The reaction below shows how silver chloride can be synthesized. AgNO3 + NaCl Right arrow. NaNO3 + AgCl How many moles of silver chloride are produced from 15.0 mol of silver nitrate? 1.0 mol 15.0 mol 30.0 mol 45.0 mol

Answer:

4.2 L O₂ is needed to completely react with 2.8 L hydrogen sulfied.

Explanation:

Without pressure and temperature we cannot calculate the this vale

We assume that the reaction  take place under standard Temperature and Pressure(STP).

At STP, One mole ([tex]6.023\times 10^{23}[/tex] particles) of any gas occupied volume 22.4 L.

The balanced equation of this reaction is

[tex]2H_2S+3O_2\rightarrow 2SO_2+2H_2O[/tex]

Now we use molar ratio.

[tex]2.8L\ H_2S . \ \frac{1 mol\ H_2S}{22.4L \ H_2S}\ . \ \frac{3 mol\ O_2}{2 mol \ H_2S} \ . \ \frac{22.4L\ O_2}{1 mol\ O_2}[/tex]

=4.2 L O₂

4.2 L O₂ is needed to completely react with 2.8 L hydrogen sulfied.

Final answer:

To determine the volume of oxygen needed to react with 2.8 liters of hydrogen sulfide, the stoichiometric ratio from the chemical equation is used, revealing that 4.2 liters of oxygen is required for complete reaction.

Explanation:

Stoichiometry of Hydrogen Sulfide and Oxygen Reaction

The question involves the stoichiometric relationship between hydrogen sulfide and oxygen gases during a chemical reaction. The balanced chemical equation for the reaction between hydrogen sulfide (H₂S) and oxygen (O₂) to produce sulfur dioxide (SO₂) and water (H₂O) is:

2H₂S(g) + 3O₂(g) → 2SO₂(g) + 2H₂O(g)

To find the volume of oxygen needed to react with 2.8 liters of hydrogen sulfide, we use the stoichiometric coefficients from the balanced equation, which tell us that 2 volumes of H₂S react with 3 volumes of O₂.

This gives us a ratio of:

2H₂S : 3O₂

Using this ratio, we can find the volume of oxygen required by setting up the proportion:

(2.8 L H₂S) / (2L H₂S) = (x L O₂) / (3L O₂)

Solving for x, we get:

x = (2.8 L H₂S) × (3L O₂) / (2L H₂S)

x = 4.2 L O₂

Therefore, 4.2 liters of oxygen gas is needed to completely react with 2.8 liters of hydrogen sulfide gas.

Answer:

On genes within chromosomes

Explanation:

-The fur pattern is a genetic trait whose instruction is carried in the DNA's base sequence.

-These instructions are organized into genes and each gene is only responsble for the making of a functional product.

-Hence, the instructions are stored on genes within chromosomes.

A  branch of science which deals with a living being is called biology.

The correct answer is DNA.

The DNA stands for Deoxyribonucleic acid. it contains all the information about the parents.

The transfer of character from one generation to another is called inheritance.

In this case which is mentioned in the question, the stripes character is a transfer from the parent to the offspring in the form of a gamete cell. Gamete has all the information of the parent which shows the character after maturing.

Hence, the correct answer is DNA stored in the gamete.

For more information, refer to the link:-

https://brainly.com/question/13899929

Final answer:

Fluorine and nitrogen react to form a molecule where nitrogen is the central atom, bonded to three fluorine atoms. This is due to nitrogen's ability to form multiple bonds and its relative electronegativity compared to fluorine.

Explanation:

The correct description of the molecule formed by fluorine and nitrogen is: There are 3 Fluorines and 1 Nitrogen. Nitrogen will be the central atom. In molecules where nitrogen is combined with halogens like fluorine, nitrogen often serves as the central atom due to its capacity to form multiple bonds and its comparably lower electronegativity than halogens. This is consistent with the general rule that less electronegative atoms tend to be central in molecular structures. For instance, nitrogen (N) has five valence electrons and can share these electrons to form covalent bonds, whereas fluorine (F), being more electronegative, typically forms single bonds and is often found as a terminal atom.

Answer:

raising the temperature increases heat in the object... heat is a form of energy that is induced in an object by raising temperature

C

Explanation:

raising temperature causes the heat of an object to increase

Final answer:

It is true that plasma spray-coating processes are used to protect materials from environments which could cause degradation due to factors like wear, corrosion, or thermal failure. Corrosion, a REDOX process, can be combatted with protective coatings, including more nobel metals or cathodic protection via sacrificial anodes.

Explanation:

True, plasma spray-coating processes are indeed utilized to provide surface protection for materials that are exposed to hostile environments. These environments may induce degradation through wear, corrosion, or thermal failure. Corrosion, specifically, is a REDOX (reduction-oxidation) process where metals deteriorate through oxidation. This fact is evident in how iron rusts or how copper develops a patina when exposed to air. Protective coatings are a common method to prevent corrosion, as they can consist of a second metal that is more difficult to oxidize, or contain more easily oxidized metals, providing cathodic protection. For instance, the application of a thin layer of zinc can protect galvanized steel and sacrificial electrodes can be attached to protect metals such as iron.

Answer:

The number of atoms present does not affects the half-life

Explanation:

The half-life, [tex]t_{1/2}[/tex] of an unstable atomic nuclei is the duration in time for the quantity of the atoms having such unstable nuclear to decrease by a factor of 2 in nature. Here nature refers to the position of the unstable nuclear in the environment. It is indicative of the rate of decay of unstable atoms and the period of survival of stable atoms

The half life is given by

[tex]N(t) = N_0 \left (\frac{1}{2} \right )^{\frac{t}{t_{1/2}}}[/tex]

Therefore,

[tex]t_{1/2} = \frac{t\cdot ln2}{ln(\frac{N_0}{N_t} )}[/tex]

Whereby as time time increases N₀ becomes larger such that [tex]t_{1/2}[/tex] remain constant.

Final answer:

The change in entropy (ΔS) for an ideal gas during a reversible adiabatic process is zero because no heat is exchanged with the surroundings. Hence, the total change in entropy (ΔS_total) is also zero for such a process.

Explanation:

To calculate the change in entropy (ΔS) of 123 g of carbon monoxide (CO) during an adiabatic reversible expansion, one should use the thermodynamic definition of entropy. However, since no specific heat is provided for CO, and the problem implies an ideal gas behavior, usually entropy change for an ideal gas in an adiabatic process is zero because no heat is transferred into or out of the system (ΔQ = 0). In adiabatic processes, all expansion work is done at the expense of the internal energy of the gas, and since entropy is a function of heat exchange at a given temperature, the net change in entropy for the gas in such a process is zero.

For the second part of the question, computing the total entropy change ΔS_total during the expansion would typically require considering the surroundings as well. In a truly adiabatic and reversible expansion, there is no heat exchange with the surroundings, thus no change in the entropy of the surroundings, and the total entropy change would likewise be zero. In the real world or in irreversible processes, ΔS_total might be different, but these require additional information.

Answer:

40g of CO2 at 10C

Explanation:

Since average kinetic energy depends on absolute temperature (directly proportional to absolute temperature) and independent of amount and nature of gas. given that is have same temperature.

40g of CO2 at 10C

Any gas at 10 ℃ would have the same average kinetic energy as 10.0 grams of CO2 at the same temperature due to the principles of the kinetic molecular theory.

The conditions that contain molecules with the same average kinetic energy as the molecules in 10.0 grams of CO2 at 10 ℃ would be any other mass of gas at the same temperature, since the average kinetic energy of the molecules of a gas depends only on temperature according to the kinetic molecular theory. This is true regardless of the type of gas or its mass, as long as the gases are at the same temperature.

For example, if you have helium gas at 10 ℃, the average kinetic energy of its molecules would be the same as that of the CO2 molecules at 10 ℃. This is because the kinetic molecular theory posits that all gases at the same temperature have the same average kinetic energy.

you have a picture so i can see it

Answer:

The empirical formula is the representation of simplest whole number ratios of the elements which comprising the compound while, molecular formula is the actual whole number ratio of elements in the formation of compounds.

Empirical formula is equal to molecular formula.

Complete Question

Identify the orbitals that overlap to form the C−Cl bonds in CH2Cl2.

a. carbon sp3 hybrid orbital with a singly occupied chlorine 3s orbital

b. carbon sp2 hybrid orbital with a singly occupied chlorine 3p orbital

c. carbon sp3 hybrid orbital with chlorine sp3  hybrid orbital

d. carbon sp3 hybrid orbital with a singly occupied chlorine 3p orbital

e. a singly occupied carbon 2p orbital with chlorine sp3 hybrid orbital

Answer:

Correct Option is D

Explanation:

         The molecular formula of the compound given is

                               [tex]CH_2 Cl_2[/tex]

The structural formula for this given compound is shown on the first uploaded image

         Looking at the structural formula we see that all the bonds are single bonds  which shows that carbon is sp3 hybridzied which means that one 2s orbital of carbon has mixed with 3 2p orbital to for a form a four hybrid orbital as shown on the second uploaded image

  For the clorine the outer shell is containing two 3s orbital which are completely filled and a 6 3p orbital which requires an electron to complete it as shown on the uploaed image

      Hence the bond between the carbon and the clorine is between a

      sp3 hybridzied orbital and a 3p orbital

Note: each orbital contains a single electron

hhhhhhkkkkkkk

Answer:

Option C is correct.

The minimum amount of material that is needed for a fission reaction to keep going is called the critical mass.

Explanation:

Nuclear fission is the term used to describe the breakdown of the nucleus of a parent isotope into daughter nuclei.

Normally, the initial energy supplied for nuclear fission is the energy to initiate the first breakdown of the first set of radioactive isotopes that breakdown. Once that happens, the energy released from the first breakdown is enough to drive further breakdown of numerous isotopas in a manner that leads to more energy generation.

But, for this to be able to be sustained and not fizzle out, a particular amount of radioactive material to undergo nuclear fission must be present. This particular amount is termed 'critical mass'

Hope this Helps!!!

Answer is option C. The gas is placed under increased pressure.

Explanation:

According to Gas laws,

If the temperature to gas increases then the molecules of gas gets additional energy and moves with more spped than earlier which gives more more colliding to the walls of container. This increases pressure.

The volume and gas in a container are directly proportional to each other.

This means if the volume gets decreased then the collision of gas molecules to the walls increases which results increase in pressure.

Therefore, volume is inversely proportional to pressure.

Answer:

55%

Explanation:

Let A represent isotope eu-151

Let B represent isotope eu-153

Let A% represent Abundance of isotope A (eu-151)

Let B represent abundance of isotope B (eu-153)

The abundance of isotope A (eu-151) can be obtained as follow:

Step 1:

Data obtained from the question include:

Atomic mass of Europium = 151.9 amu

Mass of isotope A (eu-151) = 151.0 amu

Mass of isotope B (eu-153) = 153.0

amu

Abundance of isotope A (eu-151) = A%

Abundance of B (eu-153) = B% = 100 - A%

Step 2:

Determination of the abundance of Abundance of isotope A (eu-151). This is illustrated below:

Atomic mass = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

151.9 = [(151 x A%)/100] + [(153x B%)/100]

151.9 = [(151 x A%)/100] + [(153x (100-A%))/100]

151.9 = [151A%/100] + [15300 -

153A%/100]

151.9 = (151A% + 15300 - 153A%) /100

Cross multiply to express in linear form

151.9 x100 = 151A% + 15300 - 153A%

15190 = 151A% + 15300 - 153A%

Collect like terms

15190 - 15300= 151A% - 153A%

- 110 = - 2A%

Divide both side by - 2

A% = - 110 / - 2

A% = 55%

Therefore the abundance of eu-151 is 55%

Answer:

The natural abundance of eu-153 is 45.0 %

The natural abundance of eu-151 is 55.0 %

Explanation:

Step 1: Data given

The atomic mass of europium is 151.9 amu.

eu-151 hass with a mass of 151.0 amu

eu153 hass a mass of 153.0 amu

Step 2: Calculate the percent natural abundance

natural abundance eu-151 = X

natural abundance eu-153 = 1-X

151.9 = 151.0* X + 153.0 * (1-X)

151.9 = 151.0X + 153.0 -153.0 X

-1.1 = -2.0 X

X = 0.55 = 55 %

The natural abundance of eu-153 is 45.0 %

The natural abundance of eu-151 is 55.0 %

Answer:

E. activated complex

Explanation:

Answer:

D) One half of the carbon atoms of newly synthesized acetyl CoA.

Explanation:

It will be radioactively labeled because Malonyl CoA which contains 3 Carbon molecule is synthesized from Acetyl CoA which has 2 Carbon molecule.

This happens with the addition of ‘CO2’ with the help of the enzyme called acetyl CoA carboxylase.

Final answer:

The compounds that will become radioactively labeled after inhaling 14C-labeled carbon dioxide are the carboxyl atoms of newly synthesized fatty acids, as this is the only portion derived directly from CO₂. Thus, option C is correct.

Explanation:

To determine which compounds will become radioactively labeled after industrial workers breathe air containing 14C-labeled carbon dioxide, we must understand the metabolic pathways that involve the incorporation of carbon from CO₂. During the synthesis of fatty acids, acetyl CoA serves as the two-carbon donor in the form of its activated methyl group, while malonyl CoA provides a two-carbon unit that loses one carbon as CO₂ during the elongation cycle. Though both are involved, individual carbon atoms from CO₂ do not directly become part of the fatty acid chain.

Given that the carboxyl group of the fatty acids does not originate from acetyl CoA or malonyl CoA, the correct choice would be C) The carboxyl atom of newly synthesized fatty acids. This is because the carboxyl group is the only portion derived from the original CO₂ breathed by the workers.

Answer: [tex]KCrO_4[/tex]

Explanation:

First, calculate how much percent of oxygen there is. We know that the whole compound cannot exceed 100%, so we take that, and substract it from 26.56% and 35.41%.

 100.00

-   26.56

-------------------

   73.44

-   35.41

---------------------

   38.03

That is how much of oxygen we have.

Potassium: 26.56% or 26.56g

Chromium: 35.41% or 35.41g

Oxygen: 38.03% or 38.03g

To find the empirical formula, you simply find the amount of mol that each one has. You can do this by using the atomic mass of each element.

[tex]Potassium: 26.56g(\frac{1mol}{39.10g})= 0.67mol[/tex]

[tex]Chromium: 35.41g(\frac{1mol}{52g})=0.68mol[/tex]

[tex]Oxygen: 38.03g(\frac{1mol}{16g})=2.38mol[/tex]

We now determine the lowest number and divide each mol by it. In this case, the lowest number is 0.67

[tex]Potassium: \frac{0.67mol}{0.67}=1[/tex]

[tex]Chromium:\frac{0.68mol}{0.67}=1[/tex]

[tex]Oxygen:\frac{2.38mol}{0.67}=3.55 = 4[/tex]

Finally, we take each element add add their respective number.

So, this empirical formula would be:

[tex]KCrO_4[/tex]

The empirical formula of a compound with 26.56% potassium, 35.41% chromium, and the rest being oxygen would be [tex]K_2Cr_2O_7[/tex]

The number of mole of each element in the compound can be found by dividing each element's percentage with their respective molar weights:

Potassium K = 26.56%

               = 26.56/39.1

                    = 0.68

Chromium, Cr = 35.41%

                       = 35.41/52

                        = 0.68

Oxygen, O = 100 - 26.56+35.41

                     = 38.03/16

                        = 2.38

Divide each number of moles by the smallest.

K = 0.68/0.68

         = 1

Cr = 0.68/0.68

       = 1

O = 2.38/0.68

      = 3.5

Thus, the empirical formula would be [tex]KCrO_{3.5}[/tex]

Multiply all by 2 to remove the fraction:

[tex]K_2Cr_2O_7[/tex]

More on empirical formula can be found here; https://brainly.com/question/1247523

Answer : The correct option is, (c) use of a mobile and a stationary phase.

Explanation :

Chromatography : It is a separation process or technique of a mixture in which a mixture is distributed between the two phases at different rates, one of which is stationary phase and another is mobile phase.

Mobile phase : The mixture is dissolved in a solution is known as mobile phase.

Stationary phase : It is an adsorbent medium and It is a solid, liquid or gel that remains immovable when a liquid or a gas moves over the surface of adsorbent. It remains stationary.

Hence, a characteristic feature of any form of chromatography is the use of a mobile and a stationary phase.

Answer:

1.   67.2 kJ/mol

Explanation:

Using the derived expression from Arrhenius Equation

[tex]In \ (\frac{k_2}{k_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})[/tex]

Given that:

time [tex]t_1[/tex] = 8.3 days = (8.3 × 24 ) hours = 199.2 hours

time [tex]t_2[/tex] = 10.6 hours

Temperature [tex]T_1[/tex] = 0° C = (0+273 )K = 273 K

Temperature [tex]T_2[/tex] = 30° C = (30+ 273) = 303 K

Rate = 8.314 J / mol

Since [tex](\frac{k_2}{k_1}=\frac{t_2}{t_1})[/tex]

Then we can rewrite the above expression as:

[tex]In \ (\frac{t_2}{t_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})[/tex]

[tex]In \ (\frac{199.2}{10.6}) = \frac{E_a}{8.314}(\frac{303-273}{273*303})[/tex]

[tex]2.934 = \frac{E_a}{8.314}(\frac{30}{82719})[/tex]

[tex]2.934 = \frac{30E_a}{687725.766}[/tex]

[tex]30E_a = 2.934 *687725.766[/tex]

[tex]E_a = \frac{2.934 *687725.766}{30}[/tex]

[tex]E_a =67255.58 \ J/mol[/tex]

[tex]E_a =67.2 \ kJ/mol[/tex]

Answer:

[tex]T_2=571.9K[/tex]

Explanation:

Hello,

In this case, we consider the following formula defining the energy and the temperature change for the sample of iron:

[tex]Q=n_{Fe}Cp_{Fe}(T_2-T_1)[/tex]

Now, solving the final temperature, considering a positive inlet heat, we have:

[tex]T_2=T_1+\frac{Q}{n_{Fe}Cp{Fe}} =293K+\frac{3500J}{0.5mol*25.1J/(mol*K)} \\T_2=571.9K[/tex]

Best regards.

Answer:

Explanation:

Step 1: Data given

Number of heat transfer = 3500 J

Number of moles of iron = 0.5 moles

Initial temperature = 293 K

The molar heat of iron is 25.1 J/(mol*K)

Step 2: Calculate ΔT

Q = n* C * ΔT

⇒with Q = the heat transfer = 3500 J of energy

⇒with n = the number of moles iron  = 0.5 moles

⇒with C = the molar heat of iron = 25.1 J/mol*K

⇒ΔT = the change of temperature = T2 - T1 = T2 - 293 K

3500 J = 0.5 moles *25.1 J/mol * K * ΔT

ΔT = 278.9

Step 3: Calculate ΔT

ΔT = 278.9 = T2 - T1 = T2 - 293 K

T2 = 278.9 + 293 K

T2 = 551.9 K

Answer:

C Al = 0.8975 J/g.K

Explanation:

∴ m Al = 28.4 g

∴ T Al = 39.4°C = 312.4 K

∴ m H2O = 50.0 g

∴ T1 H2O = 21°C = 294 K

∴ T2 H2O = 23°C = 296 K

∴ C H2O = 4,18 J/g.K

⇒ C Al = ?

in a calorimeter:

∴ Al give heat: Q Al < 0

∴ H2O revceives heat: Q H2O > 0

⇒ - Q Al = Q H2O

⇒ - (28.4 g)*(C Al)*(296 K - 312.4 K) = (50.0 g)*(4.18 J/g.K)*(296 K - 294 K)

⇒ - (- 465.76 g.K)*(C Al) = 418 J

⇒ C Al = (418 J) / (465.76 g.K)

⇒ C Al = 0.8975 J/g.K = 897.5 J/Kg.K

The specific heat capacity of aluminum in this example is 0.394 J/g °C. This was determined by calculating the heat gained by water and considering that it equals the heat lost by the aluminum, and subsequently solving for the specific heat capacity of aluminum.

To find the specific heat capacity (C) of aluminum, we must consider the amount of heat transferred from the aluminum to the water (expressed as q). The heat gained by water is calculated using the equation q = m * C * ΔT, where m is the mass, C is the specific heat, and ΔT is the change in temperature. According to the question, water's mass (m) is 50.0g, its specific heat (C) is 4.184 J/g °C, and the difference in its temperature (ΔT) is 2.00 °C. So, the heat gained by water is q = 50.0g * 4.184 J/g * °C * 2.00 °C = 418.4 J.

The heat lost by aluminum is equal to the heat gained by water. Therefore, using the equation q = m * C * ΔT and plug in the values of q (418.4 J), m (28.4 g), and ΔT (39.4 °C), to solve for C, the specific heat of aluminum, we can rearrange the formula to C = q / (m * ΔT) = 418.4 J / (28.4g * 39.4 °C) = 0.394 J/g °C.

https://brainly.com/question/28302909

#SPJ3

Answer:

Rocks can be simply defined as the aggregates of various minerals, and these broken rock fragments and mineral grains are formed from the weathering of rocks. Weathering refers to the breakdown of rocks due to the occurrence of various geological processes that are initiated by the agents such as wind, water and ice.

The weathering process leads to the formation of sediments of variable size and shape, and these are such as pebbles, sand, silt and clay particles.

7 moles of BaBr₂ produces 14 moles of KBr.

Explanation:

Given reaction is

BaBr₂ + K₂SO₄ → KBr + BaSO₄

It can be balanced by putting 2 in front of KBr as,

BaBr₂ + K₂SO₄ → 2 KBr + BaSO₄

From the above balanced equation, it was found that, 1 mole of Barium bromide required to produce 2 moles of KBr.

Now the molar ratio of BaBr₂ to KBr is written as 1 : 2.

In the same way, the molar ratio for 7 moles of BaBr₂, can be written as 7:14.

So 7 moles of BaBr₂ produces 14 moles of KBr.

The moles of KBr formed has been 14 mol.

The balanced chemical equation for the reaction has been:

[tex]\rm BaBr_2\;+\;K_2SO_4\;\rightarrow\;2\;KBr\;+\;BaSO_4[/tex]

From the balanced chemical equation, the coefficient has been describing the moles of reactants and products formed.

The balanced chemical equation has been given as:

[tex]\rm 1\;mol\;BaBr_2=2\;mol\;KBr[/tex]

The moles of KBr formed by 7 moles of Barium bromide has been as:

[tex]\rm 1\;mol\;BaBr_2=2\;mol\;KBr\\7 \;mol\;BaBr_2=2\;\times\;7 \;mol\;KBr\\7 \;mol\;BaBr_2=14 \;mol\;KBr\\[/tex]

The moles of KBr formed has been 14 mol.

For more information about moles, refer to the link:

https://brainly.com/question/20674302

Answer:

The normal amount of disaccharide would be produced, but fewer monosaccharides would be produced.

Explanation:

The first reaction, the conversion of starch into disaccharides, is catalyzed by the enzyme amylase. Since amylase is present in a normal amount, a normal amount of disaccharides will be produced.

In the second reaction, these disaccharides will be transformed into monosaccharides by a disaccharidase. However, since there is less disaccharidase, there will be fewer monosaccharides produced than if it was a normal amount of amylase.

Final answer:

If there is a normal amount of amylase but less disaccharidase than usual, the normal amount of disaccharide would be produced, but fewer monosaccharides would result from the reaction.

Explanation:

When examining the reaction starch → amylase → disaccharides → disaccharidase → monosaccharides, the presence of a normal amount of amylase means that starch can be broken down into disaccharides effectively. However, with less disaccharidase than usual, fewer monosaccharides would be produced from the disaccharides. The normal amount of disaccharide produced by amylase would not change, but since disaccharidase is responsible for the breakdown of disaccharides into monosaccharides, a deficiency in this enzyme means the reaction would be incomplete, leading to less monosaccharides being produced.

Answer:

 The answer is false

Explanation:

             The given reaction is

           [tex]Br_{2}_{(l)} + Mn^{2+}_{(aq)} ------->MnO_4 _{(aq)} + Br^-_{(g)}[/tex]

At the cathod the potential is

           [tex]E_{cath} = + 1.065V[/tex]               [This because it will attract the negative

                                                       charge]

At the Anode the potential is

          [tex]E_{anode} = 1.51[/tex]

The overall potential of the  cell is

           [tex]E_{cell} = E_{cath} - E_{anode}[/tex]

                    [tex]= -0.445[/tex]

Since the potential of the cell is less than 0 then the reaction is not spontenous under standard condition

The reaction below is spontaneous under standard conditions should be considered false.

Since the given reaction is br2(l) + mn2+(aq) → mno4-(aq) + br-(g)

Also, at the anode, the potential should be

Eanode = 1.51

And, the  overall potential of the  cell is

= -0.445

Also, the potential of the cell should be lower than 0 so the reaction is not spontenous under standard condition

learn more about reaction here: https://brainly.com/question/1542697

Answer:

1.7 atm

Explanation:

The formula you would want to use it P2=p1v1/v2

Plug in the numbers and solve

(1)(6)/3.5

Let me know if you need any other help!

Using Boyle's Law, we calculate the new pressure in the piston to be approximately 1.71 atm when the volume is decreased from 6.0 L to 3.5 L.

The problem at hand relates to Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In this instance, initial pressure (P1) is 1.0 atm, initial volume (V1) is 6.0 L, and the final volume (V2) is 3.5 L. The final pressure (P2) can be found by applying the formula from Boyle's Law: P1 x V1 = P2 x V2. Solving for P2, we find P2 = (P1 x V1) / V2 = (1.0 atm x 6.0 L) / 3.5 L, which simplifies to approximately 1.71 atm.

https://brainly.com/question/21184611

#SPJ2

Amount of CO₂ emission per day is 11,356.23 g.

Explanation:

Joe travelling distance per day = 60 miles

Carbon dioxide emission per day = 20 mpg

Now we have to find the amount of carbon dioxide emitted per day by dividing the distance by the emission per day given in gallons.

Amount of Carbon dioxide emission = [tex]$\frac{distance}{emission amount}[/tex]

Amount of CO₂ emission in gallons  = [tex]$\frac{ 60 miles}{20 mpg}[/tex]  

                                                            = 3 gallons

Now we have to convert the gallons to grams as,

1 gallon = 3,785.41 g

3 gallons = 3 × 3785.41 g = 11,356.23 g

So the emission of CO₂ per day is 11,356.23 g.

Answer:

Explanation:By the time, that the balloon got too high in the sky, the pressure inside the balloon will soon overcome the pressure outside, and the balloon's elasticity is not too strong to hold the air inside, that the Helium gas inside will successfully push out the walls of the balloon and so it bursts!

Answer:

The mass of KClO₃ that will absorb the same heat as 5 g of KCl is 3.424 g

Explanation:

Here we have

Heat of solution of KClO₃ = + 41.38 kJ/mol.

Heat of solution of KCl (+17.24 kJ/mol)

Therefore, 1 mole of KCl absorbs +17.24 kJ during dissolution

Molar mass of KCl = 74.5513 g/mol

Molar mass of KClO₃ = 122.55 g/mol

74.5513 g of KCl absorbs +17.24 kJ during dissolution, therefore, 5 g will absorb

[tex]\frac{17.24}{74.5513 } \times 5 \, \, kJ \, or \, 1.156 \, kJ[/tex]

Therefore the amount of KClO₃ to be dissolved to absorb 1.156 kJ of energy is given by

122.55 g of KClO₃ absorbs + 41.38 kJ, therefore,

[tex]\frac{1.156}{41.38} \times 122.55 \, g = 3.424 \, g[/tex]

Therefore the mass of KClO₃ that will absorb the same heat as 5 g of KCl = 3.424 g.

If both potassium chlorate and potassium chloride had the same specific heat, you would need 5 grams of potassium chlorate to produce the same temperature change in 100 mL of water. This is a simplified scenario and in real-life, there would be slight differences.

To answer this question, we need to assume that potassium chlorate and potassium chloride have the same specific heat and that the water's heat capacity is much greater than either salt. Therefore, the amount of heat energy required to increase the temperature of water is the same for both salts. If 5 grams of potassium chloride produce the same temperature change, an equal amount of heat energy would be required for the potassium chlorate. Hence, you would need 5 grams of potassium chlorate to produce the same temperature change.

Please understand that this is a simplified explanation. In a real-life situation, there would be some differences due to the different chemistry of the salts.

https://brainly.com/question/23184814

#SPJ3