Answer:
The time that will have to pass before one has under 1 oz of caffeine remaining is 24.53 hours
Explanation:
Here, we have the formula for half life as follows;
[tex]N(t) = N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}[/tex]
Where:
N(t) = Remaining quantity of the substance = 1 oz
N₀ = Initial quantity of the substance = 30 oz
t = Time duration
[tex]t_{1/2}[/tex] = Half life of the substance = 5 hours
Therefore, plugging in the values, we have
[tex]1= 30(\frac{1}{2})^{\frac{t}{5}}[/tex]
[tex]\frac{1}{30} = (\frac{1}{2})^{\frac{t}{5}}\\ln(\frac{1}{30}) =\frac{t}{5} ln(\frac{1}{2})\\\frac{t}{5} = \frac{ln(\frac{1}{30}) }{ ln(\frac{1}{2})} = 4.91\\ t = 4.91 \times 5 = 24.53 \ hours[/tex]
The time that will have to pass before one has under 1 oz of caffeine remaining = 24.53 hours.
A particle with charge −5 µC is located on
the x-axis at the point 10 cm , and a second
particle with charge 6 µC is placed on the
x-axis at −8 cm . What is the magnitude of the total electrostatic force on a third particle with charge
2 µC placed on the x-axis at −2 cm ? The
Coulomb constant is 8.9875 × 109 N · m2
Answer in units of N.
Answer:
36.25 N
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=9\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the magnitude of the two charges
r is the separation between the two charges
Moreover:
- The force is repulsive if the two charges have same sign
- The force is attractive if the two charges have opposite sign
In this problem, we have 3 charges:
[tex]q_1=-5\mu C = -5\cdot 10^{-6}C[/tex] is the charge located at [tex]x=+10 cm = +0.10 m[/tex]
[tex]q_2=+6\mu C=+6\cdot 10^{-6}C[/tex] is the charge located at [tex]x=-8 cm =-0.08 m[/tex]
[tex]q_3=+2\mu C=+2\cdot 10^{-6}C[/tex] is the charge located at [tex]x=-2 cm=-0.02 m[/tex]
The force between charge 1 and charge 3 is:
[tex]F_{13}=\frac{kq_1 q_3}{(x_1-x_3)^2}=\frac{(9\cdot 10^9)(5\cdot 10^{-6})(2\cdot 10^{-6})}{(0.10-(-0.02))^2}=6.25 N[/tex]
And since the two charges have opposite sign, the force is attractive, so the force on charge 3 is to the right (towards charge 1).
The force between charge 2 and charge 3 is:
[tex]F_{23}=\frac{kq_2 q_3}{(x_2-x_3)^2}=\frac{(9\cdot 10^9)(6\cdot 10^{-6})(2\cdot 10^{-6})}{(-0.08-(-0.02))^2}=30.0 N[/tex]
And since the two charges have same sign, the force is repulsive, so the force on charge 3 is to the right (away from charge 2).
So the two forces on charge 3 have same direction (to the right), so the net force is the sum of the two forces:
[tex]F=F_{13}+F_{23}=6.25+30.0=36.25 N[/tex]
To solve this, use Coulomb's Law to calculate the separate forces each charge exerts on the -2 µC charge and then add these up using the principle of superposition to get total force.
Explanation:This question involves the principle of superposition and Coulomb's Law in Physics. According to Coulomb's Law, the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In essence, it can be expressed as F = k|q1*q2|/r², where k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between them.
You need to calculate the forces that the -2 µC charge experiences due to the -5 µC and the 6 µC charges separately, and then superpose (or add up) these forces to get the total force on the -2 µC charge.
The force between the -5 µC charge and the 2 µC charge at position -2 cm, F1 = k|-5*2|/12² = k*10/144
The force between the 6 µC charge and the 2 µC charge, F2 = k*6*2/6² = k*12/36
Add up these forces to get the total force as follows: F = F1 + F2
Using the known value for k (the Coulomb constant) F = (8.9875 × 10^9 N·m²/C²) ( (10/144) + (12/36) ) N
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How does the frequency of gamma rays compare to the frequency of microwaves?
Answer:
Frequency of gamma rays is more than microwave.
Explanation:
The number of vibrations per unit time is called frequency of a wave. The SI unit of frequency is Hertz. It is equal to [tex]s^{-1}[/tex].
The frequency of gamma rays is of the order of [tex]10^{20}\ Hz[/tex]. The frequency of microwave is of the order of [tex]10^8\ Hz[/tex].
It is clear that gamma rays have more frequency that of the microwave.
Help ASAP
Just answer the first question for me please!
Answer:
Im pretty sure its b
You blow dry your wet hair. Is it physical or chemical
Answer: physical
Explanation: it's still hair, it's just dry instead of wet now
A person walks in the following pattern: 3.0 km north, then 2.1 km west, and finally 4.2 km south. (a) How far and (b) at what angle (measured counterclockwise from east) would a bird fly in a straight line from the same starting point to the same final point?
Answer:
(a) 2.42 km
(b) 119.74°
Explanation:
(a)
The shortest distance from starting to end point is the hypotenuse
[tex]C=\sqrt{a^{2}+b^{2}}[/tex]
Where a is is base and b is height. Substituting 1.2 km for a and 2.1km for b then
[tex]C=\sqrt{1.2^{2}+2.1^{2}}=2.41867732448956 km\approx 2.42 km[/tex]
(b)
The angle is given by the [tex]\theta[/tex] as indicated in the sketch
[tex]\theta=\frac {2.1}{1.2}=60.2551187030578\approx 60.26^{\circ}[/tex]
Towards East it will be 180-60.26=119.74°
A 7310 kg space probe, moving nose-first toward Jupiter at 88.3 m/s relative to the Sun, fires its rocket engine, ejecting 54.0 kg of exhaust at a speed of 246 m/s relative to the space probe. What is the final velocity of the probe
Answer:
[tex]v_{1f} = 90.12m/s[/tex]
Explanation:
As we know that Probe along with rocket system is an isolated system
So here net force on this system must be zero
and we can use momentum conservation for this system
So we will have
[tex](m_1 + m_2)v_{i} = m_1v_{1f} + m_2v_{2f}[/tex]
here we know that
[tex]7310 \times 88.3 = (7310- 54)v_{1f} + 54(v_{1f} - 246)[/tex]
[tex]645473 = 7310\times v_{1f} - 13284\\658757 = 7310 \times v_{1f}[/tex]
so we have,
[tex]v_{1f} = 90.12m/s[/tex]
Answer:
Final velocity of Probe; V_f = 656.314 m/s
Explanation:
We are given;
Mass of space probe; m_i = 7310 kg
Initial velocity of probe ; v_i = 88.3 m/s
Mass of exhaust fuel; m = 54 kg
V_rel = 246 m/s
Mass of fuel; m_f = m_i - m = 7310 kg - 54kg = 7256 kg
From Rocket equation;
V_f - V_i = V_rel[In(m_i/m_f)]
Where V_f is final velocity of probe.
Thus, plugging in the relevant values to get ;
V_f - 88.3 = 246[In(7310/7256)]
V_f - 88.3 = 246 x 2.309
V_f - 88.3 = 568.014
Thus, V_f = 568.014 + 88.3 = 656.314 m/s
Which of the following statements about polarized materials is NOT true?
Two polarized filters that have polarizing axes parallel to each other will block all the light passing through them.
Polarized materials have molecules that allow light to pass through them in only one direction.
Two sheets of polarized materials will block all light through them if they are placed so that their polarizing axes are perpendicular.
The alignment of molecules allowing only one direction of light in the material is called its polarizing axis.
Final answer:
The incorrect statement about polarized materials is that two polarized filters with their axes parallel will block all light, while in reality, they pass all light that is polarized along the axis.
Explanation:
The statement about polarized materials that is NOT true is: "Two polarized filters that have polarizing axes parallel to each other will block all the light passing through them." This statement is incorrect because when two polarizing filters are aligned with their axes parallel, all of the polarized light that passes through the first filter will also be passed by the second filter. If the second polarizing filter is rotated, only the component of the light parallel to the second filter's axis is passed. However, it is when the axes of two polarizing filters are perpendicular to each other that they will block all the light passing through them. Polarized materials have molecules that are aligned in such a way that they only allow light to pass through in one direction, which is known as the polarizing axis.. An electric sander consisting of a rotating disk of mass 0.7 kg and radius 10 cm rotates at 15 rev/s. When applied to a rough wooden wall the rotation rate decreases by 20%. (a) What is the final rotational kinetic energy of the rotating disk
The final rotational kinetic energy of the rotating disk is 9.95 J
Explanation:
Given data,
mass 0.7 kg radius 10 cm rotates at the speed of 15 rev/sec
We have the formula,
Kf= 1/2 I ω f²
I=1/2 Mr²2
ωf= (0.8) ωo
substitute in the formula we get
Kf= 1/2 (1/2 MR²2) (0.8) ² ( ωo)²
=(0.16) M R²2 ωo²2
=(0.16)(0.7)(0.10)²(15[2π)] ²
Kf=9.95 J
The final rotational kinetic energy of the rotating disk is 9.95 J
What characteristics would an Earth-like planet need to have to support life?
Answer:
water, air, vegetation, and light. also a good temperature thats not too hot or too cold
Explanation:
it would need oxygen, trees, places for animals to build habitats, and water. The temperature also cant be too high.
What would happen if the voltage impressed across a circuit is held constant while the resistance doubles
Answer:
What would happen if the voltage impressed across a circuit is held constant while the resistance doubles.
The answer is:
A change will occur in the current which is, "The new current will be half the initial value."
Explanation:
Voltage, also called electromotive force, is the measure of specific potential energy between two locations in an electrical field.
V= IR
Where, V= Voltage
I= Current
R= Resistance
The greater the voltage in a circuit, the greater its ability to push more electrons and do work.
Voltage is measured in volts (V). Voltage is the difference in charge between two points, and can also be considered as the pressure that forces the charged electrons to flow in an electrical circuit.
Current is the rate at which charge is flowing. An electric current flows when electrons move through a conductor, such as a metal wire.
Resistance is a material's tendency to resist the flow of charge (current). Resistance is measured in ohms, and can be further explained as a measure of the opposition to current flow in an electrical circuit. Resistance is good because it protects humans from the harmful energy of electricity. Resistance, R in ohms (Ω) is equal to the voltage V in volts (V) divided by the current I in amps (A).
Current is directly proportional to the voltage and inversely proportional to the resistance.
If voltage is increased, the current will also increase. The higher the resistance, the lower the current flow. The lower the resistance, the higher the current flow.
Doubling the voltage will cause the current to be doubled. Also, doubling the resistance will cause the current to be one-half the original value.
Two spherical inflated rubber balloons each have the same amount of charge spread uniformly on their surfaces. If the repelling force is 2.5 N and the distance between the balloon centers is 0.30 m, find how much charge is on each balloon.
Answer:
[tex]5.0\cdot 10^{-6}C[/tex]
Explanation:
The magnitude of the electrostatic force between two charged objects is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the two charges on the two objects
r is the separation between the two charges
The force is:
- Repulsive if the two charges have same sign
- Attractive if the two charges have opposite sign
In this problem:
F = 2.5 N is the force between the two balloons
r = 0.30 m is their separation
[tex]q_1=q_2=q[/tex] is the charge on each balloon (they have the same charge)
So, re-arranging the equation, we can find the value of q:
[tex]F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(2.5)(0.30)^2}{8.99\cdot 10^9}}=5.0\cdot 10^{-6}C[/tex]
We are also told that the force between them is repulsive: this means that the charges on the two balloons have same sign (so, either they are both positive, or both negative).
Using Coulomb's Law, we derive the formula to calculate the charge on each balloon to be q = sqrt(F * r^2 / k). By substituting the provided force and distance values into the formula, we can find the magnitude of charge on the spherical balloons.
Explanation:The question involves calculating the charge on each of two spherical balloons which repel each other with a given force, using Coulomb's Law. Coulomb's Law states that the magnitude of the electrostatic force of interaction between two point charges is directly proportional to the scalar multiplication of the magnitudes of charges and inversely proportional to the square of the distance between the two charges.
According to Coulomb's Law, F = k * (|q1 * q2|) / r^2, where F is the force between charges, k is Coulomb's constant (8.9875 x 10^9 N·m^2/C^2), q1 and q2 are the amounts of charge on the balloons which are equal in this case, and r is the distance between the centers of the two charges.
To find the amount of charge on each balloon, we rearrange the formula to solve for q: q = sqrt(F * r^2 / k). We are given that the repelling force F is 2.5 N and the distance r is 0.30 m. Plugging in these values and the value for k, we can calculate the amount of charge on each balloon.
What is the speed of a particle whose kinetic energy is equal to its rest energy.
Answer:
The speed of the particle whose kinetic energy is equal to its rest energy is 4.242*10⁸m/s.
Explanation:
The rest energy is defined as the energy equal to the mass of the particle at rest in the inertial frame of reference equal to the rest mass time square of speed of light
E₀ = mc²
The kinetic energy is defined as the energy possessed by the particle due to its motion.
K.E =0.5mv².
where, m is the mass of the particle
c is the speed of light,
v is the velocity of the particle
It is given that Kinetic energy is equal to rest energy ie K.E = E₀
0.5mv² = mc²
v² = 2c²
v =√2c
= 1.414*3*10⁸
v =4.242 *10⁸ m/s
The speed of the particle whose kinetic energy is equal to its rest energy is 4.242*10⁸m/s.
The speed of a particle whose kinetic energy equals its rest energy would be a significant fraction of the speed of light, approximately 0.914c or 91.4% of the speed of light for an electron with kinetic energy 150% of its rest mass energy.
Explanation:The question asks about the relationship between kinetic energy and speed for a particle when the kinetic energy is equal to the particle's rest energy. Using the principles of relativity, we know that a particle's total energy is the sum of its rest mass energy and its kinetic energy. According to Einstein's theory of relativity, the kinetic energy (K) of a particle approaches infinity as its speed (v) approaches the speed of light (c). Therefore, for a particle to have its kinetic energy equal to its rest mass energy (E0), it must be traveling at a significant fraction of the speed of light.
Specifically, in the case of an electron with a rest mass energy of 0.511 MeV, if its kinetic energy is 150% of this value, calculations would show that the electron is traveling at a velocity approximately 0.914c, which is around 91.4% of the speed of light. This result is consistent with relativistic effects, which become significant as particles move at speeds approaching the ultimate speed limit, c, as stated by the theory of relativity.
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Find fq, the vertical force that pier q exerts on the right end of the bridge. express the vertical force at q in terms of m and g
Answer:
[tex]F_Q=\frac{Mg}{3}[/tex]
Explanation:
We are given that
Length of beam=L
Mass of object=M
We have to find the FQ , the vertical force that pier exerts on the right end of the bridge .
Torque about P
[tex]F_Q(3L)-MgL=0[/tex]
[tex]F_Q(3L)=MgL[/tex]
[tex]F_Q=\frac{MgL}{3L}[/tex]
[tex]F_Q=\frac{Mg}{3}[/tex]
Hence, the force that exerted pier Q exerts on the right end of the bridge is given by
[tex]F_Q=\frac{Mg}{3}[/tex]
When air resistance is ignored, every object accelerates at a rate of 9.8 m/s2. Describe what this means regarding the position and velocity of the object. What would the graphs for free fall look like?Justify your answer:
Answer:
Constant acceleration, velocity varies linearly, position varies quadratically.
Explanation:
Given that acceleration is constant, the vertical velocity varies linearly and vertical position varias quadratically by applying the physical concepts of position, velocity and acceleration and the mathematical concepts of differentiation and integration. Graphics are presented below as attachments.
What impact or changes do you think this invasion of zebra mussels will have on the native species living in the Hudson River ecosystem? (Hint: Think about what it means to be the only freshwater mussel species that can attach itself toobjects.)
Answer:
The native species will be endangered or even go into extinction.
A drastic change in the food web
Explanation:
The zebra mussel or Dreissena
polymorpha is a small bivalve that originated from the Caspian Sea region, In mid 1980s the Zebra Mussels moved to North America in the ballast water of a ship.
They took over the
Great Lakes and the waters draining them. It is speculated that the Zebra mussels will eventually
move to most of the waters in North America with the exception of waters that are too warm or too saline for them to survive.
They were first discovered in the Hudson at very low densities in 1991, spreading rapidly that by 1992 they can be found throughout the river, with biomass that was greater than the combined biomass of all
other consumers viz; fish, zooplankton and bacteria, in the river.
Their densities can reach over
100,000 individuals per square meter. Because they are so many, they are able to filter all of the
water in the freshwater portion of the Hudson River every 2-4 days.
Whereas the native mussels could filter the water only every 2-3 months.
Zebra mussels are suspension feeders, eating
phytoplankton, small zooplankton, large bacteria, and organic detritus by filtering the water and straining out the edible material.
Now, because they filter small
organisms and organic particles out of the water at very high rates. (Very efficient filter-feeders)
Phytoplankton and zooplankton which form the base of the aquatic food web, as many animals depend on them for survival, this balance is tilted.
This has brought great changes and effects on the Hudson Ecosystem. The food web changes that the mussel has caused compare in magnitude to disturbances in other aquatic ecosystems caused by toxins, nutrient pollution, or acid rain. and have been found. These mussels were most likely
brought to those areas by careless human activity.
Furthermore, most of the species on the Hudson river will be endangered and some must have gone into extinction and this is due to the speed with which the Zebra mussels feed on them.
On the incomplete ray diagram for an object in front of a curved mirror, trace the path of Ray 1 as you would do to find the location and size of the image. F labels the focal point of the mirror.
You do not have to trace additional rays for this question.
Answer:
Answer:
See attached the ray diagram with the path of Ray 1, which must pass through the focal point, F.
Explanation:
The curved mirror shown is a converging lens.
To find the location and size of the image formed by a converging lens, you must draw two rays: one ray is from the upper tip of the object (the pen in your figure) that is in front of the mirror, parallel to the horizontal axis until the lens (Ray 1 in your figure) which then bends through the focal point (F in your figure). That is the ray that you must complete in your figure.
The attached figure shows this ray in blue.
The other ray would be from the upper tip of the pen straight through the center of the lens (this is not included in the figure, by instructions of the question).
For finding the location and size of the image we have to prepare it for that please look below.
Curved mirror:It is to be shown like a converging lens. For determining the location and image size i.e. created by the converging lens here two rays should be drawn i.e. one ray from the upper tip of the project that should be front of the mirror also parallel to the horizontal axis that bends via the focal point. It represents that ray that should finished the given figure.
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A and B are mutually exclusive events. PA) = 0.50 and P(B) = 0.30. What is
PA or B)?
Answer:
P(A∪B)=0.8
Explanation:
Given that,
A and B are mutually exclusive events such that,
P(A)=0.5 and P(B)=0.3
We need to find P(A or B). It means we need to find P(A∪B). If two events are mutually exclusive, P(A∩B)=0. So,
P(A∪B)=P(A)+P(B)-P(A∩B)
Putting P(A) and P(B), we get :
P(A∪B)=0.5+0.3-0
P(A∪B)=0.8
So, the value of P(A or B) is 0.8
. How does the type of medium affect a sound wave?
Answer:
As a result, sound waves travel faster in solids than in liquids, and faster in liquids than in gasses. While the density of a medium also affects the speed of sound, the elastic properties have a greater influence on the wave speed. The density of a medium is the second factor that affects the speed of sound. ( sorry its a bit long :b)
Explanation:
All of the noble gases, Group 18, have eight valence electrons in its outer shell (excluding helium which only has two). Which of these would represent the oxidation number of the noble gases such as xenon and argon?
Answer:
Zero or +2
Explanation:
The noble gases already have a avplete outermost shell. They are the least reactive elements of earth?
Their normal oxidation number is zero but some have been shown to be reactive.
Answer:
Explanation:
Since oxidation number is derived from the number of electron in the outermost shell of an element and further more this oxidation number is a function of how much electron is needed by an element to achieve a duplet ( He) or octet configuration ( complete outer most shell which is the attributes of group 18 elements or noble gases) and they don't readily react with any compound.. Since Xenon and argon are noble gases , they will have their outer most shell completely feel hence their oxidation number will be zero (0)
Which two layers of the atmosphere are responsible for the majority of the solar radiation absorption?
Answer: The stratosphere and the thermosphere are responsible for the majority of the solar radiation absorption.
Explanation:
Answer:The stratosphere and the thermosphere are responsible for the majority of the solar radiation absorption.
If a system absorbs 300.5J of heat and performs 1.50kJ of work on the surroundings, what is the ΔE?
Complete question:
If a system absorbs 300.5J of heat and performs 1.50kJ of work on the surroundings, what is the change in internal energy of the system ΔE?
Answer:
Change in internal energy of the system is 1800.5 J
Explanation:
Given:
heat transferred to the system, Q = 300.5J
work done on the surroundings, W = 1.50kJ
Change in internal energy of the system ΔE, can be calculated by applying thermodynamic equation of change in internal energy, work done and heat transferred.
ΔE = Q + W
Where;
ΔE is change in internal energy
Q is heat transfer
W is work done
ΔE = 300.5 J + 1500 J
ΔE = 1800.5 J
Therefore, change in internal energy of the system is 1800.5 J
Answer:
The intern energy of the system is -1199.5 J
Explanation:
Given:
System absorbs 300.5 J of heat
Performs 1.5 kJ = 1500 J of work on the surroundings
Question: What is the ΔE?
When a system absorbs heat, it will have a positive sign, therefore +300.5 J
When the system performs work on the surroundings, its sign will be negative, therefore, -1500 J
According the first law of thermodinamic:
ΔE = q + W = 300.5 - 1500 = -1199.5 J
A metal object is to be gold-plated by an electrolytic procedure using aqueous aucl3 electrolyte. Calculate the number of moles of gold deposited in 3.0 min by a constant current of 10. A.
Answer:
Explanation:
charges passed = current x time
= 10 x 3 x 60
= 1800 C
mole of charge = 1800 / 96500
= .01865 moles
Au⁺³ contains 3 positive charges
3 mole of charge will deposit 1 mole of Au
.01865 moles will deposit .01865 / 3 mole
= 6.2167 x 10⁻³ moles .
How does the law of inertia relate to how the planets in our solar system revolve around the sun?
Answer:
The law of inertia relates to revolution of planets round the sun due to constant motion of the planets round the sun.
Explanation:
Law of inertia states that a body at rest or uniform motion will continue to be at rest or uniform motion unless it is acted upon by an external force.
The gravitational force keeps the planets revolving round the sun in a uniform motion, this will continue till infinity unless equal and opposite force acts on our planets.
Therefore, the law of inertia relates to revolution of planets round the sun due to constant motion of the planets round the sun.
587 kJ of work against gravity when it lifts a 6500 kg concrete from at a construction site. Calculate the height, in m, the form was lifted
Answer:
The answer to your question is height = 9.20 m
Explanation:
Data
Work = 587 kJ
mass of the body = 6500 kg
height = ?
Mechanic work is defined as the force applied to a body times its mass.
Process
1.- Calculate the weight of the body
weight = mass x gravity (9.81)
weight = 6500 x 9.81
= 63765 N
2.- Calculate the height
height = work / weight
-Substitution
height = 587 000 / 63765
-Result
height = 9.20 m
A guitar string produces 3 beats/s when sounded with a 352-hz tuning fork and 8 beats/s when sounded with a 357-hz tuning fork.
Explanation:
The fluctuating sound heard when two objects vibrate with different frequencies is called beats. It is given that guitar string produces 3 beats/s when sounded with a 352 Hz tuning fork and 8 beats/s when sounded with a 357 Hz tuning fork.
It is assumed to find the vibrational frequency of the string.
For 3 beats/s, beat frequency can be :
352 - 3 or 352 + 3 = 349 Hz or 355 Hz
For 8 beats/s, beat frequency can be :
357 - 8 or 357 + 8 = 349 Hz or 365 Hz
It means that the vibrational frequency is 349 Hz.
How can you connect four of them to produce an equivalent resistance of 0.25 kω?
Answer:
Question incomplete
This is the complete question
You have a collection of 1.0 kΩ resistors.
How can you connect four of them to produce an equivalent resistance of 0.25 kΩ?
Explanation:
Given that,
We have collection of resistor
R = 1.0 kΩ.
And we want to design an equivalent resistance of
R = 0.25kΩ
We know that,
Series connection of add up resistance and this increases the value of resistance, I.e
Req = R1 + R2 + R3 +.....
While
Parallel resistance add up the reciprocal of resistance and this reduces resistance
So, 1/Req = 1/R1 + 1/R2 + 1/R3 +......
Now, we want to design 0.25kΩ
Connect four of the resistor in parallel will give a equivalent resistance of 0.25 kΩ
1/Req = 1/R1 + 1/R2 + 1/R3 + 1/R4
R1 = R2 = R3 = R4 = 1.0 kΩ
1/Req = 1/1 + 1/1 + 1/1 + 1/1
1/Req = 1+1+1+1
1/Req = 4
Taking reciprocal of both sides..
Req = ¼ kΩ
This is the required equivalent resistance
So, connect the four of the resistor in parallel will give the required 0.25 kΩ resistance
What is a sentence for absolute strength?
Sciencium-380 has a half-life of 3 days. If you started with a 100 gram sample, how much Sciencium-380 will remain after 9 days?
Answer: 12.5 grams will remain.
Explanation:
The half life time means that if we start with a quantity A of a given subtance/material, after the half time we will have half that quantity, or A/2.
We know that the half life of Sciencium-380 is 3 days.
So if we have 100 grams, after 3 days we will have 100/2 = 50 grams.
After other 3 days we will have 50/2 = 25 grams
After other 3 days we will have 25/2 = 12.5 grams.
So if we start with 100 grams, after 9 days we will have 12.5 grams.
Answer:
12.5 grams
Explanation:
Solution:-
- By definition, the half-life is the amount of time t that a substance of mass M to decay to half its its initial mass.
- We are given the mass of the Sciencium-380, M = 100 g
- The half-life for the radioactive isotope is, h = 3 days
- The amount of mass left after t = 9 days.
- We will first estimate the number of half-lives that have passed in te duration of t = 9 years.
- The number of half lives are:
n = t / h
n = 9 / 3
n = 3
- For every half life the mass is halved or mathematically the mass ( m ) of a substance remaining after " n " number of half lives can be expressed as:
m = M*0.5^n
- Plug in the given values and evaluate the mass ( m ) of the substance after n = 3 half lives.
m = 100*0.5^3
m = 12.5 grams.
Answer: We are left with 12.5 grams of Sciencium after 3 half lives have passed.
Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasoning
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Answer:
ive answered this
Explanation:
please check your previose question
The palm of the hand has more touch receptors than the back, making it more sensitive to touch. This density of receptors allows the palm to better distinguish two closely spaced points. The difference in receptor density and receptive field sizes results in the increased tactile sensitivity of the palm.
In terms of touch receptor density, you would expect to have more touch receptors on the palm of your hand compared to the back of your hand. This is because areas of the skin with a high density of touch receptors, such as the palms, are more sensitive and can detect finer details. The palm of your hand has many more receptors with smaller receptive fields, which allows it to distinguish between two closely spaced points better than the back of your hand. Skin areas with small receptive fields are better able to distinguish two similarly-spaced points. The palm has a smaller threshold for discerning between two points than the back, a result of the differences in the size of receptive fields.
If you were to perform a two-point discrimination test, you would notice that the minimum distance at which you can perceive two points as separate is much smaller on the palm than on the back of the hand. This increased sensitivity is due to the higher density of touch receptors in the palm, which is essential for tasks that require precise touch, such as gripping objects and feeling textures.
The position of a full moon is located
Answer:
opposite the sun. between the Earth and the sun. rising perpendicular to the sun.
Explanation: