To determine the longest wavelength of electromagnetic radiation that can eject an electron from the metal, one can use the equation E = hc / λ, where E equals the work function, h is Planck's constant, c is the speed of light, and λ is the wavelength. Rearranging it as λ = hc / φ and putting the given value of work function and constant values, one can find the required wavelength.
Explanation:To calculate the longest wavelength of electromagnetic radiation that can eject an electron from the surface of the metal, we need to use the equation which describes the relationship between the energy of a photon (E) and its wavelength (λ). This equation is:
E = hc / λ
Where:
E is the energy of the photon (which is equal to the work function φ in this case), h is Planck's constant (6.63 x 10-34 Js), c is the speed of light (3 x 108 m/s), and λ is the wavelength.
Given the work function φ (7.40×10-19J) and other constant values, we can rearrange this formula to calculate λ:
λ = hc / φ
The result will give you the longest wavelength of electromagnetic radiation that can eject an electron from the metal surface.
Learn more about Electromagnetic radiation and work function here:https://brainly.com/question/10759891
#SPJ3
The longest wavelength of electromagnetic radiation that can eject an electron from the surface of a piece of the metal is [tex]2.69 \times 10^{-7}\)[/tex] meters.
We use the photoelectric effect equation:
[tex]\[ E = h \nu \][/tex]
where [tex]\( E \)[/tex] is the energy of the photon, [tex]\( h \)[/tex] is Planck's constant, and [tex]\( \nu \)[/tex] is the frequency of the radiation.
The energy of the photon must be at least equal to the work function [tex](\( \phi \))[/tex] of the metal for the electron to be ejected. Therefore, we have:
[tex]\[ E = \phi \][/tex]
[tex]\[ h \nu = \phi \][/tex]
Since [tex]\( \nu = \frac{c}{\lambda} \)[/tex], where [tex]\( c \)[/tex] is the speed of light and [tex]\( \lambda \)[/tex] is the wavelength of the radiation, we can rewrite the equation as:
[tex]\[ h \frac{c}{\lambda} = \phi \][/tex]
Solving for [tex]\( \lambda \)[/tex], we get:
[tex]\[ \lambda = \frac{h c}{\phi} \][/tex]
Given that [tex]\( h = 6.626 \times 10^{-34}\)[/tex] Js (Planck's constant), [tex]\( c = 3.00 \times 10^8\)[/tex] m/s (speed of light), and [tex]\( \phi = 7.40 \times 10^{-19}\)[/tex] J (work function), we can plug in these values to find [tex]\( \lambda \)[/tex]:
[tex]\[ \lambda = \frac{6.626 \times 10^{-34} \text{ Js} \times 3.00 \times 10^8 \text{ m/s}}{7.40 \times 10^{-19} \text{ J}} \][/tex]
[tex]\[ \lambda = \frac{1.9878 \times 10^{-25} \text{ Jm/s}}{7.40 \times 10^{-19} \text{ J}} \][/tex]
[tex]\[ \lambda = 2.6862 \times 10^{-7} \text{ m} \][/tex]
An iron robot falls from rest at a great height. neglecting air resistance, what is its speed after it has fallen for 3.5 seconds? 13.3 m/s 9.8 m/s 34.3 m/s 9.8 m/s2
Consider a space pod somewhere between earth and the moon, at just the right distance so that the gravitational attractions to earth and the moon are equal. IS this location nearer earth or the moon?
The location in space where Earth's and the Moon's gravitational attractions are equal is closer to the Moon due to its significantly lesser mass compared to Earth. By applying Newton's law of universal gravitation, it can be deduced that this point must be nearer the Moon, as Earth's stronger gravitational force diminishes with increasing distance.
Explanation:The gravitational attraction between two objects depends on both their masses and the distance between them, according to Newton's law of gravitation. The force of gravity is proportional to the product of the two masses and inversely proportional to the square of the distance between their centers of mass. Based on the data provided, the Earth's gravitational force is much stronger than that of the Moon due to its greater mass. However, as the distance from the Earth increases, its gravitational pull weakens.
Given that the mass of the Moon is about 1/81 of the Earth's mass and the distance from the Earth to the Moon is approximately 3.80×105 km, there exists a point where the gravitational forces exerted by Earth and the Moon on an object are equal, known as the Lagrange point L1. This point is closer to the Moon than to Earth because the Moon's weaker gravitational force requires a shorter distance to match the stronger gravitational force of the Earth. To find this exact point, one would use the formula from Newton's law of gravitation and set the forces equal to each other, solving for the distance from Earth at which this equilibrium occurs.
Considering the information provided about the distances and gravitational forces, we can infer that the space pod mentioned in the question, at the point where Earth's and the Moon's gravity cancel each other out, would indeed be closer to the Moon. This is a consequence of the vast difference in mass between the Earth and the Moon and the inverse-square law of gravity.
(ENVIRONMENTAL SCIENCE NOT PHYSICS)
7. gradually taking over farmland over a long period of time is known as commodities. True or False
8. The 2002 farm bill gives money to farmers who grow crops like wheat and soybeans but not to fruit and vegetable farmers. True or False
9. some farmers have been selling their land to developers because it is more cost efficient to do so than to grow crops. True or False
10. The FBI regulates the use of pesticides in agricultural crops. True or False
Which of these pollutants is transferred from soil to water by organic pesticides and fertilizer runoff from farms?
A coliform
B oxygen
C carbon
D phosphates
Answer: Option D
Explanation: The fertilizers consists of the phosphates and nitrates. These aids in the growth of the plant. Fertilizers used by the plants are sometimes carried away due to the rain.
The run off from the agricultural field contains phosphates that is transferred from the field to the nearby water bodies.
When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What type of learning is Ian demonstrating?
ANSWER: Ian is demonstrating a typical example of Observational Learning. An observational learning is a learning pattern which happens by observing the behavior of others. People generally follows a role model such as parent, sibling, relative or teachers and imitate them while they are doing their work, particularly in childhood. There are four steps of observational learning which are Attention, Memory, Initiation and Motivation.
Consider two copper wires. one has twice the length of the other. how do the resistivities of these two wires compare?
The resistivity of two copper wires remains the same regardless of their lengths because resistivity is an intrinsic property of the material.
Comparing resistivities of two copper wires of different lengths but the same material, we need to understand that resistivity is an intrinsic property of the material and does not depend on the geometry of the wire. Therefore, regardless of whether one wire is twice as long as the other, the resistivity of both wires remains the same. This is a fundamental concept in the study of electrical resistance and materials.
Read the article by Michael Fumento, writer for the New York Post editorial blog, who does not support global warming. Back in 2005 I and others reviewed the entire hurricane record, which goes back over a century, and found no increase of any kind. Yes, we sometimes get bad storms—but no frequently now than in the past. The advocates simply ignored that evidence. Fact is, the earth was cooling and warming long before greenhouse gases could have been a factor. The [global warming supporters] have been proved wrong time and time again. Which best describes the reliability of the source? Nationally certified organizations are considered an unreliable source because the public can access their information. Charities are considered a reliable source because the public makes financial contributions to them. Editorial blogs are considered an unreliable source because the author may not have a science background. Editorial blogs are considered a reliable source because authors contribute to them regularly.
Answer:
the 3rd choice is the answer
Explanation:
What is the internal resistance of a 12.0-v car battery whose terminal voltage drops to 8.3 v when the starter motor draws 89 a ?
Final answer:
To find the internal resistance of a 12.0-V car battery with specific measurements, use Ohm's Law.
Explanation:
Internal resistance of a battery can be calculated using Ohm's Law, where internal resistance = (emf - terminal voltage) / current. In this case, with an EMF of 12.0 V, terminal voltage of 8.3 V, and current of 89 A, the internal resistance would be calculated as (12.0 V - 8.3 V) / 89 A.
This gives an internal resistance of approximately 0.0427 ohms.
A thermometer is taken from an inside room to the outside, where the air temperature is 30° f. after 1 minute the thermometer reads 80° f, and after 5 minutes it reads 55° f. what is the initial temperature of the inside room? (round your answer to two decimal places.)
To determine the initial temperature of the inside room, we can convert the given temperatures from Fahrenheit to Celsius and calculate the temperature change. By using the temperature change and the final temperature in Celsius, we can find the initial temperature in Celsius. The initial temperature of the inside room is approximately 27.22°C.
Explanation:To find out the initial temperature of the inside room, we can use the relationship between Fahrenheit and Celsius scales. We know that 30°F is equal to -1.11°C, and 80°F is equal to 26.67°C. By converting these temperatures to Celsius, we can determine the temperature change. Then, using the final temperature of 55°F, we can calculate the initial temperature using the temperature change.
To convert Fahrenheit to Celsius, we use the formula:
TC = (TF - 32) × (5/9)
By plugging in the given temperatures, we find:
TC1 = (30 - 32) × (5/9) ≈ -1.11°C
TC2 = (80 - 32) × (5/9) ≈ 26.67°C
Next, we calculate the temperature change:
ΔT = TC2 - TC1 = 26.67 - (-1.11) = 27.78°C
Finally, we use ΔT and the final temperature (TC=55°C) to find the initial temperature:
Initial temperature = final temperature - ΔT
Initial temperature ≈ 55 - 27.78 ≈ 27.22°C
Learn more about converting temperatures, calculating temperature change here:https://brainly.com/question/33386247
#SPJ12
A common cylindrical copper wire used in a lab is 841 m long. Find the radius (in mm) of a wire necessary to have 0.5 Ohms of resistance. (The resistivity of copper at room temperature is 1.68×10-8 Ohm × meter). Express the answer (only numerical value) to one decimal place.
Elements may have similar properties and we can use the periodic table to help us determine what they are. These three elements are alike in many ways but they do not share ALL properties. What property do these elements NOT have in common? Mg, K, and Ca A) Same phase at room temperature. B) Good conductors of electricity. C) Same number of valence electrons. D) They form cations (positive ions).
The properties that Mg, Ca and K do not have in common is "same number of valence electrons."
In the periodic table, elements are classified into groups and periods. The groups of elements show the relationships between them in terms of reactivity, valence electrons and physical properties.
Elements in the same group have the same number of valence electrons. However, Ca, K and Mg are not in the same group so they can not have the same number of valence electrons. Ca and Mg has two valence electrons while K has only one valence electron.
Learn more: https://brainly.com/question/13440572
The spacing of gravitational field lines indicates the _____ of the field.
A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.02t3 (a) find the velocity at time t (in ft/s). v(t) = .04t3−.06t2 (b) what is the velocity after 1 second(s)? v(1) = -.02 ft/s (c) when is the particle at rest? t = s (smaller value) t = s (larger value) (d) when is the particle moving in the positive direction? (enter your answer using interval notation.) (e) find the total distance traveled during the first 12 seconds. (round your answer to two decimal places.) ft (f) find the acceleration at time t (in ft/s2). a(t) = find the acceleration after 1 second(s). a(1) = ft/s2
The velocity function can be found by differentiating the position function. The velocity after 1 second is -0.02 ft/s. The particle is at rest at t = 0 and t = 1.5 seconds.
Explanation:(a) To find the velocity at time t, we can differentiate the position function. The derivative of f(t) = 0.01t^4 - 0.02t^3 is v(t) = 0.04t^3 - 0.06t^2. So, the velocity function is v(t) = 0.04t^3 - 0.06t^2 ft/s.
(b) To find the velocity after 1 second, we substitute t = 1 into the velocity function. v(1) = 0.04(1)^3 - 0.06(1)^2 = -0.02 ft/s.
(c) The particle is at rest when its velocity is equal to zero. To find the time(s) the particle is at rest, we set v(t) = 0 and solve for t. So, the particle is at rest at t = 0 and t = 1.5 seconds.
(d) The particle is moving in the positive direction when its velocity is positive. To find the time(s) the particle is moving in the positive direction, we look for the intervals where v(t) > 0. The particle is moving in the positive direction when 0 < t < 1.5 seconds.
(e) The total distance traveled during the first 12 seconds can be found by finding the area under the velocity-time graph. We integrate v(t) from 0 to 12 seconds. The total distance traveled during the first 12 seconds is approximately 96 ft.
(f) To find the acceleration at time t, we differentiate the velocity function. The derivative of v(t) = 0.04t^3 - 0.06t^2 is a(t) = 0.12t^2 - 0.12t ft/s^2.
(g) To find the acceleration after 1 second, we substitute t = 1 into the acceleration function. a(1) = 0.12(1)^2 - 0.12(1) = 0 ft/s^2.
A stone is thrown upward at an angle. what happens to the horizontal component of its velocity as it rises? as it falls?
The horizontal component of the velocity of a stone thrown upward at an angle remains constant during its flight, as there is no horizontal force to affect it. This is due to the principles of projectile motion in physics. Gravity only affects the vertical velocity, not the horizontal.
Explanation:In physics, the motion of a projectile thrown at an angle can be separated into its vertical and horizontal components. Both of these components operate independently of each other. When a stone is thrown upward at an angle, the horizontal component of its velocity remains constant throughout the flight, under ideal conditions, because there's no horizontal force to cause acceleration or deceleration.
So, as the stone rises and falls, the horizontal velocity remains unchanged because gravity only affects the vertical component of the velocity. In this process known as projectile motion, gravity pulls the object downward, causing the vertical component of velocity to decrease as the stone rises, and increase as it falls, but the horizontal component is unaffected by gravity. The effect of air resistance is typically ignored in basic physics problems, but in reality, it would gradually decrease the stone's velocity in both directions.
Learn more about Projectile Motion here:https://brainly.com/question/20627626
#SPJ12
In a heat engine, if 500 j of heat enters the system, and the piston does 300 j of work, what is the final internal (thermal) energy of the system if the initial energy is 1500 j ?
A woman wearing snowshoes stands safely in the snow. If she removes her snowshoes, she quickly begins to sink. Explain what happens in terms of force and pressure.
Antagonistic muscles move a body part in _____.
1. the same directionAnswer: Opposite direction
Skeletal muscles arise in antagonistic pairs where the muscles contract to produce opposite movements at the same joint. Antagonistic muscles move a body part in one direction by contraction, the other moves that part in opposite direction.
In addition, when a muscle contracts to produced movement, its antagonist relaxes to allow movement to take place such as biceps muscles is a flexor muscle for elbow joint and triceps is the antagonist.
an expert is someone who
Answer: D
expends the least amount of energy for the greatest result
Explanation:
edge 2020
If it takes a ball dropped from rest 2.069 s to fall to the ground, from what height h was it released?
During the forging process for a steel sword, the blacksmith places a hot iron blank into a cold bucket of water. Which of the following happens? A. The water molecules move faster. B. The steel molecules move faster. C. The water molecules move slower. D. The steel molecules do not change speed
What current flows through a 2.62 cm diameter rod of pure silicon that is 23.5 cm long, when 1000 v is applied to it? (such a rod may be used to make nuclear particle detectors, for example.) the resistivity of pure silicon is 2.30 103 ω · m?
A 0.450-kg hammer is moving horizontally at 7.00 m/s when it strikes a nail and comes to rest after driving the nail 1.00 cm into a board. (a) calculate the duration of the impact. (b) what was the average force exerted on the nail?
(a) The duration of impact of the hammer is [tex]\fbox{\begin\\1.43 \times {10^{ - 3}}\,{\text{s}}\end{minispace}}[/tex] .
(b) The average force exerted on the nail is [tex]\fbox{\begin\\2205\,{\text{N}}\end{minispace}}[/tex].
Further explanation:
When hammer hit the nail it got impacted by the hit and get into the board. This insertion in the board take time which is called duration of impact. The force exerted on the nail is directly proportional to the acceleration of the nail.
Given:
The speed of hammer is [tex]7\,{\text{m/s}}[/tex].
The distance of nail which is inserted in the board is [tex]1\,{\text{cm}}[/tex].
The mass of the hammer is [tex]0.450\,{\text{Kg}}[/tex].
Concept used:
The rate of change of displacement of a body in unit time is called speed of the body. It is a scalar quantity.
The expression for the speed of the body is given as.
[tex]v = \dfrac{s}{t}[/tex]
Rearrange the above expression for the time.
[tex]t=\dfrac{s}{v}[/tex] …… (1)
Here, [tex]s[/tex] is the distance covered, [tex]v[/tex] is the speed of body and [tex]t[/tex] is the time.
According to Newton’s second law of motion “the rate of change of momentum is equal to the force applied on the body.”
The expression for the newton’s law is given as.
[tex]F = ma[/tex] ……. (2)
The expression for the acceleration of the body is given as.
[tex]\fbox{\begin\\a = \dfrac{{\left( {v - u} \right)}}{t}\end{minispace}}[/tex] …… (3)
Here, [tex]u[/tex] is the initial velocity and [tex]v[/tex] is the final velocity.
Substitute [tex]1\,{\text{cm}}[/tex] for [tex]s[/tex] and [tex]7\,{\text{m/s}}[/tex] for [tex]v[/tex] in equation (1).
[tex]\begin{aligned}t&=\frac{{1\,{\text{cm}}}}{{7\,{\text{m/s}}}}\\&=\frac{{1\,{\text{cm}}\left( {\frac{{1\,{\text{m}}}}{{100\,{\text{cm}}}}} \right)}}{{7\,{\text{m/s}}}}\\&=1.43 \times {10^{ - 3}}\,{\text{s}} \\ \end{aligned}[/tex]
Substitute [tex]1.43 \times {10^{ - 3}}\,{\text{s}}[/tex] for [tex]t[/tex], for[tex]0\,{\text{m/s}}[/tex] and [tex]v[/tex] for in equation (3).
[tex]\begin{gathered}a= \frac{{\left( {0\,{\text{m/s}} - 7\,{\text{m/s}}} \right)}}{{\left( {1.43 \times {{10}^{ - 3}}\,{\text{s}}} \right)}} \\= \left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right) \\ \end{gathered}[/tex]
Substitute[tex]\left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right)[/tex] for [tex]a[/tex] and [tex]0.450\,{\text{Kg}}[/tex] for [tex]m[/tex] in equation (2).
[tex]\begin{aligned}F&=\left( {0.450\,{\text{Kg}}} \right)\left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right)\\&=- 2209\,{\text{N}} \\ \end{aligned}[/tex]
Thus, the duration of impact is[tex]1.43 \times {10^{ - 3}}\,{\text{s}}[/tex] and the force exerted on the nail is [tex]2209\,{\text{N}}[/tex] in the opposite direction.
Learn more:
1. Motion under friction https://brainly.com/question/7031524.
2. Conservation of momentum https://brainly.com/question/9484203.
3. Force on a body https://brainly.com/question/6125929.
Answer Details:
Grade: College
Subject: Physics
Chapter: Kinematics
Keywords:
Acceleration, force, acceleration due to gravity, friction, normal, weight, mass, motion, impact, nail, hammer, acceleration, duration of impact, 0.450 kg, 7 m/s, 2205 N,1.429*10^-3 sec, 1.43*10^-3 sec.
The duration of the impact is 0.133 seconds.
The average force exerted on the nail was 5800 N.
(a) Let's use the following equations to solve this problem:
m = 0.450 kg
v_i = 7.00 m/s
v_f = 0 m/s
d = 0.01 m
where:
m is the mass of the hammer
v_i is the initial velocity of the hammer
v_f is the final velocity of the hammer (after it strikes the nail)
d is the distance that the nail is driven into the board
We know that the hammer comes to rest after it strikes the nail, so v_f = 0. We can also set the kinetic energy of the hammer before the impact equal to the work done by the force exerted by the nail on the hammer during the impact.
[tex]KE_i = W\dfrac{1}{2}mv_i^2 = Fd\dfrac{1}{2}(0.450 kg)(7.00 m/s)^2 = F(0.01 m)F = 5800 N[/tex]
The duration of the impact can be calculated using the following equation:
[tex]t = \dfrac{d}{v_i}t = \dfrac{0.01 m}{7.00 m/s}t = 0.0133 s[/tex]
(b) The average force exerted on the nail is equal to the force exerted by the hammer on the nail divided by the duration of the impact.
F_avg = F / t
F_avg = 5800 N / 0.0133 s
F_avg = 5800 N
Therefore, the average force exerted on the nail was 5800 N.
To know more about the Board, here
https://brainly.com/question/34682939
#SPJ3
in gas exchange, oxygen passes from the alveoli into the blood . True or false ?
A terrorist throws a grenade with a 6.00 second fuse off a building 150.0 m high at a speed of 10.0 m/s. If the angle at which the grenade is thrown is 30° below the horizontal, will the grenade explode before hitting the ground? What is the horizontal distance from the building at which the grenade will land.
When the particles of a medium move with simple harmonic motion, this means the wave is a __________. when the particles of a medium move with simple harmonic motion, this means the wave is a __________. harmonic wave sinusoidal wave sound wave standing wave transverse wave?
If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.
Explanation:
A body is considered to be performing the Simple Harmonic Motion if it repeats its motion in a particular path with a specific time period. The two and fro motion of the pendulum about a fixed mean position is termed as the Simple Harmonic Motion.
The motion of the simple pendulum repeats itself after a particular time period and it continuously retraces its path during the motion. Therefore, it is termed as the simple harmonic motion.
The wave depicting the motion of a body performing the simple harmonic motion is shown in the sinusoidal manner. The motion of the body from its mean position to its extreme and then from extreme position to its mean position shows the positive cycle of the sinusoidal waveform.
The motion of the pendulum on the other side of the mean position of the pendulum represents the other half of the sinusoidal waveform.
Thus, If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.
Learn More:
A property is a characteristic of a substance that can be observed and does not change the identity of the substance brainly.com/question/859623The amount of kinetic energy an object has depends on its brainly.com/question/137098Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off. What is the net force acting on the refrigerator brainly.com/question/4033012Answer Details:
Grade: High School
Chapter: Simple Harmonic Motion
Subject: Physics
Keywords:
simple, harmonic, SHM, motion, pendulum, oscillates, mean position, extreme, repeats, time period, sinusoidal.
You hop on the carousel horse. The attendant flips the switch and you move up and down, around and around. When the ride ends, the attendant again flips the switch. The up and down motion stops, as you continue to move in a circular motion, gradually slowing to a stop. Why?
The acceleration of gravity at the surface of the moon is approximately 1/6 that at the surface of the earth (9.8 m/s2). what is the weight of an astronaut standing on the moon whose weight on earth is 210 lb?
The weight of an astronaut standing on the moon can be calculated using the equation weight = mass × acceleration due to gravity. By calculating the weight using the ratio of acceleration due to gravity on the moon compared to that on Earth, we find that an astronaut with a weight of 210 lb on Earth would weigh approximately 158.18 lb on the moon.
Explanation:The weight of an astronaut standing on the moon can be calculated using Newton's second law of motion. The formula to calculate weight is weight = mass × acceleration due to gravity. Since the acceleration due to gravity on the moon is approximately 1/6 that at the surface of the earth, we can calculate the weight using this ratio.
First, we need to convert the weight on earth from pounds to kilograms. Since 1 kilogram is approximately 2.2 pounds, we divide the weight on earth (210 lb) by 2.2 to get the weight in kilograms.
Next, we multiply the weight in kilograms by the acceleration due to gravity on the moon (1/6 of 9.8 m/s^2) to find the weight of the astronaut on the moon.
This results in a weight of approximately 158.18 lb on the moon for an astronaut whose weight on earth is 210 lb.
Learn more about Weight on the moon here:https://brainly.com/question/20195594
#SPJ6
A research van de graaff generator has a 2.00-mdiameter metal sphere with a charge of 5.00 mc on it. (a) what is the potential near its surface? (b) at what distance from its center is the potential 1.00 mv? (c) an oxygen atom with three missing electrons is released near the van de graaff generator. what is its energy in mev when the atom is at the distance found in part b?
Part A: The potential on the surface of the charged sphere is [tex]4.5 \times 10^7[/tex] volts.
Part B: The distance is [tex]4.5 \times 10^{10}[/tex] m from the center of the sphere where the potential is 1 mv.
Part C: The energy of the oxygen atom found at the distance of [tex]x = 4.5 \times 10^{10} \;\rm m[/tex] is 3me V.
How do you calculate the potential?
Given that the diameter of the sphere is 2.00 m and the charge of 5.00 mc.
Part A
The potential on the surface of a charged sphere is given below.
[tex]V = k\dfrac {Q}{R}[/tex]
Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.
[tex]V = 8.99 \times 10^9\times \dfrac {5 \times 10^{-3}}{\dfrac {2}{2}}[/tex]
[tex]V = 4.5 \times 10^7 \;\rm Volts[/tex]
Hence the potential on the surface of the charged sphere is [tex]4.5 \times 10^7[/tex] volts.
Part B
The potential of 1 mv generated at a certain distance x from the centre of the sphere is given below.
[tex]V_x = k \dfrac {Q}{x}[/tex]
[tex]1 \times 10^{-3} = 8.99 \times 10^9 \times \dfrac{5 \times 10^{-3}} {x}[/tex]
[tex]x = 4.5 \times 10^{10} \;\rm m[/tex]
Hence the distance is [tex]4.5 \times 10^{10}[/tex] m from the center of the sphere where the potential is 1 mv.
Part C
Given that an oxygen atom with three missing electrons is released near the van de-Graaff generator. It means that the charge Q = +3e
The electric potential energy of a charged particle located at some point with voltage V is given below.
[tex]U = QV[/tex]
At the distance found in part b, which is [tex]x = 4.5 \times 10^{10} \;\rm m[/tex], the energy of the oxygen atom is,
[tex]U = +3e \times 1 \times 10^{-3}[/tex]
[tex]U = 3me \;\rm V[/tex]
Hence the energy of the oxygen atom found at the distance of [tex]x = 4.5 \times 10^{10} \;\rm m[/tex] is 3me V.
To know more about potential, follow the link given below.
https://brainly.com/question/1313684.
The maximum allowed power dissipation for a 27.3-ω resistor is stated to be 10.0 w. find the largest current that this resistor can take safely without burning out.
The amount of flow of charge per unit time is known as the current. The largest current that this resistor can take safely without burning out will be 0.6 amperes.
What is power dissipation in a resistor?The process of losing power in the form of heat as a result of the main activity is known as power dissipation. Dissipation of power is a natural occurrence.
All of the circuit's resistors that have a voltage drop across them will dissipate power. Due to the conversion of electrical energy to thermal energy, all resistors will have a power rating.
The power dissipated on a resistor is given as
P = I²R
I is current flowing through it
R is the resistance
[tex]\rm {P = I^2R}\\\\I=\sqrt{\frac{P}{R} }\\\\I=\sqrt{\frac{10}{27.36\\}[/tex]
I = 0.6 A
Hence the largest current that this resistor can take safely without burning out will be 0.6 amperes.
To learn more about the power dissipated on a resistor refer to the link;
https://brainly.com/question/10728846
You charge an initially uncharged 65.7-mf capacitor through a 39.1-Ï resistor by means of a 9.00-v battery having negligible internal resistance. find the time constant of the circuit. what is the charge of the capacitor 1.95 time constants after the circuit is closed? what is the charge after a long time?