An eagle can fly at a speed of 50 mph and a starling can fly at 78 mph. How far will the starling fly in the time it takes the eagle to fly 125 miles?
PLZ HELP ASAP!!!!!!
20 POINTS!
Answer:
195 miles
Step-by-step explanation:
50*x=125
x=2.5
2.5*78=195miles
Runners in a long distance race start out going 5 kilometers south and then head west for the remainder of the race. The finish line is 13 kilometers from the starting line. How far did the runners travel?
Given that tan^2 e= 3/8 what is the value of sec e? A. +√8/3 B.+ √11/8 C. 11/8 D. 8/3
ANSWER
[tex]{ \sec}(e) = \pm \: \sqrt{\frac{11}{8} } [/tex]
EXPLANATION
We use the Pythagorean Identity,
[tex] { \sec}^{2} (e) = 1 + { \tan}^{2} (e)[/tex]
It was given that,
[tex] { \tan}^{2} (e) = \frac{3}{8} [/tex]
We substitute the values into the identity to obtain,
[tex] { \sec}^{2} (e) = 1 + \frac{3}{8} [/tex]
[tex]{ \sec}^{2} (e) = \frac{11}{8} [/tex]
We take square root of both sides to get,
[tex]{ \sec}(e) = \pm \: \sqrt{\frac{11}{8} } [/tex]
Answer:
sec e = √(11/8) ⇒ answer B
Step-by-step explanation:
* Lets revise some identities in trigonometry
# sin²x + cos²x = 1
- Divide both sides by cos²x
∴ sin²x/cos²x + cos²x/cos²x = 1/cos²x
∵ sinx/cosx = tanx
∴ sin²x/cos²x = tan²x
∵ cos²x/cos²x = 1
∵ 1/cosx = secx
∴ 1/cos²x = sec²x
* Now lets write the new identity
# tan²x + 1 = sec²x
- Let x = e
∴ tan²e + 1 = sec²e
- Substitute the value of tan²e in the identity
∵ tan²e = 3/8
∴ 3/8 + 1 = sec²e
- Change the 1 to the fraction 8/8
∴ 3/8 + 8/8 = sec²e ⇒ add the fractions
∴ 11/8 = sec²e
- Take square root for the two sides to find sec e
∴ sec e = √(11/8)
∴ The answer is B
For the data set below, calculate the standard deviation to the nearest hundredth decimal place. 27 38 47 42 33 56 37 57 38 52
Final answer:
The standard deviation of the given data set is 10.03, and the value that is one standard deviation below the mean is 32.67. Calculations involve finding the mean, computing squared deviations, calculating the sum of squared deviations, finding the variance, and taking the square root of the variance.
Explanation:
The mean is calculated as: (27 + 38 + 47 + 42 + 33 + 56 + 37 + 57 + 38 + 52) ÷ 10 = 427 ÷ 10 = 42.7.
Now we calculate each deviation from the mean, square it, and sum them:
(27 - 42.7)² = 246.49
(38 - 42.7)² = 22.09
(47 - 42.7)² = 18.49
(42 - 42.7)² = 0.49
(33 - 42.7)² = 94.09
(56 - 42.7)² = 176.89
(37 - 42.7)² = 32.49
(57 - 42.7)² = 204.49
(38 - 42.7)² = 22.09
(52 - 42.7)² = 86.49
A sum of squared deviations = 904.61.
The variance is 904.61 ÷ (10-1) = 100.51.
The standard deviation is the square root of the variance,
which is √100.51 equal to approximately 10.03.
To find the value that is one standard deviation below the mean, we subtract one standard deviation from the mean: 42.7 - 10.03 = 32.67.
Therefore, the standard deviation to the nearest hundredth is 10.03, and the value that is one standard deviation below the mean is approximately 32.67.
Design amanda wants to make this design of circles inside an equilateral triangle.
a. what is the radius of the large circle to the nearest hundredth of an inch?
b. what are the radii of the smaller circles to the nearest hundredth of an inc
Answer:
Using theorem
AE=8.66
Thus radius of large circle is one third of equilateral triangle altitude.
Radius of larger circle=2.9 inch
And radius of inner circle will be 0.96 inch
simplify 3.2-5.1n-3n+5
a dress was reduced from $100 to $85. express the discount as a % of the original price
will give braniliest....... Mom put plums and apples onto a plate. The ratio of the number of plums to the number of apples was 3:2. How many fruit did mom put on the plate, if after Ed took 6 there number of plums on the plate became the same as the number of apples?
Use parametric equations of the ellipse, ???? 2 16 + ???? 2 9 = 1, to find the area that it encloses in the first quadrant.
Make up an equation of the form y = kx +b, the graph of which passes through the following points: C (–19, 31) and D (1, –9)
what is 12.81 repeated rounded to the nearest hundredth
Construct a 90% confidence interval for the population mean, µ. assume the population has a normal distribution. a sample of 15 randomly selected math majors has a grade point average of 2.86 with a standard deviation of 0.78. round to the nearest hundredth
The 90% confidence interval for the population mean [tex]\( \mu \)[/tex] is approximately (2.50, 3.21) .
To construct a 90% confidence interval for the population mean [tex]\( \mu \)[/tex], we can use the formula:
[tex]\[ \text{Confidence Interval} = \bar{x} \pm \left( \text{Critical Value} \times \frac{s}{\sqrt{n}} \right) \][/tex]
where:
- [tex]\( \bar{x} \)[/tex] is the sample mean,
- s is the sample standard deviation,
- n is the sample size, and
- the critical value corresponds to the desired confidence level and degrees of freedom.
Given:
- Sample mean [tex]\( \bar{x} = 2.86 \),[/tex]
- Sample standard deviation s=0.78
- Sample size n=15
- Confidence level = 90%.
First, we need to find the critical value corresponding to a 90% confidence level and 14 degrees of freedom (since ( n - 1 = 15 - 1 = 14 )). We can find this value using a t-distribution table or a statistical calculator. For a 90% confidence level and 14 degrees of freedom, the critical value is approximately 1.7613.
Now, let's calculate the confidence interval:
[tex]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times \frac{0.78}{\sqrt{15}} \right) \]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times \frac{0.78}{\sqrt{15}} \right) \]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times \frac{0.78}{3.87298} \right) \]\[ \text{Confidence Interval} = 2.86 \pm \left( 1.7613 \times 0.20172 \right) \]\[ \text{Confidence Interval} = 2.86 \pm 0.35587 \][/tex]
Lower Limit:
[tex]\[ 2.86 - 0.35587 \approx 2.5041 \][/tex]
Upper Limit:
[tex]\[ 2.86 + 0.35587 \approx 3.2141 \][/tex]
hey can you please help me posted picture of question
1. Clyde has the chance to buy a piece of old Pennsylvania Dutch pottery that he thinks he can resell for $500. If Clyde needs a 125% markup on cost, what price should he pay?
2. Orchard Supply sells lawn fertilizer at a price of $12.50 per bag. If the markup is 25% of cost, find the cost.
The scatter plot shows the relationship between the number of car accidents in a month and the number of drivers attending a program on distracted driving. The equation represents the linear model for this data. y=−0.0067x+17 What does the number -0.0067 in the equation mean in this context? There were 0.67 accidents per month. The number of accidents was reduced by 0.67 per month for every additional 100 drivers in the program. The number of accidents was reduced by 0.67 per month for every additional driver in the program. The number of accidents increased by 0.67 per month for every additional 100 drivers in the program. The number of accidents was reduced by 0.67 per month every month.
Answer:
the answer is A
What is the first step in solving ln(x − 1) = ln6 − lnx for x?
Answer:
[tex]ln(x - 1) = ln(\frac{6}{x})[/tex]
Step-by-step explanation:
[tex]ln(x - 1) = ln6 - lnx[/tex]
To solve for x we need to simplify the ln
To simplify logarithmic function we use log property
[tex]ln(a) - ln(b) = ln(\frac{a}{b})[/tex]
we apply the same property on the right hand side of the given equation
[tex]ln(x - 1) = ln6 - lnx[/tex]
[tex]ln(6) - ln(x) = ln(\frac{6}{x})[/tex]
[tex]ln(x - 1) = ln(\frac{6}{x})[/tex]
This is the first step in solving the given equation
Solve the equation <(a-5)-5=3
the square in this figure has a side length of 14 inches. the radius of the quarter circle is 7 inches. what is the estimate area
The area of the shaded region is 42.14 square inches.
How the area of the shaded region is determined:
We are given a square with side lengths of 14 inches, and each corner of the square has a quarter circle with a radius of 7 inches. We need to find the area of the shaded region, which is the area of the square minus the area of the quarter circles.
To calculate the area of the figure, we need to consider both the square and the quarter circles.
1. Calculate the area of the square:
The square has a side length of 14 inches.
Area of the square = [tex]side^2[/tex] = [tex]14^2[/tex] = 196 square inches
2. Calculate the area of the quarter circles:
The quarter circle has a radius of 7 inches.
The area of a full circle is given by:
Area of the circle = [tex]\pi r^2[/tex]
Area of the quarter circle = 4/4 x [tex]\pi r^2[/tex]
= 1 x 3.14 x [tex]7^2[/tex]
= 153.86 square inches
Therefore, the area of the shaded region = Area of the square - Area of the quarter circles:
= 196 - 153.86
= 42.14 square inches
Complete Question:
The square in the figure has a side length of 14 inches. The radius of the each quarter circle is 7 inches. What is the area of the shaded region?
estimate the difference between 9,030 and 738
Joey got a 25% raise on his salary. if his original salary was 1,200, how much was it after the raise was implemented?
Which pair of triangles can be proven congruent by using the HL theorem?
What is the value of x in the following equation 1/5x=5^8
A)-8 B) 8 C)40 D)-40
6.
Valdez Construction signed a note with a payment of $5,200 per quarter for 5 years.
Find the amount they must set aside today to satisfy this capital requirement in an account earning 8% compounded quarterly.
$30,506.32
$126,346.32
$51,054.38
$85,027.44
Suppose you want to transform the graph of the function y=tan(x+pi/4)-1 into the graph of the function y=-tan(x+pi/2)+1
Answer:
A) Reflect the graph of the first function across the x-axis, translate it pi/4 units to the left, and translate it 2 units up
One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number of sterile males that mate with fertile females but produce no offspring. let p represent the number of female insects in a population and s the number of sterile males introduced each generation. let r be the per capita rate of production of females by females, provided their chosen mate is not sterile. then the female population is related to time t by t = p + s p[(r − 1)p − s] dp. suppose an insect population with 10,000 females grows at a rate of r = 1.2 and 400 sterile males are added. evaluate the integral to give an equation relating the female population to time. (note that the resulting equation can't be solved explicitly for p. remember to use absolute values where appropriate.)
To be clear, the given relation between
time and female population is an integral:
[tex]t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,
dP [/tex]
Two planes are flying in opposite directions, away from each other, one with the speed of 800 km per hour and the other with the speed of 840 km per hour. How much farther from each other are the planes getting every hour?
A patient is given a 50 mg dose of medicine the medicines effectiveness decreases every hour at a constant rate of 40% what is the exponential decay function that models this scenario how much medicine will be left in the patient's system after two hours
Answer:
[tex]A=50(0.6)^x[/tex]
18 mg of medicine will be left in the patient's system after two hours.
Step-by-step explanation:
Given,
The initial quantity of the medicine, P = 50 mg,
Also, it decreases every hour at a constant rate of 40%
That is, r = 40 %,
Thus, the quantity of the medicine after x hours,
[tex]A=P(1-\frac{r}{100})^r[/tex]
[tex]=50(1-\frac{40}{100})^x[/tex]
[tex]=50(1-0.4)^x[/tex]
[tex]=50(0.6)^x[/tex]
Which is the required exponential decay function that models this scenario.
The quantity of the medicine after 2 hours,
[tex]A=50(0.6)^2=18\text{ mg}[/tex]
PLZ HELP ASAP FEATURES OF A CIRCLE FROM ITS EXPANDED EQUATION
Two friends bring hamburger meat to your cookout. One brings 2.7 pounds, and the other brings 3.54 pounds. How much hamburger meat do they bring?
Please Help!
Khalid has a game board as shown below, which is a square with 20-cm sides. The area of the largest circle is 320 square centimeters.
What is the probability of scoring 1, 3, or 5 points with one randomly thrown dart?
A. 1/2
B. 5/8
C. 3/4
D. 4/5
Answer:
Option D. 4/5
Step-by-step explanation:
we know that
The probability of scoring 1, 3, or 5 points with one randomly thrown dart is equal to divide the area of the largest circle by the area of the square game board
step 1
Find the area of the square game board
[tex]A=b^{2}[/tex]
we have
[tex]b=20\ cm[/tex]
substitute
[tex]A=20^{2}[/tex]
[tex]A=400\ cm^{2}[/tex]
step 2
Find the probability
[tex]P=320/400[/tex]
[tex]P=0.8=8/10=4/5[/tex]