Answers
Related Questions
A horizontal line above the time axis of a speed vs. time graph means an object is ___.
a zero
b constant
c decreasing
Answers
A horizontal line on a speed vs. time graph signifies that the object is maintaining a constant velocity because there is no change in speed over time.
A horizontal line above the time axis of a speed vs. time graph indicates that an object is travelling at a constant velocity. This is because the speed does not change over time, and thus the graph shows a straight line parallel to the time axis, with no slope. When examining an acceleration vs. time graph, a horizontal line at zero would mean the acceleration is zero, which aligns with the object maintaining a constant speed, as acceleration is the rate of change of velocity.
"explain why the orbital radius and the speed of a satellite in circular orbit are not independent"
Answers
[tex]\frac{mv^2}{r}=G\frac{mM}{r^2} \\ v^2=G\frac{M}{r}\\ v=\sqrt{G\frac{M}{r}[/tex]
This relationship tells closer the closser your orbit is to the surface of the planet the faster you have to go. Which makes sense because the closer you are to the planet the stronger gravitational force gets.
A force of 230 N applied on a hydraulic lift raises an automobile weighing 6500 N. If the applied force is exerted on a 7.0 m^2 piston, what is the area of the piston beneath the automobile?
a.
2.0 x 10^2 m^2
b.
4.0 m^2
c.
0.25 m^2
d.
0.0050 m^2
Answers
Pressure = Force/Area
Let the area of the piston beneath the automobile be A. (230/7) = (6500/A) A = 197.826 m^2 or 2.0 x 10^2 m^2 if your rounded it off to the nearest hundreds.
Answer:
197.83 m^2
Explanation:
F = 6500 N, A = ?
f = 230 N, a = 7 m^2
Let the area of piston beneath the automobile is A.
By use of Pascal's law
F / A = f / a
6500 / A = 230 / 7 A = 197.83 m^2
A 2.8 kg block is dropped from rest from a height of 4.5 m above the top of the spring. when the block is momentarily at rest, the spring is compressed by 25.0 cm. what is the speed of the block when the compression of the spring is 15.0 cm?
Answers
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An experimenter finds that no photoelectrons are emitted from a particular metal unless the wavelength of light is less than 295 nm. her experiment will require photoelectrons of maximum kinetic energy 2.4 ev. what frequency light should be used to illuminate the metal?
Answers
The frequency of light is approximately [tex]\( 1.016 \times 10^{15} \)[/tex] Hz.
To determine the frequency of light that should be used to illuminate the metal in order to produce photoelectrons with a maximum kinetic energy of 2.4 eV, we can use the relationship between energy, frequency, and wavelength in the context of the photoelectric effect.
The energy of a photon (light particle) is given by Planck's equation:
[tex]\[ E = h \cdot f \][/tex]
Where:
- [tex]\( E \)[/tex] is the energy of the photon in joules (J)
-[tex]\( h \)[/tex] is Planck's constant, approximately [tex]\( 6.626 \times 10^{-34} \)[/tex] J·s
- [tex]\( f \)[/tex] is the frequency of the light in hertz (Hz)
We are given the maximum kinetic energy of the photoelectrons as 2.4 eV. To convert this to joules, we use the conversion factor [tex]\( 1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J} \)[/tex]
[tex]\[ E_{\text{max}} = 2.4 \, \text{eV} \times (1.602 \times 10^{-19} \, \text{J/eV}) \]\\\[ E_{\text{max}} = 3.845 \times 10^{-19} \, \text{J} \][/tex]
Now, since the photoelectrons are emitted only when the wavelength of light is less than 295 nm (nanometers), we can use the speed of light equation to relate frequency and wavelength:
[tex]\[ c = f \cdot \lambda \][/tex]
Where:
- [tex]\( c \)[/tex] is the speed of light, approximately [tex]\( 3.00 \times 10^8 \)[/tex] m/s
- [tex]\( f \)[/tex] is the frequency of the light in hertz (Hz)
- [tex]\( \lambda \)[/tex] is the wavelength of the light in meters (m)
First, we convert the wavelength limit of 295 nm to meters:
[tex]\[ \lambda_{\text{max}} = 295 \, \text{nm} \times (1 \, \text{m} / 10^9 \, \text{nm}) \][/tex]
[tex]\[ \lambda_{\text{max}} = 2.95 \times 10^{-7} \, \text{m} \][/tex]
Now, we can rearrange the speed of light equation to solve for frequency:
[tex]\[ f = \frac{c}{\lambda_{\text{max}}} \][/tex]
[tex]\[ f = \frac{3.00 \times 10^8 \, \text{m/s}}{2.95 \times 10^{-7} \, \text{m}} \][/tex]
[tex]\[ f = 1.016 \times 10^{15} Hz[/tex]
Therefore, the frequency of light that should be used to illuminate the metal and produce photoelectrons with a maximum kinetic energy of 2.4 eV is approximately [tex]\( 1.016 \times 10^{15} \)[/tex] Hz.
There is a 12 v potential difference between the positive and negative ends of the jumper cables, which are a short distance apart. an electron at the negative end ready to jump to the positive end has a certain amount of potential energy. on what quantities does this electrical potential energy depend? view available hint(s)
Answers
[tex]U=q \Delta V[/tex]
where q is the magnitude of the charge, while [tex]\Delta V[/tex] is the potential difference applied. So, U depends on [tex]\Delta V[/tex].
A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min. when switched off, it rotates through 48.0 revolutions before coming to rest. find the constant angular acceleration (in rad/s2) of the centrifuge.
Answers
Let's start with the initial angular speed, [tex]\omega _i = 3650 rev/min[/tex]. Keeping in mind that
[tex]1 rev = 2 \pi rad[/tex]
[tex]1 min=60 s[/tex]
we have
[tex]\omega _i = 3650 \frac{rev}{min} \cdot \frac{2 \pi rad/rev}{60 s/min} =382.0 rad/s [/tex]
And we should also convert the angle covered by the centrifuge:
[tex]\theta = 48.0 rev= 48.0 rev \cdot 2 \pi \frac{rad}{rev}=301.4 rad [/tex]
This is the angle covered by the centrifuge before it stops, so its final angular speed is [tex]\omega_f =0[/tex].
To solve the problem we can use the equivalent of
[tex]2aS = v_f^2 -v_i^2[/tex]
of an uniformly accelerated motion but for a rotational motion. It will be
[tex]2 \alpha \theta = \omega_f^2-\omega_i^2[/tex]
And by substituting the numbers, we can find the value of [tex]\alpha[/tex], the angular acceleration:
[tex]\alpha=- \frac{\omega_i^2}{2 \theta}=- \frac{(382 rad/s)^2}{2 \cdot 301.4 rad}=-242.1 rad/s^2 [/tex]
A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min, the constant angular acceleration of the centrifuge is approximately -1522.71 rad/s².
We can apply the following formula to determine the centrifuge's constant angular acceleration:
Δθ = ω₀t + (1/2)αt²
Δθ = ω₀t + (1/2)αt²
Since the final angular speed is 0, the formula becomes:
Δθ = ω₀t
48 rev * (2π rad/rev) = 381.92 rad/s * t
Simplifying:
96π rad = 381.92 rad/s * t
Dividing both sides by 381.92 rad/s:
t ≈ 0.251 s
Now, we can calculate the angular acceleration (α) using the rearranged formula:
α = (0 - ω₀) / t
α = (0 - 381.92 rad/s) / 0.251 s
α = -1522.71 rad/s²
Thus, the constant angular acceleration of the centrifuge is approximately -1522.71 rad/s².
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a body of mass 5kg falls from height of 10m above the ground what kinetic energy of the body before it strike the ground
Answers
GPE = mgh
GPE = 5kg x 9.8m/s^2 x 10m
GPE = 490 J
Kinetic Energy = 490 J
(This is assuming that gravitation field strength (g) is 9.8m/s^2, sometimes you may round this to 10m/s^2, therefore making the final result:
Kinetic energy = 500 J)
A 8.0 n force acts on a 0.70-kg object for 0.50 seconds. by how much does the object's momentum change (in kg-m/s)? (never include units in the answer to a numerical question.)
Answers
[tex]F=ma[/tex]
Rewriting the acceleration as the increment of velocity [tex]\Delta v[/tex] in a time [tex]\Delta t[/tex]: [tex]a= \frac{\Delta v}{\Delta t} [/tex], F becomes
[tex]F=m \frac{\Delta v}{\Delta t} [/tex]
But given the definition of momentum: [tex]p=mv[/tex], then [tex]m \Delta v[/tex] represents the momentum change. So we can rewrite F as
[tex]F= \frac{\Delta p}{\Delta t} [/tex]
And re-arranging the formula we can calculate the value of the change in momentum:
[tex]\Delta p = F \Delta t=(8.0 N)(0.50 s)=4 kg m/s[/tex]
Given the force acting on the object, the change in its momentum is 4kg.m/s.
Force; [tex]F = 8.0N = 8 kg.m/s^2[/tex]Mass; [tex]m = 0.7kg[/tex]Time, [tex]t = 0.50s[/tex]To determine the object's change in momentum, we use the Impulse Momentum Theorem:
The impulse applied to a body or matter is equal to the change in its momentum
Impulse = Change in Momentum
[tex]Impulse = F * dt[/tex]
Where F is the force applied and [tex]dt[/tex] is the elapsed time
Hence
[tex]Change \ in \ Momentum = F * dt[/tex]
We substitute our given values into the equation
[tex]Change \ in \ Momentum = 8 kg.m/s^2 * 0.50s\\\\Change \ in \ Momentum =4kg.m/s[/tex]
Therefore, given the force acting on the object, the change in its momentum is 4kg.m/s.
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A 42-cm-long solenoid, 1.8 cm in diameter, is to produce a 0.030-t magnetic field at its center. part a if the maximum current is 4.3 a , how many turns must the solenoid have?
Answers
[tex]B=\mu_0 \frac{N}{L} I[/tex]
where
[tex]\mu_0 = 1.26 \cdot 10^{-6} Tm/A[/tex] is the magnetic permittivity in vacuum
[tex]N[/tex] is the number of turns
[tex]L=42 cm=0.42 m[/tex] is the length of the solenoid
[tex]I=4.3 A[/tex] is the current.
Re-arranging the formula and using [tex]B=0.030 T[/tex], we find the number of turns N:
[tex]N= \frac{BL}{\mu_0 I}=2326 [/tex]
The solenoid must have about 2332 turns
[tex]\texttt{ }[/tex]
Further explanationLet's recall magnetic field strength from current carrying wire and from center of the solenoid as follows:
[tex]\boxed {B = \mu_o \frac{I}{2 \pi d} } [/tex]
B = magnetic field strength from current carrying wire (T)
μo = permeability of free space = 4π × 10⁻⁷ (Tm/A)
I = current (A)
d = distance (m)
[tex]\texttt{ }[/tex]
[tex]\boxed {B = \mu_o \frac{I N}{L} } [/tex]
B = magnetic field strength at the center of the solenoid (T)
μo = permeability of free space = 4π × 10⁻⁷ (Tm/A)
I = current (A)
N = number of turns
L = length of solenoid (m)
Let's tackle the problem now !
[tex]\texttt{ }[/tex]
Given:
Current = I = 4.3 A
Length = L = 42 cm = 0.42 m
Magnetic field strength = B = 0.030 T
Permeability of free space = μo = 4π × 10⁻⁷ T.m/A
Asked:
Number of turns = N = ?
Solution:
[tex]B = \mu_o \frac{I N}{L}}[/tex]
[tex]\frac{I N}{L} = B \div \mu_o[/tex]
[tex]IN = BL \div \mu_o[/tex]
[tex]N = BL \div (\mu_o I)[/tex]
[tex]N = ( 0.030 \times 0.42 ) \div ( 4 \pi \times 10^{-7} \times 4.3 )[/tex]
[tex]\boxed {N \approx 2332}[/tex]
[tex]\texttt{ }[/tex]
Learn moreTemporary and Permanent Magnet : https://brainly.com/question/9966993The three resistors : https://brainly.com/question/9503202A series circuit : https://brainly.com/question/1518810Compare and contrast a series and parallel circuit : https://brainly.com/question/539204[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Magnetic Field
What is the correct displacement for the following vectors: 4km south, 2 km north, 5 km south, and 5 km north ?
Answers
you get 2 km south .
Answer:
2 km south
Explanation:
In order to calculate this you just have to have in mind that your starting point will be 0, and as south and north are contrary, one of the will benegative, in this case we will take south as negative, so lets begin:
-4 km south
+2 km north
-5 km south
+5 km north
This equals -2 km, since it is negative we know that it´s south, so the displacement after all will be 2 kilometers south from the starting point.
An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 200 n. (a) what is the equivalent spring constant of the bow
Answers
[tex]F=kx[/tex]
Where
F = force
k = spring constant
x = displacement from initial position
We have information:
F=200N
x=0.4m
k=?
400=k*0.4
k=1000N/m
Which labels correctly identify the layers most closely associated with gamma rays and visible light? Z: Gamma rays X: Visible light X: Gamma rays Z: Visible light Z: Gamma rays Y: Visible light Y: Gamma rays Z: Visible light
Answers
Answer:
A on edge
Explanation:
Which electrical device makes it possible to transmit electrical energy efficiently from a power plant to users?
Answers
A Transformer. It current carrying wire.
Transformers, specifically step-up transformers, are crucial for efficiently transmitting electrical energy from power plants to users by increasing the voltage, resulting in reduced current and minimization of Joule losses. High voltage transmission leads to greater efficiency and lower energy losses, making the process both economical and environmentally friendly.
The electrical device that makes it possible to transmit electrical energy efficiently from a power plant to users is the transformer. Transformers play a critical role in adjusting the voltage levels during the transmission of electric power over long distances. When power is generated, a step-up transformer increases the voltage from the power plant, which results in a proportional decrease in current and thus minimizes resistive power losses known as Joule losses. These minimized losses are crucial for maintaining efficiency since identical currents flow through both the load and transmission lines, where power is dissipated usefully in the load but wasted in the resistance of the transmission lines.
The period of a wave is found to be 50 seconds. What is the frequency of the wave? 50 Hz 0.8 Hz 0.02 Hz not enough information given
Answers
Hope this helped!
The period of a wave is found to be 50 seconds. What is the frequency of the wave?
0.02 Hz
Read this passage from Beowulf, in which Wiglaf, one of Beowulf's men, speaks to his companions as Beowulf battles the dragon. Wiglaf then joins Beowulf and addresses him. “I remember the time when, tasting the mead-cup, We promised in the hall the lord of us all Who gave us these ring-treasures, that this battle-equipment, Swords and helmets, we’d certainly quite him, Should need of such aid ever befall him: How we have forfeited our liegelord’s confidence! In the war-band he chose us for this journey spontaneously, Stirred us to glory and gave me these jewels, Since he held and esteemed us trust-worthy spearmen, Hardy helm-bearers, though this hero-achievement Our lord intended alone to accomplish, Ward of his people, for most of achievements, Doings audacious, he did among earth-folk. Our lord is in sore need of us. The day is now come when the ruler of earthmen Needeth the vigor of valiant heroes: Let us wend us towards him, the war-prince to succor, While the heat yet rageth, horrible fire-fight.” ... Through the bale-smoke he stalked then, Went under helmet to the help of his chieftain, Briefly discoursing: “Beowulf dear, Perform thou all fully, as thou formerly saidst, In thy youthful years, that while yet thou livedst Thou wouldst let thine honor not ever be lessened. Thy life thou shalt save, mighty in actions, Atheling undaunted, with all of thy vigor; The monster advances on them. I’ll give thee assistance.” Complete the following sentences based on your reading of the passage. In his speech to his companions, Wiglaf . Throughout this passage, Wiglaf is presented as .
Answers
1. encouraging them to act and unite
2. valiant and courageous
Answer:
1. 3) urges them to remember their duty and 2. 1) a model of loyalty are the correct answers.
Explanation:
In the first question, Wiglaf tries to convince his mates not to give up and to help his lord and also remembering what their intention was. Beowulf is supposed to receive help because he is old and he cannot deal with the monster by himself anymore, so Wiglaf is there because of that.
In the second one, it is seen that Wiglaf is the only one who doesn't give up on Beowulf, even when Beowulf is about to die after the fight with the dragon and Wiglaf kills it as a maximum expression of his loyalty.
What are the three longest wavelengths for standing waves on a 280-cm-long string that is fixed at both ends? enter your answers numerically separated by commas?
Answers
[tex]\lambda_n=\frac{2L}{n}; n=1,2,3,4,5,...[/tex]
Where L is the length of a string and n is the number of nodes of the standing wave.
From this formula, we see that the more nodes you have the lower your wavelength is.
We need to calculate wavelengths for n=1, n=2, and n=3.
[tex]\lambda_1=\frac{2L}{1}=560$cm\\ \lambda_2=\frac{2L}{2}=280$cm\\ \lambda_3=\frac{2L}{3}=186.67$cm\\[/tex]
Loni makes a diagram to help organize what she has learned about the gas laws.
Which label belongs in the region marked X?
involves changes in temperature
has a constant volume
shows an inversely proportional relationship
does not describe pressure changes
Answers
This question is based on Boyle's law and Charles' law.
As per Boyle's law the volume of a given mass of a gas is inversely proportional to the applied pressure at constant temperature. Mathematically it can be written as
[tex]P\ \alpha \frac{1}{V}[/tex] [at constant T and n]
Charles'law: It states that at constant pressure the volume of a given mass of a gas increases or decreases by 1/273 th of its volume at zero degree celsius for every 1 degree centigrade rise or fall of temperature.One may say that volume is directly proportional to temperature. Mathematically it can be written as
V∝T [at constant P and n]
Here P,V,T and n stand for pressure,volume,temperature and number of moles respectively.
In the diagram given in the question the point X is present in the region where Boyle's law is obeyed.Hence the correct option will be the third one which depicts the presence inverse relationship which is true for pressure and volume at constant temperature.
A 0.32 μc particle moves with a speed of 18 m/s through a region where the magnetic field has a strength of 0.95 t . you may want to review (pages 773 - 777) . part a at what angle to the field is the particle moving if the force exerted on it is 4.8×10−6n? express your answer using two significant figures. θ = ∘ request answer part b at what angle to the field is the particle moving if the force exerted on it is 3.0×10−6n? express your answer using two significant figures.
Answers
The force on a particle in a magnetic field can be determined using F = qvBsin(\theta). By rearranging the equation to solve for \theta, we can find the angle the particle's velocity makes with the magnetic field for any given force, charge, velocity, and field strength.
Explanation:The situation described is a classic example of Lorenz force experienced by a charged particle moving through a magnetic field. The force exerted on a charged particle when it moves through a magnetic field can be calculated with the following equation:
F = qvBsin(\theta)
where:
F is the magnetic force,q is the charge of the particle,v is the velocity of the particle,B is the magnetic field strength, and\theta is the angle between the velocity vector and the magnetic field.To find the angle \(\theta\), we can rearrange the equation:
\theta = arcsin(\frac{F}{q v B})
For part A:
Using the information given, where F = 4.8 \times 10^{-6} N, q = 0.32 \times 10^{-6} C, v = 18 m/s, and B = 0.95 T, we can calculate the angle.
\(\theta = arcsin(\frac{4.8 \times 10^{-6}}{0.32 \times 10^{-6} \times 18 \times 0.95}) = arcsin(\frac{4.8}{0.32 \times 18 \times 0.95})\)
This returns an angle \(\theta\), which will be in degrees once evaluated using a calculator.
For part B, you would apply the same approach but with F = 3.0 \times 10^{-6} N, to find the different angle.
Scientists want to place a 3700 kg satellite in orbit around mars. they plan to have the satellite orbit a distance equal to 1.9 times the radius of mars above the surface of the planet. here is some information that will help solve this problem: mmars = 6.4191 x 1023 kg rmars = 3.397 x 106 m g = 6.67428 x 10-11 n-m2/kg2 1) what is the force of attraction between mars and the satellite?
Answers
[tex]F=G \frac{Mm}{d^2} [/tex]
where G is the gravitational constant, M the mass of Mars, m the mass of the satellite, and d the distance of the satellite from the center of Mars.
First we have to calculate d. Calling r the radius of Mars, we know that the satellite is located at 1.9r above the surface. This means that its distance from the center of Mars is [tex]d=1.9r +r=2.9 r[/tex].
Using this information, and the data given by the problem, we can now calculate the intensity of the gravitational attraction:
[tex]F=G \frac{Mm}{(2.9r)^2}=(6.67 \cdot 10^{-11}Nm^{-2}kg^{-2}) \frac{(6.42\cdot 10^{23}kg)(3700kg)}{(2.9\cdot3.39 \cdot 10^6m)^2}=1639 N [/tex]
Answer:
3805.59 N
Explanation:
Parameters given:
Mass of satellite, m = 3700 kg
Mass of Mars, M = [tex]6.4191 * 10^{23} kg[/tex]
Radius of Mars, r = [tex]3.397 * 10^6[/tex] m
Distance between the satellite and the surface of Mars, D = 1.9 times r
D = [tex]1.9 * 3.397 * 10^6[/tex] = [tex]6.454 * 10^6 m[/tex]
The gravitational force of attraction is given as:
[tex]F = \frac{GMm}{D^2}[/tex]
where G = gravitational constant = [tex]6.67428 * 10^{-11}Nm^2/kg^2[/tex]
[tex]F = \frac{6.67428 * 10^{-11} * 6.4191 * 10^{23} *3700}{(6.454 * 10^6)^2}[/tex]
[tex]F = 3805.59 N[/tex]
The gravitational force of attraction is 3805.59 N
The Doppler effect is a shift in the _______________ of an oscillation caused by the motion of the source of the oscillation, and occurs at speeds below the speed of sound. a) amplitude b) frequency c) speed
Answers
on the concepts. Both the question and the list of answers
are misleading. If you're serious about learning this subject,
you're better off ignoring this question, or at least not working
too hard on it.
... The Doppler shift is an APPARENT shift in the wavelength and
frequency of the waves that come from a source of oscillations.
... The shift is measured by the observer. He sees and hears
different frequency and wavelength, compared to what's actually
coming out of the source.
... The shift can be the result of EITHER the source OR the observer.
Any time the distance between them is changing, the shift occurs.
It doesn't matter which one is moving.
The peak intensity of radiation from Mars is about 14,000 nm. What is the average surface temperature of Mars rounded to the nearest whole number?
Answers
blablabla
207 K
406 K
4,857 K
Mars does not emit radiation.
Then the answer is 207 K.
Answer:
T = 206 K
Explanation:
As we know by Wein's law of displacement that if we draw all radiations intensity with all possible wavelengths radiated from the object then the wavelength corresponding to maximum intensity of radiation is inversely dependent to the absolute temperature of the object.
So here we can say
[tex]\lambda = \frac{b}{T}[/tex]
here we know
b = Wein's constant
[tex]b = 2.89 \times 10^{-3}[/tex]
now we have
[tex]\lambda = 14000 nm[/tex]
from above equation
[tex]14000 \times 10^{-9} = \frac{2.89 \times 10^{-3}}{T}[/tex]
[tex]T = 206 K[/tex]
What is the electric potential of a 4.5 × 10-5 C charge that has an electric potential energy of 0.027 J?
Answers
Answer : Electric potential is 600 V
Explanation :
It is given that,
Electric charge, [tex]q=4.5\times 10^{-5}\ C[/tex]
Electric potential energy, [tex]U=0.027\ J[/tex]
The relation between the electric potential and the electric potential energy is given by :
[tex]U=qV[/tex]
[tex]V=\dfrac{U}{q}[/tex]
[tex]V=\dfrac{0.027\ J}{4.5\times 10^{-5}\ C}[/tex]
[tex]V=600\ V[/tex]
Hence, the electric potential is 600 V.
You drive a 6,000 kg boat due north, while the wind exerts a force of 600 N due south and the water exerts a resistive force of 1,200 N due south. The generated force by the boat’s engines is 4,200 N. Find the magnitude and direction of the boat’s acceleration.
Answers
[tex] F_{net} =(mass)(acceleration)[/tex]
Since what we are looking for is acceleration, we need to tweak our formula to derive our formula for acceleration.
[tex]acceleration = F_{net}/mass [/tex]
Our only problem is we do not have the value of the net force yet, but we can do so with the given presented.
Let's first wake into account all the forces acting upon the object.
F1 = 600N South
F2 = 1,200 N South
F3 - 4,200 N North
Net Force is the sum of all forces acting on an object. But you need to take into account that the forces are not all going towards the same direction. In this case, there are forces that are going against each other.
Thinking about the Cartesian plane, if you count going downwards the values are negative and if you count going up, the numbers are positive. We can apply this to our scenario here.
South is negative and north is positive. Our Forces then will now be considered this way:
F1 = -600N South
F2 = -1,200N South
F3 = 4,200N North
Now we can come up with our net force.
[tex] F_{net} = (-600N) + (-1,200N) + 4,200N[/tex]
[tex] F_{net} = (-1,800N) + 4,200N[/tex]
[tex] F_{net} = 2,400N[/tex]
Our net force is equal to 2,400N. It is positive so the direction is North.
Since we have our net force, we can now solve for acceleration.
[tex]acceleration = F_{net}/mass [/tex]
[tex]acceleration = 2,400N/6,000kg [/tex]
[tex]acceleration = 0.40m/s^{2} [/tex]
So the boat is moving at [tex]0.40 m/ s^{2} [/tex] to the North.
The type of interference that increases the energy of the resulting wave is called interference. The type of interference that results in a loss of energy is called interference.
Answers
The type of interference that increases the energy of the resulting wave is called constructive interference. The type of interference that results in a loss of energy is called destructive interference.
When two or more waves are in the same medium, they can cross at a given point, where interference happens. When the two waves are in phase, the resulting amplitude in the point of interference is maxed. This is called constructive interference.
When the two waves are in opposing phases, the resulting amplitude in the point of interference is minimized. This is called destructive interference.
Have a nice day!
Answer:
constructive + destructive.
Explanation:
edge 22.
Argon is compressed in a polytropic process with n 5 1.2 from 120 kpa and 108c to 800 kpa in a piston–cylinder device. determine the work produced and heat transferred during this compression process, in kj/kg.
Answers
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A car with a mass of 525kg is being pushed west (left) by a force of 375n from its engine. the coefficient of friction felt by the car is .0420.
a.calculate the force weight of the car.
b.calculate the force friction acting on the car.
c.what is the net force acting on this car?
d.calculate the acceleration of the car.
Answers
Explanation:
It is given that,
Mass of the car, m = 525 kg
Applied force, F = 375 N
The coefficient of friction felt by the car is 0.42, [tex]\mu=0.42[/tex]
(a) The weight of the car is given by :
[tex]W=mg[/tex]
[tex]W=525\times 9.8[/tex]
W = 5145 N
(b) The force of friction acts in the opposite direction of motion. It can be calculated as :
[tex]f=\mu mg[/tex]
[tex]f=0.42\times 5145[/tex]
f = 2160.9 N
(c) Here, the force of friction is greater than the applied force. As a result, the ball will not moves. So, the net force acting on this car is 0.
(d) As the net force acting on the car is 0. There will be no acceleration in the car.
Final answer:
a. The force weight of the car is 5145 N. b. The force friction acting on the car is 216.09 N. c. The net force acting on the car is 158.91 N. d. The acceleration of the car is 0.714 m/s².
Explanation:
a. To calculate the force weight of the car, we can use the formula:
Force weight = mass * acceleration due to gravity
Given that the mass of the car (m) is 525 kg and the acceleration due to gravity (g) is 9.8 m/s², we can substitute these values into the formula:
Force weight = 525 kg * 9.8 m/s² = 5145 N
So, the force weight of the car is 5145 N.
b. To calculate the force friction acting on the car, we can use the formula:
Force friction = coefficient of friction * force weight
Given that the coefficient of friction (µ) is 0.0420 and the force weight is 5145 N, we can substitute these values intothe formula:
Force friction = 0.0420 * 5145 N = 216.09 N
So, the force friction acting on the car is 216.09 N.
c. The net force acting on the car can be calculated by subtracting the force friction from the force applied by the engine:
Net force = force applied - force friction
Given that the force applied by the engine is 375 N and the force friction is 216.09 N, we can substitute these values into the formula:
Net force = 375 N - 216.09 N = 158.91 N
So, the net force acting on the car is 158.91 N.
d. To calculate the acceleration of the car, we can use Newton's second law of motion:
Force = mass * acceleration
Given that the force applied by the engine is 375 N and the mass of the car is 525 kg, we can substitute these values into the formula:
375 N = 525 kg * acceleration
Solving for acceleration:
acceleration = 375 N / 525 kg = 0.714 m/s²
So, the acceleration of the car is 0.714 m/s².
what nuclear physics means?
Answers
After harvesting their main crops, such as corn and wheat, many farmers plant a second crop called a cover crop. This cover crop grows during the fall and winter and is then plowed over in the spring. What is the main purpose of a cover crop?
A.
to get rid of excess seed rather than storing during the winter
B.
to provide food and shelter for birds and animals during the winter
C.
to prevent water runoff into other parts of the farmers' field
D.
to prevent erosion of the topsoil by wind and water
Answers
Answer:
Option (D)
Explanation:
A cover crop is usually defined as a special type of crop that is cultivated in order to increase the productivity of the soil, rather than focusing on the productivity of the crop. These are very commonly used and it helps in the decreasing amount of weeds, controlling pests and diseases, increasing the fertility of the soil, reduction of soil erosion. It also enhances the biodiversity.
Thus, the main purpose of the cover crop is to prevent the erosion of the topsoil by the agents such as water and wind.
Hence, the correct answer is option (D).
A 1500-kg car traveling at 90 km/h toward the east suddenly collides with a 3000-kg car traveling at 60 km/h toward the south. the two cars stick together after the collision. what is the direction of motion of the cars after collision?
Answers
The direction of motion of the cars after collision will be south of east. This is determined by the conservation of momentum, with the direction being the sum of the momenta of the two cars, taking into account their initial velocity and mass.
Explanation:This question involves the conservation of momentum, a key concept in physics. Since the two cars stick together after the collision, the direction of their motion is the sum of their momenta, taking into account their mass and initial velocity.
First, convert the speeds from km/h to m/s. The 1500-kg car was travelling at 25 m/s towards the east (90 km/h) and the 3000-kg car was travelling at 16.67 m/s towards the south (60 km/h).
Calculating the Resulting VelocityMomentum (p) is mass (m) times velocity (v), so the momentum of the first car is 1500 kg * 25 m/s = 37500 kg*m/s and the second car's momentum is 3000 kg * 16.67 m/s = 50000 kg*m/s. Since they stick together after the collision, the total momentum must remain the same. However, the momentum now has two components, one towards the east and the other towards the south. The magnitude of the resultant velocity is found using Pythagoras' theorem, sqrt[(37500 kg*m/s)^2 + (50000 kg*m/s)^2], and the direction is given by the arctangent of the ratio of the two components. Therefore, the direction of the cars will be south of east.
Learn more about Conservation of momentum here:https://brainly.com/question/33316833
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The two cars will move together after the collision with a velocity of approximately 13.89 m/s at an angle of 53.12° south of east. This result is derived by applying the principle of conservation of momentum. We found the momentum components in the eastward and southward directions and used them to determine the direction and magnitude of the combined velocity.
This is a classic example of an inelastic collision where two objects stick together after collision. We use the conservation of momentum to find the direction of motion after the collision.
First, let's convert velocities to meters per second (m/s):
1500-kg car: 90 km/h = 25 m/s
3000-kg car: 60 km/h = 16.67 m/s
Next, we calculate the momentum of each car:
Eastward momentum of the 1500-kg car:
1500 kg * 25 m/s = 37500 kg·m/s
Southward momentum of the 3000-kg car:
3000 kg * 16.67 m/s = 50010 kg·m/s
Since the cars stick together after the collision, their combined mass is 1500 kg + 3000 kg = 4500 kg.
To find the velocity components of the combined mass after the collision:
Eastward velocity component:
(37500 kg·m/s) / 4500 kg = 8.33 m/s
Southward velocity component:
(50010 kg·m/s) / 4500 kg = 11.11 m/s
We combine these components to find the magnitude and direction of the final velocity:
Magnitude = √((8.33 m/s)² + (11.11 m/s)²)
or, Magnitude = √(69.39 + 123.4)
Magnitude ≈ 13.89 m/s
Direction: arctan(11.11 / 8.33)
Direction ≈ 53.12° south of east
So, the cars will move at a velocity of approximately 13.89 m/s in a direction that is 53.12 degrees south of east after the collision.