Final answer:
To convert the height of a column of mercury in a barometer to atmospheric pressure in atm and kPa, divide the height of the column by 760 to get the pressure in atm, and then multiply the atmospheric pressure by 101.325 to get the pressure in kPa.
Explanation:
To convert the height of a column of mercury in a barometer to atmospheric pressure in atm and kPa, we can use the conversion factors. At sea level, the standard atmospheric pressure is 760 mm Hg (millimeters of mercury) or 1 atm. Using this information, we can calculate the atmospheric pressure in atm and kPa.
To convert from mm Hg to atm, divide the height of the column by 760:
Atmospheric pressure (in atm) = 754.3 mm Hg / 760 mm Hg = 0.992 atm.
To convert from atm to kPa, multiply the atmospheric pressure by 101.325 (the number of kilopascals in 1 atm):
Atmospheric pressure (in kPa) = 0.992 atm * 101.325 kPa/atm = 100.45 kPa.
Write the chemical equation for the reaction of propylamine, c3h7nh2 with water. (include all phases in your answer)
Answer is:
CH₃-CH₂-CH₂-NH₂ + H₂O(l) ⇄ CH₃-CH₂-CH₂-NH₃⁺(aq) + OH⁻(aq).
Amine group (-NH₂) has neutral charge, bet when accepts one
proton (H⁺) has positive
charge.
Amines are compounds that contain a basic nitrogen atom with a lone pair of electrons. Amines are derivatives of ammonia, where is one or more hydrogen atoms replaced by a substituent such as an alkyl or aryl group (in this compound propyl group).
Propylamine accepts a proton from water according to the reaction equation; C3H7NH2(aq) + H2O(l) ------> C3H7NH3^+(aq) + OH^-
Propylamine is a base because it accepts a proton. Recall that according to Brownstead - Lowry, a base is any substance that accepts a proton while an acid is any substance that donates a proton. Propylamine accepts a proton because of the lone pair on nitrogen atom.
The reaction of propylamine with water is an acid base reaction because propylamine accepts a proton from water as follows;
C3H7NH2(aq) + H2O(l) ------> C3H7NH3^+(aq) + OH^-
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N2(g) + 3h2(g) ⇌ 2nh3(g) the equilibrium constant kc at 375°c is 1.2. starting with [h2]0 = 0.76 m, [n2]0 = 0.60 m and [nh3]0 = 0.48 m, which concentration(s), if any, will have increased when the mixture comes to equilibrium?
To determine which concentration(s) will have increased when the mixture reaches equilibrium, we can compare the reaction quotient (Qc) to the equilibrium constant (Kc):
N2(g) + 3 H2(g) = 2NH3(g)
Qc = (NH3^2) / { (N2)(H)^3)}
Qc= 0.48^2 /{ ( 0.60) (0.760^3) }= 0.875
Qc < Kc therefore the equilibrium will shift to the right. This implies that Nh3 concentration will increase
Calculate Qc using the initial concentrations and the balanced chemical equation.
Compare Qc to Kc:
If Qc < Kc, the reaction will proceed to the right (towards products) to reach equilibrium.
If Qc > Kc, the reaction will proceed to the left (towards reactants) to reach equilibrium.
In this case, if Qc is less than Kc, it indicates that the concentrations of products ([NH₃]) will increase, and the concentrations of reactants ([N₂] and [H₂]) will decrease when the mixture reaches equilibrium.
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Calculate the empirical formula for each natural flavor based on its elemental mass percent composition.
a. methyl butyrate (component of apple taste and smell): c 58.80%, h 9.87%, o 31.33%
What is the pH of a solution of 0.750 M KH2PO4, potassium dihydrogen phosphate?
Final answer:
The pH of a 0.750 M KH₂PO₄ solution cannot be accurately determined without additional information such as the pKa value of the dihydrogen phosphate ion (H₂PO₄₋).
Explanation:
The pH of a solution of 0.750 M KH₂PO₄, potassium dihydrogen phosphate, depends on the acid dissociation constants of phosphoric acid (H₃PO₄), as KH₂PO₄ is its conjugate salt. Typically, to calculate the pH of such a solution, one would use the Henderson-Hasselbalch equation which relates the pH of a buffer solution to the pKa of the acid and the concentrations of the acid and its conjugate base.
However, because there is no other species like phosphoric acid or its other salts present to form a buffer system, and because H₂PO₄₋ (from dissociation of KH₂PO₄) is a weak acid, we may need to approach this problem differently.
Since the direct calculation of pH in this context isn't possible without additional information such as the pKa value of the dihydrogen phosphate ion (H₂PO₄⁻), and because the problem does not ask for assumptions to be made or provide a relevant pKa value, the task cannot be completed.
In practical applications, a pKa value would be required to use the Henderson-Hasselbalch equation, or for the weak acid formula: pH = -log[H⁺] where [H⁺] can be obtained through the equilibrium expression involving the dissociation constant (Ka) and the concentration of H₂PO₄⁻.
Co(g)+h2o(g)⇌co2(g)+h2(g) kp=0.0611 at 2000 k a reaction mixture initially contains a co partial pressure of 1320 torr and a h2o partial pressure of 1760 torr at 2000 k. calculate the equilibrium partial pressure of co2.
We use the expression for Kp in terms of partial pressures, set up an equation incorporating the given initial pressures and the changes in pressure that occur as the reaction proceeds, and solve that equation to find the equilibrium partial pressure of CO2.
Explanation:To answer this question, we need to use the expression for the equilibrium constant (Kp) in terms of partial pressures. Kp is defined as the ratio of the products of the partial pressures of the products, each raised to their stoichiometric coefficients in the balanced chemical equation, to the product of the partial pressures of the reactants, each raised to the power of their stoichiometric coefficients. Based on this, the expression is:
Kp = (pCO2 * pH2) / (pCO * pH2O)
where pCO, pH2O, pCO2 and pH2 are the equilibrium partial pressures of CO, H2O, CO2 and H2 at equilibrium, respectively. We know that initially, the partial pressure of CO2 and H2 is 0 because the reaction has not yet occurred. Also, the initial partial pressures of CO and H2O are given as 1320 torr and 1760 torr respectively.
As reaction proceeds to the right, the pressures of CO and H2O will decrease while that of CO2 and H2 will increase. Let's assume the decrease in the pressures of CO and H2O is by x.
Therefore, at equilibrium:
pCO = 1320 - xpH2O = 1760 - xpCO2 = xpH2 = x
So, plug these values into the Kp expression we get:
0.0611 = (x*x) / {[1320 - x]*[1760 - x]}
Solving this quadratic equation will give the value of x.
Substituting 'x' in pCO2 = x will give us the equilibrium partial pressure of CO2.
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The equilibrium partial pressure of CO2 in a chemical reaction can be calculated using an ICE table and the given Kp value in the application of Le Chatelier's principle.
Explanation:The subject of this question is the calculation of the equilibrium partial pressure of CO2 in a chemical reaction according to Le Chatelier’s principle. We first identify the given Kp value and initial partial pressures for CO and H20. Using the equation for the reaction, CO(g) + H2O(g) ⇌ CO2(g) + H2(g), we can create an ICE (Initial, Change, Equilibrium) table to track changes in the partial pressures during the reaction. As the reaction proceeds, the concentrations of CO and H2O decrease while those of CO2 and H2 increase until equilibrium is reached. The changes for CO and H2O are negative while those for CO2 and H2 are positive. Using the equilibrium expressions and the given Kp value, we can solve for the change and add this to the initial concentrations to get the equilibrium concentrations.
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(r)-2-butanol reacts with phosphorus tribromide to give a (c4h9br). treatment of a with sodium cyanide in dmf gives b (c5h9)n. b is optically active. draw the structure of
b.
The structure of B is
H
|
H3C - C ≡ N
|
H
The reaction of (R)-2-butanol with phosphorus tribromide (PBr3) undergoes substitution reaction, replacing the hydroxyl group with a bromine atom, resulting in compound A, which is 2-bromobutane (C4H9Br).
Compound A is then treated with sodium cyanide (NaCN) in dimethylformamide (DMF), undergoing a nucleophilic substitution reaction. The cyanide ion replaces the bromine atom, forming compound B, which is 2-butyne nitrile (C5H9N).
Compound B is optically active due to the presence of the chirality at the carbon atom adjacent to the nitrile group. The carbon atom bonded to the nitrogen and the two methyl groups creates a chiral center, resulting in optical activity.
The specific rotation of B would depend on the configuration of the chiral carbon.
Complete Question:
(R)-2-butanol reacts with phosphorus tribromide to give A (C_4H_9Br). Treatment of A with sodium cyanide in DMF gives B (C_5H_9) N. B is optically active. Draw the structure of B.
The reaction of hydrogen peroxide with iodine, h2o2(aq)+i2(aq)⇌oh−(aq)+hio(aq) is first order in h2o2 and first order in i2. if the concentration of h2o2 was increased by half and the concentration of i2 was quadrupled, by what factor would the reaction rate increase?
The reaction rate for H₂O₂(aq) + I₂(aq) ⇌ OH⁻(aq) + HIO(aq) increases by a factor of 6 when the concentration of H₂O₂ is increased by half and the concentration of I₂ is quadrupled.
The rate of a reaction is influenced by the concentrations of the reactants. For the reaction H₂O₂(aq) + I₂(aq) ⇌ OH⁻(aq) + HIO(aq), the rate law is given by: Rate = k[H₂O₂][I₂]
This indicates that the reaction is first order with respect to both H₂O₂ and I₂.
Step-by-Step Explanation:
Initial Reaction Rate: The initial rate can be expressed as Rate_initial = k[H₂O₂]₀[I₂]₀.Change in Concentrations: The concentration of H₂O₂ is increased by half (1.5 times) and the concentration of I₂ is quadrupled (4 times).New Rate Calculation: The new rate can be expressed as Rate_new = k(1.5[H₂O₂]₀)(4[I₂]₀).Rate Increase Factor: To determine by what factor the rate increases, divide the new rate by the initial rate:Rate increase factor = (k(1.5[H₂O₂]₀)(4[I₂]₀)) / (k[H₂O₂]₀[I₂]₀) = 1.5 * 4 = 6.
Therefore, the reaction rate increases by a factor of 6.
Write balanced chemical equations for the two ionization steps of sulfuric acid
Sulfuric acid ionizes in two steps, each releasing a hydrogen ion to form first the bisulfate ion and then the sulfate ion. The first is H2SO4 (aq) → H+ (aq) + HSO4- (aq) and the second is HSO4- (aq) → H+ (aq) + SO4^2- (aq).
Explanation:The ionization of sulfuric acid (H2SO4) in water occurs in two steps. Each step involves the release of a hydrogen ion (H+), and the corresponding production of the hydronium ion (H3O+) is generally implied when the acid ionizes in aqueous solution.
First Ionization: H2SO4 (aq) → H+ (aq) + HSO4- (aq).This is the first ionization step where one hydrogen ion is released, creating the bisulfate ion (HSO4-).
Second Ionization: HSO4- (aq) → H+ (aq) + SO4^2- (aq). In the second ionization step, the bisulfate ion (HSO4-) releases a second hydrogen ion, resulting in the sulfate ion (SO4^2-).
Both of these equations are balanced chemical equations that depict the stepwise ionization of sulfuric acid and the formation of its conjugate bases.
if f(x)= 5x^3 -2 and g(x) =2x+1, find (f+g)(x)
a. 10x^3 -2
b. 3x^3 -1
c. 5x^3+2x-1
d. 3x^2 -1
The reaction 2a → a2 was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if the initial concentration of a was 4.00 m, what was the concentration of a (in m) after 180.0 min?
The integrated rate law for a second-order reaction is given by:
[tex] \frac{1}{[A]t} = \frac{1}{[A]0} + kt [/tex]
where, [A]t= the concentration of A at time t,
[A]0= the concentration of A at time t=0
k = the rate constant for the reaction
Given: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min
Hence, [tex] \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180) [/tex]
= 4.858
Therefore, [A]t= 0.2058 M.
Answer: Concentration of A, after 180 min, is 0.2058 M
Consider these reactions, where M represents a generic metal. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)ΔH1=−556.0 kJ HCl(g)⟶HCl(aq) ΔH2=−74.8 kJ H2(g)+Cl2(g)⟶2HCl(g) ΔH3=−1845.0 kJ MCl3(s)⟶MCl3(aq) ΔH4=−342.0 kJ Use the given information to determine the enthalpy of the reaction 2M(s)+3Cl2(g)⟶2MCl3(s)
The enthalpy of formation of [tex]\rm MCl_3[/tex] will be -5849 kJ.
The given reactions represent:
Enthalpy of reaction of M with HCl = [tex]\rm \Delta H_1[/tex] = -556 kJ
Enthalpy of sublimation of HCl = [tex]\rm \Delta H_2[/tex] = -74.8 kJ
Enthalpy of HCl formation = [tex]\rm \Delta H_3[/tex] = -1845 kJ
Enthalpy of sublimation of [tex]\rm MCl_3\;=\;\Delta H_4[/tex] = -342.0 kJ
The enthalpy of formation of [tex]\rm MCl_3[/tex] will be: [tex]\rm \Delta H_5[/tex]
[tex]\rm \Delta H_5[/tex] = [tex]\rm \Delta H_1\;+\;6\;\times\;\Delta H_2\;+\;3\;\times\;\Delta H_3\;-\;2\;\times\;\Delta H_4[/tex]
= -550 + 6 (-74.8) + 3 (-1845) - 2 (342)
= -5849 kJ.
The enthalpy of formation of [tex]\rm MCl_3[/tex] will be -5849 kJ.
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The sticky top of the pistil that collects the pollen (sperm) is the _______. ovary
style
stigma
anther
dentify which stage of the listening process is occurring in the following scenario.
Janie excitedly told her mom about a party her friend Reeve had invited her to. She promised that there would be adult supervision and begged to be allowed to go. Her mom hesitated and then said she wanted to talk to Reeve's parents first.
selecting
understanding
evaluating
responding
remembering
In this situation, the listening process stage being implemented is 'evaluating'. Janie's mom is assessing the details of the party and deciding about its validity and reliability, which indicates this stage.
Explanation:In the given scenario, the stage of the listening process that is taking place is evaluating. The event happens as Janie's mom listens to Janie's account of the party and makes a judgment about it. It means she's weighing the information she has received and is deciding on its validity and reliability. After listening to the information, she makes an evaluation that requires her to speak to Reeve's parents first before making a decision. This is the evaluating stage, where she is assessing and judging the information she has received.
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Describe how you would prepare a supersaturated solution.
Answer:
To prepare a supersaturated solution, the added amount must be higher than the solubility for the given volume of solvent
Explanation:
Hello,
This could be answered by knowing that all the solutes have a property called solubility which accounts for the maximum amount of it that can be thoroughly dissolved into a specific solvent. Thus, to prepare a supersaturated solution, the added amount must be higher than the solubility for the given volume of solvent at a specific temperature. For example, at 20°C, 45.8g of aluminium chloride are completely dissolved into 100 mL of water, so at that amount, the solution will be saturated, thus, if one adds more than 45.8g the solution will start being supersaturated.
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Calculate the heat capacity, in joules per degree and in calories per degree, for 45.8 g of nitrogen gas. [heat capacity of n2(g)= 1.04j/g0c] [1 cal=4.184j]
Answer : The heat capacity in joules per degree Celsius and calories per degree Celsius is, [tex]47.6J/^oC[/tex] and [tex]11.4cal/^oC[/tex] respectively.
Explanation : Given,
Mass of nitrogen gas = 45.8 g
Heat capacity of nitrogen gas = [tex]1.04J/g^oC[/tex]
First we have to calculate the heat capacity in joules per degree Celsius.
As, 1 gram of nitrogen gas has heat capacity = [tex]1.04J/^oC[/tex]
So, 45.8 gram of nitrogen gas has heat capacity = [tex]45.8\times 1.04J/^oC=47.6J/^oC[/tex]
Thus, the heat capacity in joules per degree Celsius is [tex]47.6J/^oC[/tex]
Now we have to calculate the heat capacity in calories per degree Celsius.
As we are given the conversion:
[tex]1cal=4.184J\\\\1J=\frac{1}{4.184}cal[/tex]
So, the heat capacity of nitrogen gas = [tex]\frac{1}{4.184}cal\times 47.6\text{ per }^oC=11.4cal/^oC[/tex]
Thus, the heat capacity in calories per degree Celsius is [tex]11.4cal/^oC[/tex]
The heat capacity, in Joules per degree Celsius and in calories per degree Celsius are 47.632 J/g°C and 11.384 cal/g°C respectively.
Given the following data:
Mass of nitrogen gas = 45.8 gramsHeat capacity of nitrogen gas = 1.04 J/g°CTo find the heat capacity, in Joules per degree Celsius and in calories per degree Celsius:
By direct proportion:
1 gram of nitrogen gas = 1.04 J/g°C
45.8 grams of nitrogen gas = X J/g°C
Cross-multiplying, we have:
[tex]X = 45.8 \times 1.04[/tex]
X = 47.632 J/g°C.
Therefore, the heat capacity, in Joules per degree Celsius, for 45.8 grams of nitrogen gas is 47.632 J/g°C.
In calories per degree Celsius:
1 calorie = 4.184 Joules
Y calorie = 47.632 Joules
Cross-multiplying, we have:
[tex]Y \times 4.184 = 47.632\\\\Y = \frac{47.632}{4.184}[/tex]
Y = 11.384 cal/g°C.
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: calculate the mass of the solute in 1.500 l of 0.30 m glucose, c6h12o6, used for intravenous injection
Looking across period 4 of the periodic table, potassium (atomic number 19) is followed by calcium (atomic number 20), which is followed by scandium (atomic number 21). Which element should have the largest atomic radius? A) potassium B)calcium C)scandium D)All three have the same atomic radius.
According to trends in the periodic table, the atomic radius decreases from left to right across a period. Therefore, potassium, being furthest to the left, would have the largest atomic radius followed by calcium and then scandium.
Explanation:The subject of this question is the atomic radius of elements on the periodic table, specifically potassium, calcium, and scandium. The atomic radius generally decreases as you go from left to right across a period in the periodic table due to the increasing positive charge of the nucleus (i.e., the increasing atomic number), which draws the electrons closer to the nucleus, thereby decreasing the atomic radius.
In the case of potassium (atomic number 19), calcium (atomic number 20), and scandium (atomic number 21)
, potassium should have the largest atomic radius, followed by calcium, and then scandium with the smallest atomic radius.
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Two teaspoons of salt are added to a glass of water which is then stirred until no more salt grains can be seen. Two more teaspoons are added and stirring is continued, but the salt grains are still evident in the glass and settle to the bottom. After the addition of the last two teaspoons of salt the solution is ___________________________.
nonpolar
polar
saturated
unsaturated
Answer: C
Explanation: I got it right
name two fluid technologies that make use of water
Answer:
Fire extenguisher and refrigerator
Explanation:
Refrigerator : There are 5 basic components in refrigeration I.e. fluid refrigerant, a compressor which controls the flow of refrigerant; the condensor coil( on the outside of the fridge), evaporation coils( on the inside of the fridge) and something calls an expansion device.
The compressor constricts the refrigerant vapour,raising its pressure and pushes it in the coils on the outside of the refrigerator.When the hot gas in the coils meets the cooler air temperature of the kitchen it becomes a liquid.Now in the liquid form at high pressure, the refrigerant cools down as it flows into the coils inside the freezer and the fridge.The refrigerant absorbs the heat inside the fridge cooling down the air.Last the refrigerant evaporates to a gas then flows back to the compressor where the cycle starts all over.Fire Extinguishers: Water performs two functions; its conversion tosteam absorbs the heat, and the steam displaces the air from the vicinity of the flame. Many siimple fire extinguishers are quipped with hand pumps or sources of compressed gas to propel water through the nozzle.
Hydraulic systems and water turbines are two fluid technologies that make use of water. Hydraulic systems use water or other fluids to transmit force or energy, while water turbines use the flow of water to generate mechanical energy and produce electricity.
Explanation:Two fluid technologies that make use of water are hydraulic systems and water turbines.
Hydraulic systems: These systems use water or other fluids to transmit force or energy. They are commonly used in heavy machinery, such as bulldozers and cranes. The force applied to a small piston can be amplified to produce a much larger force on a larger piston. This is done by Pascal's law, which states that a change in pressure of an enclosed fluid is transmitted uniformly in all directions.Water turbines: These devices use the flow of water to generate mechanical energy, which is then converted into electrical energy. Water turbines are often used in hydroelectric power plants, where the force of flowing water is used to turn the blades of the turbine, which in turn spins a generator to produce electricity.Learn more about Fluid technologies that make use of water here:https://brainly.com/question/9035490
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Give the formula for the conjugate base of the strong acid hclo4 (perchloric acid).
The formula for the conjugate base of the strong acid HClO₄ (perchloric acid) is ClO4⁻.
The conjugate base of an acid is formed when the acid donates a proton (H+) to a base. In the case of perchloric acid (HClO₄), the conjugate base is derived by removing the acidic hydrogen ion (H+) from the acid.
The formula for the conjugate base of HClO₄, known as perchlorate ion, is ClO₄-. The perchlorate ion has a negative charge (-1) due to the loss of the hydrogen ion from the acid.
The perchlorate ion is the conjugate base of perchloric acid. Its chemical formula is ClO4-. The perchlorate ion consists of one chlorine atom (Cl) bonded to four oxygen atoms (O) in a tetrahedral arrangement.
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part a: What volume of 10.0 M NaOH is needed to prepare a buffer with a pH of 7.79 using 31.52 g of TrisHCl?
answer : 6.7ml
Part B: The buffer from Part A is diluted to 1.00 L. To half of it (500. mL), you add 0.0200 mol of hydrogen ions without changing the volume. What is the pH of the final solution?
answer : pH 7.28
Part C: What additional volume of 10.0 M HCl would be needed to exhaust the remaining capacity of the buffer after the reaction described in Part B? In other words, how much more of this HCl solution is required to consume the remaining Tris in the buffer?
HELP ME FOR PART C PLEASE!!!
To calculate the volume of 10.0 M HCl needed to exhaust the remaining capacity of the buffer, determine the moles of TrisHCl remaining after adding hydrogen ions and use stoichiometry to calculate the required volume.
Explanation:To calculate the additional volume of 10.0 M HCl needed to exhaust the remaining capacity of the buffer, we need to determine the number of moles of TrisHCl that remain after adding 0.0200 mol of hydrogen ions to half of the buffer. This will give us the amount of TrisHCl that needs to be neutralized. From there, we can calculate the volume of 10.0 M HCl needed to neutralize the remaining TrisHCl.
First, calculate the moles of TrisHCl in the initial buffer solution. Use the given mass of TrisHCl (31.52 g) and its molar mass to calculate the moles.Next, calculate the moles of TrisHCl that were neutralized by adding 0.0200 mol of hydrogen ions. Subtract this value from the moles of TrisHCl calculated in step 1.Finally, calculate the additional volume of 10.0 M HCl needed to neutralize the remaining moles of TrisHCl. Use the balanced equation for the reaction between TrisHCl and HCl to determine the stoichiometric ratio between the two substances.The calculated volume will be the additional volume of 10.0 M HCl needed to exhaust the remaining capacity of the buffer.
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An additional 18 mL of 10.0 M HCl is required to exhaust the remaining capacity of the buffer. This is determined by calculating the amount of Tris that remains unreacted and can further neutralize HCl.
What additional volume of 10.0 M HCl would be needed to exhaust the remaining capacity of the buffer after the reaction described in Part B?
First, we need to understand the capacity of the buffer system. From Part A, we have 31.52 g of TrisHCl.
Step 1: Calculate the moles of TrisHCl.
Molecular Weight of TrisHCl = 157.60 g/molMoles of TrisHCl = 31.52 g / 157.60 g/mol = 0.20 molStep 2: Calculate the initial moles of Tris (conjugate base) and TrisH+ (conjugate acid).
From Part B, 0.0200 mol of hydrogen ions were added to the buffer.This will react with 0.0200 mol of Tris to form TrisH+, leaving 0.18 mol of Tris and 0.20 mol of TrisH+.Step 3: Determine the remaining capacity to neutralize more HCl.
Moles of Tris available to react = 0.18 mol (since it can accept more H+ from HCl).Step 4: Calculate the volume of 10.0 M HCl needed to exhaust the buffer.
Moles of HCl needed = 0.18 molVolume of HCl = Moles / Concentration = 0.18 mol / 10.0 M = 0.018 L = 18 mLTherefore, an additional 18 mL of 10.0 M HCl is required to exhaust the remaining capacity of the buffer.
An experiment carries out the reaction a → products at three different initial concentrations of a and the initial reaction rate were measured, as indicated in the table. [a](m) initial rate (m/s) 0.15 0.010 0.30 0.040 0.45 0.090 based on this data, what is the rate law for the reaction? view available hint(s) an experiment carries out the reaction at three different initial concentrations of and the initial reaction rate were measured, as indicated in the table. initial rate 0.15 0.010 0.30 0.040 0.45 0.090 based on this data, what is the rate law for the reaction? rate = k[a]2 rate = k[a]3 rate = k[a] rate = k
What is the formula for copper(ii) phosphate? capitalization and punctuation count!?
classify correct or incorrect.
Convection only occurs in liquids?
All substances radiate heat?
our body temp. is always equal to the temp. around us?
Answer:
1. Incorrect, it occurs in gases as well or generally in fluids.
2. Correct.
3. Incorrect.
Explanation:
Hello,
1. Convection, is a heat transport phenomena which occurs when a fluid transfers energy in the form of heat to a surface or vice-versa, in such a way, it occurs fluid, say, in both gases and liquids.
2. In this case, radiation is a heat transfer phenomena which occurs by thermal waves transferring the heat; such waves are generated by a hot body which it is said to irradiate the waves by cause of its inner temperature, therefore, as it could be surrounded by a colder space, heat is transferred. As a result of the high temperature, all substances could radiate heat.
3. In this case, it is widely known that normal temperature is between 20 and 25 ºC while the body's inner temperature is about 37 ºC for our organism to work properly. In such a way, those temperatures are different.
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Rust is formed by the interaction of iron and oxygen. When rust formed on an iron nail with a mass of 100g,the mass of the rusted nail was 143g. What mass of oxygen gas most likely reacted with the iron nail?
Final answer:
The mass of oxygen gas that reacted with the iron nail to form rust was 43 grams, which is the difference between the original mass of the iron nail (100g) and the mass after rusting (143g).
Explanation:
The mass of oxygen gas that most likely reacted with the iron nail to produce rust can be calculated by finding the difference in mass before and after the rusting process. Initially, the mass of the iron nail was 100g, and after rust formation, the mass increased to 143g. The increase in mass is due to the oxygen from the air reacting with the iron to form rust, which consists of hydrated iron(III) oxide.
Therefore, the mass of the oxygen that reacted with the iron nail can be calculated as follows:
Mass of rusted nail - Original mass of iron nail = Mass of oxygen
143g - 100g = 43g
Thus, 43 grams of oxygen reacted with the iron nail to form rust.
convert the following names to balanced formulas.
lead(IV) sulfide
why is it not Pb2S4 ?
The balanced chemical formula for lead(IV) sulfide is PbS₂, not Pb₂S₄. This correctly balances lead's +4 charge with two sulfur atoms, each with a -2 charge.
Lead(IV) sulfide is a chemical compound consisting of lead (Pb) and sulfur (S). The Roman numeral IV indicates that lead has an oxidation state of +4 in this compound. Sulfur commonly has an oxidation state of -2.
To form a neutral compound, we need to balance the charges. Lead(IV) has a charge of +4, and sulfur has a charge of -2. Therefore, it takes two sulfur atoms to balance one lead atom.
The balanced chemical formula for lead(IV) sulfide is PbS₂, not Pb₂S₄. The latter formula incorrectly represents the proportions since it can be simplified to PbS₂, as both share the same ratio.
Lead (IV) Sulfide: PbS₂Lead has an oxidation state of +4 (Pb₄+).Sulfur has an oxidation state of -2 (S₂-).The formula must balance to zero, i.e., 1(4+) + 2(2-) = 0.Thus, the correct balanced chemical formula is PbS₂.
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