The six pollutants regulated under the Clear Air Act _____ between 1970 and 2001, while energy consumption increased 42 percent.

increased only 6 percent

decreased 39 percent

decreased 24 percent

remained stable

Answers

Answer 1

Answer:

increased only 6 percent

Explanation:

The six pollutants regulated under the Clear Air Act increased only 6 percent between 1970 and 2001, while energy consumption increased 42 percent.

Answer 2

Answer:Explained

Explanation:

The six pollutants regulated under the clear air act are

leadPMSulfur dioxidecarbon monoxidenitrogen oxidesozone

Clear air act is the first and most comprehensive air quality control law and is under U.S. Environmental Protection agency.

A study of 2017 shows it causes a reduction of 10% in pollution within 3 years of implementation.


Related Questions

In the equation Ca(s) + 2H2O(l) -->Ca(OH)2(aq) + H2(g), list each element used as a reactant, and tell how many atoms of each are needed for this reaction.

Answers

Answer:

See below

Explanation:

Ca + 2H2O → Ca(OH)2 + H2

The elements involved are:

Ca — calcium H   —   hydrogen O   — oxygen

The numbers of each atom are:

1  atom  Ca 4 atoms H 2 atoms O

The 2 in front of H2O multiplies everything in the H2O.

Hear flows from water in one container to another. What difference between the two samples of water causes heat to flow?

A)one sample must have dissolved materials within it

B)one sample must contain more water molecules than the other

C)one sample must be cooler than the other

D)one sample must have more mass than the other

Answers

In order for heat transfer between bodies from one container to another, one sample must be cooler than the other.

When there is a temperature difference between two substances , energy flows in the form of heat from the warmer to the cooler body until the temperature of both the body reaches equilibrium or same. This process is commonly known as heat transfer.This is according to second law of thermodyanimcs

In summary, heat flows due to a temperature gradient or temperature difference . The substance at a higher temperature will lose energy while the substance at a lower temperature gains energy in the form of heat. This flow continues until both the body reaches an equal temperature

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Water is a(n)______ molecule, and it easily dissolves _______ molecules. A. covalent, polar B. ionic, covalent C. ionic, ionic D. covalent, covalent

Answers

Answer:

A. covalent, polar

Explanation:

Water is a(n) covalent molecule, and it easily dissolves polar molecules.

1. Complete the reaction illustrating the hydration reaction of a strong electrolyte CaCl2​

Answers

Answer:

CaCl₂(s) ⟶ Ca²⁺(aq) + 2Cl⁻(aq)

Explanation:

When the calcium chloride dissolves. the calcium and chloride ions leave the surface of the solid and go into solution as hydrated ions.

what is the volume of stank of nitrogen that contains 17 moles of nitrogen at 34 C under 12,000Pa?

Answers

Answer:

3626.76dm³

Explanation:

Given parameters:

Number of moles of Nitrogen in tank = 17moles

Temperature of the gas = 34°C

Pressure on the gas = 12000Pa

Unkown:

Volume of the tank, V =?

Converting the parameters to workable units:

We take the temperature from °C to Kelvin

K = 273 +  °C  = 273 + 34 = 307k

Taking the pressure in Pa to atm:

101325Pa = 1atm

12000Pa = 0.118atm

Solution:

To solve this problem, we employ the use of the ideal gas equation. The ideal gas law combines three gas laws which are the Boyle's law, Charles's law and the Avogadro's law.

            It is expressed as PV = nRT

The unknown is the Volume and we make it the subject of the formula

             V = [tex]\frac{nRT}{P}[/tex]

Where R is called the gas constant and it is given as 0.082atmdm³mol⁻¹K⁻¹

Therefore  V = [tex]\frac{17 x 0.082 x 307 }{0.118}[/tex] = 3626.76dm³

Answer: The volume of nitrogen will be 3614.15 L

Explanation:

To calculate the number of moles, we use the equation given by ideal gas equation:

[tex]PV=nRT[/tex]

Or,

[tex]PV=\frac{m}{M}RT[/tex]

where,

P = pressure of the gas = 12000 Pa = 12 kPa    (Conversion factor: 1 kPa = 1000 Pa)

V = Volume of gas = ?

n = number of moles of nitrogen = 17 moles

R = Gas constant = [tex]8.31\text{L kPa }mol^{-1}K^{-1}[/tex]

T = temperature of the gas = [tex]34^oC=[34+273]=307K[/tex]

Putting values in above equation, we get:

[tex]12kPa\times V=17mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 307K\\\\V=3614.15L[/tex]

Hence, the volume of nitrogen will be 3614.15 L

How many moles of oxygen must be placed
in a 3.00 L container to exert a pressure of 2.00 atm at 25.0°C?

Answers

Answer: 0.245 moles of oxygen must be placed in the container to exert the given pressure at the given temperature. The Ideal Gas Law equation gives the relationship among the pressure, volume, temperature, and moles of gas.

Further Explanation:

The Ideal Gas Equation is:  

[tex]PV = nRT[/tex]  

where:  

P - pressure (in atm)  

V - volume (in L)  

n - amount of gas (in moles)  

R - universal gas constant [tex]0.08206 \frac{L-atm}{mol-K}[/tex]  

T - temperature (in K)  

In the problem, we are given the values:  

P = 2.00 atm (3 significant figures)

V = 3.00 L  (3 significant figures)

n = ?

T = 25.0 degrees Celsius (3 significant figures)  

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:  

[tex]Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15[/tex]  

Therefore, for this problem,  

[tex]Temperature\ in \ K = 25.0 +273.15\\Temperature\ in \ K = 298.15[/tex]  

Solving for n using the Ideal Gas Equation:  

[tex]n \ = \frac{PV}{RT}\\n \ = \frac{(2.00 \ atm) \ (3.00 \ L)}{(0.08206 \ \frac{L-atm}{mol-K})( 298.15 \ K)}  \\n \ = 0.245 \ mol[/tex]

The least number of significant figures is 3, therefore, the final answer must have only 3 significant figures.

Learn More  

1. Learn more about Boyle's Law https://brainly.com/question/1437490  

2. Learn more about Charles' Law https://brainly.com/question/1421697  

3. Learn more about Gay-Lussac's Law https://brainly.com/question/6534668

Keywords: Ideal Gas Law, Volume, Pressure

Answer:

answer in picture

Explanation:

You are performing an experiment in a lab to attempt a new method of producing pure elements from

compounds. The only problem is that you do not know what element will form. By your previous calculations

you know that you will have 6.3 moles of product. When it is complete, you weigh it and determine you have

604.4 grams. What element have you produced?

Answers

Answer:

Molybdenum

Explanation:

Since, the atomic mass of the elements is a characteristic property of the elements, you can use the data given, number of moles and mass in grams of the product, to calculate the atomic mass of the product, and then compare with the atomic masses of the elements (information foun in any periodic table).

1) Atomic mass of the product:

Atomic mass = mass in grams / number of moles

Atomic mass = 604.4 g / 6.3 mol = 95.94 g/mol ≈ 94.9 g/mol (rounded to three significant figures)

2) Periodic table:

Molybdenum, Mo, the element with atomic number 42, has atomic mass equal to 95.94 g/mol.

3) Conclusion:

So, you can conclude safely that the element you have produced is Molybdenum.

19. Which of the following chemical equations represents
propane combusts?
A. 2 CsHe (g) + 5O2 (g) → 3C02(g) + 4H20 (1)
B. 2 CsHe (g) + 5O2 (g) → 3CO2(g) + 3H20(1
C. CsHe (g) + O2 (g) → CO2(g) + H2O(1)
D. CsHa (g) + 5O2 (g) → 3CO2(g) + 4H2O(1)

Answers

Answer:

C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

(option D. with the proviso that the subscripts of propane's chemical formula must be corrected)

Explanation:

Propane is the saturated hydrocarbon, alkane, with chemical formula C₃H₈ or CH₃CH₂CH₃.

The complete combustion of the hydrocarbons yield carbon dioxide (CO₂) and water (H₂O).

The chemical equation that represents this combustion is:

C₃H₈ (g) + O₂(g) → CO₂ (g) + H₂O (l) (skeleton equation: unbalanced)

Once you balance it, you get:

C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

        Left side           Right side

C         3                          3

H         8                          4×2 = 8

O        5×2 = 10               3×2 + 4 = 10

That equation corresponds to the option D. of the list, with the proviso that the subscripts of propane's chemical formula must be corrected

Explain, in terms of particles, concentration, and reaction rate, what you expect to happen when methane gas (CH4) and hydrogen sulfide gas (H2S) are sealed in a flask and reach a state of equilibrium.

CH4 (g) +2 H2S (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CS2 (g) + 4 H2 (g)

Answers

Answer:

Explanation:

The equation of this equilibrium reaction is shown below:

     CH₄ + 2H₂S ⇄ CS₂ + 4H₂

All the gases in this reaction are in a gaseous phase.

When gases are in equilibrium with one another, we can make some comments about their particles, concentration and reaction rate.

For the particles:

The magnitude of the kinetic energy here is very great according to the kinetic theory of matter. This is because the particles are in a uniform gaseous phase.

In terms of concentration

When dealing with gases in equilibrium, we talk more of the concentration with regards to pressure. Pressure is equivalent to concentration when we consider gaseous reactions. An increase in pressrue is like applying a stress to the system. Based on Le Chatelier's principle, increase in pressure favors the side with smaller volume:

                       CH₄             +         2H₂S           ⇄ CS₂        + 4H₂

                        3 moles of gases                          5 moles of gases

Increase in pressure will favor the reactant side.

Reaction rate

The rate at which this reaction will proceed would be very fast. This is because gases have the fastest rate of reaction. The equilibrium will quickly be reached.

What is generally true about the particles in a gas?

Gas particles are closer together and have stronger attraction between them than the particles in a solid.
Gas particles are closer together and able to conduct electricity better than the particles in a plasma.
Gas particles are farther apart and able to conduct electricity better than the particles in a liquid.
Gas particles are farther apart and have weaker attraction between them than the particles in a solid.

Answers

Answer:

D

Explanation:

Gases move away from each other. Solids and liquids are more attached whereas gases are separate

The true statement about gas particles is that "Gas particles are farther apart and have weaker attraction between them than the particles in a solid"

STATES OF MATTER:

Matter refers to anything that has mass and occupies space. This includes almost everything we can find in our natural environment.

There are three states of matter in existence namely:

Solids: The particles are closely packed together, hence they cannot move.

Liquids: The particles are bonded together by a weak attraction, hence, they can move about or slide past one another.

Gases: Particles of gases are far apart from one another and hence move freely at great speed.

Therefore, the true statement about gas particles is that "Gas particles are farther apart and have weaker attraction between them than the particles in a solid"

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From the following balanced equation,
4NH3(g)+5O2(g)⟶4NO(g)+6H2O(g)
how many grams of H2O can be formed from 6.12g NH3?

Answers

Final answer:

Approximately 9.73 grams of H2O can be formed from 6.12g of NH3, using stoichiometric calculations and assuming a complete reaction with no limiting reactants.

Explanation:

In order to determine how many grams of H2O can be formed from 6.12g NH3, we must first apply the concept of the stoichiometry of chemical reactions. According to the balanced equation 4NH3(g) + 5O2(g) ➔ 4NO(g) + 6H2O(g), we understand that 4 moles of NH3 produce 6 moles of H2O

Firstly, we convert grams of NH3 to moles using its molar mass (about 17.03 g/mol). So, 6.12g of NH3 equates to around 0.36 moles.

Then, for each mole of NH3, we can form 1.5 moles of H2O (since 6 moles of H2O are produced by 4 moles of NH3). Thus, 0.36 moles of NH3 could potentially produce 0.54 moles of H2O. We can then convert these moles of H2O back into grams by multiplying by the molar mass of H2O, about 18.02g/mol. Therefore, approximately 9.73g of H2O could be produced from 6.12g of NH3, assuming a complete reaction and no limiting reactants.

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The mass of H2O that can be formed from 6.12 g of NH3 is approximately 9.71 g.

To determine the mass of H2O that can be formed from 6.12 g of NH3, we need to follow these steps:

 1. Calculate the moles of NH3 using its molar mass.

2. Use the stoichiometry of the balanced equation to find the moles of H2O that can be produced from the moles of NH3.

3. Convert the moles of H2O to grams using its molar mass.

Let's start with step 1:

 The molar mass of NH3 is [tex]14.01 g/mol (Nitrogen) + 1.008 g/mol (Hydrogen) * 3 = 17.034 g/mol.[/tex]

Now, we calculate the moles of NH3:

[tex]\[ \text{moles of NH3} = \frac{\text{mass of NH3}}{\text{molar mass of NH3}} = \frac{6.12 \text{ g}}{17.034 \text{ g/mol}} \approx 0.3593 \text{ mol} \][/tex]

Next, according to the balanced equation, 4 moles of NH3 produce 6 moles of H2O. Therefore, the moles of H2O produced from 0.3593 moles of NH3 are:

[tex]\[ \text{moles of H2O} = \text{moles of NH3} \times \frac{6 \text{ moles of H2O}}{4 \text{ moles of NH3}} = 0.3593 \text{ mol} \times \frac{6}{4} \approx 0.53895 \text{ mol} \][/tex]

Finally, we convert the moles of H2O to grams using the molar mass of H2O, which is 18.015 g/mol (2 * 1.008 g/mol for Hydrogen and 16.00 g/mol for Oxygen):

[tex]\[ \text{mass of H2O} = \text{moles of H2O} \times \text{molar mass of H2O} = 0.53895 \text{ mol} \times 18.015 \text{ g/mol} \approx 9.71 \text{ g} \][/tex]

Therefore, the mass of H2O that can be formed from 6.12 g of NH3 is approximately 9.71 g.

 The answer is: 9.71.

Nitrogen is a group 15 element. What does being in this group imply about the structure of the nitrogen atom?
A. Nitrogen has 15 valence electrons.
B.
Nitrogen has 15 neutrons.
C.
Nitrogen has 5 valence electrons.
D.
Nitrogen has 5 neutrons.

Answers

c
nitrogen has 5 valence electrons

Answer: Option (C) is the correct answer.

Explanation:

As nitrogen is a group 15 element so, it means that common electronic distribution of elements of group 15 will be 2, 8, 5.

Hence, it means that all the elements of group 15 have 5 valence electrons.

Valence electrons are the electrons that are present in the outermost orbital shell.

Whereas atomic number of nitrogen atom is 7 and its atomic mass is 14. Therefore, it contains 7 protons and 7 neutrons in its nucleus.

Thus, we can conclude that nitrogen is a group 15 element it implies that nitrogen has 5 valence electrons.

Weight training has the biggest effect on __________.

Answers

i’m pretty sure it would be athletes, because it makes them stronger for whatever sports they are participating in. hope this helps :)

Weight training has the biggest effect on skeletal muscles.

A muscle fibre is another term for a single skeletal muscle cell, which is not the same as skeletal muscle. The many muscle fibres that make up skeletal muscles are bound together by connective tissue. The contraction of each muscle fibre, which is made up of a single multinucleated cell, results in force and movement.

A specific form of cell called a muscle fibre sometimes referred to as a myofiber or muscle cell, is what gives skeletal muscles their shape. Long, cylindrical cells called muscle fibres make up a muscle's length and are bound together by connective tissue. Since they have several nuclei, they are multinucleated cells, which may contract to provide force and movement.

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What is a substance used to decrease the rate of a chemical reaction

Answers

Answer:

Inhibitor.

Explanation:

An inhibitor is a substance that decreases the rate of, or prevents, a chemical reaction.

An inhibitor can reduce the effectiveness of a catalyst in a catalyzed reaction

quantity (g) of pure MgSO4 in 2.4 g of MgSO4•7H2O

Answers

Answer:

1.1724 g.

Explanation:

Firstly we need to calculate the percentage of pure MgSO₄ in (MgSO₄.7H₂O).If we have 1.0 mol of MgSO₄.7H₂O, then we will have the the mass of its molecular mass.

The molecular mass of 1.0 mol (MgSO₄.7H₂O) = 246.4 g/mol.

The molecular mass of pure MgSO₄ = 120.366 g/mol.

The molecular mass of 7(H₂O) = 7(18.0 g/mol) = 126.0 g/mol.

∴ The mass % of pure MgSO₄ = [(mass of pure MgSO₄)/(mass of MgSO₄.7H₂O)] x 100 = [(120.366 g/mol)/(246.4 g/mol)] x 100 = 48.85%.

∴ the quantity of pure MgSO₄ = (mass of MgSO₄.7H₂O)(% of MgSO₄/100) = (2.4 g)(48.85/100) = 1.1724 g.

equation for the reaction of rubidium with an Arrhenius base

Answers

Answer:

No reaction.

Explanation:

An Arrhenius base (like NaOH) increases the concentration of hydroxide ions present in the solution.

If you add Rb to an aqueous solution of NaOH, you will get an explosion.

However, the Rb does not react with the OH^-. Instead, it reacts rapidly with the water.

2Rb + 2H2O → 2RbOH + H2

So much heat is generated that the hydrogen explodes:

2H2 + O2 → 2H2O

A chemical company makes pure silver by reacting silver nitrate with zinc. The company needs to make 800 grams of pure silver for a client. They have 300 grams of zinc and 600 grams of silver nitrate. Will they be able to make enough silver to fill the order?

Answers

The reaction between zinc and silver nitrate is...

Moles of Zn = m /M = 599 /65 = 9.2 mol
Moles of AgNO3 = m /M = 1500 /169 = 8.87 mol

Silver nitrate is reacting completely to give silver. Thus, moles of Silver nitrate is equivalent to silver = 8.87

For mass of silver produced
m /M = 8.87 = m /107
m = 949.24 g

Hence, the given quantity of reactants are sufficient to produce 800 g of silver as the amount of silver produced is 949.24 g.

Answer:

yes with left over silver

A drought is a long period of dryness. If animals fight during a drought, which basic need is most likely limited? water supply shelter or space the ability to reproduce the availability of sunlight

Answers

Answer:

Water supply

Explanation:

When there is drought, which happens mostly within the tropics, water sources go dry. Plants and animals suffer alike. Animals have to scramble for the limited amount of water to quench their thirsts. Water is one of the basic requirements for the survival of living organisms like animals.

Answer:

water supply

Explanation:

Which of the following elements has the lowest electronegativity?

Ca

Sr

Fr

Answers

Answer:

Fr

Explanation:

Ca (calcium) has 1.00

Sr (strontium) has 0.95

and Fr (francium) has 0.7

making it Fr (francium)

What is the approximate percent by mass of oxygen in C2H4O2

Answers

Answer:

Approximately 53.3  %.

Explanation:

Molar mass of C2H4O2

= 2 * 12.011 + 4 * 1.008 + 2 * 15.999

=  60.052

% oxygen = (31.998* 100) / 60.052 = 53.28 %

A sample of cesium carbonate, weighing 3.80 g, requires 1.90 g of hydrogen bromide gas to completely decompose to water, cesium bromide, and carbon dioxide gas. The total mass of water and cesium bromide formed is 5.20 g and no hydrogen bromide or cesium carbonate remains. According to the law of conservation of mass, what mass of carbon dioxide must have been formed?
A. 0.50 g
B 1.40 g
C 5.49 g
D 10.90 g
E 1.90 g

PLEASE GIVE ME AN EXPLANATION ON WHY IT IS THE CORRECT ANSWER.

Answers

Answer:

Choice A. 0.50 g.

Explanation:

According to the question, the reaction here converts

caesium (cesium) carbonate and hydrogen bromide

to

cesium bromide, carbon dioxide, andwater.

By the Law of Conservation of Mass, matter can neither be created nor destroyed in a chemical reaction. (Shrestha et. al, Introductory & GOB Chemistry, Chemistry Libretexts, 2019.)

In other words, the mass of the reactants, combined, shall be the same as the mass of the products, combined.

What's the mass of the reactants?

[tex]\rm \underbrace{\rm 3.80\;g}_{\mathrm{Cs_2CO_3}} + \underbrace{\rm 1.90\; g}_{\mathrm{HBr}} = 5.70\;g[/tex].

What's the mass of the products?

Let [tex]m(\mathrm{CO_2})[/tex] represent the mass of carbon dioxide produced in this reaction.

The mass of the products will be:

[tex]\rm \underbrace{\rm 5.20\;g}_{\mathrm{CeBr}\text{ and }\mathrm{H_2O}} + \underbrace{m(\mathrm{CO_2})}_{\mathrm{CO_2}}[/tex].

The two masses shall be equal. That is:

[tex]\rm 5.20\; g + \mathnormal{m}(\mathrm{CO_2}) = 5.70\;g[/tex].

[tex]m(\mathrm{CO_2}) = \rm 0.50\;g[/tex].

In other words, by the Law of Conservation of Mass, the mass of carbon dioxide produced in this reaction will be [tex]\rm 0.50\;g[/tex].

At a temperature of 15 degrees C, a quantity of oxygen has a volume of 250 ml. If it’s temperature is raised to 45 degrees C, what will it’s volume be?

Answers

Answer:

280 mL

Explanation:

Ideal gas law:

PV = nRT

Rearranging:

V / T = nR / P

At constant pressure:

V₁ / T₁ = V₂ / T₂

Substituting values:

250 / (15 + 273) = V / (45 + 273)

V = 276

Rounded to two significant figures, the volume will be 280 mL.

When using the ideal gas law, remember to always use absolute units for temperature, like Kelvin.

Final answer:

The volume of oxygen, initially at 250 ml and 15 degrees Celsius, will increase to approximately 275.5 ml when the temperature is raised to 45 degrees Celsius, according to Charles's Law.

Explanation:

The volume of a quantity of oxygen gas changes with temperature, which can be explained by Charles's Law. This law states that at constant pressure, the volume of a gas is directly proportional to its absolute (Kelvin) temperature. To find the new volume at a higher temperature, you can use the formula V₁/T₁ = V₂/T₂, where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature.

To apply this to the student's question: The oxygen has an initial volume (V₁) of 250 ml at an initial temperature (T₁) of 15 degrees Celsius, which converts to 288.15 K (Celsius to Kelvin: C + 273.15). The final temperature (T₂) is 45 degrees Celsius or 318.15 K. Applying Charles's Law, we get:

250 ml / 288.15 K = V₂ / 318.15 K

Multiplying both sides by 318.15 K to solve for V₂ gives us:

V₂ = (250 ml * 318.15 K) / 288.15 K

V₂ ≈ 275.5 ml

So, when the temperature is raised to 45 degrees Celsius, the volume of oxygen will be approximately 275.5 ml.

A mixture contains 35.07 grams of carbon dioxide, 27.93 grams of water vapor, 12.64 grams of nitrogen, and 5.54 grams of helium. The total pressure of the system is 12 atm, What is the partial pressure of the helium?
A. 0.88 atm
B. 0.82 atm
C. 0.073 atm
D. 0.068 atm

Answers

Answer:

[tex]\boxed{\text{3.6 atm}}[/tex]

Explanation:

For this question, we must use Dalton's Law of Partial Pressures:

The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:

[tex]p = \chi p_{\text{tot}}[/tex]

1. Calculate the number of moles of each gas.

[tex]n_{\text{CO}_{2}} = \text{35.07 g} \times \dfrac{\text{1 mol}}{\text{44.01 g}} = \text{0.7969 mol}\\\\n_{\text{H}_{2}\text{O}} = \text{27.93 g} \times \dfrac{\text{1 mol}}{\text{18.02 g}} = \text{1.550 mol}\\\\n_{\text{N}_{2}} = \text{12.64 g} \times \dfrac{\text{1 mol}}{\text{14.01 g}} = \text{0.9022 mol}\\\\n_{\text{He}} = \text{5.54 g} \times \dfrac{\text{1 mol}}{\text{4.003 g}} = \text{1.384 mol}[/tex]

2. Calculate the total moles

[tex]n_{\text{tot}} = \text{(0.7969 + 1.550 + 0.9022 + 1.384) mol = 4.633 mol}[/tex]

3. Calculate the mole fraction of helium

[tex]\chi = \dfrac{n_\text{He}}{n_{\text{tot}}} = \dfrac{\text{1.384 mol}}{\text{4.633 mol}}= 0.2987[/tex]

4. Calculate the partial pressure of helium:

[tex]p_{\text{He}} = \chi_{\text{He}} p_{\text{tot}}= 0.2987 \times \text{12 atm} = \textbf{3.6 atm}\\\\p_{\text{He}} = \boxed{\textbf{3.6 atm}}[/tex]

Answer:

The partial pressure of He = 3.97 atm

Explanation:

Given:

Mass of CO2 = 35.07 g

Mass of H2O = 27.93 g

Mass of N2 = 12.64 g

Mass of He = 5.54 g

Total pressure P = 12 atm

To determine:

The partial pressure of He

Calculation:

Based on Dalton's law, the partial pressure of a gas can be expressed as a product of its mole fraction and the total pressure

[tex]P(gas)=X(gas)*P(total)-----(1)[/tex]

where X(gas) = mole fraction

[tex]X(gas)=\frac{moles(gas)}{moles(total)}----(2)[/tex]

[tex]Moles(CO2)=\frac{mass(CO2)}{mol.wt.(CO2)}=\frac{35.07g}{44g/mol}=0.7970[/tex]

[tex]Moles(H2O)=\frac{mass(H2O)}{mol.wt.(H2O)}=\frac{27.93g}{18g/mol}=1.552[/tex]

[tex]Moles(N2)=\frac{mass(N2)}{mol.wt.(N2)}=\frac{12.64g}{28g/mol}=0.4514[/tex]

[tex]Moles(He)=\frac{mass(He)}{at.wt.(He)}=\frac{5.54g}{4g/mol}=1.385[/tex]

Therefore:

Moles of He = 1.385

Total moles = 0.7970+1.552+0.4514+1.385 =4.188

Substituting the appropriate values in equation (1) gives:

[tex]P(He)=X(He)*P(total)[/tex]

[tex]P(He)=\frac{1.385}{4.188}*12 atm = 3.97 atm[/tex]

What is the charge on an atom after it loses an electron during the formation of a bond?

One positive charge
Two positive charges
Two negative charges
One negative charge

Answers

Answer:

One positive charge

Explanation:

In a neutral atom, the number of positive and negative particles are equal. This leaves the atom with a net charge of zero, 0.

When the number of protons in an atom is greater than the number of electrons, the atom becomes positively charged. When an atom loses an electron when a bond wants to form, it has a net positive charge.

The number of electrons lost or gained determines the charge.

Which of the following is a physical property of a substance? A. Hardness B. Flammability C. Reactivity D. Toxicity

Answers

Answer:

A. Hardness

Explanation:

Physical property is those that can be observed without changing the substance directly. This includes hardness, color, volume, etc.

Chemical property is observed by changing the chemical identity of the substance, for example, corrosion, oxidation, etc. Flammability, Reactivity, and Toxicity all fall under this category.

The physical property of a substance among the options is; Choice A: Hardness

The physical properties of a substance include properties which can be assessed about a substance without the substance going through any change.

On the other hand, chemical properties of a substance are properties which can only be assessed after the substance undergoes a chemical change..

The option Flammability can be assessed only upon ignition of the substance.

The option reactivity requires a chemical change to be measured.

The option Toxicity can only be assessed after testing with another entity(a biological specie perhaps).

Hence, Hardness is the only physical property of a substance among the options above.

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If 1.216g of cobalt metal react with 0.495g of oxygen gas what is empirical formula of the cobalt oxide product

Answers

First you divide each mass by the mass number of the element:

Cobalt        1.216 / 59 = 0.02

Oxygen      0.495 / 32 = 0.03

Then the result is divided by the lowest number:

Cobalt        0.02 / 0.02 = 1

Oxygen      0.03 / 0.02 = 1.5

After that you multiply with a number to obtain an integer number:

Cobalt        1 × 2 = 2

Oxygen      1.5 × 2 = 3

The empirical formula of the oxide:  

Co[tex]_{2}[/tex]O[tex]_{3}[/tex]

someone please help

Answers

Answer:

A - 8

B - 8

C - O

D - 26

E - 30

F - Fe

Explanation:

Use these things:

1. A = Z + N,

where A - mass number,

Z - atomic number,

N - number of neutrons

2. atomic number = number of protons

Which statements about oxygen and nitrogen are true? Select all the correct answers. a. They are both normally found as gases in the atmosphere. b. They can be either liquids or gases. c.They turn from gas to liquid at the same temperature. d.They can be changed from gases to liquids by heating them.

Answers

a. They are both normally found as gases in the atmosphere.  TRUE

That is correct, the oxygen and nitrogen are found in large quantities in the air around us.

b. They can be either liquids or gases. TRUE

Under certain temperatures any gas will transform into a liquid.

c.They turn from gas to liquid at the same temperature. FALSE

Oxygen it will pass into a liquid at -183 °C while nitrogen pass into a liquid at -195.8 °C.

d.They can be changed from gases to liquids by heating them. FALSE

The gases change to liquids by cooling them.

Final answer:

Oxygen and nitrogen are normally found as gases in the atmosphere, and they can be changed from gases to liquids by heating them.

Explanation:

Two statements are true about oxygen and nitrogen:

They are both normally found as gases in the atmosphere. This is true, as both oxygen and nitrogen are the two most abundant gases in Earth's atmosphere.They can be changed from gases to liquids by heating them. This is also true, as gases can be changed to liquids through the process of heating.

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How many atoms of carbon are combined to with 2.81 moles of hydrogen atoms in a sample of the compound ethane, C2H6?

Answers

Answer:

5.64×10²³ atoms C

Explanation:

Convert moles of H to moles of C:

2.81 mol H × (2 mol C / 6 mol H) = 0.937 mol C

Convert moles of C to atoms of C:

0.937 mol C × (6.02×10²³ atoms C / mol C) = 5.64×10²³ atoms C

What is bias in an experiment?
A. Something that makes the experiment more reliable

B. Something that makes the experimental results clearer

c. Something that helps the scientist analyze the data

D. Something that pushes the experimental results one way or another

Answers

Answer:

D.

Explanation:

It pushes the experimental results one way or another.  Less reliable.

Final answer:

In an experiment, bias refers to a factor that skews the results, pushing them in a particular direction and thus distorting the accuracy of the experiment's conclusions. Bias can stem from the experimental design, data collection, the researcher's subjective views, or systematic errors. Scientists work to minimize bias to ensure the validity and reliability of their results.

Explanation:

The term bias in an experiment refers to any factor that causes the results to deviate from the truth, distorting the conclusions drawn from the data. If we consider the given choices for what bias in an experiment is, the correct answer would be D. Something that pushes the experimental results one way or another. Experimental bias can come from a number of sources, such as the method of data collection, the experimental design, the researcher's expectations, or systemic errors. To maintain the integrity of an experiment, scientists aim to minimize bias by employing strategies such as random sampling, blinding, and standardization.

Biases can lead to a loss of validity, as they introduce systematic errors into the research that are not due to chance. By trying to disqualify the validity of their hypotheses, scientists work hard to remove bias from experiments, which strengthens the hypotheses that cannot be invalidated.

Bias can also come from subjective observations, which are based on personal feelings, as opposed to objective observations that are consistent regardless of who measures or observes them.

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