Mathematics High School

The price of 6 pretzels is $5.10. Simon and Sofia bought 8 pretzels an shared the cost equally. How much did each person pay?

Answers

Answer 1

Answer:

$3.40

Step-by-step explanation:

To find out the amount each person paid, let's find the total cost of the pretzels first.

6 pretzels ----- $5.10

1 pretzel ----- $5.10 ÷6= $0.85

8 pretzels ----- 8($0.85)= $6.80

The total cost of 8 pretzels is thus $6.80.

Since the total cost was shared equally amongst two people, each person paid half of the total cost.

Amount each person paid

= $6.80 ÷2

= $3.40

Answer 2

By taking a quotient between the total cost and the number of people, we can see that each one pays $3.40

How much did each person pay?

We know that the price of 6 pretzels is $5.10, then the price for each pretzel is given by the quotient:

$5.10/6 = $0.85

We know that Simon and Sofia bought 8 pretzels, so they pay:

P = 8*$0.85 = $6.80

And they divide that evenly between the two, so we can take the quotient:

p = $6.80/2 = $3.40

That is the amount that each person pays.

Learn more about quotients:

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#SPJ1

Related Questions

helpppppppppppppppppppppppp

Answers

The first thing to is factor the denominator of the rational function:
[tex] x^{2} -2x-3[/tex] to do this we'll need to find two number whose product is -3 and its sum is -2; those numbers are 1 and -3, so:
[tex] x^{2} -2x-3=(x+1)(x-3)[/tex]
Now we can rewrite our rational function as follows:
[tex]f(x)= \frac{x-3}{(x+1)(x-3)} [/tex]
Notice that we have a common factor (x-3) in both numerator and denominator; therefore we can cancel them:
[tex]f(x)= \frac{1}{x+1} [/tex]

Taking all the above into consideration we realize that x=3 is a removable discontinuity; the correct answer is the first one: there is a hole in x=3 and asymptote at x=-1.

Does the equation x2 - 4x + y2 = -3 intersect the x-axis?

Answers

To find out whether or not the equation x^2 - 4x + y^2 = -3 intersects the x-axis, we must set y = 0 in the equation (because at every point on the x-axis, y = 0).

x^2 - 4x + 0 = -3

We then want to solve for x. We can do this by factoring.

x^2 - 4x + 3 = 0

By factoring...

(x - 3)(x - 1)

We can set each of these equations = 0 to solve where the function crosses the x-axis.

x - 3 = 0
x = 3

x - 1 = 0
x = 1

So we know at x = 1 and x = 3, the function x^2 - 4x + y^2 = -3 intersects the x-axis.

Answer:

Yes, because the center is on the x-axis.

Step-by-step explanation:

First, write the equation in standard form by completing the square.

x2 - 4x + y2 = -3

x2 - 4x + 4 + y2 = -3 + 4

(x - 2)2 + y2 = 1

The circle is centered at (2, 0) with a radius of 1. Since the circle is centered on the x-axis, it intersects the x-axis two times, at (3, 0) and (1, 0).

30 POINTS + BRAINLIEST!

Answers

We have to find the value of 'x' in [tex] \sin (x+22)^{\circ}=\cos (2x-7)^{\circ} [/tex]

By using the complementary angle formula which states:

[tex] \cos (90-\Theta )=\sin \Theta [/tex]

Now,

[tex] \cos (90^{\circ}-(x+22)^{\circ})=\cos (2x-7)^{\circ} [/tex]

Therefore, we get

[tex] 90-(x+22)= (2x-7) [/tex]

[tex] 90-x-22= (2x-7) [/tex]

[tex] 68=3x -7 [/tex]

[tex] 75=3x [/tex]

[tex] x=25^{\circ} [/tex]

Answer:

Lets go by a step-by-step process.

Step-by-step explanation:

\cos (90-\Theta )=\sin \Theta

Now,

\cos (90^{\circ}-(x+22)^{\circ})=\cos (2x-7)^{\circ}

Now we have...

90-(x+22)= (2x-7)

90-x-22= (2x-7)

68=3x -7

75=3x

x=25^{\circ}

WILL GIVE A BRAINLEST!!!!!!

Solve and check : c-4/c-2=c-2/c+2 - 1/2-c

The solution is c =

How many extraneous solutions are there?

Answers

we have that
(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14

the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
all real numbers except c=-2 and c=2

The solution is c = 14

How many extraneous solutions are there? zero

Which expression is equivalent to the given expression? 17x−32x A. x(32−17) B. 17(x−32) C. 17x(1−32) D. x(17−32)

Answers

D is correct
good luck

Hey there!

When "[tex]x[/tex]" is by itself , it substitute as a invisible [tex]1 [/tex]

[tex]x(32 - 17) = 32x - 17x (Incorrect) \\ \\ 17(x - 32) = 17x - 544 (Incorrect) \\ \\ 17x (1 - 32 ) = 17x - 32 (Incorrect) \\ \\ x(17 - 32) = 17x - 32 (Correct) \\ \\ Answer: D. \\ \\ \\ Good \\ luck \\ on \\ your \\ assignment \\ and \\ enjoy \\ your \\ day! \\ \\ \\ LoveYourselfFirst:)[/tex]

.
The acronym CPCTC stands for “__________ parts of congruent triangles are congruent.”

calculated

congruent

corresponding

coordinated

Answers

corresponding is the answer.

Answer:

The acronym CPCTC stands for " Corresponding parts of congruent triangles are congruent. "

Step-by-step explanation:

CPCTC--

It is a rule which states that if any of the two triangles are congruent by any of the congruency such as ASA, RHS , SAS or SS then the remaining sides and the remaining angles which were not covered in the congruency are also congruent.

Also, the acronym is:

Corresponding parts of congruent triangles are congruent.

Find the value of the missing side of a triangle practice

Answers

There are many formulas to finding a side of a triangle.

Be sure to understand the differences between a right-angled triangle and an irregular-shaped triangle.

Right-angled triangle
Two sides must be known.
[tex] {a}^{2} = {b}^{2} + {c}^{2} [/tex]
where 'a' squared is the hypotenuse of the triangle.

To find the non-hypotenuse side, the formula can be rearranged to
[tex] {b}^{2} = {a}^{2} - {c}^{2} [/tex]
'b' can be any non-hypotenuse side.

Non-right angled triangle.
Cosine rule
Two sides and an angle must be know.
[tex]a = {b}^{2} + {c }^{2} - 2ab \cos(angle \: facing \: a) [/tex]
That is just a few of the formulas I have listed.

Which graph represents y – 1 = 2(x – 2)?

Answers

Answer:

The graph is attached below

Step-by-step explanation:

y – 1 = 2(x – 2)

y-1 = 2x - 4

add 1 on both sides

y = 2x - 3

To graph the given equation we make a table

Plug in some number for x and find out the value of y

x y = 2x-3

-1 2(-1)-3= -5

0 2(0) -3= -3

1 2(1) -2= -1

The point to get the graph of the given equation is

(-1,-5) (0,-3) (1,-1)

The graph is attached below

Answer:

The answer is the first graph or graph A.

BTW this is just the short answer...

Its quicker. :-)

The prime factorization of a number is 2^3*3^2*5. Which is a true statement about the factors of the number?
1. Fifteen is a factor of the number because both 3 and 5 are prime factors.
2. Fifteen is not a factor of the number because 15 is odd and the number is even.
3. Sixteen is a factor for the number because 2^3=8 and 16 is divisible by 8.
4. Sixteen is not a factor of the number because the exponent of 2 is not even.

Answers

2^3 = 8
3^2 = 9

8 * 9 * 5 = 360
15 is a factor of 360, so the answer would be 1. Fifteen is a factor of the number because both 3 and 5 are prime factors

Fifteen is a factor of the number because both 3 and 5 are prime factors and this can be determined by using the arithmetic operations.

Given :

Number -- [tex]2^3\times 3^2\times 5[/tex]

The following steps can be used in order to determine the correct statement:

Step 1 - Write the given number.

[tex]2^3\times 3^2\times 5[/tex]

Step 2 - Simplify the above expression.

[tex]= 8\times 9 \times 5[/tex]

Step 3 - Multiply 8 by 9 in the above expression.

[tex]= 72\times 5[/tex]

Step 4 - Multiply 72 by 5 in the above expression.

= 360

Step 5 - 15 is a factor of 360.

Therefore, the correct option is 1).

For more information, refer to the link given below:

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PLEASE HELP
7.03

1. Write the sum using summation notation, assuming the suggested pattern continues.
1 - 3 + 9 - 27 + ...

A) summation of one times three to the power of n from n equals zero to infinity
B) summation of one times three to the power of the quantity n plus one from n equals zero to infinity
C) summation of one times negative three to the power of n from n equals zero to infinity
D) summation of one times negative three to the power of the quantity n plus one from n equals zero to infinity

2. Write the sum using summation notation, assuming the suggested pattern continues.
-4 + 5 + 14 + 23 + ... + 131

A) summation of the quantity negative four plus nine n from n equals zero to fifteen
B) summation of negative thirty six times n from n equals zero to fifteen
C) summation of the quantity negative four plus nine n from n equals zero to infinity
D) summation of negative thirty six times n from n equals zero to infinity

3. Write the sum using summation notation, assuming the suggested pattern continues.
25 + 36 + 49 + 64 + ... + n2 + ...

A) summation of n squared from n equals five to infinity
B) summation of n minus one squared from n equals five to infinity
C) summation of n squared from n equals six to infinity
D) summation of n plus one squared from n equals five to infinity

4. Find the sum of the arithmetic sequence.
-1, 2, 5, 8, 11, 14, 17

A) 56
B) 63
C) -7
D) 20

5. Find the sum of the geometric sequence.
1, one divided by four, one divided by sixteen, one divided by sixty four, one divided by two hundred and fifty six

A) 341
B) one divided by one hundred and ninety two
C) one divided by seven hundred and sixty eight
D) three hundred and fourty one divided by two hundred and fifty six

6. Find the sum of the first 8 terms of the sequence. Show all work for full credit.
1, -3, -7, -11, ...

Answers

6.
1, -3, -7, -11, -15, -19, -23, -27...

sum:
8/2 (1 + -27)
8/2 (-26)
-104

This are 6 question and 6 answers

Problem 1. Write the sum using summation notation, assuming the suggested pattern continues.
1 - 3 + 9 - 27 + ...

Answer: option C) summation of one times negative three to the power of n from n equals zero to infinity

Explanation:

1) Sequence: 1 - 3 + 9 - 27: given

2) ratio of two consecutive terms:

- 3 / 1 = - 3

9 / (-3) = - 3

-27 / (9) = - 3

=> ratio = - 3 means that every term is the previous one multiplied by - 3

3) terms

First term: 1 * (-3)^0 = 1

Second term: 1* (-3)^1 = - 3

Third term: 1 * (-3)^2 = 9

Fourth term: 1 * (-3)^3 = - 27

So, the summation is:

∞
∑ 1 * (-3)^n ,
n=0

which is read summation of one times negative three to the power of n from n equals zero to infinity => option C.

Problem 2. Write the sum using summation notation, assuming the suggested pattern continues.

- 4 + 5 + 14 + 23 + ... + 131

Answer: option A) summation of the quantity negative four plus nine n from n equals zero to fifteen

Probe the statement A):

15
∑ (- 4 + 9n)
n=0

Now develop that summation: - 4 +9(0) - 4+ 9(1) - 4 + 9(2) - 4 + 9(3) +....+ - 4 + 9(15) = - 4 + 5 + 14 + 23 + 131

Which is the very same sequence given.Therefore, the first statement if right.

Problem 3. Write the sum using summation notation, assuming the suggested pattern continues.
25 + 36 + 49 + 64 + ... + n^2 + ...

Answer: option A) summation of n squared from n equals five to infinity

Explanation

First term: 25 = 5^2
Second term: 36 = 6^2
Third term: 49 = 7^2
Fourth term: 64 = 8^2

nth term n^2

last term: the sequence is infinite

So, you can see that the sequence is the sum of the square of the integers from n = 5 to infinity =
∞
∑ (n^2)
n = 5

which is what summation of n squared from n equals five to infinity means.

Problem 4. Find the sum of the arithmetic sequence.
-1, 2, 5, 8, 11, 14, 17

Answer: option A) 56

Explanation:

You just have to sum all the terms (since they are few numbers that is the best way): - 1 + 2 + 5 + 8 + 11 + 14 + 17 = 56

Answer: 56

Problem 5. Find the sum of the geometric sequence.
1, one divided by four, one divided by sixteen, one divided by sixty four, one divided by two hundred and fifty six

Answer: option D) 341 / 256

Explanation:
Write in form of fractions: 1 + 1/4 + 1/16 + 1/64 + 1/256

You'd better use the formula for the summation of a geometric sequence

k
∑ A * (r^n) = A * (1 - r^k) / (1 - r)
n=1

In this case: r = 1/4 (the ratio)
k = 5 (the number of terms)
A = 1 (the first term)

=> The sum = 1 * [1 - (1/4)^5 ] / [ 1 - 1/4], which when you simplify turns into 341 / 256 which is the option D.

Problem 6. Find the sum of the first 8 terms of the sequence. Show all work for full credit.
1, -3, -7, -11, ...

Answer: - 104

Explanation:

You can either sum the 8 terms or use the formula for the sum of an aritmetic sequence.

I will sum the 8 terms.

Note the the constant distance to sum is - 4, so the sum of the first eight terms is:

1 - 3 - 7 - 11 - 15 - 19 - 23 - 27 = - 104

A FIELD HOCKEY TEAM IS A RECTANGLE 60YARDS BY 100YARDS .WHAT IS THE LENGTH OF THE DIAGONAL FROM ONE CORNER TO THE FIELD TO THE OPPOSITE CORNER ROUND YOUR ANSWER TO THE NEAREST HUNDRETH

Answers

60^2 + 100^2 = X^2
3600 + 10000 = X^2
13600 = x^2
X = Sqrt(13600)
X = 116.619

Diagonal = 116.62 yards

60^2 + 100^2 = c^2
3600 + 10000 = c^2
13600 = c^2
c = 116.62 yd

Which polynomial is a quintic trinomial?

x³ + 2x² -8x + 16
x² + 4
3x⁵ + 7x² -9x⁴
-x⁴ -5x² +1

Answers

Answer:

3x⁵ + 7x² -9x⁴

Step-by-step explanation:

In the order given, the polynomials have degrees 3, 2, 5, 4. The one of degree 5 is "quintic." That one also happens to be a trinomial. It is ...

3x⁵ + 7x² -9x⁴

Steve ordered plastic cases for storing his baseball cards. Each case has a length of 12 centimeters, a width of 6.5 centimeters ,and a height of 1.25 centimeters, what is the volume, in cubic centimeters, of one baseball card case?

Answers

For this case you should see the box as a rectangular prism.
The volume of a rectangular prism is given by:
V = (L) * (W) * (H)
Where,
L: length
W: width
H: height.
Substituting the values we have:
V = (12) * (6.5) * (1.25)
V = 97.5 cm ^ 3
Answer:
the volume, in cubic centimeters, of one baseball card case is:
V = 97.5 cm ^ 3

Answer:

97.5

Step-by-step explanation:

What is the area of a sector with a central angle of π3 radians and a radius of 12.4 m? Use 3.14 for π and round your final answer to the nearest hundredth. Enter your answer as a decimal in the box.

Answers

Answer: [tex]80.47\ m^2 [/tex]

Step-by-step explanation:

The area of a sector is given by :-

[tex]\text{Area of sector}=\frac{\theta}{2}\times( r^2), \text{where }\theta\text{ is measure of central angle in radians.}[/tex]

Given :Central angle = [tex]\theta=\frac{\pi}{3}[/tex]

radius = 12.4 m

Then,

[tex]\text{Area of sector}=\frac{\frac{\pi}{3}}{2}\times( (12.4)^2)\\\\\Rightarrow\ \text{Area of sector}=\frac{\pi}{6}\times153.76\\\\\Rightarrow\ \text{Area of sector}=\frac{3.14}{6}\times153.76\\\\\Rightarrow\ \text{Area of sector}=80.4677333333\approx80.47\ m^2 [/tex]

The perimeter of a rectangle is 42 inches. If the length of the rectangle is 14 inches, which equation could be used to find the width, x? A. 2(x + 14) = 42 B. x + 2(14) = 42 C. 14(x + 2) = 42 D. x + 14 = 42

Answers

A. 2(x+14) = 42

(2x = 14
x = 7

2(7) + 2(14) = 14 + 28 = 42)

Answer:

Option A is correct

equation [tex]2(x+14)=42[/tex] could be used.

Step-by-step explanation:

Given: The length of a rectangle [tex](l)[/tex] is 14 inches and perimeter of rectangle is 42 inches.

Perimeter(P)of a rectangle in inches is given by:

[tex]P= (2l+w)[/tex] ; where [tex]l[/tex] is the length of the rectangle and w is the width of the rectangle.

Substitute the value of P=42 inches , w =x inches and [tex]l = 14[/tex] inches in the above formula we get;

[tex]42 = 2 \cdot (14+x)[/tex]

Divide by 2 on both sides we get;

[tex]21 = 14+x[/tex]

On simplify, we get;

x = 21-14 = 7 inches

therefore, the width of the rectangle is, x = 7 inches

Check :

Substitute the value of x =7 in option A.

[tex]2(x+14) =42[/tex]

[tex]2(7+14)=42[/tex]

[tex]2\cdot 21 =42[/tex]

42 = 42

Hence, the only equation that could be used to find the width, x is, [tex]2(x + 14) = 42[/tex]

Answers anybody???????

Answers

The area of the 150° sector is
.. As = (1/2)*r^2*(5π/6)

The area of the white triangle in that sector is
.. At = (1/2)*r^2*sin(5π/6)

The orange shaded area is the difference between these.
.. A = As -At = (1/2)*r^2*(5π/6 -sin(5π/6))
.. = (1/2)*(27.8 in)^2*(5π/6 -1/2)

.. A ≈ 818.4 in^2

what is the slope of the line through (2,-2) and (9,3)

Answers

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 2 &,& -2~) % (c,d) &&(~ 9 &,& 3~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-(-2)}{9-2}\implies \cfrac{3+2}{9-2}\implies \cfrac{5}{7}[/tex]

Write an equation of the line pictured in the graph.

Answers

The equation is y= -2x + 1

The answer is y = -2x + 1

the width of an architects desk is represented by four times x squared and the length is represented by the expression 2x cubed. what represents the area of the tabletop

Answers

You will use the formula A=lw to find the area. Substitute 2x^3 in for the length and 4x^2 for the width. You would multiply both of these. 2×4 = 8, and x cubed times x squared equals X to the fifth power. You will add the exponents together because the exponent tells you how many times to multiply that value. If there are three x multiplied together (in x cubes) and two x multiplied together(in x squared) that makes five x multiplied together. The answer is represented as A=8x^5. ^ means to the power of.

Could someone explain this to me?

Answers

This is a simple differentiation problem. Let's start by taking the derivative of both sides (with respect to x):
[tex]5y^4\frac{dy}{dx}+6y^2x+6x^2y\frac{dy}{dx}+20x^3 = 0[/tex]

Simplify:
[tex] \frac{dy}{dx} (5y^4+6x^2y) + 6y^2x+20x^3 = 0[/tex]

Solve for dy/dx:
[tex] \frac{dy}{dx} = \frac{-6y^2x-20x^3}{5y^4+6x^2y} [/tex]

Now, plug in the given points:
[tex]\frac{dy}{dx} = \frac{-6(2)^2(-1)-20(-1)^3}{5(2)^4+6(-1)^2(2)} = \frac{24+20}{80+12}[/tex]

Further simplification gives:
[tex]\frac{dy}{dx}|_{(2,-1)} =\frac{44}{92} = \frac{11}{23} [/tex]

So, your answer is 11/23 or B.

A field project superintendent earns an annual salary of $72,800, and she contributes $7900 per year to her 401(k) plan. If she has a required deduction for income taxes (federal, state, and local combined) of 28% of pretax income, how much does she have withheld in income taxes per year?

Answers

Contributions to one's 401K plan are taken out without paying tax on them (they are pre-tax contributions). In the end, when you retire you will pay taxes on the money but it is deferred for now.

What this means in terms of the question is that we should deduct the $7,900 first and then take 28% of what is left for taxes.

This person's salary is $72,800 a year and they set aside $7,900 for their retirement account (401K) so that leaves $72800-$7900 = $64,900

She now pays taxes of 28% on this amount ($64,900). Percent means "out of 100" so 28% means [tex] \frac{28}{100}=.28 [/tex] and to find 28% of 64900 we multiply (64900)(.28) = $18172.

That is she has $18,172 withheld in taxes each year.

An investment of $750 will be worth $1500 after 12 years of continuous compounding at a fixed interest rate. What percent is the interest rate?

Answers

Final answer:

The interest rate is 100%, or 1 as a decimal, for continuously compounded interest.

Explanation:

To find the interest rate, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final amount ($1500)P is the principal amount ($750)r is the interest rate (unknown)n is the number of times interest is compounded per year (continuously compounded)t is the time in years (12)

Using the given information, we can plug in the values and solve for r:

$1500 = $750(1 + r/1)^(1*12)$2 = 1 + rr = $2 - 1 = $1

The interest rate is 100%, or 1 as a decimal, for continuously compounded interest.

The interest rate, for continuous compounding, is approximately 5.775%.

To find the interest rate for continuous compounding, we can use the formula for compound interest:

[tex]\[ A = P \times e^{rt} \][/tex]

Where:

- [tex]$ A $[/tex] is the final amount of money,

- [tex]$ P $[/tex] is the principal amount (initial investment),

- [tex]$ r $[/tex] is the interest rate (annual rate in decimal),

- [tex]$ t $[/tex] is the time the money is invested for (in years),

- [tex]$ e $[/tex] is the base of the natural logarithm, approximately equal to 2.71828.

Given:

- [tex]$ P = $750 $[/tex],

- [tex]$ A = $1500 $[/tex],

- [tex]$ t = 12 $[/tex] years.

We need to solve for [tex]$ r $[/tex], the interest rate.

Step 1 :

**Substitute the Given Values into the Formulaa :

[tex]\[ 1500 = 750 \times e^{12r} \][/tex]

Step 2 :

**Divide Both Sides by 750**:

[tex]\[ \frac{1500}{750} = e^{12r} \][/tex]

[tex]\[ 2 = e^{12r} \][/tex]

Step 3 :

**Take the Natural Logarithm of Both Sides**:

[tex]\[ \ln(2) = \ln(e^{12r}) \][/tex]

[tex]\[ \ln(2) = 12r \ln(e) \][/tex]

[tex]\[ \ln(2) = 12r \][/tex]

Step 4 :

**Solve for [tex]$ r $[/tex]**:

[tex]\[ r = \frac{\ln(2)}{12} \][/tex]

[tex]\[ r = \frac{0.693}{12} \][/tex]

[tex]\[ r = 0.05775 \][/tex]

Step 5 :

**Convert the Interest Rate to a Percentage**:

[tex]\[ r_{\text{percentage}} = 0.05775 \times 100\% \][/tex]

[tex]\[ r_{\text{percentage}} = 5.775\% \][/tex]

So, the interest rate is approximately 5.775%.

What is the approximate area of the circle shown below 60cm

Answers

It is A 2827cm
This is the answer your welcome

Answer:

[tex]\text{Hence, the approx. area of circle }2827 cm^2[/tex]

Step-by-step explanation:

Given the diameter of circle 60 cm

we have to find the area of circle

Diameter=60 cm

Radius=30 cm

[tex]\text{Area of circle=}\pi r^2[/tex]

[tex]=\frac{22}{7}\times (30)^2=2828.57143\sim 2827(approx)[/tex]

[tex]\text{Hence, the approx. area of circle }2827 cm^2[/tex]

Option A is correct

If c is a constant such that 9x^2+10x+c is equal to the square of a binomial, then what is c?

I NEED HELP SO BAD PLEASE PLEASE PLEASE

Answers

(9x^2+10x+c) = (3x+b)^2
= 9x^2 + 6b x+ b^2

1) 6b= 10
b+ 5/3

2) c=b^2
c= (5/3) ^2
c= 25/9

(9x^2+10x+25/9)=(3x+5/3)^2

I hope this helps:)

A metal Fabricating Company produces 150,000 souvenir tokens each year. In a random sample of 400 tokens, 3 have stamping errors. Predict the total number of coins that will have stamping errors in a year.

Answers

1125
150000 divided by 400 equals 375, times 3 equals 1125.

1.4 + 2/5x = 3/15x - 0.8 How do you solve this?

Answers

it appears you are looking for x.
1.4+2/5x=3/15x-.08

you have to isolate the x
first add .08 to both sides
1.48+2/5=3/15x
i would now find the equivalence fraction of 2/5 with the denominator of 15. To do this you have to multiply 5 by 3 to get 15 so, you multiply the original numerator to get the equivalent one. 2(3)=6
1.48+6/15x=3/15x
now i am going to subtract 6/15x from both sides
1.48= -3/15x
to get rid of the fraction i am going to convert it to a decimal.
-3/15= -.2

1.48= -.2x

now i have to divide both sides by -.2
7.4=x

Can someone help me please I would appreciate it.
I well mark brainliest if u explain
Please.

Answers

The answer is c to my calculations.

what is a possible value for the missing term of the geometric sequence ?
50, blank, 450, ..

a. 1,350
b. 150
c. 3
d. 53

Answers

50 * 3 = 150 and 150 * 3 = 450

So the answer is b 150

What is the sum of the “outer” and “inner” products as described in the FOIL method when multiplying (x + 5)(x - 6)?

A. -6x

B. -x

C. x

D. 5x

Answers

The "outer" terms are x and -6, so their product is -6x.
The "inner" terms are +5 and x, so their product is 5x.
The sum of "outer" and "inner" terms is -6x +5x = -x. (selection B)

Match each whole number with a rational exponential expression. HELPP ME PLEEASE FASTTT

Answers

1. 343^(2/3)
3rdrt[(343(343)]
49

2. [2,197^(1/3)]^2
[3rdrt(2,197)]^2
169

3. 729^(2/3)
3rdrt[729(729)]
81

4. (1,000^2)^(1/3)
3rdrt(1,000^2)
100

5. [3rdrt(9261)]^2
441

6. [3rdrt(216^2)]
36

Hope this helps!

Answer:

1. 49

2. 169

3. 81

4. 100

5. 441

6. 36

Step-by-step explanation:

1. [tex](343)^{\frac{2}{3}}=\sqrt[3]{(343)^{2} }[/tex]

= [tex]\sqrt[3]{(343)(343)}=\sqrt[3]{(7^{3})(7)^{3}}[/tex]

= 7×7 = 49

2. [tex](2197^{\frac{1}{3}})^{2}=(\sqrt[3]{2197})^{2}[/tex]

= [tex](\sqrt[3]{13^{3}})^{2}=13^{2}[/tex]

= 169

3. [tex]729^{\frac{2}{3} }=(\sqrt[3]{729})^{2}[/tex]

= [tex](\sqrt[3]{9^{3}})^{2} = 9^{2}[/tex]

= 81

4. [tex](1000^{2})^{\frac{1}{3}}=(\sqrt[3]{1000})^{2}[/tex]

= 10²

= 100

5. [tex](\sqrt[3]{9261})^{2}=(\sqrt[3]{(21)^{3} })^{2}[/tex]

= 21²

= 441

6. [tex](\sqrt[3]{216})^{2}=(\sqrt[3]{6^{3} })^{2}[/tex]

= 6²

= 36

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