True / False
. Fixed length instruction sets are generally slower to execute than variable-length instruction sets.

Answers

Answer 1

Answer: False

Explanation:

Fixed length instructions are faster than variable length instruction because the fixed length instruction uses one clock cycle for their instruction whereas variable instruction takes more than one clock cycle. As RISC uses fixed length instruction and its CPI(cycles per instruction) is less compared to CISC which uses variable length instructions.

So fixed length instruction sets are faster than variable length instruction.


Related Questions

There is no reason to put comments in our code since we knew what we were doing when we wrote it. TRUE

Answers

Answer:

False: There are reasons to put comments in our code. We should have the habit of that.

Explanation:

sometimes when we start to debug our program due to some error in execution, we don't recognize properly which code we have written for what purpose.if we distribute the code to others as a team, others get the intention of our code more clearly due to comments.The code can be reused taking it's sections to form an other program, where the comments has a vital role.

public class Myfile { public static void main (String[] args) { String biz = args[1]; String baz = args[2]; String rip = args[3]; System.out.println("Arg is " + rip); } } Select how you would start the program to cause it to print: Arg is 2 A. java Myfile 222 B. java Myfile 1 2 2 3 4 C. java Myfile 1 3 2 2 D. java Myfile 0 1 2 3

Answers

Answer:

java MyFile 1 3 2 2

Explanation:

Option is is the correct answer, whatever we pass as commadD line arguments can be accessed using String array args by passing index

Array indexes starts with zero, in our case when we say

java MyFile 1 3 2 2

its going to be store like args[0] = 1, args[1] = 3, args[2] = 2, args[3] = 2

now we are saying  System.out.println("Arg is " + rip);

it means its going to print Args is with value of rip i.e. 2 (rip=args[3])

Write a program to display a message telling the educational level of a student based on their number of years of school. The user should enter a number indicating the number of years of school, and the program should then print the corresponding message given below. Be sure to use named constants rather than any numbers other than 0 in this program.

Answers

Answer:

#include <iostream>

using namespace std;

int main()

{

   int years;

   cout<<"enter the number of years of school: ";

   cin>>years;

   cout<<"The educational level is: "<<years<<endl;

}

Explanation:

First include the library iostream in c++ program for input/output.

then create the main function and declare the variable.

after that, display the message by using cout instruction for asking the user to enter the value.

then, cin instruction store the value in the declare variable.

finally, display the message with corresponding value.

Final answer:

The provided Python program prompts for a score between 0.0 and 1.0, validates the input, and then outputs the corresponding grade or an error message if the input is not a number or out of range.

Explanation:

Here is a Python program that prompts for a score between 0.0 and 1.0, checks whether the score is in the valid range, and then prints the corresponding grade based on the score provided:

# Define named constants for grade thresholds
GRADE_A = 0.9
GRADE_B = 0.8
GRADE_C = 0.7
GRADE_D = 0.6
try:
   score = float(input('Enter a score between 0.0 and 1.0: '))
   if score < 0.0 or score > 1.0:
       print('Error: Score is out of range.')
   elif score >= GRADE_A:
       print('A')
   elif score >= GRADE_B:
       print('B')
   elif score >= GRADE_C:
       print('C')
   elif score >= GRADE_D:
       print('D')
   else:
       print('F')
except ValueError:
   print('Error: Please enter a numeric input.')
The program uses try and except blocks to handle non-numeric inputs gracefully, outputting an error message in such cases. Depending on the score entered by the user, the appropriate grade is printed using comparison operations against the named constants defining grade thresholds.

What is the cause of thrashing?How does the systemdetect thrashing.Once it detects thrashing what can the system doto eliminate this problem

Answers

Answer:

Thrashing :- It is a situation when the system most of it's time is handling page faults, but the actual work done by CPU is very less.

Thrashing is caused by when a process is allocated too few number of frames, then there will be continuous page faults.The actual Utilization of CPU is very less.

Thrashing detection can be done by the system by determining the CPU Utilization as compared to degree of multi programming if it comes out to be less then there is thrashing.

Thrashing can be eliminated by decreasing the Degree of multi programming.

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