°
Answer:
100
Step-by-step explanation:
If a ball is dropped near the surface of the earth, then the distance it falls is directly proportional to the square of the time it has fallen. A ball is dropped over the edge of a vertical cliff and falls 39.2 meters in two seconds. Determine the distance (in meters) the ball would have dropped in 3.5 seconds.
what is a solution to the equation 6t=114
How can I solve this please:
Solve for q: (4q - 6n)/(3m) = f
General Idea:
Solving for a variable means getting that variable by itself by UNDOING whatever is done to it. We need to perform reverse operation to UNDO.
Applying the concept:
[tex] \frac{4q-6n}{3m}=f\\ \\ To \; undo \; 3m\; in\; the \; denominator \; 3m, \; MULTIPLY \; 3m\; on\; both\; sides [/tex]
[tex] 3m \times \frac{4q-6n}{3m}=f \times 3m\\ \\ 4q-6n=3mf\\Add \; 6n \; both\; sides\\ \\ 4q-6n+6n=3mf+6n\\ Combine \; like\; terms\\ \\ 4q=3mf+6n\\Divide \; 4\; on\; both\; sides\\ \\ \frac{4q}{4} =\frac{3mf+6n}{4} \\ Simplify\; fraction\; in\; left\; sides\\ \\ q=\frac{3mf+6n}{4} [/tex]
Conclusion:
[tex] Solving \; the \; equation \; \frac{4q-6n}{3m}=f \; for q, \; we get...\\ \\q=\frac{3mf+6n}{4} [/tex]