The groups_per_user function receives a dictionary, which contains group names with the list of users. Users can belong to multiple groups. Fill in the blanks to return a dictionary with the users as keys and a list of their groups as values.
def groups_per_user(group_dictionary):
user_groups = {}
# Go through group_dictionary
for ___:
# Now go through the users in the group
for ___: # Now add the group to the the list of
# groups for this user, creating the entry
# in the dictionary if necessary
return(user_groups)
print(groups_per_user({"local": ["admin", "userA"],
"public": ["admin", "userB"],
"administrator": ["admin"] }))

Answer:

See explaination

Explanation:

Mutation Testing:

Mutation Testing is a type of software testing where we mutate (change) certain statements in the source code and check if the test cases are able to find the errors. It is a type of White Box Testing which is mainly used for Unit Testing. The changes in the mutant program are kept extremely small, so it does not affect the overall objective of the program.

We say a mutant is valid if it is syntactically correct. We say a mutant is useful if, in addition to being valid, its behavior differs from the behavior of the original program for no more than a small subset of program test cases.

VALID MUTANTS

1. if (x < 12 && (r – 3 > 12)) LOR

2. if (x < 12 || (r – 3 < 12)) ROR

3. if (x < 12 || (x – 3 < 12)) IVR

INVALID MUTANTS

1. if (x < 12 ||(r – 3 > 12) UPR

2. if (x < 12 (r – 3 < 12)) MLO

3. (x < 12 || (x – 3 < 12)) CSM

Note:

LOR: LOGICAL OPERATOR REPLACEMENT

ROR: RELATIONAL OPERATOR REPLACEMENT

IVR: INVALID VARIABLE REPLACEMENT

UPR: UNBALENCED PARANTHISIS REPLACEMENT

MLO: MISSING LOGICAL OPERATOR REPLACEMENT

CSM: CONTROL OPERATOR MISSING REPLACEMEN

Answer:

import java.util.*;

public class num3 {

   public static void main(String[] args) {

   String sentence = "All good people";

       System.out.println("The vowels in the sentence are ");

       returnVowels(sentence);

   }

   public static void returnVowels(String word){

       String newWord = word.toLowerCase();

       String vowels ="";

       for (int i = 0; i < newWord.length(); i++){

           if(newWord.charAt(i)=='a'||newWord.charAt(i)=='e'||newWord.charAt(i)==i||

           newWord.charAt(i)=='o'||newWord.charAt(i)=='u'){

               vowels = vowels+newWord.charAt(i);

               //System.out.print(newWord.charAt(i)+" ");

           }

       }

       String [] chars = vowels.split("");

       Set<String> uniqueVowels = new LinkedHashSet<>();

       for (String s : chars) {

           uniqueVowels.add(s);

       }

       System.out.println(uniqueVowels);

   }

}

Explanation:

In Java

Create the method/function to receive a string as argument

Change the string to all small letters using the toLowerMethod

Iterate through the string using if statement identify the vowels and store in a new String

Since the sentence does not contain unique vowel characters, use the set collections in java to extract the unique vowels and print out

Answer:

Go to explaination for the step by step answer.

Explanation:

a)Code

function[y]=operation(x) % this function takes x as input and returns y as output

y=(-0.2*x^3+7*x^2)*exp(-0.3*x)

end

% call this function in command widow by typing operation(value of x) like shown in figure in the first attachment.

b. write a code of above function in one script window and save the code with same name as name of function that is name of script should be saved as operation.Now copy paste the below code in new script window and run the code

clc

clear all

x=-2:.1:6

n=length(x)

for i=1:1:n

a=x(i)

y(i)=operation(a)

end

plot(y,x)

xlabel('X')

ylabel('Y')

Please kindly check attachment for pictorial answers that supports the code.

1. The reason that Am..on (creator of Dynamo), G..gle (creator of Bigtable), and F...book (creator of Cassandra) allowed their employees to publish academic papers about the new breed of database technologies is that technologies were custom-made.

A custom-made technology is created specifically to meet some peculiar business strategies and cannot be utilized elsewhere.

2. The reason the companies did not keep these technologies as proprietary secrets is that other companies cannot use the technologies in their businesses since they were created to meet specific business requirements.

Database technologies are technologies that collect, store, organize, and process information and unstructured data for defined users. Some database technologies come in many shapes and sizes. Examples of database technologies include Dynamo, Bigtable, and Cassandra.

Learn more about database technologies at https://brainly.com/question/15334693

Final answer:

Companies like those who created Dynamo, Bigtable, and Cassandra published academic papers about their innovations to establish themselves as leaders, attract top talent, and foster adoption of their technologies as industry standards, despite the potential risk of giving away proprietary information.

Explanation:

The question asks why companies like those who created Dynamo, Bigtable, and Cassandra chose to publish academic papers about their database technologies, rather than keeping them as proprietary secrets. The decision to openly disclose information about these new database technologies can be attributed to several strategic advantages. First, publishing helps in establishing these companies as leaders in technological innovation, attracting top talent who want to work on cutting-edge projects. Furthermore, by sharing the innovations, these companies foster a community of developers who can contribute to the improvement of the technology, indirectly benefiting the original creators. Lastly, it encourages the adoption of their technologies as standards in the industry, which can lead to wider use and integration into other services, products, and technologies.

These reasons collectively contribute to why companies might decide to publish their innovations in the realm of big data and database technologies. Even though it might seem counterintuitive at first to share proprietary technologies, the long-term benefits of establishing industry standards, fostering a collaborative ecosystem, and attracting top talent can outweigh the risks of competitors gaining insights into their technologies.

Answer:

See explaination for program code

Explanation:

%save as AdjustMinValue.m

%Matlab function that takes three arguments

%called number of samples count, user samples

%and min vlaue and then returns a data samples

%that contains values which are double of usersamples

%that less than min vlaue

%

function dataSamples=AdjustMinValue(numberSamples, userSamples, minValue)

dataSamples=userSamples;

%for loop

for i=1:numberSamples

%checking if dataSamples value at index,i

%is less than minValue

if dataSamples(i)<minValue

%set double of dataSamples value

dataSamples(i)= 2*dataSamples(i);

end

end

end

Sample output:

Note:

File name and calling method name must be same

--> AdjustMinValue(4, [2,12,9,20],10)

ans =

4 12 18 20

Answer:

Explanation:

I don't know about the answer in java.

This is what I did in C#. Find attached the answer

public class JobApplication

   {

       private string name;

       public string Name

       {

           get { return name; }

           set { name = value; }

       }

       private string phoneNumber;

       public string PhoneNumber

       {

           get { return phoneNumber; }

           set { phoneNumber = value; }

       }

       private bool isSKilledInWordProcessing;

       public bool IsSkilledInWordProcessing

       {

           get { return isSKilledInWordProcessing; }

           set { isSKilledInWordProcessing = value; }

       }

       private bool isSkilledInSpreadsheets;

       public bool IsSkilledInSpreadsheets

       {

           get { return isSkilledInSpreadsheets; }

           set { isSkilledInSpreadsheets = value; }

       }

       private bool isSkilledInDatabases;

       public bool IsSkilledInDatabases

       {

           get { return isSkilledInDatabases; }

           set { isSkilledInDatabases = value; }

       }

       private bool isSkilledInGraphics;

       public bool IsSkilledInGraphics

       {

           get { return isSkilledInGraphics; }

           set { isSkilledInGraphics = value; }

       }

       public JobApplication(string name, string phoneNumber, bool isSKilledInWordProcessing,

           bool isSkilledInSpreadsheets, bool isSkilledInDatabases, bool IsSkilledInGraphics)

       {

           Name = name;

           PhoneNumber = phoneNumber;

           IsSkilledInDatabases = isSkilledInDatabases;

           IsSkilledInGraphics = isSkilledInGraphics;

           IsSkilledInWordProcessing = IsSkilledInWordProcessing;

           IsSkilledInSpreadsheets = isSkilledInSpreadsheets;

       }

   }

   class Program

   {

       static void Main(string[] args)

       {

           JobApplication jobApplication1 = new JobApplication("Emmanuel Man", "+39399399", false, true, true, true);

           CheckIfQualified(jobApplication1);

       }

       static void CheckIfQualified(JobApplication jobApplication)

       {

           if(jobApplication.IsSkilledInSpreadsheets && jobApplication.IsSkilledInGraphics  

               && jobApplication.IsSkilledInWordProcessing && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           } else if (jobApplication.IsSkilledInSpreadsheets && jobApplication.IsSkilledInGraphics

               && jobApplication.IsSkilledInWordProcessing)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           }

           else if (jobApplication.IsSkilledInSpreadsheets && jobApplication.IsSkilledInGraphics

               && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           } else if (jobApplication.IsSkilledInWordProcessing && jobApplication.IsSkilledInGraphics

               && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           }else if (jobApplication.IsSkilledInWordProcessing && jobApplication.IsSkilledInSpreadsheets

               && jobApplication.IsSkilledInDatabases)

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is qualified for the job");

           }

           else

           {

               Console.WriteLine("The applicant, " + jobApplication.Name + " is not qualified for the job");

           }

       }

   }

Answer:

import java.util.Scanner;

public class TestJobApplicant{

public static void main(String[] args)

{

   JobApplicant applicant1 = new JobApplicant("Ted","555-1234", true, false, false, false);

   JobApplicant applicant2 = new JobApplicant("Lily", "655-1235", true, false, true, false);

   JobApplicant applicant3 = new JobApplicant("Marshall", "755-1236", false, false, false, false);

   JobApplicant applicant4 = new JobApplicant("Barney", "855-1237", true, true, true, false);

   JobApplicant applicant5 = new JobApplicant("Robin", "955-1238", true, true, true, true);

   String qualifiedMessage = "is qualified for an interview. ";

   String notQualifiedMessage = "is not qualified for an interview at this time. ";

   if (isQualified(applicant5))

       display(applicant5, qualifiedMessage);

   else

       display(applicant5, notQualifiedMessage);

}

   public static boolean isQualified(JobApplicant applicant) {

       int count = 0;

       boolean isQualified;

       final int MIN_SKILLS = 3;

       if(applicant.getWord())

           count += 1;

       if(applicant.getSpreadsheet())

           count += 1;

       if(applicant.getDatabase())

           count += 1;

       if(applicant.getGraphics())

           count += 1;

       if(count >= MIN_SKILLS)

           isQualified = true;

       else

           isQualified = false;

       return isQualified;

   }

   public static void display(JobApplicant applicant, String message) {

       System.out.println(applicant.getName() + " " + message +" Phone: " + applicant.getPhone());

   }

}

class JobApplicant {

   private String name, phone;

   private boolean word, spreadsheet, database, graphics;

   public JobApplicant(String name, String phone, boolean word, boolean spreadsheet, boolean database, boolean graphics){

       this.name = name;

       this.phone = phone;

       this.word = word;

       this.spreadsheet = spreadsheet;

       this.database = database;

       this.graphics = graphics;

   }

   public String getName() {return name;}

   public String getPhone() {return phone;}

   public boolean getWord() {return word;}

   public boolean getSpreadsheet() {return spreadsheet;}

   public boolean getDatabase() {return database;}

   public boolean getGraphics() {return graphics;}

}

Explanation:

Inside the JobApplicant class:

- Declare the variables

- Initialize the constructor

- Create the get methods for each variable

Inside the TestJobApplicant class:

- Create an isQualified method that checks if given applicant is qualified for the job.

- Create a display method that prints the name, message and phone number for the applicant

Inside the main:

- Initialize the applicant objects and messages

- Call the isQualified method with an applicant to see the result

Answer:

Changing the customer number on a record in the Orders table to a number that does not match a customer number in the customer table would violate referential integrity.

If deletes do not cascade, deleting a customer that has orders would violate referential integrity.

If deletes cascade, customer can be deleted and all orders for that customer will automatically be deleted.

Final answer:

To determine the number of coins that player 2 will spend in a given round of the game, check the rules based on the value of the round: divisible by 3 = 3 coins, divisible by 2 but not by 3 = 2 coins, not divisible by 3 and not divisible by 2 = 1 coin.

Explanation:

To determine the number of coins that player 2 will spend in a given round of the game, we need to check the rules based on the value of the round:

If the round is divisible by 3, player 2 will spend 3 coins.

If the round is not divisible by 3 but is divisible by 2, player 2 will spend 2 coins.

If the round is not divisible by 3 and not divisible by 2, player 2 will spend 1 coin.

So, the method getPlayer2Move should be defined as follows:

public

int getPlayer2Move(int round)

{

if (

round % 3 == 0) { return 3;

}

else if

(

round % 2 == 0

) {

return 2;

} else {

return 1;

} }

Final answer:

The getPlayer2Move method returns 1, 2, or 3 based on the given rules.

Explanation:

The method getPlayer2Move returns 1, 2, or 3 based on the rules given in the question. If the round number is divisible by 3, the method returns 3. If the round number is not divisible by 3 but is divisible by 2, the method returns 2. If the round number is not divisible by 3 and not divisible by 2, the method returns 1. For example, if the round number is 4, which is divisible by 2 but not divisible by 3, the method would return 2.

Answer:

See explaination

Explanation:

#include <iostream>

#include <iterator>

#include <list>

using namespace std;

list <int> :: iterator maxLoc(list<int>& alist){

list<int> :: iterator max;

list<int> :: iterator it;

int maxs = -199999999;

for (it = alist.begin(); it != alist.end();it++){

int c = *it;

if(maxs < c){

max = it;

maxs = *it;

}

}

alist.erase(max);

return max;

}

list <char> :: iterator maxLoc(list<char>& alist){

list<char> :: iterator max;

list<char> :: iterator it;

int maxs = -199999999;

for (it = alist.begin(); it != alist.end();it++){

char c = *it;

if(maxs < c){

max = it;

maxs = *it;

}

}

alist.erase(max);

return max;

}

int main() {

int intArr[] = {23, 49, -3, 29, 17, 200, 38, 93, 40};

int intSize = sizeof(intArr) / sizeof(int);

list <int> intlist(intArr, intArr + intSize);

list<int> :: iterator it;

for(int i = 0;i<intSize;i++){

list<int> :: iterator m = maxLoc(intlist);

cout << *m << endl;

}

char chrArr[] = "Hello World!";

int chrSize = sizeof(chrArr);

list<char> chrlist(chrArr, chrArr + chrSize);

for(int j = 0;j<chrSize;j++){

list<char> :: iterator m = maxLoc(chrlist);

cout << *m << endl;

}

}

Answer:

See explaination

Explanation:

#include <stdio.h>

#include <malloc.h>

typedef struct {

int eid;

char name[30];

char address[50];

float hourlyRate;

int totalHours;

float bonus;

float salary;

}employee;

void readEmployee(employee *employees, int size){

int i;

for(i = 0; i < size; ++i){

printf("Enter details of employee %d\n", i + 1);

printf("Enter eid: ");

scanf("%d", &employees[i].eid);

printf("Enter name: ");

scanf("%s", employees[i].name);

printf("Enter address: ");

scanf("%s", employees[i].address);

printf("Enter hourly rate: ");

scanf("%f", &employees[i].hourlyRate);

printf("Enter total hours: ");

scanf("%d", &employees[i].totalHours);

printf("Enter bonus percentage: ");

scanf("%f", &employees[i].bonus);

}

}

void ComputeSalary(employee *employees, int size){

int i;

for(i = 0; i < size; ++i){

employees[i].salary = (1 + (employees[i].bonus / 100.0)) * employees[i].hourlyRate * employees[i].totalHours;

}

}

void PrintEmployee(employee *employees, int size){

int i;

for(i = 0; i < size; ++i){

printf("Employee %d\n", i + 1);

printf("Eid: %d\n", employees[i].eid);

printf("Name: %s\n", employees[i].name);

printf("Address: %s\n", employees[i].address);

printf("Total hours: %d\n", employees[i].totalHours);

printf("Hourly rate: $%.2f\n", employees[i].hourlyRate);

printf("Bonus: %.2f%%\n", employees[i].bonus);

printf("Salary: $%.2f\n", employees[i].salary);

}

}

int main(){

int i, size;

employee *employees;

printf("Enter number of employees: ");

scanf("%d", &size);

employees = (employee *) malloc(sizeof(employee) * size);

readEmployee(employees, size);

ComputeSalary(employees, size);

PrintEmployee(employees, size);

return 0;

}

Answer:

#include <stdio.h>

int main()

{

   float afTest1[5] = {90, 30, 25, 45, 55};

   for (int i = 0; i < 5; i++) {

       printf("%f ", afTest1[i]);

   }

   return 0;

}

Explanation:

Initialize the elements of the array as 90, 30, 25, 45, 55

Create a for loop that iterates through the array

Inside the loop, print each element using printf function

Answer:

file = open("numbers.txt")

numbers = []

for line in file:

   numbers.append(int(line))

print("The numbers in the file: " + str(numbers[0]) + " " + str(numbers[1]))

print("The sum of the numbers: " + str(numbers[0] + numbers[1]))

Explanation:

The code is in Python.

Open the file named numbers.txt

Create an empty list, numbers, to hold the numbers in the file

Create a for loop that iterates through file and adds the number inside the file to the list

Print numbers

Calculate and print the sum of the numbers

Final answer:

To read two integers from a file and print their sum, use a Python script to open the file, convert the strings to integers, calculate the sum, and print the results with the equation format.

Explanation:

To construct a program that reads the content from the file numbers.txt and prints out the two numbers along with their sum, you would need to use a programming language. Below is an example of how you might write such a program in Python:

with open('numbers.txt', 'r') as file:
   numbers = file.read().splitlines()

num1 = int(numbers[0])
num2 = int(numbers[1])
sum_of_numbers = num1 + num2

print(f"{num1} + {num2} = {sum_of_numbers}")

This program opens the file numbers.txt, reads its content line by line, converts the lines to integers, and then calculates their sum. Finally, it prints out the numbers and the sum in the format specified. It is assumed that numbers.txt contains one number per line and that these can be converted directly to integers.

Answer:

=($B$4 * B23)

Explanation:

Given

Billable Rate: B4

Total Billable Hours: B23

Required:

Daily Bill: B25

Write the following formula in cell B25

=($B$4 * B23)

The question asks that the cell for billable rate should be referenced using the absolute cell reference.

To use absolute reference in a cell, we start by writing a dollar sign and we also separate the cell name and the cell number with a dollar sign.

Hence, cell B4 becomes $B$4

Also, the question asks that the cell $B$4 be multiplied by cell B23.

To write a formula in Excel, we start by writing the equal to sign (=), then we continue with the expression itself

$B$4 multiplied by cell B23 will be written as $B$4 * B23

So, the full formula to calculate daily bill that'll be written in cell B25 becomes is =($B$4 * B23)

The Excel formula in cell B25 that can be used to calculate the daily bill for Monday, July 29 is =($B$4 × B23)

An excel formula represents the expression of a code in an Excel sheet that operates within a range of cell(s).

From the parameters  given:

By using the absolute reference for billable rate, we need to begin the formula with a $ sign, the cell name in conjunction with the cell number is being separated by a $ sign.

Therefore, the cell in B4 can be written as:

Now, multiplying it with cell in B23, we have using the excel formula method, we have:

=($B$4 × B23)

Learn more about the Excel Formula here:

https://brainly.com/question/25879801

Answer:

Check the explanation

Explanation:

Iterators in C++

==================

Iterators are used to point at the memory addresses of STL containers. They are primarily used in sequence of numbers, characters etc. They reduce the complexity and execution time of program.

Operations of iterators :-

1. begin() :- This function is used to return the beginning position of the container.

2. end() :- This function is used to return the after end position of the container.

// C++ code to demonstrate the working of

// iterator, begin() and end()

#include<iostream>

#include<iterator> // for iterators

#include<vector> // for vectors

using namespace std;

int main()

{

vector<int> ar = { 1, 2, 3, 4, 5 };

// Declaring iterator to a vector

vector<int>:: iterator ptr;

// Displaying vector elements using begin() and end()

cout << "The vector elements are : ";

for (ptr = ar. begin(); ptr < ar. end(); ptr++)

cout << *ptr << " ";

return 0;

}

Iterators in Java

==================

‘Iterator’ is an interface which belongs to collection framework. It allows us to traverse the collection, access the data element and remove the data elements of the collection.

java. util package has public interface Iterator and contains three methods:

boolean hasNext(): It returns true if Iterator has more element to iterate.

Object next(): It returns the next element in the collection until the hasNext()method return true. This method throws ‘NoSuchElementException’ if there is no next element.

void remove(): It removes the current element in the collection. This method throws ‘IllegalStateException’ if this function is called before next( ) is invoked.

// Java code to illustrate the use of iterator

import java. io.*;

import java. util.*;

class Test {

public static void main(String[] args)

{

ArrayList<String> list = new ArrayList<String>();

list. add("A");

list. add("B");

list. add("C");

list. add("D");

list. add("E");

// Iterator to traverse the list

Iterator iterator = list. iterator();

System. out. println("List elements : ");

while (iterator. hasNext())

System. out. print(iterator. next() + " ");

System. out. println();

}

}

Every class that implements Iterable interface appropriately, can be used in the enhanced For loop (for-each loop). The need to implement the Iterator interface arises while designing custom data structures.

Example:

for(Item item: customDataStructure) {

   // do stuff

}

To implement an iterable data structure, we need to:

Implement Iterable interface along with its methods in the said Data Structure

Create an Iterator class which implements Iterator interface and corresponding methods.

We can generalize the pseudo code as follows:

class CustomDataStructure implements Iterable<> {

// code for data structure

public Iterator<> iterator() {

return new CustomIterator<>(this);

}

}

class CustomIterator<> implements Iterator<> {

// constructor

CustomIterator<>(CustomDataStructure obj) {

// initialize cursor

}

// Checks if the next element exists

public boolean hasNext() {

}

// moves the cursor/iterator to next element

public T next() {

}

// Used to remove an element. Implement only if needed

public void remove () {

// Default throws Unsupported Operation Exception.

}

}

Note: The Iterator class can also, be implemented as an inner class of the Data Structure class since it won’t be used elsewhere.

Answer:

#include <stdio.h>

#include <string.h>

int main(void) {

  char simonPattern[50];

  char userPattern[50];

  int userScore;

  int i;

  userScore = 0;

  scanf("%s", simonPattern);

  scanf("%s", userPattern);

  for(i = 0;simonPattern[i]!='\0';i++){

         if(simonPattern[i]!=userPattern[i]){

            userScore=i;

            break;

     }

  }

  printf("userScore: %d\n", userScore);

  return 0;

}

Explanation:

Answer:

See explaination

Explanation:

Kindly check the attachment for the details

Answer:

Explanation:

The first diagram shows the DFA that accepts that accepts any string except 11 and 111

The second diagram shows every odd position of w is 1

Answer:

Complete Python code along with step by step explanation is provided below.

Python Code:

# create a recursive countdown function that will count in decreasing order

def countdown(n):

   if n >= 0:

       print(n)

       countdown(n-1)

# create a recursive countup function that will count in increasing order.

def countup(n):

   if n <= 0:

       print(n)

       countup(n+1)  

# driver code

def main():

# get input from the user

   n = int(input("Please enter any number: "))

# call the countdown function if input n is zero or greater than zero.

# whether you choose countdown or countup for input n the outcome will be same in both cases

   if n >= 0:

       countdown(n)

# call the countup function for the remaining case that is n is less than zero.

   else:

       countup(n)

# call the main function

main()

Output:

Test 1:

Please enter any number: 5

5

4

3

2

1

0

Test 2:

Please enter any number: -6

-6

-5

-4

-3

-2

-1

0

Test 3:

Please enter any number: 0

0

Following  are the python program to the given question:

Program Explanation:

Program:

def countdown(n):#defining a method

   if n <= 0:#defining an if block that checks n value less than equal to 0

       print('Blastoff!')#print message

   else:#defining else block  

       print(n)#print number value

       countdown(n - 1)#calling method countdown

def countup(n):#defining countup method that takes one parameter

   if n >= 0:#defining if block that checks parameter value greater than equal to 0

       print('Blastoff!')#print message

   else:#defining else block

       print(n)#print the parameter value

       countup(n + 1)#Calling method countup

n = int(input("Enter an integer: "))   #defining n variable that inputs value

if n < 0:#defining if block that check n value less than 0

   countup(n)#Calling countup method

else:#defining else block  

   countdown(n)#Calling countdown method

Output:

Please find the attached file.

Learn more:

brainly.com/question/16999822

Answer:

def sum_cubes(n):

   if n == 1:

       return 1

   else:

       return n * n * n + sum_cubes(n-1)

print(sum_cubes(3))

Explanation:

Create a function called sum_cubes that takes one parameter, n

If n is equal to 1, return 1. Otherwise, calculate the cube of n, and add it to the sum_cubes function with parameter n-1

If we want to calculate the cubes of the first 3 numbers:

sum_cubes(3) = 3*3*3 + sum_cubes(2)

sum_cubes(2) = 2*2*2 + sum_cubes(1)

sum_cubes(1) = 1

If you substitute the values from the bottom, you get 27+8+1 = 36

Final answer:

The lab involves analysis of financial ratios, banking operations evaluation using T-account balance sheets, and quantitative modeling in biology, highlighting the importance of data analysis across disciplines.

Explanation:

The request refers to a step-by-step completion of a lab that involves interpreting financial data, specifically using an income statement to calculate various ratios for company analysis. The lab directs students to use specific data analysis tools and apply concepts such as the money multiplier and T-account balance sheets to evaluate banking operations. One part of the lab requires creating a spreadsheet to analyze data in terms of mass fractions relative to sodium, underlining the importance of quantitative modeling skills, even in biology.

Moreover, statistics play a role in the exercise, as students must calculate measures such as mean, standard deviation, median, and interquartile range. The lab encompasses a cross-disciplinary approach, including data analysis in biology and economics, showcasing how quantitative skills are leveraged in diverse fields.

Lastly, the lab also involves learning how to collect and interpret data, which includes skills like observation, sketching, using geography tools, and graphical interpretation. These fundamental skills are critical for successful data analysis in various academic and professional contexts.

Answer:

I have answered the first part in another question of yours, but the second part is in the provided screenshot!

Explanation:

Steps to solve this problem:

Go through all the numbers from 1 -> n1, every time you go through each of these numbers, go through all the numbers from 1 -> n2. Multiply these numbers and add them to an output string. Print each line of output.

Answer:

Explanation:

Correct choice is C.

Answer:

import java.util.Scanner;

public class num9 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter year");

       int givenYear =in.nextInt();

       if(givenYear>=2101){

           System.out.println("Distant Future");

       }

       else if(givenYear>=2001){

           System.out.println("21st Century");

       }

   }

}

Explanation:

Answer:

public class Main

{

public static void main(String[] args) {

 PrintFeetInchShort(5, 8);

}

public static void PrintFeetInchShort(int numFeet, int numInches) {

    System.out.println(numFeet + "'" + " " + numInches + "\"");

}

}

Explanation:

Create a function called PrintFeetInchShort that takes two parameters, numFeet, and numInches

Print the given values in required format. Use System.out.println to print the values, ends with a new line.

Inside the main, call the function with two integers as seen in the example

Explanation:

The outlines given in question statement can be written in many programming languages. The below program would be written in C language, which is one of the basic computer languages

Program code

String main (int MAX_SEV_IR)

{

string INJURY

if (MAX_SEV_IR = =1 or MAX_SEV_IR == 2)

INJURY = "yes"

elseif (MAX_SEV_IR = =0)

INJURY = "No"

else

INJURY = "Invalid data"

return INJURY

}

Answer:

# main function is defined

def main():

# the value of MAX_SEV_IR is gotten

# from the user via keyboard input

MAX_SEV_IR = int(input ("Enter MAX_SEV_IR: ")

# if statement to check for prediction

# if MAX_SEV_IR == 1 or 2

# then there is injury and it is displayed

if (MAX_SEV_IR == 1 or MAX_SEV_IR == 2):

print("INJURY = ", injury)

print("PREDICTION: Accident just reported will involve an injury")

# else if MAX_SEV_IR == 0 then no

# injury and it is displayed

elif (MAX_SEV_IR == 0):

injury = "NO"

print("INJURY = ", injury)

print("PREDICTION: Accident just reported will not involve an injury")

# the call main function to execute

if __name__ = '__main__':

main()

Explanation:

The code is written in Python and well commented.

Final answer:

Daniel is employing Computer-Aided Design (CAD) software and 3D printing to create 3D models for his construction company. This allows for detailed, precise visualizations and virtual tours of home designs, aiding clients in understanding the end product before building commences.

Explanation:

Daniel is using Computer-Aided Design (CAD) software coupled with 3D printing technology to develop the 3D models. CAD software allows users to create detailed, precise representations of products, buildings, and other projects, which then can be used to create physical models through 3D printing. This method is widely utilized in various industries, including construction, architecture, and product design to facilitate visualization and prototyping. The realistic representations and simulations provided by today's CAD programs help professionals like Daniel to effectively communicate design concepts to clients without the need for traditional physical mock-ups, enhancing the design process significantly.

Through this technology, Daniel can construct virtual tours offering exact views of the architectural designs. These models not only help in visualizing the structures but also in making more informed decisions on the design before any actual construction begins. Daniel's utilization of technology for creating 3-dimensional paper models demonstrates how contemporary architectural practices leverage digital tools to bring concepts to life for both the design teams and their clients.

Answer:

System.out.printf("The square root is %.4f\n",sqrt);

Explanation:

In Java programming language using the print format method of System.out One can specify the the number of decimal places. In this case to 4 decimal places.

See a complete code snippet below

public class num1 {

   public static void main(String[] args) {

       double num =5;

       double sqrt = Math.sqrt(5);

       System.out.printf("The square root is $%.4f\n",sqrt);

   }

}

Answer:

total time to read whole file = ( 81.380208 mili seconds ) + 80ms + 80ms

Explanation:

Size of a surface = 675/15 = 45 MB

Size of a track = (Number of sectors per track)*(Size of a sector)

= (144*512)Bytes

= 73.728 KB

Number of tracks where 360KB file is located = 360/73.728 = 4.8828125 (Approx 5 tracks)

So Seek time to go the first track of the file = 80 ms

And after seek time for track to track movement = 4*20 = 80 ms

We need 4.8828125 rotations to read whole file.

Time for 4.8828125 ratations = (60.0/3600.0)*4.8828125 seconds = 0.081380208 seconds = 81.380208 mili seconds

So total time to read whole file = ( 81.380208 mili seconds ) + 80ms + 80ms

Answer:

enum Flower { ROSE, DAISY, PETUNIA }

Flower flora = Flower.ROSE

Explanation:

Flower is of Enumeration data type and it contains the constants ROSE, DAISY and PENTUA.

To write a statement that declares a variable of that type you use

Var_of_enum_type Var_name

And to initialize it with a constant of the enumeration data type you use the dot (.) operator.

Var_of_enum_type.CONSTANT