The windmill has 7 blades and rotates at an angular speed of 0.5 rad/s. The opening between successive blades is equal to the width of a blade. A golf ball of diameter 9.0 x 10⁻² m is just passing by one of the rotating blades at a minimum speed of 0.1 m/s.
What is the angular acceleration of the windmill?

1. 3 significant figures

2. 6 significant figures

3. 4 significant figures

Answer:

57.16

Explanation:

The minimum weight of the ballast required to bring the CG of the aircraft within the given range is approximately 15.2 lbs. This is calculated using the weight of the aircraft, the distances the CG needs to move and the distance from the CG to the location where the ballast is placed.

The subject matter of this problem is physics, specifically dealing with the concept of Centres of Gravity (CG). In order to find the minimum weight of the ballast required to bring the CG within the given CG range, we first need to establish how far the current CG is from the lower limit of the range. That is 32.0 - 30.5 = 1.5 inches. We can assume that the weight required to move the CG 1 inch can be found using the formula: (Weight of aircraft X Distance CG needs to move) / Distance from CG to ballast. So, in this case, the minimum ballast weight will be: (4954 lbs * 1.5 inches) / (162 inches - 30.5 inches). Carrying out the calculations, this gives us a ballast weight of approximately 15.2 lbs.

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Answer:

When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line

the answer is -183 degree celcius

Answer:

90= C+273

C=273-90= - 183

The energy transferred out of the system as heat is 3950 J, or in scientific notation, [tex]\rm \( 3.95 \times 10^3 \, \text{J} \)[/tex]

The amount of energy q required to change the temperature of a substance can be calculated using the formula:

[tex]\rm \[ q = m \cdot C \cdot \Delta T \][/tex]

Where:

m is the mass of the substance

C is the specific heat capacity of the substance

[tex]\rm\( \Delta T \)[/tex] is the change in temperature

Given that the change in temperature is from the system's current temperature to [tex]\( 0^\circ \text{C} \)[/tex], which is -T in Kelvin, and the specific heat capacity C is typically given in [tex]\rm \( \text{J/g}^\circ \text{C} \)[/tex], we can express the formula as:

[tex]\rm \[ q = m \cdot C \cdot (-T) \][/tex]

Given that the energy is to be expressed in joules, we need to use the SI unit for mass (kilograms) and convert the specific heat capacity to [tex]\rm \( \text{J/kg}^\circ \text{C} \)[/tex]

The conversion factor from [tex]\rm \( \text{J/g}^\circ \text{C} \)[/tex] to [tex]\( \text{J/kg}^\circ \text{C} \)[/tex] is 1000 since [tex]\( 1 \, \text{g} = 0.001 \, \text{kg} \)[/tex]:

[tex]\rm \[ C_{\text{SI}} = C_{\text{g}} \cdot 1000 \][/tex]

Now, we can use the formula to calculate q.

Given:

m (mass of the substance) = [tex]\rm \( 4.70 \, \text{kg} \)[/tex] (assuming mass)

C (specific heat capacity) = [tex]\rm \( 4.18 \, \text{J/kg}^\circ \text{C} \)[/tex]

T (temperature change) = [tex]\rm \( 0^\circ \text{C} - 20^\circ \text{C} = -20^\circ \text{C} \)[/tex]

Substitute the values:

[tex]\rm \[ q = (4.70 \, \text{kg}) \cdot (4.18 \, \text{J/kg}^\circ \text{C}) \cdot (-20^\circ \text{C}) \]\\\\rm q = -3949.6 \, \text{J} \][/tex]

Since the answer is expected in kilojoules (kJ), convert the value from joules to kilojoules:

[tex]\rm \[ q = -3949.6 \, \text{J} \\= -3.9496 \, \text{kJ} \][/tex]

Now, express the result with the correct number of significant figures:

[tex]\rm \[ q = -3.95 \, \text{kJ} \][/tex]

Since the question asks for the energy transferred out of the system as heat, take the absolute value:

[tex]\rm \[ q_{\text{abs}} = 3.95 \, \text{kJ} \\= 3950 \, \text{J} \][/tex]

Therefore, the energy transferred out of the system as heat is 3950 J, or in scientific notation, [tex]\rm \( 3.95 \times 10^3 \, \text{J} \)[/tex]

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To calculate the energy transfer in joules, we need the specific heat capacity of the substance, its mass, and the initial temperature. The formula for this is q = mcΔT. Without these values, we cannot provide a specific numerical answer.

To calculate how much energy needs to be transferred out of the system as heat in order to lower its temperature to 0°C, you would need more information. A key factor of this calculation is the specific heat capacity of the substance in the system, as well as its mass. The formula for heat transfer is q = mcΔT, where m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. Without the values of m and c as well as the initial temperature, it is not possible to provide a numerical answer in joules.

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Answer:

(a) Tension on both side of wire

[tex]T_1=46.706 N[/tex]

[tex]T_2=51.710 N[/tex]

(b) acceleration of the Box

[tex]a = 3.336 \frac{m}{sec^2}[/tex]

(c) The horizontal and vertical components

Horizontal component [tex]T_1=46.706 N[/tex]

Vertical Component  =130.19 N

Explanation:

Refer attached figure for details.

[tex]T_1\ \&\ T_2\ are\ tensions\ in\ the\ string\ and\ a\ is\ the\ acceleration\ of\ the\ masses.[/tex]

Applying Newton's 2 law of motion for 14 kg block in horizontal direction

[tex]T_1 = 14\ a[/tex]-----------(i)

Similarly, applying Newton's 2 law of motion for 8 kg block in vertical direction

[tex]8 g - T_2 =8 a[/tex]-----(ii)

Consider the case of pulley,

[tex]\tau_e_x_t= I\alpha--------(iii)\\\\Where,\\\tau_e_x_t =Torque\ acting\ on\ the\ pulley\\I=moment\ of\ inertia\ of\ pulley\\\alpha= angular\ acceleration[/tex]

where,

[tex]I= \frac{MR^2}{2} (for\ pulley\ disk)[/tex]

[tex]I=\frac{3\cdot0.5^2}{2} =0.375\ kgm^2[/tex] (since mass of the pulley = 3 kg & Radius = 0.5 m)

&[tex]\tau_e_x_t= Net\ force \cdot Distance\ from\ application\ point[/tex]

Hence [tex]\tau_e_x_t = (T_2-T_1) \cdot \frac{1}{2} = 0.375\cdot\alpha[/tex]

[tex]T_2-T_1=0.75\cdot\alpha[/tex]--------(iv)

Relation between linear acceleration (a) and angular acceleration (α) is as follows,

[tex]a = R\alpha=0.5\cdot\alpha \ (R\ is \ radius\ of \ pulley)[/tex]

[tex]\alpha=2a[/tex]--------------------(v)

Putting the value of (v) in to (iv)

[tex]T_2 -T_1= 1.5 a[/tex]---------(vi)

adding equation (i),(ii) & (vi) gives

8g =22 a + 1.5 a

[tex]a = 3.336 \frac{m}{sec^2}[/tex]

now putting the value of a in equation (i) & (ii) we get

[tex]T_1=46.706 N[/tex]

[tex]T_2=46.706 +1.5 \cdot 3.336[/tex] = 51.710 N

(a) Hence Tension on both side of wire

[tex]T_1=46.706 N[/tex]

[tex]T_2=51.710 N[/tex]

(b) acceleration of the Box

[tex]a = 3.336 \frac{m}{sec^2}[/tex]

(c) The horizontal and vertical components

Horizontal component [tex]T_1=46.706 N[/tex]

Vertical Component = [tex]T_2+8\cdot g[/tex] =51.710 + 8 x 9.81 =130.19 N

Answer:

Tension, T1 = 46.2 N and T2 = 52 N, where as acceleration = 3.3 ms^-2.

Forces on the pulley are 46.2 N , 81.4 N horizontal and vertical

respectively.

Explanation:

Given:

Mass of the box on rest,[tex]m_1[/tex] = 14 kg

Mass of the attached box,[tex]m_2[/tex] = 8 kg

Mass of the pulley, [tex]m_3[/tex] = 3 kg

Diameter of the pulley, [tex]d[/tex] = 1 m

Radius of the pulley, [tex]r[/tex] = 0.5 m

Here we will be using the concept of net force ([tex]F_n_e_t[/tex]),net torque ([tex]\tau_n_e_t[/tex]) and acceleration of the pulley .

A FBD is attached with.

Lets find the tension on the wire using Fnet.

⇒ [tex]T_1=m_1(a)[/tex]                                                                                       ...for m1

⇒ [tex]m_2g-T_2=m_2(a)[/tex] can be written as [tex]T_2=m_2g-m_2(a)[/tex]                ...for m2

Considering clockwise torque as negative and anticlockwise torque as positive.

Moment of inertia (I) of the disk/pulley = [tex]\frac{m_3r^2}{2}[/tex] and [tex]\alpha=\frac{a}{r}[/tex] .

Now using net torque on the pulley we can say that.

⇒ [tex](T_2-T_1)r=I\alpha[/tex]

⇒ [tex](T_2-T_1)r=\frac{m_3r^2}{2}\times \frac{a}{r}[/tex]

⇒ [tex](T_2-T_1)=\frac{m_3a}{2}[/tex]

⇒ Plugging T1 and T2 .

⇒ [tex]m_2g-m_2a-m_1a=\frac{m_3a}{2}[/tex]

⇒ Isolating a from the rest.

⇒ [tex]m_2g=\frac{m_3a}{2}+m_2a+m_1a[/tex]

⇒ [tex]m_2g=a\ [\frac{m_3}{2}+m_2+m_1][/tex]

⇒ [tex]\frac{m_2g}{\frac{m_3}{2} +m_2+m_1} =a[/tex]

⇒ Plugging the numeric value

⇒ [tex]\frac{(8\times 9.8)}{(\frac{3}{2} +8+14)} =a[/tex]

⇒ [tex]3.3 =a[/tex]

⇒ Acceleration = 3.3 [tex]ms^-^2[/tex]

So,

(a).

Tension in the wire

⇒ [tex]T_1=m_1(a)=14\times 3.3 =46.2\ N[/tex]

⇒ [tex]T_2=m_2g-m_2(a)=8(9.8-3.3)=52\ N[/tex]

(b).

The acceleration of the box is 3.3 ms^-2.

(c).

Forces on the pulley.

Horizontal force, [tex]P_H[/tex] = [tex]T_1[/tex] = [tex]46.2\ N[/tex]

Vertical force,[tex]P_V[/tex] = [tex]T_2+m_3g[/tex] = [tex]52+3(9.8)[/tex] = [tex]81.4\ N[/tex]

The values are as follows:

Tension as T1 = 46.2 N and T2 = 52 N ,where as acceleration =3.3 ms^-2.

Forces on the pulley are 46.2 N , 81.4 N horizontal and vertical

respectively.

Train has the most momentum if they were all traveling 50 mph

Explanation:

Answer:

0.0176m

Explanation:

Given that,

railroad track has a length of 40 m

temperature is T₁ −5 ◦C

temperature is T₂ 35 ◦C

linear expansion coefficient of steel is 11 × 10−6 ( ◦C)−1

Lo = 40 m

T₁ = -5° C

T₂ = 35° C

dT = T₂ - T₁

    = 35 - (-5)

     = 40°C

L = Lo*(1+alpha*dT)

dL = Lo*alpha*dT

dT =  40°C

alpah = 11 x 10⁻⁶

Lo = 40 m

dL = 40 × 11 x 10⁻⁶  × 40

 = 0.0176m

Answer:

ΔL = 0.0176m

Explanation:

We are given;

Length of railroad track; L = 40 m

First Temperature; T1 = −5 ◦C

Second temperature; T2 = 35 ◦C

linear expansion coefficient of steel; α = 11 × 10^(−6) (◦C)^(-1)

The increase in length is given by the equation;

ΔL = α•L•ΔT

Where,

α is linear coefficient

L is length

ΔT is change in temperature.

ΔT = first temperature - Second Temperature

Thus, ΔT = 35 - (-5) = 35 + 5 = 40°C

Thus,plugging in relevant values,

ΔL = α•L•ΔT = 11 × 10^(−6)•40•40

ΔL = 0.0176m

Answer:

[tex]T = 12910.5\,N[/tex] for a craft with a mass of 1500 kg.

Explanation:

Let consider that craft has a mass of 1500 kg. The submersible craft is modelled after the Newton's Laws, whose equation of equilibrium is:

[tex]\Sigma F = T - W +F_{D} = 0[/tex]

The tension experimented by the cable while the craft is lowering to the seafloor is:

[tex]T = W - F_{D}[/tex]

[tex]T = (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)-1800\,N[/tex]

[tex]T = 12910.5\,N[/tex]

Answer:

Decreasing in altitude and increasing in velocity

Explanation:

The formula for potential energy is:

[tex]E_p = mgh[/tex]

where m is mass, g is constant gravitational energy and h is the potential altitude.

The formula for kinetic energy is:

[tex]E_k = mv^2/2[/tex]

where v is the velocity

Since m,g are constant, to convert from potential energy to kinetic energy, h must decreases while v increases. For example dropping an object from a height.

Answer:

Explanation:

Atractive forces tries to stop objects when they try to escape of the influence of these forces. Examples of this situation are the gravitational force and electric force.

When the object loses speed, its speed is decreasing, that is, its kinetic energy is decreasing, because the kinetic energy depends on speed:

[tex]E_k=\frac{1}{2}mv^2[/tex]

this lost of kinetic energy is equilibrated by the increase of the potential energy generated by the atractive force.

Because of this dynamic between the kinetic energy and the potential energy, the total mechanical energy of the object is conserved.

Answer:

As you learned, scientists standardized the short-hand way we represent elements, by their chemical symbol. One of the main reasons this was developed was because using letters was the easiest way to represent the elements. Another reason that we use chemical symbols is to allow us to write chemical formulas easily

Or

One set of chemical symbols means that every science student and scientist -- no matter what languages they speak -- can identify these chemicals.

I hope this helps

As you taught, scientists standardized the use of an element's chemical symbol as a shorthand for representing it. This was created in part because representing the elements with letters was the simplest method. Utilizing chemical symbols also makes it easier to formulate chemical formulas.

All identified chemical elements are arranged in rows (referred to as periods) and columns (referred to as groups) in the periodic table of chemical elements, also known as the periodic table, in ascending order of atomic number.

The periodic table is used by scientists to quickly refer to details about an element, such as its atomic mass and chemical symbol. Scientists can identify trends in element properties like electronegativity, ionization energy, and atomic radius thanks to the periodic table's arrangement.

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Answer:

6 m/s²

Explanation:

We know that the force acting on an object varies directly with the acceleration. The force, F, and acceleration, a, are related by:

F = m * a

Where m is the mass of the object

We then need to find the mass of the object before we can find its acceleration when the force is 30 m/s².

Therefore, when the force is 20 N and the acceleration is 4 m/s²:

20 = m * 4

=> m = 20/4 = 5 kg

The mass of the object is 5 kg. Hence, we can find the acceleration of the object when the force is 30 N

30 = 5 * a

=> a = 30/5 = 6 m/s²

The acceleration of the object is 6 m/s²

Answer:

6m/s²

Explanation:

According to Newton's second law

Force F acting on an object varies directly with the object's acceleration a. Mathematically it is expressed as

F = ma where;

m is the mass of the object

F is the applied force

a is the acceleration

Let m be constant

m = F/a

If a force of 20 N acts on a certain object with an acceleration of 4m/s²

m = 20/4

m = 5kg

If the force is changed to 30 N, its new acceleration can be gotten using the previous formula.

F = ma

a = F/m

a = 30/5 (since mass is kept constant)

a = 6m/s²

Answer:

The two word term is "ICE SHOVES"

Explanation:

An ice shove also known as ice surge, ice heave, ivu, or shoreline ice pileup is simply a surge of ice which occurs from an ocean or large lake and drops on the shore. These ice shoves are usually caused by ocean currents, strong winds, or temperature differences which tend to push the ice to the shore. The ice shoves can create ice piles up to 12 metres high and more.

Ice shoves has been recorded in at least three lakes in the past years. They are Lake Dauphin (Manitoba, Canada), Mille Lacs Lake (Minnesota), Lake Winnebago (Wisconsin), etc.

Answer:

ICE SHOVE

Explanation:

An Ice Shove is a situation or phenomenon that occurs when the wind carries or pushes melting ice from frozen lakes down to the lake shore.

Agents involved in the pushing of melting ice down to the lake shore includes: currents in the ocean, very strong winds as well as variations and fluctuations in the temperature of the lake.

Ice shoves can result in a pile up and accumulation of ice on the lake shore to be at about 30-40 feet high.

Ice shoves can result in negative effects in the lives of living organisms. Such negative effects includes:

a. Damages to the shoreline of the lakes

b. Damages to the habitats of any living organisms by the lake.

c. Damages to structures (buildings) that can be found at the lake shore.

Answer:

Explanation:

Given that,

Mass of counterweight m= 4kg

Radius of spool cylinder

R = 8cm = 0.08m

Mass of spool

M = 2kg

The system about the axle of the pulley is under the torque applied by the cord. At rest, the tension in the cord is balanced by the counterweight T = mg. If we choose the rotation axle towards a certain ~z, we should have:

Then we have,

τ(net) = R~ × T~

τ(net) = R~•i × mg•j

τ(net) = Rmg• k

τ(net) = 0.08 ×4 × 9.81

τ(net) = 3.139 Nm •k

The magnitude of the net torque is 3.139Nm

b. Taking into account rotation of the pulley and translation of the counterweight, the total angular momentum of the system is:

L~ = R~ × m~v + I~ω

L = mRv + MR v

L = (m + M)Rv

L = (4 + 2) × 0.08

L = 0.48 Kg.m

C. τ =dL/dt

mgR = (M + m)R dv/ dt

mgR = (M + m)R • a

a =mg/(m + M)

a =(4 × 9.81)/(4+2)

a = 6.54 m/s

Answer:

a) τnet = 3.1392 N-m

b) L = (0.48 Kg-m)*v

c) a = 6.54 m/s²

Explanation:

Given

m = 4 Kg

R = 8 cm = 0.08 m

M = 2 Kg

a) τnet = ?

b) L = ?

c)  a = ?

Solution

a) We use the formula

τnet = R*m*g*Sin 90°

τnet = 0.08 m*4 Kg*9.81 m/s²*(1)

τnet = 3.1392 N-m

b) We apply the equation

L= R*m*v + R*M*v = R*(m + M)*v

then

L = (0.08 m)*(4 Kg + 2 Kg)*v = (0.48 Kg-m)*v

c) We use the relation

τ = dL/dt = d((0.48 Kg-m)*v)/dt = (0.48 Kg-m)*dv/dt

τ = (0.48 Kg-m)*a

then

τ/(0.48 Kg-m) = a

⇒   a = 3.1392 N-m/((0.48 Kg-m)

a = 6.54 m/s²

The answer for the following question is explained below.

Explanation:

Work:

A force causing the movement or displacement of an object.

Given:

mass of the person (m) = 65 kg

height of the cliff (h) = 2000 m

To calculate:

work done (W)

We know;

According to the formula:

  W = m × g × h

Where;

m represents mass of the person

g represents the acceleration due to gravity

where the value of g is;

  g = 10 m/ s²

h represents the height of the cliff

From the above formula;

  W = 65 × 10 × 2000

 W = 130,000 J

  W = 130 Kilo Joules

Therefore the work done is 130 kilo Joules.

The process of removing heat from a place where it is not wanted and transferring that heat to a place where it makes little or no difference is known as B) refrigeration.

The evaporator in a refrigeration device must be chillier than the refrigerated space for the purpose to take in heat. The boiling factor of a refrigerant ought to be low sufficient at atmospheric strain to preserve the machine stress above 0 PSIG when working at low temperatures.

The evaporator can be thought of as a “warmness sponge.” Vapor is more dense than liquid and, because the liquid refrigerant boils, it has a tendency to sink. The handiest area wherein the refrigerant vapor is superheated is within the evaporator.

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Answer:

Common stock

Explanation:

Common stock is also regarded to as shares in which dividends are paid to the holders according to how profitable the organization is.

Common stock is a type of equity security and it is also the least considered in the case of bankruptcy due to its variability and the probability of stockholders not getting anything because of the debtor being insolvent.

Kepler's Third Law helps calculate the period of satellites orbiting Earth based on their radius, aiding in various applications.

Kepler's Third Law: The period of an orbiting object is related to the radius of its orbit. Using the formula n²a³ = GM (where n is the mean motion, a is the semi-major axis, and GM is the product of the gravitational constant and the Earth's mass), we can calculate the period of the satellite's circular orbit.

Calculations: For a satellite at an altitude of 20,200 km above Earth's surface (a = 26,578 km), with GM = 3.986005 x 10¹⁴ m³/s², the period T comes out to be 43,122 seconds.

Application: Understanding Kepler's laws helps in determining crucial parameters for artificial satellites orbiting Earth, aiding in satellite communication, weather observation, and other scientific endeavors.

Answer:

the answer is ture

Explanation:

because the energy substances must absorb in order to change from liquid to gas

Answer:

C. 1500.

Explanation:

750 / .5 = 1500.

Hope this helps & best of luck!

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The hydrostatic force on one end of the trough can be found using the formula F = pghA, where p is the density of the liquid, g is the acceleration due to gravity, h is the height of the liquid, and A is the area of the end of the trough. In this case, the ends of the trough are equilateral triangles with sides 4m long.

To find the hydrostatic force on one end of the trough, we can use the formula F = pghA, where F is the force, p is the density of the liquid, g is the acceleration due to gravity, h is the height of the liquid, and A is the area of the end of the trough. Since the ends of the trough are equilateral triangles, each side has a length of 4m. The area of an equilateral triangle is given by A = sqrt(3)/4 * s^2, where s is the length of the side. In this case, A = sqrt(3)/4 * (4m)^2 = 4sqrt(3)m^2. Plugging in the values, we have F = (835kg/m^3)*(9.8m/s^2)*h*(4sqrt(3)m^2).

The change in gravitational potential energy of the book is 9.81 J.

The change in gravitational potential energy is calculated as follows:

ΔGPE = m * g * Δh

where:

In this case, the mass of the book is 2 kg, the acceleration due to gravity is 9.81 m/s², and the change in height is 0.5 m (2 m - 1.5 m).

Therefore, the change in gravitational potential energy is:

ΔGPE = 2 kg * 9.81 m/s² * 0.5 m = 9.81 J

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Answer:

Magnetic compass

Explanation:

A magnetic field is a field that describes the magnetic effect of electric charges in a relative motion.

Magnetic field allows magnets to interact without contact. The principle involved in the function of the compass is that a magnetic field exerts a force on any moving charge and can be measured and detected by this effect.

Answer:

Magnetic compass

Explanation:

The magnetic compass is the most familiar compass type. It functions as a pointer to "magnetic north", the local magnetic meridian, because the magnetized needle at its heart aligns itself with the horizontal component of the Earth's magnetic field

Compasses are mainly used in navigation to find direction on the earth. This works because the Earth itself has a magnetic field which is similar to that of a bar magnet (see the picture below). The compass needle aligns with the Earth's magnetic field direction and points north-south.

Answer:

D. Alaska is in the half of Earth that's illuminated longer by sunlight.

Explanation:

Alaska is closer to the north poll than Florida causing longer day during the summer because Alaska is facing the sun (roughly) 20 hours out of the day.

If we do the simple equation of 4,000J subtracted by 2,500J  we can easily see that the energy that wasn't useful or wasted is 1,500J

Answer:

4000J transfer and 2500J stored which means you have an energy produce power equals to 6500J. Therefore take 6500J and subtract it with 4000J transfer and there you left with 2500J. so the question is, how much energy is wasted? about 4000 of your energy is been transfer which means it moves out of the original source.

Explanation:

Answer:

65 years

Explanation:

The arc that ends at 4000 Hz intersects the 20 db hearing intensity at 65 years.

Answer:

65

Explanation:

Answer:

For a plane mirror, the image distance equals the object distance, so the image distance will increase as the object distance increases

The height of the image stays the same and the image distance increases.)

Explanation:

For plane mirrors, the object distance (is equal to the image distance. That is the image is the same distance behind the mirror as the object is in front of the mirror. If you stand a distance of 2 meters from a plane mirror, you must look at a location 2 meters behind the mirror in order to view your image

Answer:

True

Explanation:

This can be done when the output gear is rotating in a counterclockwise direction. The initial direction of the clockwise gear changes when it comes in contact with the counter clockwise rotating gear. This will thus cause the motor to change its direction due to the counter clockwise rotating gear.

Answer: higher temperature increases reaction rates for both endothermic and exothermic reactions

Explanation: i took the test

The wrong statement with the student's reasoning is Higher temperature increases reaction rates for both endothermic and exothermic reactions. Hence option A is correct.

When the reactant absorbs heat energy from the surroundings to form products is called an endothermic reaction. When the heat is absorbed from the surroundings, the system remains cooler and the enthalpy of the system increases.

When the energy is released in the form of heat to form the product is called an exothermic reaction. In this reaction, the temperature of the substance increases due to the release of heat, and the enthalpy of the system decreases.

If the temperature increases the reaction rates increase in the exothermic reaction and it decreases in the endothermic reaction. Hence, increases in temperature increases the reaction rates for both endothermic and exothermic reactions is wrong.

Hence, the ideal solution is A.

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