Find the two square roots of the number 1
Answer:
+ 1 or - 1
Step-by-step explanation:
[tex]\sqrt{1}[/tex] = ± 1
Since 1 × 1 = 1 and - 1 × - 1 = 1
Which problem can be represented by the equation 49y−8=89 ?
A. A water filter filters 89 ounces of water per day. The first 8 ounces of water cannot be consumed and must be dumped out. How many days will it take the water filter to produce 49 ounces of consumable water?
B. A water filter filters 49 ounces of water per day. The first 8 ounces of water cannot be consumed and must be dumped out. How many days will it take the water filter to produce 89 ounces of consumable water?
C. A water filter filters 89 ounces of water per day. The first 49 ounces of water cannot be consumed and must be dumped out. How many days will it take the water filter to produce 8 ounces of consumable water?
D. A water filter filters 8 ounces of water per day. The first 49 ounces of water cannot be consumed and must be dumped out. How many days will it take the water filter to produce 89 ounces of consumable water?
Answer: B
Step-by-step explanation:
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Answer:
4000×.06×2 which is 480
Step-by-step explanation:
You must times the money by the ir and then the year. Or money times the year then ir, it wouldn't really matter as long you times the three of them together
Can someone help me with this word problem? I will mark anyone that offers me a useful answer the most brainiest!
I know that you have to split up the money between the 3 based on how much work they have done, but I don't understand how to do that...
Please don't answer this unless you actually understand!! Thanks! :)
Step-by-step explanation:
Hours of work- Alvin: 6 hours Theodore: 4.5 hours Simon: 1.25 hours
6+1.25+4.5= 11.75 hours Calculate the total amount of hours all of them worked together61÷11.75= $5.19 Divide the total amount of money by number of hours.5.19×6= $31.14 for Alvin, 5.19×4.5= $25.43 for Theodore, 5.19×1.25= $6.49 for Simon Multiply the number of hours worked by each chipmunk by the money made per hour.Find the missing endpoint if S is the midpoint of RT
R(-9,4) and S(2,-1) ; Find T
Answer:x-coordinate of T: from -9 to 2, there's 11 units, so you add 11 to 2 to find the x-coordinate of T, which is 13.
y-coordinate of T: from 4 to -1 there's -5 units, so you subtract 5 from -1 to find the y-coordinate of T, which is -6.
Step-by-step explanation:
What is the value of the expression given below? (5+3i)-(5+3i)(5-5i)
Answer:
-35 + 13iStep-by-step explanation:
[tex]i=\sqrt{-1}\to i^2=-1\\\\(5+3i)-(5+3i)(5-5i)\qquad\text{distribute}\\\\=(5+3i)(1-(5-5i))=(5+3i)(1-5-(-5i))=(5+3i)(-4+5i)\\\\\text{use}\ FOIL:\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(5)(-4)+(5)(5i)+(3i)(-4)+(3i)(5i)\\\\=-20+25i-12i+15i^2=-20+13i+15(-1)\\\\=-20+13i-15=-35+13i[/tex]
perfect square of 401
A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 401 is about 20.025. Thus, the square root of 401 is not an integer, and therefore 401 is not a square number.
Answer:
apparently In what I believe, 401 is not a perfect square mate!
Step-by-step explanation:
401 is an odd number, because it is not evenly divisible by 2.
A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 401 is about 20.025.
Thus, the square root of 401 is not an integer, and therefore 401 is not a square number.
92.3-(3.2 divided by 0.4) times 8
Answer:
28.3 that's the answer
Step-by-step explanation:
Find the first, fourth, and 10th terms of the arithmetic sequence described by the given rule.
A(n) = -6 + (n - 1)(1/5)
[tex]\bf \begin{array}{ll} \stackrel{term}{n}&\stackrel{-6+(n-1)\frac{1}{5}}{value}\\ \cline{1-2} 1&-6+(1-1)\frac{1}{5}\\ &-6+0\\[1em] &-6\\[1em] 4&-6+(4-1)\frac{1}{5}\\ &-6+\frac{3}{5}\\[1em] &\frac{-27}{5}\\[1em] 10&-6+(10-1)\frac{1}{5}\\ &-6+\frac{9}{5}\\[1em] &\frac{-21}{5} \end{array}[/tex]
Answer with Step-by-step explanation:
We are given a arithmetic sequence as:
[tex]A(n)=-6+(n-1)(\dfrac{1}{5})[/tex]
We have to find the first, fourth and tenth term
First term:
n=1
[tex]A(1)=-6+(1-1)(\dfrac{1}{5})[/tex]
A(1)= -6
Fourth term:
n=4
[tex]A(4)=-6+(4-1)(\dfrac{1}{5})[/tex]
[tex]A(4)=-6+\dfrac{3}{5}[/tex]
[tex]A(4)=-\dfrac{27}{5}[/tex]
Tenth term:
n=10
[tex]A(10)=-6+(10-1)(\dfrac{1}{5})[/tex]
[tex]A(10)=-6+\dfrac{9}{5}[/tex]
[tex]A(10)=-\dfrac{21}{5}[/tex]
Question 1 of 10
2 Points
The circle below is centered at the point (-3, 4) and has a radius of length 3.
What is its equation?
O
O A. (x-4)2 + (y + 3)2 =
32
O
O B. (x+4)2 + (x-3)2 =
O C. (x+3)2 + (x-4)2 = 9
O D. (x - 3)2 + (y + 4)2 = 9
SUBMIT
Answer:
C. (x + 3)^2 + (y - 4)^2 = 9.
Step-by-step explanation:
The general form of a circle with center (a,b) and radius r is:
(x - a)^2 + (y - b)^2 = r^2
So substituting the given values the equation of our circle is:
(x - (-3)^2 + (y - 4)^2 = 3^2
(x + 3)^2 + (y - 4)^2 = 9.
The cost of Mr. Patten’s car insurance increased by 5% to $86.82 per month. What was the cost of his insurance before it increased?
Answer:
Considering is a compunded increase rate of the yearly car insurance fee and x is the initial value of the insurance fee then
x×(1.05)^12=$86.82
×=$86.82/(1.05)^12
The cost of his insurance before it increased is $82.48.
Here,
The cost of Mr. Patten’s car insurance increased by 5% to $86.82 per month.
We have to find the cost of his insurance before it increased.
What is Percentage?
A percentage (from Latin per centum "by a hundred") is a number or ratio expressed as a fraction of 100.
Now,
The cost of Mr. Patten’s car insurance increased by 5% to $86.82 per month.
Increased cost = [tex]\frac{5}{100} * 86.82 = 4.34[/tex]
Hence, The cost of his insurance before it increased = $86.82 - $4.34
= $82.48
So, The cost of his insurance before it increased is $82.48.
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When riding a bicycle, wear.
O gloves
SH
O a jacket
O a helmet
glasses
Answer:
Most often people wear a helmet when riding a bike.
Classify the following angles.
13°
180°
Answer: The acute angle is the small angle which is less than 90°. If you choose the larger angle you. will have a Reflex Angle instead: The smaller angle is an Acute Angle, but the larger angle is a Reflex Angle.
Step-by-step explanation: An angle that is exactly 90 degrees is called a right angle. Angles greater than 90 degrees and less than 180 degrees are called obtuse angles. An angle that is exactly 180 degrees is called a straight angle. butt
What’s the slope of the line in the graph?
Check the picture below, let's use those two points on the line to get its slope.
[tex]\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{0}}}\implies \cfrac{2}{2}\implies 1[/tex]
What is the input other than -2 for which h(x) =6
Answer:
x = - 6
Step-by-step explanation:
Reading from y = 6 on the y- axis
There are 2 points where y = 6 intersects with the graph, that is
x = - 2 and x = - 6
How would the sum of cubes formula be used to factor x^3y^3+343? Do not write the factorization
Answer:
[tex]\large\boxed{x^3y^3+343=(xy+7)(x^2y^2-7xy+49)}[/tex]
Step-by-step explanation:
[tex]x^3y^3=(xy)^3\\\\343=7^3\\\\x^3y^3+343=(xy)^3+7^3\qquad\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(xy+7)\bigg((xy)^2-(xy)(7)+7^2\bigg)=(xy+7)(x^2y^2-7xy+49)[/tex]
help pls pls pls pls pls
Answer:
12.I know that whole numbers go inside the integers circle, and that natural numbers (counting numbers) go inside the whole numbers circle. The irrational numbers circle is in its own category.]
13. It is true that 5 to the 2nd power is 25. So I guess you should just prove that it is true? The way they phrased the question was awkward.
Please mark brainliest! I would really appreciate it! :)
A coordinate plane with a line passing through (negative 4, 3), (0, 1), and (4, negative 1). Which linear function is represented by the graph? f(x) = –2x + 1 f(x) = –f(x) equals negative StartFraction one-half EndFraction x plus 1.x + 1 f(x) = f(x) equals StartFraction one-half EndFraction x plus 1.x + 1 f(x) = 2x + 1
Answer:
Step-by-step explanation:
If these 3 points are collinear, then we can find the slope of the linear function using any 2 of those points. Suppose we use (-4, 3) and (0, 1):
As we move from (-4, 3) to (0, 1), x increases by 4 and y decreases by 2. Hence, the slope of this lilne is m = rise/run = -2/4, or m = -1/2.
Using the slope-intercept formula y = mx + b and replacing y with 1, x with 0 and m with -1/2, we get:
1 = (-1/2)(0) + b, or b = 1. Then the desired equation is y = f(x) = (-1/2)x + 1
Answer:
B
Step-by-step explanation:
Multiply: (3x + 2)(4x + 2)
Answer:
[tex]12x^{2} +14x+4[/tex]
Step-by-step explanation:
3x *4x = [tex]12x^{2}[/tex]
[tex]3x+4x*2=14x[/tex]
2 + 2 = 4
[tex]12x^{2} +14x+4[/tex]
Laura has a backyard that she wants to renovate. Her
backyard is (x + 4) feet wide and (x + 6) feet long.
Laura wants to place a rectangular garden that is x
feet wide and (x + 2) feet long in the middle of her
backyard. Laura also wants to pour in concrete that
surrounds her garden in the backyard that will serve
as a walkway. What is the expression that represents
the area of the walkway? Refer to the diagram.
Answer:
Area of the walkway = 8x + 24
Step-by-step explanation:
Area of the total backyard = [tex]l\times b[/tex]
Area of total backyard = [tex](x+6)\times (x+4) = x^{2} +10x + 24[/tex]
Now, Area of the rectangular garden = [tex]l\times b[/tex]
Area of the rectangular garden = [tex]x (x+2) = x^{2} + 2x[/tex]
Now area of the walkway poured with concrete = Area of the backyard - Area of the rectangular garden
= [tex](x^{2} +10x +24) - (x^{2} +2x)[/tex]
= [tex]x^{2} + 10x +24 - x^{2} -2x[/tex]
= 8x + 24
Is -34 a whole number, integer, rational number?
-34 is indeed a "whole number, integer, and a rational number." Whole numbers are full numbers including negatives, not including fractions, decimals, and percents. Integers are whole numbers can be negative or positive. Also rational numbers are anything that can be expressed as a fraction.
Hope this helps.
What is the center of a circle represented by the equation (x-5)2+(y+6)2=42?
[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-5)^2+(y+6)^2=42\implies [x-\stackrel{h}{5}]^2+[y-(\stackrel{k}{-6})]^2=(\stackrel{r}{\sqrt{42}})^2~~ \begin{cases} \stackrel{center}{(5,-6)}\\\\ \stackrel{radius}{\sqrt{42}} \end{cases}[/tex]
Answer:
(5, -6)Step-by-step explanation:
The equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have:
[tex](x-5)^2+(y+6)^2=42\\\\(x-5)^2+(y-(-6))^2=42[/tex]
Therefore
[tex]h=5,\ k=-6,\ r^2=42\to r=\sqrt{42}[/tex]
How many inches are in 3 miles
Answer:
190,080 inches
Step-by-step explanation:
Inches converted into miles. 3 miles will equal to 190080 inches according to the conversion.
Hope this helped!
Nate
Using the graph as your guide, complete the following statement.
The discriminant of the function is
Answer:
Using the graph as your guide, complete the following statement.
The discriminant of the function is
Step-by-step explanation: Remember a parable of the form f(x) = a[tex]a x^{2} + bx + c[/tex], satisfy:
(1) has only one root if and only if [tex] b^2 - 4ac = 0[\tex]
(2) has two real roots if and only if [tex] b^2 - 4ac > 0[\tex]
(3) has two complex roots if and only if [tex] b^2 - 4ac < 0[\tex].
The number b^2 - 4ac is called the discriminant of the parable f(x).
From the graph we can see that the parable has only one root approx in x =1. Thus from point (1) we can conclude that the discriminant should be zero.
PD: a root of a polynomial f(x) is a number a such thast f(a) =0.
The answer is A.
Answer: The answer is A because the vertex lies on the x axis which makes it zero.
Answer= A
Complete the following equation, then distribute 9 multiply 27=9(_+7)
Answer:
9(x + 7)= 27
9x + 63 = 27
9x = -36
x = -4
Step-by-step explanation:
simplify 5^(-2)
PLEASE HURRY
Answer:
.04
i think
hope that helps
Answer: The required simplified value is 0.04.
Step-by-step explanation: We are given to simplify the following :
[tex]E=5^{-2}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We will be using the following property of exponents :
[tex]a^{-n}=\dfrac{1}{a^n}.[/tex]
The simplify of (i) is as follows :
[tex]E\\\\=5^{-2}\\\\=\dfrac{1}{5^2}\\\\=\dfrac{1}{25}\\\\=0.04.[/tex]
Thus, the required simplified value is 0.04.
What is 0.888 as a fraction, in simplest form?
Answer:
111÷125
Step-by-step explanation:
0.888 as fraction is 888÷1000
Divide by 2 u get
444÷500 furher divide by 2
222÷250
and last divide
111÷125 and u cant change into more lower fraction so the answer is 111÷125
The required fraction of the number 0.888 is 111 / 125.
Given that,
To determine the 0.888 as a fraction, in simplest form.
What is a number system?
A number system is described as a technique of composing to represent digits. It is the mathematical inscription for describing the numbers of a given set by using numbers or other characters in a uniform method. It delivers a special presentation of every digit and describes the arithmetic structure.
What is the fraction?Fraction is defined as the number of compositions that constitutes the Whole.
Here,
Given number = 0.888
Fraction = 0.888 = 888 / 1000
Faction = 111 / 125
Thus, the required fraction of the number 0.888 is 111 / 125.
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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select three options. y = –Two-fifthsx – 2 2x + 5y = −10 2x − 5y = −10 y + 4 = –Two-fifths(x – 5) y – 4 = Five-halves(x + 5)
Answer:
Step-by-step explanation:
Two lines are perpendicular if the first line has a slope of [tex]m[/tex] and the second line has a slope of [tex]\frac{1}{-m}[/tex].
With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:
[tex]5x - 2y = -6[/tex]
[tex]-2y = -5x - 6[/tex]
[tex]y = \frac{5}{2}x + 3[/tex]
We now know that [tex]m = \frac{5}{2}[/tex] for the first line, which means that the slope of the second line is [tex]m = \frac{-2}{5}[/tex]. With this, we have the following equation for our new line:
[tex]y = \frac{-2}{5}x + C[/tex]
where [tex]C[/tex] is the Y-intercept that we now need to determine with the coordinates given in the problem statement, [tex](5, -4)[/tex]:
[tex]y = \frac{-2}{5}x + C[/tex]
[tex](-4) = \frac{-2}{5}(5) + C[/tex]
[tex]-4 = -2 + C[/tex]
[tex]C = -2[/tex]
Finally, we can create our line:
[tex]y = \frac{-2}{5}x - 2[/tex]
[tex]5y = -2x - 10[/tex]
[tex]2x + 5y = -10[/tex]
Answer:
a,b,d
Step-by-step explanation:
took test on edu
(a) A dog owner records the weight of her dog. She finds that from the age of 20 weeks to the age of 48 weeks, the dog’s weight can be modelled by the equation w = 0.92t−0.15 (20 ≤ t ≤ 48), where w is the weight of the dog in kilograms, and t is the age in weeks.
(i) Find the weight of the dog at age 26 weeks according to this model.
(ii) Explain the inequality (20 ≤ t ≤ 48) that follows the equation.
(iii) Using algebra, calculate the age at which the dog’s weight is 40kg
(iv) Write down the gradient of the straight line represented by the equation w = 0.92t−0.15. What does this measure in the practical situation being modelled? (v) Either using Graphplotter or by hand, sketch the graph of w = 0.92t−0.15, putting w on the vertical axis and covering the time interval 20 ≤ t ≤ 48.
(vi) Explain why the model cannot be extended to model accurately the dog’s weight at birth
Answer:
(i)23.77kg
(ii)(ii) the inequality 20≤t≤48 means the weight of the dogs determined is for dogs that have the age of 20 weeks or less to the age of 48 weeks not more.
(iii)44 weeks
(iv)0.92
(v)Attached
(vi)The value of weight will be negative,which is unrealistic.
Step-by-step explanation:
(i)Given that the weight is modeled by the equation;
w = 0.92t−0.15 (20 ≤ t ≤ 48)
then substitute the value of t in the equation given that t=26 weeks
w=0.92*26-0.15=23.77kg
(ii) the inequality 20≤t≤48 means the weight of the dogs determined is for dogs that have the age of 20 weeks or less to the age of 48 weeks not more.
(iii)Apply the equation for weight
w=0.92t-0.15
40=0.92t-0.15
40+0.15=0.92t
40.15=0.92t
40.15/0.92=t
43.6⇒⇒44 weeks
(iv) Here , write the equation in slope intercept form of y=mx+c where m is the slope and c is the y-intercept
w=0.92t-0.15
y=mx+c
m=0.92
(v)sketch attached
(vi)
At birth, t=0 hence to find weight
w=0.92t-0.15
w=0.92*0-0.15
w=0-0.15
w=-0.15
The model cannot be extended to model accurately the dog's weight at birth because you will get a negative value for weight which is not realistic.
If the ratio of m to n is 7 to 6, which of the following could be true?
O A. m = 8, n = 7
O B. m = 12,n= 14
O c.m=14, n=0
OD. m = 42, n = 42
O E. m = 7/3, n = 2
Answer:
E
Step-by-step explanation:
Consider each of the given values for m and n
A
m : n = 8 : 7 ≠ 7 : 6
B
m : n = 12 : 14 = 6 : 7 ≠ 7 : 6
C
m : n = 14 : 0 ≠ 7 : 6
D
m : n = 42 : 42 = 1 : 1 ≠ 7 : 6
E
m : n = [tex]\frac{7}{3}[/tex] : 2 = [tex]\frac{7}{3}[/tex] : [tex]\frac{6}{3}[/tex] = 7 : 6
Thus E is the only true ratio
Answer:
E. m = 7/3, n = 2
Step-by-step explanation:
The correct answer