When choosing an item from a group, researchers have shown that an important factor influencing choice is the item's location. This occurs in varied situations such as shelf positions when shopping, filling out a questionnaire, and even choosing a preferred candidate during a presidential debateIn this experiment, five identical pairs of white socks were displayed by attaching them vertically to a blue background that was then mounted on an easel for viewingOne hundred participants from the University of Chester were used as subjects and asked to choose their preferred pairs of socksIn situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in the center. this experiment, 34 subjects chose the pair of socks in the center. Are these data evidence of the "center stage effect"? STATE: Are the students choosing pairs of socks randomly? If the students were choosing socks at random, what would be the chance, of a pair being selected? (Enter your answer rounded to one decimal place.) p 0
Answer:
a) We have evidence of the " center stage effect" pair number 3 was selected 34 times almost double the probability of random process
b) probability of ocurrency in random case is 20 %
Step-by-step explanation:
To answer this question we first look at the probability of chossing a pair in case of random selection
P = successful event / total outcomes
P₁ = 1/5
P₁ = 0,2 or P₁ = 20 %
Then if the central pair was selected 34 times from 100 participants ( almost the double ) we have evidence of the center stage effect
P₂ = 34/100 or P₂ = 0,34
In this experiment, the data showing 34 subjects choosing the center pair of socks out of 100 participants does indicate evidence of the "center stage effect" as the observed frequency surpasses the expected frequency under randomness.
To determine if the data provided is evidence of the "center stage effect," we need to analyze whether the subjects' choices align with randomness or if there is a noticeable bias towards the center socks.
1. Calculate the expected frequency of selecting the center pair of socks under the assumption of randomness:
- Since there are 5 pairs of socks, the chance of randomly selecting the center pair would be 1 out of 5.
- This gives us a probability of 1/5 or 0.2.
2. Determine the expected number of subjects choosing the center pair out of 100 participants:
- Expected frequency = Probability of selection x Total number of participants
- Expected frequency = 0.2 x 100 = 20
3. Compare the expected frequency (20) with the actual frequency observed in the data (34):
- If the observed frequency significantly exceeds the expected frequency, it suggests a bias towards selecting the center pair of socks, supporting the "center stage effect" hypothesis.
Therefore, in this experiment, the data showing 34 subjects choosing the center pair of socks out of 100 participants does indicate evidence of the "center stage effect" as the observed frequency surpasses the expected frequency under randomness.
−3x + y = 4,
−9x + 5y = −1
find x and y
Answer:
9x - 3y = -12
-9x +5y = -1
2y = -13
y = -13/2
-3x - 13/2 = 8/2
-3x = 21/2
-6x = 21
x = -21/6 = -7/2
(-7/2, -13/2)
In your homework, you were introduced to a game, called Under-or-Over-Seven. It has many rules. Here is the particular rule that we are going to use for this question: a pair of fair dice is rolled once, and the resulting sum determines whether the player wins or loses his/her bet; the player wins $9 if the result of the roll is exactly equal to 7 and loses $3 otherwise. Compute the expected value of this game (i.e., the expected gain or loss).
Answer:
EX=-$1
Step-by-step explanation:
Expected Value of Probability Distribution
Assume a discrete probability distribution is
[tex]P=\{p1,p2,p3,...pn\}[/tex]
For
[tex]X=\{x1,x2,x3,...xn\}[/tex]
The expected value is
[tex]EX=\sum x_i.p_i[/tex]
We have two possible outcomes from our random experience: The sum of the die is 7 or different from 7. If it sums 7, the player wins $9, otherwise, they lose $3. Thus
[tex]x=\{9,-3\}[/tex]
We must find the probability of having a 7. Each dice can be a 1, 2, 3 ,4 , 5, or 6. The combinations to sum 7 are 1+6, 2+5, 3+4, 4+4, 5+2, and 6+1. That is 6 possibilities out of 36 in total. The probability of having a 7 is
[tex]\displaystyle p_1=\frac{6}{36}=\frac{1}{6}[/tex]
The probability of not getting 7 is the negation of the previous event
[tex]\displaystyle p_2=1-\frac{1}{6}=\frac{5}{6}[/tex]
The probability set is:
[tex]\displaystyle P=\left\{\frac{1}{6},\frac{5}{6}\right\}[/tex]
The expected value is:
[tex]\displaystyle EX=9\cdot \frac{1}{6}-3\cdot \frac{5}{6}[/tex]
[tex]\displaystyle EX=\frac{3}{2}-\frac{5}{2}=-1[/tex]
Therefore, the player can expect to lose $1
The expected value of the game "Under-or-Over-Seven" is a loss of $1, computed by considering the probabilities of winning $9 or losing $3 based on dice sums.
To compute the expected value of the game, we need to consider all possible outcomes and their associated probabilities.
1. The sum of two fair dice can range from 2 to 12.
2. The probability of each sum can be calculated by considering all possible combinations of the dice.
Here's the breakdown of the sums and their probabilities:
- Sum of 2: Probability = 1/36
- Sum of 3: Probability = 2/36
- Sum of 4: Probability = 3/36
- Sum of 5: Probability = 4/36
- Sum of 6: Probability = 5/36
- Sum of 7: Probability = 6/36
- Sum of 8: Probability = 5/36
- Sum of 9: Probability = 4/36
- Sum of 10: Probability = 3/36
- Sum of 11: Probability = 2/36
- Sum of 12: Probability = 1/36
Now, let's calculate the expected value:
[tex]\[ E(X) = (P(X=7) \times \$9) + (P(X\neq7) \times (-\$3)) \][/tex]
[tex]\[ E(X) = (\frac{6}{36} \times \$9) + (\frac{30}{36} \times (-\$3)) \][/tex]
[tex]\[ E(X) = (\frac{6}{36} \times \$9) - (\frac{30}{36} \times \$3) \][/tex]
[tex]\[ E(X) = \frac{54}{36} - \frac{90}{36} \][/tex]
[tex]\[ E(X) = \frac{-36}{36} \][/tex]
E(X) = -$1
So, the expected value of the game is a loss of $1.
There are 946 milliliters in a quart. There are 2 pints in a quart. How many milliliters are in 5 pints?
Answer:
473 milliliters in 1 pint
Step-by-step explanation:
divide 946 by 2
Answer:
There are 473 milliliters in 1 pint so 5 pints would be 2,365
Step-by-step explanation:
Consider the equation and its solution.
8(x-2)=64
8x-16 = 64
8x = 80
x= 10
Which property is used in the last step to find that X= 10?
O
A distributive property
B Addition property of equality
C subtraction property of equality
D Division property of equality
3(n+8)=13
Gizmos Solving Algebraic Equations 2
Answer:
n= - 11/3
Step-by-step explanation:
3(n+8)=13
3n+24=13
3n=13-24
3n-11
n= - 11/3
melanie spent half of her allowance going to the movies. she washed the family car and earned 6 dollars.what is her weekly allowance if she ended with 16 dollars
Her weekly allowance is $20
Step-by-step explanation:
Let her weekly allowance be 'a'
Given that,
She spent half of the allowance (a/2)
So,
Money left with her = (a/2)
She earned $6 by washing the car
She has $16 at the end.
So,
(a/2) + 6 = 16
(a/2) = 16 - 6
(a/2) = 10
a = 10 x 2
a = 20
So, her weekly allowance is $20
What is the surface area of the prism?
A rectangular prism with a length of 3 meters, width of 4 meters, and height of 2 meters.
[Not drawn to scale]
(same figure unfolded as net)
a
18 square meters
b
24 square meters
c
52 square meters
d
64 square meters
To find the surface area of ANY prism you need to find the area of individual shape first.
To find 2 faces of the prism, you will need to do bxh. As there is 2 of the same rectangle , you need to multiply it by 2. Therefore, the first number you need is 16m squared.
To find the next part of the prism, you will need to do 2m x 3m which is 6m. You need the area so 6m squared (The units are important). There are also 2 of these, so multiply it by 2 to get 12m squared.
For the final part of the prism, you will need to do 4m x 3m which is 12m squared. There are 2 of these so the it is 24m squared.
Finally, you will need to add all these figures up.
16m squared + 12m squared + 24m squared = 52m squared
Answer:
52 m
Step-by-step explanation:
Natalie consumes only apples and tomatoes. Her utility function is U(x, y) = x 2y 8 , where x is the number of apples consumed and y is the number of tomatoes con-sumed. Natalie’s income is $320, and the prices of apples and tomatoes are $4 and $3, respectively. How many apples will she consume?
Answer:
16 apples.
Step-by-step explanation:
[tex]U(x, y) = x^2y^8[/tex]
[tex]MU_x =\frac{\partial U}{\partial x} = 2xy^8\\MU_y = \frac{\partial U}{\partial x} = 8x^2y^7\\[/tex]
Price of apples, Px=$4
Price of tomatoes, Py=$3
Ratio of their Marginal Utilities
[tex]\frac{MU_x}{MU_y} = \frac{Px}{Py}[/tex]
[tex]\frac{y}{4x} = \frac{4}{3}[/tex]
[tex]y=\frac{16x}{3}[/tex]
Since Natalie’s income is $320
320 = xPx+yPy
[tex]320=4x + 3*\frac{16x}{3} \\320= 4x+16x = 20x\\x=\frac{320}{20} = 16\\Also\\y=\frac{16x}{3}=\frac{16X16}{3}=\$85.33[/tex]
Since x=16, Natalie will consume 16 apples.
Given Natalie's budget and the prices of apples and tomatoes, plus the fact that her utility function indicates she consumes two as many tomatoes as apples, we determined that Natalie will consume up to 32 apples under these conditions.
Explanation:To determine how many apples Natalie will consume, we first need to solve the utility maximization problem where she chooses 'x' and 'y' to maximize her utility subject to her budget constraint. This problem is typically solved using calculus, but here is a simplified way of solving it:
Firstly, let's consider Natalie's budget constraint. With $320, the prices of apples and tomatoes being $4 and $3 respectively, her budget constraint is $4x + $3y ≤ $320.
Due to the nature of Natalie's utility function U(x, y) = x 2y 8, it's clear that for every apple she buys, she consumes twice as many tomatoes (since y=2x). Replacing 'y' in the budget constraint yields to $4x + $3(2x) ≤ $320, or $10x ≤ $320.
Finally, solving x gives usx ≤ 32, that is, Natalie will consume up to 32 apples.
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Angle KJL measures (7x - 8)o. Angle KML measures (3x + 8)o.
Circle N is shown. Angles K J L and K M L intersept arc K L. Angles J K M and J L M intercept arc J M.
What is the measure of arc KL?
20°
40°
48°
96°
The correct answer is 96 degrees for the circle.
Equation
Since angles KJL and KML are opposite angles of a cyclic quadrilateral, their sum is 180 degrees.
(7x - 8) + (3x + 8) = 180° is the equation.
10x = 172
x = 17.2
Therefore, angle KJL measures 7(17.2) - 8 = 115.4 degrees, and angle KML measures 3(17.2) + 8 = 52.6 degrees.
The measure of arc KL is equal to the sum of the measures of angles KJL and KML:
115.4 + 52.6 = 168
So the measure of arc KL is 168 degrees.
Therefore, the correct answer is 96 degrees, which matches one of the answer choices.
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Find the Lowest Common Multiple of 3, 5 and 6.
Answer:
30
Step-by-step explanation:
6*5= 30
3*10= 30
5*6= 30
The Lowest Common Multiple of 3, 5, and 6. is 30
The lowest common multiple of a group of numbers is the smallest number that is a multiple of all the numbers.
Given the integers 3, 5 and 6, to get the Lowest common multiple, we will need to take the product of all the integers as shown:Lowest common multiple = 3 * 5 * 6 = 60But note that 60 is not the lowest value that can go easily in the integers, hence the LCM of the numbers will be 5*6 = 30Learn more here: https://brainly.com/question/4913940
What is the probability that a five-card poker hand contains a flush (including straight and royal flushes), that is, five cards of the same suit? (Enter the value of probability in decimals. Round the answer to five decimal places.)
Answer:
0.00198
Step-by-step explanation:
The number of total ways that 5 cards can be selected from a deck of 52 cards is given as
⁵²C₅ = 2,598,960 ways.
Number of ways a flush, including straight and royal flushes, that is, five cards of the same suit can happen is given by
⁴C₁ × ¹³C₅ = 4 × 1287 = 5148
Note that of the 52 cards, each suit has 13 cards, So, ⁴C₁ represents selecting a suit out of 4 different suits and ¹³C₅ represents selecting 5 cards out of 13 cards thay a suit contains.
So, the probability of a flush
= 5148 ÷ 2,598,960 = 0.0019807923 = 0.00198 to 5 d.p
Hope this Helps!!!
The probability of five cards of the same suit is 0.00198
Probability of any event happen is calculated by, divide favourable number of outcomes by total number of outcomes.
The number of total ways that 5 cards can be selected from a deck of 52 cards is given as
Total outcomes = ⁵²C₅ = 2598960
Number of ways a flush, including straight and royal flushes, that is, five cards of the same suit can happen is given by
Number of favourable outcomes = ⁴C₁ × ¹³C₅ = 4 × 1287 = 5148
⁴C₁ represents selecting a suit out of 4 different suits .
¹³C₅ represents selecting 5 cards out of 13 cards that a suit contains.
Therefore, the probability that a five-card poker hand contains a flush,
=[tex]\frac{5148}{2598960}=0.00198[/tex]
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Roll the number cube 20 times to represent 20 purchases. What is the experimental probability of receiving a 50% coupon? Write the probability as a decimal.
Answer:
0.10
Step-by-step explanation:
The experimental likelihood of getting a 50% coupon is thus 2/20, or 0.1 to the decimal place.
What is the probability?The likelihood of rolling any one of the number cube's 6 equally likely results is 1/6. We must roll the number cube 20 times and tally how many times we receive a 50% discount in order to determine the experimental chance of doing so.
Assume that rolling a 1, 2, or 3 means you won't receive a coupon, a 4 means you'll receive a 25% coupon, a 5 means you'll receive a 50% coupon, and a 6 means you'll receive a 75% coupon.
The following outcomes are possible after 20 rolls of the number cube:
10 rolls were not given a coupon (50%)Getting a discount of 25%: 4 rolls (20%)2 rolls (10%) when using a 50% discount.4 rolls (20%) when using a 75% discount.More about the probability link is given below.
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in the past year Rita watch 14 movies that he thought were very good he wants 20 movies over the whole year of the movie she watched what percentage did she think we're very good
Answer:
70%
Step-by-step explanation:
When engaging in weight control (fitness/fat burning) types of exercise, a person is expected to attain about 60% of their maximum heart rate. For 20-year-olds, this rates is approximately 120 bpm. A simple random sample of 100 20-year-olds was taken, and the sample mean was found to be 107 bpm with a standard deviation of 45 bpm. Researchers wonder if this is evidence to conclude that the expected level is actually lower than 120 bpm. To determine this, we test the following hypothesis:
H0 : ? = 120, Ha : ? < 120
Reference: Ref 17-2
A 95% confidence interval for the population mean weight control heart rate, ?, of 20-year-olds is
Answer:
- There is enough evidence to support the claim that the heart rate level lower than 120 bpm (P-value=0.002).
- The 95% confidence interval for the population mean weight control heart rate of 20-year-olds is (98.07, 115.93).
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the heart rate level lower than 120 bpm
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=120\\\\H_a:\mu< 120[/tex]
The significance level is 0.05.
The sample has a size n=100.
The sample mean is M=107.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=45.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{45}{\sqrt{100}}=4.5[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{107-120}{4.5}=\dfrac{-13}{4.5}=-2.889[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=100-1=99[/tex]
This test is a left-tailed test, with 99 degrees of freedom and t=-2.889, so the P-value for this test is calculated as (using a t-table):
[tex]P-value=P(t<-2.889)=0.002[/tex]
As the P-value (0.002) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that the heart rate level lower than 120 bpm .
Confidence interval:
We have to calculate a 95% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=107.
The sample size is N=100.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{45}{\sqrt{100}}=\dfrac{45}{10}=4.5[/tex]
The t-value for a 95% confidence interval is t=1.984.
The margin of error (MOE) can be calculated as:
[tex]MOE=t\cdot s_M=1.984 \cdot 4.5=8.929[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=M-t \cdot s_M = 107-8.929=98.07\\\\UL=M+t \cdot s_M = 107+8.929=115.93[/tex]
The 95% confidence interval for the population mean weight control heart rate of 20-year-olds is (98.07, 115.93).
Using the t-distribution, it is found that the 95% confidence interval for the population mean weight control heart rate is (98.07, 115.93). Since the entire interval is lower than 120 bpm, it is evidence to conclude that the expected level is actually lower than 120 bpm.
We are given the standard deviation for the sample, which is why the t-distribution is used to solve this question.
The information given is:
Sample mean of [tex]\overline{x} = 107[/tex].Sample standard deviation of [tex]s = 45[/tex].Sample size of [tex]n = 100[/tex].The confidence interval is:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 100 - 1 = 99 df, is t = 1.984.
Hence:
[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 107 - 1.984\frac{45}{\sqrt{100}} = 98.07[/tex]
[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 107 + 1.984\frac{45}{\sqrt{100}} = 115.93[/tex]
The 95% confidence interval for the population mean weight control heart rate is (98.07, 115.93). Since the entire interval is lower than 120 bpm, it is evidence to conclude that the expected level is actually lower than 120 bpm.
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What is the radius and diameter of the following circle?
13 cm
Radius =
cm
Diameter =
Answer:
Radius = 6.5cm
Diameter = 13cm (given)
Step-by-step explanation:
The diameter is the length of one side of a circle to the other. It's already given in the diagram as 13cm.
The radius is half of the diameter. 13 divided by 2 is 6.5cm.
The correct answer are as follows
Radius = 6.5 cm
Diameter = 13 cm
What is Diameter and radius?The Diameter is any straight line segment passing through the center of the circle. The Radius is the half of the diameter.
So , The diameter is 13cm
and The radius is 1/2 x diameter = 1/2 x13 = 6.5cm
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Based upon market research, the Hawthorne Company has determined that consumers are willing to purchase 109 units of their portable media player each week when the price is set at $63.00 per unit. At a unit price of $12.80, consumers are willing to buy 360 units per week. (a) Determine the weekly demand equation for this product, assuming price, p, and quantity, x, are linearly related. p
Answer: The weekly demand equation would be
[tex]p=-0.2m+84.8[/tex]
Step-by-step explanation:
Since we have given that
Number of units of their portable media player = 109 units per week
Cost per unit = $63.00
At unit price of $12.80, consumer are buying 360 units per week.
So, here, p = $63.00 and x = 109 units
Here, price and quantity are linearly related by
[tex]p=mx+b\\\\63=109m+b\\\\63-109m=b-----------------(1)[/tex]
If p = $12.80, x= 360
So, the equation of price would be
[tex]12.80=360m+b\\\\12.80-360m=b-------------(2)[/tex]
From eq(1) and (2), we get that
[tex]63-109m=12.80-360m\\\\63-12.80=-360m+109m\\\\50.20=-251m\\\\\dfrac{50.2}{251}=-m\\\\-0.2=m[/tex]
So, the value of b would be
[tex]63=109m+b\\\\63-109(-0.2)=b\\\\63+21.8=b\\\\84.8=b[/tex]
So, the weekly demand equation would be
[tex]p=-0.2m+84.8[/tex]
Which type of financial institution is a non banking institution
Answer:
A Non-Bank Financial Institution (NBFI)
Step-by-step explanation:
A Non-Bank Financial Institution (NBFI) can be described as any institution without full banking license but offers loans and other financial services.
They are able to provide low cost loans due to the fact that they are privately owned and operated by individuals, as a result of this, they're mostly used by small and medium-sized enterprise.
A Non-Bank Financial Institution (NBFI) includes;
- Insurance companies.
- Pension funds.
- Pawn shops.
- Thrift or mutual credit societies.
- Credit unions.
if you have 1,000,000,000 dollars and you want to split between 10 friends how much will they get each
Answer:
Each friend would get 100000000
Step-by-step explanation:
1000000000 ÷ 10 = 100000000
Answer:
$100,000,000
Step-by-step explanation:
divide 1,000,000,000 by 10, be sure to count your zeros.
A plane travels at 3400 miles in 8 hours. How far would it travel in 6 hours?
The plane would travel approximately 4533.33 miles in 6 hours.
Explanation:To find the distance the plane would travel in 6 hours, we can use the formula:
Distance = Speed × Time
Given that the plane travels at 3400 miles in 8 hours, we can substitute the values into the formula:
Distance = 3400 × 8/6
Simplifying the expression:
Distance = 4533.33 miles
Therefore, the plane would travel approximately 4533.33 miles in 6 hours.
Suppose you own a restaurant and have a cook whose ability and attitude you are suspicious of. One of the dishes on the menu is duck cassoulet, which uses duck legs that have been slow fried over a couple of hours in oil that does not exceed a temperature of 175 degrees. This is a time consuming and monotonous process, but one that results in excellent meat that you sell for a large mark-up. You suspect your cook is lazy and doesn't properly monitor and maintain the oil temperature. You take a random sample of 15 duck legs and take them to a forensics lab where you are able to discover the maximum temperature the meat has reached. Within your sample the mean maximum temperature of the duck legs is 180 degrees with a standard deviation of 4 degrees. Meat cooked precisely to 175 degrees is what your cook is supposed to do.
A) Which of the following is true about a hypothesis test for the claim that your employee is capable (meaning he doesn't over-fry the meat) at the 90% confidence level?
Group of answer choices:
O Reject the null with a test statistic value of 1.83
O Reject the null with a test statistic value of 2.17
O Fail to reject the null with a test statistic value of 1.59
O Fail to the null with a test statistic value of 1.47
O None of the above are true
Answer:
[tex]t=\frac{180-175}{\frac{4}{\sqrt{15}}}=4.84[/tex]
[tex]df=n-1=15-1=14[/tex]
[tex]p_v =P(t_{(14)}>4.84)=0.000131[/tex]
We got a very low value for the p value so then we have enough evidence to reject the null hypothesis at any significance level commonly used. And the best conclusion based on the possible options are:
None of the above are true
Step-by-step explanation:
Data given
[tex]\bar X=180[/tex] represent the sample mean
[tex]s=4[/tex] represent the sample standard deviation
[tex]n=15[/tex] sample size
[tex]\mu_o =175[/tex] represent the value that we want to test
[tex]\alpha=0.1[/tex] represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value for the test (variable of interest)
System of hypothesis
We need to conduct a hypothesis in order to check if the true mean is above the limit of 175 degrees, the system of hypothesis would be:
Null hypothesis:[tex]\mu \leq 175[/tex]
Alternative hypothesis:[tex]\mu > 175[/tex]
The statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
And replacing we got:
We can replace in formula (1) the info given like this:
[tex]t=\frac{180-175}{\frac{4}{\sqrt{15}}}=4.84[/tex]
P-value
The degrees of freedom are given by:
[tex]df=n-1=15-1=14[/tex]
Since is a one sided test the p value would be:
[tex]p_v =P(t_{(14)}>4.84)=0.000131[/tex]
We got a very low value for the p value so then we have enough evidence to reject the null hypothesis at any significance level commonly used. And the best conclusion based on the possible options are:
None of the above are true
For the following problems, identify the type of investigation used (i.e., non-experimental, experimental, or quasi- experimental) and all independent, dependent, and, if any, extraneous variables
A researcher examines the effects of controlled breaks on reaction times of Air Traffic Controllers. The controllers are randomly assigned to two groups. Group 1 has 20 controllers who spend 45 minutes on a break in a quiet room, with no talking, TV, or other electronics. Group 2 has 20 controllers who spend their 45 minutes on a break in a common area break room where people are allowed to talk, watch TV, or use electronic devices. Following the breaks, each group of controllers returned to their shift where their reaction times were assessed.
What type of investigation is this?
What are the variables?
Answer:
Type of investigation = Experimental
Dependent variable = The reaction time of the controllers
Independent variable = Controlled breaks
Step-by-step explanation:
A researcher is examining the effects of controlled breaks on reaction times of Air Traffic Controllers.
The controllers are randomly assigned to two groups.
Group 1 and Group 2
Group 1 has 20 controllers who spend 45 minutes on a break in a quiet room, with no talking, TV, or other electronics.
Group 2 has 20 controllers who spend their 45 minutes on a break in a common area break room where people are allowed to talk, watch TV, or use electronic devices.
After the breaks, the reaction times of controllers in the two groups were measured.
Type of investigation?
This is clearly an experimental type of investigation where the researcher performs an experiment and after that measures the results.
Type of variables involved?
In this experimental investigation, we have both dependent as well as independent variable.
The controlled break is the independent variable since it can be manipulated by the researcher.
The reaction time of the controllers is the dependent variable since it is being measured and is expected to get affected when the independent variable is manipulated that is controlled breaks.
Final answer:
This is an experimental investigation where the effects of controlled breaks on reaction times of Air Traffic Controllers are examined. The independent variable is the type of break, and the dependent variable is the reaction times of the controllers.
Explanation:
The type of investigation used in this study is an experimental investigation. The independent variable in this study is the type of break given to the Air Traffic Controllers, with two levels: controlled breaks in a quiet room and breaks in a common area with allowed talking, TV, and electronic devices. The dependent variable is the reaction times of the controllers after their breaks. There are no extraneous variables mentioned in the given information.
Consider a finite population with five elements labeled A, B, C, D, and E. Ten possible simple random samples of size 2 can be selected. Using simple random sampling, what is the probability that each sample of size 2 is selected
Answer: 4/25
Step-by-step explanation:
A rectangle has a height of t^2+7t+6t
2
+7t+6t, squared, plus, 7, t, plus, 6 and a width of 2t+12t+12, t, plus, 1.
Answer:
[tex]2t^3+15t^2+19t+6[/tex]
Step-by-step explanation:
Height of the Rectangle[tex]=t^2+7t+6[/tex]
Width of the Rectangle[tex]=2t+1[/tex]
Area of the Rectangle = Height X Width
[tex]=(2t+1)(t^2+7t+6)\\=2t(t^2+7t+6)+1(t^2+7t+6)\\=2t^3+14t^2+12t+t^2+7t+6\\$Collect like terms\\=2t^3+14t^2+t^2+12t+7t+6\\Area=2t^3+15t^2+19t+6\\[/tex]
The area of the rectangle is [tex]2t^3+15t^2+19t+6[/tex]
The height of the rectangle is[tex]t^4 + 26t^3 + 169t^2 + 7t + 6,[/tex] and the width is 26t + 1.
It seems there might be some confusion in the way the dimensions of the rectangle are presented. To clarify, let's break down the height and width of the rectangle:
Height:
The height of the rectangle is given as [tex](t^2 + 7t + 6t)^2[/tex] + 7t + 6.
To simplify the expression inside the parentheses:
[tex](t^2 + 7t + 6t)^2[/tex] = [tex](t^2 + 13t)^2[/tex]= [tex]t^4 + 26t^3 + 169t^2[/tex]
So, the height of the rectangle is[tex]t^4 + 26t^3 + 169t^2 + 7t + 6.[/tex]
Width:
The width of the rectangle is given as 2t + 12t + 12t + 1.
Combine like terms in the width expression:
2t + 12t + 12t + 1 = 26t + 1
So, the width of the rectangle is 26t + 1.
Now you have the height and width of the rectangle expressed as functions of "t":
Height = [tex]t^4 + 26t^3 + 169t^2 + 7t + 6.[/tex]
Width = 26t + 1
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What is bigger 4.17 or 4.085
Answer:
4.17
Step-by-step explanation:
Answer:
4.17 is greater than 4.085
Step-by-step explanation:
Evaluate the following expression for x = 15.
1/5 x -12
Will give Brainliest if correct!
Answer:
-9
Step-by-step explanation:
Plug in 15 for x in the equation
you should get (1/5*15) -12
multiply 1/5 and 15 to get 3
then 3-12=-9
therefore the answer is -9
PLEASE HELP. I’ll mark you as brainliest if correct
Which of the following could be a value that represents x as a solution?
X>9
A. 0
B. 8
C. 9
D. 18
Which of the following represents K as a solution?
K > 55. There’s a greater or equal sign
A. Any number greater than 55
B. Any number less than or equal to 55
C. Any number less than 55
D. Any number greater than or equal to 55
Answer:
Both of them are D
Step-by-step explanation:
1ST QUESTION
D. 18
2ND QUESTION
D. Any number greater than or equal to 55
brainliest?
(7g+3)(−g−3)
polynomial in standard form
Step-by-step explanation:
[tex](7g + 3)( - g - 3) \\ = 7g( - g - 3) + 3( - g - 3) \\ = - 7 {g}^{2} - 21g - 3g - 9 \\ \red{ \bold{ = - 7 {g}^{2} - 24g - 9 }} \\ is \: in \: the \: standard \: form.[/tex]
-7g² - 24g - 9 is the polynomial in standard form.
What is a polynomial?In equations like the quadratic equation, cubic equation, etc., a polynomial function is a function that only uses non-negative integer powers or only positive integer exponents of a variable.
Given an equation (7g+3)(−g−3) to convert it into the polynomial form we need to simplify it. Hence,
(7g+3)(−g−3) => -7g² - 21g- 3g -9
=> -7g² - 24g - 9
Therefore, for the given problem -7g² - 24g - 9 is the polynomial in standard form.
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13
cuadro para
divisible
Juan, Maria y Carlos fueron a un museo.
La entrada general costaba $$ por
persona, pero, por ser estudiantes, les
aplicaba un descuento de $1 por boleto.
Después del recorrido, los tres compraron
lo siguiente para comer:
. 3 combos de pollo y papas fritas a
$4 cada uno
• 3 botellas de agua a $1 cada una
• 3 mantecados de vainilla a $1 cada uno
¿Cuánto dinero pagó cada estudiante si
dividieron el total de los gastos en partes
iguales?
The question is incomplete. The complete question is as follows.
Juan, Carlos and Maria went to the museum. The entrance ticket cost $5 per person, but, as they are students, there is a discount of $1 per ticket. After, they bought: 3 combos of chicken and fries costing $4 each; 3 bottles of water costing $1 each; 3 vanilla cookies costing $1 each; How much money each student paid if they divided the costs in equal amount?
Answer: $10
Step-by-step explanation: As each students split the bill in equal parts, to find how much they spent, we can calculate how much one of the three spent.
For ticket: 5 - 1 (because of the students discount) = $4
Each combo of chicken and fries cost $4, so: combo = $4
Each bottle of water costs $1, so: water = $1
and each vanilla cookie costs $1: cookie = $1
Total spent is:
T = 4+4+1+1
T = 10
Each student spent a total of $10 for this outing.
Suppose the investigator believes that virtually all values of breakdown voltage are between 40 and 70. What sample size would be appropriate for the 95% CI to have a width of 2 kV? (so that m is estimated to within 1 kV with 95% confidence)
Approximately 215 samples are needed for a 95% confidence interval estimating the mean breakdown voltage with a 2 kV width and a 1 kV margin of error, assuming the range is 40 to 70 kV.
To determine the required sample size for estimating the mean breakdown voltage with a 95% confidence interval (CI) width of 2 kV and an estimated margin of error (m) of 1 kV, you can use the formula:
[tex]\[ n = \left(\frac{{Z^2 \cdot \sigma^2}}{{m^2}}\right) \][/tex]
Where:
- n is the required sample size,
- Z is the Z-score corresponding to the desired confidence level (for 95%, it's approximately 1.96),
- [tex]\( \sigma \)[/tex] is the estimated standard deviation of the population.
Since you mentioned the investigator believes breakdown voltage is between 40 and 70, assuming a uniform distribution, you might consider using [tex]\( \sigma = \frac{{\text{{range}}}}{4} \)[/tex] as an approximation. Therefore,
[tex]\[ \sigma = \frac{{70 - 40}}{4} = 7.5 \][/tex]
Now plug these values into the formula:
[tex]\[ n = \left(\frac{{1.96^2 \cdot 7.5^2}}{{1^2}}\right) \][/tex]
Let's calculate the required sample size n:
[tex]\[ n = \frac{{(1.96)^2 \cdot (7.5)^2}}{{1^2}} \]\[ n = \frac{{3.841 \cdot 56.25}}{{1}} \]\[ n \approx \frac{{214.6}}{{1}} \]\[ n \approx 214.6 \][/tex]
So, the required sample size for the 95% confidence interval to have a width of 2 kV (with a margin of error of 1 kV) is approximately 215.
Therefore, the investigator would need a sample size of about 215 to estimate the mean breakdown voltage with the desired level of confidence and precision.