If time is an explanatory variable and temperature is the corresponding response variable which of these would be represented by the x-axis on a scatter plot? A. Neither Time nor Temperature B. Time C. Both Time and Temperature D. Temperature
Answer:
B. Time
Step-by-step explanation:
In general, x-axis is the variable (cause) and the y-axis is the response (effect)
So, according to the given information, TIME would be represented by the x-axis.
What is the area of this figure? Enter your answer in the box.
Michael bought a new soccer Jersey that was $24.99. after taxes the total cost was $28.99. What is the percent if increase
Assuming boys and girls are equally likely, find the probability of a couple having a baby boy boy when their fourth fourth child is born, given that the first three three children were all boys all boys.
34 + 4 ⋅ 5 = ____
PLEASE HELP ASAP FOR BRAINLIEST!!!!!
which equation is in slope-intercept form and represents a line with slope 3 through the point (9,-4)
Slope-intercept form is y = mx +b, where the variable m represents the slope of the line and the variable b represents the y-intercept of the line. Since we weren't given the y-intercept, one way to solve this problem is substitute the slope for the variable m and then the x and y values from the ordered pair to solve for b.
y = mx + b
y = 3x + b
-4 = 3(9) + b
Now, we can simplify by computing the multiplication on the right side of the equation.
-4 = 27 + b
Finally, we can find the value for b by subtracting 27 from both sides of the equation to get:
-31 = b
Now, we should substitute this value for b back into our equation with the slope.
y = 3x - 31
Therefore, your answer is y = 3x - 31.
Hope this helps!
Answer:
The correct answer would be y = 3x - 31
Step-by-step explanation:
In order to find the answer to this question, we must use point-slope from, which is listed below.
y - y1 = m(x - x1)
Now we input the ordered pair in for x1 and y1 and the slope in for m.
y - -4 = 3(x - 9)
Then we solve for y.
y + 4 = 3x - 27
y = 3x - 31
BRAINLIEST!!!!!!!!
When you have two shapes to compare on a coordinate plane, you can determine the scale factor, knowing that the transformation was a dilation. Generate instructions you would give another student to determine the scale factor.
You can calculate the scale factor by dividing the coordinates of the image by the corresponding coordinates of the pre-image.
What is scale factor?A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).
Assume that the initial coordinates are (x, y) and that the dilated coordinates are (x', y').
The dilation is therefore:
(x, y) → (x', y')
Now, let's assume that the dilation factor is k.
Therefore:
x' = kx
y' = ky
To get the initial coordinates and the final ones and then substitute in any of the above two equations to get the value of k, which is the scale factor,
For example =
Assume an original point at (2,4) is dilated to coordinates (4,8) we need to find the dilation factor.
Assume the dilation coefficient is k.
(x, y) are (2,4) and (x', y') are (4,8)
Therefore:
x' = kx → 4 = k×2 → k = 2
or:
y' = ky → 8 = k×4 → k = 2
Based on the above, the dilation coefficient would be 2.
Learn more about scale factors, click;
https://brainly.com/question/30215119
#SPJ3
21 out of 25 cars have 4 doors what percentage have four doors
What is the solution of the system of equations?y = –4x + 10y = –2x – 6(–22, 8)(8, –22)(–2, –2)(–2.67, 20.67)?
Find the percent of increase or decrease. 55mph to 70mph
Which number is an irrational number?
a) square root of 100
b)1/8
c)-2.2675
d)exponent 3 square root of 16
Answer:
D
Step-by-step explanation:
How many 2-digit numbers are multiples of neither 5 nor 7?
Answer:
Step-by-step explanation:
You take the amount of 2-digit numbers there are (90) and subtract it from the amount of two digit numbers that are multiples of 5 and 7 (29). You should get 61.
Answer: The number 2-digit numbers are multiples of neither 5 nor 7 is 61.
Step-by-step explanation: We are given to find the number of 2-digit numbers that are multiples of neither 5 nor 7.
Let A denote the set of 2-digit numbers that are multiples of 5 and B denote the set of 2-digit numbers that are multiples of 7.
Then,
A = {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95}
and
B = {14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98}
That is, n(A) = 18 and n(B) = 13.
Now, the set of 2-digit numbers that are multiples of both 5 and 7 is given by
[tex]A\cap B=\{35, 70\}~~~~~~\Rightarrow n(A\cap B)=2.[/tex]
Therefore, the number of 2-digit numbers that are multiples of either 5 or 7 is given by
[tex]n(A\cup B)=n(A)+n(B)-n(A\cup B)=18+13-2=29.[/tex]
Now, there are 90 2 -digit numbers.
Thus, the number 2-digit numbers are multiples of neither 5 nor 7 is
90 - 29 = 61.
Hence, the total number of numbers is 61.
write a cosine function for the graph?
Answer(s):
[tex]\displaystyle y = 4cos\:(4\theta \pm \pi) \\ y = -4cos\:4\theta[/tex]
Step-by-step explanation:
[tex]\displaystyle y = Acos(B\theta - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\pm\frac{\pi}{4}} \hookrightarrow \frac{\pm\pi}{4} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 4[/tex]
OR
[tex]\displaystyle y = -Acos(B\theta - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 4[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that this cosine graph will have TWO equations because the curvature begins upward from [tex]\displaystyle [0, -4][/tex] instead of downward from [tex]\displaystyle [0, 4],[/tex] telling you that one equation will have a “negative” symbol inserted in the beginning of the equation. Before we go any further though, we must figure the period of the graph out. So, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, -4],[/tex]from there to [tex]\displaystyle [-\frac{\pi}{2}, -4],[/tex] they are obviously [tex]\displaystyle \frac{\pi}{2}\:unit[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{\pi}{2}.[/tex] Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 4cos\:4\theta.[/tex] Now, if you look hard enough, you will see that both graphs are “mirror reflections” of one another, meaning you can figure the rest of the terms out one of two ways. The first way is to figure the appropriate C-term out that will make the graph horisontally shift and map onto the original cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also, keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the rightward graph is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] on both sides of the y-axis, which means that in order to match the original graph, we need to shift the graph back, which means the C-term will be both negative and positive; and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\pm\frac{\pi}{4}} = \frac{\pm\pi}{4}.[/tex]So, one equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 4cos\:(4\theta \pm \pi).[/tex] Now that we got this out the way, we can focuss on finding the second equation. Another way is to write an equation with a “negative” symbol inserted in the beginning [like I mentioned earlier]. Now, sinse we are writing an equation with the negative, the graph will not have a horisontal shift; so, C will be zero. With this said, the second equation is [tex]\displaystyle y = -4cos\:4\theta.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex] in which each crest is extended four units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
A bakery purchase all of the pumpkins to make pies. If she a 100 bill to pay for the pumpkins, how much change will she receive?
What is the area, in cm2, of the circle shown above? Round your answer to the nearest tenth.
A line passes through the (1, -6) and has a slope of 5. write an equation for this line
does anyone have idea of a poem with using number 16
Hey can you please help me posted picture of question
Which of the following is the domain of the function G(F(x))?
F(x) = x + 4, G(y) =
G(F(x)) =
A. All numbers less than or equal to 4
B. All numbers less than or equal to -4
C. All numbers greater than or equal to -4
D. All numbers greater than or equal to 4
a salesman's commission on 150,000 sale is 3000. what is the percent?
Evaluate Cot0 if sin0= square root of 6/5
Find the feet of c and d
When a graph is periodic, its shape repeats, again and again. Think of at least five events in your life that are periodic and whose periods are long. For example, an event might repeat only once or twice a year, or even once a month. What is the period and frequency of each event? Which incidents repeat most frequently? Which repeat least frequently?
hello can you please help me posted picture of question
(a) find the slope m of the tangent to the curve y = 5 + 5x2 − 2x3 at the point where x =
a. m = (b) find equations of the tangent lines at the points (1, 8) and (2, 9). y(x) = (at the point (1, 8)) y(x) = (at the point (2, 9))
The slope of the tangent will be "[tex]10a-6a^2[/tex]". The equation at point (1, 8) is "[tex]y = 4x+4[/tex]" and at point (2,9) is "[tex]y = -4x+17[/tex]".
Given equation is:
[tex]y = 5+5x^2-2x^3[/tex](a)
The slope of the tangent to the curve point where [tex]x = a[/tex] is:
→ [tex]\frac{dy}{dx} = m = 10x-6x^2[/tex]
→ [tex]= 10a-6a^2[/tex]
(b)
The equation of tangent at point (1,8) will be:
→ Slope, [tex]m = 10-6[/tex]
[tex]= 4[/tex]
→ [tex]y-8=4(x-1)[/tex]
[tex]y = 4x-4+8[/tex]
[tex]y = 4x+4[/tex]
and,
The equation of tangent at point (2,9) will be:
→ Slope, [tex]m = 10\times 2-6\times 2^2[/tex]
[tex]= 20-24[/tex]
[tex]= -4[/tex]
→ [tex]y-9=-4(x-2)[/tex]
[tex]y-9=-4x+8[/tex]
[tex]y = -4x+17[/tex]
Thus the above answer is right.
Learn more about tangent here:
https://brainly.com/question/10462284
What is the quotient of -19/2 divided by 38/ 7
Algebraically determine if the relation y=10x is symmetric with respect to the x-axis, y-axis, the origin or has no symmetry
A.) y-axis
B.)no symmetry
C.)the origin
D.)x-axis
Hey can you please help me posted picture of question
Audrey can drive 135 miles on 6 gallons of gas and 225 miles on 10 gallons of gas.
stans cookie recipe makes 24 cookies and calls for exactly 384 sprinkles he is wondering how many sprinkles he would need to make 60 cookies he assumes each cookie will have same number of sprinkles how many sprinkles does Stan need to make 60 cookies
Answer:
Stan would need 960 sprinkles to make 60 cookies.
Step-by-step explanation:
Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.
Since we are given 3 values, which are the amount of sprinkles to make 24 cookies, 60 cookies, and give us one variable. We can use the Rule of Three technique to find the amount of sprinkles needed for 60 cookies. This technique is shown in the picture that is attached below.
24 cookies ⇒ 384 sprinkles
60 cookies ⇒ x
[tex]\frac{60*384}{24} = x[/tex]
[tex]960 sprinkles = x[/tex]
Therefore, we can see that Stan would need 960 sprinkles to make 60 cookies.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.