The revenue from manufacturing and selling x units of toaster ovens is given by:
R(x) = –.03x^2 + 200x – 82,000
How much revenue should the company expect from selling 3,000 toaster ovens?

assuming 30 days per month.

[tex]\bf \begin{array}{ccll} pages&days\\ \cline{1-2} 1787&11\\ x&30 \end{array}\implies \cfrac{1787}{x}=\cfrac{11}{30}\implies 53610=11x \\\\\\ \cfrac{53610}{11}=x\implies 4873\frac{7}{11}=x[/tex]

Answer: 4873.64

Step-by-step explanation:

I'm assuming that you're asking how many pages there are in a month. On average, the typical month is 30 days, correct? We can plug this information into proportions.

1787/11 = x/30

1787 multiplied by 30 is 53610, and that divided by 11 would be 4873.64, when rounded to the nearest hundredth.

I hope that helped!

Answer:

Explained

Step-by-step explanation:

The trunk of a tree grows in two different ways, first in height and second in diameter.Usually tree grows one ring per year in diameter. So, counting the number of rings we can determine the age of a tree. Both height and diameter growth does not occur at the same rate. Tree grows more in height than in their diameter. Mature trees usually grows 1 inch in diameter every year.

Water oak gains 24 inches in height  every year and  1.5 inch growth in diameter annually, meaning if we divide 1.5 inches by 12 months we gets 0.125 inches growth monthly. So a water oak tree needs only 8 months to grow 1 inch in diameter.

Notice that

[tex](n+1)^4-n^4=4n^3+6n^2+4n+1[/tex]

so that

[tex]\displaystyle\sum_{i=1}^n((n+1)^4-n^4)=\sum_{i=1}^n(4i^3+6i^2+4i+1)[/tex]

We have

[tex]\displaystyle\sum_{i=1}^n((i+1)^4-i^4)=(2^4-1^4)+(3^4-2^4)+(4^4-3^4)+\cdots+((n+1)^4-n^4)[/tex]

[tex]\implies\displaystyle\sum_{i=1}^n((i+1)^4-i^4)=(n+1)^4-1[/tex]

so that

[tex]\displaystyle(n+1)^4-1=\sum_{i=1}^n(4i^3+6i^2+4i+1)[/tex]

You might already know that

[tex]\displaystyle\sum_{i=1}^n1=n[/tex]

[tex]\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2[/tex]

[tex]\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6[/tex]

so from these formulas we get

[tex]\displaystyle(n+1)^4-1=4\sum_{i=1}^ni^3+n(n+1)(2n+1)+2n(n+1)+n[/tex]

[tex]\implies\displaystyle\sum_{i=1}^ni^3=\frac{(n+1)^4-1-n(n+1)(2n+1)-2n(n+1)-n}4[/tex]

[tex]\implies\boxed{\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4}[/tex]

If you don't know the formulas mentioned above:

Answer:

The gcd(474,147) = 3 and the linear combination is [tex]3=9\cdot 474 - 29\cdot 147[/tex] and the proof is below.

Step-by-step explanation:

The greatest common divisor (GCD) of two whole numbers is the largest natural number that divides evenly into both without a remainder.

To find the GCD you can use the Euclidean algorithm which is an efficient method for computing the greatest common divisor (GCD) of two integers, without explicitly factoring the two integers. Here is an outline of the steps:

To compute gcd(474,147), divide the larger number by the smaller number, using the division algorithm we have

[tex]\frac{474}{147} \\= 474-147=327\\327-147=180\\180-147=33\\[/tex]

At this point, we cannot subtract 147 again. Hence 3 is the quotient ( we subtract 147 from 474 3 times) and 33 is the remainder. We can express this as a linear combination [tex]474 = 147*3+33[/tex]

Using the same reasoning and the steps of the Euclidean algorithm we have

[tex]gcd(474,147) = \\474 =147\cdot 3+33\\147=33\cdot 4 +15\\33=15\cdot 2+3\\15=3\cdot 5+0[/tex]

To find the linear combination you need to use the Bezout's identity that says that the equation [tex]ax+by=gcd(a,b)[/tex] has solutions x, y. So we need to find the solution of the equation [tex]474x+147y=3[/tex].

To find the values of x and y you can run the Euclidean Algorithm backward.

We know that

[tex]33=15\cdot 2+3[/tex]

We can express 3 as linear combination

[tex]3=33- 2\cdot15\\3=33-2\cdot(147-33*4)=9\cdot 33 -2\cdot147\\3=9\cdot 33 -2\cdot147=9\cdot (474-147\cdot 3)-2 \cdot 147\\3= 9\cdot 474-27 \cdot 147-2 \cdot 147\\3=9\cdot 474 - 29\cdot 147[/tex]

The gcd(474,147) = 3 and the linear combination is [tex]3=9\cdot 474 - 29\cdot 147[/tex]

The principle of mathematical induction is stated as follows:

Let n be a natural number and let P(n) be an statement that depends on n. If

Then P(n) is true for all natural numbers n.

Proposition: For all positive integers n, 2+4+6+...+2n = n(n+1).

Proof. Let's let P(n) be the statement "2+4+6+...+2n = n(n+1)" .The proof will now proceed in two steps: the initial step and the inductive step.

Initial step. We must verify that P(1) is true

[tex]n=1\\2\cdot 1=1\cdot (1+1)[/tex]

which is clearly true. So we are done with the initial step.

Inductive step. We must prove the following assertion: "If there is a k such that P(k) is true, then (for this same k) P(k+1) is true." Thus, we assume there is a k such that 2+4+6+...+2k = k(k+1), this is called the inductive assumption. We must prove, for this same k, the formula P(k+1): 2+4+6+...+2k+2(k+1) = (k+1)(k+2)

To prove that P(k+1) holds, we will start  with the expression on the left-hand side of P(k+1) and show that it is equal to the expression on the right-hand side.

[tex]2+4+6+...+2k+2(k+1)[/tex]

we know that [tex]2+4+6+...+2k+2(k+1)=k(k+1)[/tex] for the inductive assumption

[tex]k(k+1)+2(k+1)\\k^{2}+k+2k+2\\k^2+3k+2\\(k+1)(k+2)[/tex]

we see that the result [tex](k+1)(k+2)[/tex], is the expression on the right-hand side of P(k+1). Thus by mathematical induction P(n) is true for all natural numbers n.

Answer:

164.6 mg

Step-by-step explanation:

Given:

Weight of the patient= 120 lbs

Height of patient = 5'8" = 5 × 12 + 8 = 68 inches

Dose of Taxol to be administered= 100 mg/ m²

Now,

the surface area of the body of patient = [tex]\textup{(Weight in kg)}^{0.425}\times\textup{(Height in cms)}^{0.725}\times0.007184[/tex]

Also,

weight of patient in kg = 120 × 0.454 = 54.48 kg

Height of patient in cm = 68" × 2.54 = 172.72 cm

therefore,

Body surface area = [tex]\textup{(54.48)}^{0.425}\times\textup{(172.72)}^{0.725}\times0.007184[/tex]

or

= 5.47 × 41.89 × 0.007184

or

= 1.646 m²

Hence,  

Dose of Taxol to be received by the patient

= 100 mg/m²  × surface area of the patient

= 100 × 1.646

= 164.6 mg

Answer:

[tex]\displaystyle\frac{d(y(t))}{dt} =\displaystyle\frac{d(f(u(t)))}{dt} = f'(u(t)).u'(t)[/tex]

Step-by-step explanation:

The chain rule helps us to differentiate functions and a composition of two functions.

Let r(u) and s(u) be two function. Then, composition of these two functions can be be differentiated with the help of chain rule. It states that:

[tex]\displaystyle\frac{d(r(s(u)))}{du} = r'(g(u)).s'(u)[/tex]

Now, we are given

[tex]y(t) = f(u(t))[/tex]

Then, by chain rule, we have:

[tex]\displaystyle\frac{d(y(t))}{dt} =\displaystyle\frac{d(f(u(t)))}{dt} = f'(u(t)).u'(t)[/tex]

Answer:

  corresponding angles

Step-by-step explanation:

Corresponding angles are congruent where a transversal crosses parallel lines. Such a geometry has 4 pairs of corresponding angles. The corresponding angles of each pair are congruent.

Answer:

corresponding angles

Step-by-step explanation:

Answer:

Actual length = 883 feet

Actual height = 175 feet

A)  If a model is built to have a scale ratio of 1 in : 36ft , how long will the model be?

36 feet = 1 inch

Actual length = 883 feet

So, 883 feet = [tex]\frac{883}{36} inch[/tex]

883 feet = [tex]24.527 inch[/tex]

So, If a model is built to have a scale ratio of 1in : 36ft ,the model will be 24.527 inch long.

B)  If a model is built to have a scale ratio of 1 in : 22 ft , how tall will the model be?

22 feet = 1 inch

Actual height = 175 feet

So, 175 feet = [tex]\frac{175}{22} inch[/tex]

883 feet = [tex]7.9545 inch[/tex]

So,  If a model is built to have a scale ratio of 1 in : 22 ft , the model will be 7.9545 inch tall.

C) If a model is built to have a ratio of 1: 30 , how tall will the model be?

Let the height be x

Actual length = 883 feet

Ratio of 1: 30

So, [tex]\frac{1}{30}=\frac{883}{x}[/tex]

[tex]x=\frac{883}{30}[/tex]

[tex]x=29.433[/tex]

So, If a model is built to have a ratio of 1: 30 ,the model will be 29.433 inches tall .

Answer:

a) The x value of the point where the two equations intersect in terms of a is [tex]x=\frac{40}{4+5a}[/tex]

b) The value of the functions at the point where they intersect is [tex]\frac{10 (28 + 15 a)}{4 + 5 a}[/tex]

c) The partial derivative of f with respect to [tex]x[/tex] is [tex]\frac{\partial f}{\partial x} = -5a[/tex] and the partial derivative of f with respect to [tex]a[/tex] is [tex]\frac{\partial f}{\partial x} = -5x[/tex]

d) The value of [tex]\frac{\partial f}{\partial x}(3,2) = -10[/tex] and [tex]\frac{\partial f}{\partial a}(3,2) = -15[/tex]

e) [tex]\upsilon_1=-\frac{3}{4} = -0.75[/tex] and [tex]\upsilon_2=-\frac{3}{4} = -0.75[/tex]

f) equation [tex]\upsilon_1 = \frac{-5a\cdot x}{70-5ax}=\frac{ax}{ax-14}[/tex] and [tex]\upsilon_2 = \frac{-5a\cdot a}{70-5ax}=\frac{a^2}{ax-14}[/tex]

Step-by-step explanation:

a) In order to find the [tex]x[/tex] we just need to equal the equations and solve for [tex]x[/tex]:

[tex]f(x,a)=g(x)\\70-5xa = 30+4x\\70-30 = 4x+5xa\\40 = x(4+5a)\\\boxed {x = \frac{40}{4+5a}}[/tex]

b) Since we need to find the value of the function in the intersection point we just need to substitute the result from a) in one of the functions. As a sanity check , I will do it in both and the value (in terms of [tex]a[/tex]) must be the same.

[tex]f(x,a)=70-5ax\\f(\frac{40}{4+5a}, a) = 70-5\cdot a \cdot  \frac{40}{4+5a}\\f(\frac{40}{4+5a}, a) = 70 - \frac{200a}{4+5a}\\f(\frac{40}{4+5a}, a) = \frac{70(4+5a) -200a}{4+5a}\\f(\frac{40}{4+5a}, a) =\frac{280+350a-200a}{4+5a}\\\boxed{ f(\frac{40}{4+5a}, a) =\frac{10(28+15a)}{4+5a}}[/tex]

and for [tex]g(x)[/tex]:

[tex]g(x)=30+4x\\g(\frac{40}{4+5a})=30+4\cdot \frac{40}{4+5a}\\g(\frac{40}{4+5a})=\frac{30(4+5a)+80}{4+5a}\\g(\frac{40}{4+5a})=\frac{120+150a+80}{4+5a}\\\boxed {g(\frac{40}{4+5a})=\frac{10(28+15a)}{4+5a}}[/tex]

c) [tex]\frac{\partial f}{\partial x} = (70-5xa)^{'}=70^{'} - \frac{\partial (5xa)}{\partial x}=0-5a\\\frac{\partial f}{\partial x} =-5a[/tex]

[tex]\frac{\partial f}{\partial a} = (70-5xa)^{'}=70^{'} - \frac{\partial (5xa)}{\partial a}=0-5x\\\frac{\partial f}{\partial a} =-5x[/tex]

d) Then evaluating:

[tex]\frac{\partial f}{\partial x} =-5a\\\frac{\partial f}{\partial x} =-5\cdot 2=-10[/tex]

[tex] \frac{\partial f}{\partial a} =-5x\\\frac{\partial f}{\partial a} =-5\cdot 3=-15[/tex]

e) Substituting the corresponding values:

[tex]\upsilon_1 = \frac{\partial f(3,2)}{\partial x}\cdot \frac{3}{f(3,2)} \\\upsilon_1 = -10 \cdot \frac{3}{40}  = -\frac{3}{4} = -0.75[/tex]

[tex]\upsilon_2 = \frac{\partial f(3,2)}{\partial a}\cdot \frac{3}{f(3,2)} \\\upsilon_2 = -15 \cdot \frac{2}{40}  = -\frac{3}{4} = -0.75[/tex]

f) Writing the equations:

[tex]\upsilon_1=\frac{\partial f (x,a)}{\partial x}\cdot \frac{x}{f(x,a)}\\\upsilon_1=-5a\cdot \frac{x}{70-5xa}\\\upsilon_1=\frac{-5ax}{70-5ax}=\frac{-5ax}{-5(ax-14)}\\\boxed{\upsilon_1=\frac{ax}{ax-14} }[/tex]

[tex]\upsilon_2=\frac{\partial f (x,a)}{\partial x}\cdot \frac{a}{f(x,a)}\\\upsilon_2=-5a\cdot \frac{a}{70-5xa}\\\upsilon_2=\frac{-5a^2}{70-5ax}=\frac{-5a^2}{-5(ax-14)}\\\boxed{\upsilon_2=\frac{a^2}{ax-14} }[/tex]

Answer:

The function's graphic is the one that is below the first one in th right.

Step-by-step explanation:

If we want to know how much Chelsea earns for dogsitting her neighbours' dogs, we have to form a linear equation, that must have the following formula:

[tex]y= ax + b[/tex]

In this case, B is the constant value. We know Chelsea charges 12$ for dogsitting, and that doesn't depend on anything (B). But, if you want to Chelsea to walk your dog, then you'd to pay 2.50$ for each walk (X).

[tex]y= 2.50x + 12[/tex]

So, if Chelsea doesn't walk the neighbour's dog (x=0), she would be earning 12 dolars.

[tex]y= 2.50 x 0 + 12 = 12[/tex]

If she walks four times the dog, she would be earning:

[tex]y= 2.50 x 4 + 12 = 10 + 12 = 22 [/tex]

Knowing these two values, we can graph the equation. When x=0, y=12, and when x=4, y=22

The function's graphic is the one that is remarked in the attachment.

Answer: i guess the problem is with P(x) => "x = [tex]x^{2}[/tex]", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and [tex]0^{2}[/tex] = 0. So p(0) is true.

b) x = 1 and [tex]1^{2}[/tex] = 1, so P(1) is true.

c) x = 2, and [tex]2^{2}[/tex] = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and [tex]1^{2}[/tex] = 1, and 1 ≠ -1, so P(-1) is false.

The truth value of P(0) and P(1) is true while the truth value of P(2) and P(-1) is false

The statement is given as:

[tex]x = x^2[/tex]

For P(0), we have:

[tex]0 = 0^2[/tex]

[tex]0 = 0[/tex] --- this is true

For P(1), we have:

[tex]1 = 1^2[/tex]

[tex]1 = 1[/tex] --this is true

For P(2), we have:

[tex]2 = 2^2[/tex]

[tex]2= 4[/tex] -- this is false

For P(-1), we have:

[tex](-1) = (-1)^2[/tex]

[tex](-1) = 1[/tex] --- this is false

Hence, the truth value of P(0) and P(1) is true while the truth value of P(2) and P(-1) is false

Read more about truth values at:

https://brainly.com/question/10678994

Answer:

[tex]h(t)=-\dfrac{11}{3}t[/tex]

Step-by-step explanation:

A snorkeler dives for a shell on a reef. After entering the water, the diver decends [tex]\frac{11}{3}[/tex] ft in one second.

Let t be the time passed after entering the water, in seconds, and h(t) be the position of the snorkeler under the water, in feet.  

The initial position of the snorkeler was 0 feet under the water.

An equation that models the divers position with respect to time is

[tex]h(t)=0-\dfrac{11}{3}t\\ \\h(t)=-\dfrac{11}{3}t[/tex]

Here the position is negative, because the diver decends (he deepens under the water)

Answer: 686 N

Step-by-step explanation:

Hi!

Second Newton's law is: F=m*a, where F is force, m is mass, and a acceleration

On the Earth's surface, weight is the gravity force W=m*g, where g=9.8 m/s² is the acceleretion of gravity on Earth. So the weight of someone with mass m=70 kg is W=70*9.8 kg*m/s² = 686 N.

The unit N (Newton) is defined as 1 N = 1 kg*m/s²

Answer:  30 people

Step-by-step explanation: So you start with 12 people

12+6= 18 because 6 more people moved in then an additional 12 move in because it doubles every month

The total number of people occupying the development on 31 March 2017 is 466.

To determine how many people occupy the development on 31 March 2017, we need to consider the pattern of people moving in each month since January 2016.

Initial Occupants: There were 12 people in the development as of January 2016.

Additional Occupants in January 2016: During January 2016, 6 more people moved in.

Monthly Pattern: Each subsequent month, 4 more people move in than the previous month. So, we need to figure out this sequence from February 2016 to March 2017.

Calculating Monthly Increase:

Sum of Monthly Increases: We need to determine the total number of new occupants from February 2016 to March 2017. This period includes 14 months.

The sequence of increases is: 6, 10, 14, 18, ..., up to March 2017.

This is an arithmetic sequence where the first term [tex]a = 6[/tex] and the common difference [tex]d = 4[/tex].

The [tex]n^{th}[/tex] term of an arithmetic sequence is given by: [tex]a_n = a + (n-1)d[/tex]

For March 2017 (14 months after January 2016): $a_{14} = 6 + (14-1) * 4 = 6 + 52 = 58 people.

Sum of an Arithmetic Sequence: The sum of the first [tex]n[/tex] terms of an arithmetic sequence is given by: [tex]S_n = \{n}{2} \times (2a + (n-1)d)[/tex]

Here, [tex]a = 6[/tex], [tex]d = 4[/tex], and [tex]n = 14[/tex].

[tex]S_{14} = \{14}{2} \times(2 \times 6 + (14-1) \times 4)[/tex]

[tex]S_{14} = 7 \times (12 + 52) = 7 \times 64 = 448[/tex] people moved in from February 2016 to March 2017.

Total Occupants at the End of March 2017:

Initial occupants: 12

Additional in January 2016: 6

New occupants from February 2016 to March 2017: 448

Total = 12 + 6 + 448 = 466 people

Answer: The dimensions of rectangle are 32 feet and 16 feet.

Step-by-step explanation:

Let the width of rectangle be 'x'.

Let the length of rectangle be '2x'.

Perimeter of fence = 96 feet

As we know the formula for "Perimeter":

[tex]Perimeter=2(l+b)\\\\96=2(2x+x)\\\\\dfrac{96}{2}=3x\\\\48=3x\\\\x=\dfrac{48}{3}\\\\x=16\ ft[/tex]

Hence, the length of rectangle is 2x=2×16 = 32 feet and width is 16 feet.

Therefore, the dimensions of rectangle are 32 feet and 16 feet.

Answer:

1.176 grams

Step-by-step explanation:

Given:

Recommended dose

21 mg per day for 6 weeks

Now,

1 week = 7 days

Thus,

number of days in 6 weeks = 6 × 7 = 42 days

Therefore, the total dose = dose per days × number of days

= 21 × 42 = 882 mg

further,

14 mg per day for 2 weeks

Now,

1 week = 7 days

Thus,

number of days in 2 weeks = 2 × 7 = 14 days

Therefore, the total dose = dose per days × number of days

= 14 × 14 = 196 mg

further,

7 mg per day for 2 weeks

Now,

1 week = 7 days

Thus,

number of days in 6 weeks = 2 × 7 = 14 days

Therefore, the total dose = dose per days × number of days

= 7 × 14 = 98 mg

Hence, the total dose = 882 + 196 + 98 = 1176 mg

also,

1 g = 1000 mg

thus,

1176 mg = 1.176 grams

total quantity received during this course is 1.176 grams

Answer:

The value of given expression is [tex]\frac{21}{128}[/tex].

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

[tex]q=1-p=1-\frac{1}{2}=\frac{1}{2}[/tex]

The given expression is

[tex]C(n,x)p^xq^{n-x}[/tex]

It can be written as

[tex]^nC_xp^xq^{n-x}[/tex]

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

[tex]^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}[/tex]

[tex]\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}[/tex]

[tex]\frac{7!}{2!5!}(\frac{1}{2})^{2+5}[/tex]

[tex]\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}[/tex]

[tex]21(\frac{1}{2})^{7}[/tex]

[tex]\frac{21}{128}[/tex]

Therefore the value of given expression is [tex]\frac{21}{128}[/tex].

Answer:

[tex]300\cdot \$1.50+\$125=\$450+\$125=\$575[/tex]

Step-by-step explanation:

The marginal cost is said to be $1.50. Marginal cost is just how much the cost increases per additional unit produced. In this case we're dealing with a shop of slices of pizza, so the marginal cost just represents how much the cost increases per additional slice of pizza produced, or in simpler words, how much it costs to produce a slice of pizza.

We want to compute the total cost to sell 300 slices in one day, so we have to compute how much it costs to produce those 300 slices and add up the fixed costs (which is $125, no matter how many slices we produce). Since the marginal cost is $1.50, that means each slice costs $1.50 to produce. So the 300 slices cost [tex]300\cdot \$1.50=\$450[/tex] to produce. And so the total cost is

[tex]\$450+\$125=\$575[/tex]

Answer:

NOR Gate

Step-by-step explanation:

NOR gate is a two input gate.

It is defined as the complement of (X or Y), where X and Y are the inputs of the gate.

X    Y    X+Y   Complement(X+Y)   NOR

1      1        1                  0                       0

1      0       1                  0                       0

0     1        1                  0                       0

0     0       0                  1                        1

Ut is an operator which gives a value of 1 only when the bvoth the inputs are 0.

A truth table for the logical operator NOR is:

P Q NOR

T T F

T F F

F T F

F F T

How to construct a Truth Table?

A truth table is a mathematical table used in logic to show all possible combinations of truth values for the input variables of a Boolean function and their corresponding output.

To construct a truth table for the logical operator NOR, we can use the following table:

P Q NOR

T T F

T F F

F T F

F F T

The NOR operator returns true only when both inputs are false. Otherwise, it returns false.

This can also be expressed as ¬(P ∨ Q), which is logically equivalent to P NOR Q.

Answer:

450 mL/hr

Step-by-step explanation:

Given:

Order for vasopressin = 18 units/hour

Available vasopressin = 200 units in 5000 mL

Now,

Volume of vasopressin per unit =  [tex]\frac{\textup{Volume of vasopressin}}{\textup{Number of units}}[/tex]

or

Volume of vasopressin per unit =  [tex]\frac{\textup{5000}}{\textup{200}}[/tex]

or

Volume of vasopressin per unit = 25 mL/unit

Thus,

Drip rate in mL/hr  

= volume of vasopressin per unit × order for vassopressin

or

Drip rate in mL/hr  = 25 × 18 = 450 mL/hr

The drip rate for an order of Vasopressin 18 units/hr, given a solution concentration of 200 units in 5000 mL, is calculated to be 450 mL/hr.

To find the drip rate in mL/hr, we start by determining the concentration of the vasopressin solution. It is 200 units in 5000 mL D5W, so the concentration is 0.04 units/mL (200 units/5000 mL).

Next, we know the doctor prescribed 18 units/hr of vasopressin. To find out how many mL this corresponds to, we divide the order of 18 units/hr by the concentration in units/mL,  which gives us 450 mL/hr (18 units/hr / 0.04 units/mL).

Therefore, the drip rate for the Vasopressin order is 450 mL/hr.

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Answer:

0.84

Step-by-step explanation:

Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:

P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95

We are to find out P(A'UB)

We have

[tex]P(AUB) =P(A)+P(B)-P(A\bigcap B)\\0.95=0.86+0.79-P(A\bigcap B)\\P(A\bigcap B)=0.70[/tex]

[tex]P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84[/tex]P(A \bigcap B)[/tex]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(c) 0.3

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

[tex]A\cap B\subset A[/tex] and [tex]A\cap B\subset B[/tex]

[tex]P(A\cap B)\leq P(A)[/tex] and [tex]P(A\cap B)\leq P(B)[/tex]

[tex]P(A\cap B)\leq 0.6[/tex] and [tex]P(A\cap B)\leq 0.4[/tex]

From these two inequalities we conclude that

[tex]P(A\cap B)\leq 0.4[/tex]

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let [tex]P(A\cap B)=0.3[/tex]

We need to find the probability that student has one of these two types of cards.

[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)[/tex]

Substitute the given values.

[tex]P(A\cup B)=0.6+0.4-0.3=0.7[/tex]

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

[tex]P(A'\cup B')=1-P(A\cup B)[/tex]

[tex]P(A'\cup B')=1-0.7=0.3[/tex]

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

[tex]A-B[/tex]

It can also written as

[tex]A\cap B'[/tex]

The probability of this event is

[tex]P(A\cap B')=P(A)-P(A\cap B)[/tex]

[tex]P(A\cap B')=0.6-0.3=0.3[/tex]

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

[tex]P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)[/tex]

[tex]P(A\cap B')+P(A\cap B')=0.7-0.3[/tex]

[tex]P(A\cap B')+P(A\cap B')=0.4[/tex]

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

Answer:

0.9503

Step-by-step explanation:

First of all, there are some wrong figures in the original text. Because there is a total of 362362 people, the figures should be 86086 (people in the 18-21 age bracket), 43043 (people in the 18-21 age bracket  who respond) and 43043 people in the 18-21 age bracket who refuse to respond. In the same way, because there are 276276 people in the 22-29 age bracket, it should be 18018 and not 1818 who refuse to respond in this subset of people. Now, let's define the following events:

R: a person respond

A: a person belongs to the 18-21 age bracket. So,

The number of people who respond is 43043 + 258258 = 301301, so

P(R) = 301301/362362 = 0.8315

P(A) = 86086/362362 = 0.2376

P(R | A) = 43043/86086 = 0.5

We are looking for P(A∪R) = P(A) + P(R) - P(A∩R),

P(A∩R) = P(R | A)P(A) = (0.5)(0.2376) = 0.1188, so,

P(A∪B) = 0.2376 + 0.8315 - 0.1188 = 0.9503

The initial position has no effect on the velocity, so you can ignore that value (unless there's another part to the question not included, of course).

We have

[tex]v(t)=v(0)+\displaystyle\int_0^t a(u)\,\mathrm du[/tex]

[tex]v(t)=55+\int_0^t\cos(\pi u)\,\mathrm du[/tex]

[tex]\boxed{v(t)=55+\dfrac1\pi\sin(\pi t)}[/tex]

The velocity of an object given the acceleration function a(t) = cos(πt) and an initial velocity of v(0) = 55 is found by integrating the acceleration function. This gives v(t) = (1/π)sin(πt) + 55.

The object's acceleration, velocity, and position can be determined using principles of calculus. The acceleration function is given as a(t) = cos(πt). We find the velocity by integrating the acceleration function. Therefore, v(t) = ∫a(t) dt = ∫cos(πt) dt. Using fundamental calculus principles, the integral of cos(πt) with respect to time (t) is (1/π)sin(πt).

However, the initial velocity is provided as v(0) = 55. To account for this initial condition, we add this known velocity to our integral, giving us v(t) = (1/π)sin(πt) + 55. Thus, the velocity of the object at any time t is given by v(t) = (1/π)sin(πt) + 55.

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Answer:

y = x'

z = y'

z' = x + t

Step-by-step explanation:

Hi!

You need to define two new variables y and z:

y = x'

z = y'

Then:

z = y' = x''

z' = x''' = x + t

Now you have a system of 3 equations with only first derivatives

Answer:

a) The z-score for the mileage of the car is -3.16

b) It appears that the car is getting unusually low gas mileage.

Step-by-step explanation:

The z-score formula is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In which: X is the mileage per gallon we are going to find the z-score of, [tex]\mu[/tex] is the mean value of this mileage and [tex]\sigma[/tex] is the standard deviation of this value.

a. Find the​ z-score for the gas mileage of your​ car, assuming the advertised claim is correct.

The gas mileage for you car is 16.4 mpg, so [tex]X = 16.4[/tex]

The advertised gas mileage is 20 mpg, so [tex]\mu = 20[/tex]

The standard deviation is 1.14 mpg, so [tex]\sigma = 1.14[/tex]

The z-score is:

[tex]Z = \frac{X - \mu}{\sigma} = \frac{16.4 - 20}{1.14} = -3.16[/tex]

b. Does it appear that your car is getting unusually low gas​ mileage?

The general rule is that a z-score lower than -1.96 is unusually low. So yes, it appears that the car is getting unusually low gas mileage.

To find the z-score for the gas mileage of your car, use the formula z = (x - μ) / σ. A z-score of -3.16 indicates that your car is getting unusually low gas mileage as it is more than 3 standard deviations below the mean.

To find the z-score for the gas mileage of your car, we can use the formula:

z = (x - μ) / σ

where x is the observed mileage, μ is the mean mileage, and σ is the standard deviation.

In this case, since the advertised mileage is 20 mpg, we have:

z = (16.4 - 20) / 1.14 = -3.16

For part b, a z-score of -3.16 indicates that your car is getting unusually low gas mileage as it is more than 3 standard deviations below the mean. Therefore, the answer is Yes.

In a normally distributed scenario, roughly 99.7% of data falls within three standard deviations from the mean, therefore for this question where we need to determine the blood pressure within 3 standard deviations from the mean, the answer is 99.7%.

The topic under discussion pertains to statistics, particularly, the properties of a normal distribution. In a normally distributed dataset, the rule of three standard deviations states that approximately 99.7% of all data falls within three standard deviations from the mean. This is also known as the empirical rule or the 68-95-99.7 rule. Therefore, in this case, since we are asked about the percentage of 18-year-old women who have a systolic blood pressure that falls within three standard deviations of the mean, the answer is 99.7%, which corresponds to choice (D).

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Answer:

  It is a multiple of 8

Step-by-step explanation:

The product may or may not be a factor of 8. We usually think of the factors of an integer as being positive integers, so the factors of 8 would be 1, 2, 4, or 8. If 8n is to be a factor of 8, then n must be 1/8, 1/4, 1/2, or 1. This will not be the case in general.

__

The product of 8 and any number is a multiple of 8. (Again, we usually think of a multiple of 8 as being an integer, which would require the number n to be an integer.)

__

No product of two (integer) numbers is a prime number. If 8n is to be a prime, then the value of n must be (some prime number)/8. Again, this will not be the case in general.

__

n is a factor of the product; not the other way around.

In the equation n x 8, the product is always a multiple of 8. The product is not necessarily a factor of 8, a prime number, or a factor of n.

In the given equation, n x 8, the product of n and 8 is always a multiple of 8. This is because when we multiply any number by 8, the resulting product is included in the sequence of multiples of 8 (i.e., 8, 16, 24, 32, and so forth). Hence, regardless of the value of n, the product is always a multiple of 8. Note that the product is not necessarily a factor of 8, a prime number, or a factor of n, as these properties depend on the specific value of n.

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The number of letters in word "ALGORITHM" = 9

The number of combinations to select r things from n things is given by :-

[tex]C(n,r)=\dfrac{n!}{r!(n-r)!}[/tex]

Now, the number of combinations to select 6 letters from 9 letters will be :-

[tex]C(9,8)=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!\times3!}=84[/tex]

Thus , the number of ways can six of the letters of the word ALGORITHM=84

The number of ways to arrange n things in a row :[tex]n![/tex]

So, the number of ways can the letters of the word ALGORITHM be arranged in a be seated together in the row :-

[tex]9!=362880[/tex]

If GOR comes together, then we consider it as one letter,  then the total number of letters will be = 1+6=7

Number of ways to arrange 9 letters if "GOR" comes together :-

[tex]7!=5040[/tex]

Thus, the number of ways to arrange 9 letters if "GOR" comes together=5040

Answer:

There are two more sides on a hexagon than on a quadrilateral

Step-by-step explanation:

If the hexagon has 6 sides, and the quadrilateral has 4, then 6-4=2