there are 3 times as many boys as girls. If there are 24 more boys than girls, how many children are there?

How would I put this into a bar diagram? I can do it with algebra but I am having trouble drawing a bar diagram to help represent this problem.

Answers

Answer 1

Answer:

There are 48 children.

Step-by-step explanation:

Given :There are 3 times as many boys as girls.

            There are 24 more boys than girls,

To Find : how many children are there?

Solution:

Let the number of girls be x

Now we are given that there are 3 times as many boys as girls.

So, no. of boys = 3x

Now we are given that there are 24 more boys than girls.

So, [tex]3x-x=24[/tex]

[tex]2x=24[/tex]

[tex]x=12[/tex]

So, no. of girls = 12

No. of boys = 3x = 3(12) = 36

Now the total no. of children = 12+36 = 48

Hence there are 48 children.


Related Questions

If A=W/(m2-°C), B=m2, C=°C and D = A x B x C, what are the units of D?

Answers

Answer:

[tex]\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]

Step-by-step explanation:

We are given that A=[tex]\frac{W}{m^2-C^{\circ}}[/tex]

B=[tex]m^2[/tex]

C=[tex]C^{\circ}[/tex]

We are given that [tex]D=A\times B\times C[/tex]

We have to find the unit if D

Substitute the values then we get

[tex]D=\frac{W}{m^2-C^{\circ}}\times m^2\times C^{\circ}=\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]

[tex]D=\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]

Hence, units of D=[tex]\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]

A 1L solution containing 25,000 units of heparin must run at 30mL/hr. How much heparin is administered per hour?

Answers

Answer:

750 units

Step-by-step explanation:

As given in question,

speed of solution = 30 mL/hr

1 L of solution contains heparin = 25000 units

=> 1000 mL of solution contains heparin = 25000 units

[tex]=>\ \textrm{1 mL of solution contains heparin}\ =\ \dfrac{25000}{1000}\ units[/tex]

                                                                             = 25 units

Hence, 30 mL of solutions contains heparin = 30 x 1 mL of solution contains heparin

                                                                         = 30 x 25

                                                                         = 750 units

Hence, heparin administered per hour = 750 units

Final answer:

To find the amount of heparin administered per hour at a rate of 30mL/hr in a 1L solution with 25,000 units, calculate the concentration in units/mL and multiply by the hourly rate. This results in 750 units of heparin administered per hour.

Explanation:

To calculate the amount of heparin administered per hour when the infusion rate is 30mL/hr, use the given total units of heparin in the 1L solution. Since there are 25,000 units in 1L (1,000 mL), we can find the amount per mL and then multiply by the hourly rate.

First, calculate the units per mL:
Units per mL = Total units / Total volume
Units per mL = 25,000 units / 1,000 mL
Units per mL = 25 units/mL

Next, calculate the units delivered per hour:
Units per hour = Units per mL * Infusion rate (mL/hr)
Units per hour = 25 units/mL * 30 mL/hr
Units per hour = 750 units/hr

Therefore, 750 units of heparin are administered per hour.

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

2x1 + 3x2 − x3 = 14

x1 + 2x2 + x3 = 4

5x1 + 9x2 + 2x3 = 7

1 0 -5 16

0 1 3 -6

0 0 0 -19

Incorrect

Answers

Answer:

The reduced row-echelon form of the linear system is [tex]\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right][/tex]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rowsMultiply one row by a nonzero numberAdd a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

[tex]\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right][/tex]

You need to follow these steps:

Divide row 1 by 2 [tex]\left(R_1=\frac{R_1}{2}\right)[/tex]

[tex]\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right][/tex]

Subtract row 1 from row 2 [tex]\left(R_2=R_2-R_1\right)[/tex]

[tex]\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right][/tex]

Subtract row 1 multiplied by 5 from row 3 [tex]\left(R_3=R_3-\left(5\right)R_1\right)[/tex]

[tex]\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right][/tex]

Subtract row 2 multiplied by 3 from row 1 [tex]\left(R_1=R_1-\left(3\right)R_2\right)[/tex]

[tex]\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right][/tex]

Subtract row 2 multiplied by 3 from row 3 [tex]\left(R_3=R_3-\left(3\right)R_2\right)[/tex]

[tex]\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right][/tex]

Multiply row 2 by 2 [tex]\left(R_2=\left(2\right)R_2\right)[/tex]

[tex]\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right][/tex]

Divide row 3 by −19 [tex]\left(R_3=\frac{R_3}{-19}\right)[/tex]

[tex]\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right][/tex]

Subtract row 3 multiplied by 16 from row 1 [tex]\left(R_1=R_1-\left(16\right)R_3\right)[/tex]

[tex]\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right][/tex]

Add row 3 multiplied by 6 to row 2 [tex]\left(R_2=R_2+\left(6\right)R_3\right)[/tex]

[tex]\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right][/tex]

kindly solve using the second shifting theorem. thanks. please include explanation that I can understand. many thanks. L[t^2 u(t – 3)] -3)]

Answers

Answer:

[tex]\dfrac{2}{s^3}e^{-3s}\ +\ \dfrac{6}{s^2}e^{-3s}\ +\ \dfrac{9}{s}e^{-3s}\ -\ \dfrac{3}{s}[/tex]

Step-by-step explanation:

Given polynomial,

[tex]f(t)\ =\ t^2.u(t-3)\ -\ 3[/tex]

we can write above polynomial as

[tex]f(t)\ =\ (t-3+3)^2.u(t-3)\ -\ 3[/tex]

     [tex]=\ ((t-3)^2\ +\ 2\times 3\times (t-3)\ +\ 3^2).u(t-3)-3[/tex]

     [tex]=\ (t-3)^2.u(t-3)\ +\ 6(t-3).u(t-3)\ +\ 9.u(t-3)\ -\ 3[/tex]

Now, we have to calculate the Laplace of above polynomial

according to shifting property of Laplace transform, we can write

[tex]f(t-t_0)\ =\ F(s).e^{-st_0}[/tex]

So, we can write the Laplace transform of above polynomial as

[tex]L[f(t)]\ =\ L[(t-3)^2.u(t-3)\ +\ 6(t-3).u(t-3)\ +\ 9.u(t-3)\ -\ 3][/tex]

          [tex]=\ \dfrac{2}{s^3}e^{-3s}\ +\ \dfrac{6}{s^2}e^{-3s}\ +\ \dfrac{9}{s}e^{-3s}\ -\ \dfrac{3}{s}[/tex]

So, the Laplace transform of the given polynomial will be[tex]\ \dfrac{2}{s^3}e^{-3s}\ +\ \dfrac{6}{s^2}e^{-3s}\ +\ \dfrac{9}{s}e^{-3s}\ -\ \dfrac{3}{s}[/tex]

In how many ways can 3 girls divide 10 pennies if each must end up with at least one penny?

Answers

Answer:

36.

Step-by-step explanation:

We are asked to find the number of ways in which 3 girls can divide 10 pennies such that each must end up with at least one penny.

The selection can be done by selecting two dividing likes between the 10 pennies such that the set is divided into three parts.

Since each girl must have one penny, so no girl can have 0 penny. So the dividing like cannot be placed at end points, beginning and at the end. Therefore, we are left with 9 positions.  

Now we need to find number of ways to select two positions out of the 9 positions that is C(9,2).

[tex]_{2}^{9}\textrm{C}=\frac{9!}{7!*2!}=\frac{9*8*7!}{7!*2*1}=\frac{9*8}{2}=9*4=36[/tex]

Therefore, there are 36 ways to divide 10 pennies between 3 girls.

What does frequency refer to as it pertains to a frequency histogram? а. Proportion b. Count C. Mean d. Variance

Answers

Answer:

(a) PROPORTION.

Step-by-step explanation:

A relative frequency histogram has bars whose height is equal to either the proportion of cases that are between the upper and lower bounds of the bar.

The relative frequency in a relative frequency histogram refers to PROPORTION.

A relative frequency histogram is a graph that has the same shape and the same horizontal scale as the corresponding frequency histogram. The difference is that the vertical scale measures the relative frequencies (percentages or proportions).

Hence, option (a) is right option.

Senior management of a consulting services firm is concerned about a growing decline in the firm’s weekly number of billable hours. The firm expects each professional employee to spend at least 40 hours per week on work. In an effort to understand this problem better, management would like to estimate the standard deviation of the number of hours their employees spend on work-related activities in a typical week. Rather than reviewing the records of all the firm’s full-time employees, the management randomly selected a sample of size 51 from the available frame. The sample mean and sample standard deviations were 48.5 and 7.5 hours, respectively. Construct a 99% confidence interval for the standard deviation of the number of hours this firm’s employees spend on work-related activities in a typical week

Answers

Answer:  (45.79, 51.21)

Step-by-step explanation:

Given : Significance level : [tex]\alpha: 1-0.99=0.01[/tex]

Sample size : n= 51 , which is a large sample (n>30), so we use z-test.

Critical value: [tex]z_{\alpha/2}=2.576[/tex]

Sample mean : [tex]\overline{x}= 48.5\text{ hours}[/tex]

Standard deviation : [tex]\sigma=7.5\text{ hours}[/tex]

The confidence interval for population means is given by :-

[tex]\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}[/tex]

i.e. [tex]48.5\pm(2.576)\dfrac{7.5}{\sqrt{51}}[/tex]

i.e.[tex]48.5\pm2.70534112234\\\\\approx48.5\pm2.71\\\\=(48.5-2.71, 48.5+2.71)=(45.79, 51.21)[/tex]

Hence, 99% confidence interval for the standard deviation of the number of hours this firm’s employees spend on work-related activities in a typical week =  (45.79, 51.21)

Final answer:

To construct a 99% confidence interval for the standard deviation of firm's employees' work hours, follow the steps to calculate the interval between 6.26 and 9.08 hours.

Explanation:

Confidence Interval Calculation:

Calculate the degrees of freedom (df) using the formula df = n - 1. For a sample size of 51, df = 51 - 1 = 50.

Determine the critical values from the chi-squared distribution for a 99% confidence level with 50 degrees of freedom. These critical values are 30.984 and 73.361.

Next, calculate the confidence interval for the standard deviation using the formula CI = sqrt((n-1) ×s² / chi-squared upper) to sqrt((n-1) ×s² / chi-squared lower), which results in 6.26 to 9.08 hours.

If there are 2.54 centimeters in 1 inch, how many centimeters are in 500 inches

Answers

Answer: There are 196.85 cm in 500 inches.

Step-by-step explanation:

Since we have given that

1 inch = 2.54 centimeters

We need to find the number of centimeters are in 500 inches.

Since 1 inch = 2.54 centimeters

1 inch = [tex]\dfrac{1}{2.54}\ cm[/tex]

500 inches = [tex]\dfrac{500}{2.54}=196.85\ cm[/tex]

Hence, There are 196.85 cm in 500 inches.

Final answer:

To convert 500 inches to centimeters, use the conversion factor 2.54 cm = 1 inch. Cross-multiply and solve for x to find that there are approximately 1270 centimeters in 500 inches.

Explanation:

To convert inches to centimeters, we use the conversion factor 2.54 cm = 1 inch. In this case, we have 500 inches, so we can set up the following proportion:



2.54 cm = 1 inchx cm = 500 inches



We can cross-multiply and solve for x:



2.54x = 1 * 5002.54x = 500x = 500 / 2.54



Calculating x, we find that there are approximately 1270 centimeters in 500 inches.

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4. Mary is reviewing her algebra quiz. She has determined that one of her solutions is incorrect. Which one is it? A. 2x + 5 (x-1) 9, X 2 B. p - 3(p-5) 10, p 2.5 C. 4 y +3 y 28, y 4 E. t - 2t - 3t 32, t 8

Answers

Answer:

E. t - 2t - 3t =32, t=8

Step-by-step explanation:

A. 2x + 5 (x-1)= 9, X= 2 it's ok because

[tex]2x+5(x-1)=9\\ 2x+5x-5=9\\ 7x=14\\ x=2[/tex]

B. p - 3(p-5)= 10, p= 2.5 it's ok as well because

[tex]p-3(p-5)=10\\ p-3p+15=10\\ -2p=-5\\ p=\frac{-5}{-2} \\ p=2.5[/tex]

C. 4 y +3 y=28, y=4 also it's ok because

[tex]4y+3y=28\\ 7y=28\\ y=\frac{28}{7} \\ y=4[/tex]

E. t - 2t - 3t =32, t=8 it's not ok because

[tex]t-2t-3t=32\\-4t=32\\t=\frac{32}{-4} \\t=-8[/tex]

a (-) is missing!

Final answer:

After reviewing the solutions provided by Mary, we can conclude that the incorrect solution is Option E, where the solution should be t = -8 instead of the provided answer t = 8.

Explanation:

Mary is reviewing her algebra quiz and needs to determine which one of her solutions is incorrect. We must go through each option and verify the results given.

Option A

2x + 5(x - 1) = 9, solution X = 2.

First, expand the equation: 2x + 5x - 5 = 9.

Then combine like terms: 7x - 5 = 9.

Next, add 5 to both sides: 7x = 14.

Finally, divide by 7: x = 2.

This solution is correct.

Option B

p - 3(p - 5) = 10, solution p = 2.5.

First, expand the equation: p - 3p + 15 = 10.

Then combine like terms: -2p + 15 = 10.

Next, subtract 15 from both sides: -2p = -5.

Finally, divide by -2: p = 2.5.

This solution is correct.

Option C

4y + 3y = 28, solution y = 4.

First, combine like terms: 7y = 28.

Then, divide by 7: y = 4.

This solution is correct.

Option E

t - 2t - 3t = 32, solution t = 8.

First, combine like terms: -4t = 32.

Next, divide by -4: t = -8.

This solution is incorrect because the given answer is t = 8. The correct answer should be t = -8.

Which of the following completes the statement?

In the number 45,569, the 5 in the hundreds place is ______ the 5 to its left.

A. the same value as
B. 1/10 the value of
C. 10 times the value of
D. 100 times the value of

Answers

Answer:

  B.  1/10 the value of

Step-by-step explanation:

In our base-10 place-value number system, the place value of a number is multiplied by 10 when it moves 1 place to the left. It is multiplied by 1/10 when it moves 1 place to the right.

A digit has 1/10 the value of the same digit one place to its left.

Answer:    B

Step-by-step explanation:

Show that 2^2n-1 +1 is divisible by 3 for all n > 1.

Answers

Answer:

The proof makes use of congruences as follows:

Step-by-step explanation:

We can prove this result using congruences module 3. First of all we shall show that

[tex]2^{2n-1}\equiv 2 \pmod{3}[/tex] for all [tex]n\in \mathbb{N}[/tex]. By induction we have

[tex]n=2[/tex]. For [tex]n=2[/tex] we have [tex]2^{4-1}=8\equiv 2 \pmod{3}[/tex]Suppose that the statement is true for [tex]n=k[/tex] and let's prove that it is also true for [tex]n=k+1[/tex]. In fact,  [tex]2^{2(k+1)-1}=2^{2k-1+2}=2^{2k-1}2^{2}\equiv 2\cdot 2^{2}\equiv 8 \equiv 2 \pmod{3}[/tex]

Then induction we proved that [tex]2^{2n-1}\equiv 2 \pmod{3}[/tex] for all [tex]n>1[/tex]. Then

[tex]2^{2n-1}+1\equiv 2+1\equiv 3\equiv 0 \pmod{3}[/tex]

From here we conclude that the expression [tex]2^{2n-1}+1[/tex] is divisible by 3.

A web page design firm has two designs for an online hardware store. To determine which is the more effective​ design, the firm uses one page when on a mobile platform and a second page when on a desktop. For each​ visit, the firm records the amount spent by the visitor and the amount of time visiting the site. Complete parts​ (a) through​ (c) below (a) What is the explanatory variable in this study? Is it qualitative or quantitative? O A. The explanatory variable is the amount spent by the visitor. This explanatory variable is quantitative. O B. The explanatory variable is the web page design. The explanatory variable is qualitative. ° C. The explanatory variable is the amount of time visiting the site. This explanatory variable is quantitative O D. The explanatory variable is the age group. This explanatory variable is qualitative. (b) What are the two response variables? For each response variable, state whether it is qualitative or quantitative. Select all that apply. □ A- One response variable is the amount spent by the visitor. This response variable is quantitative. B. One response variable is the web page design. This response variable is qualitative. C. One response variable is the age group. This response variable is qualitative D. One response variable is the amount of time visiting the site. This response variable is quantitative. (c) Explain how confounding might be an issue with this study. Choose the correct answer below d A. Since there are two response variables in this study, they may interact, causing the results to be misleading or incorrect. B. Since there is only one explanatory variable, and two response variables, the explanatory variable will not affect both response variables equally, resulting in misleading results O C. Since the designs are being tested with two different age groups, preferences depending on the age group may affect the response variables for those groups. O D. Since the variables are not all quantitative or all qualitative, they may interact, causing the results to be misleading or incorrect.

Answers

Final answer:

The explanatory variable is the web page design. The response variables are the amount spent by the visitor and the amount of time visiting the site. Confounding could be an issue if other factors are not accounted for.

Explanation:

(a) The explanatory variable in this study is the web page design. It is a qualitative variable because it represents different design options.

(b) The two response variables are the amount spent by the visitor and the amount of time visiting the site. The amount spent is a quantitative variable, while the amount of time is also quantitative.

(c) Confounding could be an issue in this study if there are other factors that could affect the response variables and are not accounted for. For example, if there are differences in the age groups of the visitors using mobile and desktop platforms, their preferences may affect the response variables.

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Describe the variable​ Yr_Built. Choose the correct answer below. A. The variable​ Yr_Built is​ quantitative, with units years. B. The variable​ Yr_Built is an identifier variable. C. The variable​ Yr_Built is categorical and ordinal. D. The variable​ Yr_Built is categorical and nominal.

Answers

Answer:

A. The variable​ Yr_Built is​ quantitative, with units years.

Step-by-step explanation:

Since, Yr_Built means the year built, Also year has a numerical value like 2008, 2000, 1865, etc.

So, it is quantitative.

Further, Data is said to be quantitative if it has a numerical value.

Categorical data is that data which has categories. For example, Gender: It has two categories Female and Male.

The data which as ordering is called ordinal data. Example, Bad, Average, Good.

Identifier Variable is the variable that is used for identity. Example, Employee No., etc.

ANSWER PLEASE ITS AN EMERGENCY. COULD SOMEONE ALSO HELP WITH OTHER QUESTIONS TOO?ILL GIVE BRAINLIEST
Angle G and Angle K are complementary angles.

The measure of Angle K is 5 times the measure of Angle G.

Find the measures of Angle G and Angle K.

Measure of Angle G =

degrees.



Measure of Angle K =

degrees.

Answers

Answer:

angle k:75

angle g:15

Step-by-step explanation:

Aspirin tablets generally contain 325 mg of aspirin. How many such tablets may be prepared from 5 kg of aspirin?

Answers

Answer:

15,384 such tablets may be prepared from 5 kg of aspirin

Step-by-step explanation:

The problem states that aspirin tablets generally contain 325 mg of aspirin. And asks how many such tablets may be prepared from 5 kg of aspirin.

Since the problem measures the weight of a tablet in kg, the first step is the conversion of 325mg to kg.

Each kg has 1,000,000mg. So

1kg - 1,000,000mg

xkg - 325mg.

1,000,000x = 325

[tex]x = \frac{325}{1,000,000}[/tex]

x = 0.000325kg

Each tablet generally contains 0.000325kg of aspirin. How many such tablets may be prepared from 5 kg of aspirin?

1 tablet - 0.000325kg

x tablets - 5kg

0.000325x = 5

[tex]x = \frac{5}{0.000325}[/tex]

x = 15,384 tablets

15,384 such tablets may be prepared from 5 kg of aspirin

Final answer:

Around 15,385 tablets of aspirin can be created from 5 kilograms of aspirin, using the assumption that one tablet typically contains 325 milligrams of aspirin.

Explanation:

This question requires a basic understanding of the conversion from kilograms to milligrams. 5 kilograms of aspirin is equal to 5,000,000 milligrams (as 1 kilogram = 1,000,000 milligrams). So, if one aspirin tablet contains 325 mg of aspirin, we can calculate the number of tablets from 5kg, or 5,000,000 mg, of aspirin by simply dividing the total milligrams of aspirin by the milligrams per tablet.

To calculate:
Number of tablets = Total mass / Mass per tablet
= 5,000,000 mg / 325 mg/tablet

So, roughly 15,385 tablets of aspirin can be produced from 5 kg of aspirin.

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Team A and Team B play each other in a best out of 7 tournament. So the team that wins 4 games first wins the tournament. How many possible sequences are there for team A to win? Examples: AAAA, AAABA, AABAA, etc.

Answers

Answer: There 64 possible sequences in which team A wins

Step-by-step explanation:

Hi!

The sequences in which team A wins, are the ones with at least 4 A's.

Sequences with 4, 5, 6 or 7 A's. To calculate how many of each type exist, we use the formula of combinations. If you select K objects from a set of N objects, there are C(N, K) possibilities, give by the formula:

[tex]C(N,K) = \frac{N!}{K! (N-K)!)}[/tex]

Then the total M number of sequences in which team A wins is:

[tex]M = C(7,7) + C(7,6) + C(7,5) + C(7,4) = 1 + 7 +21+35 = 64[/tex]

Divide and simplify to the form a+bi. 5+6i 5+6i 6+ i (Simplify your answer. Type an integer or a fraction. Type your answer in the form a+bi.)

Answers

Answer:

[tex]-\frac{6}{37} + \frac{371}{37}i[/tex]

Step-by-step explanation:

We need to evaluate [tex]\frac{(5+6i)(5+6i)}{6+i}[/tex]

(5+6i)(5+6i) = (25 + 36i² + 60i) = (25 - 36 + 60i) = -11 + 60i

= [tex]\frac{-11+60i}{6+i}[/tex]

Now we rationalize the denominator.

Now, multiplying both the numerator and denominator by (6-i)

[tex]\frac{-66 + 11i + 360i - 60i^2}{36 - i^2} = \frac{-66 + 60  + 371i}{37} = \frac{-6 + 371i}{37}[/tex]

= [tex]-\frac{6}{37} + \frac{371}{37}i[/tex]

Formula used:

(a+b)² = a² + b² + 2ab

i² = -1

A breath analyzer, used by the police to test whether drivers exceed the legal limit for blood alcohol percentage while driving, is known to satisfy P ( A | B ) = P ( A c | B c ) = p where A is the event "breath analyzer indicates that legal limit is exceeded" and B is the event "driver's blood alcohol percentage exceeds legal limit." On Saturday night, about 5% of all drivers are known to exceed the limit. If we want P ( B | A ) to equal 0.9, what value of p should we use, rounded to 4 decimal places? Group of answer choices

Answers

Final answer:

To find the value of 'p' that satisfies the equation, we use Bayes' theorem and substitute the given values into the equation.

Explanation:

In this question, we need to find the value of p which satisfies the equation P(A|B) = P(A' | B'), where A is the event 'breath analyser indicates that legal limit is exceeded' and B is the event 'driver's blood alcohol percentage exceeds legal limit.'

We are given that approximately 5% of all drivers exceed the legal limit for blood alcohol percentage while driving, which means P(B) = 0.05.We are also given that we want P(B|A) = 0.9. Using Bayes' theorem, we can write:
P(B|A) = (P(A|B) * P(B)) / P(A).Since P(A|B) = P(A' | B'), we can substitute P(A' | B') for P(A|B) in the equation from step 2.After substituting the values, we can solve for P(A). P(A) = (P(B) * P(A|B')) / P(B'|A').Substituting the given values and solving the equation, we can find the value of p which satisfies the given conditions.

Therefore, the value of p that should be used, rounded to 4 decimal places, can be calculated using the above steps.

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Is .13 less than .32

Answers

Yes, .13 is less than .32

(1/2) (10t) = 50,000

Answers

Answer: The value of t become 10000.

Step-by-step explanation:

Since we have given that

[tex]\dfrac{1}{2}\times 10t=50000[/tex]

We need to find the value of t from the above expression:

first we divide 10t by 2 to get 50000.

[tex]\dfrac{10t}{2}=50000\\\\5t=50000\\\\t=\dfrac{50000}{5}\\\\t=10000[/tex]

Hence, the value of t become 10000.

If you roll one die and flip one coin, what is the probability of rolling a 2 and flipping a head? Why?

Answers

Answer:

Probability of rolling a 2 and flipping a head will be [tex]\frac{1}{12}[/tex]    

Step-by-step explanation:

If we roll one die then probability to get any one side is [tex]\frac{1}{6}[/tex]

Therefore, probability to get 2 by rolling the die will be P(A) = [tex]\frac{1}{6}[/tex]

Now we flip a coin then getting head or tale probability is [tex]\frac{1}{2}[/tex]

Or probability to get head by flipping the coin P(B) = [tex]\frac{1}{2}[/tex]

Probability of happening both the events (rolling a 2 and flipping a head) will be denoted by

P(A∩B) = P(A)×P(B)

           = [tex]\frac{1}{6}\times \frac{1}{2}[/tex]

           = [tex]\frac{1}{12}[/tex]

Therefore, probability of rolling a 2 and flipping a head will be [tex]\frac{1}{12}[/tex]        

Answer:

The probability of rolling a 2 and flipping a head is [tex]\frac{1}{12}[/tex]

Step-by-step explanation:

Notice that rolling a die and flipping a coin are two independent events this means that the probability that one event occurs in no way affects the probability of the other event occurring. When we determine the probability of two independent events we multiply the probability of the first event by the probability of the second event.

[tex]P(X and \:Y) =P(X) \cdot P(Y)[/tex]

When you roll a die there six outcomes from 1 to 6 and when you flip a coin are two possible outcomes (heads or tails).

We know that the probability of an event is

[tex]P=\frac{the \:number \:of \:wanted\:outcomes}{the \:number \:of \:possible \:outcomes}[/tex]

So the probability of rolling a 2 and flipping a head is

[tex]P(2 \:and \:H) = P(2) \cdot P(H)\\P(2 \:and \:H) = \frac{1}{2} \cdot \frac{1}{6}\\P(2 \:and \:H) = \frac{1}{12}[/tex]

What is the quotient of the fractions below? 4/7 + 7/5

Answers

Answer:

  (4/7) ÷ (7/5) = 20/49

Step-by-step explanation:

You show a sum, not a quotient.

Perhaps you want the quotient ...

  (4/7) ÷ (7/5) = (4/7)×(5/7) = (4·5)/(7·7) = 20/49

The amount of garbage, G, in tons per week, produced by a city with population p, measured in thousands of people, is given by G = f ( p ) The town of Tola has a population of 50,000 and produces 14 tons of garbage each week. Express this information in terms of the function f

Answers

Answer: [tex]G=f(50)=14[/tex]

Step-by-step explanation:

Given : The amount of garbage, G, in tons per week, produced by a city with population p, measured in thousands of people, is given by G = f(p).

Also, The town of Tola has a population of 50,000 and produces 14 tons of garbage each week.

Then, the expression in terms of the function G will be :-

[tex]G=f(50)=14[/tex]

Suppose that a worker in Country A can make either 10 iPods or 5 tablets each year. Country A has 100 workers. Suppose a worker in Country B can make either 2 iPods or 10 tablets each year. Country B has 200 workers. A bundle of goods that Country A could not make would be:

Answers

Answer:

A bundle of goods that Country A has are 1000 iPods and 500 Tablets.

Step-by-step explanation:

Country A can produce either  iPods and Tablets.

Total man power  Country A has 100 workers.

As per information in the question w

100 worker make either ipod or 100 worker make tablets

1 worker can produce 10 iPods.

Therefore

100 workers can produce (100 * 10) = 1000 iPods.

on the other hand

1 worker can produce 5 tablets.

Therefore

100 workers can produce (100 * 5)=  500 Tablets

Thus,

A bundle of goods that Country A has are 1000 iPods and 500 Tablets.

xy′ = √(1 − y2 ), y(1) = 0

Answers

Answer:

The particular solution is [tex]y=\sin (\ln|x|)[/tex] .

Step-by-step explanation:

The given differential equation is

[tex]xy'=\sqrt {1-y^2}[/tex]

It can be written as

[tex]x\frac{dy}{dx}=\sqrt {1-y^2}[/tex]

Use variable separable method to solve the above equation.

[tex]\frac{dy}{\sqrt {1-y^2}}=\frac{1}{x}dx[/tex]

Integrate both sides.

[tex]\int \frac{dy}{\sqrt {1-y^2}}=\int \frac{1}{x}dx[/tex]

[tex]\sin^{-1} y=\ln|x|+C[/tex]            .... (1)

It is given that y(1)=0. It means y=0 at x=1.

[tex]\sin (0)=\ln|1|+C[/tex]

[tex]0=0+C[/tex]

[tex]0=C[/tex]

The value of constant is 0.

Substitute C=0 in equation (1) to find The required equation.

[tex]\sin^{-1} y=\ln|x|+0[/tex]

Taking sin both sides.

[tex]y=\sin (\ln|x|)[/tex]

Therefore the particular solution is [tex]y=\sin (\ln|x|)[/tex] .

For what side length(s) is the area of an equilateral triangle equal to 30 cm?? Only enter the number, in centimeters, rounded to two decimal places. A cm ►

Answers

Answer: The sides length are 8.32 cm

Step-by-step explanation:

An equilateral triangle has all his sides of the same lenght, so we assume that the triangle has an L lenght in his sides.

The area of a triangle is [tex]Area = \frac{base * height}{2}[/tex] where the base is L, the Area is 30 and an unknown height.

To determine the height, we cut the triangle in half and take one side. By simetry, one side has a base of [tex]\frac{L}{2}[/tex], a hypotenuse of L and a the unknown height.  

Then we apply the Pythagoras theorem, this states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, or, [tex]hypotenuse = \sqrt{c^{2} + c^{2} }[/tex] Where one c is [tex]\frac{L}{2}[/tex] and the other is the height.

Then we find one of the c of the equation wich will be the height.

[tex]height = \sqrt{hypotenuse^{2}-base^{2} }[/tex]

[tex]height = \sqrt{ L^{2} -\frac{L}{4} ^{2}}\\height = \sqrt{\frac{ 3L^{2}}{4} } \\\\height = \frac{\sqrt{3}L }{2}[/tex]

Finally, we use the triangle area mentioned before an find the value of L.

[tex]30 = \frac{L*\frac{\sqrt{3}L }{2} }{2} \\\\L = \sqrt{\frac{120}{\sqrt{3} } } \\\\L = 8.32 cm[/tex]

What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)?

Answers

Answer:

Step-by-step explanation:

Let's remember the equation of a line:

y = mx + b

m: slope (we know it's 3)

b: the y-intercept

So far, we have y = 3x + b, now we need to find b.

Replacing y and x for the given points (-3,-5):

-5 = 3*(-3) + b

-5 = -9 + b

b = -5 + 9

b = 4

The equation of the line that passes through the point (-3,-5) with a slope of 3 is y = 3x + 4

Answer:

y = 3x + 4

Step-by-step explanation:

Ethanol fuel mixtures have "E" numbers that indicate the percentage of ethanol in the mixture by volume. For example, E10 is a mixture of 10% ethanol and 90% gasoline. How much E5 should be mixed with 6000 gal of E10 to make an E9 mixture?

Answers

Final answer:

To figure out how much E5 should be mixed with 6000 gal of E10 to make an E9 mixture, we need to use a weighted average equation: 0.10*6000 + 0.05*X = 0.09 * (6000 + X). Solving this equation will provide the required amount of E5 gasoline.

Explanation:

To solve this problem, we use a technique known as a weighted average. The weight is the number of gallons and the 'value' is the percentage of ethanol. We can formulate an equation using the principle that the sum of the ethanol in the initial gasolines will equal to the ethanol in the final mixture.

Let's denote by X the needed amount of E5 gasoline. Therefore, the total ethanol before mixing would be 0.10*6000 (from the E10 gasoline) + 0.05*X (from the E5 gasoline). After mixing, the total ethanol will be 0.09 (6000 + X).

Equating these two gives us 0.10*6000 + 0.05*X = 0.09 * (6000 + X). Solving this equation will give the needed amount of E5 gasoline.

Learn more about Weighted Average here:

https://brainly.com/question/36895489

#SPJ12

To create an E9 mixture, you need to mix 1500 gallons of E5 with 6000 gallons of E10. This is calculated using the volume percentages of ethanol in each mixture and solving a linear equation. The final mixture will contain 9% ethanol.

To solve the problem of finding out how much E5 should be mixed with 6000 gallons of E10 to create an E9 mixture, we need to set up an equation based on the percentage volumes of ethanol.

Let's denote the amount of E5 to be added as x (in gallons).

E10 contains 10% ethanol and 90% gasoline. Therefore, in 6000 gallons of E10, the amount of ethanol is:

0.10 × 6000 = 600 gallons of ethanol.

E5 includes 5% ethanol and 95% gasoline. Therefore, in x gallons of E5, the amount of ethanol is:

0.05 × x gallons of ethanol.

We want to create an E9 mixture, which means the final mixture should contain 9% ethanol. The total volume of the final mixture will be:

6000 + x gallons.

The amount of ethanol in the final mixture can be represented as:

(600 + 0.05x) gallons of ethanol.

This amount should be 9% of the total final volume:

0.09 × (6000 + x) = 600 + 0.05x

Solving for x:

0.09(6000 + x) = 600 + 0.05x540 + 0.09x = 600 + 0.05x0.09x - 0.05x = 600 - 5400.04x = 60x = 1500

Therefore, you need to mix 1500 gallons of E5 with 6000 gallons of E10 to create an E9 mixture.

Everyone in a group is being assigned a secret code of 3 characters. The first character must be a letter and the second and third are numbers which can not be the same. How many possible codes can be made? O A. 46 O B. 126 C. 2340 O D. 2600

Answers

Answer: C. 2340

Step-by-step explanation:

Hi!

The first character is a letter. There are 26 letters in the alphabet. For each letter you choose a two digit number, but you cannot repeat the digits. There are 100 (0 to 99) two digit numbers, and you have to discard 00, 11, 22, 33, 44, 55, 66, 77, 88, 99. Those are the 10 numbers with repeated digits.

So, for each letter, you have any of 90 possible numbers. The answer is then 26*90 = 2340

Ana and Bella are sisters.They are responsible for keeping the
family's driveway clear of snow.If they work together they can
complete the shoveling in 30 minutes.
One day Ana had to do the job alone.It took her 40 minutes.How long
would it have taken Bella to shovel the same amont alone?You can
assume that each girl always shovels at a constant speed.

Answers

Answer:

Bella can complete work alone in 120 minutes

Step-by-step explanation:

Ana and Bella together can  complete the shoveling in 30 minutes.

They can do a part of work in 1 minute = [tex]\frac{1}{30}[/tex]

Ana can do work alone in 40 minutes

She can do part of work in 1 minute = [tex]\frac{1}{40}[/tex]

So, Bella can do a part of work in 1  minute =  [tex]\frac{1}{30}-\frac{1}{40}[/tex]

                                                                        =  [tex]\frac{1}{120}[/tex]

Bella can do [tex]\frac{1}{120}[/tex] part of work in 1  minute

Bella can do whole work in minutes = 120

Hence Bella can complete work alone in 120 minutes

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