The function f(x) = 2x + 26 represents the distance a flock of birds travels in in miles. The function g(x) = x − 1 represents the time the flock traveled in hours.

Solve f divided by g of 5, and interpret the answer.

Answers

Answer 1

Final answer:

The average speed of the flock of birds over 5 hours is 9 miles per hour, calculated by dividing the distance function f(x) by the time function g(x) at x equal to 5.

Explanation:

The student asked to solve f divided by g of 5 for the given functions f(x) = 2x + 26 and g(x) = x − 1. This will give us the average speed of the flock of birds over the time interval when x equals 5.

First, we substitute x with 5 in both functions:

f(5) = 2(5) + 26 = 10 + 26 = 36 miles

g(5) = 5 − 1 = 4 hours

Next, we divide the outcome of function f by the outcome of function g:

\(\frac{f(5)}{g(5)} = \frac{36}{4} = 9 \) miles per hour

This result represents the average speed of the flock of birds over the time interval when x equals 5 hours.


Related Questions

Please please help me with this!!!!!!!

Answers

Answer:

Option C

Step-by-step explanation:

As you can see in the graph the shaded region is in 1st quadrant which means that both x and y are greater than or less than equal to zero. From this statement only option A and B get eliminated. But still we will look further...

The equation of the yellow line should be determined in order to know the complete answer. If you don't know how to write equation of line in intercept form then just assume the line's equation to be :

y=mx + c    ; where m and c are constants.

Now you just need to find two points satisfying the line's equation. As you can see in the graph (2,0) and (0,-2) are the points lying on the line. Now put them in the assumed line's equation to determine the constants.

0 = m × 2 + c  .........equation (1)

-2 = m × 0 + c .........equation (2)

solving equation (2) gives c = -2

put the value of c in equation (1) then solve it to get the value of m

0 = m × 2 - 2

m=1

Therefore line's equation is y = x - 2

Since the value of y is greater than and equal to the value of y which we get from the line's equation so

y ≥ x - 2

rearrange the above inequality

x - y ≤ 2

So these three conditions are there

x ≥ 0

y ≥ 0

x - y ≤ 2

which gives the shaded region

Identify the data set that could be quadratic. HELP ASAP!!

Answers

Answer:

the 3rd one (:

Step-by-step explanation:

Answer:

First One:

x { 6, 9, 12, 15, 18 }
y { -14, -4, 8, 22, 38 }

Step-by-step explanation:

Not sure if the other guy is trolling...
The x values constantly rise by 3, so we find the y value change
The differences are 10, 12, 14, 16
If we do it again we get 2, 2, 2. So since we did the reduction 2 times, this is a quadratic function.
Why isn't "the third one"
Constant rise by 2

Change of 9, 9, 9, 9
This is one reduction, so it is not quadratic.

Abit is planning a birthday party for his granddad. He bought a cake for $18\$18$18dollar sign, 18. He also wants to buy some balloons, which are $4\$4$4dollar sign, 4 each. Abit has $35\$35$35dollar sign, 35 to spend all together. How much money will Abit have left after he buys the cake and as many balloons as possible?

Answers

Answer:

$1.00

Step-by-step explanation:

Total Budget = $35

Cake Spent = $18

Remaining Money = 35 - 18 = $17

Since, each balloon is worth $4, to find how many balloons he will get with remaining money ($17), we divide the the remaining money by price of each balloon:

17/4 = 4.25

We can't have fractional balloons, so Abit can get 4 balloons, MAXIMUM.

4 balloons cost = $4 per balloon * 4 = $16

So, from $17 if he spends $16 for balloons, he will have left:

$17 - $16 = $1.00

A 25-ft ladder leans against a building so that the angle between the ground and the ladder is 51 degrees. How high does the ladder reach up the side of the building? Please round your answer to 2 decimal places.

Answers

Answer:

19.43 ft

Step-by-step explanation:

Using SOHCAHTOA,

opposite = x

Hypothenus = 25ft

Sin α = opposite /Hypothenus

Sin 51° = x/25

x = 25(Sin51°)

x = 19.4286

x = 19.43(approximate to 2 d.p)

Use the position equation s = −16t2 + v0t + s0 where s represents the height of an object (in feet), v0 represents the initial velocity of the object (in feet per second), s0 represents the initial height of the object (in feet), and t represents the time (in seconds). A projectile is fired straight upward from ground level (s0 = 0) with an initial velocity of 128 feet per second.(a) At what instant will it be back at ground level?(b) When will the height be less than 128 feet? (Enter your answer using interval notation.) i NEED HELP WITH PART B. IT IS SUPPOSED TO BE AN INTERVAL NOTATION AND LOOK LIKE THIS [?,?) U (?,?] ex.[0,6-2 RADICAL6) U (6+2RADICAL6,12)

Answers

The projectile will be back at ground level at t = 0 (initially fired) and t = 8 seconds after being fired.

To find when the height of the projectile is less than 128 feet, we set s < 128 and solve for t using the given position equation:

[tex]\[ -16t^2 + v_0t + s_0 < 128 \][/tex]

Given:

- [tex]\( v_0 = 128 \)[/tex]  feet per second

- [tex]\( s_0 = 0 \)[/tex] (since the object is fired upward from ground level)

Substitute these values into the equation:

[tex]\[ -16t^2 + 128t < 128 \][/tex]

Now, let's solve this inequality for t. First, let's rewrite it in standard quadratic form:

[tex]\[ -16t^2 + 128t - 128 < 0 \][/tex]

Divide all terms by -16 to simplify:

[tex]\[ t^2 - 8t + 8 > 0 \][/tex]

Now, we need to find the values of t for which this inequality holds true.

To solve quadratic inequalities, we can find the roots of the corresponding quadratic equation [tex]\( t^2 - 8t + 8 = 0 \)[/tex], and then determine the intervals where the quadratic expression [tex]\( t^2 - 8t + 8 \)[/tex] is positive.

The roots of the quadratic equation [tex]\( t^2 - 8t + 8 = 0 \)[/tex] can be found using the quadratic formula:

[tex]\[ t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \][/tex]

where [tex]\( a = 1 \), \( b = -8 \), and \( c = 8 \).[/tex]

[tex]\[ t = \frac{-(-8) \pm \sqrt{(-8)^2 - 4 \cdot 1 \cdot 8}}{2 \cdot 1} \][/tex]

[tex]\[ t = \frac{8 \pm \sqrt{64 - 32}}{2} \][/tex]

[tex]\[ t = \frac{8 \pm \sqrt{32}}{2} \][/tex]

[tex]\[ t = \frac{8 \pm 4\sqrt{2}}{2} \][/tex]

[tex]\[ t = 4 \pm 2\sqrt{2} \][/tex]

So, the roots of the equation are [tex]\( t = 4 - 2\sqrt{2} \) and \( t = 4 + 2\sqrt{2} \).[/tex]

Now, we can test the intervals [tex]\( (-\infty, 4 - 2\sqrt{2}) \), \( (4 - 2\sqrt{2}, 4 + 2\sqrt{2}) \), and \( (4 + 2\sqrt{2}, \infty) \)[/tex] to determine where the inequality [tex]\( t^2 - 8t + 8 > 0 \)[/tex] holds true.

However, it seems there might be an error in the equation. Let's reassess the situation. If the projectile is fired straight upward from ground level, it will reach its maximum height and then fall back to the ground. The time at which it returns to the ground can be found by setting \( s = 0 \) in the position equation:

[tex]\[ -16t^2 + 128t = 0 \][/tex]

Factor out -16t:

-16t(t - 8) = 0

This equation will be true when either -16t = 0 or t - 8 = 0.

Solving each equation:

1.  -16t = 0

t = 0

2. t - 8 = 0

t = 8

So, the projectile will be back at ground level at t = 0 (when it's initially fired) and at t = 8 seconds after being fired.

find the missing variables​

Answers

Answer:

x = 9y = 13

Step-by-step explanation:

You have to assume the the marked lines are parallel.

Alternate exterior angles are congruent, so ...

  (15x -26)° = (12x +1)°

  3x = 27 . . . . . . divide by °, add 26-12x

  x = 9 . . . . . . . . .divide by 3

Then the alternate exterior angles are ...

  (12·9 +1)° = 109°

___

The angle at upper right is vertical with the obtuse interior angle of the triangle whose other interior angles are marked. The sum of them is 180°, so we have ...

  28° +109° +(4y -9)° = 180°

  4y = 52 . . . . . . divide by °, subtract 128

  y = 13 . . . . . . . . divide by 4

Then the third interior angle of the triangle is ...

  (4·13 -9)° = 43°

Oil leaks out of a tanker at a rate of r=f(t) liters per minute, where t is in minutes. If f(t) = A e^{-k t}, write a definite integral expressing the total quantity of oil which leaks out of the tanker in the first hour. total quantity = \int_{a}^{b} (where a = and b = ). What are the units of this integra

Answers

Answer:

[tex]V_{total} = \displaystyle\int_0^{60} A e^{-k t}~dt[/tex]

Step-by-step explanation:

We are given the following in the question:

Oil leaks out of a tanker at a rate of r = f(t) liters per minute, where t is in minutes.

[tex]f(t) = A e^{-k t}[/tex]

Let V be the volume, then we are given that rate of leakage is:

[tex]\displaystyle\frac{dV}{dt} = f(t) = A e^{-k t}[/tex]

Thus, we can write:

[tex]dV = f(t).dt = A e^{-k t}~dt[/tex]

We have to find the  a definite integral expressing the total quantity of oil which leaks out of the tanker in the first hour.

Thus, total amount of oil leaked will be the definite integral from 0 minutes to 60 minutes.

[tex]dV =A e^{-k t}~dt\\V_{total} = \displaystyle\int_a^b f(t)~dt\\\\a = 0\text{ minutes}\\b = 60\text{ minutes}\\\\V_{total} = \displaystyle\int_0^{60} A e^{-k t}~dt[/tex]

The units of integral will be liters.

Final answer:

The total amount of oil leaked in the first hour can be expressed as the definite integral [tex]\int_{0}^{60} A e^{-k t}[/tex] dt. The unit of this integral is liters, as the rate of oil leak is given in liters per minute and the time is in minutes.

Explanation:

The rate of the oil leak is given by [tex]f(t)=Ae^{-kt}[/tex], where A represents the initial rate of the leak, k is a constant, t is time in minutes, and e is the base of the natural logarithm. To express the total amount of oil leaked in the first hour in the form of a definite integral, we need to integrate this rate function from t=0 (the start of the leak) to t=60 (the end of the first hour).

So, the required integral would be expressed as: [tex]\int_{0}^{60} A e^{-k t} dt[/tex]. This integral calculates the total quantity of oil leaked in the first 60 minutes. The units of this integral would be liters, as the rate of the leak is given in liters per minute and the time is in minutes. Integrating a rate over time gives us a total quantity in the original unit of the rate, in this case liters.

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Solve for (g).

−3+5+6g=11−3g
g= ?

Answers

Answer:

g equals 1

g = 1

Isolate the variable by dividing each side by factors that don't contain the variable.

Hope this helps!

Answer:

g=1

Step-by-step explanation:

Given equation is \[−3+5+6g=11−3g\]

Simplifying, \[2 + 6g = 11 - 3g\]

Bringing all terms containing g to the left side of the equation and all the numeric terms to the other side,

\[3g + 6g = 11 - 2\]

=> \[9g = 9\]

=> \[g=\frac{9}{9}\]

=> g = 1

Validating by substituting in the given equation:

Left Hand Side = -3 + 5 + 6 = 8

Right Hand Side = 11 - 3 = 8

Hence the two sides of the equation are equal when g = 1.

The age of an ancient tree trunk is estimated using radiocarbon dating. If the trunk has a C-14 decay rate that is 34% of what it is in living plants, how old is the trunk? The half-life of C-14 is 5730 years.

Answers

Answer:

8923 years

Step-by-step explanation:

Half life of C-14 = 5730yrs

decay rate= 34%

Halt life (t^1/2) = (ln2) / k

5730 = (ln2) /k

k = (ln2) / 5730

k = 1.209 * 10^-4

For first order reaction in radioactivity,

ln(initial amount) = -kt

ln(34/100) = -(1.209*10^-4)t

-1.0788 = -(1.209*10^-4)t

t = -1.7088/ -1.209*10^-4

t = 8923 years

It would take 8918 years for the tree to decay to 34%.

Half life

The half life is the time taken for a substance to decay to half of its value. It is given by:

[tex]N(t) = N_0(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\where\ t=period, N(t)=value\ after\ t\ years, N_o=original\ amount, t_\frac{1}{2} =half\ life\\\\Given\ t_\frac{1}{2} =5730,N(t)=0.34N_o, hence:\\\\0.34N_o=N_o(\frac{1}{2} )^\frac{t}{5730} \\\\t=8918\ years[/tex]

It would take 8918 years for the tree to decay to 34%.

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A survey of 120 teachers determined the following: 70 had high blood pressure, 40 had heart trouble, 20 had both high blood pressure and heart trouble. What percent of the teachers surveyed had neither high blood pressure nor heart trouble?

Answers

Final answer:

Using the principle of inclusion-exclusion, it's calculated that 25% of the teachers surveyed had neither high blood pressure nor heart trouble.

Explanation:

To find the percentage of teachers who had neither high blood pressure nor heart trouble, we can use the principle of inclusion-exclusion in set theory. We begin by adding the number of teachers with each condition, then subtract those counted twice because they have both conditions.

The formula we will use is:

Total surveyed - (High blood pressure + Heart trouble - Both) = Neither condition

Substituting the numbers from the survey, we get:

120 - (70 + 40 - 20) = 120 - (90) = 30

So, 30 teachers had neither high blood pressure nor heart trouble.

To find the percentage, we divide the number of teachers with neither condition by the total surveyed and then multiply by 100:

(30 / 120) * 100 = 25%

Therefore, 25% of the teachers surveyed had neither high blood pressure nor heart trouble.

Use the rules of equations and inverse operations to solve the equation. In your final answer, include all of your work.
4 - x^2 = -16

Answers

Answer:

[tex]x= +2\sqrt{5} or -2\sqrt{5}[/tex]

Step-by-step explanation:

for the given equation,

[tex]4 - x^{2} = -16[/tex]

using rules of equation and inverse operations as isolating x on one side of equation,

interchanging sides  of equation  we get,

[tex]x^{2} =20[/tex]

[tex]x= +\sqrt{20} or x= -\sqrt{20}[/tex]

[tex]x= +2\sqrt{5}  or x= -2\sqrt{5}[/tex]

Assume Jones Manufacturing begins January with 10 units of inventory that cost $10 each. During January, the following purchases and goods sold were: Jan 5 Purchased 8 units at $11. Jan 7, Sold 11 units. What is the weighted average cost per unit in the perpetual system at the time the 11 units are sold on January 7?

Answers

Answer:

10.44

Step-by-step explanation:

The weighted average cost per unit method seeks to get the cost of goods sold as an average of all cost of goods in the inventory as at the time of sales.

Part of its objective is to strike a balance between the (FIFO and LIFO) inventory valuation methods.

Beginning inventory ( Jan) = 10 units

Cost of beginning inventory per unit = $10

Total cost of beginning inventory = Cost * Number of units

In this case (10*$10) = $100

Additional purchase (Jan 5) = 8 units

Cost of additional purchase per unit = $11

Total cost of additional purchase = 8 * $11 = $88

Weighted average cost per unit at the time 11 units are sold on January 7 = Total cost of units at that time / number of units available at that time.

= ($100+ $88) / (10+8)

= 188/18

=10.44 (approximated to 2 decimal places)

I hope this helps make the concept clear.

99 POINTS BRAINLIEST!! No fake answers
A standard six-sided dice is repeatedly rolled until it lands on a two. What is the probability that the first two is rolled after the first six rolls?
A) 33%
B) 41%
C) 53%
D) 67%

Suppose you buy one ticket for $1 out of a lottery of 1,000 tickets where the for the one winning ticket is to be $500. What is your expected value?
A) $0.00
B) $-1.00
C) $-0.40
D) $-0.50

Answers

Answer:

Step-by-step explanation

so the probability of not getting 2 first is 5/6, and this happens six times so we do (5/6)^6 and this is 0.33489797668 , or 33%, so A.

The formula for the expected value would be:

Expected Value = (Probability of Winning)*(Prize if won) + (Probability of not winning)*(Prize if not won)

The price you get if you don't win is 0, so we can ignore the 2nd term. Now, the probability of winning is 1/1000, because you bought 1 ticket out of 1000. Since the prize is $500:

 

Exp. Value = (1/1000)*500 = $0.50 , so its D

I hope this helps!

Answer:

1). A 33%

2). D $-0.50

Step-by-step explanation:

1).  The probability of not getting a 2 first is 5/6 that is 1-1/6=5/6 = 0.8333

number of occurrence is 6

probability = (5/6)^6

= 0.8333^6

= 0.33489797668 ,

= approximately 0.33 to two decimal place

= 33%

The formula for the expected value would be:

Expected Value = (Probability of Winning)*(Prize if won) + (Probability of not winning)*(Prize if not won)

The price you get if you don't win is 0,

so expected value = (probability of winning)*(prize if won)

So, the probability of winning is 1/1000, because you bought 1 ticket out of 1000.

Since the prize is $500:

 

Exp. Value = (1/1000)*500 = $0.50 , so its D

Suppose a country has a population of 50 million and projects a growth rate of 4% per year for the next 20 years. What will the population of this country be in 11 years? (Round your answer to two decimal places.)

Answers

Answer:

The population of this country in 11 years will be 76972702.82

Step-by-step explanation:

The population of this country in 11 years can be calculated using the formula

Population in 11 years =  Starting population x [tex](1+growth rate)^{period}[/tex]

Thus

Population in 11 years =50000000×[tex](1+0.04)^{11}[/tex] =76972702.82

The population of this country in 11 years will be 76.97 million.

In order to determine the population of a country in 11 years, this formula would be used:

FV = P (1 + r)^n

FV = Future value of the population = 50 million  P = Present population R =rate of growth = 4% N = number of years = 11

50 million x (1 + 0.04)^11

= 50 million x (1.04)^11

= 76.97 million

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Zoe is comparing two local yoga programs. Yo-Yoga charges a $35 registration fee and $90 a month. Essence Yoga charges a registration fee of $75 and $80 per month. After how many months will the 2 programs be the same?

Answers

Answer:

After 4 months

Step-by-step explanation:

The cost at both the programs consists of a "fixed cost" (reg fee)  & "variable cost" ( per month fee).

Let number of months be "x"

Yo-Yoga:

35 fixed

90 per month

So equation would be: 35 + 90x

Essence Yoga:

75 fixed

80 per month

So equation would be: 75 + 80x

To find number of month when cost would be same, we equate both equations and solve for x:

35 + 90x = 75 + 80x

10x = 40

x = 40/10

x = 4

hence, after 4 months, both cost would be same

Translate the sentence into an inequality.
Eight times the sum of a number and 29 is less than 17
Use the variable for the unknown number.

Answers

Answer:

8x + 29 < 17

Step-by-step explanation:

Let the unknown number be x .

According to the question ,

8 times x when added to 29 will give a sum less than 17 .

So , we can write

8x + 29 < 17.

We can also solve it

so we will get

8x < -12

x<-1.5.

Water is flowing into a vertical cylindrical tank of diameter 8 m at the rate of 5 m3/min.
Find the rate at which the depth of the water is rising. (Round your answer to three decimal places.)
m/min

Answers

Final answer:

The depth of the water in the cylindrical tank is increasing at a rate of 0.1 m/min. This result is gotten by using the concept of related rates in calculus and differentiating volume with respect to time. The given rate of water inflow and dimensions of the cylindrical tank are substituted into the resultant formula.

Explanation:

This question is dealing with rates of change, specifically in the context of volume and height within a cylindrical tank. It's a problem in calculus, more specifically related to related rates.

To start, let's understand that the volume V of a cylinder is given by the formula V = πr²h, where r is the radius, h is the height, and π is a constant (~3.14159). We can substitute r with 4m (half of the diameter of 8m) and differentiate both sides with respect to time. Differentiating both sides of the equation with respect to t (time) gives dV/dt =πr² dh/dt (since r is constant with respect to time, but h changes).

Given that the rate at which water flows into the tank, dV/dt, is 5m³/min we can substitute this into the formula. This gives us 5 = π(4)²dh/dt. Simplifying the equation gives us dh/dt = 5 / (π(4)²), which approximately equals 0.1 m/min when rounded to three decimal places.

So, the depth of the water in the tank is increasing at a rate of 0.1 m/min.

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The rate at which the depth of water is rising in the cylindrical tank with a diameter of 8 m and water flowing in at 5 m^3/min is approximately 0.199 m/min.

To find the rate at which the depth of the water is rising, we can use the formula for the volume of a cylinder:

[tex]\[ V = \pi r^2 h \][/tex]

where:

V is the volume of the water in the tank,r  is the radius of the tank (half of the diameter),h is the depth of the water.

Differentiating both sides of the equation with respect to time \( t \) gives us:

[tex]\[ {dV}/{dt} = \pi (2r)(dh/dt) \][/tex]

Given that the diameter is 8 m, the radius \( r \) is 4 m. We are also given that the rate of change of volume dV/dt is 5 m³/min. Plugging in these values, we can solve for \( dh/dt \), the rate at which the depth of the water is rising:

[tex]\[ 5 = \pi (2 \times 4)(dh/dt) \][/tex][tex]\[ 5 = 8\pi (dh/dt) \][/tex][tex]\[ dh/dt = \frac{5}{8\pi} \][/tex]

Calculating this gives:

[tex]\[ dh/dt \approx 0.199 \text{ m/min} \][/tex]

So, the rate at which the depth of the water is rising is approximately 0.199 m/min.

Alice borrowed 16700 from the bank at a simple interest rate of 9% to purchase a used car.At the end of the loan,she had paid a total of 24215.How many months was the car loan

Answers

Answer:

Step-by-step explanation:

Alice borrowed 16700 from the bank at a simple interest rate of 9% to purchase a used car. It means that the interest is not compounded. Simple interest is usually expressed per annum. The formula for simple is

I = PRT/100

Where

I = interest

P = principal(amount borrowed from the bank)

R = 9% ( rate at which the interest is charged

T = number of years

At the end of the loan,she had paid a total of 24215. This means that the interest + the principal = 24215

Therefore,

The interest = 24215 - 16700 = 7515

Therefore

7517 = (16700 × 9 × t)/100

751700 = 150300t

T = 751700/150300

T = 5 years

Converting 5 years to months,

1 year 12 months

5 months = 12 × 5 = 60 months

Final answer:

Alice's car loan was for 60 months. This was calculated using the simple interest formula and the total interest paid, which was the difference between the total amount paid and the principal amount borrowed.

Explanation:

To determine how many months the car loan was, we can use the simple interest formula, I = PRT, where:


I is the interest paid
P is the principal amount (the initial amount borrowed)
R is the annual interest rate (as a decimal)
T is the time in years

Alice borrowed $16,700 at a rate of 9%, and the total amount paid was $24,215. The total interest paid is the total amount minus the principal, which is $24,215 - $16,700 = $7,515.

Using the formula, we get:


Interest (I) = $7,515
Principal (P) = $16,700
Annual interest rate (R) = 9% or 0.09

   Time in years (T) = I / (P * R)
   
Substitute the known values: T = $7,515 / ($16,700 * 0.09) = $7,515 / $1,503 = 5 years
Since we need the time in months, multiply the time in years by 12: 5 years * 12 months/year = 60 months

Thus, Alice's car loan was for 60 months.

Robert's mother pours a cup of milk for him and then realizes that the cup has a small crack in the rim. Not wanting her son to cut his lip, she pours the milk into another cup. The second cup happens to be shorter and wider than the first cup. Robert is not upset because he knows that the amount of milk has remained the same. Robert is at LEAST _____ years old.

Answers

Answer:

7 years old

Step-by-step explanation:

Robert's mother pours a cup of milk for him and realizes that cup has a small crack so she pour the milk into another cup. Robert is not upset because he knows that the amount of milk has remained same.

As Robert is 7 year old . He can groups the milk in the cup according to size , shape and color. He has a better understanding of numbers and can understand problems easily.

Final answer:

Robert's recognition of the conservation of volume implies he is at least 7 years old, the age at which children typically enter the concrete operational stage and understand this concept.

Explanation:

The question asks us to determine Robert's age based on his understanding of the concept of conservation of volume. According to developmental psychology, children gain the ability to understand that a change in the form of an object does not necessarily imply a change in the volume or quantity after a certain age. This concept is typically acquired during the concrete operational stage of development, which is from about 7 to 11 years old. Since Robert recognizes that the same amount of milk remains constant despite being poured into cups of different shapes, we can infer that Robert is at least in the concrete operational stage of development. Thus, Robert is at least 7 years old.

PLEASE PLEASE HELP WILL GIVE BRAINLIEST!!!!!
Given the functions k(x) = 2x2 − 8 and p(x) = x − 4, find (k ∘ p)(x).
a. (k ∘ p)(x) = 2x2 − 16x + 24
b. (k ∘ p)(x) = 2x2 − 8x + 8
c. (k ∘ p)(x) = 2x2 − 16x + 32
d. (k ∘ p)(x) = 2x2 − 12

Answers

Answer:

A

Step-by-step explanation:

(kop)(x)=k{p(x)}

=k(x-4)

=2(x-4)²-8

=2(x²-8x+16)-8

=2x²-16x+32-8

=2x²-16x+24

Answer:

a.  2x^2 - 16x + 24.

Step-by-step explanation:

k(x) = 2x^2 − 8

p(x) = x − 4

To find ( k o p)(x) we replace the x in k(x) by x - 4:

= 2(x - 4)^2 - 8

= 2x^2 - 16x + 32 - 8

= 2x^2 - 16x + 24.

Kian has been asked to create a company logo to be put on all company merchandise. The logo needs to be contained within a rectangular space that is 2 inches wide and 3 inches long. How much space does Kian have to work with:
5 units5 inches6 square inches6 cubic inches

Answers

Answer:

C) 6 square inches.

Step-by-step explanation:

The length of the logo = 3 inches

The width of the logo = 2 inches.

It is rectangle shape.

The area of a rectangle = length × width

So, the space needed to work on the logo = 3 × 2 = 6 square inches.

The answer is C) 6 square inches.

Please answer i will give brainliest

Answers

Answer:

Sometime between the third and fourth year (3.5 years)

Step-by-step explanation:

According to the data provided, we know the initial enrollment in the Spanish class is 555. The trend shows 33 more students will enroll each year. So, being y the time in years, the equation for the number of students in the Spanish class is

[tex]S=555+33y[/tex]

As for the French class, since we lose 2 students each year the equation is

[tex]F=230-2y[/tex]

We require to know the value of y in the exact moment when S=3F

[tex]555+33y=3(230-2y)[/tex]

Operating

[tex]555+33y=690-6y[/tex]

Reducing

[tex]39y=690-555[/tex]

[tex]39y=135[/tex]

[tex]y=135/39=3.5\ years[/tex]

It means that sometime between the third and fourth year, there will be 3 times as many students taking Spanish as French

According to the data provided, we know the initial enrollment in the Spanish class is 555. The trend shows 33 more students will enroll each year. So, being y the time in years, the equation for the number of students in the Spanish class is

According to the data provided, we know the initial enrollment in the Spanish class is 555. The trend shows 33 more students will enroll each year. So, being y the time in years, the equation for the number of students in the Spanish class is

According to the data provided, we know the initial enrollment in the Spanish class is 555. The trend shows 33 more students will enroll each year. So, being y the time in years, the equation for the number of students in the Spanish class is

Janet's math test consists of 20 problems. For every correctly solved problem,sherecieves 8 points. For every inccorectly solved problem, she subtracts 5 points.For every problem that she skips, she recieves 0 points. Janet earned 13 points onthe test. How many problems did Janet try and solve? Explain​

Answers

Answer:

6 problems correct 7 incorrect, and 5 skipped over

Step-by-step explanation:

3+5=8 multiple of 8 that ends in 8:48

she got 6 problems corrects

4x6=48 48-13=35

35/5=7

20-7-8=5

After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is closest to A. The point P = (3, 5) looks promising. To check that P really is the point on y = 2x − 1 that is closest to A, what should Kendall do? Is P closest to A?

Answers

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

[tex]d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}[/tex]

and we found the distance PQ and QA

; [tex]d_{PQ}=\sqrt{125}[/tex], [tex]d_{QA}=12[/tex]

be the APQ triangle we must find <APQ through the cosine law (graph 2).

Can someone answer this question please I need it right now

Answers

Answer: Choice B) -5.2 degrees

=====================

Work Shown:

Add up the given temperatures

-42 + (-17) + 14 + (-4) + 23 = -26

Then divide by 5 since there are 5 values we're given

-26/5 = -5.2

The number of kilograms of water in a human body varies directly as the mass of the body. An 87​-kg person contains 58 kg of water. How many kilograms of water are in a 75​-kg ​person?
nothing kg of water are in a 75​-kg person.

Answers

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form [tex]y=kx[/tex], where y varies directly with x and k is constant of variation.

We are told that an 87​-kg person contains 58 kg of water. We can represent this information in an equation as:

[tex]58=k\cdot 87[/tex]

Let us find the constant of variation as:

[tex]\frac{58}{87}=\frac{k\cdot 87}{87}[/tex]

[tex]\frac{29*2}{29*3}=k[/tex]

[tex]\frac{2}{3}=k[/tex]

The equation [tex]y=\frac{2}{3}x[/tex] represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute [tex]x=75[/tex] in our given equation and solve for y.

[tex]y=\frac{2}{3}(75)[/tex]

[tex]y=2(25)[/tex]

[tex]y=50[/tex]

Therefore, there are 50 kg of water in a 75​-kg person.

Final answer:

To find out how many kilograms of water are in a 75 kg person, we can set up a proportion and solve for x. The number of kilograms of water is directly proportional to the mass of the body.

Explanation:

To solve this problem, we can use the concept of direct variation. Direct variation states that two variables are directly proportional to each other. In this case, the number of kilograms of water is directly proportional to the mass of the body.

We are given that an 87 kg person contains 58 kg of water. To find out how many kilograms of water are in a 75 kg person, we can set up a proportion:

(87 kg) / (58 kg) = (75 kg) / (x kg)

Cross multiplying, we get:

87 kg * x kg = 58 kg * 75 kg

Simplifying, we find that x = 39 kg.

Learn more about direct variation here:

https://brainly.com/question/9775007

#SPJ3

Determine the sum: 21.6 x 10^4 + 5.2 x 10^7. Write your answer in scientific notation.

Answers

Answer:

It's D

Step-by-step explanation:

Hope this helps :))

Solve for (d).

4d−4=5d−8

d= ?

Answers

Answer(s):

d= 4 (D=4) or 4=d (4=D)

Step-by-step explanation: You can solve it in 2 ways.

The [tex]1^{st}[/tex] way:

4d−4 = 5d−8

   +4        +4

   4d = 5d-4

  -5d   -5d

    -1d = -4

     /-1    /-1

      d = 4

The [tex]2^{nd}[/tex]

4d−4 = 5d−8

   +8        +8

   4d+4 = 5d

  -4d       -4d

        4 = 1d

        /1    /1

        4 = d

Hope this helps. :)

A certain cold remedy has an 88% rate of success of reducing symptoms within 24 hours. Find the probability that in a random sample of 45 people who took the remedy

Answers

Answer:

The probability of cured people in who took the remedy is 8/9.

Step-by-step explanation:

Success rate of the cold remedy = 88%

The number of people who took the remedy = 45

Now, 88% of 45 = [tex]\frac{88}{100}  \times 45 = 39.6[/tex]

and 39.6 ≈ 40

So, out of 45 people, the remedy worked on total 40 people.

Now, let E: Event of people being cured by cold remedy

Favorable outcomes = 40

[tex]\textrm{Probability of Event E}  = \frac{\textrm{Total number of favorable outcomes}}{\textrm{Total outcomes}}[/tex]

or, [tex]\textrm{Probability of people getting cured}  = \frac{\textrm{40}}{\textrm{45}}[/tex]  = [tex]\frac{8}{9}[/tex]

Hence, the probability of cured people in who took the remedy is 8/9.

Final answer:

To find the probability of at least four patients out of 25 actually having the flu, the binomial probability formula is used. For the expected number of flu cases, the probability (4%) is multiplied by the number of patients (25).

Explanation:

The question pertains to the calculation of probabilities regarding how many patients actually have the flu given a certain success rate of 4% for flu diagnosis among those reporting symptoms. Specifically, we are asked to find the probability that at least four out of the next 25 patients calling in actually have the flu. To solve this, we would use the binomial probability formula:

P(X ≥ k) = 1 - ∑ [ P(X = i) where i goes from 0 to k-1 ]

In this case, X represents the number of patients who actually have the flu, k is the number we are interested in (at least four), and P(X = i) is the probability that exactly i patients have the flu. To express the distribution of X, we use a binomial distribution as we are dealing with a fixed number of independent trials, each with two possible outcomes (having the flu or not).

To determine the expected number of patients with the flu, we would multiply the probability of an individual having the flu (4%) by the number of patients calling in, which is 25.

Expected number of patients with the flu = 25 * 0.04 = 1

The expression m divided by 4 is teh distance each person runs in a relay race that is m miles. How far does each person run in a relay race that is 12 miles

Answers

Answer:

Each person runs 3 miles in a relay race.

Step-by-step explanation:

Given:

Distance of Relay race m = 12 miles.

The expression m divided by 4 is the  distance each person runs in a relay race that is m miles.

Each person runs in relay race = [tex]\frac{m}{4}[/tex]

Now given the total distance of the relay race is 12 miles.

i.e. value of m = 12 miles

Now substituting the value of m in above equation we get;

Each person runs in relay race = [tex]\frac{m}{4} = \frac{12}{4}=3 \ miles[/tex]

Hence each person runs 3 miles in a relay race.

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