The reaction rate is the rate at which reactants convert to the product. The rate of appearance of hydrogen is [tex]\bold{ 0.070 ms^-^1}[/tex]
The given reaction,
[tex]\bold { 2HBr(g) \rightarrow H_2 (g)+Br_2(g)}[/tex]
2 moles of HBr degrade to form 1 mole of Hydrogen and 1 mole of bromine.
The rate of disappearance of HBr = 0.140 m [tex]\bold {s^-^1}[/tex]
Since the molar ratio between HBr and Hydrogen is 2:1.
So,
[tex]\bold{Ra(H_2) = \dfrac {Rd(HBr)} {2}}[/tex]
Where,
[tex]\bold{Ra(H_2)}[/tex] - Rate of appearance of Hydrogen
[tex]\bold{ Rd(HBr)}[/tex]- Rate of disappearance of HBr
Put the value,
[tex]\bold{Ra(H_2) = \dfrac {Rd(HBr)} {2}}\\\\\bold {Ra(H_2) = \dfrac {0.140 m/s} {2}}\\\\\bold { Ra(H_2) = 0.070 ms^-^1}[/tex]
Therefore, the rate of appearance of hydrogen is [tex]\bold{ 0.070 ms^-^1}[/tex].
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Asexual reproduction involves
A.
two parents and results in offspring that are identical to one parent.
B.
only one parent and results in offspring that are very different from the parent.
C.
two parents and results in offspring that are different from both parents.
D.
only one parent and results in offspring that are identical to the parent.
Answer:
d) only one parent and results in offspring that are identical to the parent.
Explanation:
just did the study island
Final answer:
Asexual reproduction requires only one parent and gives rise to genetically identical offspring, seen in processes like binary fission.
Explanation:
Asexual reproduction involves only one parent and results in offspring that are genetically identical to the parent. This method of reproduction is seen in all prokaryotes and some eukaryotes, through various mechanisms such as binary fission, fragmentation, and budding.
In binary fission, a common form of asexual reproduction, the parent cell divides to form two identical daughter cells.
Asexual reproduction requires only one parent and gives rise to genetically identical offspring, seen in processes like binary fission.
Give the product of the reaction of excess benzene (2 equivalents) with dichloromethane and alcl3.
In the presence of AlCl3, excess benzene reacts with dichloromethane to undergo a Friedel-Crafts alkylation, resulting in the product 1,2,4-trichloro-5,5-diphenylpentane.
Explanation:When dichloromethane is treated with excess benzene in the presence of an aluminum chloride catalyst (AlCl3), a Friedel-Crafts alkylation occurs. This is a type of electrophilic aromatic substitution reaction that introduces an alkyl group into the benzene ring. Here, the final product would be a dichloromethylated benzene molecule.
However, considering biselective alkylation resulting from the use of 2 equivalents of benzene, the product would be 1,2,4-trichloro-5,5-diphenylpentane. The reaction would be as follows: 2 equivalents of Benzene + CH2Cl2 (Dichloromethane) ->[AlCl3 catalyst] 1,2,4-trichloro-5,5-diphenyl pentane
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Lithium is a metal with an oxidation number of 1+ and oxygen is a nonmetal with an oxidation number of 2-. which chemical formula represents the compound formed by these two elements?
a.li2o
b.li3o
c.lio
d.lio2
Answer: Option (a) is the correct answer.
Explanation:
According to the cross multiplication method, charges present on the combining atoms cross multiply with the atoms in order to keep the molecule formed neutral.
For example, oxidation number of lithium is +1 and oxidation number of oxygen is -2.
So, when both of them chemically combine with each other then lithium atom will get multiplied by 2 whereas oxygen atom will get multiplied by 1.
Therefore, we can conclude that formula of this chemical compound will be [tex]Li_{2}O[/tex].
This radioactive particle, emitted from carbon-14, has a negative charge. It contains sufficient energy to burn human skin and can pass through paper. It is a(n) ___________ particle.
The radioactive particle, emitted from carbon-14, has a negative charge and is known as a Beta particle.
What is a Beta particle?A beta particle can be described as a high-energy, high-speed electron or positron emitted by the radioactive decay of an atomic nucleus in beta decay. There are β− decay and β+ decay, which produce electrons and positrons respectively. Beta particles have negative charge electrons released by the nucleus on the decay splitting of a neutron.
Beta particles have an energy of 0.5 MeV and a range of about one meter in the air. Beta particles are ionizing radiation but less ionizing than alpha particles. The higher the ionizing effect, the more damage to the living tissue of human tissue.
The beta particle has medium penetrating power and medium ionizing power. Although the beta particles emitted by different radioactive materials vary in energy and this radioactive carbon-14 also emits beta particles.
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Which of the following is NOT true of fusion?
Question 9 options:
2 or more smaller atoms come together to create a larger atom
Occurs in the stars, such as the sun
Used in nuclear power plants
High density, high temperature is required
How much energy is required to decompose 800 g of pcl3, according to the reaction below? the molar mass of pcl3 is 137.32 g/mol and may be useful. 4 pcl3(g) → p4(s) + 6 cl2(g) δh∘rxn = +1207 kj how much energy is required to decompose 800 of , according to the reaction below? the molar mass of is 137.32 and may be useful. 4 (g) (s) + 6 (g) = +1207 1.76×103 kj 4.53×103 kj 2.31×103 kj 6.72×103 kj 5.90×103 kj?
The amount of energy required to decompose 800 g of [tex]{\text{PC}}{{\text{l}}_{\text{3}}}[/tex] is [tex]\boxed{{\text{1757}}{\text{.8 kJ}}}[/tex].
Further explanation:
Decomposition reactions:
The opposite of combination reactions is called a decomposition reaction. Here, a single reactant gets broken into two or more products. Such reactions are usually endothermic because energy is required to break the existing bonds between the reactant molecules.
Examples of decomposition reactions are as follows:
(a) [tex]2{{\text{H}}_2}{{\text{O}}_2}\to2{{\text{H}}_2}{\text{O}}+{{\text{O}}_2}[/tex]
(b) [tex]2{\text{NaCl}}\to{\text{2Na + C}}{{\text{l}}_2}[/tex]
Stoichiometry of a reaction is used to determine the amount of species present in the reaction by the relationship between reactants and products. It is used to determine moles of a chemical species when moles of other chemical species present in the reaction is given.
Consider the general reaction,
[tex]{\text{A}}+2{\text{B}}\to3{\text{C}}[/tex]
Here,
A and B are reactants.
C is the product.
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.
The decomposition of [tex]{\text{PC}{\text{l}_3}[/tex] occurs as follows:
[tex]{\text{4PC}}{{\text{l}}_3} \to {{\text{P}}_4} + 6{\text{C}}{{\text{l}}_2}[/tex]
The formula to calculate the moles of [tex]{\text{PC}}{{\text{l}}_3}[/tex] is as follows:
[tex]{\text{Moles of PC}}{{\text{l}}_3}=\frac{{{\text{Given mass of PC}}{{\text{l}}_3}}}{{{\text{Molar mass of PC}}{{\text{l}}_3}}}[/tex] …… (1)
The given mass of [tex]{\text{PC}}{{\text{l}}_3}[/tex]is 800 g.
The molar mass of [tex]{\text{PC}}{{\text{l}}_3}[/tex]is 137.33 g/mol.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Moles of PC}}{{\text{l}}_3}&=\left( {{\text{800 g}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{137}}{\text{.33 g}}}}}\right)\\&=5.8253\;{\text{mol}}\\\end{aligned}[/tex]
From the balanced chemical reaction of decomposition of [tex]{\text{PC}}{{\text{l}}_3}[/tex], 4 moles of [tex]{\text{PC}}{{\text{l}}_3}[/tex] require 1207 kJ of energy. So the amount of energy required to decompose 5.8253 moles of [tex]{\text{PC}}{{\text{l}}_3}[/tex] is calculated as follows:
[tex]\begin{aligned}{\text{Amount of energy required}}&=\left({5.8253\;{\text{mol PC}}{{\text{l}}_3}}\right)\left({\frac{{{\text{1207 kJ}}}}{{{\text{4 mol PC}}{{\text{l}}_3}}}}\right)\\&={\text{1757}}{\text{.7842}}\;{\text{kJ}}\\&\approx{\text{1757}}{\text{.8 kJ}}\\\end{aligned}[/tex]
So the amount of energy required to decompose 800 g of [tex]{\mathbf{PC}}{{\mathbf{l}}_{\mathbf{3}}}[/tex] is 1757.8 kJ.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole Concept
Keywords: PCl3, P4, Cl2, 6 Cl2, 4 PCl3, amount of energy, 1757.8 kJ, moles of PCl3, molar mass, given mass, 800 g, 137.33 g/mol, stoichiometry, reactant, product, decomposition reaction, 1207 kJ.
To determine the quantity of energy required to decompose 800 grams of [tex]PCl_3[/tex] is 1,757.82 kJ.
Given the following data:
Mass of [tex]PCl_3[/tex] = 800 gramsMolar mass of [tex]PCl_3[/tex] = 137.32 g/molTo determine the quantity of energy required to decompose 800 grams of [tex]PCl_3[/tex]:
First of all, we would write the properly balanced chemical equation for the decomposition of [tex]PCl_3[/tex]:
[tex]4PCl_3_{(g)} --->P_4_{(s)} +6Cl_2_{(g)} \ \;\delta h^{\circ}rxn =+1207 \;kJ[/tex]
Next, we would find the number of moles of [tex]PCl_3[/tex] contained in the chemical equation:
[tex]Number\;of\;moles = \frac{Mass}{molar\;mass}\\\\Number\;of\;moles = \frac{800}{137.32 }[/tex]
Number of moles = 5.8254 moles.
By stoichiometry:
4 moles of [tex]PCl_3[/tex] = 1207 kJ
5.8254 moles of [tex]PCl_3[/tex] = X kJ
Cross-multiplying, we have:
[tex]4 \times X = 1207 \times 5.8254\\\\4X=7,031.2578\\\\X=\frac{7,031.2578}{4}[/tex]
Energy, X = 1,757.82 kJ
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Maple syrup has a density of 1.325 g/ml, and 100.00 g of maple syrup contains 67 mg of calcium in the form of ca2+ ions. what is the molarity of calcium in maple syrup?
The molarity of calcium in maple syrup is 33.4 M.
Explanation:To find the molarity of calcium in maple syrup, we need to first convert the given amount of calcium from milligrams to grams. Since there are 1000 milligrams in a gram, 67 mg is equal to 0.067 g. Next, we divide the mass of calcium by the density of maple syrup to find the volume of maple syrup.
Volume of maple syrup = mass of calcium / density of maple syrup = 0.067 g / 1.325 g/ml = 0.0506 ml
Now, we can calculate the molarity of calcium (Ca2+) in maple syrup by dividing the moles of calcium by the volume of maple syrup in liters:
Molarity = moles of calcium / volume of maple syrup = (0.067 g / 40.08 g/mol) / (0.0506 ml / 1000 ml/L) = 33.4 M
Compound b (c9h9no4) is a carboxylic acid that has a nitro group attached to an aromatic ring. draw this compound based on its 1h nmr spectrum.
How many moles of al does 13.49 g of al represent?
how many moles of Na3PO4 would be required to react with 1.0 mol of AgNO3?
Answer: The number of moles of sodium phosphate required is 0.33 moles
Explanation:
We are given:
Moles of silver nitrate = 1 mole
The chemical equation for the reaction of sodium phosphate and silver nitrate follows:
[tex]Na_3PO_4+3AgNO_3\rightarrow 3NaNO_3+Ag_3PO_4[/tex]
By Stoichiometry of the reaction:
3 moles of silver nitrate reacts with 1 mole of sodium phosphate.
So, 1.0 moles of silver nitrate will react with = [tex]\frac{1}{3}\times 1.0=0.33mol[/tex] of sodium phosphate.
Hence, the number of moles of sodium phosphate required is 0.33 moles
Shown below is a lewis structure of the formamidinium ion. what geometry is exhibited by the two nitrogens in the formamidinium ion?
The geometry around the nitrogens in the formamidinium ion can be inferred based on principles of molecular geometry, likely exhibiting either trigonal planar or tetrahedral geometry, depending on their specific bonding and hybridization states.
Explanation:The question asks about the geometry exhibited by the two nitrogens in the formamidinium ion. To answer this, we refer to basic principles of molecular geometry and electron-pair geometry in chemistry. While the formamidinium ion isn't directly analogous to the ammonium ion, NH4+, which exhibits a tetrahedral electron-pair geometry and a tetrahedral molecular structure, we can deduce similarities based on the presence of nitrogen atoms and their bonding characteristics. In general, nitrogen atoms in amides or similar compounds tend to exhibit sp2 or sp3 hybridization, depending on their bonding and lone pairs.
In the case of the formamidinium ion, each nitrogen would likely be surrounded by three regions of electron density (due to bonds or lone pairs), suggesting an approximate trigonal planar geometry around each nitrogen if they exhibit sp2 hybridization, or a tetrahedral geometry if there's additional bonding or lone pairs leading to sp3 hybridization. However, without the explicit Lewis structure presented, it's crucial to consider the context of the ion's structure, including resonance and the role of any lone pairs or charged species in determining final geometry.
What is the difference between traits and characteristics?
A Characteristic is the unique assets, talents, and qualities of a person. On the other hand, a trait is a feature of a person that is hereditary or inherited from parents or offspring. The characteristics are usually something that a person can learn and built by absorption, a trait, on the other hand, is something you have since birth.
Answer:
the person on top is correct
Explanation:
Draw the lewis structure with the atoms arranged as hclo. include all non-bonding electronsand non-zero formal charges. do not draw cl with an expanded octet.
The Lewis structure of HClO consists of bonds from Cl to each of H and O, with Cl having 5 pairs of non-bonding electrons and O having 2 pairs.
Explanation:To create the Lewis structure for HCLO, start by counting valence electrons. Hydrogen (H) has 1, Oxygen (O) has 6, and Chlorine (Cl) has 7. This totals to 14. Next, choose the atom with the least electronegativity (Cl in this case) to be the central atom, and draw bonds to other elements. A bond to each H and O from Cl uses up 4 electrons, leaving 10. Now fill the octets of the H and O atoms.
The Lewis structure should then look like this:
H - Cl - O
With 5 pairs of non-bonding electrons around Cl and two pairs of non bonding electrons around O.
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How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield for the reaction is 65.0%? 3 na2s(aq) + 2 fecl3(aq) → fe2s3(s) + 6 nacl(aq)?
100mL of [tex]\rm \bold { Fe_2Cl_3}[/tex] is needed to react with an excess of [tex]\rm \bold {Na_2 S}[/tex] to produce 1.38 g of [tex]\rm \bold { Fe_2S_3}[/tex] .
The reaction is
[tex]\rm \bold{3 Na_2S(aq) + 2 FeCl_2(aq) \rightarrow Fe_2S_3(s) + 6 NaCl(aq)}[/tex]
The mass of [tex]\rm \bold { Fe_2S_3}[/tex] is 1.38 g
The number of moles of [tex]\rm \bold { Fe_2S_3}[/tex] will be 0.00664 moles.
If the if the percent yield for the reaction is 65.0% or 0.65.
[tex]\rm \bold { Theoritical Yield = \frac{0.00664}{0.65} }\\\\\rm \bold { Theoritical Yield = 0.01 Moles}[/tex]
Since 2 mole of [tex]\rm \bold { Fe_2Cl_3}[/tex] is needed to produce 1 mole of [tex]\rm \bold { Fe_2S_3}[/tex].
[tex]\rm \bold { Fe_2Cl_3}[/tex] concentration is 0.020 mol
To find the from molarity formula
[tex]\rm \bold { V = \frac{n}{M} = \frac{0.020 mol}{ 0.2 M} / = 0.1 liter = 100 ml}\\\\\rm \bold { V = \frac{0.020 mol}{ 0.2 M} }\\\\\rm \bold { V = 0.1 liter = 100 ml}[/tex]
Hence we can conclude that 100mL of [tex]\rm \bold { Fe_2Cl_3}[/tex] is needed to react with an excess of [tex]\rm \bold {Na_2 S}[/tex] to produce 1.38 g of [tex]\rm \bold { Fe_2S_3}[/tex] .
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To learn more about the genetic material of plant and animal cells, where would a person look?
A.in the lysosomes
B.in the nucleus
C.inside the chloroplasts
D.on the cell wall
Draw the major organic product formed when the compound shown below undergoes a reaction with two equivalents of ch3ch2mgbr and then is treated with water.
The product of the reaction is 3-ethylpentan-3-ol .
What is the Grignard reagent?The Grignard reagent is a compound that is composed of an alkyl magnesium halide. Hence the general formula of a Grignard reagent is RMgX.
Since we are using two equivalents of ch3ch2mgbr and then is treat with water, the product compound is 3-ethylpentan-3-ol as shown in the image attached to this answer.
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6. The illustration below represents the Grand Canyon..
When concentrated [tex]CaCl_{2}(aq)[/tex] is added to [tex]Na_{2}HPO_{4}[/tex], a white precipitate forms that is 38.7% Ca by mass. Write a net ionic equation representing the probable reaction that occurs.
When concentrated is added to , a white precipitate forms that is 38.7% Ca by mass a net ionic equation is CO₃²⁻ ( aqueous ) + Ca₂²⁻( aqueous ) ⇒ CaCO3 (s)
What is molecular formula ?Chemical element symbols, numbers, and occasionally additional symbols like parentheses, dashes, brackets, commas, and plus and minus signs are used in a chemical formula to represent information about the chemical proportions of the atoms that make up a certain chemical compound or molecule.
Molecular formula:
Na₂CO₃ ( aq ) + CaCl₂ ( aq ) = CaCO₃ ( s ) + 2 NaCl
Ionic formula:
2 Na+ ( aq ), CO₃²⁻ ( aq ), Ca₂ ( aq ), and 2 Cl⁻ ( aq ) result in CaCO3²⁻ (s) +2 Na+ ( aq ) and 2 Cl⁻ (aq)
Net ionic formula
CO₃²⁻ ( aqueous ) + Ca₂²⁻( aqueous ) ⇒ CaCO3 (s)
Thus, When concentrated is added to , a white precipitate forms that is 38.7% Ca by mass a net ionic equation is CO₃²⁻ ( aqueous ) + Ca₂²⁻( aqueous ) ⇒ CaCO3 (s)
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Final answer:
The probable reaction between concentrated CaCl₂(aq) and Na₂HPO₄ forms calcium phosphate, Ca₃(PO₄)₂, as a white precipitate. The net ionic equation for the formation of this precipitate is 3Ca²⁺(aq) + 2PO₄³⁺(aq) → Ca₃(PO₄)₂(s). This demonstrates the common ion effect, decreasing the solubility of a sparingly soluble salt.
Explanation:
When concentrated CaCl₂(aq) is added to Na₂HPO₄, it is likely that a precipitation reaction occurs resulting in the formation of calcium phosphate, which is very slightly soluble in water. The white precipitate formed is most probably calcium phosphate, Ca₃(PO₄)₂, which is 38.7% Ca by mass.
The net ionic equation for the reaction that would lead to the formation of this precipitate is:
3Ca²⁺(aq) + 2PO₄³⁺(aq) → Ca₃(PO₄)₂(s)
Through this reaction, we see the common ion effect, which reduces the solubility of calcium phosphate in the presence of additional Ca²⁺ ions provided by the CaCl₂, leading to the precipitation of Ca₃(PO₄)₂.
A part of the periodic table is shown. A portion of the fifteenth and sixteenth columns of the periodic table is shown. Column 15 from top to bottom reads seven nitrogen, 15 phosphorus, and 33 arsenic. Column 16 reads eight oxygen, 16 sulfur, and 34 selenium. Which of the following elements is more reactive than the others? Nitrogen (N) Oxygen (O) Selenium (Se) Sulfur (S)
Answer: The correct answer is oxygen.
Explanation:
Reactivity is defined as the tendency of an atom to loose or gain electrons.
The reactivity of non-metal increases as we move from left to right in a period and decreases as we move from top to bottom in a group.
The given elements are non-metals as they belong to group 15 and group 16 of the periodic table.
For the given options:
Nitrogen (N): It belongs to Group 15 and Period 2 of the periodic table.
Oxygen (O): It belongs to Group 16 and Period 2 of the periodic table.
Selenium (Se): It belongs to Group 16 and Period 4 of the periodic table.
Sulfur (S): It belongs to Group 16 and Period 3 of the periodic table.
From the given elements, the most reactive element will be oxygen.
Order of reactivity of metals follows:
[tex]\text{Oxygen}>\text{Nitrogen}>\text{Sulfur}>\text{Selenium}[/tex]
Hence, the correct answer is oxygen.
How can a charged atom (an ion) attract a neutral atom? 1. the charged atom can hit the neutral atom and make it positively charged or negatively charged. 2. an ion polarizes a nearby neutral atom, so that the part of the atom nearer to the ion acquires a charge opposite to the charge of the ion, and the part of the atom farther from the ion acquires a charge of the same sign as the ion. 3. the charged atom can produce secondary electrons to interact with the neutral atom and make it positively charged or negatively charged. 4. the charged atom can emit x-rays to induce ionization of the neutral atom?
What energy conversion is occurring in a solar panel?
a). Nuclear energy is converted to electrical energy
b). Electrical energy is converted to radiant energy
c). Radiant energy is converted to electrical energy
d). Radiant energy is converted to nuclear energy
Which of the following is the correct name for the compound MgBr2?
Magnesium bromate
Magnesium bromide
Magnesium dibromide
Magnesium (1) bromide
If a reaction mixture initially contains a co concentration of 0.1470 and a cl2 concentration of 0.175 at 1000k. what is the equilibrium concentration of co at 1000 k?
Which atom would be expected to have a half-filled 4s subshell?
The element Vanadium (V) is expected to have a half-filled 4s subshell due to its unique electron configuration that favors stability, with the configuration shifting to [Ar] 3d54s1 to achieve a half-filled 4s orbital.
Explanation:An atom expected to have a half-filled 4s subshell is Vanadium (V), with an atomic number of 23. The electronic configuration is [Ar] 3d34s2. However, due to the stability offered by half-filled subshells, one electron from the 4s orbital will move to the 3d subshell, resulting in the configuration of [Ar] 3d54s1, which is half-filled in its 4s subshell.
Other elements like Chromium (Cr) and Copper (Cu) also exhibit adjustments in their electron configurations in favor of stability with either half-filled or fully-filled d subshells. The electron configuration of Cr is [Ar] 3d54s1 and for Cu, it is [Ar] 3d104s1, both deviating from what would be predicted by the Aufbau principle, highlighting the special stability of half-filled and fully-filled subshells.
when the ph of a solution changes from a ph of 5 to a ph of 3 the hydronium ion concentration is
When the pH of a solution changes from 5 to 3, the hydronium ion concentration increases significantly.
PH of Solution:
The relationship between pH and hydronium ion concentration
[H₃O⁺] is given by the formula:
pH = -log [H₃O⁺]
To find the hydronium ion concentrations at pH 5 and pH 3:
At pH 5: [H₃O⁺] = 10⁻⁵ M
At pH 3: [H₃O⁺] = 10⁻³ M
Thus, the hydronium ion concentration increases by a factor of 100 when the pH changes from 5 to 3
Consider this reaction: 2Al(s) + 3 CuCl2(aq) → 2AlCl3(aq) + 3 Cu(s) If the concentration of CuCl2 drops from 1.000 M to 0.655 M in the first 30.0 s of the reaction, what is the average rate of reaction over this time interval?
For 520.0 ml of a buffer solution that is 0.175 m in hc2h3o2 and 0.165 m in nac2h3o2, calculate the initial ph and the final ph after adding 0.020 mol of hcl.
Which of the following statements describes an interaction between the geosphere and biosphere?
A.Soil acidity affects plant growth
B.Polar animals find their habitat in frozen ice.
c. Wind energy is used to create electrical power.
DLevel of precipitation has an impact on crop yield
Answer:
The correct answer is A) Soil acidity affects plant growth.
Explanation:
What happens when you place a plant in soil and of course add water? The soil helps it grow.
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An object that is traveling around another body in space is in ______ around that body
An object traveling around another body in space is in orbit. This balance between inertia and gravitational pull defines the path and shape of the orbit, which can be circular or elliptical.
An object that is traveling around another body in space is in orbit around that body. An orbit is a regular, repeating path that one object in space takes around another one. An object in orbit is in a delicate balance between the inertia of its motion in a straight line and the gravitational pull that the other body exerts on it. Familiar examples include the Earth orbiting the Sun or the Moon orbiting Earth. The shape of an orbit can be circular or elliptical, and the mechanics of orbits are governed by the laws of physics, particularly by Newton's Law of Universal Gravitation and his laws of motion.
If the δh°soln of hno3 is –33.3 kj/mol, then how much heat is evolved by dissolving 0.150 mol hno3 in 100.0 ml of water?
By using the equation q = nΔH, where 'q' is the heat evolved or absorbed, 'n' is the number of moles, and 'ΔH' is the enthalpy change per mole, it is calculated that 5.0 kJ of heat is evolved when 0.150 mol of HNO3 is dissolved in 100.0 ml of water.
Explanation:The amount of heat released or absorbed in a reaction is typically calculated using the equation q = nΔH, where 'q' is the heat evolved or absorbed, 'n' is the number of moles, and 'ΔH' is the enthalpy change per mole. Given that the enthalpy of dissolving HNO3, ΔH°soln, is -33.3 kJ/mol, and we are dissolving 0.150 mol HNO3, we can substitute these values into the equation.
So, q = nΔH = 0.150 mol * -33.3 kJ/mol = -5.0 kJ.
The negative sign indicates that the heat is evolved (released), as per the question. Thus, 5.0 kJ of heat is evolved by dissolving 0.150 mol HNO3 in 100.0 ml of water.
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When 0.150 mol of HNO3 is dissolved in 100.0 ml of water, 5 kJ of heat is released. This is calculated using the equation q = n x δh°soln over the negative valence of the enthalpy change -33.3 KJ/mol.
Explanation:The amount of heat evolved from dissolving a substance in solution can be found using the equation q = n x δh°soln, where q is the heat evolved, n is the number of moles, and δh°soln is the enthalpy change per mole of solute. In this case, you have been given the enthalpy change per mole of HNO3 (δh°soln) as -33.3 kJ/mol, and the number of moles (n) as 0.150 mol. Plugging these into the equation gives q = 0.150 mol x -33.3 kJ/mol = -5 kj. This means that 5 kJ of heat is released when 0.150 mol of HNO3 is dissolved in 100.0 ml of water.
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