The zone of earthquakes and volcanoes surrounding the pacific ocean is called

Answer

A molecule with seesaw molecular geometry has a bond angle of 90° and 120°.

Seesaw is a type of molecular geometry where there are four bonds attached to a central atom.

Bond is observed in the shape of playground seesaw that is why it is known as a seesaw bond.

Four bonds attached to the central bond formed results as tetrahedral or square planar geometry.

In see-saw, shape maximizes the bond angle of the lone pair and the other atoms in the molecule.

lone pair in the equatorial position offer 120 and 90-degree bond angles whereas bond angle will be 90-degree bond angles if placed at axial position.

A molecule with seesaw molecular geometry has bond angles that are less than 120 degrees for equatorial positions and less than 90 degrees for axial positions, due to lone pair repulsion. Hence the correct option is 1.

Bond Angles in Seesaw Molecular Geometry

A molecule with a seesaw molecular geometry has four nuclei and one lone pair of electrons. This molecular structure is based on a trigonal bipyramidal geometry but with one equatorial position occupied by a lone pair. As a result, the bond angles are adjusted due to electron pair repulsion.

The bond angles for a seesaw geometry are:

The correct question is:

A molecule with a seesaw molecular geometry has a bond angle of

1. <120 for equatorial bonds and <90 for axial bonds.

2.180

3. <90

4. 120 for equatorial bonds and 90 for axial bonds.

5.120

Answer:

[tex]0.0172rad/day=1.99x10^{-7}rad/second[/tex]

Explanation:

The definition of angular velocity is as follows:

[tex]\omega=2\pi f[/tex]

where [tex]\omega[/tex] is the angular velocity, and [tex]f[/tex] is the frequency.

Frequency can also be represented as:

[tex]f=\frac{1}{T}[/tex]

where [tex]T[/tex] is the period, (the time it takes to conclude a cycle)

with this, the angular velocity is:

[tex]\omega=\frac{2\pi}{T}[/tex]

The period T of rotation around the sun 365 days, thus, the angular velocity:

[tex]\omega=\frac{2\pi}{365days}=0.0172rad/day[/tex]

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:

Firt conveting to hous

[tex]365days(\frac{24hours}{1day} )=8760hours[/tex]

then to minutes

[tex]8760hours(\frac{60minutes}{1hour} )=525,600minutes[/tex]

and finally to seconds

[tex]525,600minutes(\frac{60seconds}{1minute})=31,536x10^3seconds[/tex]

thus, angular velocity in rad/second is:

[tex]\omega=\frac{2\pi}{31,536x10^3seconds}=1.99x10^{-7}rad/second[/tex]

Answer: False

Explanation:

Using the angular frequency formula derived from Hooke's law we have :

[tex]\omega =\sqrt{\frac{ k }{ m }} [/tex]

[tex]{\omega}^{ 2 }=\frac {k}{m}[/tex]  

where k- is Hooke's constant

           m- is mass attached to a spring

According to the formula the mass is inversely proportional to the square of the angular frequency angular  which means that increasing the mass attached to the spring will decrease the angular frequency.

The statement is false. Increasing the mass attached to a spring will decrease, not increase, the angular frequency of its vibrations due to the inverse proportional relationship between mass and angular frequency in a mass-spring system.

The statement, 'Increasing the mass attached to a spring will increase the angular frequency of its vibrations', is false. According to the principles of simple harmonic motion, the angular frequency of a mass-spring system fundamentally depends on the mass and the force constant (spring constant) of the system. However, the relationship is inversely proportional; meaning that increasing the mass will actually decrease the angular frequency. This is because the angular frequency (ω) is calculated as the square root of the ratio of the force constant (k) to the mass (m: ω = sqrt(k/m). Hence, increasing the mass causes a decrease in the angular frequency, which consequently increases the period of the motion - the time it takes for one complete cycle of vibration to pass a given point.

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Answer:

The south-component of its velocity is the same

Explanation:

You could say several things concerning the object.

These are some of them:

- The south-component of its velocity is the same.

- Its speed (module of the velocity) is greater now.

- The velocity has now a west-component.

- The object is now moving due west of south.

- The object did not move in a straight line.

Final answer:

After experiencing a westward net force, the object will change its velocity and once the force is removed, it will continue at a new constant velocity in a direction that combines the original southward and the newly added westward components.

Explanation:

According to Newton's first law of motion, an object at rest or moving with a constant velocity will continue to do so unless acted upon by a net force. In the scenario provided, the object initially moving due south at a constant velocity experiences a net force acting due west. This force will cause the object to accelerate in the direction of the force, which is westward, changing the object's velocity.

After the short time interval, when the net force becomes zero, the object will then move at a constant velocity in a new direction that is the resultant of the south and west velocity components.

Answer:

a) [tex] F=32.0 N [/tex]

b) [tex] T_{1}=19.2 N [/tex]

c) [tex] T_{2}= 16.0 N [/tex]

d) [tex] T_{3}=3.2 N [/tex]  

Explanation:

Let's do the free body diagram per each body. In this particular case the rope has a mass so we have:

First block

[tex] F-T_{1}-m_{1}g=m_{1}a [/tex]                           (1)

Frist rope

[tex] T_{1}-T_{2}-m_{r}g=m_{r}a [/tex]                     (2)

Second block

[tex] T_{2}-T_{3}-m_{2}g=m_{2}a [/tex]                   (3)

Second rope

[tex] T_{3}-m_{r}g=m_{r}a [/tex]                               (4)

When,

T

₁ is the tension at the top of the rope 1

T

₂  is the tension at the bottom of the rope 1

T

₃ is the tension at the top of the rope 2

Now, if we add all equations from (1) to (4), we will get the value of F,

[tex] F-(m_{1}+m_{2}+2m_{r})g=(m_{1}+m_{2}+2m_{r})a[/tex]

a) Solving this equation for F:

[tex] F=(m_{1}+m_{2}+2m_{r})(a+g)[/tex]

[tex] F=(m_{1}+m_{2}+2m_{r})(a+g)[/tex]

[tex] F=32.0 N[/tex]

b) Using the equation (1), we can find T₁

[tex] T_{1}=F-m_{1}(g+a)[/tex]

[tex] T_{1}=19.2 N[/tex]

c) Let's use the equation (2) to find T₂

[tex] T_{2}=T_{1}-m_{r}(g+a) [/tex]

[tex] T_{2}= 16.0 N [/tex]

d) Using the equation (4) we can find T₃:

[tex] T_{3}=m_{r}(a+g) [/tex]  

[tex] T_{3}=3.2 N [/tex]  

Have a nice day!

Answer:

294.3 N

Explanation:

In this situation, we are told that the crate is not accelerating in the horizontal plane. But also it is not accelerating in the vertical plane. Meaning that the sum of all vertical forces add up to zero.

Fnet =  ma

Weight + Normal force = mass *  acceleration

-(30 kg * 9.81 m/s²) + Normal force = 30.0 kg * 0 m/s²

                                  Normal force = 294.3 N

The normal force exerted by the floor on the crate is equal to the weight of the crate when it's at rest. It can be calculated by multiplying mass and acceleration due to gravity. For a crate with a mass of 30.0 kg, the normal force would be 294 N.

The key to answering this question involves understanding how friction and forces work. In this scenario, the crate is not accelerating, so the forces acting on it are balanced, meaning the upward normal force equals the downward gravitational force. The normal force exerted by the floor on the crate is determined by the weight of the crate, which can be calculated using the formula for weight, W = mg (mass times gravity). Here, the mass m is 30.0 kg and the acceleration due to gravity g is 9.8 m/s².

So, we can substitute these values into the formula to find the weight: W = (30.0 kg) * (9.8 m/s²) = 294 N. This weight also equals the normal force since the crate is not moving vertically, so the normal force exerted by the floor on the crate is 294 N.

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Answer:

A. Antibodies against rabies given to someone who was bitten by a potentially rabid dog

Explanation:

passive immunization is the immunity or protection against certain infectious diseases by injecting antigens or antibodies to the blood stream or certain antibodies can be gotten through colostrum or breast milk.

for option A. Antibodies against rabies given to someone who was bitten by a potentially rabid dog. the immunity against rabies infection is administer to the person

For option B:is only telling us the type of infection but not stating the immunity administered

option c can be fairly correct, because its another method of immunization but its not passive immunization

Answer:

[tex]P=1000000Pa=1MPa=1000kPa[/tex]

Explanation:

When the force that is applied is normally and uniformly distributed on a surface, the magnitude of the pressure is obtained by dividing the force applied on the corresponding area:

[tex]P=\frac{F}{A}[/tex]

Where:

[tex]P=Pressure\hspace{3}in\hspace{3}Pa.\\F=Force\hspace{3}in\hspace{3}N\\A=Area\hspace{3}in\hspace{3}m^2[/tex]

Converting cm to m:

[tex]10cm*\frac{1m}{100cm} = 0.1m[/tex]

The area of a square is:

[tex]A=l^2=(0.1)^2=0.01m^2[/tex]

Therefore:

[tex]P=\frac{1.00\times10^4}{0.01} =1000000Pa=1MPa=1000kPa[/tex]

Answer:

c. P₁/T₁=P₂/T₂

Explanation:

neither Avogadro’s, Charles’, or Boyle’s law formula can be used, since some parameters like volume is not given,

to find P₂, given P₁, T₁, and T₂ we will therefore use Gay-lussac's law.

gay lussacs law state that, provided volume is kept constant, pressure is directly proportional to temperature.

the volume volume is said to be filled, i.e its is kept constants when temperature is change

The new electric force is equal to the original force

Explanation:

The electrostatic force between two charges is given by Coulomb's law:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the charges

In this problem, at the beginning we have

[tex]q_1 = -q\\q_2 = -q\\r=r[/tex]

So the force is

[tex]F=k\frac{(-q)(-q)}{r^2}=\frac{kq^2}{r^2}[/tex]

Later, the amount of both charges is doubled, so:

[tex]q_1' = -2q\\q_2' = -2q[/tex]

and the separation is doubled as well:

[tex]r'=2r[/tex]

So the new force is:

[tex]F'=k\frac{(-2q)(-2q)}{(2r)^2}=\frac{kq^2}{r^2}=F[/tex]

This means that the new electric force is equal to the original force.

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Answer:

What happens inside a star while it expands into a sunlight is that It is fusing hydrogen into helium in a shell outside the core after which the fused hydrogen in the shell outside the core generates enough thermal pressure to push the upper layers outward.

Answer:

Explanation:

We shall apply law of  conservation of mechanical energy for projectile being thrown .

Total energy on the surface = total energy at height h required

a ) At height h , velocity = .351 x ( 2 GM/R x h )

[tex]\frac{-GM}{R} + \frac{m\times(.351\times\sqrt{2GM})^2 }{2R } = \frac{-GMm}{R+h} + 0[/tex]

[tex]\frac{-GMm}{R} +\frac{1}{2}\times  \frac{-2GMm}{R} \times0.123=\frac{-GMm}{R+h}[/tex]

[tex]\frac{0.877GMm}{R} =\frac{-GMm}{R+h}[/tex]

h = .14 R

b )

[tex]\frac{-GM}{R} + \frac{m\times(.351\times2GM) }{2R } = \frac{-GMm}{R+h} + 0[/tex]

[tex]\frac{-0.649GMm}{R} = \frac{-GMm}{R+h}[/tex]

h = .54 R

c ) least initial mechanical energy required at launch if the projectile is to escape Earth

= GMm / R + 1/2 m (2GM/R)

= 0

Answer:

2.08335 hours

Explanation:

T = Time period = 12.5 h

Angular frequency is given by

[tex]\omega=\frac{2\pi}{T}\\\Rightarrow \omega=\frac{2\pi}{12.5}\\\Rightarrow \omega=0.50265\ rad/h[/tex]

The distance moved from highest to lowest level is given by

[tex]d=2x_{m}\\\Rightarrow x_m=\frac{d}{2}\\\Rightarrow x_m=0.5d[/tex]

At the ocean surface [tex]x_m=0.25d[/tex]

[tex]x_0=x_mcos(\omega t+\phi)[/tex]

[tex]\phi[/tex] = Phase constant = 0 as clock is started at [tex]x_0=x_m[/tex]

[tex]0.25d=0.5dcos(0.50265t)\\\Rightarrow cos(0.50265t)=\frac{0.25}{0.5}\\\Rightarrow 0.50265t=cos^{-1}0.5\\\Rightarrow t=\frac{1.047}{0.50265}\\\Rightarrow t=2.08335\ h[/tex]

The time taken for the water to fall the distance is 2.08335 hours

The depth of the well can be calculated using the formula for gravitational potential energy, taking the work done to lift the bucket as equal to the gravitational potential energy gained by the bucket. This gives us the equation: Depth of the well (h) = Work done (W) / (mass (m) * acceleration due to gravity (g)), which we solve to find the depth.

The physics concept involved in this question is called gravitational potential energy, which refers to the energy an object possesses because of its higher position in a gravity field.

In such cases, the energy can be calculated using the formula for work, which is force times distance. When you're lifting an object, the force you're countering is the force of gravity on the object, which is its mass multiplied by the acceleration due to gravity (9.8 m/s^2). This amount of work is equivalent to the gravitational potential energy gained by the bucket when it is lifted.

So, the formula we'll use is: Work = mgh (mass * gravity * height)

We know the work done (5.92 kJ or 5920 J), the mass (25.9 kg) and the acceleration due to gravity (9.8 m/s^2). We want to find height (h), which in this context, means the depth of the well.

Rearranging the formula and solving for h gives us: h = Work / (m*g). By substituting the known values, h = 5920 J / (25.9 kg * 9.8 m/s^2).

By solving this, we get the depth of the well.

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Bio-gas is the naturally produced fossil fuel, a by-product when bacteria decompose organic material under anaerobic conditions.

Organic matter particularly waste material is broken down by bacteria through fermentation in an environmental condition without any presence of oxygen. This process of decomposition leads to formation of bio-gas with "carbon dioxide and methane" in a 2:3 ratio.

The above biological process is termed as bio-digestion or anaerobic digestion. Methane is flammable and thus bio-gas can be used as "energy source", a waste-to-energy transformation. The remaining decomposed matter is ideal as manure for plants due to its rich nutrient level.

Answer:

A.) A particle of water in a wave moves in a circular motion when viewed in cross section

Explanation:

Water waves are transverse waves. Waves transport energy, not water. As a wave crest passes, the water particles move in circular paths

The water particles don't move, they still end up in the place in which they began, the water particle moves up and down while the wave that passes through them moves in a perpendicular direction to the direction of the water particles moving up and down with respect to the crests and troughs of the wave (since water is a transverse wave). This will cause the wave to transverse in a circular path

The answer cannot be C because wavebase is equal to one-half the wavelength measured from still water level

Answer:

Explanation:

Given

Diameter of main rotor [tex]d_1=7.56 m[/tex]

Tail rotor [tex]d_2=1 m[/tex]

[tex]N_1=453 rev/min[/tex]

[tex]N_2=4137 rev/min[/tex]

[tex]\omega =\frac{2\pi N}{60}[/tex]

[tex]\omega _1=\frac{2\pi 453}{60}=47.44 rad/s[/tex]

[tex]\omega _2=\frac{2\pi 4137}{60}=433.28 rad/s[/tex]

Speed of the tip of main rotor[tex]=\omega _1\times r_1=47.44\times \frac{7.56}{2}=179.32 m/s[/tex]

Speed of tail rotor[tex]=\omega _2\times r_2=433.28\times \frac{1}{2}=216.64 m/s[/tex]

Answer:a)8.01 m/s

Explanation:

Given

mass of ball [tex]m=0.9 kg[/tex]

initial speed [tex]u=9 m/s[/tex]

launch angle [tex]\theta =27 [/tex]

As the projectile reaches its highest point its vertical velocity component becomes zero and there will only be horizontal component

velocity at highest Point [tex]v=u\cos \theta [/tex]

[tex]v=9\cos 27[/tex]

[tex]v=8.01 m/s[/tex]

(b)maximum height h

Maximum height is given by

[tex]H_{max}=\frac{u^2\sin^2 \theta }{2g}[/tex]

[tex]H_{max}=\frac{9^2\sin^2 (27)}{2\times 9.8}[/tex]

[tex]H_{max}=0.85 m[/tex]

Final answer:

The speed of the ball at its highest point is its horizontal velocity component, calculated using the cosine of the angle. The height reached by the ball is found using the kinematic equation for vertical motion, considering the initial vertical velocity and the acceleration due to gravity.

Explanation:

When addressing the question of a 0.90-kg ball thrown at an upward angle, we are dealing with a two-dimensional projectile motion problem in physics. This type of problem can be broken down into horizontal and vertical components. Since gravity acts only in the vertical direction, it does not affect the horizontal velocity of the projectile.

(A) Speed at the highest point: The speed of the ball at its highest point is solely the horizontal component of its initial velocity because the vertical component will be zero at that point. The horizontal velocity (
vx) can be calculated using
vx =
v cos(
θ). So,
vx = 9.0 m/s cos(27°).

(B) Maximum height: To find the maximum height, we need to consider the vertical component of the velocity (
vy) and the acceleration due to gravity (
g), which is -9.81 m/s² (negative sign indicates the direction is opposite to the velocity). The initial vertical velocity (
vy) is
v sin(
θ), thus
vy = 9.0 m/s sin(27°). We can then use the kinematic equation
v2 = u2 + 2as to find the maximum height (
h), where u is the initial velocity, s is the displacement, and a is the acceleration. At the highest point, the final vertical velocity (
v) is 0 m/s. Rearranging the equation to solve for
s, we get
s = v2 / (2g).

The speed of the ping-pong ball must be 97.8 m/s

Explanation:

The kinetic energy of an object is the energy possessed by an object due to its motion. It is calculated as

[tex]E_k = \frac{1}{2}mv^2[/tex]

where

m is the mass of the object

v is its speed

Here we have a bowling ball that has

Mass: m = 7.29 kg

Speed: v = 1.73 m/s

So its kinetic energy is

[tex]E_k = \frac{1}{2}(7.29)(1.73)^2=10.9 J[/tex]

Now we want the ping-pong ball to have the same kinetic energy, so

[tex]E_k = 10.9 J[/tex]

its mass is

[tex]m=2.28 g = 2.28\cdot 10^{-3} kg[/tex]

So, we can find the speed it should have by re-arranging the equation:

[tex]v=\sqrt{\frac{2E_k}{m}}=\sqrt{\frac{2(10.9)}{2.28\cdot 10^{-3}}}=97.8 m/s[/tex]

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The temperature at which hydrogen molecules would have a root-mean-square velocity equal to the Moon's escape velocity is approximately 112 million Kelvin.

The root-mean-square speed of an ideal gas is given by the equation: vrms = sqrt(3RT/M), where R is the ideal gas constant (8.314 J mol-1 K-1), T is the temperature in Kelvin, and M is the molar mass in kg/mol. To find the temperature necessary for hydrogen molecules to achieve the Moon’s escape velocity (2.38 km/s), we first need to convert the escape velocity to m/s and the molar mass of hydrogen to kg/mol.

So, 2.38 km/s is equal to 2380 m/s, and the molar mass of hydrogen is equal 2.016 g/mol, which is 0.002016 kg/mol. Then, we solve the equation (2380 = sqrt (3RT/0.002016)) for T to get the temperature.

By resolving this equation we find that the necessary temperature would be approximately 112 million Kelvin. Therefore, for hydrogen molecules to have a root-mean-square velocity equal to the Moon's escape velocity, they must be at this extremely high temperature.

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Answer:

In order from lowest urgency to highest, the sequence which properly ranks the product categories issued by the National Weather Service are as follows:

B- Outlook, Watch, Advisory, Warning.

Explanation:

An outlook for a hazardous weather describes the potential hazardous weather of concern in day 1 through 7. There are total two segments of the outlook, one for the marine zones and the second for the land based zones.  

A watch is issued when there is the possibility of hazardous weather within 48 hours, it does not guarantee that a hazardous weather is going to come, it just reminds the possibilities of any such weather to come.

Advisory comes third in the urgency ranking, we can explain this through an example: a winter weather advisory may be issued for amount of freezing rain or when there are chance of 2 to 4 inches of snow. And, in winter weather, an warning may be issued when there is one fourth inch or more of ice accumulation.

The National Weather Service orders their product categories based on urgency: Outlook, Watch, Advisory, and finally Warning. An outlook is prospective, a watch means conditions are favorable, an advisory means the event is likely, and a warning means the event is expected within 24 hours.

The National Weather Service issues their product categories in a sequence based on the impending urgency of the weather condition. The correct order from lowest to highest urgency is: Outlook, Watch, Advisory, and then Warning.

An Outlook is used when hazardous weather is possible over the next week. A Watch is used when conditions are favorable for a hazard to occur; it typically means there is a possibility of the occurrence within the next 48 hours. An Advisory is used when a hazardous event is occurring, imminent or likely, but it is considered less severe than a warning.

A Warning is issued when a hazardous weather event is occurring, imminent or has a very high probability of occurring; it typically means the event is expected within the next 24 hours. Therefore, the correct answer is B. Outlook, Watch, Advisory, Warning.

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Answer:

The speed of cart is 5.5 m/s.

Explanation:

Given that,

Mass of cart = 100 kg

Distance = 3 m

Speed = 6 m/s

We need to calculate the speed of cart

Using relation of centripetal force and normal force

[tex]N+mg=\dfrac{mv^2}{r}[/tex]

[tex]\dfrac{m}{2}+mg=\dfrac{mv^2}{r}[/tex]

Put the value into the formula

[tex]\dfrac{1}{2}+9.8=\dfrac{v^2}{3}[/tex]

[tex]v=\sqrt{3(\dfrac{1}{2}+9.8)}[/tex]

[tex]v=5.5\ m/s[/tex]

Hence, The speed of cart is 5.5 m/s.

Final answer:

The speed of the cart at the top of the loop is 4.24 m/s.

Explanation:

In order to find the speed of the cart at the top of the loop, we can use the principle of conservation of mechanical energy. The total mechanical energy of the cart is the sum of its gravitational potential energy and its kinetic energy. At the top of the loop, the gravitational potential energy is zero, so the total mechanical energy is equal to the kinetic energy. The kinetic energy of the cart is given by the formula KE = 1/2 * m * v^2, where m is the mass of the cart and v is its velocity.

Given that the mass of the cart is 100 kg and the radius of the loop is 3 m, we can first find the centripetal acceleration at the top of the loop using the formula a = v^2 / r. Plugging in the values, we get a = (6 m/s)^2 / 3 m = 12 m/s^2. Since the force exerted by the track on the cart at the top of the loop is half the cart's mass, we can use this force to find the net force acting on the cart. The net force is equal to the centripetal force, which is given by F = m * a. Plugging in the values, we get F = (1/2 * m) * a = (1/2 * 100 kg) * 12 m/s^2 = 600 N.

Since the net force equals the centripetal force, we can equate it to the formula F = m * v^2 / r. Plugging in the values, we get 600 N = 100 kg * v^2 / 3 m. Solving for v, we get v^2 = 600 N * 3 m / 100 kg = 18 m^2/s^2. Taking the square root of both sides, we find that v = sqrt(18 m^2/s^2) = 4.24 m/s.

Answer:

It has the greatest apparent brightness of any star in this region of the sky.

Explanation:

We can conclude that Sirius is brighter than the other stars by the question saying "Larger dots represent brighter stars, and a few of the brightest stars are identified."

It can be viewed that it has the greatest apparent brightness of any star in this region of the sky.

The brightest star in the sky at night is Sirius. It gets its name from the Greek word for 'glowing' or 'scorching.'

Sirius is known as the Dog Star because it is the brightest star in the Canis Major constellation. It's extremely bright because it's one of the stars closest to our sun. The name could be derived from ancient Egypt.

This star map depicts the stars as seen from Earth, centered on the constellation Canis Major. The brighter stars are represented by larger dots, and a few of the brightest stars are identified.

It has the highest apparent brightness of any star in this region of the sky, as can be seen.

Thus, this can be concluded regarding Sirius.

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Your question seems incomplete, the missing image is attached below:

Answer:

a)Time taken will be 2.783 s

b)Time taken will be 2.564 s

Explanation:

a)Since the pulley has mass ,

[tex]m_{1}g-T_{1}= m_{1}a//T_{2}-m_{2}g=m_{2}a[/tex] ------3

             αR = a ;                    ------1

[tex](T_{1} - T_{2})*R=m*R^{2}*(alpha)=5*R^{2}*\frac{a}{R}[/tex] ------2

solving these we get ,

[tex]a=\frac{4g}{33}[/tex]

∴

a)time taken :

[tex]s=ut+\frac{1}{2} at^{2}\\u=0\\a=\frac{4g}{33} \\s=4.6\\4.6=\frac{1}{2} * \frac{4*9.8}{33} *t^{2}\\t= 2.783 sec[/tex]

ANS : 2.783 sec

b)

In case of B, mass is zero.

Thus, there is no rotation of the pulley. this is equivalent to a normal 1 Dimension motion question

[tex]m_{1}g-T_{1}=m_{1}a\\T_{1}-m_{2}g=m_{2}a\\a= \frac{m_{1}-m_{2}}{m_{1}+m_{2}}g\\a=\frac{4g}{28} \\a=\frac{g}{7} \\a=1.4ms^{-2}[/tex]

Thus time t will be ,

[tex]s=\frac{1}{2} at^{2}\\4.6=\frac{1}{2}*1.4*t^{2}\\ t=2.564 sec[/tex]

ANS : 2.564 sec

The time it takes the block to reach the ground can be found by making

use of the law of conservation of energy.

Reasons:

Given parameters are;

Mass of block m₁ = 16.0 kg

Mass of block m₂ = 12.0 kg

Mass of the pulley, M = 5.00 kg

By conservation of energy, we have;

m₁g·h - m₂·g·h = 0.5×(m₁ + m₂)·v² + 0.5·I·ω²

[tex]\omega = \dfrac{v}{R}[/tex]

[tex]Moment \ of \ inertia\ of \ pulley, I = \dfrac{1}{2} \cdot M \cdot R^2[/tex]

Therefore;

[tex]m_1 \cdot g \cdot h - m_2 \cdot g \cdot h = 0.5 \cdot (m_1 + m_2) \cdot v^2 + 0.5 \cdot I \cdot \dfrac{v}{R}[/tex]

Which gives;

(16 - 12)×9.81×4.6 = 0.5×(16+12)×v² + 0.5×(0.5×5×0.3²)× [tex]\left(\dfrac{v}{0.3} \right)^2[/tex]

Solving gives, v ≈ 21.93 m/s

We have;

v ≈ 3.544

v² = 2·a·h

[tex]a = \dfrac{v^2}{2 \times h}[/tex]

Which gives;

[tex]a = \dfrac{3.544^2}{2 \times 4.6} \approx 1.365[/tex]

v = a×t

[tex]t = \dfrac{v}{a} = \dfrac{3.544}{1.365} \approx 2.596[/tex]

The time it takes the the block m₁ to hit the floor, t ≈ 2.596 seconds

b. When the mass of the pulley is neglected, we have;

[tex]m_1 \cdot g \cdot h - m_2 \cdot g \cdot h = 0.5 \cdot (m_1 + m_2) \cdot v^2[/tex]

(16 - 12)×9.81×4.6 = 0.5×(16+12)×v²

180.504 = 14·v²

[tex]v = \sqrt{\dfrac{180.504}{14} } \approx 3.591[/tex]

[tex]a = \dfrac{3.591^2}{2 \times 4.6} \approx 1.401[/tex]

[tex]t = \dfrac{v}{a} = \dfrac{3.591}{1.401} \approx 2.562[/tex]

The time it takes the the block m₁ to hit the floor,  if the mass of the pulley were neglected, t ≈ 2.562 seconds.

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Answer: A Whip

Explanation:

Answer:

a. Palladio's villa plans are frequently organized around a Great Room onto which other rooms open. This room provides the basis for arranging everything else.

Answer:

(A)  power  = 0.208 kW = 208 watts

(B)  energy = 6.6 x 10^{9} joules

Explanation:

energy consumed per day = 5 kWh

(a) find the power consumed in a day

         1 day = 24 hours

        power = \frac{energy}{time}

        power = \frac{5}{24}

          power  = 0.208 kW = 208 watts

(b) find the energy consumed in a year

    assuming it is not a leap year and number of days = 365 days

     1 year = 365 x 24 x 60 x 60 = 31,536,000 seconds

            energy = power x time

            energy = 208 x 31,536,000

            energy = 6.6 x 10^{9} joules

The average power consumption of an appliance that uses 5.00 kWh of energy per day is approximately 208.33 watts. In a year, this appliance consumes about 6.57 × 10^12 joules of energy.

The average power consumption of an appliance that uses 5.00 kWh of energy per day can be calculated as follows:

To convert kilowatt-hours to watts, we need to know that 1 kilowatt-hour equals to 1,000 watt-hours, and there are 24 hours in a day. Hence, 5.00 kWh is equal to 5,000 watt-hours. Therefore, the power consumption in watts is 5,000 watt-hours divided by 24 hours, yielding an average power consumption of approximately 208.33 watts.

To calculate the energy consumed in a year, we know that 1 kWh equals 3.6 million joules. Therefore, 5.00 kWh equals 18 million joules. Since there are 365 days in a year, the appliance uses 18 million joules per day times 365 days which equals 6.57 × 10^12 joules per year.

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Answer:

26m/s

Explanation:

Assuming that the acceleration is constant, we can start by calculating the train speed when it's free of the congested area:

[tex]a = \frac{\deltav}{\deltat} = \frac{12 - 5}{8} = \frac{7}{8} = 0.875 m/s^2[/tex]

Then with the same acceleration we can find out the final speed:

[tex]v = v_0 + at = 12 + 0.875*16 = 26m/s[/tex]

Explanation:

Both of our eyes have a blind spot, in the retina of eye where there are no rods (light vision) or cons (color vision) cells. Its about a size of pinhead. The blind spot is place where the optic nerves exit the eye and connect to our brain. The problem is that we cannot notice this blind as the brain fills in information for us.

Answer:

B = 0.0307 T = 30.74 mT

Explanation:

Given

m = 0.150 kg

I = 15.0 A

d = 0.510 m

μk = 0.16

B = ?

Balancing the forces on the rod in the j direction

N - m*g = 0   ⇒   N = m*g

and in the i direction

I*d*B - μk*N = 0     ⇒      B = μk*N / (I*d)

⇒      B = μk*m*g / (I*d)

⇒      B = (0.16)*(0.150 kg)*(9.8 m/s²) / (15.0 A*0.510 m)

⇒      B = 0.0307 T = 30.74 mT