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Related Questions
In which graph does y vary directly as x? It’s not C, I got it wrong.
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What information is found in the left column of a two column proof?
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Answer: C) Statements
A statement is simply a sentence with words and/or math expression. For example, one statement could be "Segment AB is parallel to segment CD". That same statement can be translated to "AB || CD". The two vertical lines indicate "parallel".
What is the y-intercept of the line that has a slope of -1/2 and passes through the point (2, 3)?
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y - 3 = -1/2(x) + 1
y = -1/2(x) + 4
y intercept is 4
answer
y intercept (0,4)
what are the slope and why intercept shown on the graph below
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Let's start by finding the slope of the line. You can calculate the slope by dividing the change in y-values by the change in x-values using the following formula:
[tex] \frac{ y_{1}- y_{2} }{ x_{1} - x_{2} } [/tex]
The plotted coordinates are (0, 5) and (4, -5); let's plug those into the formula:
[tex] \frac{5(-5)}{0-4} [/tex]
Simplify:
[tex] \frac{5+5}{-4} [/tex]
[tex] \frac{10}{-4} [/tex]
[tex] \frac{-5}{2} [/tex]
The slope is [tex] \frac{-5}{2} [/tex].
Now, the y-intercept is where the line intersects the y-axis, or when x equals 0. x equals 0 when y equals 5, so the y-intercept is 5.
I hope this helps!
y2 = -5
y1 = 5
x2 = 4
x1 = 0
Let's subtract. -5 - 5 is -10. 4 - 0 is 4. -10/4 is -2 1/2 in simplest form or -5/2 as a mixed number. We found the slope. The y-intercept is where the line crosses, where the x-axis is 0. In this case, we can see by the point given out that the slope intercept is 5. There. The slope is -5/2 and the slope-intercept is 5. The answer is B.
What is the sum of 4.2 × 105 and 5.3 × 10^5?
A.)95 × 10^5
B.)95 × 10^10
C.)9.5 × 10^5
D.)9.5 × 10^10
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441 + 530000
530441
-----------
If your problem is (4.2*10^5)+(5.3*10^5), it would be
420000 + 530000
950000
Answer:
Option C.
Step-by-step explanation:
The two expressions are [tex]4.2\times 10^{5}[/tex] and [tex]5.3\times 10^{5}[/tex]
We have to find the total of these two terms.
[tex](4.2\times 10^{5}[/tex] + [tex]5.3\times 10^{5})[/tex]
Now we take out [tex]10^{5}[/tex] as a common term.
[tex]10^{5}(4.2+5.3)[/tex]
= [tex]9.5\times 10^{5}[/tex]
Therefore, Option C. will be the answer.
Matt has $550 in his savings account. He is eager to know how much interest the bank will pay him for the whole year. He knows that the bank pays a 3 percent interest rate. He sits down with a pen, paper, and calculator to find out the simple interest. Let’s help him out. Matt has already jotted down the formula he needs to use: I = P × r × t First, help him substitute the correct values in this formula. Write down the appropriate numbers for principal, rate of interest, and time
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I=P×r×t
P=principle amount (amount invested)
r=rate
t=time
From the information given:
P=$550
r=0.03
t=1
therefore
I=550*0.03*1
I=$16.5
Answer:I = 550 × 0.03 × 1
Step-by-step explanation: from plato
the radius of a quarter circle is 1 mile. What is the quarter circle's perimeter?
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A jar of crunchy peanut butter contains 1.35 kg of peanut butter. if you use 8.0 % of the peanut butter for a sandwich, how many ounces of peanut butter did you take out of the container?
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-The jar of crunchy peanut butter contains 1.35 kilograms of peanut butter.
-You use 8.0 % of the peanut butter.
2. You must convert 1.35 kilograms to ounces, as below:
1 kilogram=35.2739 ounces
=(1.35 kilogram)(35.2739 ounces/1 kilogram)
=1.35x35.2739 ounces
=47.61 ounces
3. Then, you have:
47.61 ounces-----100%
x-----8%
8%/100=0.08
100%/100=1
x=(0.08x47.61 ounces)/1
x=3.80 ounces
How many ounces of peanut butter did you take out of the container?
The answer is: 3.80 ounces
There are approximately 2.2 million births in a country each year. Find the births per minute.
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2. you divide by 24 to get per hour,
3. and then divide by 60 to get per minute.
(1. days in a year, 2. hours in a day, 3. minutes in an hour)
An electronics shop offers a small ic chip for $1.50 per unit and $4.00 for large ic chip. on a certain day, 2200 chips were sold and $5050 is collected. how many small ic chips and how many large ic chips were sold?
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.. s + l = 2200
.. 1.50s +4.00l = 5050
Solving these by your favorite method gives
.. s = 1500
.. l = 700
1500 small ICs and 700 large ICs were sold.
To determine the number of small and large IC chips sold, we set up a system of linear equations with the given total number of chips (2200) and total earnings ($5050). Solving the system, we found that 1500 small IC chips and 700 large IC chips were sold.
To solve the problem, we can set up a system of linear equations to represent the sales for small and large IC chips. We have two unknowns: the number of small IC chips (let's call it x) and the number of large IC chips (let's call it y). We have two pieces of information to create our equations:
The total number of chips sold is 2200, so x + y = 2200.
The total amount collected is $5050, so 1.50x + 4.00y = 5050.
Solving this system of equations, we multiply the first equation by 1.50 to align it with the second equation:
1.50x + 1.50y = 3300 (Multiply the first equation)
1.50x + 4.00y = 5050 (Second equation)
Subtracting the first new equation from the second gives us:
2.50y = 1750
Dividing both sides by 2.50 to find y gives us y = 700. That means 700 large IC chips were sold. Now, we can substitute y in the first equation to find x:
x + 700 = 2200
x = 2200 - 700
x = 1500
Hence, 1500 small IC chips and 700 large IC chips were sold.
a coin is tossed twice what is the probability of the coin landing heads up both times
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The successful result is 1/2 * 1/2 = 1/4.
You can make a table to show this.
H H
T H
H T
T T
1/4 ways gives 2 heads. <<<< answer
Experts/ace/geniuses
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5 3/4 in a improper fraction?
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Which of the following describes the roots of the polynomial function f(x)=(x-3)^4(x-6)^2? –3 with multiplicity 2 and 6 with multiplicity 4 –3 with multiplicity 4 and 6 with multiplicity 2 3 with multiplicity 2 and –6 with multiplicity 4 3 with multiplicity 4 and –6 with multiplicity 2
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For example, this term is used to refer to the number of times a certain polynomial has a root at a certain point.
For this polynomial we have:
f (x) = (x-3) ^ 4 (x-6) ^ 2
3 with multiplicity 4 and 6 with multiplicity 2
Answer:
3 with multiplicity 4 and 6 with multiplicity 2
Answer:
3 with multiplicity 4 and -6 with multiplicity 2
Surface area of right cone radius of 8 and 14 height
A. 896
B. 224
C. 176
D. 167
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The value of Surface area of right cone with radius of 8 and 14 height is,
⇒ SA = 606.31
What is Multiplication?To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
Radius of cone = 8
And, Height = 14
We know that;
Surface area of right cone is,
SA = πr (r + √h² + r²)
SA = 3.14 × 8 (8 + √14² + 8²)
SA = 606.31
Thus, The value of Surface area of right cone with radius of 8 and 14 height is,
⇒ SA = 606.31
Learn more about the multiplication visit:
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G let z be a random variable with a standard normal distribution. find the indicated probability. p(z ≤ −0.27)
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The probability P(Z <= -0.27) in a standard normal distribution is determined by finding the corresponding right-tail probability of Z = 0.27 and subtracting it from 1, reflecting the distribution's symmetry.
To find the probability P(Z \<= -0.27), we use the properties of the standard normal distribution, which is symmetric about zero. The probability of Z scoring below -0.27 is equal to the probability of Z scoring above 0.27 due to this symmetry. Looking up the corresponding value for Z = 0.27 in a standard normal table, or using a calculator, we would find the right-tail probability. To get our desired left-tail probability for Z = -0.27, we subtract this from 1. For example, if the right-tail probability for Z = 0.27 was 0.3936, then P(Z \<= -0.27) would be 1 - 0.3936 = 0.6064.
tossing a number cube numbered from 1 to 6 and getting an even number that is greater than or equal to 2
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Experts/ace/geniuses
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eva estimates that 475 songs will fit on her mp3 player the actual that fit is 380 findc the percent error
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https://studysoup.com/questions/math/100256/eva-estimates-the-475-songs-will-fit-on-mp3-player
Does anyone know how to prove that OAC and OBC are Congruent.
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The first step is to see that sides OA, OC, OB are all equal because they are the radii of the circle. Knowing that those sides are equal means that we have isosceles triangles. That gives us that the base angles are the same.
In OAC, we can subtract 118 from 180 to give us 62 degrees for the 2 bases angles. This would make each angle 31 degrees.
In OBC, the base angles are already 31, leaving the other angle 118.
There we have all the angles the same and 2 sides the same.
You could use SAS or ASA to prove that the triangles are congruent.
I hope this helps!
Good luck,
MrEquation
Answer:
You could use SAS or ASA to prove that the triangles are congruent.
Step-by-step explanation:
Find the area under the curve y = 5/x3 from x = 1 to x = t. evaluate the area under the curve for t = 10, t = 100, and t = 1000. t = 10 t = 100 t = 1000 find the total area under this curve for x ≥ 1.
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The area under the curve from x = 1 to x = t is [tex]-\frac{5}{2} (\frac{1}{t^2} -1)[/tex].
For, t = 10, 100, and 1000, the areas are 2.475, 2.49975, and 2.4999975 respectively.
The total area is 2.5.
Given that:
[tex]y=\frac{5}{x^3}[/tex]
In order to find the area integrate it with limits from x = 1 to x = t.
[tex]A=\int\limits^t_1 {\frac{5}{x^3} } \, dx[/tex]
This can be written as:
[tex]A=\int\limits^t_1 {5x^{-3} } \, dx[/tex]
[tex]=5[\frac{x^{-2}}{-2} ]_1^t[/tex]
[tex]=-\frac{5}{2} (t^{-2}-1^{-2})[/tex]
So, the area is [tex]A=-\frac{5}{2} (\frac{1}{t^2} -1)[/tex].
When t = 10,
[tex]A=-\frac{5}{2} (\frac{1}{10^2} -1)[/tex]
[tex]=2.475[/tex]
When t = 100,
[tex]A=-\frac{5}{2} (\frac{1}{100^2} -1)[/tex]
[tex]=2.49975[/tex]
When t = 1000,
[tex]A=-\frac{5}{2} (\frac{1}{1000^2} -1)[/tex]
[tex]=-2.4999975[/tex]
To find the total area, the value of t = ∞.
Now, ∞⁻² is always 0, since any negative number to the power of infinity is 0.
So, the area is:
[tex]A=-\frac{5}{2} (0-1)[/tex]
[tex]A=2.5[/tex]
Hence, the total area is 2.5.
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tossing a number cube numbered from 1 to 6 and getting an odd number that is less than or equal to 3
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2/6=1/3
If two fair dice are rolled, find the probability that the sum of the dice is 77, given that the sum is greater than 33.
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1.
Find the Compound Amount.
Round to the nearest cent.
Amount = $980
Rate = 8%
Compounded = Quarterly
Time (Years) = 5
2.
Find the Interest Earned.
Round to the nearest cent.
Amount = $980
Rate = 8%
Compounded = Quarterly
Time (Years) = 5
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Principal Amount = P = $980
Interest rate = r = 8% = 0.08
Compounding periods = n = 4
Time = t = 5 years
Formula to be used for finding compounding amount:
[tex]A=P (1+ \frac{r}{n} )^{nt} [/tex]
Using the values in the formula, we get:
[tex]A=980 (1+ \frac{0.08}{4} )^{5*4} =1456.23[/tex]
Therefore, the amount compounded over a period of 5 years will be $1456.23
2)
Principal Amount = $980
Compounded Amount = $1456.23
Interest Earned = Compounded Amount - Principal Amount
Interest Earned = 1456.23 - 980 = $ 476.23
Therefore, $476.23 interest will be earned over a period of 5 years.
Trigonometric Help Plz?
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[tex]\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\\\ cos(\theta )=\sqrt{1-sin^2(\theta )}\\\\ -------------------------------\\\\ sin(x)=cos(x)-1\implies sin(x)=\sqrt{1-sin^2(x)}-1[/tex]
[tex]\bf sin(x)+1=\sqrt{1-sin^2(x)}\implies [sin(x)+1]^2=1-sin^2(x) \\\\\\ sin^2(x)+2sin(x)+1=1-sin^2(x)\implies 2sin^2(x)+2sin(x)=0 \\\\\\ 2sin(x)[sin(x)+1]=0\implies \begin{cases} 2sin(x)=0\\ sin(x)=0\\ \measuredangle x=0~,~\pi ~,~2\pi \\ -------\\ sin(x)+1=0\\ sin(x)=-1\\ \measuredangle x=\frac{3\pi }{2} \end{cases}[/tex]
2)
[tex]\bf 3sin(x)+cos^2(x)=2 \\\\\\ 3sin(x)+[1-sin^2(x)]=2 \\\\\\ 3sin(x)-sin^2(x)+1=2 \\\\\\ 3sin(x)-sin^2(x)-1=0 \\\\\\ sin^2(x)-3sin(x)+1=0 \\\\\\ \boxed{[sin(x)-3][sin(x)+1]=0}\impliedby \textit{check closely this }FOIL[/tex]
2/3 of the product of 3/8 and 16
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To solve this problem, we should first find the product of 3/8 and 16 and multiply the solution by 2/3.
Let's find the product first.
3/8 × 16 = 48/8
Simplify.
48/8 = 48 ÷ 8 = 6
Now, we find 2/3 of 6.
6 ÷ 3 × 2 = 2 × 2 = 4
So, your answer is 4.
Hope this helps!
Which of the following functions is graphed below?
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observing the graph of the problem, it is evident that the solution is option D, since the graph of the parabola presents a domain for x <4 and the line presents a domain for x> = 4 and the only option with these two conditions is option D
using a graph tool
I proceed to verify
see the attached figure
the answer is the option D
The graph consists of two parts: left part (with sign < or ≤) - parabola and right part (with sign > or ≥) - straight line.
Determine signs:
From the diagram you can see that the right endpoint (4,19) of parabola is not included. This means that x cannot be equal to 4 at this part of graph and the sign should be <.
Also you can see that the left endpoint (4,8) of line is included. This means that x=4 belongs to the right part and the sign should be ≥.
Using previous conclusions, you can state that correct choice is D.
Find all integer solutions to the pair of congruences (if any) x ≡ 17 (mod 23) 70x ≡ 3 (mod 93).
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[tex]70x\equiv3\pmod{93}\implies\begin{cases}70x\equiv3\equiv0\pmod3\\70x\equiv3\pmod{31}\end{cases}[/tex]
so in fact we're dealing with the system
[tex]\begin{cases}x\equiv17\pmod{23}\\70x\equiv0\pmod3\\70x\equiv3\pmod{31}\end{cases}[/tex]
Now, 3, 23, and 31 are relatively prime, so we can use the Chinese remainder theorem. But before we do that, we need to rework and ultimately eliminate the coefficients of [tex]x[/tex].
From the second equivalence, it follows immediately [tex]x[/tex] is some multiple of 3; this is because [tex]70x[/tex] is divisible by 3, but 3 doesn't divide 70, so it must divide [tex]x[/tex].
For the third equivalence, we can write [tex]70x=62x+8[/tex]. Then modulo 31, we have that [tex]62x\equiv0[/tex], which leaves us with [tex]8x\equiv3\pmod{31}[/tex]. We want a congruence of the form [tex]x\equiv\cdots[/tex], and to get that we can multiply [tex]8x[/tex] and 3 by the inverse of 8 modulo 31.
To find this inverse, we solve for [tex]y[/tex] in the relation
[tex]8y\equiv1\pmod{31}[/tex]
by using the Euclidean algorithm, or making just making the observation that [tex]8\times4\equiv32\equiv1\pmod{31}[/tex], so [tex]8^{-1}\equiv4\pmod{31}[/tex]. Distributing 4 across the third equivalence in our system gives [tex]x\equiv4\pmod{31}[/tex].
So to recap, we now have
[tex]\begin{cases}x\equiv17\pmod{23}\\x\equiv0\pmod3\\x\equiv12\pmod{31}\end{cases}[/tex]
and we're ready to use the CRT.
As a starting point, let's take
[tex]x=(17)+(23)+(23)=63[/tex]
It's clear that taken modulo 23, the latter two terms vanish and we have a remainder of 17, as desired. 63 is already a multiple of 3, but just to avoid doing more work later, let's multiply each term by 3 anyway to keep getting a remainder of 0:
[tex]x=(17\times3)+(23\times3)+(23\times3)=146[/tex]
Now multiply the first two terms by 31 to make sure they vanish when taken modulo 31. Meanwhile, [tex]23\times3\equiv69\equiv7\pmod{31}[/tex], but we want to get 12, so we would multiply this term by the inverse of 7 mod 31, and again by 12.
We can make a quick observation that [tex]7\times9=63=31\times2+1[/tex], so [tex]7^{-1}\equiv9\pmod{31}[/tex]. Alternatively, you can use the Euclidean algorithm to find this inverse. Either way, we get
[tex]x=(17\times3\times31)+(23\times3\times31)+(23\times3\times9\times12)=11,172[/tex]
So we're told that
[tex]x=11,172+(23\times3\times31)k=11,172+2139k[/tex]
is our solution set, where [tex]k\in\mathbb Z[/tex]. We can "simplify" this slightly by finding the least positive residue modulo the product of our moduli, which would be
[tex]11,172\equiv477\pmod{2139}[/tex]
so we end up with
[tex]x=477+2139k[/tex]
for integers [tex]k[/tex].
Estimate by division ..70/9.24
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hope this helped :)
alisa202
Here we have to divide 70 by 9.24.
we can first covert the decimal 9.24 into fraction, shifting the decimal two units to the right and dividing by 100, we have
9.24 = 924/100
Now let us divide 70 by 924/100
in division of fraction we take reciprocal of second fraction and multiply it with first.
reciprocal of 924/100 is 100/924.
multiplying 70* 100/924, we have
[tex] 70 * \frac{100}{924} [/tex]
[tex] = \frac{7000}{924} [/tex]
converting into decimal we have
[tex] \frac{7000}{924} = 7.5757..... [/tex]
0.698 to the bestest hundreth
Answers
Is the answer ok.
The 9 is in the hundredths place
Since 9 is greater than 5 we will round up.
0.70 is your answer