The law of conservation of mass and how it applies to chemical changes

Answers

Answer 1
The law of conservarion of mass states that mass can neither be destroyed nor created, but only changed into other forms. So through chemical reactions, the chemical makeup may change but the amount of substance is still equal to the sum of the amount of original chemicals before the reaction.
Answer 2

According to law of conservation of mass, mass is neither created nor destroyed and hence for a chemical reaction the mass of reactants and products is equal.

What is law of conservation of mass?

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.

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Related Questions

What volume of O2(
g. at 810. mmHg pressure is required to react completely with a 4.50g sample of C(s) at 48°C? 2 C(s) + O2(
g. → 2 CO(
g.

Answers

Answer is: volume of oxygen is 4.63 liters.
Balanced chemical reaction: 2C + O₂ → 2CO.
m(C) = 4.50 g.
n(C) = m(C) ÷ M(C).
n(C) = 4.50 g ÷ 12 g/mol.
n(C) = 0.375 mol.
From chemical reaction: n(C) : n(O₂) = 2 : 1.
n(O₂) = 0.1875 mol.
T = 48°C = 321.15 K.
p = 810 mmHg ÷ 760 mmHg/atm= 1.066 atm.
R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
V(O₂) = n·R·T / p.
V(O₂) = 0.1875 mol · 0.08206 L·atm/mol·K · 321.15 K / 1.066 atm.
V(O₂) = 4.63 L.

A 5.00 L sample of helium at STP expands to 20.0 L. What is the new pressure on the gas?

Answers

Answer is: the new pressure on the gas is 0.25 atm or 25.33 kPa.
Boyle's Law: the pressure volume law - volume of a given amount of gas held  varies inversely with the applied pressure when the temperature and mass are constant.
p₁V₁ = p₂V₂.
1 atm · 5.00 L = p₂ · 20.0 L.
p₂ = 1 atm · 5 L ÷ 20.0 L.
p₂ = 0.25 atm, but same amount of helium.

An element found in another galaxy exists as two isotopes. if 80.0 percent of the atoms have an atomic mass of 80.00 atomic mass units and the other 20.0 percent have an atomic mass of 82.00 atomic mass units, what is the atomic mass of the element?

Answers

relative atomic mass of the element is the weighted average atomic mass of the element with regard to the abundance of the isotopes in nature.
atomic mass of the element is the sum of the products of the isotope mass by the percentage abundance of that isotope 
isotope 1 - abundance 80 % - 80.00 a.m.u
isotope 2 - abundance 20 % - 82.00 a.m.u 
atomic mass = 80.00 x 80% + 82.00 x 20% 
                     = 64.00 + 16.40 = 80.40 a.m.u
atomic mass of the element is 80.40 a.m.u

Which quantity or quantities must always be the same on both sides of a chemical equation? (a) the number of atoms of each kind (b) the number of molecules of each kind (c) the number of moles of each kind of molecule (d) the sum of the masses of all substances involved?

Answers

Explanation:

An equation that contains same number of atoms on both reactant and product side is known as a balanced chemical equation.

Also, mass of substances involved and formed in a chemical reaction will be equal.

For example, [tex]2K + Cl_{2} \rightarrow 2KCl[/tex]

Number of K atoms on both reactant and product side are 2.

Number of Cl atoms on both reactant and product side are 2.

Therefore, this equation is balanced.

Also, mass of K = 39.09 g/mol, mass of Cl = 35.45 g/mol.

Sum of reactant molecules = [tex](2 \times 39.09 g/mol) + (2 \times 35.45 g/mol)[/tex]

                                             = 149.08 g/mol

Sum of product molecules = [tex]2 \times (39.09 g/mol + 35.45 g/mol)[/tex]

                                             = 149.08 g/mol

Therefore, masses of atoms involved is same on both reactant and product side.

Thus, we can conclude quantity or quantities that must always be the same on both sides of a chemical equation are as follows.

the number of atoms of each kind.the sum of the masses of all substances involved.

The quantities which must always be the same on both sides of a chemical equation is:

(a) the number of atoms of each kind.

(d) the sum of the masses of all substances involved.

A chemical reaction refers to a chemical process that involves the rearrangement or transformation of the ionic, atomic or molecular structure of a chemical element through the breakdown and formation of chemical bonds in order to produce a new compound.

A chemical equation is typically used to denote or represent a chemical reaction between two or more chemical elements.

A balanced chemical equation is one in which the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

This ultimately implies that, both the charge on each atom and sum of the masses of the chemical substances in a chemical equation are properly balanced.

Additionally, all chemical equations must be in accordance with the Law of Conservation of Mass because mass can neither be created nor destroyed.

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What will be the effect on the amount of gas produced if the experiment is repeated using 0.35g of k?

Answers

Hello there, I believe you are practicing for the AP Chemistry exam. If you are, so am I :) 

Anyways, the answer is that some gas will be produced but less than the amount of gas produced by Li.

To understand this, we first need to look at the number of moles we have of each substance. For 0.35 grams of Li, we have an estimated value (I am estimating because the multiple choice of the exam is non calculator) of 0.05 moles. For K however, we have an estimated value of 0.01 moles used.

Now look at the two equations: 2K +3H2O ---> 2H2 + 2K(OH)
                                                  2Li +3H2o ---> 2H2 +2Li(OH)
In the question, it specifies that H2 gas is produced as a product. Because both equations produce H2 in a 2:2  ratio (or a simplified ratio of 1:1), 0.05 moles of H2 will be produced for the Li equation, while 0.01 moles of H2 will be produced for the K equation. Therefore, the Li produces more moles of gas than K. 

I hope that makes sense. Happy studying :)

The effect on the amount of gas produced if the experiment is repeated using 0.35g of potassium is that less amount of hydrogen gas is produced.

What is the stoichiometry?

Stoichiometry of any reaction gives idea about the amount of species present and before the completion of the reaction.

Chemical reaction with repect to Lithium (Li) and Potassium (K) will be represented as:

2K + 3H₂O → 2H₂ + 2KOH

2Li + 3H₂O → 2H₂ + 2LiOH

From the stoichiometry of the reaction it is clear that 2 moles of K & Li produces 2 moles of hydrogen gas.

Moles will be calculated as:

n = W/M, where

W = given mass = 0.35g

M = molar mass

Moles of 0.35g Li = 0.35 / 6.9 = 0.0507 moles

Moles of 0.35g K = 0.35 / 39 = 0.0089 moles

From the moles of both elements it is clear that lithium will produce more gas.

Hence on replacing lithium with potassium, less gas will be produced.

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Help Please earth science

Answers

Use the image to determine which of the following statements is true?

1) The granite is younger than unit B.2) Unit B and the granite are the same age.3) The relative ages of teh granite and unit B cannot be determined from the information given.4) Unit B is younger than the granite.

Which reaction may be described as an acid-base neutralization reaction? 1. be(oh)2 + h2so4 → beso4 + 2 h2o 2. ba(oh)2 + 2 licl → bacl2 + 2 lioh 3. naoh + h2o → h3o + + nao− 4. hno2 + h2o → h3o + + no− 2?

Answers

 The reaction that describe an acid an acid- base neutralization reaction is

Be(OH)2 + H2SO4 = BeSO4 +2 H2O

Neutralization reaction involve an acid  and a base reaction whereby the acid  neutralization the base. for the reaction above Be(OH)2 is  the base while H2SO4 is the acid  thus H2SO4  neutralizes  Be(OH)2 to form BeSO4 and H2O

The energy stored in the motion or vibration of molecules in a substance is a definition for
A. heat.
B. work.
C. radioactivity.
D. electromagnetism.

Answers

the answer is A.

A: heat

plz give me brainliest <3

Why might someone choose to use U-238 over C-14 to determine the age of a specimen?

Answers

Carbon 14 and and Uranium 238 are not used together to determine fossil ages, because of the huge differences in the half lives of C -14 and U -238 that cannot be used together. C -14 can only be used to date fossils of a very recent age. U -238 can only be used to date volcanic rocks of a very old age. 
I hope I helped you :) 

The half life of C-14 is 5700 years and that of U-238 is 4.5 billion years. So U-238 can be used to determine the age of ancient objects. U-238 is used to date the age of the Earth. U-238 is found in volcanic rocks but not in fossils. Fossils contain C-14 only. C-14 is used to date fossils of recent age.

A gas is contained in a thick walled balloon. when the pressure changes from 417 mm hg to 576 mm hg, the volume changes from ____ L to 4.78 L and the temperature changes from 497 K to 386 K

Answers

Initial volume is 8.5. Could I get best answer??

Answer: 8.5

Explanation:

When bismuth-212 undergoes alpha decay, it becomes which of the following?


A asatine-208 + an alpha particle
B lead-210 + an alpha particle
C polonium-210 + and alpha particle
D thallium-208 + and alpha particle

Answers

Answer is: D thallium-208 + and alpha particle.
Nuclear reaction: ²¹²Bi → ²⁰⁸Tl + α (alpha particle).
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

Le Châtelier's principle tells us that chemical _____ will adjust in an attempt to remove a stressor.
a. formulas
b. equations
c. equilibrium
d. concentrations

Answers

Le Châtelier's principle tells us that chemical c. equilibrium will adjust in an attempt to remove a stressor.

"what is the concentration of positive charge and mass in rutherford's atomic model called?"

Answers

The concentration of positive charge and mass in Rutherford's atomic model is called the nucleus. Rutherford's experiments involving the use of alpha particle beams directed onto thin metal foils demonstrated the existence of the nucleus. The nucleus of an atom contains positively charge particles called protons and other uncharged particles called neutrons. According to this model most volume of an atom is made up of an empty space. 

Calculate h3o+ in an aqueous solution that is 0.10M NaNO2 and 0.055M HNO2

Answers

Answer is: concentration of hydronium ions is 8.13·10⁻⁴ M.
c(HNO₂) = 0.055 M.
c(NaNO₂) = 0.10 M.
Ka(HNO₂) = 4.5·10⁻⁴.
This is buffer solution, so use Henderson–Hasselbalch equation: 
pH = pKa + log(c(NaNO₂) ÷ c(HNO₂)).
pH = -log(4.5·10⁻⁴) + log(0.055 M ÷ 0.10 M).
pH = 3.35 - 0.26.
pH = 3.09.
[H₃O⁺] = 10∧(-3.09).
[H₃O⁺] = 8.13·10⁻⁴ M.

Differences in which property allows the separation of a sample of sand and sea water by filteration

Answers

Answer:
            Differences in Particle Size allows the separation of a sample of sand and sea water by filtration.

Explanation:
                     This is a very simple example which can be conducted at home. When Salt dissolved in water is filtered all the solution get passed through filter paper, while solution of sand and water on filtration separates the sand from water. This is because of the particle size. The size of Na⁺ and Cl⁻ ions are very small and can easily pass through the pores of filter paper, while the size of sand particles are very large and fails to pass through the pores of filter paper.

Filtration is a type of process in which components of a mixture are separated based in the size. The sea water and sand can be separated by filtration due to different particle size.

Seawater is a mixture of several substances, including salt, sand, and stones. The substances of seawater can be separated via filtration. The filter paper in this technique separates the substances based on the size of particles.

The filtration separates sand and seawater as:

Seawater and sand are dissolved in each other. When the filtration technique is performed, it separates out the water from sand. The size of the sand particles are larger than the pore size of filter paper, thus, it easily separates the sand from seawater.

Therefore, difference in the particle size allows the separation of seawater and sand.

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Which must be the same when comparing 1 mol of oxygen, O2, with 1 mol of carbon monoxide has, CO?

Answers

Answer: 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.

Justification:


Althought the question is too open, other answers may arise, the most remarkable similarity between the two compounds is that both are diatomic.

That means that both molecules oxygen, O₂, and carbon monoxide, CO have two atoms.

So, 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.


You must remember that 1 mol means a specific number. It is Avogadro's number, which is 6.022 × 10 ²³.

So 1 mol of CO and 1 mol of O₂ are the same number of representative particles: 6.022 ×10²³ molecules eac, and two times that number of atoms each (since each molecule has two atoms).

What can the size and shape of a sand dune tell you about how it was formed?

Answers

It could tell you how much mass contains inside

Iron, an important component of the steel used in the construction of buildings, bridges, and railroads, combines with oxygen to form fe2o3, which we recognize as rust. at room temperature, iron

Answers

I don't understand, what you want?

What mass of KBr is present in 25 mL of a 0.85 M solution of potassium chloride?

Answers

Answer : The correct answer for mass of KBr = 2.53 g

Given :

Molarity of KBr solution = 0.85 M

Volume of KBr solution = 25 mL

Converting volume from mL to L ( 1 L = 1000 mL )

[tex] Volume of solution = 25 mL * \frac{1 L }{1000mL} [/tex]

Volume of solution = 0.025 L

Mass of KBr = ?

Mass of KBr can be calculated using following steps :

1) To find mole of Kbr :

Mole of KBr can be calculated using molarity .

Molarity : It is defined as mole of solute present in volume of solution in Liter .

It uses unit as M or [tex] \frac{mol}{L} [/tex]

It can be expressed as :

[tex] Molarity = \frac{mol of solute (mol)}{volume of solution (L)} [/tex]

Plugging value of molarity and volume

[tex] 0.85 \frac{mol}{L} = \frac{mol of Kbr}{0.025 L} [/tex]

Multiplying both side by 0.025 L

[tex] 0.85 \frac{mol}{L} * 0.025 L = \frac{mole of KBr}{0.025 L} * 0.025 L [/tex]

Mole of KBr = 0.02125

2) To find mass of Kbr :

Mass of Kbr can be calculated using mole . Mole can be expressed as :

[tex] Mole (mol) = \frac{mass (g) }{molar mass \frac{g}{mol} } [/tex]

Mole of Kbr = 0.02125 mol

Molar mass of KBr = 119.00 [tex] \frac{g}{mol} [/tex]

Plugging values in mole formula

[tex] 0.02125 mol = \frac{mass (g)}{119.00 \frac{g}{mol}} [/tex]

Multiplying both side by 119.00 [tex] \frac{g}{mol} [/tex]

[tex] 0.02125 mol * 119.00 \frac{g}{mol} = \frac{mass (g)}{119.00 \frac{g}{mol}} * 119.00\frac{g}{mol} [/tex]

Mass of KBr = 2.53 g


Final answer:

To find the new volume of a diluted 0.885 M KBr solution after dilution to 0.500 M, use the formula (M1×V1) / M2, resulting in a new volume of 266.85 mL.

Explanation:

The subject of this question is determining the new volume of a diluted potassium bromide (KBr) solution in chemistry. When a 0.885 M solution of KBr with an initial volume of 76.5 mL is diluted to a concentration of 0.500 M, we can use the concept of molarity (M), which is defined as moles of solute per liter of solution, to find the new volume.

To find the new volume (V2) after dilution, we can apply the formula M1×V1 = M2×V2, where M1 and V1 are the initial molarity and volume, and M2 is the final molarity. By rearranging the formula, V2 = (M1×V1) / M2. Substituting the given values, we get V2 = (0.885 moles/L × 76.5 mL) / 0.500 moles/L = 133.425 mL / 0.500 = 266.85 mL. Thus, the new volume is 266.85 mL.

What is the most abundant gas in our atmosphere?
1. oxygen
2. hydrogen
3. nitrogen
4. water

Answers

Nitrogen <---- Itś at 73% of Earths atmosphere.
3. Nitrogen. It's 73% of the Earth's atmosphere.

calculate the pressure in atm, if 0.00825 moles occupies 174 mL at -15 celcius.

Answers

Answer is: the pressure is 1.12 atm.
n(O₂) = 0.00825 mol, amount of substance.
V = 174 mL ÷ 1000 mL/L = 0.174 L, volume of gas.

T = 15°C = 288.15 K; temperature.
R = 0.08206 L·atm/mol·K, universal gas constant.
Ideal gas law: p·V = n·R·T.
p = n·R·T / V.
p = 0.00825 mol · 0.08206 L·atm/mol·K · 288.15 K / 0.174 L.
p = 1.12 atm.


The pressure is calculated using the Ideal Gas Law. Given the moles, volume in liters, and temperature in Kelvin, the pressure is approximately 0.100 atm. This calculation involves converting units and applying the gas constant.

To calculate the pressure in atmospheres (atm) given the number of moles, volume, and temperature, we need to use the Ideal Gas Law formula:

PV = nRT

Here:

P is the pressure in atm.V is the volume in liters. Since the given volume is in milliliters (174 mL), we need to convert it to liters:

        174 mL × 0.001 L/mL = 0.174 L.

n is the number of moles, which is 0.00825 moles.R is the ideal gas constant, which is 0.0821 (L atm)/(K mol).T is the temperature in Kelvin. We need to convert the temperature from Celsius to Kelvin:

        T = -15 °C + 273 = 258 K.

Now, we substitute the known values into the Ideal Gas Law equation:

P × 0.174 L = 0.00825 moles × 0.0821 (L atm)/(K mol) × 258 K

Simplify and solve for P:

P = (0.00825 moles × 0.0821 × 258) / 0.174

P ≈ 0.100 atm

explain why many compounds that contain one or more hydrogen atoms are not classified as arrhenius acids

Answers

Final answer:

Not all compounds containing hydrogen atoms are classified as Arrhenius acids because they do not release hydrogen ions when dissolved in water. Methane and acetic acid are examples of compounds that contain hydrogen atoms but are not classified as Arrhenius acids.

Explanation:

In order for a compound to be classified as an Arrhenius acid, it must release hydrogen ions (H+) when dissolved in water. However, not all compounds that contain hydrogen atoms are classified as Arrhenius acids because they do not release H+ ions. For example, methane (CH4) and acetic acid (CH3COOH) both contain hydrogen atoms but they are not classified as Arrhenius acids because their hydrogen atoms are not capable of ionizing.

Which is an acceptable Lewis structure for a diatomic nitrogen molecule?

Answers

Answer:
            Acceptable Lewis structure of Diatomic Nitrogen Molecule is as follow,

                                                      :N≡N:

Explanation:
                     
The given lewis structure is acceptable because each nitrogen atom has a complete octet and and the formal charge of each nitrogen atom is zero. So those lewis structures which has zero or least formal charges are said to be more stable and acceptable. The formal charge is calculated is,

Formal Charge  =  # of Valence e⁻s - [# of non-bonded e⁻ + 1/2 # of bonded                                           e⁻]

For N,

Formal Charge  =  5 - [ 2 + 6/2]

Formal Charge  =  5 - [ 2 + 3 ]

Formal Charge  =  5 - 5

Formal Charge  =  0

Same result will come for the second N atom.
Final answer:

The Lewis structure for a diatomic nitrogen molecule  would indicate a triple bond between the two nitrogen atoms, with each atom having a pair of lone electrons. The concept of resonance doesn't apply to this molecule.

Explanation:

The diatomic nitrogen molecule has a triple bond between the two nitrogen atoms. A Lewis structure, in this context, represents the arrangement of electrons in a molecule. The Lewis structure for N2 would therefore show the nitrogen atoms sharing three pairs of electrons - indicating the triple bond - with each nitrogen atom also having one pair of lone (non-bonding) electrons.

Using the concepts of resonance and electron-pair geometries, it's possible to show that the actual distribution of electrons is an average between various possible Lewis structures. However, the resonance only applies to molecules where it's not possible to depict the molecule's structure using a single Lewis structure, as in the case of nitrogen dioxide (NO2) and related compounds, not diatomic nitrogen.

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Assume that the rate law for a generic chemical reaction is rate = [a][b]3 . what is the reaction order in a, the reaction order in b, and the overall reaction order?

Answers

If the reaction is
     X + Y → Products

Then the rate is
     R = k[X]ᵃ [Y]ᵇ

Where,
R = the rate of the reaction (mol L⁻¹ s⁻¹)
k = rate constant
[X] and [Y] = concentrations of the reactants (mol L⁻¹)
a = order of the reaction with respect to X
b = order of the reaction with respect to Y
overall reaction order, n = a + b

according to the given rate expression,
rate = [a][b]³

order of the reaction with respect to 'a' is 1
order of the reaction with respect to 'b' is 3

Overall reaction order = 1 + 3
                                       = 4

The order of reaction in a is 1 while the order of reaction in b is 3.

What is order of reaction?

The rate law is obtained from the reaction equation or from experiment. We can determine the order of reaction by summing up the exponents in the rate law as shown in the equation of the rate law.

Now, we have;  rate = k[a][b]3, the order of reaction in a is 1 while the order of reaction in b is 3.

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A substance that is not soluble in a polar solvent is

Answers

I believe its a Nonpolar substance.

What is the new mass/volume (m/v)% of a koh solution that is prepared by diluting 110 ml of a 6% (m/v) koh solution to 330 ml?

Answers

we can use the dilution formula where we make diluted solutions from more concentrated solutions
c1v1 = c2v2 
c1 is concentration and v2 is volume of the concentrated solution
c2 is concentration and v2 is volume of the diluted solution to be prepared 
in this case we have been given m/v % which we can use as the concentrations
substituting the values in the equation 
6% x 110 mL = C x 330 mL 
C = 2%

the new m/v % of the diluted solution prepared is 2% (m/v) 

How many kj of heat are needed to completely vaporize 1.30 moles of h2o? the heat of vaporization for water at the boiling point is 40.6 kj/mole?

Answers

The Kj of heat that  are needed to completely vaporize 1.30  moles of H2O  if  the heat of vaporization  for water is 40.6 Kj/mole  is calculated as  below

Q(heat) = moles x heat  of vaporization)

=1.30 mol  x40.6 kj/mol= 52.78 Kj  is needed

Explanation:

Heat of vaporization is defined as the amount of heat required to change one mole of a liquid into vapor state without any change in the temperature.

It is known that for 1 mole of water, latent heat of vaporization is 40.6 kJ/mol.

Therefore, heat of vaporization for 1.30 moles will be calculated as follows.

              [tex]1.30 moles \times 40.6 kJ/mol[/tex]

               = 52.78 kJ

Thus, we can conclude that the 52.78 kJ of heat are needed to completely vaporize 1.30 moles of [tex]H_{2}O[/tex].

A student pours exactly 26.9 mL of HCl acid of unknown molarity into a beaker. The student then adds 2 drops of the indicator and titrates the acid to neutrality using 43.7 mL of 0.13 M NaOH base.
a. Write and balance the neutralization reaction of the acid and base
b. What is the molarity of the acid?

Answers

a.
Acids react with bases and give salt and water and the products.

Hence, HCl reacts with NaOH and gives NaCl salt and H₂O as the products. The reaction is,
            HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

To balance the reaction equation, both sides hould have same number of elements.

Left hand side,                                             Right hand side,
             
H atoms = 2                                               H atoms = 2
            Cl atoms = 1                                               Cl atoms = 1
            Na atoms = 1                                               Na atoms = 1 
           O atoms = 1                                                   O atoms = 1

Hence, the reaction equation is already balanced.

b. 
Molarity (M)= moles of solute (mol) / Volume of the solution (L)
 
          HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

Molarity of NaOH = 0.13 M
Volume of NaOH added = 43.7 mL
Hence, moles of NaOH added = 0.13 M x 43.7 x 10⁻³ L
                                                 = 5.681 x 10⁻³ mol

Stoichiometric ratio between NaOH and HCl is 1 : 1

Hence, moles of HCl = moles of NaOH
                                    = 
5.681 x 10⁻³ mol

5.681 x 10⁻³ mol of HCl was in 26.9 mL.

Hence, molarity of HCl = 5.681 x 10⁻³ mol / 26.9 x 10⁻³ L
                                     = 0.21 M

If a sample of a certain solution is determined to have a [h3o+][h3o+] concentration of 4.91×10−44.91×10−4 moles/liter, what is its ph? round off your answer to one decimal place.

Answers

pH scale is used to determine how acidic , basic or neutral a solution is. It can be calculated using the following equation 
pH = -log [H₃O⁺]
hydronium ion concentration has already been given 
[H₃O⁺] = 4.91 x 10⁻⁴ M
pH = -log[4.91 x 10⁻⁴ M]
pH = 3.3
the pH of medium is 3.3

In alpha and beta decay the parent element and the daughter element can be

Answers

In alpha and beta decay the parent element and the daughter element will be different isotope and not the same. 
This is because as alpha particles comes out; the new element will have two less in atomic number; that is the atomic number will reduce by two and the mass number will reduce by four. While in a beta particle decay, the new element will have one higher in atomic number; that is the atomic number will increase by one. 
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