the sum of 3x^2+4x-2 and x^2-5x+3 is

Hey there!

There are a few ways to do this, but I'll give you the one I can explain best.

This is a right triangle. We know this because one of the angles is 90º.

The lengths of the sides of the right triangle can be represented by the following equation:

a² + b² = c²

We already have the values for a and c, c being the hypotenuse.

3² + b² = (√18)²

Let's square a and c.

9 + b² = 18

Subtract 9 from each side of the equation.

b² = 9

To find the final value for b, find the square root of each side of the equation.

b = 3

Your answer is 3, or option D.

Hope this helps!

The length of leg s in the right angled triangle given is 3.

A triangle is a three-sided polygon with three edges and three vertices. the sum of angles in a triangle is 180 degrees. A right angled triangle is a triangle in which of its angle measure 90 degrees.

Here, we have,

This is a right triangle. We know this because one of the angles is 90º.

The lengths of the sides of the right triangle can be represented by the following equation:

a² + b² = c²

We already have the values for a and c, c being the hypotenuse.

3² + b² = (√18)²

Let's square a and c.

9 + b² = 18

Subtract 9 from each side of the equation.

b² = 9

To find the final value for b, find the square root of each side of the equation.

b = 3

The answer is 3, or option D.

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Number line showing -20,0, 30 in attachment below.

the total bill before taxes and tip is $18.

To calculate the total bill before taxes and tip, we simply need to sum up the costs of the sausage and eggs breakfast and the ham omelet.

Cost of sausage and eggs breakfast = $8

Cost of ham omelet = $10

Total bill before taxes and tip = Cost of sausage and eggs breakfast + Cost of ham omelet

Total bill before taxes and tip = $8 + $10

Total bill before taxes and tip = $18

So, the total bill before taxes and tip is $18.

The probable question maybe:

In a restaurant You order the sausage and eggs breakfast That costs $8, and your friend orders the ham omelet That costs $10. How much is the bill before the taxes and tip?

Answer:

12, 18, 24, 107

Step-by-step explanation:

Our inequality is

2x+7 ≤ 3x-5

First we will subtract 3x from each side:

2x+7-3x ≤ 3x-5-3x

-1x+7 ≤ -5

Subtract 7 from each side:

-1x+7-7 ≤ -5-7

-1x ≤ -12

Divide both sides by -1:

-1x/-1 ≤ -12/-1

When we multiply or divide an inequality by a negative number, we flip the inequality symbol:

x ≥ 12

We want numbers that are equal to or larger than 12; this leaves us with

12, 18, 24, and 107.

ANSWER

The correct answer is option C

EXPLANATION

The graph of [tex]f(x)=tan^{-1}(x)[/tex] is shown in the attachment.

You can see clearly that as

[tex]x\rightarrow \infty, f(x)\rightarrow \frac{\pi}{2}[/tex]

and as

[tex]x\rightarrow -\infty, f(x)\rightarrow -\frac{\pi}{2}[/tex]

These are are actually the two horizontal asymptotes to the given function.

Answer:

The answer is C I just took the test.

Answer:

1: 30

2: 90

Step-by-step explanation:

Answer:

In 12 minutes, She can answer 30 math questions.

In 36 minutes, She can answer 90 math questions.

Step-by-step explanation:

Jill can answer 50 math questions every 20 minutes.

1)

How many questions can she answer in 12 minutes

Let (x) represent the number of questions she can answer in 12 minutes:

So, if 50 math question = 20 minutes

   and (x) math question = 12 minutes

To  solve for (x); we have:

(x) × 20 minutes = 50 math question × 12 minutes

(x)  = [tex]\frac{50*12}{20}[/tex]

(x)  = [tex]\frac{600}{20}[/tex]

(x)  = 30 math questions

∴  In 12 minutes, She can answer 30 math questions.

2)

How many math questions can she answer in 36 minutes?

Let (y) represent the number of questions she can answer in 36 minutes:

So, if 50 math question = 20 minutes

   and (y) math question = 36 minutes

To  solve for (y); we have:

(y) × 20 minutes = 50 math question × 36 minutes

(y) = [tex]\frac{50*36}{20}[/tex]

(y) = [tex]\frac{1800}{20}[/tex]

(y) = 90 math questions.

∴  In 36 minutes, She can answer 90 math questions.

Answer:

Option A is correct.

Step-by-step explanation:

Let the full price of the wallet be represented by = x

Total amount that Nathan paid for the wallet = $17.67

Discount percentage = 5% or 0.05 = 0.05x (5% of full price)

So, equation becomes: full price - discount price = 17.67

[tex]x-0.05x=17.67[/tex]

[tex]0.95x=17.67[/tex]

x = $18.60

Therefore, the full price of the wallet is $18.60.

We can also check this by taking out 5% of 18.60

[tex]0.05\times18.60=0.93[/tex]

And[tex]18.60-0.93=17.67[/tex]

So, option A is correct.

the square root of 8 is an irrational number

Root 8 is irrational as 8 = 2×2×2

Root of 8 is 2 root 2

0 is whole no.

-8/4 = 2 is an integer

49/7=7 is an integer

Rest .333333 and 9.23456 are rational as .3333 is non terminating repeating and 9.23456 is terminating

This doesn't give any information

Your question is very vague. More info?

Answer:(6,-4)

Step-by-step explanation:

6x+7y=4x+4y

If (?,-4)

So we are solving for x. Substitute the y with -4.abd solve.

6x+7(-4)=4x+4(-4)

Multiply 7(-4) on left side and 4(-4) on right side.

6x-28=4x-16

Subtract 4x both sides to get x term on left side

6x-4x-28= -16

Now add 28 to both sides to move to the right side because you want to keep x on left side.

6x-4x=28-16

2x= 28-16

Subtract 28 from 16

2x= 12

Divide 2 to both sides

X=12/2

Solve 12÷2=6

X=6

Answer:

[tex]S=\left \{ \left ( 6,-4 \right ) \right \}[/tex]

Step-by-step explanation:

1) In this equation we have one solution already given for y. y=-4. Let's make it one simplest equation:

[tex]6x+7y=4x+4y\\6x-4x=-7y+4y\Rightarrow 2x=-3y[/tex]

Now, plugging in the y value already given:

2)[tex]2x=-3(-4)\Rightarrow 2x=12\Rightarrow x=6[/tex]

[tex]S=\left \{ \left ( 6,-4 \right ) \right \}[/tex]

Answer:

The correct option is:   A.  [tex]0=x^2+3x+2[/tex]

Step-by-step explanation:

Quadratic formula:  [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

After substituting the values of a, b and c into the formula, Ramiya's equation is:   [tex]x=\frac{-3\pm\sqrt{3^2-4(1)(2)}}{2(1)}[/tex]

Comparing the above equation with the quadratic formula, we will get........

[tex]2a= 2(1)\\ a=1\\ \\ -b=-3\\ b=3\\ \\ 4ac=4(1)(2)\\ 4(1)c=4(1)(2)\\ c=2[/tex]

The standard form of any quadratic equation is:  [tex]ax^2+bx+c=0[/tex]

So, Ramiya’s quadratic equation will be:  [tex]1x^2+3x+2=0[/tex] or,  [tex]0=x^2+3x+2[/tex]

The Ramya's quadratic equation is 0 = x^2 + 3x + 2 option (A) is correct.

Any equation of the form [tex]\rm ax^2+bx+c=0[/tex]  where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

The quadratic formula is:

[tex]\rm x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]

Ramiya equation is:

[tex]\rm x=\frac{-3\pm \sqrt{3^2-4(1)(2)} }{2(1)}[/tex]

Comparing the Ramiya equation to the quadratic formula, we get:

-b = -3 ⇒ b = 3

2a = 2(1) ⇒ a = 1

4ac = 4(1)(2) ⇒ c = 2

Put these values in the standard equation, we get:

[tex]\rm x^2+3x+2=0[/tex]  or

[tex]0=\rm x^2+3x+2[/tex]

Thus, the Ramya's quadratic equation is 0 = x^2 + 3x + 2 option (A) is correct.

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The ratio 9:7 gives you following statement:

Then the probability that Carl will lose is

[tex]Pr(\text{Carl will lose})=\dfrac{7}{16}.[/tex]

Answer: [tex]Pr(\text{Carl will lose})=\dfrac{7}{16}.[/tex]

Answer:

(20,5) is NOT a solution of the equation [tex]6x+10y=150[/tex].

The point (20,5) implies that there are 20 small tables and 5 large tables.

Step-by-step explanation:

We have been given that a catering company is expecting 150 people to attend the wedding. There are two types of tables, ones which can fit 6 people and ones which can fit 10 people.

If there are x tables which can fit 6 people and there are y tables which can fit 10 people, we can express the total number of people that can fit on all available tables as: [tex]6x+10y[/tex].

Since there are total 150 people expected in the wedding, the equation can be framed as: [tex]6x+10y=150[/tex].

Let us check if the point (20,5) is a solution of the equation.

[tex]6*20+10*5=150[/tex]

[tex]120+50=150[/tex]

[tex]170=150[/tex]

Since we get a false statement, therefore, (20,5) is NOT a solution of the equation [tex]6x+10y=150[/tex].

The point (20,5) implies that there are 20 small tables and 5 large tables.

To determine if a point is a solution to an equation, substitute the values into the equation. The point (20,5) in the context of a catering company setting up tables represents 20 tables of 6 seats and 5 tables of 10 seats. However, this point is not a solution to the equation 6x + 10y = 150 because substituting these values does not make the equation true.

The point (20,5) in the context of this question represents the numbers of 6-seat and 10-seat tables the catering company needs to set up. To determine if the point (20,5) is a solution to the equation 6x+10y=150, you can substitute the first value of the ordered pair into the equation for x, and the second value for y.

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h(x) = -5x² + 15x - 3

It's a quadratic function. The domain of quadratic function is the set of all real numbers.

Therefore

[tex]D=\mathbb{R}[/tex]-all real numbers.

The scientific notation of the given 0.0123 will be 123 x 10^{-4}.

The number is written in the form  a x 10^b.

The number b shows the order, which is the most important figure for which scientific notation is used. It tells us how much order large or small a value is in powers of 10.

We can for a time, ignore the value of 'a' for two comparable quantities and only compare their orders(this type of comparison is useful when difference is too big, like size of human to size of a star etc sort of comparisons).

Scientific notations have some of the profits as Better readability due to compact representation.

Its value in terms of power of 10 is known, which helps in easy comparison of quantities differing by a large value.

The scientific notation of the given 0.0123 will be 123 x 10^{-4}.

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First, let's calculate the total cost for food. We know that we have 20 people to feed, and it costs $5 to provide food for each person. Therefore, we multiply the number of people by the cost per person to get the total cost for food. That would be:

20 people * $5/person = $100

So, the total cost for food is $100.

Next, let's calculate the total cost for the games. We're assuming that each person is playing x number of games, and that each game costs $1 to play. Therefore, we multiply the number of people by the cost per game and the number of games each person plays to find the total cost for games:

20 people * $1/game * x games = $20x

So, the total cost for the games depends on the number of games that each person plays.

If we want to find out the total cost of the party, we need to add the total cost for food and the total cost for games. This can be represented as:

$100 + $20x

This means the total cost of the party will be $100 plus $20 times the number of games each person plays. The exact total cost will depend on the value of x, i.e., the number of games each person plays.

( 2 + 76 ÷ 1 + 9 ) + 4 - 3 x 9

64

Answer:

36 centimeters.

Step-by-step explanation:

1. To solve this problem you must find the Greatest common factor.

2. List the prime factor of 108 and 72:

[tex]108:(2)(2)(3)(3)(3)=(2^{2})(3^{3})\\ 72:(2)(2)(2)(3)(3)=(2^{3})(3^{2})[/tex]

3. Now, you must choose the common prime numbers with the lowest exponents and multiply them:

[tex](2^{2})(3^{2})=(4)(9)=36[/tex]

Answer: He needs 36 cm to make the shelves.

Step-by-step explanation:

Since we have given that

Length of first wood = 108 cm

Length of second wood = 72 cm

We need to find the greatest length so that he can make the shelves.

Greatest length = h.c.f. of 108 and 72 { 36 cm.

Hence, he needs 36 cm to make the shelves.

Answer:

4.)60

5.)about 13

6.)58

Step-by-step explanation:

1.4 as a fraction is 1 4/10 (simplified to 1 2/5).

[tex]1.4=\dfrac{14}{10}=\dfrac{14:2}{10:2}=\dfrac{7}{5}[/tex]

The second answer is correct since the associative property has the do with how you use parenthesis.

5/8th of the complete project is finished by you and your friend.

A fraction is some part of a total amount given.Fractions are of two types one is proper fraction and other is improper fraction.

According to the given question You finish 3/8 of the project.

Your friend finishes 1/4 of the project.

∴ The total fraction of the project that is finished will be the sum of out total work which is

= 3/8 + 1/4.

Now we have to take LCM of the denominators which is 8.

So,

3/8 + 1/4.

= (3 + 2)/8.

= 5/8.

So, 5/8th of the project is finished by both of us.

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-3a-2b

-3 times -4= 12

-2 times -3= 6

12+6=18

hope this helps

also can u give brainy

Plug in a=-4 and b=-3 into -3a-2b

-3(-4) -2(-3)

= 12 + 6

= 18

Answer

18

The answer to this question is 290

The number has 2 hundreds so 200

The tens place is 9 more than the ones place so its 9

The last number is 0

We need 10 small sized tables and 9 large sized tables to fit 150 people.

Two or more expressions connected with an equal sign is called as Equation.

We have been given that a catering company is expecting 150 people to attend the wedding.

There are two  kinds of tables,

The first kind of tables are small tables in which six people can be fitted.

The second kind of table are big tables in which ten people can be fitted.

Let us form a linear equation by considering  x as the tables which can fit 6 people and y as the tables which can fit 10 people,

The total number of people that can fit on all available tables as:

6x+10y

If there are total 150 people expected in the wedding, then equation can be framed as:

6x+10y=150

Now let us take x as 10.

Then

6(10)+10y=150

60+10y=150

10y=150-60

10y=90

y=9

Therefore, you'd need 10 small sized tables and 9 large sized tables to fit 150 people.

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120 is the answer, I may be wrong.

The perimeter of a shape is the sum of all it sides.

The perimeter of the square is [tex]16x - 4[/tex]

Given that:

[tex]Length = 4x - 1[/tex]

The perimeter (P) of the square is:

[tex]P = 4 \times Length[/tex]

So, we have:

[tex]P = 4 \times (4x -1)[/tex]

Open brackets

[tex]P = 16x - 4[/tex]

Hence, the perimeter of the square is 16x - 4

See attachment for the image of the square

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