Answer:
The correct answer is A. The hidden value of the overflow style keeps the element at the specified height and width, but cuts off excess content.
Explanation:
Hidden variable theories are interpretations of quantum physics, which means that a quantum mechanical system cannot be fully described by a wave function, but at least one additional variable is needed.
Hidden values would give unambiguous value to the properties of a quantum mechanical particle - position, amount of motion and energy - whether observed or not. During the evolution of quantum physics, hidden variables were advocated by, among others, Albert Einstein, but today, especially after the presentation of Bell's theorem, they have weak support among physicists. The only such theory that is still minimally shown with interest is Bohemian mechanics, which uses non-local hidden variables.
What is the weight of a 45 kg box?
Final answer:
The weight of a 45 kg box, assuming standard Earth gravity, would be 441.45 Newtons, which is calculated by multiplying the mass by the acceleration due to gravity.
Explanation:
The weight of an object is the force due to gravity acting on its mass. It is calculated using the equation Weight = Mass × Gravity. The mass of the box is given as 45 kg, and assuming standard Earth gravity which is approximately 9.81 m/s2, the weight can be calculated as follows:
Weight = 45 kg × 9.81 m/s2 = 441.45 Newtons (N)
Therefore, the weight of a 45 kg box would be 441.45 Newtons under Earth's gravity.
Which statement about work and power correctly describes an automobile race?
The car do different amount of work depending on how fast they finish.
The car that finishes last has the lowest
Power
The car with the greatest power travels the greatest distance
The car do different amounts of work depending on their power.
Answer: "The car that finishes last has the lowest power."
How many Neutrons does this atom have?
4
6
10
14
As we can see in the given figure there are four spheres of blue color which are having + sign
They represents protons inside the nucleus
And the other red spheres have no sign so these are the neutral one which we say as neutrons
SO here in this figure the atom must have 6 neutrons
so correct answer will be
N = 6
Without inertia, how would an object that is experiencing a centripetal force behave?
It would move in a line away from the circle’s center.
It would move in a line toward the circle’s center.
It would move in a curved, circular path.
It would move in a line tangent to the circular path.
B. It would move in a line toward the circle’s center.
Explanation:
got it right on edge 2022
When a temperature of a pot in a kiln is 1 , 200 ∘ 1,200∘f, an artist turns off the heat and leaves the pot to cool at a controlled rate of 81 ∘ 81∘f per hour. express the temperature of the pot in degrees celsius as a function of the time t t (in hours) since the kiln was turned off?
Final answer:
The temperature of the pot in Celsius as a function of time since the kiln was turned off is given by the linear equation T(t) = 648.89 - 45t.
Explanation:
When a temperature of a pot in a kiln is 1,200°F, and the artist turns off the heat, allowing the pot to cool at a controlled rate of 81°F per hour, the temperature of the pot in degrees Celsius as a function of the time t (in hours) can be calculated using two steps. First, convert the starting temperature from Fahrenheit to Celsius using the formula C = °(F - 32) ÷ 1.8. For 1,200°F, this converts to approximately 648.89°C. Second, since the cooling rate is 81°F per hour, which equals 45°C per hour (using the conversion factor 1°F = 5/9°C), the temperature as a function of time t in Celsius is given by the linear equation T(t) = 648.89 - 45t.
To get an spaceship into orbit, it has to move
about as fast as the speed of sound
about as fast as the speed of light
about 18,000 miles per hour
there is no minimum speed for orbital motion
"which of newton's laws could we have used to predict that the forces in parts a and b are equal and opposite?"
Newton's third law of motion, stating every action has an equal and opposite reaction, allows us to predict equal and opposite forces in different parts of a system. The interaction of these forces depends on the chosen system of interest and whether the forces are internal or external to that system.
The Newton's third law of motion is the principle we could use to predict that the forces in parts a and b are equal and opposite.
This law states that for every action there is an equal and opposite reaction, which means that whenever one body exerts a force on another, the second body exerts a force that is equal in magnitude but opposite in direction on the first body.
The choice of the "system of interest" is crucial as it affects whether the action-reaction forces are internal and cancel each other out, or if they are external and do not cancel. If both bodies are included in the system, the forces are internal and cancel because they are equal and opposite.
However, if only one body is chosen as the system of interest, the force exerted by the other body is considered external, and therefore, it does not cancel out within the system being analyzed.
A negatively charged object is located in a region of space where the electric field is uniform and points due north. the object may move a set distance d to the north, east, or south. rank the three possible movements by the change in electric potential energy (ue) of the object. rank from greatest increase to decrease in ue.
(a) There will be an increase in the potential energy when the charge moves North.
(b) The variation of potential energy will be zero when the charge is moving to the east.
(c)There is a loss in potential energy when a charge moves to the South.
What will be the potential energy of the charge at different directions?(a) The largest increase in potential energy occurs when the charge is moving north. This is because the charge is negative,
so it acquires potential energy when moving in the same direction of the field (vice versa, a positive charge when moving in the direction of the field loses potential energy converting it into kinetic energy).
The amount of potential energy gained is equal to the product of the charge and the distance covered:
[tex]\rm \Delta PE=qD[/tex]
(b) The second-largest increase is when the charge is moving east. In this case, actually, the variation of potential energy is zero.
This is because the charge is moving perpendicular to the field, and so it is moving along points with the same potential. Therefore, in this case, the variation of potential energy is zero:
[tex]\rm \Delta PE=0[/tex]
(c) Finally, when the charge is moving south, it loses potential energy. This is because it is moving against the electric field,
since it is a negative charge, in this direction it loses potential energy converting it into kinetic energy. Therefore, in this case
[tex]\rm \Delta PE=-qD[/tex]
Thus
(a) There will be an increase in the potential energy when the charge moves North.
(b) The variation of potential energy will be zero when the charge is moving to the east.
(c)There is a loss in potential energy when a charge moves to the South.
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Brad is working on a speed problem in physics class. The problem tells him that a girl runs from her house to the park 0.05 km away in 10 s. Brad calculates that her speed is 0.005 m/s. Is he correct? If not, explain the flaw or flaws in his problem solving process.
Answer:
He is incorrect! Her speed was 5m/s.
Explanation:
For calculating the speed, first we shall remember that:
[tex]v=\dfrac{d}{t}[/tex]
Where [tex]v[/tex] is the speed, [tex]d[/tex] is the distance travelled and, [tex]t[/tex] is the time it takes to travel distance [tex]d[/tex].
So one migth think that velocity can be easely compute:
[tex]v=\dfrac{0.05}{10}[/tex]
[tex]v=0.005\dfrac{m}{s}[/tex]
Be carefull, he does not make a proper dimensional analisis!
Before computing the speed we must know in what dimensions our values are.
[tex]d=0.05km[/tex], distances is measure in Kilometers.
[tex]t=10s[/tex], time is measure in seconds.
If we want our speed to be in [tex]m/s[/tex], first we need to be sure that our values are expressed in meters and seconds.
Time is already expressed in seconds, distance is not in Kilometers.
So
[tex]0.05Km=50m[/tex],
now we can compute the speed:
[tex]v=\dfrac{d}{t}[/tex]
[tex]v=\dfrac{50m}{10s}[/tex]
[tex]v=\5dfrac{m}{s}[/tex]
You walk into an elevator, step onto a scale, and push the "up" button. you recall that your normal weight is 639 n . when the elevator has an upward acceleration of magnitude 2.90 m/s2 , what does the scale read?
This question deals with the concepts of the actual weight and apparent weight.
The apparent weight of the person is "827.9 N".
APPARENT WEIGHTThe apparent weight of an object is the reaction of the elevator floor on the person while the elevator is in accelerated motion. It is not the actual weight but the weight felt by the person for that time. In this case the elevator is moving up. Hence the apparent weight will be:
[tex]W_a=m(g+a)=mg+ma\\W_a=W+ma[/tex]
where,
W = actual weight = 639 Nm = mass = [tex]\frac{W}{g}=\frac{639\ N}{9.81\ m/s^2}[/tex] = 65.14 kga = acceleration = 2.9 m/s²[tex]W_a[/tex] = apparent weight = ?Therefore,
[tex]W_a=639\ N + (65.14\ kg)(2.9\ m/s^s)[/tex]
[tex]W_a=827.9\ N[/tex]
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The scale reading in an elevator accelerating upwards will display an increased weight due to the additional force of acceleration. When an elevator accelerates with a magnitude of 2.90 m/s^2, the scale will show a higher value than the normal weight, calculated by the sum of gravitational force and force of acceleration.
Explanation:When you step onto a scale in an elevator that is accelerating upwards with a magnitude of 2.90 m/s2, the scale reading will be higher than your normal weight due to the additional force required to accelerate you upwards. Given that your normal weight is 639 N, we can calculate the new scale reading by incorporating the effects of the elevator's acceleration using Newton's second law of motion.
To find the new scale reading, we first determine the apparent weight. The apparent weight is the sum of the true weight (gravitational force) and the force of acceleration (ma).
Apparent weight = True weight (W) + Force of acceleration (ma)
Where the true weight W = mg (mass times gravity), and a is the acceleration of the elevator.
Assuming Earth's gravity to be 9.81 m/s2, we can calculate the apparent weight as follows:
Apparent weight = mg + ma
Now, we need to find the mass (m) from the given weight (639 N), which is m = W/g = 639 N / 9.81 m/s2.
Then plug the mass and the given acceleration into the equation for apparent weight.
The scale reading in an accelerating elevator is directly proportional to the acceleration; it increases as the elevator accelerates upwards. However, once the elevator reaches a constant velocity, the scale reading will return to your normal weight, 639 N, because there will be no additional force from acceleration (a = 0).
When a puddle dries up what are the particles really doing
Final answer:
When a puddle dries up, water undergoes evaporation, where the particles change from liquid to gas and eventually disperse into the atmosphere as invisible water vapor. The rate of evaporation increases with temperature, and sediment particles in the puddle settle down due to gravity.
Explanation:
Understanding Evaporation of Puddles
When a puddle dries up, the water particles are undergoing a phase change from liquid to gas, known as evaporation. On a warm day after it has rained, the increase in temperature causes the water in mud puddles to evaporate more quickly. This is because warmer air can hold more moisture. During the process of evaporation, the liquid water particles gain energy and transition into the gaseous state, becoming invisible water vapor in the air.
Similarly, on a cold, dry day, ice can sublimate, which means it changes directly from solid to gas without going through the liquid phase, also leaving no water behind. In both cases, the particles that were once part of the puddle are now dispersed into the atmosphere as water vapor. Dust and other sediment particles in the puddle settle down due to gravity, unless they are colloidal in size, which can stay suspended because of Brownian motion.
The equation for gear ratio
justin and his friends are on the football team. they consider skateboarders at their school to be an out-group. what does this mean?
Explanation:
Justine and his friends feel superior of themselves to the skateboarders team as they have a negative feeling about the skateboarders team. They always isolate and out group the skateboarders team in the school. They feel that football is the only superior sport and all has to play and support football and not skateboarding as a sport.
Thus they have a negative feeling towards the skateboarders team.
How many cells must be connected in series to give the 350 v a large catfish can produce?
Final answer:
Approximately 2333 electro plaques, or biological cells, would be needed to be connected in series to produce 350 V, given that each cell produces 0.15 V.
Explanation:
To calculate the number of cells required to produce a voltage of 350 V, similar to what a large catfish can produce, we must understand that when cells are connected in series, the total voltage is the sum of the individual voltages of each cell. If each cell, similar to those in an electric eel, produces an electromotive force (emf) of 0.15 V, then the number of cells required to reach 350 V would be the total voltage desired divided by the voltage of one cell.
(350 V) / (0.15 V per cell) = 2333.33 cells
Therefore, approximately 2333 cells would need to be connected in series to produce 350 V. This figure is derived by understanding that the potential difference across each cell adds up when they are connected in a series circuit, a principle that is crucial in the functioning of biological cells called electro plaques in electric fish.
How much heat energy, in kilojoules, is required to convert 76.0 g of ice at −18.0 ∘c to water at 25.0 ∘c ?
The total heat energy required to convert 76.0 g of ice at -18.0°C to water at 25.0°C is 35.184 kJ. This includes the energy to heat the ice to 0°C, melt the ice, and heat the water to 25°C.
Explanation:To calculate the heat energy required, we need to account for three processes: heating the ice to 0°C, melting the ice, and then heating the water to 25°C.
For the first process, we use the formula Q=mcΔT, where m is mass, c is specific heat, and ΔT is the temperature change. Ice has a specific heat of 2.09 J/g°C. So Q = 76.0 g * 2.09 J/g°C * 18°C = 2854.56 J.
For the second part, we use the formula Q = mLf, where m is mass and Lf is heat of fusion. For ice, Lf = 334 kJ/kg or 334 J/g. So Q = 76.0 g * 334 J/g = 25384 J.
For the last process, we once again use Q=mcΔT, this time with the specific heat of water, 4.184 J/g°C. So Q = 76.0 g * 4.184 J/g°C * 25°C = 7946 J.
To get the total heat energy required, we add these three quantities together and convert from joules to kilojoules. Q_total = (2854.56 J + 25384 J + 7946 J) / 1000 = 35.184 kJ. So, it requires 35.184 kJ of heat energy to convert 76.0 g of ice at -18.0°C to water at 25.0°C.
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When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What type of learning is Ian demonstrating?
Answer: observational learning and modeling
Explanation: