This graph describes the motion of a sky diver that jumped from an airplane. The skydiver is MOST LIKELY ?

A) being influenced by equal amounts of gravity and air resistance.
B) slowing down because of an unbalanced force of air resistance.
C) accelerating because of an unbalanced force of gravity.
Eliminate
D) on the ground and is not falling anymore.

The final momentum is 120 kg m/s

Explanation:

According to the impuls theorem, the impulse exerted on an object (the product of force applied and time interval) is equal to its change in momentum. Mathematically:

[tex]F \Delta t = \Delta p = p_f - p_i[/tex]

where

F is the average force on the object

[tex]\Delta t[/tex]  is the time interval during which the force is applied

[tex]p_f[/tex] is the final momentum

[tex]p_i[/tex] is the initial momentum

In this problem:

F = 30 N is the force applied

[tex]\Delta t = 4 s[/tex] is the time interval

[tex]p_i = 0[/tex] is the initial momentum, since the object starts from rest

Solving for [tex]p_f[/tex], we find the final momentum:

[tex]p_f = F\Delta t=(30)(4)=120 kg m/s[/tex]

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Answer:

D

Explanation:

The reproduction parts of the plant are in the flower and around it so this would eliminate the plants ablity to reproduce.

If an object is moving to the right in translational equilibrium, it means the sum of all the forces acting on the object is zero indicating a state of balanced forces. Translational equilibrium indicates the body is moving in a straight line at a constant speed or at rest. Equilibrium does not mean the absence of forces, but the balance of forces.

When an object is moving to the right in translational equilibrium, it means it is in a state of steady motion, either at rest or moving at a constant velocity, with no acceleration. This equilibrium occurs when the sum of all the forces acting on the object is zero, indicating the forces are balanced. If we consider three forces acting on the object: F1, F2, and F3, for it to be in translational equilibrium, the vector sum of the three forces must be zero. This can be represented mathematically as: F1 + F2 + F3 = 0. If any of the forces change its magnitude or direction, it would disrupt the equilibrium status.

Translational equilibrium stands for a body moving in a straight line at a constant speed or being at rest, while rotational equilibrium refers to objects rotating at a constant rotation or being steady.

An important point to remember is that an equilibrium state does not necessarily mean the absence of forces but signifies that forces are equally balanced.

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The gravitational force between the two objects A) It increases.

Explanation:

The gravitational force between two objects is given by:

[tex]F=G\frac{m_1 m_2}{r^2}[/tex] (1)

where

G is the gravitational constant

[tex]m_1, m_2[/tex] are the masses of the two objects

r is the separation between the objects

In this problem, object A and object B are initially at a distance of

r = 100 m

And at that distance, the force between them is

F

Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:

F' > F

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Answer:

wind

Explanation:

A steeper incline plane will require more force to move an object up. This is because the component of the gravitational force acting parallel to the incline increases with the steepness, necessitating a greater force to oppose it. The force required to move objects up an incline plane, therefore, increases with the steepness of the incline.

When analyzing an object at rest on an inclined plane, the force of gravity acting on the object is divided into two crucial components - a force acting perpendicular to the plane and a force acting parallel to the plane. The perpendicular force of weight is typically equal in magnitude, but opposite in direction to the normal force. However, the force that impacts the effort needed to move an object up an incline directly is the component of force acting parallel to the plane.

As the slope of an incline plane gets steeper, this parallel component of the gravitational force increases, and it requires more force to oppose this component and move the object up the incline. Therefore, a steeper incline plane will require more force to move an object up.

In simpler terms, think of it as pushing a cart up a steep hill versus a gentle slope - the steeper hill requires more effort, or force, to push the cart up.

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Answer:

Magnitude 17.85 cm

Angle: 69.36 degrees

Explanation:

Analytical sum of vectors

We have the vector 1 with magnitude 12 cm and angle 45 degrees. We'll find its cartesian components by using

[tex]v1_x=12cos45^o=8.49\ cm[/tex]

[tex]v1_y=12sin45^o=8.49\ cm[/tex]

Now we find the components of v2

[tex]v2_x=8.5cos105^o=-2.2\ cm[/tex]

[tex]v2_y=8.5sin105^o=8.21\ cm[/tex]

To add both vectors, we add their components separately

[tex]\vec{v3}=\vec{v2}+\vec{v1}[/tex]

[tex]v3_x=v1_x+v2_x=8.49\ cm-2.2\ cm=6.29\ cm[/tex]

[tex]v3_y=v1_y+v2_y=8.49\ cm+8.21\ cm=16.7\ cm[/tex]

Magnitude of [tex]\vec{v3}[/tex]:

[tex]\left \| \vec{v3} \right \|=\sqrt{v3_x^2+v3_y^2}[/tex]

[tex]\left \| \vec{v3} \right \|=\sqrt{(6.29)^2+(16.7)^2}[/tex]

[tex]\left \| \vec{v3} \right \|=17.85\ cm[/tex]

Angle of [tex]\vec{v3}[/tex]:

[tex]\theta_3=atan\left ( \frac{16.7}{6.29} \right )=69.36^o[/tex]

Answer:

Impossible to determine

Explanation:

In other words, no machine can be more than 100% efficient. Machines cannot multiply energy or work input. ... If a machine were 100% efficient then it can't have any energy losses to friction, so no friction can be present. In that case the theoretical and actual mechanical advantages would be equal.

Answer:True

Explanation:

Answer:true

Explanation:because the glass material is template and the wood is natural for SAE convention and normalitation have in chard that glass is more resistive than the wood

Answer: A resultant vector

Explanation: Addition of two vectors can not be a scalar because vectors have a magnitude and a direction. so that they are explained by means of these two chacteristics. If addition is different from zero it will give a vector.

The angular acceleration is [tex]6.25 rad/s^2[/tex]

Explanation:

To solve this problem we can use the equivalent of Newton's second law for rotational motions:

[tex]\tau = I \alpha[/tex] (1)

where

[tex]\tau[/tex] is the torque acting on the body

I is the moment of inertia of the body

[tex]\alpha[/tex] is the angular acceleration

In this problem we have:

[tex]\tau = 450 Nm[/tex] is the torque

The moment of inertia of a solid cylinder about its axis is

[tex]I=\frac{1}{2}MR^2[/tex]

where

M = 100 kg is the mass

R = 1.2 m is the radius

Substituting,

[tex]I=\frac{1}{2}(100)(1.2)^2=72 kg m^2[/tex]

And solving eq.(1) for [tex]\alpha[/tex], we find the angular acceleration:

[tex]\alpha = \frac{\tau}{I}=\frac{450}{72}=6.25 rad/s^2[/tex]

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The frequency of the wave is 4 Hz

Explanation:

The relationship between wave, frequency and speed of a wave is given by the equation:

[tex]v=f \lambda[/tex]

where

v is the speed of the wave

f is the frequency

[tex]\lambda[/tex] is the wavelength

For the wave in this problem, we have:

[tex]v=60 cm/s[/tex] is the speed

[tex]\lambda=15 cm[/tex] is the wavelength

Solving the equation for f, we find its frequency:

[tex]f=\frac{v}{\lambda}=\frac{60 cm/s}{15 s}=4 s^{-1} = 4 Hz[/tex]

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Answer:

[tex]\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

Explanation:

Mass of the kid 23.7 kg.

[tex]\text { The kid is accelerating down at an angle is } 47.2^{\circ} .[/tex]

[tex]^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]

We need to find the acceleration of the kid,

We know that, Parallel force acted on the kid at an angle is

F = m × g × sinθ (F = ma)

m × a = m × g × sinθ

Now, substitute the given values in the above formula to find acceleration of the kid,

[tex]23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}[/tex]

23.7 × a = 232.26 × 0.733

23.7 × a = 170.24

[tex]a=\frac{170.24}{23.7}[/tex]

[tex]a=7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

[tex]\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

Answer:  600 kg-m/s

Explanation:

Momentum = mass x velocity

momentum of spaceship 1 = 200 x 2

= 400 kg-m/s

momentum of spaceship 2 = 200 x 2

= 200 kg-m/s

Their combine momentum = 400 + 200 = 600 kg-m/s

The Answer is 600 kg-m/s

Answer:

240 cm³

Explanation:

Weight = Buoyancy

mg = ρVg

m = ρV

(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V

V = 2160 cm³

The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.

Answer:

R=50 meters

Explanation:

We'll use the Pythagoras's theorem

[tex]R^2=a^2+b^2[/tex]

A right triangle with legs of a=40 m and b=30 m has an hypotenuse of

[tex]R^2=30^2+40^2=900+1600[/tex]

[tex]R=\sqrt{2500} =50[/tex]

[tex]R=50\ meters[/tex]

Answer:

b 50

Explanation:

just did it

Answer:

S = 108m

Explanation:

According to Second Law of Motion:

S = Vi*t + 0.5*a*t^2

Vi = 21m/s

a = 3m/s^2

t = 4s

Putting all values in Equation

S = 21*4 + 0.5*3*4^2

S = 84 + 24

S = 108m

Answer:

At the same time.

Explanation:

In the first case ,

intial velocity = 0

displacement = -h

acceleration = -g

Using second equation of motion,

s = ut + .5a[tex]t^{2} \\[/tex]

- h = - 0.5g[tex]t^{2} \\[/tex]

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

In the second case, consider only motion along y axis,

intial velocity = 0 ( all the velocity is along x axis)

displacement = -h ( height is same in both cases)

acceleration = -g

Using second equation of motion,

s = ut + .5a[tex]t^{2} \\[/tex]

- h = - 0.5g[tex]t^{2} \\[/tex]

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

In both cases time is same.

Hence, they will reach the ground simultaneously.

Answer:

The positively charged ions are called cations and negatively charged ions are called anions.

Explanation:

Answer:

I think the answer is A) Power

Explanation:

Answer:

The answer A. Power

Explanation:

Answer:Kinetic Energy. Kinetic energy is motion — of waves, molecules, objects, substances, and objects. Chemical Energy is energy stored in the bonds of atoms and molecules.

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Answer:

Chemical Energy

Explanation:

Energy is the ability to perform work, it is usually stored in many forms. A body at rest has potential energy, a car moving has kinetic energy while  boiling water posses thermal energy. Energy is usually transformed from one form to another, it cant be destroyed.

Chemical energy is the type of energy that is stored in the bonds of the atom of chemical substances. This is the potential energy that is released when the bonds of molecules are broken. For example, the human digestive system breaks down a molecule of food and release mechanical energy for our day to day activities.

The energy stored in between bonds of atoms is chemical energy that are released  and converted to another form of energy when it is broken down.

The force of gravity causes a volleyball to accelerate downwards when it rises in the air.

Initially, as the ball rises, gravity slows down its vertical velocity until it comes to a stop at its maximum height and then starts descending back to the ground due to the force of gravity.

The mass of the water is 41.9 g

Explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex], according to the equation :

[tex]Q=mC_s \Delta T[/tex]

where :

m is the mass of the substance

[tex]C_s[/tex] is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the change in temperature

In this problem, we have:

Q = 525 J is the amount of heat supplied to the water

[tex]\Delta T = 3^{\circ}C[/tex] is the change in temperature of the water

[tex]C_s = 4.18 J/gC[/tex] is the specific heat capacity of the water

Solving for m, we find the mass of the water:

[tex]m=\frac{Q}{C_s \Delta T}=\frac{525}{(4.18)(3.0)}=41.9 g[/tex]

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Final answer:

Using the specific heat capacity formula, we calculate the mass of water that can have its temperature increased by 3.0° C with the addition of 525 J of heat.

Explanation:

To solve the problem presented, we need to use the concept of specific heat capacity, which is the amount of heat required to raise the temperature of one kilogram of a substance by one degree Celsius. The specific heat capacity of water is commonly accepted as 4,184 J/kg/
°C. We can use the formula q = mcΔT, where q is the heat added (in Joules), m is the mass of the water (in kilograms), c is the specific heat capacity, and ΔT is the change in temperature (in degrees Celsius).

We are given q = 525 J and ΔT = 3.0°C. We need to find the mass m. Rearranging the formula to solve for m, we get m = q / (cΔT). Substituting the given values:

m = 525 J / (4,184 J/kg/
°C
* 3.0°C)

By calculating this, we find the mass of water that can have its temperature raised by 3.0°C with 525 J of heat.

Answer:

A. 22 [tex]ms^{-1}[/tex]

B. NO

Explanation:

A.

During a collision , the net external force on the system is zero .

hence , the total momentum of the system can be CONSERVED .

let the mass of frosty and snowflake be m ;

therefore from principle of conservation of momentum ,

[tex]m*v_{F_{i} } +  m*v_{S_{i} } = m*v_{F_{f} } +  m*v_{S_{f} }[/tex]

so ,

[tex]m*25 + m*10 =m*13 +m*x[/tex]

[tex]x = 25+10-13 = 22 ms^{-1}[/tex]

answer for A. 22 [tex]ms^{-1}[/tex]

B.

The collision is NOT ELASTIC.

this is because if it had been elastic , the coefficient of restitution should have been 1 but it isnot i.e

[tex]e =\frac{ v_{F_{f} } - v_{S_{f} } }{ v_{S_{i} } - v_{F_{i} } } \\=\frac{13-22}{10-25} \\=\frac{9}{15} = \frac{3}{5} = 0.6[/tex] ≠ 1

thus it's an inelastic collision.

Particle A orbits the nucleus, and Particle B is located in the nucleus.

Explanation:

The atoms consists of three types of particle:

- Proton: it is located in the nucleus of the atom, its mass is approximately [tex]1.67\cdot 10^{-27}kg[/tex], and its charge is [tex]+e=1.6\cdot 10^{-19}C[/tex] (positive charge)

- Neutron: it is also located in the nucleus of the atom, its mass is similar to that of the proton, and it has no electric charge

- Electron: it orbits around the nucleus, it is much lighter than the proton and the neutron (mass: [tex]9.11\cdot 10^{-31}kg[/tex]), and it is negatively charged ([tex]q=-e=-1.6\cdot 10^{-19}C[/tex])

Looking at the definitions above, and since we know that particle A has very little mass in comparison to particle B (so, particle A must be an electron), we can only conclude the following:

Particle A orbits the nucleus, and Particle B is located in the nucleus.

In fact, we cannot determine whether particle B is a proton or a neutron, since we don't know anything about its charge.

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Answer: the correct answer would be Particle A orbits the nucleus, and Particle B is located in the nucleus. I think Particle A represents the electrons while B represents protons and neutrons.

Explanation:

Answer:

The distance of the student from the center of the merry-go-round is, r = 1.74 m

Explanation:

Given,

The acceleration of the student in merry go round, a = 3.6 m/s²

The tangential velocity of the student is, v = 2.5 m/s

The acceleration of the merry go round is given by the formula,

                                a = v² / r

Therefore,

                                 r = v² / a

                                    = 2.5² / 3.6      

                                    = 1.74 m

Hence, the distance of the student from the center of the merry-go-round is, r = 1.74 m

Answer:

the mass of the object is 10 kg

Explanation:

In the image attached, we can see the free body diagram and using the newton's second law of movement, we will have one equation with one unknown value (the mass of the object).

where:

m [kg]

a [m/s^2]

F [N] or [kg*m/s^2]

Answer:

10kg

Explanation:

The information we have is:

Force: [tex]F=30N[/tex]

acceleration: [tex]a=3m/s^2[/tex]

What we need to know is the mass of the object. For this we can use Newton's second law:

[tex]F=ma[/tex]

Where F is the Force applied, m is the mass of the object, and a is its acceleration.

from this equation we clear for the mass [tex]m[/tex]:

[tex]m=\frac{F}{a}[/tex]

and we substitute the known values:

[tex]m=\frac{30N}{3m/s^2}=10kg[/tex]

The mass of the object is 10kg

The volume of the balloon will halve

Explanation:

Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,

[tex]pV=const.[/tex]

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

[tex]p_1 V_1 = p_2 V_2[/tex]

And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:

[tex]p_1 = 101 kPa[/tex] is the initial pressure at sea level (the atmospheric pressure)

[tex]V_1[/tex] is the initial volume

[tex]p_2 = 202 kPa[/tex] is the final pressure

[tex]V_2[/tex] is the final volume

Substituting into the equation, we find:

[tex]V_2 = \frac{p_1 V_1}{p_2}=\frac{(101)V_1}{202}=\frac{V_1}{2}[/tex]

Which means that the volume of the balloon will halve.

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Answer:

Voltage difference causes charge to flow from higher potential to that of a lower potential.

Explanation:

Voltage Difference:

It is work done per unit charge in moving a charge from one point to another point.

V = Voltage difference

W = Work done

Q = Charge

Then,

[tex]V = \frac{W}{Q}[/tex]

unit : Volt or Joule/Coulomb

Flow of charge :

A free positive charge move from a region of higher potential to that of lower potential whereas a free negative charge moves from lower potential region to a higher potential.

Thus, a voltage difference is required for the flow of charge.

Direction of conventional current is from positive terminal to negative terminal.

Direction of electron is from negative to positive.

Voltage difference causes charge to flow from higher potential to that of a lower potential.

This is also known as Voltage difference and it is the difference in electric potential between two points.

V= W/Q

where v is potential difference, w is work done and q is charges.

This allows for charges to flow from higher potential to that of a lower potential.

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The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

[tex]\sum F_x = ma_x[/tex]

where

m is the mass of the block

[tex]a_x[/tex] is the horizontal acceleration

However, the block is moving at constant speed, so the acceleration is zero:

[tex]a_x = 0[/tex]

So the equation becomes

[tex]\sum F_x = 0[/tex] (1)

The net force here is given by

[tex]\sum F_x = F cos \theta - F_f[/tex] (2)

And so, by combining (1) and (2), we find the magnitude of the friction force:

[tex]F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N[/tex]

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Answer:

gravity

Explanation:

gravity

Answer:

This is because the earth is already going very fast. This means the earth is constantly trying to leave orbit and hurtle off into space like a ball attached to a string would if you spun it around. The only thing keeping that ball from going into your face it the speed.

Explanation:

The gravity is the string.

The earth doesn't really slow down because space offers little resistance.