The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which:

Answers

Answer 1

Final answer:

The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is one where both the tert-butyl and methyl groups are in equatorial positions to minimize steric repulsion, thus stabilizing the molecule.

Explanation:

The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which the bulky substituents, tert-butyl and methyl groups, are in the more spacious equatorial positions. This conformation reduces steric interactions, particularly the 1,3-diaxial interactions that would otherwise occur if the bulky groups were in the axial positions. Since the molecule is trans, the substituents are on opposite sides of the cyclohexane ring, therefore, the most stable conformation would have the tert-butyl group equatorial on one face of the ring and the methyl group equatorial on the opposite face.

These orientations minimize steric repulsion between the bulky groups and the hydrogens on the cyclohexane ring, thus following similar principles to those observed in conformations of butane and monosubstituted cyclohexanes. Cyclohexane chair conformations, as well as cis-trans isomerism in cycloalkanes, influences the stability of the molecule depending on the spatial arrangement of the substituents.

Answer 2

The correct answer is: b. both groups are equatorial. The most stable conformation of trans-1-tert-butyl-2-methylcyclohexane is the one in which both groups are equatorial.

The most stable conformation of cis-1-tert-butyl-2-methylcyclohexane is determined by the preference for bulky substituents (tert-butyl and methyl groups) to occupy the less sterically hindered positions, which are typically the equatorial positions in cyclohexane rings.

In cyclohexane, substituents prefer to be in the equatorial positions to minimize steric hindrance. Therefore, the most stable conformation of cis-1-tert-butyl-2-methylcyclohexane is when both the tert-butyl group and the methyl group are in equatorial positions. This minimizes steric interactions and maximizes stability compared to having one or both groups in axial positions.

The complete question is- The most stable conformation of cis-1-tert-butyl-2-methylcyclohexane is the one in which

a. the molecule is in the half chair conformation

b. both groups are equatorial

c. both groups are axial.

d. the methyl group is axial and the tert-butyl group is equatorial

e. the tert-butyl group is axial and the methyl group is equatorial.


Related Questions

Which product(s) would be obtained by the dehydration of 2 heptanol and 2-methyl-1-cyclohexanol?

Answers

In the dehydration of alcohol, all you have to do is take out the oxygen from the -OH bond which reacts with the H+ ions from the acid to produce water. 

So, for 2-heptanol, the products would be water and heptane. For 2-methyl-1-cyclohexanol, the products would be water and 2-methylcyclohexane.

Answer:

Answers are in the image.

Explanation:

In dehydration reaction of alcohols, alcohols lose water to generate alkene proceeds by heating the alcohols in the presence of a strong acid, such as sulfuric or phosphoric acid (HX), at high temperatures. The most substituted alkene are formed preferentially

The products and mechanism are in the images.

I hope it helps!

Calculate the enthalpy change for the thermite reaction: 2al(s)+fe2o3(s)→2fe(s)+al2o3(s), δh∘rxn=−850 kj when 8.00 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3. express your answer to three significant figures and include the appropriate units.

Answers

Enthalpy change for the balanced equation is -850kj
And from the balanced equation we come to know that for 2 moles of Al, the value is -850kj
for 1 mole of Al = -850/2 = -425 kj
We have to find the enthalpy change for 8 moles of Al = 8 x -425 = 3400kj
Thus, the enthalpy change for 8 mol of Al is -3400kj.
Final answer:

The enthalpy change for the thermite reaction when 8.00 mol of Al reacts is -6812 kJ.

Explanation:

The enthalpy change for the thermite reaction can be calculated using Hess's law. The overall reaction can be broken down into three steps, each with its own known enthalpy change values. The enthalpy change for the reaction is the sum of the enthalpy changes for each step.

In this case, the enthalpy change for the reaction is -851.5 kJ/mol of Fe₂O₃. To calculate the enthalpy change when 8.00 mol of Al reacts, you can multiply the enthalpy change by the number of moles of Al consumed, which is 8.00 mol. This gives a total enthalpy change of -851.5 kJ/mol x 8.00 mol = -6812 kJ.

Therefore, the enthalpy change for the thermite reaction when 8.00 mol of Al reacts is -6812 kJ.

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What is the total number of orbitals associated with the principal quantum number n = 3?

Answers

Actually the third shall is composed of 1 s orbital, 3 p orbitals, and 5 d orbitals. Each of these orbital holds 2 electrons therefore the total number of electrons are:

(1 + 3 + 5) * 2 = 18

There are 18 electrons that can fall in the 3rd shell. And there are 9 orbitals.

Uranium-235 has a half-life of 713 million years, while carbon-14 has a half-life of about 5,730 years. Which isotope would be more useful for dating a fossil from Precambrian time?

Answers

Uranium-235 is more useful.
Uranium - 235. It has a longer half - life, which means that it can be used to trace events/items further back in history than carbon - 14 can.

Using the round 2 fasttrack bond table (page 2), how is digby's "yield" calculated for their 10.0s2020 bond?

Answers

This is based on the round 2 FastTrack bond table, Digby’s “yield” for their 10.0S2020 bond is calculated in this format:


= ($100 - 93.41) / 100


= 10.0 / 93.41


= (2480 - 2020) / 2020


= (2480 - 2020) / 2480


= 0.1855 or 15.55% is the yield


NOTE: It isn’t computed, it is reported.

How does the behavior of the water molecules change as the pan of water is heated?

Answers

The behavior of the water molecules change as the pan of water is heated, As the water is heated, the water molecules move faster and farther apart. The molecules change as the water is heated and the water molecules move faster and farther.

Weather is a condition of the atmosphere at a particular time and place. Wind, rain, and cloud formations are all forms of weather phenomena. What is the primary source of energy for weather phenomena?

Answers

Answer:

Solar radiation

Explanation:

Umm.. i just guessed and got the question right so...sksksks

look at the picture below for the anwse

Calculate zeff for a valence electron in an oxygen atom. express your answer numerically.

Answers

Answer: 8 - 3.45 = 4.55 And (theoretically of course) if there were more problems like this, the answers would probably be something like this: B) 29 - 25.30 = 3.70 C) 29 - 21.15 = 7.85 D) 1.effective nuclear charge
Final answer:

The effective nuclear charge (Zeff) for a valence electron in an oxygen atom is calculated using the formula Zeff = Z - S, with Z being the atomic number (8 for oxygen) and S the shielding constant (2 for oxygen). Thus, Zeff for a valence electron in oxygen is 6.

Explanation:

To calculate the effective nuclear charge (Zeff) for a valence electron in an oxygen atom, we first need to know the electron configuration of an oxygen atom. Oxygen has an atomic number of 8, so its electron configuration is 1s2 2s2 2p4. The valence electrons are those in the highest energy level, so for oxygen, they are the four electrons in the 2p orbital.

Using the formula Zeff = Z - S, where Z is the atomic number and S is the shielding constant, we can estimate Zeff for oxygen. Oxygen's atomic number (Z) is 8, and the shielding constant (S) is approximately equal to the number of nonvalence electrons, which for oxygen is 2 (the two electrons in the 1s orbital).

Therefore, Zeff for a valence electron in an oxygen atom is calculated as follows:
Zeff = Z - S = 8 - 2 = 6

The Zeff of 6 means that valence electrons in an oxygen atom experience an effective charge of +6 from the nucleus.

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ΔABC and ΔDEF are similar. The lengths of and are 5 units each, and the length of is 6 units. If the length of is 3 units, then the length of is units. If is 53°, then is °.

Answers

Final answer:

The length of DC is 10 units and the measure of angle ∠C is 74°.

Explanation:

To find the length of DC, we can use the concept of similar triangles. Since triangles ΔABC and ΔDEF are similar, the corresponding sides are proportional. We can set up the following proportion: AB/DE = BC/EF = AC/DF. Plugging in the given lengths, we have 5/3 = BC/6. Cross-multiplying gives us BC = 10 units. Therefore, the length of DC is 10 units.

To find the measure of angle ∠C, we can use the fact that corresponding angles in similar triangles are congruent. Since angle ∠B = 53° in ΔABC, we know that angle ∠F = 53° in ΔDEF. Therefore, angle ∠C = 180° - 53° - 53° = 74°.

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Find the total number of atoms in a sample of cocaine hydrochloride, c17h22clno4, of mass 23.0 mg .

Answers

From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of nitrogen = 14 grams
mass of oxygen = 16 grams
mass of chlorine = 35.5 grams
Therefore,
molar mass of c17h22clno4 = 17(12) + 22(1) + 35.5 + 14 + 4(16) = 339.5 grams

number of moles = mass / molar mass
number of moles = (23*10^-3) / (339.5)
number of moles = 6.77 * 10^-5 moles

number of atoms = number of moles * Avogadro's number
number of atoms = 6.77*10^-5 * 6.022*10^-23
number of atoms = 4.079 * 10^-27 atoms

If you examine the ir spectrum of an unknown how could you tell if it is an alcohol

Answers

The ir spectrum or the infrared spectrum is a plot of the percentage transmittance of radiation versus the decreasing frequency of radiation expressed as a wave number. Infrared spectroscopy measures the absorption of infrared radiation by various organic functional groups. Alcohols typically register frequencies of 3000-3700 cm-1 for the O-H functional group and 900-1300 for the C-O functional group. 
Final answer:

To determine if an unknown compound is an alcohol using its IR spectrum, look for a distinct broad O-H stretch in the 3300 to 3400 cm⁻¹ range indicative of hydrogen bonding, and a strong C-O stretch. These features differentiate alcohols from other compounds with similar functional groups.

Explanation:

If you examine the IR spectrum of an unknown and want to determine if it is an alcohol, look for two key features: the O-H stretch and the C-O stretch. Alcohols are characterized by a very broad, strong O-H stretch in the range of 3300 to 3400 cm⁻¹, which is indicative of hydrogen bonding within the alcohol.

Additionally, alcohols exhibit a strong C-O stretch typically around 1000 to 1300 cm⁻¹. Unlike ethers and epoxides, which also display a C-O stretch, alcohols can be distinguished by the presence of the broad O-H stretch.

The exact position and the breadth of the O-H absorption can vary based on the level of hydrogen bonding, thus providing further clues about the structure of the unknown alcohol. To confirm the identity, comparing the IR spectrum of the unknown sample against known standards can be very helpful.

6 m nh3 a basic solution cannot be found on the reagent shelf, but 6m naoh also a base is available, what would be observed if the 6m naoh is substituted for the 6m nh3, in testing the reference solution

Answers

The difference will be that whatever chemical reaction is taking place, it will take place faster. For example, if a titration was being carried out to neutralize an acid, the acid will neutralize faster with NaOH. 
The reason for this is because NaOH is a stronger base. It dissociates more than does ammonia; therefore, it reacts faster.
Final answer:

Substituting 6M NaOH for 6M NH3 in testing the reference solution would result in a more basic solution and a higher pH.

Explanation:

When testing a reference solution, if 6M NaOH is substituted for the 6M NH3, a different observation would be made. NH3 is a weak base, while NaOH is a strong base. In this case, the pH of the solution would change significantly since NaOH completely dissociates in water, producing a high concentration of hydroxide ions. On the other hand, NH3 only partially reacts with water, resulting in a lower concentration of hydroxide ions. Therefore, substituting NaOH for NH3 would result in a more basic solution and a higher pH.

A diatomic molecule (0.500 m) dissociates in a first order reaction with a rate constant, k, of 0.0775 sâ1. what is the half-life of this reaction? hints

Answers

The half-life of the reaction is ln 2 / k
   
= ln 2 / (0.0775 s-1)
   
= 0.693 s / 0.0775
     
= 8.94 s

Which solvent was more effective for the recrystallization of naphthalene ethanol or hexane?

Answers

Purification technique for crystalline organic solids is known as recrystalization. For recrystallization of naphthalene, the polar solvents such as water and ethanol are bad solvents. On the other hand, the non polar solvents such as benzene, hexane, etc are good solvents for non polar solids like naphthalene.

Answer: HEXANE is a more effective solvent for the recrystallization of naphthalene.

For the recrystallization of naphthalene, ethanol is likely more effective than hexane due to its ability to form hydrogen bonds and its polar nature, allowing for better dissolution when heated and potentially higher recovery rates.

The effectiveness of a solvent in the recrystallization of naphthalene depends on the solubility of naphthalene in that solvent at different temperatures. For recrystallization, a solvent in which the desired compound is slightly soluble when cold but more soluble when hot is ideal. Ethanol is a polar solvent that can form hydrogen bonds and therefore, can dissolve a wide range of organic compounds, including naphthalene, more effectively when heated.

Whereas, hexane is nonpolar and might not be as effective at dissolving naphthalene, especially if the substance is more polar. Based on solubility profiles and hydrogen bonding capabilities, ethanol would likely be a more effective solvent for recrystallization of naphthalene compared to hexane.

what is the PH of 8.1x10^-5 M HCLO4 solution

Answers

HCl04 is a strong acid solution. So, in theory everything dissociates.

pH= -log(0.000081)= 4.09

The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Therefore, the pH of  0.000081M  HClO₄  is 4.09. pH is a unitless quantity.

What is pH?

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7.

The concentration of  HClO₄ is 0.000081M or 8.1x10⁻⁵M

Concentration of H₃O⁺ in HClO₄ =0.000081M or 8.1x10⁻⁵M

Mathematically,

pH=-log[H⁺]

Substituting the values

pH=-log[0.000081]

pH of HClO₄=4.09

Thus the pH of  0.000081M HClO₄ is 4.09.

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Which statement best describes Rutherford's model of the atom?

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A big stadium that has a positive charged marble in the center of the stadium.

Answer is: Huge stadium with a positively charged marble at the center.

According to Rutherford model of the atom:

1) Atoms have their charge concentrated in a very small nucleus.

2) Major space in an atom is empty.

3) Atoms nucleus is surrounded by negatively charged particles called electrons.

4) An atom is electrically neutral.


Predict the mass of iron (III) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of yellow sulfur solid, S8(s).

Answers

the answer is 5.5g Fe

Answer : The mass of iron(III)sulfide is, 5.4288 g

Solution : Given,

Mass of iron, Fe = 3 g

Mass of sulfur, [tex]S_8[/tex] = 2.5 g

Molar mass of Fe = 56 g/mole

Molar mass of [tex]S_8[/tex] = 256 g/mole

Molar mass of iron(III)sulfide, [tex]Fe_2S_3[/tex] = 208 g/mole

The balanced chemical reaction is,

[tex]16Fe(s)+3S_8(s)\rightarrow 8Fe_2S_3(s)[/tex]

First we have to calculate the moles of iron and sulfur.

[tex]\text{ Moles of Fe}=\frac{\text{ Mass of Fe}}{\text{ Molar mass of Fe}}=\frac{3g}{56g/mole}=0.054moles[/tex]

[tex]\text{ Moles of }S_8=\frac{\text{ Mass of }S_8}{\text{ Molar mass of }S_8}=\frac{2.5g}{256g/mole}=0.0098moles[/tex]

From the balanced reaction, we conclude that

16 moles of Fe react with 3 moles of [tex]S_8[/tex]

0.054 moles of Fe react with [tex]\frac{3}{16}\times 0.054=0.010125[/tex] moles of [tex]S_8[/tex]

Therefore, the excess reagent in this reaction is, Fe and limiting reagent is, [tex]S_8[/tex]

Now we have to calculate the moles of FeS.

As, 3 moles of [tex]S_8[/tex] gives 8 moles of [tex]Fe_2S_3[/tex]

So, 0.0098 moles of [tex]S_8[/tex] gives [tex]\frac{8}{3}\times 0.0098=0.0261[/tex] moles of [tex]F_2eS_3[/tex]

The moles of [tex]Fe_2S_3[/tex] = 0.0261 moles

Now we have to calculate the mass of [tex]Fe_2S_3[/tex].

Mass of [tex]Fe_2S_3[/tex] = Moles of [tex]Fe_2S_3[/tex] × Molar mass of [tex]Fe_2S_3[/tex]

Mass of [tex]Fe_2S_3[/tex] = 0.0261 g × 208 g/mole = 5.4288 g

Therefore, the mass of iron(III)sulfide is, 5.4288 g

much of this frozen glaciers and ice caps, so we don't consider is usable. a. salt water b. fresh water c. rainwater d. ice

Answers

Answer : Option B) Fresh water.Explanation :

Much of this frozen glaciers and ice caps, so we don't consider it usable freshwater.

This statement tells about the freshwater usage out of the whole water available on earth some are stored in the form of glaciers, ice caps, etc. Which cannot be used as freshwater.

Answer:

1. Aquifer

2. Deposition

3. recharge

4. water table

5. 97%

6. 1%

7. Fresh Water

8. Rain

9. underground

10. water contamination

Explanation:

Got a 100% on the quiz

Nitroglycerin (c3h5n3o9) is a powerful explosive. its decomposition may be represented by 4c3h5n3o9 → 6n2 12co2 10h2o o2 this reaction generates a large amount of heat and gaseous products. it is the sudden formation of these gases, together with their rapid expansion, that produces the explosion. (a) what is the maximum amount of o2 in grams that can be obtained from 4.50 × 102 g of nitroglycerin

Answers

Answer:

15.8528 grams of oxygen will be obtained.

Explanation:

[tex]4C_3H_5N_3O_9\rightarrow 6N_2+12CO_2+10H_2O+O_2[/tex]

Mass of nitroglycerin = [tex]4.50\times 10^{2} g[/tex]

Moles of nitroglycerin:

[tex]\frac{4.50\times 10^{2} g}{227.08 g/mol}=1.9816 mol[/tex]

According to reaction, 4 moles of nitroglycerin gives 1 mole of oxygen gas.

then 1.9816 mol of nitroglycerin will give:

[tex]\frac{1}{4}\times 1.9816=0.4954 [/tex] moles of oxygen gas.

Mass of oxygen ;

[tex]0.4954 mol\times 32 g/mol=15.8528 g[/tex]

15.8528 grams of oxygen will be obtained.

The maximum mass of O₂ that can be obtained from 4.5×10² g of nitroglycerin is 15.86 g

The balanced equation for the reaction is given below:

4C₃H₅N₃O₉ —> 6N₂ + 12CO₂ + 10H₂O + O₂

Next, we shall determine the mass of C₃H₅N₃O₉ that decomposed and the mass of O₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₃H₅N₃O₉ = (12×3) + (5×1) + (14×3) + (16×9)

= 36 + 5 + 42 + 144

= 227 g/mol

Mass of C₃H₅N₃O₉ from the balanced equation = 4 × 227 = 908 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 1 × 32 = 32 g

SUMMARY:

From the balanced equation above,

908 g of C₃H₅N₃O₉ decomposed to produce 32 g of O₂.

Finally, we shall determine the mass of O₂ that will be produce from the decomposition of 4.5×10² g of C₃H₅N₃O₉. This can be obtained as follow:

From the balanced equation above,

908 g of C₃H₅N₃O₉ decomposed to produce 32 g of O₂.

Therefore, 4.5×10² g of C₃H₅N₃O₉ will decompose to produce = [tex]\frac{4.5*10^{2} * 32}{908}[/tex] = 15.86 g of O₂

Thus, the maximum mass of O₂ obtained from 4.5×10² g of nitroglycerin is 15.86 g

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Suppose there are two known compounds containing the generic elements X and Y. You have a 1.00-g sample of each compound. One sample contains 0.30 g of X and the other contains 0.39 g of X. Identify plausible sets of formulas for these two
compounds.
XY and X3Y
X3Y and X4Y
XY3 and XY4
X2Y and X3Y
X4Y2 and X3Y
X2Y5 and X3Y5
XY and X2Y

Answers

To solve this, we must remember that the number of moles in each formula must a whole number.

So we are given two X’s:

X = 0.3

X = 0.39

 

We divide the two by the smallest X, so divide by 0.3:

X = 0.3 / 0.3 = 1

X = 0.39 / 0.3 = 1.3

 

However the second X is not a whole number yet, therefore multiply the two X’s by 3 to make them whole numbers:

X = 1 * 3 = 3

X = 1.3 * 3 = 4

 

So the X’s must be: X3 and X4 and based from the choices, the answer is:

 

X3Y and X4Y

The plausible sets of formulas for these two  compounds are:

A. X2Y and X3Y

B. XY3 and XY4

C. X3Y and X4Y

D. XY and X3Y

E. XY and X2Y

F. X2Y5 and X3Y5

G. X4Y2 and X3Y

Further explanation

I think the correct answers are A and F. and G:

A. X2Y and X3Y F. X2Y5 and X3Y5 G. X4Y2 and X3Y

If we look at the combining masses of X and Y in each of the two compounds, the first compound contains 0.25 g of X combined with 0.75 g of Y, therefore the ratio (by mass) of X to Y is 1 : 3. Whereas the second compound contains 0.33 g of X combined with 0.67 g of Y, therefore the ratio (by mass) of X to Y is 1 : 2.

Then, suppose prepared each of these two compounds, starting with the same fixed mass of element Y (I will choose 12 g of Y for an easy calculation) 

The first compound will then contain 4g of X and 12g of Y. Next the second compound will then contain 6g of X and 12g of Y. The ratio which combined the masses of X and the fixed mass (12 g) of Y = 4 : 6 or 2 : 3.

So, the ratio of Moles of X which combined with the fixed amount of Y in the two compounds is also 2 : 3. Then the two compounds given with the plausible formula must therefore contain the same ratio.

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Answer details

Grade:  9

Subject: Chemistry  

Chapter: compounds

Keywords: the generic elements X,  the generic elements Y,  two  compounds, XY, X3Y

For sulfurous acid (h2so3, a diprotic acid) write the equilibrium dissociation reactions and the corresponding expressions for the equilibrium constants

Answers

Since the acid is diprotic, there are two equilibrium dissociation reactions for it. Consequently, there will also be two expression for equilibrium constants, Ka₁ and Ka₂.

First reaction:
H₂SO₃ ⇄ 2H⁺ + HSO₃²⁻          ------>     Ka₁ = [H⁺][HSO₃²⁻]/[H₂SO₃]

Second reaction:
HSO₃²⁻ ⇆ H⁺ + SO₃²⁻             ------>     Ka₂ = [H⁺][SO₃²⁻]/[HSO₃²⁻]

When a chemical process reaches equilibrium, the equilibrium constant (often represented by the letter K) sheds light on the interaction between the reactants and products. The reciprocal of the initial equilibrium serves as the equilibrium constant for the reverse equilibrium.

The ratio of the concentration of the products to the concentration of the reactants, each raised to their respective stoichiometric coefficients, is the equilibrium constant of concentration (denoted by Kc) of a chemical process at equilibrium.

Since the acid is diprotic, there are two equilibrium dissociation reactions for it. Consequently, there will also be two expressions for equilibrium constants, Ka₁ and Ka₂.

First reaction:

H₂SO₃ ⇄ 2H⁺ + HSO₃²⁻          ------>     Ka₁ = [H⁺][HSO₃²⁻]/[H₂SO₃]

Second reaction:

HSO₃²⁻ ⇆ H⁺ + SO₃²⁻             ------>     Ka₂ = [H⁺][SO₃²⁻]/[HSO₃²⁻]

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Calculate the number of repetitions of the β-oxidation pathway required to fully convert a 12-carbon activated fatty acid to acetyl-scoa molecules.

Answers

A 12-carbon activated fatty acid requires 5 cycles of the β-oxidation pathway to be fully converted into acetyl-CoA molecules.

The β-oxidation pathway is a critical metabolic process that breaks down fatty acids into acetyl-CoA molecules.

To calculate the number of repetitions needed to fully convert a 12-carbon activated fatty acid into acetyl-CoA molecules, we can use the formula: [tex]\frac{n}{2} -1[/tex], where n is the number of carbon atoms in the fatty acid.

For a 12-carbon fatty acid:

n = 12Number of β-oxidation cycles = [tex]\frac{12}{2} - 1[/tex] = 6 - 1 = 5

Therefore, a 12-carbon activated fatty acid requires 5 repetitions of the β-oxidation pathway to be fully converted into acetyl-CoA molecules.

A car is 8.4 lb. what is the mass of the cat in kilograms?

Answers

Do you have round to anything? If you don't have to round the answer is 3.81018 kg. :)

A 0.229-g sample of an unknown monoprotic acid is titrated with 0.112 m naoh. the resulting titration curve is shown here. part a determine the molar mass of the acid. express your answer using two significant figures.

Answers

Answer: 81.8 g/mol

Explanation:

We’re being asked to calculate the molar mass of an unknown acid based on our interpretation of the titration curve.  

Recall that at the equivalence point of a titration:

[tex]moles\ acid=moles\ base[/tex]

We can use this equation to calculate the moles of the unknown acid. Since the unknown acid only has a single Ka value, it is a monoprotic acid, which means there will be one equivalence point for the titration.

Mole-to-mole comparison: A mole-to-mole comparison will then show that 1 mole of the unknown acid reacts with 1 mole of Na(OH).

Molarity of NaOH: The molarity of NaOH (the base) is given as 0.112 M or 0.112 mol/L NaOH.

As for the volume of NaOH (the base) added, we can interpret this from the graph:  

we can see that at the equivalence point, 25 mL of the vase was added.

Vbase is more or less 25.00 mL

Recall:  

1 mL = 10-3 L  

Solving for MMacid:  

Again, at the equivalence point of a titration:

[tex]moles\ acid=moles\ base=0.112*25*10^{-3}[/tex]

[tex]moles\ acid = 0.0028\ moles[/tex]

Molar mass is defined as the mass in grams of one mole of a substance.  

The units of molar mass are grams per mole, abbreviated as g/mol and uses the formula below:

[tex]molar\ mass=\frac{mass\ of\ compound\ in\ grams}{mole\ of\ compound\ in\ moles}[/tex]

[tex]=\frac{mass\ of\ acid}{moles\ acid}[/tex]

[tex]=\frac{0.229g}{0.0028mol}[/tex]

molar mass acid = 81.8 g/mol

The molar mass of the unknown acid is 81.8 g/mol.

An acid that donates a single hydrogen atom or proton is called monoprotic acid. The molar mass of the unknown acid in titration is 81.8 gm/mol.

What is molar mass?

The molar mass of any substance is the ratio of the mass of the substance in grams and moles of the same substance in mol. The molar mass is given by g/mol.

In titration, the moles of acid are equivalent to acid and can be used to determine the moles of the unknown acid from the base.

We know, that the molarity of base (NaOH) is 0.112 M, and the graph is used to know the volume to be 25 ml.

The moles of the base is calculated as:

[tex]\begin{aligned} \rm moles &=\rm molarity \times volume\\\\&= 0.112 \;\rm M \times 25 \times 10^{-3}\;\rm L\\\\&= 0.0028\;\rm moles\end{aligned}[/tex]

Hence, moles of acid is 0.0028 mol.

The molar mass of acid is calculated as:

[tex]\begin{aligned}\rm Molar \;mass &= \rm \dfrac{mass}{moles}\\\\&= \dfrac{0.229}{0.0028}\\\\&= 81.8\;\rm g/mol\end{aligned}[/tex]

Therefore, 81.8 g/mol is the molar mass of unknown monoprotic acid.

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Summarize the Venn diagram. A) Compounds are found inside the matter of atoms. B) A pure substance may contain subatomic particles but not atoms. C) Compounds are the most basic form of matter. They combine to form larger atoms. D) Atoms are the most basic form of matter. They combine to form larger electrically stable compounds.

Answers

Answer:

D

Explanation:

just took the test

The venn diagram illustrates D) Atoms are the most basic form of matter. They combine to form larger electrically stable compounds.

Further explanation

Material / Substance can be divided into 2 parts namely a single substance and a mixture. A single substance can be an element or a compound. While the mixture can be a homogeneous or heterogeneous mixture.

1. Elements are: A group of atoms that have the same number of protons in their nucleus (atomic number). The element is a single substance that can no longer be divided into smaller parts.

2. Compounds: a single substance consisting of several elements. Compounds are formed from at least 2 different elements

3. Mixed: material consisting of two or a single substance (from elements and compounds)

Let see the answer choices :

A) Compounds are found inside the matter of atoms.

Inside the atom consists of a nucleus containing 3 basic particles namely protons and neutrons, while electrons move around the nucleus.

So the statement is false

B) A pure substance may contain subatomic particles but not atoms.

Subatomic particles inside the atoms, so a pure substance contain atoms

So the statement is false

C) Compounds are the most basic form of matter

the most basic form of matter is atom

So the statement is false

D) Atoms are the most basic form of matter. They combine to form larger electrically stable compounds.

Compounds can consist of several atoms

So the statement is true

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The subatomic particle that has the least mass

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The part of an atom that is mostly empty space

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statement about subatomic particles

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Keywords : subatomic particles , atoms, matter, compound, element

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Oxygen is killing us This isnt for science this is real talk the reason oxygen kills us because it damages our cells as we dont know thats why we dont live as long to 103 or more pure oxygen will kill you more the less oxygen we have on earth the more we live longer because of 20% of 21% of oxygen falling it increases the life on humans and animals plants

Answers

I can tell you're not very educated because everyone knows that breathing pure oxygen for long periods of time can sometimes hurt us. Oxygen in lower levels, such as levels found in atmosphere are just right for us to breathe. Get a life and stop trying to scare young kids that just want help on their homework.
Final answer:

Oxygen is essential for life, but too much can be harmful. Lack of oxygen leads to brain damage and death. The optimal level for supporting life is about 20% oxygen in the atmosphere.

Explanation:

Oxygen is a vital component for life and is necessary for the chemical reactions that keep our bodies alive. It is a key player in the production of ATP, which is the energy currency of cells. Lack of oxygen can lead to brain damage within minutes and death within a short period of time.

While oxygen is essential for life, too much of it can be harmful. Pure oxygen at high concentrations can be toxic and cause damage to cells. The atmosphere contains about 20% oxygen, which is the optimal level for supporting life.

It is incorrect to say that less oxygen on Earth would lead to longer life spans. In fact, organisms require a certain amount of oxygen to survive and thrive. Oxygen is necessary for the process of respiration, which generates energy for the body.

A 50-gram sample has a half-life of 12 days. How much material will remain after 12 days?

Answers

A 50-gram sample with a half-life of 12 days will have a remaining mass of 25 grams after its 12-day half-life. Every cycle of a half-life, the sample will lose half of its mass, so if the half-life, itself, is 12 days and the time period passing is 12 days, one half-life has passed and the material will be halved.

Answer:25 grams

Explanation:

What promotes greater hardness in minerals? A smaller atoms and stronger bonds B larger atoms and weaker bonds C larger atoms and stronger bonds D smaller atoms and weaker bonds

Answers

smaller atoms and stronger bonds

Option A. Smaller atoms and stronger bonds.

Smaller the size of the atoms, less will be the distance between positive charge nucleus of one atom and electrons (negative charge) of other atom. This results in strong interaction between them.

Also, stronger bonds are difficult to break, making the minerals harder. Thus, small atoms and strong bonds in minerals makes then harder than the minerals with weak bonds or larger atoms.


1 mole of ch3oh(l) has a greater entropy than 1 mole of c2h5oh(l). true or false

Answers

Final answer:

The statement is likely false. The entropy of a substance generally increases with its molecular complexity and size, suggesting C₂H₅OH(l) would have higher entropy than CH₃OH(l). Additionally, the physical state (solid, liquid, gas) impacts entropy, but in this case, both substances are liquids.

Explanation:

The statement that 1 mole of CH₃OH(l) has a greater entropy than 1 mole of C₂H₅OH(l) is likely false. Entropy, a measurement of disorder or randomness in a system, generally increases with the complexity and size of a molecule. For example, a larger molecule with more atoms (like C₂H₅OH, also known as ethanol) typically has more potential arrangements or microstates, leading to a higher entropy than a smaller, less complex molecule (like CH₃OH, also known as methanol).

Furthermore, it should be noted that the physical state can significantly impact entropy. In general, gases have higher entropy than liquids, which in turn, have higher entropy than solids due to the increased disorder and freedom of movement in these states. However, as both substances in this case are in the liquid state, the primary factor influencing the entropy is likely the size and complexity of the molecule.

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The statement 1 mole of CH3OH(l) has a greater entropy than 1 mole of C2H5OH(l) is False.

To understand why this statement is false, let's consider the factors that affect the entropy of a substance. Entropy is a measure of the disorder or randomness in a system. In general, for liquids, the larger the molecule, the more ways there are for the molecules to arrange themselves, leading to higher entropy.

CH3OH, methanol, has a molar mass of approximately 32.04 g/mol, while C2H5OH, ethanol, has a molar mass of approximately 46.07 g/mol. Since ethanol has a larger molecule than methanol, it is expected to have a higher entropy due to the increased number of possible arrangements of its molecules in the liquid state.

Furthermore, experimental data supports this expectation. The standard molar entropy (S°) for methanol (CH3OH) at 298 K is about 126.8 J/(mol·K), while the standard molar entropy for ethanol (C2H5OH) at 298 K is about 160.7 J/(mol·K). Therefore, ethanol has a higher entropy than methanol in the liquid state.

In conclusion, 1 mole of C2H5OH(l) actually has a greater entropy than 1 mole of CH3OH(l), making the original statement false.

How high in meters must a column of glycerol be to exert a pressure equal to that of a 760-mm column of mercury? The density of glycerol is 1.26g/mL, whereas that of mercury is 13.6g/mL.

Answers

Using PV=nRT formula it should be clear that the pressure inversely proportional with the volume. Density is directly proportional to volume, make it also inversely proportional with the pressure (assuming the same mass of substance used).
The calculation would be: 760mm*13.6 / 1.26= 8203.17 mm * 1000 meter/mm= 8.2 meter
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