The record of an earthquake obtained from a seismic instrument is a(n) ________.

The answer is 250 W

Apex

450kg would be your answer.

Hope it helped you.

Answer:

450

Explanation:

Final answer:

The light-gathering power of a 4-meter telescope is significantly greater than that of a 2-meter telescope due to the proportional increase in aperture area, allowing it to collect four times as much light.

Explanation:

The light-gathering power of a 4-meter telescope is significantly greater than that of a 2-meter telescope. This is because the light-gathering ability of a telescope is determined by the area of its aperture (the mirror or lens that collects light), and this area increases with the square of the diameter of the aperture. Therefore, a 4-meter diameter telescope has an aperture area that is 4 times larger than that of a 2-meter diameter telescope, allowing it to gather significantly more light.

To illustrate, if a 1-meter telescope collects a certain amount of light, a 4-meter telescope, with 16 times the area, would collect 16 times as much light. Similarly, compared to a 2-meter telescope, a 4-meter telescope, having an area four times greater (since the area is proportional to the square of the diameter), can collect four times as much light.

The projectile will ascend to a height of 9.9 meters above the water's surface.

To find the maximum height above the water, we can use the equations of motion for projectile motion. First, we need to find the time it takes for the projectile to reach the surface of the water. We can use the equation y = v0t + (1/2)at2, where y is the displacement, v0 is the initial velocity, a is the acceleration due to gravity, and t is the time.

Given that the initial velocity is -13m/s (since the projectile is moving in the opposite direction of the acceleration due to gravity), the acceleration due to gravity is -9.8m/s2, and the displacement is 0 (since the projectile breaks through the surface of the water), we can rearrange the equation to solve for t: 0 = -13t + (1/2)(-9.8)t2. By solving this quadratic equation, we find that t = 1.33s or t = 0.

Since the time can't be negative, we discard the t = 0 solution. Therefore, the time it takes for the projectile to reach the surface of the water is t = 1.33s. Now, to find the maximum height above the water, we can use the equation v = v0 + at, where v is the final velocity, v0 is the initial velocity, a is the acceleration, and t is the time.

Using the known values: v = 0m/s (since the projectile comes to a stop at its maximum height), v0 = -13m/s, a = -9.8m/s2, and t = 1.33s, we can rearrange the equation to solve for the maximum height h: 0 = -13 - 9.8(1.33) + h. By solving this equation, we find that h = 9.9m. Therefore, the projectile will ascend to a height of 9.9 meters above the water's surface.

C.

Changes in how much of the sunlit side of the moon faces Earth

Final answer:

To find the expression for the velocity of the second car, consider the motion of both cars separately. The velocity of the second car can be described as v2 = 24 - 6t.

Explanation:

To find the expression for the velocity of the second car, we need to consider the motion of both cars separately.

Let's assume that the first car passes the second car at time t = 0. The position of the first car can be described as x1 = 30t, where t is the time elapsed since the first car passed the second car.

The position of the second car can be described as x2 = (24)t - (1/2)(6)t^2, where the negative term represents the deceleration of the second car due to slowing down at 6.0 m/s^2.

Now, we can find the expression for the velocity of the second car by taking the derivative of its position equation with respect to time: v2 = 24 - 6t.

The velocity of the second car, which starts at 24 m/s and decelerates at 6.0 m/s², can be described by the function v(t) = 24 - 6t. This equation shows how the car's velocity decreases over time. For any given time t, you can calculate the velocity using this expression.

To find the expression of the velocity of the second car, we need to consider its deceleration. The second car's initial velocity is 24 m/s, and it decelerates at a rate of 6.0 m/s². The general equation for the velocity of an object under constant acceleration (or deceleration) is:

v(t) = v₀ + at

Here, v(t) is the velocity at time t, v₀ is the initial velocity, and a is the acceleration (note that since it is deceleration, the acceleration will be negative).

Given:

We can substitute these values into the equation:

v(t) = 24 m/s - (6.0 m/s²) * t

So, the expression for the velocity of the second car as a function of time is:

v(t) = 24 - 6t

To draw a free body diagram for the skier, identify the forces acting on the skier including the gravitational force, normal force, and frictional force. The normal force can be found by taking the component of the gravitational force perpendicular to the incline. The acceleration of the skier down the hill can be determined using Newton's second law.

To draw a free body diagram for the skier, we need to identify the forces acting on the skier. These include the gravitational force (mg) acting straight down, the normal force (N) perpendicular to the incline, and the frictional force (f) parallel to the incline. The acceleration of the skier down the hill can be determined using Newton's second law, which states that the net force (Fnet) equals the mass (m) times the acceleration (a): Fnet = ma.

The normal force can be found by taking the component of the gravitational force perpendicular to the incline, which is given by N = mg*cos(theta).

The acceleration of the skier down the hill can be determined using the equation Fnet = ma, where the net force is the difference between the gravitational force parallel to the incline and the frictional force: Fnet = mg*sin(theta) - f.

The normal force acting on the skier is approximately 550.32 N.The skier's acceleration down the hill is approximately 3.03 m/s².

Here's how to solve the problem:

a. Free body diagram:

The free body diagram for the skier should show the following forces acting on them:

Weight (mg): This is the force of gravity acting on the skier, directed downwards. Its magnitude is given by `mg`, where `m` is the skier's mass (65 kg) and `g` is the acceleration due to gravity (approximately 9.81 m/s²). In this case, the weight would be `65 kg * 9.81 m/s² ≈ 637.65 N`.

Normal force (N): This is the force exerted by the slope on the skier, perpendicular to the slope. Its magnitude depends on the weight and the angle of the slope.

Friction force (f): This is the force opposing the skier's motion, parallel to the slope. Its magnitude is proportional to the normal force and the coefficient of friction (`μ`).

b. Normal force:

The normal force can be calculated using the component of the weight perpendicular to the slope. This can be done using trigonometry:

N = mg * cos(θ)

where `θ` is the angle of the slope (30° in this case).

Therefore, the normal force would be:

N = 637.65 N * cos(30°) ≈ 550.32 N

c. Acceleration:

The acceleration of the skier can be calculated using Newton's second law of motion:

ΣF = ma

where `ΣF` is the net force acting on the skier, `m` is the skier's mass, and `a` is the acceleration.

The net force is the difference between the downhill component of the weight and the friction force:

ΣF = mg * sin(θ) - μ * N

Substituting the known values:

ΣF = 637.65 N * sin(30°) - 0.1 * 550.32 N ≈ 196.81 N

Finally, solving for the acceleration:

a = ΣF / m = 196.81 N / 65 kg ≈ 3.03 m/s²

Therefore, the skier's acceleration down the hill is approximately 3.03 m/s².

I just had this question, the correct answer is March 5

Answer:

Mass does not change

Weight redueces on the moon

Explanation:

The mass of an object never changes with respect to the astronomical body it is on. The mass of an object is the resistance it provides to a force which is applied.

A 1 kg object is an 1 kg object anywhere in the universe.

Weight is the affect of an astronomical object's gravity on it

[tex]W=mg[/tex]

where,

m = Mass of the object

g = Acceleration due to gravity

[tex]g_e[/tex]=Acceleration due to gravity on Earth = 9.81 m/s²

[tex]g_m[/tex]=Acceleration due to gravity on Moon = 1.62 m/s²

Weight on Earth

[tex]W_e=mg_e\\\Rightarrow W_e=9.81m[/tex]

Weight on Moon

[tex]W_m=mg_m\\\Rightarrow W_m=1.62m[/tex]

Dividing the equations we get

[tex]W_m=\frac{1.62}{9.81}W_e\\\Rightarrow W_m=0.165W_e[/tex]

The weight of the astronaut on the moon will be 0.165 times the weight on Earth.

So, the weight of the astronaut will be reduced on the moon

Answer : The correct option is (A) [tex]-9.8\ m/s^2[/tex]

Explanation :

The formula is given as :

[tex]v_y=a_yt[/tex]

Where,

[tex]v_y[/tex] is vertical component of velocity.

[tex]a_y[/tex] is the vertical component of acceleration.

In a projectile motion, the particle moves in a path under the influence of gravity.

So, the vertical component of acceleration is -g i.e acceleration due to gravity.

Hence, the correct option is (a) " [tex]a_y=-9.8\ m/s^2[/tex] ".

A moist, unstable air mass is an air mass that has a high moisture content, Low density and Warm temperatures.

Explanation:

A moist, unstable air mass is an air mass that has a high moisture content and is not very dense. This means that the air molecules are not very tightly packed together, which makes it easier for them to rise and form clouds and precipitation.

Here are some of the characteristics of a moist, unstable air mass:

Find more exercises on unstable air;

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Answer:

The answer is b for anyone wondering.

Explanation:

Answer:

Gravitational force will accelerate the cart.

Explanation:

In the given case the cart is on a ramp in this situation the gravitational force is applied normally on the cart and its horizontal component which is [tex]mgcos\theta[/tex] and its vertical component which is [tex]mgsin\theta[/tex] acting along the ramp.

In this situation as we the acceleration is increased by a factor [tex]gsin\theta[/tex] which helps in increasing its acceleration.

Therefore acceleration due to gravity will accelerate the cart.

Newton Calculation Error

in the book "Principia Mathematica" contains a simple calculation error that was not discovered for 300 years. Errors occur in Proposition Eight, where Newton presents a formula for calculating the mass of the planet, involving angles formed by two specific lines.

The mistakes made by scientists:

He was wrong from the start, starting his efforts to explain the tidal movements with a false premise - namely that it was caused by the rotation of the earth around the sun. This means the theory is incorrect because it is based on mistakes.

One problem with Darwin's original theory concerns heredity. Many people have a misconception about how characteristics are passed down from parents to their children. The problem is that this notion of mixed genetics contradicts Darwin's own theory. If that is true, then the characteristics will not change from generation to generation through natural selection.

Despite getting the Nobel Prize, Pauling admitted there was an error in his discovery. The model is wrong for a very simple reason: This includes the triple helix. He also made a basic mistake in his calculations, and the nucleic acid molecule in his model was actually not acidic.

According to Hubble, the universe is two billion years old. This statement is proven wrong. In the 1930s, a study said the earth was between three and five billion years old. Obviously, our planet cannot be older than the universe, so something's wrong with Hubble.

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Scientist https://brainly.com/question/6701391

The Mistakes from Scientist https://brainly.com/question/6701391

Details

Class: High School

Subject: Physics

Keywords: scientist, mistake, newton

Answer:

The answer is C

Explanation:

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