Trehalose, sophorose and turanose are disaccharides. Trehalose is found in the cocoons of some insects, sophorose turns up in a few bean varieties, and turanose is an ingredient in low-grade honey made by bees with indigestion from a diet of pine tree sap. Identify trehalose, sophorose, and turanose (may be none of the above) among the following structures on the basis of the following information.
a. Turanose and sophorose are reducing sugars. Trehalose is non-reducing.
b. Upon hydrolysis, sophorose and trehalose give two molecules each of aldoses. Turanose gives one molecule of an aldose and one molecule of a ketose.
c. The two aldoses that constitute sophorose are anomers to each other.

Rock candy is formed through a chemical process known as crystallization which requires a supersaturated sugar solution. In the scenario, batch A prepared with hot water is more likely to form rock candy as it can dissolve more sugar creating a supersaturated solution. Batch B prepared at room temperature may not form as much rock candy due to lesser sugar dissolution.

The question relates to the chemical process of crystallization, particularly in the formation of rock candy. When making rock candy, a supersaturated solution of sugar and water is required. This condition is achieved when as much sugar as possible is dissolved in hot water. Once cooled, the oversaturated solution starts to crystallize and forms rock candy. So in the given scenario, batch A is more likely to produce rock candy because it involves the preparation of a supersaturated solution through dissolving sugar in hot water. Batch B, prepared at room temperature, may not dissolve as much sugar as batch A, and thus, less or no rock candy might be formed.

https://brainly.com/question/32130991

#SPJ3

Batch A, which dissolved sugar in hot water that was then cooled, is more likely to form rock candy as the cooling process can lead to the crystallization of sugar from a supersaturated solution.

The process of making rock candy involves dissolving sugar in water to create a saturated solution from which sugar crystals can form upon cooling or evaporation of the solvent. The solubility of sugar increases with temperature, which means hot water can dissolve more sugar than room temperature water. Therefore, for batch A, dissolving sugar in hot water likely supersaturates the solution, and as it cools to room temperature, excess sugar will crystallize out.

Batch B, on the other hand, dissolves sugar at room temperature, potentially creating a saturated solution, but without the temperature change, it is less likely to form a supersaturated environment and thus may yield less crystallization compared to batch A. In summary, batch A is more likely to form rock candy due to the temperature-dependent solubility of sugar, and the cooling process allows crystals to form from the supersaturated solution.

Answer:

a) True

Explanation:

a) From the definition of the equilibrium. When a reversible reaction is carried out in a closed vessel, a stage is reached when the forward and the backward reactions proceed with the same speed. This stage is known as chemical equilibrium.

Answer: The change in energy of the gas mixture during the reaction is 60 kJ. The reaction is endothermic.

Explanation:

According to first law of thermodynamics:

[tex]\Delta E=q+w[/tex]

[tex]\Delta E[/tex]=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system

w = -155 kJ

q = +215kJ   {Heat absorbed by the system is positive}

[tex]\Delta E=+215+(-155)kJ=60kJ[/tex]

As the heat is absorbed and enthalpy increases, the reaction is endothermic.

Answer:

0.1046M NaOH solution

Explanation:

a. KHP is a salt used as primary standard because allows direct standarization of bases solutions. The reaction of KHP with NaOH is:

KHP + NaOH → H₂O + KP⁻ + Na⁺

As you can see, KHP has 1 acid proton that reacts with NaOH.

Molar mass of KHP is 204.22g/mol; 0.5527g of KHP contains:

0.5527g KHP × (1mol / 204.22g) = 2.706x10⁻³moles of KHP. As 1 mole of KHP reacts per mole of NaOH, at equivalence point you must add 2.706x10⁻³moles of NaOH

As you spent 25.87mL of the solution, molarity of the solution is:

2.706x10⁻³moles of NaOH / 0.02587L = 0.1046M NaOH solution

Answer:

NaOH + KHC8H4O4 → NaKC8H4O4 + H2O

Concentration NaOH = 0.105 M

Explanation:

Step 1: Data given

Mass of KHP = 0.5527 grams

Molar mass KHP = 204.22 g/mol

Volume of NaOH = 25.87 mL

Step 2: The balanced equation

NaOH + KHC8H4O4 → NaKC8H4O4 + H2O

Step 3: Calculate moles KHP

Moles KHP = mass KHP / molar mass KHP

Moles KHP = 0.5527 grams / 204.22 g/mol

Moles KHP = 0.002706 moles

Step 4: Calculate moles NaOH

For 1 mol NaOH we need 1 mol KHP to react

For 0.002706 moles KHP we need 0.002706 moles NaOH

Step 5: Calculate concentration NaOH

Concentration = moles / volume

Concentration NaOH = 0.002706 moles / 0.02587 L

Concentration NaOH = 0.105 M

Answer:

pH = 6.82

Explanation:

To solve this problem we can use the Henderson-Hasselbach equation:

We're given all the required data to calculate the original pH of the buffer before 0.341 mol of HCl are added:

By adding HCl, we simultaneously increase the number of HOCl and decrease NaOCl:

Answer:

Details of true/false statements are given below.

Explanation:

The rate law is deduced directly from the coefficients of the overall reaction. False

The rate equation for this mechanism is rate = k [O][ClO]. ClO(g) is an intermediate formed in this reaction mechanism. True

Step 2 of the mechanism is a bimolecular. True

The sum of the two steps is equal to the overall reaction: O(g) + O3(g) → 2O2(g). True

Cl(g) is a catalyst in this reaction mechanism. True

Answer:

See explanation below

Explanation:

The anode reaction is :

2I^-(aq) -------> I2(g) +2e

Cathode reaction

F2(g) + 2e------> 2F^-(aq)

In the external circuit, electrons migrate from the I-|I2 electrode (anode) to the F-|F2 electrode (cathode)

In the salt bridge, anions migrate from the F-|F2

A voltaic cell is a type of cell in which a spontaneous redox reaction generates an electric current. This current is generated by the migration of electrons from the anode to the cathode in the external circuit, and the migration of anions in the salt bridge maintains electrical neutrality.

A voltaic cell is a type of electrochemical cell where a spontaneous redox reaction generates an electric current. In this particular voltaic cell, the anode reaction is 2I-(aq) -> I2(s) + 2e-, where iodide ions are oxidized to solid iodine (losing electrons). The cathode reaction is F2(g) + 2e- -> 2F-(aq), where gaseous fluorine is reduced to fluoride ions (gaining electrons).

In the external circuit, electrons migrate from the anode (I-|I2 electrode) to the cathode (F-|F2 electrode). This migration of electrons generates the electric current. Lastly, in the salt bridge, anions migrate from the anode compartment (I-|I2) to the cathode compartment (F-|F2), allowing the cell to maintain electrical neutrality throughout the redox reaction.

https://brainly.com/question/29186551

#SPJ11

Correct answer:

•Does pressure have an effect on the volume of a gas?

•Which brand of soap is the best for cleaning grease off dishes?

The questions that can be answered by science must be empirical, that is they must be answerable by experiments.

The question that can be answered by science is; Which brand of soap is the best for cleaning grease off dishes?

This question can be answered by using various brands of soap to clean the same type of dish with the same type of grease and comparing the results. The answer to this question is pure empirical.

The other questions listed can not be answered by experiment. Their answer may vary from person to person therefore they are not scientific questions.

Learn more: https://brainly.com/question/20955213

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correction option is  is  [tex]I[/tex]

Explanation:

  The mechanism of the reaction is show on the second uploaded image

Explanation:

Given that,

The wavelength of high‑frequency radio wave, [tex]\lambda=0.25\ km=250\ m[/tex]

We need to find the energy of exactly one photon of this radio wave radiation. It is given by :

[tex]E=\dfrac{nhc}{\lambda}[/tex]

Here, n = 1

[tex]E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{250}\\\\E=7.95\times 10^{-28}\ J[/tex]

So, the energy of exactly one photon of this radio wave radiation is [tex]7.95\times 10^{-28}\ J[/tex].

The energy of exactly one photon of this radio wave radiation is [tex]7.95 \times 10^{-28}J[/tex].

Given that,

Based on the above information, the calculation is as follows:

We know that

[tex]E = nhc \div \lambda\\\\= (6.63 \times 10^{-34} \times 3 \times 10^8) \div 250[/tex]

= [tex]7.95 \times 10^{-28}J[/tex]

Therefore we can conclude that the energy of exactly one photon of this radio wave radiation is [tex]7.95 \times 10^{-28}J[/tex].

Learn more: brainly.com/question/23334479

The concentration of the unknown solution 'Q' from Part B is determined to be 0.282 M using Beer's Law. The original concentration of the unknown 'Q' from Part A, before dilution, is calculated to be 0.94 M.

The concentration of the unknown solution Q can be determined using the Beer's Law plot. Beer's Law or the Beer-Lambert law connects the absorbance of a solution to its concentration through the following equation: A = εcl, where 'A' is the absorbance, 'ε' is the molar absorptivity, 'c' is the concentration and 'l' is the path length. The slope of the Beer's Law plot corresponds to the product, 'εl'. So, the concentration can be calculated as: c=A/(εl), which gives c= 0.145/0.515 M-1 = 0.282 M

Regarding the dilution of the solution in Part A, we are given that 15.00 mL of the solution was diluted to a final volume of 50.00 mL. This can be used to calculate the original concentration. The formula used in this case is C1V1 = C2V2, where C1 is the original concentration, V1 is the original volume, C2 is the diluted concentration, and V2 is the final volume. Substituting C2 with the concentration we just calculated, the original concentration C1 can be calculated as: C1 = (C2V2)/V1 = (0.282 M × 50.00 mL)/ 15.00 mL = 0.94 M.

https://brainly.com/question/33649091

#SPJ11

If the standard reduction potential of a half-cell is positive, the reduction reaction is spontaneous when paired with a hydrogen electrode

Explanation:

Answer:

Reduction

Explanation:

Answer:

The equilibrium constant at 2000 K is 0.7139

The equilibrium constant at 3000 K is 8.306

ΔH = 122.2 kJ/mol

Explanation:

Step 1: Data given

the standard molar Gibbs energy of formation of X(g) is 5.61 kJ/mol at 2000 K

the standard molar Gibbs energy of formation of X(g) is -52.80 kJ/mol at 3000 K

Step 2: The equation

1/2X2(g)⟶X(g)

Step 3: Determine K at 2000 K

ΔG = -RT ln K

⇒R = 8.314 J/mol *K

⇒T = 2000 K

⇒K is the equilibrium constant

5610 J/mol = -8.314 J/molK * 2000 * ln K

ln K = -0.337

K = e^-0.337

K = 0.7139

The equilibrium constant at 2000 K is 0.7139

Step 4: Determine K at 3000 K

ΔG = -RT ln K

⇒R = 8.314 J/mol *K

⇒T = 3000 K

⇒K is the equilibrium constant

-52800 J/mol = -8.314 J/molK * 3000 * ln K

ln K = 2.117

K = e^2.117

K = 8.306

The equilibrium constant at 3000 K is 8.306

Step 5: Determine the value of ΔH∘rxn

ln K2/K1 = -ΔH/r * (1/T2 - 1/T1)

ln 8.306 /0.713 = -ΔH/8.314 * (1/3000 - 1/2000)

2.455 = -ΔH/8.314 * (3.33*10^-4 - 0.0005)

2.455 = -ΔH/8.314 * (-1.67*10^-4)

-14700= -ΔH/8.314

-ΔH = -122200 J/mol

ΔH = 122.2 kJ/mol

When The constant at 2000 K is 0.7139

Then The constant at 3000 K is 8.306

ΔH = 122.2 kJ/mol

Step 1: Data is given

When the quality molar Gibbs effectiveness of the formation of X(g) is 5.61 kJ/mol at 2000 K

When the quality molar Gibbs effectiveness of the formation of X(g) is -52.80 kJ/mol at 3000 K

Step 2: The equation is:

[tex]1/2X2(g)⟶X(g)[/tex]

Step 3: Then Determine K at 2000 K

ΔG = -RT ln K

[tex]⇒R = 8.314 J/mol *K[/tex]

⇒[tex]T = 2000 K[/tex]

⇒ at that time K is that the constant

Then 5610 J/mol = [tex]-8.314 J/molK * 2000 * ln K[/tex]

ln K is = [tex]-0.337[/tex]

K is =[tex]e^-0.337[/tex]

K is = [tex]0.7139[/tex]

When The constant at 2000 K is 0.7139

Step 4: Then Determine K at 3000 K

ΔG = -RT ln K

⇒[tex]R = 8.314 J/mol *K[/tex]

⇒[tex]T = 3000 K[/tex]

⇒K is that the constant

[tex]-52800 J/mol = -8.314 J/mol K * 3000 * ln K[/tex]

ln [tex]K = 2.117[/tex]

K = e^2.117

K = 8.306

The constant at 3000 K is 8.306

Step 5: at the moment Determine the worth of ΔH∘rxn

ln K2/K1 = -ΔH/r * (1/T2 - 1/T1)

ln 8.306 /0.713 = -Δ[tex]H/8.314 * (1/3000 - 1/2000)[/tex]

2.455 = -ΔH/8.314 * (3.33*10^-4 - 0.0005)

2.455 = -ΔH/8.314 * [tex](-1.67*10^-4)[/tex]

-14700= -ΔH/8.314

-ΔH = [tex]-122200 J/mol[/tex]

Then ΔH = [tex]122.2 kJ/mol[/tex]

Find more information about Equilibrium here:

https://brainly.com/question/26251269

Answer:

[tex]m_{ice} = 65.336\,g[/tex]

Explanation:

Accoding to the First Law of Thermodynamics, the heat released by the water melts a portion of ice. That is to say:

[tex]Q_{water} = Q_{ice}[/tex]

[tex](100\,g)\cdot \left(4.184\,\frac{J}{kg\cdot ^{\textdegree}C}\right)\cdot (52\,^{\textdegree}C - 0\,^{\textdegree}C) = m_{ice}\cdot \left(333\,\frac{J}{g} \right)[/tex]

The amount of ice that is melt is:

[tex]m_{ice} = 65.336\,g[/tex]

Answer:

These three factors are required for ionization potential or ionization energy.

Explanation:

Ionization potential refers to the amount of energy which is required for the removal of outermost electron of the atom. If the atom size is big so the outermost electron is far from the nucleus and low energy is required for its removal due to lower force of attraction between nucleus and outermost electron. If the nuclear charge is higher, so the electron is tightly held by the nucleus and require more energy for its removal. Nuclear charge means number of protons present in the nucleus.

Answer:

Density= 1.7g/dm3

Explanation:

Applying

P×M= D×R×T

P= 2atm, Mm= 28, D=? R= 0.082, T= 400K

2×28= D×0.082×400

D= (2×28)/(0.082×400)

D= 1.7g/dm3

Answer:

The reduced coenzymes generated by the citric acid cycle donate electrons in a series of reactions called the electron transport chain. The energy from the electron transport chain is used for oxidative phosphorylation.

a)The compounds that donate electrons to the electron transport chain are NADH and . FADH2

b) O2 is the final electron acceptor.

c) The final products of the electron transport chain and oxidative phosphorylation are NAD+, H2O, ATP and FAD

Explanation:

Answer : The line-bonds structure of oleic acid (cis‑9‑octadecenoic acid) is shown below.

Explanation :

In line-bonds formula, the organic structures of the compound are represented in such a way that covalent bonds are represented by line and frame the structure by zig-zag straight lines which emits all the hydrogen atom.

The terminals of the line and vertex represents carbon atoms whose valences are satisfied by formation of single bonds with H atom.

The given compound is, (cis‑9‑octadecenoic acid)

In this compound, the parent chain is 18 membered and the carboxylic acid functional group is attached to it.

Answer:

1) H₂O₂ + 2H⁺ + 2e⁻ → 2H₂O

2) H₂O₂ → 2H⁺ + 2e⁻  O₂

3) 2H₂O₂ → 2H₂O + O₂

Explanation:

Half-reaction equation for when H₂O₂(aq) acts as an oxidizing agent in an acidic solution (this means H₂O₂ is reduced):

It is a reduction because the oxidation number of O changes from -1 to -2.

Half-reaction equation for when H₂O₂(aq) acts as a reducing agent in an acidic solution (this means H₂O₂ is oxidized):

H₂O₂ → 2H⁺ + 2e⁻  O₂

It is an oxidation because the oxidation number of O changes from -1 to 0.

Disproportionation reaction of H₂O₂(aq):

2H₂O₂ → 2H₂O + O₂

Hydrogen peroxide can act as both an oxidizing and a reducing agent in an acidic solution. It becomes oxidized when acting as a reducing agent and gets reduced when it acts as an oxidizing agent. In a disproportionation reaction, it can both oxidize and reduce itself.

Hydrogen peroxide (H2O2) can indeed act as either an oxidizing or reducing agent depending on the species present in solution. When

H2O2

acts as an oxidizing agent in an acidic solution, the balanced half-reaction is:

H2O2 + 2H+ + 2e- → 2H2O

This reaction shows H2O2 being reduced, thus it is acting as an oxidizer because it causes the oxidation of other substances by accepting electrons. In contrast, when

H2O2 acts as a reducing agent in an acidic solution, the balanced half-reaction is:

H2O2 → O2 + 2H+ + 2e-

In this case, H2O2 is being oxidized to O2 so it acts as a reducer because it donates electrons which allows the reduction of other substances.

Finally, in a disproportionation reaction, H2O2 can act as both the oxidizing and reducing agent, showing the same substance functioning as an oxidant and a reductant. The complete balanced equation for this disproportionation reaction of H2O2 is:

2H2O2 → 2H2O + O2

https://brainly.com/question/13978139

#SPJ12

Answer:

B) I2(s) is a stronger oxidizing agent than Al3 (aq), and Al(s) is a stronger reducing agent than I-(aq).

Explanation:

An oxidizing agent accepts electrons in a redox reaction and become reduced while a reducing agent looses electrons and become oxidized.

Hence in a redox reaction, oxidizing agents are reduced while reducing agents are oxidized.

Looking at I2 and Al3+, I2 is a better oxidizing agent since it has a reduction potential of +0.54V compared to -1.66V for Al3+.

Given the statements above, the converse must be true, that is; All is a better reducing agent compared to I-

Answer:

The standard entropy change for the reaction is -197.8 J/mol*K

Explanation:

Step 1: Data given

S°(CO(g)) = 197.7 J/(mol*K)

S°(CO2(g)) = 213.8 J/(mol*K)

S°(NO(g)) = 210.8 J/(mol*K)

S°(N2(g)) = 191.6 J/(mol·K)

Step 2: The balanced equation

2 CO(g) + 2 NO(g) → N2(g) + 2 CO2(g)

Step 3: Calculate ΔS°

ΔS° = ∑S°(products) - ∑S°(reactants)

ΔS° = (191.6 + 2*213.8) - (2*210.8+2*197.7)  J/mol*K

ΔS° = 619.2 J/mol*K - 817.0 J/mol *K

ΔS° = -197.8 J/mol* K

The standard entropy change for the reaction is -197.8 J/mol*K

Answer:funk

hot dog cat

Explanation:

uhughuhuhuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

Answer:

They occur when the sun reaches its highest or lowest point in the sky

The charges and sizes of ions in an ionic compound determine the strength of its lattice energy.

The strength of the lattice energy in an ionic compound is determined by the charges and sizes of the ions. The larger the charges and the smaller the ion sizes, the stronger the electrostatic interaction and the higher the lattice energy. Based on this, the compounds can be arranged in order of their magnitudes of lattice energies:

MgS has the highest lattice energy because of the high charge and small size of both the Mg2+ and S2- ions.

So the order of lattice energies would be: MgS > MgCl_2 > NaCl > KBr

https://brainly.com/question/34679410

#SPJ3

Answer:

Methane is produced as a new product.

Explanation:

[tex]CH_{3}MgBr[/tex] acts as a base toward -COOH group in p-methylbenzoic acid.

Hence an acid-base reaction occurs between p-methylbenzoic acid and [tex]CH_{3}MgBr[/tex] to produce methane and p-methylbenzoate.

[tex]H_{3}O^{+}[/tex]addition will convert p-methylbenzoate back to p-methylbenzoic acid.

Hence, methane is produce as a new product.

Reaction sequences are given below.

Answer:

At [tex]P_{total} = 0.240\ atm[/tex]; 95.0% of the molecules will dissociate at this temperature

Explanation:

The chemical  reaction of this dissociation is:

[tex]O_2 \leftrightarrow 2O_g[/tex]

The ICE table is as follows:

                        [tex]O_2 \ \ \ \ \ \ \ \leftrightarrow \ \ \ \ \ \ \ \ 2O_g[/tex]

Initial               100                        0

Change            -83                      +166

Equilibrium          17                      166

The mole fractions of each  constituent is now calculated as:

[tex]Mole \ fraction \ of \ O(X_o) = \frac{166}{183}[/tex] = 0.9071

[tex]Mole \ fraction \ of \ O_2(X_o_2_}}) = \frac{17}{183}[/tex] = 0.0929

Given that the total pressure [tex]P_{total}[/tex] = 1.000 atm ; the partial pressure of each gas is calculated by using Raoult's Law.

[tex]Partial \ Pressure \ of \ O (P_o) = X_oP_{total}\\\\ = 0.9071 \ atm[/tex]

[tex]Partial \ Pressure \ of \ O_2 (P_o_2) = X_oP_{total}\\\\ = 0.0929 \ atm[/tex]

Now; we proceed to determine the equilibrium constant [tex]K_c[/tex]; which is illustrated as:

[tex]K_c = \frac{Po^2}{Po_2} \\ \\ K_c = \frac{(0.9072)^2}{0.0929} \\ \\ =8.86 \ atm[/tex]

Let assume that the partial pressure of [tex]O_2[/tex] be x ;&

the change in pressure of  [tex]O_2[/tex] be y ; then

we can write that the following as the changes in concentration of species :

                          [tex]O_2 \ \ \ \ \ \ \ \leftrightarrow \ \ \ \ \ \ \ \ 2O_g[/tex]

Initial                    x                         0

Change              -y                          +2 y

Equilibrium         x - y                    2 y

From above; we can rewrite our equilibrium constant as:

[tex]K_c = \frac{(2y)^2}{x-y} \\ \\ 8.86 = \frac{(2y)^2}{x-y} ----- equation (1)[/tex]

From the question; we are told that provided that 95% of the molecules dissociate at this temperature. Therefore, we have:

[tex]\frac{y}{x}*100 = 95[/tex]%   -------- equation (2)

Solving and equating equation 1 and 2 ;

x = 0.123 atm

y = 0.117 atm

Thus, the pressure required can be calculated as :

[tex]P_{total} = (x-y) +2y \\ \\ P_{total} = (0.123- 0.117)+ 2(0.123) \\ \\ \\ P_{total} = 0.240 \ atm[/tex]

Question:

The question is incomplete. See the attached file for the complete question and answer.

Explanation:

Find attached for explanation.

The first two pages is the additional question while the 3rd and last page is the answer .

Answer:

a. Minimum 1.70 V

b. There is no maximum.

Explanation:

We can solve this question by remembering that the cell potential is given by the formula

ε⁰ cell = ε⁰ reduction -  ε⁰  oxidation

Now the problem states the cell must provide at least 0.9 V and that the reduction potential of the  oxidized species  0.80 V, thus

ε⁰ reduction -  ε⁰  oxidation ≥  ε⁰ cell

Since ε⁰  oxidation is by definition the negative of ε⁰ reduction , we have

ε⁰ reduction - ( 0.80 V )  ≥  0.90 V

⇒ ε⁰ reduction  ≥ 1.70 V

Therefore,

(a) The minimum standard reduction potential is 1.70 V

(b) There is no maximum standard reduction potential since it is stated in the question that we want to have a cell that provides at leat 0.9 V

Answer:

A. The molar mass of the unknown gas is 16g/mol

B. Compound is CH4 i.e methane

Explanation:

A. Step 1:

Representation:

Let t1 be time for unknown gas

Let t2 be the time for bromine vapor

Let M1 be molar mass of the unknown gas

Let M2 be the molar mass of bromine vapor

A. Step 2 :

Data obtained from the question.

Time for the unknown gas (t1) = 1.50 min

Time for Br2 (t2) = 4.73 min

Molar Mass of unknown gas (M1) =?

Molar Mass of Br2 (M2) = 80 x 2 = 160g/mol

A. Step 3:

Determination of the molar mass of the unknown gas.

Applying the equation:

t2/t1 = √(M2/M1)

The molar mass of can be obtained as follow:

t2/t1 = √(M2/M1)

4.73/1.5 = √(160/M1)

Take the square of both side

(4.73/1.5)^2 = 160/M1

9.94 = 160/M1

Cross multiply to express in linear form.

9.94 x M1 = 160

Divide both side by 9.94

M1 = 160/9.94

M1 = 16g/mol

Therefore, the molar mass of the unknown gas is 16g/mol

B. Identification of the gas.

The gas contains C and H only. From the calculations made above, the molar mass of the unknown gas is 16g/mol.

We know also that the molar mass of carbon is 12g/mol and that of Hydrogen is 1g/mol

Therefore,

C + H = 16

There would be only 1 atom of C in the compound since the molar mass of the compound is 16g/mol. With these understanding, let us determine the number of H atom in the compound. This is illustrated below :

C + H = 16

12 + H = 16

H = 16 - 12

H = 4

Divide by the molar mass of H i.e 1

H = 4/1 = 4

There are 4 atoms of H in the compound. Therefore, the compound is CH4 i.e methane

The molar mass of the unknown gas is 16 g/mol hence the unknown gas is methane.

We must note that the time taken for a gas to diffuse is directly proportional to the molar mass of the gas.

Hence;

t1/t2 = √M1/M2

Let t1 = time taken for the flammable gas to diffuse = 1.50 min

Let t2 = time taken for the bromine vapor to diffuse = 4.73 min

M1 = molar mass of the flammable gas = ?

M2 = molar mass of the bromine vapor = 160 g/mol

Substituting values;

1.50/4.73 = √M1/160

(1.50/4.73)^2 = M1/160

0.1006 =  M1/160

M1 = 0.1006 × 160

M1 = 16 g/mol

The unknown gas is methane.

Learn more: https://brainly.com/question/24381583

Answer: The pressure that is needed is around 405kPa-755kPa

To summarize into 405PPM-755PPM

Explanation: In which 405 PPM-755 PPM which is about the same amount of pressure that water pressurises a car in water or a better example is that it's the same amount of pressure as if a penny was dropped from the sky towards a person holding a square piece of cardboard in which then the penny would directly go straight through the piece of cardboard.

Answer:

Explanation:

1s²2s²2p⁶3s² = magnesium ionization energy, 0.738 MJ/mol atomic radius 160 pm

1s²2s²2p⁶3s¹ = Sodium, ionization energy, 0.496 MJ/mol, atomic radius 186 pm

1s²2s²2p⁵ = Florine ionization energy, 1.681 MJ/mol, atomic radius 64 pm

Ionization energy is the minimum amount of energy needed to remove an electron from its orbital around the atom from the influence of the atom while atomic radius is one-half the distance between the nuclei of identical atoms that are bonded together.