The surface gravity on jupiter is about three times as much as the surface gravity on earth. this means

Answer: The correct answer for the fill in the blank is B.  Mental age involves calculating the chronological age at which a person functions.

Mental age corresponds to the attainment of mental abilities by an individual. It is related to intelligence and based on the chronological age ( calculated from the date on which individual was born) at which any average individual attains the same level of mental abilities.

Therefore, mental age involves calculation of the chronological age at which a person functions and attains mental abilities.

Final answer:

The capture theory suggests the Moon was a passing asteroid that Earth's gravity pulled into orbit, but this theory is challenged by the Moon's orbit and compositional similarities to Earth. The widely accepted explanation is the giant impact hypothesis.

Explanation:

The theory that proposes the Moon was a passing asteroid pulled into orbit by Earth's gravity is known as the capture theory. However, there are significant challenges with this theory, including the need for a substantial loss of energy for a body to achieve orbit, which is difficult to explain for an object of the Moon's size. Moreover, the capture theory does not account for the nearly circular orbit of our Moon, nor does it explain the compositional similarities between the Earth and the Moon, particularly regarding isotopes of oxygen. The currently accepted explanation for the Moon's origin favoring these evidences is the giant impact hypothesis, which suggests the Moon formed from the debris of a collision between Earth and a Mars-sized body.

Here we’re solving a problem where a ball is projected horizontally from a height of h=1.8 m with a horizontal velocity of Vx. At the impact with the ground, the ball has travelled 0.5 m horizontally.

Solution:

We will need kinematic equations

V1^2-V0^2=2aS ………………….(1)

S=V0*t + (1/2)at^2………………..(2)

Where

S=displacement (distance), m

V0=initial velocity, m/s

V1=final velocity, m/s

a=acceleration, m/s^2

t=time, seconds

At the point of impact, there a vertical velocity (downwards) of Vy.

The horizontal velocity Vx remains constant since projection till impact.

Vertical velocity Vy:

Using equation (1),

V0=0 (projected horizontally, so vertical velocity=0)

S=1.8 m (downwards)

a=9.81 m/s^2 (acceleration due to gravity, downwards)

=>

Vy=V1=sqrt(V0^2+2*a*S)=sqrt90+2*9.81*1.8)=5.9427

Horizontal velocity, Vx:

ball travelled 0.5m in time t it took ball to hit ground.

Using equation (2),

S=1.8m

V0=0

a=9.81

=>

1.8=0*t+(1/2)(9.81)t^2

Solve for t

t=sqrt(2*1.8/9.81)=0.60578 s

Horizontal velocity, Vx = 0.5/0.60578 = 0.82538 s

Speed of ball on impact is the vectorial sum of Vx and Vy:

Speed = sqrt(Vx^2+Vy^2)=sqrt(5.9427^2+0.82538^2)=5.99977 m/s, say 6.0 m/s.

Answer: 0.82

On ED2020

Given second-harmonic frequencies and added mass, solve [tex]\(1.5^2 = \frac{m + 1.2}{m}\) to find \( m = 0.96 \)[/tex] kg.

To find the mass [tex]\( m \)[/tex] that results in the given second-harmonic frequencies, we will use the formula for the frequency of standing waves on a wire under tension.

The second-harmonic frequency for a wire is given by:

[tex]\[f = \frac{2}{L} \sqrt{\frac{T}{\mu}}\][/tex]

where:

- [tex]\( f \)[/tex] is the frequency,

- [tex]\( L \)[/tex] is the length of the wire,

- [tex]\( T \)[/tex] is the tension in the wire,

- [tex]\( \mu \)[/tex] is the linear mass density of the wire.

The tension [tex]\( T \)[/tex] in the wire is due to the hanging mass [tex]\( m \)[/tex] and is given by:

[tex]\[T = mg\][/tex]

where [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]).

The second-harmonic frequency is given, so for the initial mass [tex]\( m \)[/tex]:

[tex]\[f_1 = 180 \, \text{Hz}\][/tex]

[tex]\[180 = \frac{2}{L} \sqrt{\frac{mg}{\mu}}\][/tex]

When an additional 1.2 kg is added to the mass, the new mass becomes [tex]\( m + 1.2 \)[/tex] kg and the second-harmonic frequency becomes:

[tex]\[f_2 = 270 \, \text{Hz}\][/tex]

[tex]\[270 = \frac{2}{L} \sqrt{\frac{(m + 1.2)g}{\mu}}\][/tex]

To find [tex]\( m \)[/tex], we will set up the ratio of the two frequencies and solve for [tex]\( m \)[/tex]:

[tex]\[\frac{f_2}{f_1} = \frac{270}{180} = 1.5\][/tex]

Using the ratio of the frequencies:

[tex]\[\frac{270}{180} = \frac{\sqrt{\frac{(m + 1.2)g}{\mu}}}{\sqrt{\frac{mg}{\mu}}}\][/tex]

Squaring both sides to eliminate the square roots:

[tex]\[\left(\frac{270}{180}\right)^2 = \frac{(m + 1.2)g}{mg}\][/tex]

[tex]\[\left(1.5\right)^2 = \frac{(m + 1.2)}{m}\][/tex]

[tex]\[2.25 = \frac{m + 1.2}{m}\][/tex]

Multiplying both sides by [tex]\( m \)[/tex]:

[tex]\[2.25m = m + 1.2\][/tex]

Solving for [tex]\( m \)[/tex]:

[tex]\[2.25m - m = 1.2\][/tex]

[tex]\[1.25m = 1.2\][/tex]

[tex]\[m = \frac{1.2}{1.25}\][/tex]

[tex]\[m = 0.96 \, \text{kg}\][/tex]

Therefore, the mass [tex]\( m \)[/tex] is [tex]\( 0.96 \)[/tex] kg.

Answer:

B.A circuit that has little or no resistance

Explanation: a circuit is said to be short circuit if it has little or no resistance.

Shirt circuiting is very dangerous and can be done intentionally or unintended

D could also be correct if an amount of wire is ought to be used and you use a little wire. Knowing that wires have internal resistance too.

It could lead to short circuit

To find the net force on the donkey, we decompose the angled forces into horizontal and vertical components and add them accordingly. Since the vertical components cancel out, the net force is the sum of Jack's force and the combined horizontal components from Jill and Jane, resulting in a net force of 149 N ahead.

The problem presented requires an analysis of forces and vector addition to calculate the net force exerted on a donkey by three different people. We have Jack applying 97.9 N directly ahead, Jill pulling with 72.7 N at a 45° angle to the left, and Jane pulling with 145 N at a 45° angle to the right. To solve this, we must break down Jill's and Jane's forces into their horizontal and vertical components and then combine these with Jack's force.

Jill's horizontal component: 72.7 N × cos(45°) = 51.4 N to the left

Jill's vertical component: 72.7 N × sin(45°) = 51.4 N up

Jane's horizontal component: 145 N × cos(45°) = 102.5 N to the right

Jane's vertical component: 145 N × sin(45°) = 102.5 N up

Now we can subtract Jill's horizontal component from Jane's because they are in opposite directions: 102.5 N (Jane's right) - 51.4 N (Jill's left) = 51.1 N to the right. The vertical components from Jill and Jane will cancel each other since the donkey is stubborn and not moving vertically, hence we are left with only the horizontal forces to combine with Jack's force.

The total horizontal force exerted by Jack and combined with the net horizontal force from Jill and Jane is 97.9 N (Jack's force)+ 51.1 N (net horizontal force) = 149 N.

Thus, the magnitude of the net force the people exert on the donkey is 149 N directly ahead, assuming no vertical movement.

The expression for the velocity of a rider on the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex] is given by:

[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]

To find the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex], we can use kinematic equations for rotational motion.

The kinematic equation relating angular displacement [tex](\( \delta \theta \))[/tex], initial angular velocity [tex](\( \omega_0 \))[/tex], angular acceleration [tex](\( \alpha \))[/tex], and time [tex](\( t \))[/tex] is:

[tex]\[ \delta \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \][/tex]

Since the Ferris wheel starts from rest, [tex]\( \omega_0 = 0 \)[/tex], so the equation simplifies to:

[tex]\[ \delta \theta = \frac{1}{2} \alpha t^2 \][/tex]

We're interested in finding the angular velocity [tex](\( \omega \))[/tex] after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex]. To find [tex]\( \omega \)[/tex], we can use the kinematic equation relating angular displacement, initial angular velocity, angular acceleration, and final angular velocity:

[tex]\[ \omega^2 = \omega_0^2 + 2 \alpha \delta \theta \][/tex]

Since [tex]\( \omega_0 = 0 \)[/tex], this equation simplifies to:

[tex]\[ \omega^2 = 2 \alpha \delta \theta \][/tex]

Taking the square root of both sides:

[tex]\[ \omega = \sqrt{2 \alpha \delta \theta} \][/tex]

This gives us the angular velocity of the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex].

However, to find the velocity of a rider at a particular point on the Ferris wheel, we need to convert this angular velocity to linear velocity. The linear velocity [tex](\( v \))[/tex] is related to the angular velocity [tex](\( \omega \))[/tex] by the equation:

[tex]\[ v = r \omega \][/tex]

Where:

- v is the linear velocity.

- r is the radius of the Ferris wheel.

So, substituting the expression for [tex]\( \omega \)[/tex] into this equation:

[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]

This is the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex].

Answer: The correct option is Option A.

Explanation:

Atmosphere is defined as the layer of gases which form an envelope around a planet.

Venus is the second and Neptune is the last planet of our solar system.

Venus's atmosphere mainly consists of carbon dioxide with trace amounts of nitrogen, argon , helium and neon.

Neptune's atmosphere mainly consists of helium and hydrogen with 2.5 to 3% of methane gas in it.

From the above information, the correct answer comes out to be Option A.

If you double the velocity of an object, its momentum doubles. But for the same increase in velocity, the kinetic energy increases four times.

Explanation:

We can prove this statement by looking at the formulas for the momentum and kinetic energy of an object.

Momentum: [tex]p=mv[/tex]

Kinetic energy: [tex]K=\frac{1}{2}mv^2[/tex]

where m is the mass of the object and v its velocity.

From the two formulas, we see that the momentum is directly proportional to the velocity, while the kinetic energy is proportional to the square of the velocity. Therefore, if we double the velocity, the momentum increases by a factor 2, while the kinetic energy increases by a factor [tex]2^2=4[/tex].

Momentum is directly proportional to an object's mass and velocity, while kinetic energy is directly proportional to an object's mass and the square of its velocity. When velocity is doubled, kinetic energy increases four times, while momentum doubles.

Momentum and kinetic energy are both physical quantities that describe the motion of an object. Momentum is directly proportional to an object's mass and velocity, while kinetic energy is directly proportional to an object's mass and the square of its velocity.

In terms of velocity, if you double the velocity of an object, its kinetic energy increases four times (K = (1/2)mv²), but its momentum doubles. This is because momentum is equal to mass times velocity (p = mv), so when velocity doubles, momentum also doubles. However, since kinetic energy is proportional to the square of velocity, when velocity doubles, kinetic energy increases by a factor of four.

Therefore, the statement that best compares momentum and kinetic energy is: If you double the velocity of an object, its kinetic energy increases four times. But for the same increase in velocity, the momentum doubles.

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The answer i got was 50 miles per hour

Answer:

C) TURBINE

Explanation:

As we know that wind powered system is used to generate electricity using wind energy.

Here wind powered system has different components

1) Blades: these are long plates connected to the turbine. when these plates encountered high speed wind they start rotating on its axle.

This will produce kinetic energy in the axle which is transferred to the turbine.

2) Turbine: It is used to convert mechanical energy of the wind into useful electrical energy.

This is continuously driven by the kinetic energy of wind

So here correct answer is

C) Turbine

the 2 magnetic fields repel eachother

for the whole quiz of intro to psychology ;)

1. Stimulus--> Physiological changes--> emotion

2. Darwin

3.You experience physiological changes and a feeling of fear simultaneously

4. Cannon-Bard theory

5. James-Lange theory

6. David G. Myers

7. Happiness

8. Acting happy

9. negative and dysfunctional aspects of emotion and behavior.

10. an aspect of consciousness characterized by a certain physical arousal involving facial and bodily changes, brain activation, and tendencies toward action, all shaped by cultural rules.

I do this cause i wished someone did this for me. So stress no more from falling behind and Ace that quiz. your welcome comrades

-10/11/18

According to the Cannon-Bard theory, physiological changes and the feeling of fear occur simultaneously.

The Cannon–Bard theory is also called the thalamic theory of emotion which is related to the thalamus. It is a part of the brain that deals with sensory and motor functions. The main concepts of this theory are that emotional expression arises from the function of hypothalamic structures while emotional feeling arises from stimulation of the dorsal thalamus.

This theory states that the lower part of the brain controls the experience of emotion while the upper part of the brain, called the cortex, controls the expression of emotion. These two parts of the brain react together

In this theory, stimulating events trigger emotions and physiological responses that occur at the same time. For example, seeing a bear in the woods can cause both a feeling of fear (an emotional response) and a faster heartbeat (a physical response).

Thus, according to the Cannon-Bard theory, physiological changes and the feeling of fear occur simultaneously.

Learn more about Cannon-Bard theory, here:

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B.What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"

Solution:

A) A charge q under an electric field of intensity E will experience a force F  equal to:

[tex]F=qE[/tex]

In our problem we have [tex]q=-2.5 nC=-2.5\cdot 10^{-9} C[/tex] and [tex]F=18 nN = 18 \cdot 10^{-9} N[/tex], so we can find the magnitude of the electric field:

[tex]E= \frac{F}{q}= \frac{18\cdot 10^{-9}N}{2.5\cdot 10^{-9}C}=7.2 V/m [/tex]

The charge is negative, therefore it moves against the direction of the field lines. If the force is pushing down the charge, then the electric field lines go upward.

B) The proton charge is equal to

[tex]e=1.6\cdot 10^{-19} C[/tex]

Therefore, the magnitude of the force acting on the proton will be

[tex]F=eE=1.6\cdot 10^{-19} C \cdot 7.2 V/m=1.15 \cdot 10^{-18} N[/tex]

And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.

a dense substance that is hard and incompressible

The resistance of the radio circuit is 16.7 kΩ.

To calculate the resistance of the radio circuit when it operates at 3.0 volts and draws a current of 1.8 x 10-4 amperes, we can use Ohm's Law, which states that Resistance (R) equals Voltage (V) divided by Current (I), or R = V/I. Plugging in the given values, R = 3.0 V / (1.8 x 10-4 A), we find that the resistance is approximately 16,666.67 Ω, or 16.7 kΩ when rounded to three significant digits. When dealing with electrical circuits, it is important to understand concepts like resistance, voltage, and current, as they are fundamental to analyzing and predicting the behavior of the circuit.

Answer:

A

Explanation:

If the distance between them is increased to 3d then the force of repulsion between them is,  It will be one-ninth the original force

The force of repulsion between two identical charges is given by Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:

F = k x (q₁ x q₂) / d²

where F is the force of repulsion, q₁ and q₂ are the magnitudes of the charges, d is the distance between the charges, and k is the Coulomb constant.

When the distance between the charges is increased to 3d,

the force of repulsion will decrease,

since the denominator in the above equation will increase.

Specifically, the force will become one-ninth the original force, since the square of 3 is 9.

So the answer to the question is (A) It will be one-ninth the original force.

To know more about electric force check:

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Newton's universal law of gravitation states that the force that makes an apple fall and the force that keeps the moon in its orbit are both caused by gravity. The force of gravity is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Newton's universal law of gravitation states that every object in the universe attracts every other object with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This means that the force that makes an apple fall and the force that keeps the moon in its orbit are both caused by gravity. In both cases, the force of gravity is acting between two bodies and is dependent on their masses and the distance between them.

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Erosion removes rocks and soil by wind, water, ice, and gravity.

When the light hits an opaque object, none of the light will pass through the object. Hence, option B is correct.

Electromagnetic radiation that the human eye can detect as light. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than roughly 1 1011 meter, electromagnetic radiation occurs throughout a very broad range of wavelengths.

The wavelengths of light that are visible to humans fall into a very small range within that wide spectrum, ranging from about 700 nanometers for red light to roughly 400 nm for violet light.

Infrared and ultraviolet are two spectral bands that are close to the visible region and are repeatedly alluded to as light as well.

Anything that doesn't let any light through is opaque. Instances of opaque materials include concrete, wood, and metal.

To know more about Light:

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There are two types of planets as classifieds by astronomers in our solar system.

The classification is based on the asteroid belt present in our solar system.

These are named as - [1] inner planets

                                    [2]outer planets

The inner planets are the planets which are  very close to the sun and present before the asteroid belt starting from sun.

The outer planets which are present after the asteroid belt are Jupiter,Uranus,Neptune and Pluto[if we consider Pluto as a planet]

There are four planets considered as inner planets. These are arranged from closest to the farthest as Mercury,Venus,Earth ad Mars.

The distance of Mercury from the sun is 57.91 million km

The distance of Venus from sun is 108.2 million km

The distance of Earth from sun  is 149.6 million km

Finally the distance of Mars from the sun is 227.9 million km