Think about a carbon atom that is released into the atmosphere from the burning of wood in a campfire. If it were to go through the whole carbon cycle,

Step 1 A caterpillar gets the carbon by eating the tree's leaves.
Step 2 The bird decomposes and the carbon is added to the atmosphere.
Step 3 A bird gets the carbon by eating the caterpillar.
Step 4 The bird flies into a building and dies instantly. It falls to the ground
Step 5 A tree absorbs the carbon from the atmosphere into its leaves for photosynthesis.
plz help me by telling me what order this go's in?

Answer:

Option A= through gates that,s open up

Explanation:

The sodium and potassium ions transfer in and out the axon through electrical process. This process is called depolarization and re-polarization.

Depolarization:

Depolarization is occur when stimulus is given to the resting neuron. In this process gates of sodium ions on the membrane become open and sodium ions that are present out side. inter into the cell. because of this process the charge of the nerve changes (-70 mv to -55 mV).

Re-polarization:

when the re-polarization occur, potassium gates are open and the potassium ions goes outside the membrane. During this process electrical potential becomes negative inside the cell until the potential of -70 mV is re-attain i.e, resting potential.

In short we can say that depolarization allow sodium ions to inter into the nerve membrane and re-polarization allow potassium ions to moves out side the membrane.

Answer:

A.) Through gates that open up

Explanation:

Odyssey ware

Final answer:

In gas chromatography, compounds elute based on their boiling points, with those having lower boiling points eluting first. Since anisole has a lower boiling point than d-limonene, anisole is expected to elute first.

Explanation:

The question asks which compound, anisole or d-limonene, would elute first in gas chromatography (GC) based on their boiling points. In gas chromatography, compounds generally elute in order of increasing boiling points because compounds with lower boiling points have lower retention times on the GC column. Also, the elution order correlates with the strength of intermolecular forces (IMFs) affecting the compounds; compounds with stronger IMFs tend to have higher boiling points and adhere more to the stationary phase, thus eluting later. Although the specific boiling points of anisole and d-limonene are not provided in this answer, it is known that anisole has a boiling point of about 154°C, and d-limonene has a boiling point around 176°C. Therefore, one would expect anisole to elute first in gas chromatography due to its lower boiling point compared to d-limonene.

The biggest elctronegative difference is between silicon and sulfur. So  Si-S will be most polar bond.

The polarity between the two atoms is determined by their relative difference in electronegativity.

The Electronegativity of ,

Silicon= 1.9

Phosphorus= 2.19

Sulfur= 2.58

The direction of polarity,

[tex]\rm \bold{ \delta^+Si\rightarrow \delta^-P}\\\rm \bold{ \delta^+Si\rightarrow \delta^-S}\\\rm \bold{ \delta^+P\rightarrow \delta^-S}[/tex]

Since, the biggest elctronegative difference is between silicon and sulfur (Si-S).

Hence we can say that Si-S will be most polar bond.

To know more about  electronegativity, refer to the link:

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Explanation:

An oxidizing agent is defined as a substance which readily accepts an electron and itself gets reduced in order to oxidize another substance in a chemical reaction.

For example, [tex]2H^{+} + 2e^{-} \rightarrow H_{2}[/tex]

Here, hydrogen is getting reduced as its oxidation state is changing from +1 to 0 and hence it acts like an oxidizing agent.  

In an oxidizing agent, a decrease in oxidation state occurs.

Whereas in [tex]Sn \rightarrow Sn^{2+} + 2e^{-}[/tex], tin is getting oxidized by gaining electrons. Therefore, it is acting as a reducing agent. An increase in oxidation state occurs for a reducing agent.

Thus, we can conclude that in the given reaction hydrogen is the oxidizing agent.

Answer:

[tex]0.00515molCaCO3[/tex]

Explanation:

Hello,

By following the down below simple mass-mole relationship, the requested moles are computed, considering that the calcium carbonate has a molecular mass of 100g/mol:

[tex]M_{CaCO3}=40+12+16*3=100g/mol\\\\n_{CaCO3}=0.515gCaCO3*\frac{1molCaCO3}{100gCaCO3}=0.00515molCaCO3[/tex]

Best regards.

Final answer:

To calculate the number of moles of CaCO₃ in a 0.515 g antacid tablet, divide the mass of the CaCO₃ by its molar mass, yielding approximately 0.005144 moles of CaCO₃.

Explanation:

To find the number of moles of CaCO₃ in an antacid tablet containing 0.515 g of CaCO₃, we need to use the molar mass of CaCO₃. The molar mass of CaCO₃ (calcium carbonate) is approximately 100.09 g/mol. To calculate the moles, we divide the mass of the sample by its molar mass.

The calculation is as follows:

Therefore, there are approximately 0.005144 moles of CaCO₃ in the antacid tablet.

Answer:

The percentage of potassium in the given complex is 35.54 %.

Explanation:

Mass of potassium in [tex]K_3Fe(CN)_6[/tex] = 3 × 39.10 g mol=117.3 g/mol

Molar mass of [tex]K_3Fe(CN)_6[/tex] =329.15 g/mol

Percentage of potassium (K) in the the complex:

[tex]\% K=\frac{\text{mass of potassium}}{\text{molar mass of complex}}\times 100[/tex]

[tex]\%K=\frac{117.3 g/mol}{329.15 g/mol}\times 100=35.54\%[/tex]

The percentage of potassium in the given complex is 35.54 %.

This question involves the application of the Arrhenius equation in chemistry, particularly in calculating the temperature dependence of reaction rates. Given the rate constant and the activation energy at a certain temperature, one can find the rate constant at a different temperature

The question pertains to the use of the Arrhenius equation, which calculates the temperature dependence of reaction rates. The equation is k = A * e^(-Ea/RT), where k is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

The given reaction has a rate constant (k) of 1.35 x 10² s-1 at 25.0°C (or 298.15K). The activation energy (Ea) is given as 85.6 kJ/mol. To find the rate constant at another temperature, rearrange the Arrhenius equation to solve for A, substitute the given values for Ea, k, R and T to find A. Then, plug the calculated A, given Ea, the new temperature in Kelvin (75.0°C or 348.15K), and R into the Arrhenius equation to solve for the new rate constant, k.

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Answer:

No triplet.

Explanation:

A triplet is observed in proton nmr when the neighboring, chemically non equivalent, carbon atoms bear two hydrogen atoms.

Let us examine the structure of o-chlorotoluene [shown in figure].

As shown in the figure there is no carbon bearing two equivalent hydrogen.

There are five non equivalent kind of hydrogen on the molecule

Three hydrogen are equivalent (Ha)

So we will observe only

a) Singlet

b) Doublet

c) Double doublet (split doublet)

Explanation:

It is known that number of moles present in a substance is equal to the mass divided by molar mass.

Mathematically,      No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

As it is given that number of moles are 0.432 moles and molar mass of [tex]C_{8}H_{9}O_{4}[/tex] is 169.15 g/mol.

Hence, calculate the mass of [tex]C_{8}H_{9}O_{4}[/tex] is as follows.

                 No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                     0.432 mol = [tex]\frac{mass}{169.15 g/mol}[/tex]

                         mass = 73.072 g

Thus, we can conclude that the mass of 0.432 moles of [tex]C_{8}H_{9}O_{4}[/tex] is 73.072 g.

[H⁺]=3.608.10⁻¹²

Weak acid ionization reaction occurs partially (not ionizing perfectly as in strong acids)

The ionization reaction of a weak acid is an equilibrium reaction

HA (aq) ---> H⁺ (aq) + A⁻ (aq)

The equilibrium constant for acid ionization is called the acid ionization constant, which is symbolized by Ka

The values ​​for the weak acid reactions above:

[tex]\rm Ka=\dfrac{[H][A^-]}{[HA]}[/tex]

The greater the Ka, the stronger the acid, which means the reaction to the right is also greater

Where Kb is the base ionization constant

LOH (aq) ---> L⁺ (aq) + OH⁻ (aq)

[tex]\rm Kb=\dfrac{[L][OH^-]}{[LOH]}[/tex]

Kb of Ethylamine (C₂H₅NH₂) : 6.4.10⁻⁴

The ethylamine ionization reactions occur in water as follows:

C₂H₅NH₂ + H₂O ⇒ C₂H₅NH₃⁺ + OH⁻

with a Kb value:

[tex]\rm Kb=\dfrac{[C_2H_5NH_3^+][OH^-]}{[C_2H_5NH_2]}[/tex]

for example x = number of moles / concentration that reacts

Initial concentration of  Ethylamine (C₂H₅NH₂) : 1.2.10⁻²

Concentration at equilibrium = 1.2.10⁻²  -x

Initial concentration of C₂H₅NH₃ = 0

Concentration at equilibrium = x

Initial concentration OH⁻ = 0

Concentration at equilibrium = x

so the value of Kb =

[tex]\rm Kb=\dfrac{[x][x]}{[1.2.10^{-2}-x]}\\\\assumption\:x=so\:small\:then\\\\6.4.10^{-4}=\dfrac{x^2}{1.2.10^{-2}}\\\\x^2=7.68.10^{-6}\\\\x=2.771.10^{-3}[/tex]

x = [OH⁻] = 2.771.10⁻³

Ka x Kb = [H⁺] [OH-]

a water equilibrium constant value (Kw) of 1.10⁻¹⁴ at 25 °C

Ka x Kb = [H +] [OH-] = 1.10⁻¹⁴

1.10⁻¹⁴ = [H⁺] . 2.771.10⁻³

[H⁺]=3.608.10⁻¹²

an equilibrium constant https://brainly.com/question/9173805

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Calculate the value of the equilibrium constant, Kc

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Concentration of hi at equilibrium

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Ionic compounds are generally formed from a metal cation (positively charged ion) and a nonmetal anion (negatively charged ion), so the correct answer to your question is option C.

Ionic compounds are typically composed of a metal cation and nonmetal anion. This means the correct answer to your question is option C. A cation is a positively charged ion, and in this context, it is typically formed by an element from the left side of the periodic table, or a metal. An anion, on the other hand, is a negatively charged ion, usually formed by an element from the right side of the periodic table, or a nonmetal. When these ions combine, they create an ionic compound, such as NaCl (sodium chloride), where sodium is the metal cation and chloride is the nonmetal anion.

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Final answer:

Rubbing alcohol molecules as a gas have the same structure as in the liquid but with more kinetic energy and less intermolecular attraction, which upon evaporation causes a cooling effect through evaporative cooling.

Explanation:

When rubbing alcohol evaporates from your hand, it leaves a cooling sensation because the molecules in the liquid state require a certain threshold of kinetic energy to overcome intermolecular forces and escape into a gas state. The correct statement regarding how the molecules of gas compare to the molecules as a liquid is:

In the gaseous state, particles move faster and are further apart compared to when they are in the liquid state, where particles are closer together and have stronger intermolecular attractions. This process of evaporation involves evaporative cooling, where the molecules with higher kinetic energy escape, leaving behind those with lower kinetic energy, which results in a decrease in temperature.

Answer: The formation of water is a chemical change.

Explanation:

Physical change is defined as the change in which change in shape and size takes place. The chemical composition of a substance remains the same. No new substance is formed during this.

For Example: Melting of ice

Chemical change is defined as the change in which change in chemical composition takes place. A new substance is formed in this.

For Example: Formation of water molecule.

The chemical equation for the formation of water molecule follows:

[tex]2H_2+O_2\righatarrow 2H_2O[/tex]

Hence, the formation of water is a chemical change.

Answer : The correct option is, 0.2 mole Y left over .

Explanation : Given,

Moles of X = 4.8 mole

Moles of Y = 3.4 mole

The balanced chemical reaction is,

[tex]3X+2Y\rightarrow X_3Y_2[/tex]

From the balanced reaction, we conclude that

As, 3 moles of X react with 2 moles of Y

So, 4.8 moles of X react with [tex]\frac{2}{3}\times 4.8=3.2[/tex] moles of Y

From this we conclude that, the reactant Y is an excess reagent and X is a limiting reagent.

The moles of excess reagent left over at the end of the reaction = Given moles of X - Required moles of X

The moles of excess reagent left over at the end of the reaction = 3.4 - 3.2 = 0.2 mole

Therefore, the moles of excess reagent left over at the end of the reaction is, 0.2 mole Y left over.

Answer:

The correct answer is : '0.2 mol Y left over'.

Explanation:

[tex]3X + 2Y \rightarrow  X_3Y_2[/tex]

Moles of X = 4.8 moles

Moles of Y = 3.4  moles

According to reaction, 3 moles of X react with 2 moles of Y .

Then 4.8 moles of X react with :

[tex]\frac{2}{3}\times 4.8=3.2 [/tex]moles of Y

Moles of Y reacted = 3.2 moles

Moles of Y left unreacted = 3.4 moles - 3.2 moles = 0.2 moles

As we can see that X is in limiting amount and y is present in an excessive amount.And the left over amount of Y is 0.2 moles.

Answer:

The second structure is the most stable of all three.

Explanation:

The Formal Charge in the different resonance structures of HCNO is,

[tex]\rm FC=V-N+B[/tex]

Where,

FC- Formal charge

V- Valence Electron

N- Non-bonding Electron

B- Number of bonds

So,  Formal charge In the atoms of first resonance structure is

H = 1-0+1=0

C = 4 -4+2 = -2

N = 5 - 0+4 = 1

O = 6 - 2 + 3 = 1

Formal charge In the atoms of Second resonance structure is

H = 1-0+1 = 0

C = 4 - 0 + 4 =0

N = 5 - 0 + 4 = 1

O = 6 - 6+1 = -1

Formal charge In the atoms of Third resonance structure is

H = 1-0 + 1 = 0

C = 4 - 2 +3 = -1

N = 5 - 0 + 4 = 1

O = 6 - 4 +2 = 0  

To Figure out the most stable resonance structure we have to keep two things in mind:

1) The stable molecular structure tend to have the least number of charged atom.

2) In a stable molecular structure the negative charge is present in the more electronegative atom.

Here decreasing order of electronegativity is,

 N > O > C > H

From the Explanation above, the second structure (B) follows both points

Therefore, The second structure is the most stable of all three.

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The order of the reaction with respect to clo2 is 1.

The order of the reaction with respect to clo2 can be determined by comparing the initial rates of different experiments and analyzing the effect of changing the concentration of clo2 on the reaction rate. By comparing the rates of Experiment 1 and Experiment 2, we can see that when the concentration of clo2 is halved, the rate of the reaction is also halved. This indicates that the reaction rate is directly proportional to the concentration of clo2. Therefore, the order of the reaction with respect to clo2 is 1.