The fundamental frequency of a pipe that is open at both ends is 564 hz . part a how long is this pipe?

Answers

Answer 1
. when a pipe is open at both end
l= k / 2
l= length of the pipe
k=wave length of the pipe
there fore 2l = k
we have
f = v k
f = frequency of the wave
v = velocity of the wave
k = wave length of the pipe
f = v k
f = v (2l)
l = f / 2v
l= 564 / (2 * 344)
l= 564/ 688
l =.82m
l=82m
Answer 2

The length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.

What is the frequency?

Frequency is defined as the no of waves that are passing from the point in respect to a given time. Frequency can be measured in Hertz. Humans, whose capacity to hear is normal, can hear between the frequency of 20 Hertz to 20000 Hertz.

Given:

The frequency, f = 564 Hz,

Calculate the length by the formula given below,

[tex]l= k / 2[/tex]

2l = k

Calculate the length of the pipe by the formula given below,

[tex]f = v k[/tex]

f = v (2l)  [Substitute the value of k]

l = f / 2v

l = 564 / (2  × 344)

l= 564 / 688

l = 0.82 m or 82 cm

Therefore, the length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.

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Related Questions

A monochromatic laser is exciting hydrogen atoms from the n=2 state to the n=5 state. part a what is the wavelength λ of the laser?

Answers

The energy levels of the hydrogen atom are given by
[tex]E_n=-13.6 \frac{1}{n^2} [eV] [/tex]
where n is the level number.

In order to make transition from n=2 state to n=5 state, the electron should acquire an energy equal to the difference between the two energy levels:
[tex]\Delta E= E_5 - E_2 = -13.6 \frac{1}{5^2}-(-13.6 \frac{1}{2^2})= -0.54+3.4=2.86 eV[/tex]

Keeping in mind that [tex]1 eV = 1.6 \cdot 10^{-19}eV[/tex], we can convert this energy in Joules
[tex]\Delta E = 2.86 eV \cdot 1.6 \cdot 10^{-19} J/eV=4.58 \cdot 10^{-19} J[/tex]

This is the energy the photons of the laser should have in order to excite electrons from n=2 state to n=5 state. Their frequency can be found by using
[tex]\Delta E=hf[/tex]
where h is the Planck constant and f is the photon frequency. Re-arranging it, we find
[tex]f= \frac{\Delta E}{h}= \frac{4.58 \cdot 10^{-19} J}{6.6 \cdot 10^{-34} Js}=6.94 \cdot 10^{14} Hz [/tex]

and finally we can use the relationship between frequency, wavelength and speed of light which holds for photons, in order to find their wavelength:
[tex]\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{6.94 \cdot 10^{14} Hz}=4.32 \cdot 10^{-7} m =432 nm [/tex]
and this is the laser wavelenghth.

A vertical polarizing filter is used on the lens of a camera. Which waves do not strike the lens?

Answers

A vertical polarizing filter permits only to vertical polarized light to pass through it. This means that the filter will allow the vertical component of the light to pass through, while it will stop the horizontal component of the light. This also means that waves which are already polarized in the horizontal direction will be stopped by the filter as well.

A person on earth would weigh a lot more on the sun due to increased ________________. gravity mass atoms energy

Answers

The correct answer is: gravity.

The complete sentence is:
"A person on earth would weigh a lot more on the sun due to increased gravity"

In fact, the weight of a person is given by
[tex]F=mg[/tex]
where m is the mass of the person, while g is the gravitational acceleration. While the mass m of the person does not change moving from Earth to the Sun, the gravitational acceleration g does depend on the mass of the planet/star. In fact:
[tex]g= \frac{GM}{r^2} [/tex]
where G is the gravitational constant, M is the mass of the planet/star, r is its radius. Due to the fact that the mass of the sun is huge compared to the Earth's mass, the gravitational acceleration at the Sun's surface is much more than the gravitational acceleration at Earth's surface, so a person would weigh much more on the Sun than on Earth.

(by comparison, the value of g at the Sun's surface is approximately 28 times the value of g at Earth's surface).

How is the size of a planet related to the thickness of its atmosphere?

Answers

The bigger the mass of a planet when in right and specific conditions the more atmosphere can attract, if there any floating by the planet

a brick is suspended above the ground at a height of 6.6 m. it has a mass of 5.3 kg. what is the potential energy of the brick

Answers

The formula for potential energy is
E(p) = mgh

(Mass x gravity x height)

Therefore energy = (5.3)(9.8)(6.6)
= 342.8 J

How did I get 9.8?
9.8 is the constant for gravity

What is the acceleration of a skateboarder of mass 46 kg who is being pushed forward with a force 120N?

Answers

Force = mass * acceleration. Therefore, given the force of 120 N and the mass of 46 kg:
120 N = 46 kg * acceleration
120 kg-m/s^2 = 46 kg * acceleration (in m/s^2)
acceleration = 120/46 = 2.61 m/s^2

Answer:

The acceleration of this skateboarder is 2.61 m/s^2.

Explanation:

120=46*a

/46   /46

2.61 m/s^2=a

a star with an original mass of 8 to 25 solar masses will ultimately become a ?
a) red giant
b)white dwarf
c) neutron star
d)main sequence star

Answers

The answer is C. Neutron star.

The cathode ray tube uses which of the following to direct electron beams...

A) electric fields
B) bar magnets
C) magnetic fields
D) gravitational field

Also...what did the cathode ray tube allow J.J. Thomson to do?

A) study static charges in electric fields
B) study and discover the positively charged nucleus
C) study moving electrons in the presence of a magnetic field
D) study the shapes of magnetic fields around solenoids.

Thanks! :)

Answers

The cathode ray tube is vacuum tube that contains a stream of electrons. These electrons are negatively charged particles. In order to direct these electrons to a specific pathway, a magnetic field is being used to exert forces over the negatively charged particles that are in motion.

Therefore, the answer is C. MAGNETIC FIELD

J.J. Thompson discovered the electron, which a constituent of the subatomic particles under the cathode ray tube experiment.

Therefore, the answer is C. STUDY OF MOVING ELECTRONS IN THE PRESENCE OF MAGNETIC FIELD.

Conventionally, the field strength around a charged object is the direction of the force acting on a .

Answers

unit positive test charge

Answer:

Field Strength:

Any charged body has the capacity to effect any test charge that comes inside its field or region. It can be also defined as,

"The total amount or magnitude of force,F or intensity felt by any unit test charge when it enters an electromagnetic or electric field."

For an electric field its unit will be, volt per meter or simply V/m.

Explanation:

A unit test charge inside an electric field:

When a unit test charge enters a given parameters or area set by the charged particle then it will surely experience a force,F equal to the magnitude of that charge body and it will be different as it continues to move closer or far inside the field.

As, we have, "E=F/q",(where "F" is the field strength and "q" is the unit test charge placed inside the field).

What is the escape speed of an electron launched from the surface of a 1.1-cm-diameter glass sphere that has been charged to 8.0 nc ?

Answers

Final answer:

The calculation of escape speed from a charged glass sphere involves principles from electrostatics and classical mechanics, requiring an understanding of how kinetic and electric potential energies equate as an electron moves away from the sphere. Unfortunately, without detailed formulae specific to this electrostatic scenario, a precise answer cannot be provided here.

Explanation:

The question involves calculating the escape speed of an electron from a charged glass sphere, which is a task that falls under the domain of electrostatics and classical mechanics in physics. Generally, the escape speed from a celestial body like Earth is determined by its mass and the gravitational forces involved. However, in this electrostatic context, the key forces are electrical, not gravitational. The escape speed in this scenario would depend on the electric potential energy and kinetic energy equivalence. Given the unique nature of the question which combines concepts from electrostatics with classical escape velocity calculations, a straightforward formula application from physics textbooks might not directly apply without considering the electric force on the electron due to the charged sphere. Nonetheless, the principle remains that to calculate escape speed, one would need to equate the kinetic energy of the electron with the work done against the electric force as it moves to infinity (where the electrical potential energy becomes zero).

The escape speed of an electron from the surface of a charged sphere can be found using the formula, yielding approximately 162 meters per second. This is derived considering the charge of the sphere, its radius, and Coulomb's constant.

To find the escape speed of an electron from a charged sphere, you need to use the concept of electric potential energy and kinetic energy. The escape speed, vesc, is given by:

vesc = √((2 * k * Q) / r)

where Q is the charge of the sphere, r is the radius of the sphere, and k is Coulomb's constant (k = 8.99 × [tex]10^9[/tex] N [tex]m^2[/tex]/[tex]C^2[/tex]).

Given:

Diameter of the sphere = 1.1 cm → radius, r = 0.55 cm = 0.0055 mCharge of the sphere, Q = 8.0 nC = 8.0 × [tex]10^{-9}[/tex] C

Using the formula:

vesc = √((2 * 8.99 × [tex]10^9[/tex] N [tex]m^2[/tex]/[tex]C^2[/tex] * 8.0 × [tex]10^{-9}[/tex] C) / 0.0055 m)vesc = √((1.4384 × [tex]10^2[/tex] ) / 0.0055 m)vesc ≈ √(2.6145 × [tex]10^4[/tex])vesc ≈ 162 m/s

Thus, the escape speed of the electron from the surface of the charged sphere is approximately 162 meters per second.

Make a rule: how would you find the resistance of a parallel circuit with n identical resistors?

Answers

When n resistors are connected in parallel, it means they are connected to the same potential difference V:
[tex]V=V_1 =V_2 =...=V_n[/tex] (2)
It also means that the total current in the circuit is given by the sum of the currents flowing through each branch (each resistor) of the circuit:
[tex]I=I_1+I_2 +...+I_n[/tex] (1)

By using Ohm's law:
[tex]I= \frac{V}{R} [/tex]
we can rewrite (1) as
[tex] \frac{V}{R_{eq}} = \frac{V_1}{R_1}+ \frac{V_2}{R_2}+...+ \frac{V_n}{R_n} [/tex]
However, we said that the potential difference across each resistor is equal (eq.(2)), so we can rewrite the last formula as
[tex] \frac{V}{R_{eq}} = \frac{V}{R_1}+ \frac{V}{R_2}+...+ \frac{V}{R_n}[/tex]
From which we find an expression for the equivalent resistance of n resistors in parallel:
[tex] \frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+....+ \frac{1}{R_n} [/tex]
Final answer:

To find the resistance of a parallel circuit with n identical resistors, divide the resistance of one resistor by n.

Explanation:

The rule to find the resistance of a parallel circuit with n identical resistors is to divide the value of one resistor by the number of resistors (n). So, the formula is Requiv = R/n, where R is the resistance of one resistor and n is the number of resistors in parallel.

When you have n identical resistors in parallel, you can find the equivalent resistance (Requiv) using the formula:

Requiv = R / n

Where:

Requiv is the equivalent resistance of the parallel combination.

R is the resistance of one individual resistor.

n is the number of identical resistors in parallel.

This formula simplifies the calculation and is useful when you want to determine the overall resistance in a parallel circuit, which is a common scenario in electrical circuits and electronics.

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Which color in the visible spectrum has the highest frequency?

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Which color in the visible spectrum has the highest frequency?

The color in the visible spectrum that has the highest frequency is the violet

Violet waves have the most energy of the visible spectrum.

Remember:  c=fλ

Therefore:  f=c/λ

Here c is the speed of light in a vacuum.

So:

As wavelength decreases, frequency increases and, as E=hf, where h is constant (Planck's constant), so does the energy that the waves carry. Waves with a short wavelength have the most energy.

Red waves have a relatively long wavelength (in the 700 nm range), and violet waves are much shorter - roughly half that.

Because violet waves have the shortest wavelength of the visible light spectrum, they carry the most energy.

Violet is the color in the visible spectrum that has the highest frequency. (option b)

The visible spectrum consists of various colors that we can see with our eyes, ranging from red to violet. Each color corresponds to a specific wavelength of light. Wavelength is the distance between consecutive peaks (or troughs) of a wave. The frequency of a wave, on the other hand, refers to how many waves pass a particular point in space per unit of time.

The relationship between frequency (f), wavelength (λ), and the speed of light (c) can be described by the equation:

c = f × λ

where c is the speed of light in a vacuum (approximately 3 × 10^8 meters per second), f is the frequency, and λ is the wavelength.

As per this equation, the higher the frequency of light, the shorter the wavelength. Conversely, the lower the frequency, the longer the wavelength.

Hence the correct option is (b),

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Complete Question:

Which color in the visible spectrum has the highest frequency?

a) Blue

b) Violet

c) Green

d) Red

A mechanical high-speed bat is flying along a path perpendicular to a wall. it emits a sound with a frequency f0 . the night is clear and the air is still. let the speed of sound waves in the still air be vs . the bat hears a sound wave reflected from the wall with a frequency fnew . from this information one can determine the speed vbat at which the bat is flying. install a detector at the wall. 0 bat f v what is the detected frequency? 1. f1 = vs + vbat vs f0 2. f1 = vs vs − vbat f0 3. f1 = vs vs + vbat f0 4. f1 = vs + vbat vs − vbat f0 5. f1 = 2 vs vs − vbat f0 6. f1 = vs − vbat vs f0 7. f1 = vs − vbat vs + vbat f0 8. f1 = f0 9. f1 = 2 vs vs + vbat f0

Answers

Final answer:

The detected frequency f1 can be calculated using the Doppler effect formula, which leads to the conclusion that option 3 is the correct answer (f1 = vs / (vs + vbat) * f0). This equation allows to determine the actual speed of the bat.

Explanation:

This question can be addressed using the Doppler effect principle, which describes how the frequency of sound changes for an observer moving in relation to a sound source.

Given that the bat is moving perpendicular to the wall with the speed vbat and since the night is clear and air is still (meaning no additional obstructions in the sound path), the detected frequency f1 can be calculated using the Doppler effect formula:

f1 = vs / (vs + vbat) * f0.

Therefore, option 3 is the correct answer. To measure the actual speed of the bat, you can install a detector on the wall and make use of the fact that frequencies f0 and f1 are known and the speed of sound vs is also known or can be easily determined from the conditions (e.g., air temperature).

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Final answer:

The question pertains to the Doppler Effect, and the formula for the detected frequency of the bat's echo, considering the bat's speed, is f1 = vs / (vs + vbat) * f0.

Explanation:

The question deals with the concept of the Doppler Effect in physics. This effect relates to the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. In this specific scenario, a mechanical bat emits a sound with a frequency of f0 and moves towards a wall. The sound wave reflects off the wall and returns to the bat. The frequency that the bat hears is affected by its own velocity (vbat) and the speed of sound (vs) in the air around it.

Based on the formulas listed, the correct one is number 3, f1 = vs / (vs + vbat) * f0, based on the standard equation for Doppler Effect when the observer (in this case, the bat) is moving towards a stationary source (in this case, the reflected sound wave). When this happens, the observed frequency increases, since the bat is chasing the sound wave that it emitted.

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Assume that you have two objects, one with a mass of 6 kg and the other with a mass of 17 kg, each with a charge of −0.027 c and separated by a distance of 3 m. what is the electric force that these objects exert on one another? answer in units of n. what is the gravitational force between them? answer in units of n.

Answers

Electric force is the attractive or reflective force of interception between two charged object.

A) The electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.B) The gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.

Given information-

The mass of first object is 6 kg.

The mass of second object is 17 kg.

The charge on both the object is 0.027 C.

The distance between the two object is 3 m.

What is electric force?

Electric force is the attractive or reflective force of interception between two charged object. It can be calculated using the Coulomb's law as,

[tex]F=k_e\dfrac{q_1\q_2}{r^2}[/tex]

Here, [tex]q[/tex] is the charge on the object and [tex]r[/tex] is the distance between the objects. [tex]k_e[/tex] is coulombs constant [tex](8.987\times 10^9)[/tex] N-m squared per C squared.

A) Electric force that these objects exert on one another-

Put the values in above formula to find out the electric force between given objects-

[tex]F=8.987\times10^9\dfrac{(-0.027)\times(-0.027)}{3^2}\\F=7.28\times 10^5[/tex]

Hence the electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.

B) Gravitational force between them-

Gravitational force between two object with mass [tex]m_1[/tex] and [tex]m2[/tex] can be given as,

[tex]F_g=G\dfrac{m_1m_2}{r^2}[/tex]

Here [tex]G=6.67\times 10^{-11}[/tex] N-m squared per kg squared.

Put the values,

[tex]F_g=6.67\times 10^{-11}\times\dfrac{6\times17}{3^2}\\F_g=7.56\times10^{-10}[/tex]

Thus, the gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.

Hence,

The electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.The gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.

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Final answer:

The electric force and gravitational force between two objects can be calculated using specific laws involving charge, mass, and distance.

Explanation:

The electric force between two objects can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The gravitational force between the two objects can be determined using Newton's Law of Universal Gravitation, where the force is proportional to the product of the masses and inversely proportional to the square of the distance between them.

If 3.0 × 10^15 electrons flow through a section of a wire of diameter 2.0 mm in 4.0 s, what is the current in the wire? (e = 1.60 × 10^-19 c)

Answers

Using the given relationship between electrons and coulombs;

1 e = 1.60*10^-19 C

Total charge = 3.0*10^15*1.6*10^-19 = 4.8*10^-4 C

Current = Coulombs/Time = (4.8*10^-4)/4 = 1.2*10^-4 C/s = 1.2*10^-4 Amps

Current in amperes, A = 0.00012 A = 0.12 mA

The current through the wire is of 0.00012 amperes.

How to find the current?

By definition, current will be equal to the quotient between the total charge that flows and the time in which it flows.

Here we have 3.0*10^15 electrons, each one with charge:

e = 1.6*10^(-19) C

Then the total charge that we have is:

Q = (1.6*10^(-19) C)*(3.0*10^15) = 0.00048 C

Finally, the current is:

I = Q/T

where:

Q = 0.00048 CT = 4.0 s

I = (0.00048 C)/(4s) = 0.00012 A

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how have increased carbon dioxide levels and temperatures affected living organisms

Answers

Answer:

Carbon dioxide is a greenhouse gas that traps heat on eath increasing the global average temperature. This for example is melting the arctic ice faster and more than usual. This is leading many arctic species to loose their habitats.

Answer:

Carbon dioxide is a greenhouse gas that traps heat on eath increasing the global average temperature. This for example is melting the arctic ice faster and more than usual. This is leading many arctic species to loose their habitats

Explanation:

twas correct ed2022

Emily finds a rock with crystals 2 cm large. Her rock _____.

Answers

When Emily finds a rock with crystals 2c large, her rock has a glassy texture. One of the characteristics of a crystalline solid has a glassy feature. This is because crystalline solids have a regular geometry and has a short range order that enable one to view it having the same feature in each angle.
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has a coarse texture

Explain why wet clothes that are hung on a washing line dry best

Answers

because the sun evaporates the water out of the clothes

Nickel is a common ferromagnetic material. t/f

Answers

This is true. Nickel is one of the elements present on a rather short list of ferromagnetic materials, along with iron, cobalt, and neodymium, amongst others.

Why does the sound of something moving away from you seem to change to a lower and lower pitch?
A) As the source moves away, the increased distance creates more interference; so the pitch drops.
B) As the source moves away, the frequency of the sound waves is being compressed, so the pitch drops.
C) As the source moves away, the sound waves speed up to reach the observer; this causes the pitch to drop.
D) As the source moves away, the sound waves stretches out relative to the person standing still; so the pitch drops.

Answers

The sound of something moving away from you does NOT seem
to change to a lower and lower pitch.  It simply has a lower pitch
than the sound that was actually emitted.  HOW MUCH lower depends
on the speed with which the source is moving away from you.

As the source moves away, the sound waves "stretch out" relative to
the person standing still; so the pitch drops.  (D)

By the way ... it doesn't matter whether it's the source or the listener moving away, or the listener or the source standing still.  As long as
the distance between them is increasing, the listener hears a sound
with a pitch that's lower than it should be. 

What is the frequency of a photon that has the same momentum as a neutron moving with a speed of 1.90 × 103 m/s?

Answers

The frequency of a photon can be determined by relating its momentum to the speed of a neutron. The resulting frequency is 4.8 × 10¹4 Hz.

The frequency of a photon can be calculated using the relation between momentum and speed. Given that the speed of a neutron is 1.90 × 103 m/s, the frequency of the photon with the same momentum would be 4.8 × 10¹4 Hz.

How many electrons must be removed from an electrically neutral silver dollar to give it a charge of +2.4 μC?

Answers

The total charge to be removed is -2.4 μC. The number of
electrons corresponding to this charge is
                      N = (-2.4 x 10^-6 C)/(-1.60 x 10^-19 C)
                          = 1.5 x 10^13 electrons
Therefore 1.5 x 10^13 electrons need to be removed from the neutral silver dollar.

The total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.

Charge and Electron

A charge can be defined as a property of any matter that causes it to experience a force when it's placed in an electric or magnetic field. The electron is negatively charged. The value of an electron charge is [tex]1.6\times 10^{-19}\;\rm C[/tex]

Given that the neutral silver dollar has a charge [tex]q = +2.4 \mu \rm C[/tex] .

The charge can be given as,

[tex]q=ne[/tex]

Where n is the number of electrons. Thus,

[tex]n =\dfrac { q}{e}[/tex]

[tex]n = \dfrac {+2.4 \times 10 ^{-6}}{1.6\times 10^{-19}}[/tex]

[tex]n = 1.5 \times 10^{13}[/tex]

Hence we can conclude that the total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.

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A teacher pushed a 98 newton desk across a floor for a distance of 5 meter he exerted a horizontal force of 20 newton for four seconds

Answers

Missing question: "how much work is done by the teacher?" (found on internet)

Solution:
The work done to move the desk across the floor is equal to
[tex]W=Fd[/tex]
where F is the horizontal force applied to move the desk, and d is the distance covered by the desk. If we use F=20 N and d=5 m, we find the work done:
[tex]W=Fd=(20 N)(5 m)=100 J[/tex]
Final answer:

The work done by the teacher in pushing the desk is calculated by multiplying the force exerted (20 newtons) by the distance covered (5 meters), which gives a total work done of 100 joules.

Explanation:

To calculate the amount of work done in moving an object, we use the formula: Work = Force x Distance.

In this case, the teacher exerted a force of 20 newtons across a distance of 5 meters. Therefore the work is calculated as: 20N x 5m = 100 joules.

To summarise, the teacher did 100 joules of work on the desk when pushing it through a 5 meter distance.

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The complete question is here:

A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. She exerted a horizontal force

of 20 newtons. How much work was done?

what is showed in the diagram /Users/jacinta/Desktop/NNNNNN.png

Answers

You did not post the photo, looks like you pasted the name of the image and the directory it’s in.

help asap please!! An aluminum block of mass 12.00 kg is heated from 20 C to 118 C. If the specific heat of aluminum is 913 J-1 kg K-1 then how much energy is required?
A. 10.956 kJ
B. 1073.688 kJ
C. 64.640 kJ
D. 7456.167 kJ

Answers

Q = mCΔT, where Q = Amount of energy required, m = mass of the blcok, C = specific heat, ΔT = change in temperature.

Using the given values;

Q = 12*913*(118-20) = 1073688 J = 1073.688 kJ.

The correct answer in B.

If a spaceship of proper length 40 m is measured to have a length 30 m, how fast is it moving?

Answers

In special relativity, the length contraction of an object moving with speed v is given by
[tex]L=L_0 \sqrt{1- \frac{v^2}{c^2} } [/tex]
where
L is the measured length
L0 is the proper length
v is the speed of the object
c is the speed of light

In our problem, the measured length is 30 m while the proper length was 40 m, therefore if we re-arrange the equation we can calculate the speed of the spaceship:
[tex]v=c \sqrt{1- (\frac{L}{L_0})^2 }=(3 \cdot 10^8 m/s ) \sqrt{1-( \frac{30m}{40 m} )^2}=1.98 \cdot 10^8 m/s [/tex]

What is the maximum power consumption of a 3.0-v portable cd player that draws a maximum of 330 ma of current?

Answers

The power used by an electrical device is given by:
[tex]P=VI[/tex]
where V is the potential difference through the device while I is the current flowing through it.

For the cd-player in our problem, [tex]V=3.0 V[/tex], while the current is
[tex]I=330 mA=0.33 A[/tex]
Therefore, the power used is
[tex]P=VI=(3.0 V)(0.33 A)=0.99 W[/tex]

Final answer:

The maximum power consumption of a 3.0-v portable CD player drawing 330 mA of current is calculated using the formula P = IV, giving a result of 0.99 W, which is not directly listed in the provided options.

Explanation:

The question asks for the maximum power consumption of a 3.0-volt portable CD player that draws a maximum of 330 milliamps of current. To find the power, we use the formula P = IV, where P is the power in watts, I is the current in amperes, and V is the voltage in volts.

In this case, I = 330 mA = 0.33 A (since 1A = 1000mA), and V = 3.0 V. Substituting these values into the formula gives:

P = 0.33 A × 3.0 V = 0.99 W.

Benjamina started her walk from the front door of her ground floor apartment. She walked 6 meters to the corner of the building and then turned the corner and walked 10 meters to her friend’s apartment. Identify the difference between the distance she walked and her displacement.

Answers

The distance is the total distance she walked which is 16 meters adding the 6 meters to the corner and 10 meters to her friend's apartment. Her displacement is the distance from her original starting point so you set up a triangle with side lengths of 6 and 10 and solve for the hypotenuse which gives you a displacement of 11.66 meters.  

Answer:

The change in her position (from beginning to end), along with the direction, is considered her displacement. This value is a measurement and a direction. The total distance along the path from her starting point to her end point is considered her distance. This value is a measurement only.

Explanation:

A diver 40 m deep in 10∘C fresh water exhales a 1.0-cm-diameter bubble.

What is the bubble's diameter just as it reaches the surface of the lake, where the water temperature is 20∘C? Assume that the air bubble is always in thermal equilibrium with the surrounding water.
Express your answer to two significant figures and include the appropriate units.

Answers

The diameter of the air bubble when it reaches the surface is about 1.7 cm

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Further explanation

The basic formula of pressure that needs to be recalled is:

Pressure = Force / Cross-sectional Area

or symbolized:

[tex]\large {\boxed {P = F \div A} }[/tex]

P = Pressure (Pa)

F = Force (N)

A = Cross-sectional Area (m²)

Let us now tackle the problem !

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In this problem , we will use Ideal Gas Law as follows:

Given:

initial diameter of bubble = d₁ = 1.0 cm

initial depth of the diver = h = 40 m

initial temperature = T₁ = 10 + 273 = 283 K

atmospheric pressure = Po = 1.0 atm = 10⁵ Pa

final temperature = T₂ = 20 + 273 = 293 K

density of water = ρ = 1000 kg/m³

Unknown:

final diameter of bubble = d₂ = ?

Solution:

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]

[tex]\frac{P_1 (\frac{1}{6} \pi (d_1)^3)}{T_1} = \frac{P_2(\frac{1}{6} \pi (d_2)^3)}{T_2}[/tex]

[tex]\frac{P_1 (d_1)^3}{T_1} = \frac{P_2 (d_2)^3}{T_2}[/tex]

[tex]\frac{(P_o + \rho g h ) (d_1)^3}{T_1} = \frac{P_o (d_2)^3}{T_2}[/tex]

[tex]\frac{(10^5 + 1000(9.8)(40) ) (1.0)^3}{283} = \frac{10^5(d_2)^3}{293}[/tex]

[tex]\frac{(492000 ) (1.0)^3}{283} = \frac{10^5(d_2)^3}{293}[/tex]

[tex]d_2 \approx 1.7 \texttt{ cm}[/tex]

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Learn moreMinimum Coefficient of Static Friction : https://brainly.com/question/5884009The Pressure In A Sealed Plastic Container : https://brainly.com/question/10209135Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454

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Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

By applying the ideal gas law, we find the diameter at the surface to be approximately 1.7 cm.

To determine the bubble's diameter when it reaches the surface, we use the ideal gas law. Since temperature and volume are directly proportional under constant pressure, we can express this relationship as:

(V₁/T₁) = (V₂/T₂)

where,

V₁ = initial volume of the bubble   T₁ = initial temperature of the water (10°C = 283 K)V₂ = final volume of the bubbleT₂ = final temperature of the water (20°C = 293 K)

Given that V₁ is π(0.005 m)² * h (since the volume of a sphere is directly proportional to the radius cubed), we know the final volume V₂ will change due to both temperature and the reduction in pressure as the bubble rises.

Hydrostatic pressure P₁ at 40 meters depth is given by:

P₁ = P₀ + ρgh

P₀ = atmospheric pressure = 1 atmρ = density of water ≈ 1000 kg/m³g = 9.8 m/s²h = 40 m

P₁ ≈ 1 + (1000 * 9.8 * 40) / 101325 ≈ 4.93 atm

At the surface, the only pressure is P₀ (1 atm).

Using the combined gas law P₁V₁/T₁ = P₂V₂/T₂:

4.93V₁/283 = 1V₂/293

Solving for V₂ we get:

V₂ = 4.93 * V₁ * 293 / 283

V₂ ≈ 5.09 * V₁

Since the volume ratio (D₂/D₁)³ = 5.09, taking the cube root:

D₂ ≈ 1.71 * D₁

So, if initial diameter D₁ is 1.0 cm:

D₂ = 1.71 * 1.0 cm ≈ 1.7 cm

Therefore, the bubble's diameter at the surface is approximately 1.7 cm.

Light of wavelength 520 nm passes through a slit of width 0.220 mm. (a) the width of the central maximum on a screen is 8.30 mm. how far is the screen from the slit?

Answers

In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
[tex]y_n= \frac{n \lambda D}{a}[/tex] (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
[tex]\lambda[/tex] is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem,
[tex]\lambda=520 nm=5.2 \cdot 10^{-7} m[/tex]
[tex]a=0.22 mm=0.22 \cdot 10^{-3} m[/tex]
while the width of the central maximum on the screen corresponds to twice the distance of the first minimum from the center, and it is equal to
[tex]2 y_1 = 8.30 mm=8.3 \cdot 10^{-3} m[/tex]
Therefore the distance of the first minimum from the center is
[tex]y_1 = \frac{8.3 \cdot 10^{-3} m}{2}=4.15 \cdot 10^{-3} m[/tex]

If we plug these numbers into eq.(1), we can find D, the distance of the screen from the slit:
[tex]D= \frac{y_1 a}{ 1 \lambda }= \frac{(4.15 \cdot 10^{-3} m)(0.22 \cdot 10^{-3} m)}{(1)(5.2 \cdot 10^{-7} m)}= 1.76 m[/tex]
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