Answer
Gravitational force is between two object caused by energy in mass. Here when you are in a mine the radius of the earth in case of calculating gravity is reduced to the length between you and the center.
This means the mass of earth is decreasing even though the distance is decreasing. Relative to the decrease in distance squared the decrease in the mass of the second object(earth) is more. As a result your weight decreases.
Answer:
Explanation: that means as you descend into the earth, all of the mass in all the shells above you gets canceled. If the centre of the earth were not molten iron, but instead hollowed out, you would be weightless inside.
The physics problem is actually a little more general. It applies to inverse square force laws such as the electrical force. So if you put an electron inside a positively or negatively charged sphere, it will also have a net force on it of zero.
how far does a car go in 30 seconds at a speed of 29 m/s?
Answer:
870 metres
Explanation:
Speed = Distance/Time
Distance = Speed x Time
Distance = 29 x 30
= 870 metres
If the magnitude of the electrostatic force felt by a charge is three times that from another charge, but their charges are the same, then the electric field strength of this charge is _____ the strength of the other charge.
three times
nine times
one-third
one-ninth
Answer:
three times
Explanation:
F=Eq
3F=3Eq
Answer:
three times
Explanation:
The relation between the force and the electrostatic field is given by
F = q E
where, F be the force , q be the charge and E be the strength of electrostatic field.
Here the charge is q
F = q E .... (1)
Now the charge remains same but the force three times, let E' be the electrostatic field strength.
3F = q E' .... (2)
Divide equation (2) by equation (1)
E' / E = 3F / F
E' = 3 E
The voltmeter reads 117 V and ammeter reads 0.13 A .If the resistance of ammeter and voltmeter are 9 kilo ohm and 0.015 ohm respectively ,find the value of R. 3marks
R = 899.985Ω.
The ammeter gives a lecture of I = 0.13A through the resistor and the voltmeter gives a lecture of V = 117V between the points a and c, the ammeter resistance is Ra = 0.015Ω. So, the voltmeter reading is the sum of the potential difference Vbc (through the ammeter) and Vab (through the resistor).
To obtain the voltage Vbc through the ammeter from its known current and resistance, Ohm's law is used.
Vbc = I*Ra = (0.13A)(0.015Ω) = 0.00195V
Vab = V - Vbc = 117V - 0.00195V = 116.99805V
We know that Vab = I*R. Clear R from the equation:
R = Vab/I = 116.99805V/0.13A = 899.985Ω
You have 13.0 gallons of gasoline. How many liters is this? (1 gallon equals
about 3.79 L.)
Answer:
I believe the answer is C
Explanation:
For this case we must make a conversion, we have as data that:
1 gallon is equivalent to 3.79 liters
By making a rule of three we have:
1 gallon ------------> 3.79 L
13 gallons --------> x
Where "x" represents the equivalent in liters:
[tex]x = \frac {13 * 3.79} {1}\\x = 49.27[/tex]
So, we have 49.27 liters of gasoline.
Answer:
Option C
Chris is about to do an experiment to measure the density of water at several temperatures. His teacher has him prepare and sign a safety contract before beginning the experiment.
Which item is most likely part of the safety contract?
The safety contract will include basic lab safety guidelines such as:
Remove all flammable materials from the work station. Avoid leaving the heating set-up unattended. Fold long sleeves, tie back long hair, remove all accessories that may catch on fire. Wear proper lab attire.Avoid horse-playing in the lab.Report any injuries to the teacher, no matter how minor, as soon as possible. Avoid working alone inside the lab. Make sure you are aware of the location of the safety equipment and features of the lab especially the first aid kit, fire exit, fire blanket, and fire extinguisher.Follow instructions carefully.Dispose materials properly.Report any faulty equipment as soon as possible.Avoid touching hot surfaces with bare hands. Wash all used glassware.Keep workstation clean and tidy to avoid accidents.Avoid eating and drinking inside the lab.Put away unnecessary things. Only materials needed for the investigation must be on the workstation.Further Explanation:
In his safety contract, Chris will find statements that has him agreeing that he will behave appropriately inside the lab especially since they will be working with an open fire (Bunsen burner) or a heating equipment (hot plate) to change the temperature of the water. Proper behavior and basic expectation inside a lab are in the items listed above.
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Answer:
th
Explanation:
A trained sea lion slides from rest down a long
ramp into a pool of water. If the ramp is inclined at
an angle of 23° above the horizontal and the
coefficient of kinetic friction between the sea lion
and ramp is 0.26. Calculate the acceleration of the
sea lion as it slides down the ramp.
Answer:
1.5 m/s²
Explanation:
Draw a free body diagram. There are three forces acting on the sea lion: gravity pulling down, normal force perpendicular to the ramp, and friction parallel to the ramp.
Sum of the forces perpendicular to the incline:
∑F = ma
N − mg cos θ = 0
N = mg cos θ
Sum of the forces parallel to the incline:
∑F = ma
mg sin θ − Nμ = ma
Substitute for N:
mg sin θ − (mg cos θ) μ = ma
g sin θ − g cos θ μ = a
a = g (sin θ − μ cos θ)
Given θ = 23° and μ = 0.26:
a = 9.8 (sin 23 − 0.26 cos 23)
a = 1.48
Rounded to two significant figures, the sea lion accelerates at 1.5 m/s².
Given:
Coefficient of Kinetic energy = [tex]0.26[/tex]Angle = [tex]23^{\circ}[/tex]By using the Newton's second equation, we get
→ [tex]mgSin \Theta-F_k = ma[/tex]
or,
→ [tex]mgSin \Theta-\mu mg Cos \Theta =ma[/tex]
→ [tex]g Sin \Theta-\mu g Cos \Theta =a[/tex]
hence,
The acceleration will be:
→ [tex]a = 9.8 Sin 23^{\circ} - 0.26\times 9.8\times Cos23^{\circ}[/tex]
[tex]= 1.484 \ m/s^2[/tex]
Thus the above response is correct.
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A particle of mass, m = 3.0kg movers with a uniform velocity, v = (5m/s)I +(3m/s)j. At the time, t, the particle passes through the point r = (2m)i - (3m)j from the origin. Calculate the magnitude and direction of the angular momentum about the origin at time t. (Angular momentum is given by L= mv x R
Answer:
The magnitude is 63 kg m²/s, and the direction is -k.
Explanation:
Plug the values into the equation:
L = m v×r
L = (3.0 kg) (<5 i + 3j> m/s × <2i − 3j> m)
Take the cross product. The cross product of two dimensional vectors is:
<v₁ i + v₂ j> × <r₁ i + r₂ j> = <(v₁ r₂ − v₂ r₁) k>
Therefore:
L = (3.0 kg) <((5)(-3) − (3)(2)) k m²/s>
L = (3.0 kg) <-21 k m²/s>
Multiply:
L = <-63 k kg m²/s>
The magnitude is 63 kg m²/s, and the direction is -k.
If the specific heat of water is 1.0 calorie/gram°C, how many calories are required to raise 500 grams of water 10.0°C?
510 cal
5,000 cal
50 cal
501 cal
Answer:
5,000 cal
Explanation:
q = m C ΔT
where q is heat, m is mass, C is specific heat, and ΔT is change in temperature.
q = (500 g) (1.0 cal/g/°C) (10.0°C)
q = 5,000 cal
QUESTION 3
When completing a scientific investigation, you will know your results are reliable when you are able to
duplicate your results
communicate your results
evaluate your results.
Answer:
duplicate your results
Explanation:
the results are reliable when you can duplicate the expirement and repeat the results without error.
Answer:
Duplicate your results.Explanation:
A scientific investigation refers to researches where we apply the scientific method, which is characterized by involving systematic observations, measurements, experimentation, analysis, system of hypothesis, and other elements.
Basically, when we have a hypothesis, we try to prove it developing a scientific investigation which must be defined with the relation between a dependent variable and an independent variable. So, through systematic observations, we study the relation between these variables, experimenting and analysing all results we get from those observations.
So, one important characteristic of scientific investigation is research reliability, which is the degree to which a research produces consistent results, and one ingredient to obtain that it's the posibility of reproducing the results, that is, duplicating them in other contexts. For example, if we study Newton's second law, you will be able to reproduce the results of such law in different contexts.
Therefore, the right answer is "duplicate your results".
How much momentum will a dumb-bell of mass 10 kg transfer
to the floor if it falls from a height of 80 cm? Take its downward
acceleration to be 10 m s–2 .
We want to find how much momentum the dumbbell has at the moment it strikes the floor. Let's use this kinematics equation:
Vf² = Vi² + 2ad
Vf is the final velocity of the dumbbell, Vi is its initial velocity, a is its acceleration, and d is the height of its fall.
Given values:
Vi = 0m/s (dumbbell starts falling from rest)
a = 10m/s² (we'll treat downward motion as positive, this doesn't affect the result as long as we keep this in mind)
d = 80×10⁻²m
Plug in the values and solve for Vf:
Vf² = 2(10)(80×10⁻²)
Vf = ±4m/s
Reject the negative root.
Vf = 4m/s
The momentum of the dumbbell is given by:
p = mv
p is its momentum, m is its mass, and v is its velocity.
Given values:
m = 10kg
v = 4m/s (from previous calculation)
Plug in the values and solve for p:
p = 10(4)
p = 40kg×m/s
By using the equations of motion and momentum, it can be determined that a 10 kg d.umbbell falling from a height of 80 cm will transfer 40 kg m/s of momentum to the floor.
Explanation:The subject of this question is Physics, particularly dealing with the concept of momentum. To find out how much momentum a d.umbbell will transfer to the floor, we first need to calculate its velocity right before it hits the ground. This can be calculated using the equation of motion: v² = u² + 2gh, where u (initial velocity) is 0 (because it starts from rest), g (gravity) is 10 m/s², and h (height) is 0.8m (80cm).
Using the given values in the equation, the velocity v comes out to be √(2*10*0.8) = √16 = 4 m/s. The momentum is then calculated using the formula p=mv, where p represents momentum, m is mass, and v is velocity. Substituting the mass (10 kg) and the velocity (4 m/s), we find out that the momentum transferred to the floor is 40 kg m/s. Therefore, a d.umbbell of mass 10 kg falling from a height of 80 cm transfers 40 kg m/s momentum to the floor.
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Which type of modulation is applied to radio-controlled toys?
Answer:
Pulse modulation
Explanation:
Remote control toys use the radiations that lie in the range of infrared for their working. The frequency of these infrared radiations is 36-46 kilo Hertz.
The signals we give to the toys through remote control are actually given in the form of bits of data which are then modulated with the any desired carrier frequency. Therefore, the data we are sending is in the form of pulses and the pulses' duration determines that whether the signal will be read as OFF (0) or ON (1). This modulation is pulse modulation which is an effective method to lower the power value delivered by a signal by cutting the signal into smaller parts.
Similarly there are some other kinds of modulations used in some other purposes like frequency and amplitude modulation for signals transmission video and music.
Hope it helps!
Answer:
pulse
Explanation:
if the ball rises with a force of 150 N, what pressure did the patient apply to his side of the tube?
The following formula relates applied force to pressure:
P = F/A
P is the pressure, F is the applied force, and A is the area over which the force is applied.
Unfortunately we cannot calculate the pressure if we don't know the area of contact between the ball and the tube.
Which factors affect gravitational force? Check all that apply.
composition of the objects
distance between the objects
masses of the objects
volume of the objects
weights of the objects
Intro
Done
Answer:
distance between the objects
masses of the objects
Explanation:
Gravitational force is a force of attraction that pulls two objects with masses together.
To best understand the concept of gravitational force, newton's law of universal gravitation provides a good insight. The law states that "every object in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".
From the law, we see that gravitational force is dependent on the masses of the object and their distances.
Answer:
B. distance between the objects
C. masses of the objects
The following diagram shows resistors in a circuit.
Answer:
The following diagram shows resistors in a series circuit.
Gravity is the force that keeps us on the Earth. It pulls us towards the center of the Earth. If you were to move from the surface of the Earth to a point higher up, away from the Earth, what type of energy would be gained? A. Chemical potential energy B. Gravitational potential energy C. Gravitational kinetic energy D. Kinetic potential energy
Explanation:
The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field.
That is why this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.
In the case of the Earth, in which the gravitational field is considered constant, the value of the gravitational potential energy [tex]U_{p}[/tex] will be:
[tex]U_{p}=mgh[/tex]
Where [tex]m[/tex] is the mass of the object, [tex]g[/tex] the acceleration due gravity and [tex]h[/tex] the height of the object.
As we can see, the value of [tex]U_{p}[/tex] is directly proportional to the height.
Two bricks of the same mass are each on ledges. Brick 1 is 100 feet high and Brick 2 is 300 feet high. Brick 2 has:
1. zero times more potential energy
2. two times more potential energy
3. three times more potential energy
4. four times more potential energy
5. nine times more potential energy
Answer: 3 times more potential energy
Explanation:
Final answer:
Brick 2 has three times more gravitational potential energy than Brick 1, as it is three times higher and both bricks have the same mass. The potential energy is calculated using the formula GPE = mgh.
Explanation:
The question relates to the concept of gravitational potential energy (GPE), which is the energy an object possesses by virtue of its height above the ground and its mass. The formula to calculate GPE is GPE = mass x gravitational field strength (g) x height. For comparable masses, the only variable affecting the potential energy is height. Given that Brick 1 is at 100 feet and Brick 2 is at 300 feet, the potential energy is directly proportional to height since mass and gravitational acceleration are constant.
Therefore, Brick 2 has three times the potential energy of Brick 1 because it is at three times the height (300 feet compared to 100 feet). This relationship is captured by the formula GPE = mgh, where m is the mass, g is the acceleration due to gravity (assumed constant here), and h is the height.
Electrostatic charges are created by _____.
stripping outer electrons from substances
running electric current through a substance
stripping protons from the nucleus of a substance
running a substance through a magnetic field
Answer:
Electrostatic charges are created by stripping outer electrons from substances - first choice.
10. A worker covers a distance of 40 km from his house to his place of
work, and 10 km towards his house back. Then the displacement
covered by the worker in the whole trip is
The displacement covered by the worker in the whole trip is 30km.
The easiest way to solve this problem is using the displacement equation:
Δx = x₂ - x₁
A worker covers a distance of 40 km from his house to his place of
work, and 10 km towards his house back. So:
Δx = x₂ - x₁ = 40km - 10km = 30km
Since displacement is a vector quantity, the displacement of the worker from the data is 30Km.
What is displacement?Displacement refers to distance covered in a specific direction. Hence, unlike distance, we include direction in our discussion of displacement.
As such, displacement is a vector quantity therefore, the displacement of the worker is obtained from 40 Km - 10 Km = 30Km.
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what is change in internal energy if 30j of heat are released from a system that does 50j of work on its surroundings
Answer:
-80 J
Explanation:
The first law of thermodynamics states that:
[tex]\Delta U = Q - W[/tex]
where
[tex]\Delta U[/tex] is the change in internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system
In this problem, we have:
Q = -30 J is the heat released by the system (negative because the system releases it)
W = +50 J is the work done by the system on the surrounding (positive since it is done by the system)
Therefore, the change in internal energy is
[tex]\Delta U = -30 J - (+50 J) = -80 J[/tex]
Answer: -80 J
Explanation:
A satellite with a mass of 5.6 E 5 kg is orbiting the Earth in a circular path. Determine the satellite's velocity if it is orbiting at a distance of 6.8 E 5 m above the Earth's surface. Earth's mass = 5.98 E 24 kg; Earth's radius = 6.357 E 6 m.
6,800 m/s
7,200 m/s
7,500 m/s
7,900 m/s
Answer:
7500 m/s
Explanation:
Centripetal acceleration = gravity
v² / r = GM / r²
v = √(GM / r)
Given:
G = 6.67×10⁻¹¹ m³/kg/s²
M = 5.98×10²⁴ kg
r = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m
v = √(6.67×10⁻¹¹ (5.98×10²⁴) / (7.037×10⁶))
v = 7500
The orbital velocity is 7500 m/s.
The orbital velocity is 7500 m/s.
What is orbital velocity ?Orbital velocity is defined as the minimum velocity a body must maintain to stay in orbit.
Given
h = 6.8 E 5 m = 6.8 * [tex]10^{5}[/tex] m
mass of satellite = 5.6 * [tex]10^{5}[/tex] kg
Earth's mass : m(e) = 5.98 E 24 kg
Earth's radius ; R(e) = 6.357 E 6 m
orbital velocity :v(orbiting ) = [tex]\sqrt{Gm(e) / R(e) + h}[/tex]
R(e) + h = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m
v = √(6.67×10⁻¹¹ * (5.98×10²⁴)) / (7.037×10⁶))
v = 7500 m/s
The orbital velocity is 7500 m/s.
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the period and freqency of a wave are inversely related true or false
Answer: false
Explanation: the longer the period, the less thef= frequency
Answer:
True
Explanation:
As frequency increases, period decreases, and vice versa.
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6. On a quiet day, the atmospheric pressure results in a force of about 10,0000 N on a window pane with an area of 1 square meter. a. Why does this large force not shatter the window? b. How will this change if a strong wind is blowing across the window pane?
Explanation:
a. The same atmospheric pressure that's pushing the window from the outside is also pushing on the window from the inside. So the forces are balanced.
b. If a strong wind is blowing across the window pane, the pressure will drop, as described by the Bernoulli principle. So the pressure inside will be greater than the pressure outside, causing the window to bow out a little.
Final answer:
The large force applied by atmospheric pressure does not shatter a window because it is evenly distributed and balanced by internal pressures. A strong wind can change the pressure on the window by creating a differential. Air pressure is considerable but not damaging due to balance with internal body pressure.
Explanation:
Atmospheric Pressure and Its Effect
a) On a quiet day, the atmospheric pressure results in a force of about 100,000 N on a window pane with an area of 1 square meter. This large force does not shatter the window because the pressure is exerted evenly over the entire surface of the window and is balanced by internal pressures within the building.
b) If a strong wind is blowing across the window pane, the pressure on the window will change due to the wind's pressure differential causing a net force that could potentially cause damage if strong enough.
Starting from rest on a frictionless floor you move 160 kg crate accelerated by a net force of 60N applied for 4s. Enter units for acceleration as m/s^2.
What is the acceleration of the crate from Newton’s 2nd law?
If it starts from rest, how far does it travel in time of 4 s?
How much work is done by the 60N net force?
What is the velocity of the crate at the end of 4s?
What is the kinetic energy of the crate at this time?
1. Acceleration: [tex]0.375 m/s^2[/tex]
Newton's second law states that the net force on an object is equal to the product between the object's mass and its acceleration:
F = ma
where
F is the net force
m is the mass
a is the acceleration
For the crate in this problem we have
F = 60 N
m = 160 kg
Re-arranging the equation, we can find the acceleration of the crate:
[tex]a=\frac{F}{m}=\frac{60 N}{160 kg}=0.375 m/s^2[/tex]
2. Distance: 3 m
For this problem we can use the following SUVAT equation:
[tex]S=ut+\frac{1}{2}at^2[/tex]
where
S is the distance travelled by the crate
u = 0 is the initial velocity, since it starts from rest
t = 4 s is the time elapsed
[tex]a=0.375 m/s^2[/tex] is the acceleration
Substituting all numbers into the equation,
[tex]S=0+\frac{1}{2}(0.375)(4)^2=3 m[/tex]
3. Work done: 180 J
The work done by a force, assuming that the force is parallel to the displacement of the object, is given by
W = F d
where
W is the work done
F is the magnitude of the force
d is the displacement
Here we have
F = 60 N
d = 3 m
So the work done is
[tex]W=(60 N)(3 m)=180 J[/tex]
4. Final velocity: 1.5 m/s
The final velocity of the crate can be found by using the following SUVAT equation:
[tex]v^2 = u^2 +2ad[/tex]
where here
u = 0 is the initial velocity
[tex]a=0.375 m/s^2[/tex] is the acceleration
d = 3 m is the distance covered
Substituting all the numbers that we have, we found:
[tex]v=\sqrt{u^2 +2ad}=\sqrt{0^2+2(0.375)(3)}=1.5 m/s[/tex]
5. Kinetic energy: 180 J
The kinetic energy of an object is given by
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the object
v is the velocity
Here we have
m = 160 kg is the mass of the crate
v = 1.5 m/s is its final velocity
So the kinetic energy of the crate is
[tex]K=\frac{1}{2}(160)(1.5)^2=180 J[/tex]
HOW Tar does a car go in 30 seconds at a speed of 29 m/s? (the equation for
distance is d = st.)
A. 1.03 m
B. 900 m
C. 59 m
D. 870 m
Answer:B
Explanation:it’s the answer
a weight lifter performed 200 J of work lifting a weight in 2 seconds. what was his power
Answer:
100 Watts
Explanation:
Power is work per time.
P = W / t
P = 200 J / 2 s
P = 100 W
Answer: 100 Watts
Explanation:
12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolley
travelling in the same direction at 1.5m/s. Find their common
velocity. Assume that there is no external unbalanced force
working in the horizontal direction.
Answer:
4 m/s
Explanation:
Momentum is conserved.
m₁ v₁ + m₂ v₂ = (m₁ + m₂) v
(50)(5) + (20)(1.5) = (50 + 20) v
v = 4
The final velocity is 4 m/s.
Which agency helps with disaster response
Answer:
AMURT
Explanation:
BUT THERE ARE MANY OTHERS LIKE THE AMERICAN RED CROSS ETC
Answer: Mercy corps
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Sierra did 500 J of work to move her couch. If she exerts 250 N of force on the couch, how far did she move it?
Answer:
2 m
Explanation:
Work = force × distance
500 J = 250 N × d
d = 2 m
She moved the couch 2 meters.
A baseball is launched straight up (vertically) next to a tall building with an initial velocity of 30.0 m/s[up]. The ball continues upward to a stop, and then falls until caught by a player leaning out of a window 14.0 m above the ground. How long is the ball in the air before the player catches it?
Answer:
5.61 seconds
Explanation:
Given:
y₀ = 0 m
y = 14.0 m
v₀ = 30.0 m/s
a = -9.8 m/s²
Find: t
y = y₀ + v₀ t + ½ at²
14 = 0 + 30t − 4.9t²
4.9t² − 30t + 14 = 0
Solve with quadratic formula:
t = [ -b ± √(b² − 4ac) ] / 2a
t = [ 30 ± √(900 − 274.4) ] / 9.8
t = 0.509, 5.61
t = 0.509 is the time when the ball first reaches the height of 14.0 meters on the way up. t = 5.61 is the time when the ball reaches the height of 14.0 meters on the way down.
Since we know the ball reaches its maximum height and begins falling again, we want the second time. t = 5.61 seconds.
a bike can climb the inclined road at uniform speed of 72 km/hr by applying force 500N what will be the power applied by the bike ?
Answer:
10 kW
Explanation:
First convert km/hr to m/s.
72 km/hr × (1000 m / km) × (1 hr / 3600 s) = 20 m/s
The power is:
P = Fv
P = (500 N) (20 m/s)
P = 10000 W
P = 10 kW
The power applied by the bike is 10 kW.
The power applied by the bike climbing the inclined road at a constant speed with a force of 500 N is calculated as 10000 watts or 10 kW using the formula Power = Force x Velocity.
The problem at hand involves calculating the power applied by a bike when it ascends an inclined road at a uniform speed while applying a force. To find the power, we need to use the formula for power in the context of mechanical systems, which is Power (P) = Force (F) × Velocity (v). Here, force is given as 500 N and the velocity can be converted from 72 km/hr to meters per second (m/s) by multiplying it with (1000 m/km) / (3600 s/hr), which gives us 20 m/s.
Therefore, the power applied by the bike is P = 500 N × 20 m/s = 10000 watts or 10 kW.
This is the instantaneous power delivered by the force that the bike exerts on the road to overcome resistant forces like friction and air resistance while moving uphill. It's important to note that the power can change if any of the variables, such as speed or the force, change.