Given, half life of a certain radioactive element = 800 years.
Amount of substance remaining at time t = 12.5%
Lets consider the initial amount of the radioactive substance = 100%
Using the half life equation:
A = A₀(1/2)^t/t₁/₂
where A₀ is the amount of radioactive substance at time zero and A is the amount of radioactive substance at time t, and t₁/₂ is the half-life of the radioactive substance.
Plugging the given data into the half life equation we have,
12.5 = 100 . (1/2)^t/800
12.5/100 = (1/2)^t/800
0.125 = (0.5)^t/800
(0.5)^3 = (0.5)^t/800
3 = t/800
t = 2400 years
Thus the object is 2400 years old.
The age of the object can be calculated using the given half-life and the percentage of remaining atoms which is 2888.8 years
Explanation:The half-life of a radioactive element is the time it takes for half of its radioactive atoms to decay, transforming into a stable form. It's a fundamental concept in nuclear physics and radiometric dating, used to estimate the age of rocks and archaeological artifacts. The half-life of a radioactive element is the time it takes for half of its nuclei to decay. If only 12.5% of the radioactive atoms remain, it means that 87.5% of the atoms have decayed. Using the given half-life of 800 years, we can calculate the age of the object by finding the number of half-lives it would take for 87.5% decay:
Age of half-lives = log2(87.5%) ≈ 3.61
Age of the object = 3.61 x 800 years = 2888.8 years
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Calculate the frequency of a wave with a wavelength of 8.00x10 m. In what region of the electromagneti spectrum is this?
The frequency of the wave with a wavelength of is 3.748 × 10 ⁶ /s.
I attached the working and the answer to the question below. I hope I was able to help.
Please note that C = speed of light (2.998 × 10⁸ m/s), ν = frequency and λ= wavelength.
which of these is an example of a physical change
A. breaking Bread
B. baking Bread
C. digesting Bread
D. toasting Bread
As the speed increases how does the potential kinetic and total energy levels change
As speed increases, the potential energy in the object decreases, while the kinetic energy increases. Both of those are forms of mechanical energy. Hope this helps!
Which layer of the sun is only seen during the height of a total solar eclipse? A. Photosphere B. Corona C. Convection zone D. core
Question:Which layer of the sun is only seen during the height of a total solar eclipse?
Answer: Corona
Explanation:During a total solar eclipse parts of the Sun that we normally can't see become visible but during it we can see the corona
question answered by
(jacemorris04)
The layer of the Sun which is only seen during the height of a total solar eclipse is: B. Corona.
An eclipse refer to an astronomical event that usually takes place when a celestial body in space gets in between the Sun and another celestial body, leading to the total or partial obscuration (blocking) of light to the celestial body.
In Science, there are two (2) main types of eclipse and these are;
Lunar eclipse: this is an astronomical event that takes place when planet Earth comes in between the Moon and the Sun thereby causing it to cover the Moon with its shadow.Solar eclipse: this is an astronomical event that takes place when the Sun is obscured (blocked) by the Moon and engulfing a portion of the Earth.Total solar eclipse involves the total obscuration (blocking) of the Sun is obscured (blocked) by the Moon causing a complete engulfment of the Earth.
During the height of a total solar eclipse, Corona is the layer of the Sun that is only seen while the core, Photosphere, and Convection zone are not seen.
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Calculate the number of moles of bromine present in 20.5 mL of Br2(l), whose density is 3.12 g/mL.
There are 0.400 mol Br₂ in the sample..
Mass of Br₂ = 20.5 mL Br₂ × 3.12 g Br₂/1 mL Br₂ = 63.96 g Br₂.
Moles of Br₂ = 63.96 g Br₂ × (1 mol Br₂/159.81 mol Br₂) = 0.400 mol Br₂
The 20.5 ml of bromine sample has been consisted of 0.4 mol.
Density can be defined as the mass of an element per unit volume. The density (D) can be expressed as:
[tex]D=\dfrac{M}{V}[/tex]
Where, m has been the mass of the compound
V has been the volume of the compound.
The given Bromine has:
[tex]D=3.12\;\text {g/ml}\\V=20.5\;\rm ml[/tex]
The mass of bromine has been calculated by substituting the values as:
[tex]3.12=\dfrac{m}{20.5}\\\\m=3.12\;\times\;20.5\;\text g\\\\m=63.96\;\text g[/tex]
The mass of bromine sample has been 63.96 g. The moles of the sample has been calculated as:
[tex]M=\dfrac{m}{mwt}[/tex]
Where, mass of the substance, [tex]m=63.96\;\text g[/tex]
Molecular weight of the substance, [tex]mwt=159.81\;\text{g/mol}[/tex]
Substituting the values for calculating moles (M) as:
[tex]M=\dfrac{63.96}{159.81}\;\text{mol}\\\\M= 0.4\;\text{mol}[/tex]
The number of moles of [tex]\rm Br_2[/tex] present in 20.5 ml has been 0.4 mol.
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when a flower is ready to become a fruit here would the instruction be found A.Plant ovum B.Nucleus C.Mitochondria D.Ribosomes
Answer:
Answer is A. Nucleus.
Flower is the reproductive organ of a flowering plant that contains male reproductive organ ( stamen) and female reproductive organ (carpel). Anther of the stamen produces male gamete and within the ovary of the carpel produced female gamete. After fertilization male gamete and female gamete fuses to form zygote. Zygote is a single cell whose nucleus has chromosomes, where all the genetic information regarding development of fruit and seed are stored.
Explanation:
how are physical properties used to describe matter?
If a yes or no question, Yes
Physical properties are used to observe and describe matter. Physical properties can be observed or measured without changing the composition of matter. These are properties such as mass, weight, volume, and density.
A 75.0-milliliter lightbulb is filled with neon. There are 7.16 × 10-4 moles of gas in it, and the absolute pressure is 116.8 kilopascals after the bulb has been on for an hour. How hot did the bulb get?
n = number of mole of sample of helium gas = 7.16 x 10⁻⁴ moles
T = temperature of the gas = temperature of the bulb ?
V = Volume of helium gas = 75 mL = 7.5 x 10⁻⁵ m³
P = pressure of the helium gas = 116.8 kPa = 116.8 x 10³ Pa (1 k = 1000)
Using the equation
P V = n R T
inserting the values
(116.8 x 10³) (7.5 x 10⁻⁵) = (7.16 x 10⁻⁴) (8.314) T
T = 1471.6 C
Answer: 1470 K
Explanation: It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.
Given:
V = 75.0 mL = 0.0750 L
P = 116.8 kPa
We know that 101.325 kPa = 1 atm
So,
= 1.15 atm
R is universal gas constant and its value is .
T = ?
Let's plug in the values in the equation and solve it for T.
0.08625 = 0.00005878(T)
T = 1467 K
So, the temperature of the light bulb would be 1467 K, but since we have to round the total to equal 3 significant figures, the answer is 1470 K
The reaction between zinc and hydrogen chloride produces zinc chloride, hydrogen gas, and heat. If more heat is removed from the reaction, how does the rate of reaction change to counter the action?
When more heat is removed from the reaction, the rate of reaction slows down to counteract the heat loss. This can be controlled by changing the temperature or using a catalyst.
Explanation:When more heat is removed from the reaction between zinc and hydrogen chloride, the rate of the reaction slows down to counteract the heat loss. This is because the reaction is exothermic, meaning it releases heat as a product. By slowing down the reaction rate, less heat is produced, helping to maintain equilibrium in the system.
One way the rate of reaction can be controlled is by changing the temperature of the system. When heat is removed, the temperature decreases, which decreases the kinetic energy of the reactant molecules. As a result, the frequency of successful collisions between reactant molecules decreases, slowing down the overall rate of the reaction.
Another way the rate of reaction can be controlled is by using a catalyst. A catalyst is a substance that speeds up the rate of a reaction without being consumed in the process. By providing an alternative pathway for the reaction to occur, a catalyst can help overcome the activation energy barrier, allowing the reaction to proceed at a faster rate.
You have a cup of water and a packet of powdered juice mix. You stir some of the powder into the cup of water and it quickly dissolves. You decide to add more juice mix to the cup and stir again. Again, the powder quickly dissolves. What can you conclude about the juice powder and water solution?
The powdered juice mix quickly dissolves in the water, indicating that it forms a solution. Stirring the mixture can increase the rate of dissolution. The fact that the mix dissolves again when more is added suggests that the solution was not saturated.
Explanation:The fact that the powdered juice mix quickly dissolves when added to the cup of water suggests that it forms a solution with the water. A solution is a homogenous mixture in which the solute particles are very small and become uniformly dispersed throughout the solvent. The rate of dissolution can be increased by stirring the mixture, which allows fresh solvent molecules to continually come into contact with the solute. Additionally, the fact that the mix quickly dissolves again when more is added suggests that the solution was not saturated and still had room for more solute to be dissolved.
Final answer:
The powdered juice mix forms a stable solution with the water, as indicated by its quick and complete dissolution. The act of stirring increases the rate of dissolution by allowing fresh solvent molecules to interact with the solute particles. The solution remains stable, without any settling or changes, and can pass through a filter without any separation.
Explanation:
The quick dissolution of the powdered juice mix in the cup of water indicates that it forms a stable solution. When a solute, such as the juice mix, is fully dissolved in a solvent, like water, it creates a homogeneous mixture called a solution. In this case, the solute particles in the juice mix are very small, allowing them to dissolve easily in the water.
Stirring the solution aids in dissolving more of the juice mix because it increases the frequency of collisions between the solvent molecules (water) and the solute particles (juice mix), increasing the rate of dissolution. Agitating the solution ensures that fresh solvent molecules continuously come into contact with the solute, speeding up the process.
By observing the quick dissolution of the juice mix and its ability to stay in solution without settling or changing upon passing through a filter, we can conclude that the juice powder and water solution forms a stable and fully dissolved mixture.
Give the masses of the three most abundant Cl2O molecules
Chlorine has the following % abundance and mass:
Cl-35 = 75.76 %, 34.9688 amu
Cl-37 = 24.24 %, 36.9659 amu
Oxygen has the following % abundance and mass:
O-16 = 99.757 %, 15.9949 amu
O-17 = 0.038 %, 16.9991 amu
O-18 = 0.205 %, 17.9991 amu
Based in the % abundance O-16 is the most abundant oxygen isotope and Cl-35 is the most abundant chlorine isotope
So the most abundant molecule of Cl2O and their respective mass are as follows:
1) Cl-35, Cl-35, O-16
Mass = 34.9688 amu + 34.9688 amu + 15.9949 amu = 85.9325 amu
2) Cl-35, Cl-37, O-16
Mass = 34.9688 amu + 36.9659 amu + 15.9949 amu = 87.9296 amu
3) Cl-37, Cl-37, O-16
Mass = 36.9659 amu + 36.9659 amu + 15.9949 amu = 89.9267 amu
Mass is the quantity of matter present in a substance. The masses of the most abundant molecule of [tex]\rm Cl_{2}O[/tex] are 85.9325, 87.9296, and 89.9267 amu.
What are isotopes?Isotopes are the elements of the same species with the same atomic number but differ in atomic mass and physical properties.
% abundance and mass of chlorine are:
Cl-35 = 34.9688 amu
Cl-37 = 36.9659 amu
% abundance and mass of oxygen are:
O-16 = 15.9949 amu
O-17 = 16.9991 amu
O-18 = 17.9991 amu
O -16 is the most abundant form of the oxygen isotope and Cl -35 of chlorine.
The masses of the most abundant molecule are given as:
Cl-35, Cl-35, O-16:
[tex]34.9688 \;\rm amu + 34.9688 \;\rm amu + 15.9949 \rm \;amu = 85.9325\;\rm amu[/tex]
Cl-35, Cl-37, O-16:
[tex]34.9688 \;\rm amu + 36.9659 \;\rm amu + 15.9949 \;\rm amu = 87.9296 \;\rm amu[/tex]
Cl-37, Cl-37, O-16:
[tex]36.9659 \;\rm amu + 36.9659 \;\rm amu + 15.9949 \;\rm amu = 89.9267 \;\rm amu[/tex]
Therefore, 85.9325, 87.9296, and 89.9267 amu are the masses of the most abundant form of the molecule.
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Which statements describe molecules? Check all that apply.
Molecules are made of two or more atoms. A
Molecules are all the same size B
Molecules range in size. C
Molecules are only made of atoms of the same element. D
Molecules are only made of atoms of different elements. E
Molecules are made of atoms of the same element or different elements.F
The following answers are A, C, and F
Molecules are composed of two or more atoms and can vary greatly in size. They can be made of either the same or different elements. Examples include O₂ for the same element and H₂O for different elements.
Let's review each statement to determine whether it accurately describes molecules:
Molecules are made of two or more atoms. (Correct) - Molecules are composed of two or more atoms bonded together chemically. For example, an oxygen molecule (O₂) consists of two oxygen atoms.Molecules are all the same size. (Incorrect) - Molecules vary in size depending on the number of bonded atoms and their arrangement. Smaller molecules, like O₂, have only a few atoms, whereas larger molecules, like DNA, can have millions of atoms.Molecules range in size. (Correct) - As mentioned, molecules can range from very small, like hydrogen molecules (H₂), to very large, like DNA.Molecules are only made of atoms of the same element. (Incorrect) - Molecules can consist of atoms of the same element or different elements. For instance, a water molecule (H₂O) consists of two hydrogen atoms and one oxygen atom.Molecules are only made of atoms of different elements. (Incorrect) - While some molecules, like CO₂, have different elements, others, like O₂, are made of the same element.Molecules are made of atoms of the same element or different elements. (Correct) - Molecules can be formed from either the same element, like O₂, or different elements, like H₂O.How many atoms are in 1.45 mol of pure aluminum
There are approximately 8.7319 × 10²³ aluminum atoms in 1.45 mol of pure aluminum, calculated by multiplying the moles of aluminum by Avogadro's number.
To determine the number of atoms in 1.45 mol of pure aluminum (Al), we use Avogadro's number, which states that one mole of any substance contains 6.022 × 10²³ atoms.
The calculation is as follows:
Identify the amount in moles: 1.45 mol of Al.
Multiply the amount in moles by Avogadro's number: 1.45 mol × 6.022 × 10²³ atoms/mol.
Perform the multiplication to find the total number of atoms: 1.45 × 6.022 × 10²³ = 8.7319 × 10²³ atoms of Al.
The SI defining constant Avogadro constant, often known as NA or L, has a precise value of 6.02214076×10²³ mol⁻¹. It serves as a normalisation factor for the amount of substance in a sample and is defined as the number of constituent particles per mole.
Therefore, there are approximately 8.7319 × 10²³ aluminum atoms in 1.45 mol of pure Al.
Hydrogen (atomic number 1) has three isotopes: ¹H, ²H, and ³H. What is the number of protons in an atom of hydrogen with the highest mass number?
(a) 2
(b) 1
(c) 0
(d) 3
Hydrogen, regardless of its isotopes, always has 1 proton. This is due to its atomic number being 1. Therefore, even the isotope of hydrogen with the highest mass number (³H) still has only 1 proton.
Explanation:The atom of hydrogen with the highest mass number is ³H. The number before 'H' represents the mass number, which is the total number of protons and neutrons in the nucleus. However, regardless of its isotopes, hydrogen's atomic number is 1, indicating that it always has 1 proton. So, in response to your question, the hydrogen atom with the highest mass number still has just 1 proton.
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1.00 g of He, 14.0g F2, and 19.0 g Ar are placed in a 13.0-L container at 20.0 °C. The total pressure (in atm) in the container is _____ atm.
Final answer:
To find the total pressure in the container, calculate the moles of each gas, use the ideal gas law to find the partial pressures, and then sum them up.
Explanation:
To find the total pressure in the container, we need to calculate the partial pressures of each gas and then sum them up.
First, we calculate the moles of each gas using their molar masses:
He: 1.00 g / 4.0026 g/mol = 0.2499 mol
F2: 14.0 g / 38.0 g/mol = 0.3684 mol
Ar: 19.0 g / 39.948 g/mol = 0.4755 mol
Next, we use the ideal gas law to calculate the partial pressures:
He: P(He) = (moles of He) x (R) x (temperature) / (volume) = (0.2499 mol) x (0.0821 L atm/mol K) x (293.0 K) / (13.0 L) = 0.498 atm
F2: P(F2) = (moles of F2) x (R) x (temperature) / (volume) = (0.3684 mol) x (0.0821 L atm/mol K) x (293.0 K) / (13.0 L) = 1.064 atm
Ar: P(Ar) = (moles of Ar) x (R) x (temperature) / (volume) = (0.4755 mol) x (0.0821 L atm/mol K) x (293.0 K) / (13.0 L) = 1.276 atm
Finally, we sum up the partial pressures to get the total pressure in the container:
Total pressure = P(He) + P(F2) + P(Ar) = 0.498 atm + 1.064 atm + 1.276 atm = 2.838 atm
how do new scientific discoveries affect our everyday life
It affects our everday life because of new inventions and easier ways to make/produce different stuff!
What is the density of a 22.91 irregularly shaped object if the initial volume of water was 22.3 and the volume rose to 66.8mL after the object was added?
The density is 0.515 g/cm³.
Mass = 22.91 g
Volume = 66.8 mL – 22.3 mL = 44.5 mL = 44.5 cm³
Density = mass/volume = 22.91 g/44.5 cm³ = 0.515 g/cm³
Please help!!!
Its not chemistry is science.
Select all that apply.
Which of the following are homogeneous solutions?
sugar water
air
peanuts and water
an unopened soft drink
cement
please help question is attached
What happened during the Renaissance that encouraged progress in the study of matter?
During the dark ages-All that wasn't around the christian religion were lost. Knowledge and discoveries before the Dark Ages were mainly in Greek ideas. Biblic scripts however were in Latin. Therefore all inventions up to the dark ages were lost and only religious scripts preserved in the churches. Outside the church, no one knew how to write, read or even communicate.
The Renaissance period has been encouraged the progress in study with the emergence of Italian masters, and new world.
Renaissance has been a French word that means rebirth. The period has been started in the early 13th century and has been lasted up to 16th century.
Progress during Renaissance periodThe period has been started in France. It has been the reconstructive period for the literature and art.
The period has been marked with the emergence of Italian masters such as Leonardo da Vinci, Raphael and Michelangelo. There has been the discovery of the new world with the work of Columbus.
Thus, the Renaissance period has been encouraged the progress in study with the emergence of Italian masters, and new world.
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what is a golf ball and a bowling ball are moving the ball and both have the same kinetic energy which one is moving faster
If they are moving on a plane, the bowling ball would be moving faster if applied the same amount of force as the golf ball.
This is because the bowling ball has a greater mass, and therefore greater kinetic energy.
The greater the kinetic energy, the faster the object will move.
Hope this helps and have a nice day! :)
What is the pH of a solution that has a [H+] of 1.5 × 10−5 M?
pH = 4.82
[H⁺] = 1.5 × 10⁻⁵ mol·L⁻¹.
pH = -log[H⁺] = -log(1.5 × 10⁻⁵) = 4.82
As the firetruck got closer, Sal noticed that the pitch of the siren got higher. Why did this happen?
The change in pitch of the firetruck's siren as it gets closer to the observer is due to the Doppler effect. As the firetruck approaches, the siren's pitch appears to increase, and as it moves away, the pitch appears to decrease. This phenomenon can be observed with passing cars, airplanes, and trains as well.
Explanation:The change in pitch of the siren as the firetruck gets closer is due to the Doppler effect. This effect describes the change in frequency of a sound wave or light wave as the source of the wave or the observer of the wave moves relative to each other.
In the case of the firetruck siren, as the firetruck approaches Sal, the pitch of the siren appears to increase because the sound waves are compressed, resulting in a higher frequency. As the firetruck moves away from Sal, the pitch appears to decrease because the sound waves are stretched, resulting in a lower frequency.
This change in pitch can also be observed with passing cars, airplanes, and trains, where the pitch decreases as they move away from the observer. The faster the firetruck (or any moving source) moves, the greater the shift in pitch.
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As the firetruck moves towards Sal, [tex]\( v_s \)[/tex] is negative (since it is moving towards the observer), which results in [tex]\( f' \)[/tex] being greater than [tex]\( f \)[/tex], indicating a higher pitch. Once the firetruck passes Sal and moves away, [tex]\( v_s \)[/tex] becomes positive, and the pitch Sal hears decreases, becoming lower than the emitted frequency.
The phenomenon Sal observed is known as the Doppler effect. As the firetruck approached Sal, the pitch of the siren got higher due to the Doppler effect.
The Doppler effect is a change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. This effect is commonly experienced with sound waves, such as the siren of an approaching firetruck.
When the firetruck is moving towards Sal, each successive sound wave is emitted from a position closer to Sal than the previous one. This causes the waves to be compressed in front of the firetruck, leading to a higher frequency of sound waves reaching Sal's ears. Since frequency is perceived as pitch, the siren sounds higher in pitch as the firetruck approaches.
Mathematically, the Doppler effect can be described by the following equation for sound waves:
[tex]\[ f' = \left( \frac{v + v_o}{v + v_s} \right) f \][/tex]
where:
[tex]- \( f' \)[/tex] is the observed frequency (the pitch Sal hears).
[tex]- \( f \)[/tex] is the emitted frequency (the actual pitch of the siren).
[tex]- \( v \)[/tex] is the speed of sound in air.
[tex]- \( v_o \)[/tex]is the speed of the observer (in this case, Sal is stationary, so[tex]\( v_o = 0 \))[/tex].
[tex]- \( v_s \)[/tex] is the speed of the source (the firetruck).
20 POINTS!
ANSWER THESE 5 QUESTIONS!
Correct forms of the equation of Charles’s law is (are)
According to Charles' Law the volume of an ideal gas is directly proportional to its absolute temperature in Kelvin keeping the pressure constant.
V∝ T, P is constant
where V, T and P are volume, temperature and pressure
[tex]\frac{V1}{T1 }[/tex] = [tex]\frac{V2}{T2}[/tex]
where V₁, T₁, V₂ and T₂ are initial volume, initial temperature, final volume and final temperature.
Select the atomic models that belong to the same element.
Left Panel
The trick is to look at the protons, all other things being equal. The yellow spheres are neutrons we are led to believe. All the diagrams show the same number of electrons(2), so there is no help there.
The upper left
The upper right
The Lower left
All have 2 protons and 2 electrons. <<<< Answer Read the 3 lines above.
The center one has only 1 proton And the lower right has 3. Both of them are wrong.
Right Panel
You have answered this one correctly
Show the empirical formula manganese fluoride; 59.1% Mn and 40.9% F. Fill in the subscripts on the formula below. Make sure to have a whole number of each subscript, even if it is a 1. Mn____ F____.
Hey there!:
Given % of Mn=59.1% means 59.1 g of Mn present in 100 g of manganese fluoride.
Molar mass of Mn= 54.938 g/mol
Moles of Mn = mass / molar mass
59.1 /54.938 => 1.07 ≈ 1 mol.
and % of F=40.9% means 40.9 g of of F present in 100 g of manganese fluoride.
Molar mass of F=18.998 g/mol
Moles of F :
40.9 / 18.999 => 2.15 mol ≈ 2 mol.
The mole ratio between Mn:F= 1 : 2
Therefore the empirical formula of manganese fluoride:
=> MnF2=Mn1F2
Hope that helps!
Answer : The empirical formula of manganese fluoride is [tex]Mn_1F_2[/tex].
Solution : Given,
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of Mn = 59.1 g
Mass of F = 40.9 g
Molar mass of Mn = 54.94 g/mole
Molar mass of F = 18.99 g/mole
Step 1 : convert given masses into moles.
Moles of Mn = [tex]\frac{\text{ given mass of Mn}}{\text{ molar mass of Mn}}\times 1\text{ mole of Mn}[/tex] = [tex]\frac{59.1g}{54.94g/mole}\times 1\text{ mole of Mn}[/tex] = 1.076 moles
Moles of F = [tex]\frac{\text{ given mass of F}}{\text{ molar mass of F}}\times 1\text{ mole of F}[/tex] = [tex]\frac{40.9g}{18.99g/mole}\times 1\text{ mole of F}[/tex] = 2.154 moles
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Mn = 1.076/1.076 = 1
For F = 2.154/1.076 ≈ 2
Mn : F = 1 : 2
The mole ratio of the element is represented by subscripts in empirical formula.
Therefore, the Empirical formula = [tex]Mn_1F_2[/tex]
which of the follow are pure substances
the answer is v
hope it helps!
Pure substances in Chemistry are either elements or compounds. Elements are the simplest form of pure substances, examples include gold or oxygen. Compounds are made up of two or more different types of elements in a fixed ratio, such as water or carbon dioxide.
Explanation:In Chemistry, pure substances are substances that are made up of only one type of particle and have a fixed or constant structure. They are classified into elements and compounds. Elements are the simplest form of pure substances and cannot be broken down any further.
Examples include gold, copper, oxygen and carbon. Compounds are pure substances that are made up of two or more different types of elements that are chemically combined in a fixed ratio. Examples include water (H2O), carbon dioxide (CO2), and sodium chloride (NaCl).
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what are all of the elements that end with F electrons
The elements whose electron configurations end with f electrons are in the Lanthanide and Actinide series: those long series at the bottom of the Periodic Table (see image).
The atoms are adding electrons into f orbitals, but the f electrons are not always the last electrons in the electron configuration.
For example, the electron configuration of Eu is [Xe]6s²4f⁷, but that of Gd
is [Xe] 6s²4f⁷5d.
I have blocked off in red all the exceptions like Gd.