Answers
The oxygen of the epoxide adds syn to the alkene, which means the oxygen is on one face of the molecule. Therefore, the epoxide has 2 chiral centers. The dimethyl amine is a nucleophile and it attack a carbon bound to oxygen in an sn2 fashion. This causes the epoxide ring to open, and after a proton transfer, the molecule now has a dimethyl amino group and an adjacent hydroxy group in an anti-relationship. The amine is able to attack either of the two carbons bound to the oxygen in the epoxide and this leads to two isomers. The isomers formed are a pair of enantiomers with the stereochemistry (R,R) and (S,S). Therefore, the second isomer that the question asks for is the (S,S) product shown.
Related Questions
Magnesium hydroxide (Mg(OH)2): g/mol
Answers
To determine the molar mass, you need to get the atomic mass of the molecule. To do this, check the periodic table for the atomic mass or average atomic weight of each element.
Mg = 24.305 x 1 = 24.305 amu
O = 15.9994 x 2 =31.9988 amu
H = 1.0079 x 2 = 2.0158 amu
Then, add all the components to get the atomic mass of the molecule.
24.305 amu + 31.9988 amu + 2.0158 amu = 58.3196 amu
The atomic mass is just equivalent to its molar mass.
So, the molar mass of Magnesium hydroxide (Mg(OH)2) is 58.3196 g/mol.
molar mass of Mg(OH)2 = 58.305 grams/mole
Explanation:
From the periodic table:
atomic mass of Mg = 24.305 grams
atomic mass of oxygen = 16 grams
atomic mass of hydrogen = 1 gram
Now the given compound has:
1 mole of Mg, 2 moles of oxygen and 2 moles of hydrogen
Therefore:
molar mass of Mg(OH)2 = 24.305 + 2(16) + 2(1) = 58.305 grams/mole
what is the number of electrons shared between the atoms in I2 molecule (That is an i not a 1)
1) 7
2) 2
3) 8
4) 4
Answers
Iodine has seven valence electrons. Using valence shell electron pair repulsion (VSEPR) theory, we can predict the Lewis dot structure for [tex]I_2[/tex]. We see there are fourteen electrons, and we can make a covalent bond, leaving three lone pairs on each atom. The bond replaces two electrons, so the number of electrons shared is two.
I2, or iodine, is a diatomic molecule held together by a single covalent bond. In this bond, two electrons are shared. Therefore, the answer is 2.
Explanation:The molecule of I2, or iodine, is a diatomic molecule; that is, a molecule consisting of two iodine atoms. This molecule is held together by a single covalent bond. Covalent bonds are formed when atoms share electrons. In a single covalent bond, two electrons are shared - one from each atom involved. Therefore, in an I2 molecule, the number of electrons shared between the atoms is 2.
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The anticaking agent added to table salt is calcium metasilicate (casio3). this compound can absorb up to 2.5 times its mass in water and still remain a free-flowing powder. calculate the percent composition of casio3.
Answers
Ca = 40.1 g/mol
Si = 28.1 g/mol
O = 16.0 g/mol
The total molecular weight is as follows:
[(40.1 g/mol) x 1 mol Ca] + [28.1 g/mol x 1 mol Si] + [(16 g/mol) x 3 mol O] = 116.2 g/mol
Now that we have the total mass of CaSiO₃, we can calculate the percent composition in 1 mol of CaSiO₃:
% Ca = [(40.1 g/mol x 1 mol Ca)/116.2 g] x 100% = 34.5% Ca
% Si = [(28.1 g/mol x 1 mol Si)/116.2 g] x 100% = 24.2% Si
% O = [(16 g/mol x 3 mol O)/116.2 g] x 100% = 41.3% O
The percent composition of CaSiO₃ is found to be 34.5% Ca, 24.2% Si and 41.3% O.
The percent composition of calcium metasilicate (CaSiO₃) is approximately 34.49% calcium, 24.17% silicon, and 41.33% oxygen.
To calculate the percent composition of a compound, you need to determine the molar mass of each element in the compound and then divide by the total molar mass of the compound. Here’s the step-by-step breakdown:
Calculate the molar masses:
Calcium (Ca): 40.08 g/molSilicon (Si): 28.09 g/molOxygen (O): 16.00 g/mol per atom. Since there are three oxygen atoms, the total is 3 x 16.00 = 48.00 g/mol.Determine the molar mass of CaSiO₃:
The total molar mass of CaSiO₃ is 40.08 + 28.09 + 48.00 = 116.17 g/mol.
Calculate the percent composition:
Percent composition of Ca: (40.08 / 116.17) x 100 ≈ 34.49%Percent composition of Si: (28.09 / 116.17) x 100 ≈ 24.17%Percent composition of O: (48.00 / 116.17) x 100 ≈ 41.33%So, the percent composition of CaSiO₃ is approximately 34.49% calcium, 24.17% silicon, and 41.33% oxygen.
20 points
Choose all the answers that apply. Which of the following is an example of an ion?
Na+
Cl-
Ar
F+
Answers
na+ cl- and f+ is the answer
Calculate the theoretical yield of ammonia produced by the reaction of 100g of H2 gas and 200g of N2 gas
Answers
first, we should have the balanced equation of the reaction:
3H2(g) + N2(g) → 2NH3(g)
Second, we start to convert mass to moles
moles of N2 = N2 mass / N2 molar mass
= 200 / 28 = 7.14 moles
third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,
moles of NH3 = 7.14 * 2 = 14.28 moles
finally, we convert the moles of NH3 to mass again to get the mass of ammonia:
mass of NH3 = no.moles * molar mass of ammonia
= 14.28 * 17 = 242.76 g
Starting with acetylene and bromoethane, show how you would use reagents from the table to synthesize 4-methyl-3-hexanone. (enter your choices as a string of letters without punctuation, i.e. ace.)
Answers
With the 3-hexyne in hand, the triple bond is reduced using Lindlar's catalyst which will hydrogenate only to the alkene and stop. The 3-hexene is then reacted with a peroxycarboxylic acid which is used to epoxidize the alkene, to give the epoxide.
The epoxide is reacted with the grignard reagent which treats the methyl as a strong nucleophile. The methyl adds to one carbon of the epoxide and opens the ring. The acid is added at the end to protonate the alcohol.
Finally, the alcohol is oxidized with chromic acid which will oxidize a secondary alcohol to the ketone. The final product is 4-methyl-3-hexanone.
If the concentration of cucl2 drops from 1.000 m to 0.655 m in the first 30.0 s of the reaction, what is the average rate of reaction over this time interval?
Answers
The average rate of reaction is calculated by dividing the change in concentration of a reactant or product by the time interval. For CuCl₂ decreasing from 1.000 M to 0.655 M in 30.0 s, the average rate of reaction is 0.0115 M/s.
The average rate of reaction over a given time interval can be determined by calculating the change in concentration of a reactant or product and dividing by the time interval over which the change occurred. In the scenario provided, the concentration of CuCl₂ decreases from 1.000 M to 0.655 M over a period of 30.0 seconds. To calculate the average rate of reaction, we follow these steps:
Identify the initial concentration and final concentration of CuCl₂. In this case, [tex]C_{i}[/tex]= 1.000 M and [tex]C_{f}[/tex] = 0.655 M.Calculate the change in concentration (ΔC) using the formula ΔC = [tex]C_{f}[/tex]- [tex]C_{i}[/tex]. Therefore, ΔC = 0.655 M - 1.000 M = -0.345 M. The negative sign indicates a decrease in concentration.Determine the time interval (t) over which the change in concentration has occurred, which is given as 30.0 s.Calculate the average rate of reaction (Rate) using the formula Rate = ΔC / t. The correct answer is thus Rate = -0.345 M / 30.0 s = -0.0115 M/s.The negative sign in rate typically indicates the consumption of a reactant. However, when discussing rates of reaction, it is common to report them as positive values, so the average rate of reaction from this calculation would be 0.0115 M/s.
the variable that a scientist changes when conducting an experiment is called the _____variable.
a. dependent
b.responding
c.manipulated
Answers
Answer: The correct answer is option (a).
Explanation:
Dependent variables are the variables whose value depend on another variable. Its value changes as the independent variable changes.
Independent variables are the variables which do not depend on any other variable beside . Its value does not change with a change in other dependent variables.
While conducting experiment scientist changes dependent variable in order to record observations.
Nacl(aq)+hg2(c2h3o2)2(aq)→ express your answer as a chemical equation. enter noreaction if no reaction occurs. identify all of the phases in your answer. nac2h3o2(aq)+hg2cl2(s)nac2h3o2(aq)+hg2cl2(s)
Answers
The chemical reaction of NaCl with H₂O, leading to the formation of NaOH, H₂, and Cl₂, can be expressed as a balanced molecular equation, a complete ionic equation, and a simplified net ionic equation, where Na⁻ and Cl⁻ act as spectator ions.
The initial equation provided, NaCl(aq) + H₂O(1) → NaOH(aq) + H₂(g) + Cl₂ (g), is an example of a chemical reaction involving the decomposition of sodium chloride (NaCl) in the presence of water to form sodium hydroxide (NaOH), hydrogen gas (H₂), and chlorine gas (Cl₂).
The balanced molecular equation for this reaction is:
2NaCl(aq) + 2H₂O(l) → 2NaOH(aq) + H₂(g) + Cl₂ (g)
The complete ionic equation would be:
2Na+ (aq) + 2Cl + (aq) + 2H₂O(l) → 2Na+ (aq) + 2OH - (aq) + H₂(g) + Cl₂ (g)
And the net ionic equation simplifies to:
2H₂O(l) → H₂(g) + Cl₂ (g), since Na⁺ and Cl ⁻ are spectator ions and do not participate in the reaction.
What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare
100.0 milliliters of a 0.50 M acetic acid solution?
Use the equation
Mconcentrated × Vconcentrated = Mdilute × Vdilute
Answers
c₁(CH₃COOH) = 2,5 M.
c₂(CH₃COOH) = 0,5 M.
V₂(CH₃COOH) = 100 mL.
V₁(CH₃COOH) = ?
c₁(CH₃COOH) · V₁(CH₃COOH) = c₂(CH₃COOH) · V₂(CH₃COOH).
2,5 M · V₁(CH₃COOH) = 0,5 M · 100 mL.
V₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.
V₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.
Describe how the periodic table differentiates between metals and nonmetals. what type of element is most abundant: metals, nonmetals, or metalloids? give the names and symbols of three metalloids from the periodic table. identify items in your life that are made of each type of element: metal, nonmetal, and metalloid. for each item, explain why the properties of that type of element are necessary for the function of that item. prezi
Answers
1. Elements of the periodic system are divided into three groups of metals, nonmetals, and metalloids. Metals in the periodic table are separated of nonmetals by metalloids. Metals are located on the left side and the nonmetals on the right side of the periodic table. On a periodic table often is showed a stair-step line from boron to polonium which represents metan-nonmetal border. The only exception is hydrogen that is nonmetal although it is situated on the left side.
2. The most numerous elements in the periodic system are metals. At the moment, there are a total of 94 metals. There are 38 transition metals, 15 lanthanides, 15 actinides, 6 alkali metals, 6 alkaline earth metals, and 14 post-transition Metals. As regarding nonmetals, their number in the periodic table is 17 and there are 7 metalloids.
3. Metal: I would choose a copper wire, made as the name suggests from a copper that has the ability to perfectly conduct electricity.
Metalloid: I would choose a smartphone that contains computer chips made from silicon that has the property of a semiconductor.
Nonmetal: I would choose a camera flash that contains xenon, a gas which produces a white flash light when it is electrically excited.
4. Boron is a metalloid with the chemical symbol B and a serial number 5. In the periodical system, it is located in the 13th group and 2nd period.
Silicon is a metalloid with the chemical symbol Si and a serial number 14. In the periodical system, it is located in the 14th group and 3rd period.
Antimony is a metalloid with the chemical symbol Sb and serial number 51. In the periodical system, it is located in the 15th group and 5th period.
Which of the following orbitals is the largest in size?
A. 2s
B. 4s
C. 1s
D. 3s
E. all s orbitals are the same size
Answers
The orbital which is the largest in size is 4s.
Hence option (B) is correct.
What is Shape of S-orbital ?The shape of s-orbital is spherical around the nucleus of the atom. S-orbital have the probability to find the electrons at a given distance which is equal in all the directions.
Now lets check all options one by one
Option (A): 2s is a larger sphere than 1s but not 4s.
So, option A is incorrect.
Option (B): Here 1s is a small sphere, 2s is a larger sphere, 3s is more larger than 2s and 1s and 4s is the largest orbital from all of these.
So, option B is correct.
Option (C): 1s is smallest sphere from all of these.
So option C is incorrect.
Option (D): 3s is also smaller than 4s orbital.
So option D is incorrect.
Option (E): All the s-orbital have the same shape which is spherical not same size.
So option E is incorrect.
Thus, from above conclusion we can say that the orbitals which is largest in size is 4s.
The correct answer is option (B).
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What is the correct formula for the compound formed between sodium and iodine based on their positions in the periodic table?
Answers
Because the charges on anion and cation are the same; the molecular formula will be NaI
The compound formed from sodium and iodine, based on their positions on the periodic table, is Sodium Iodide (NaI). Sodium and Iodine combine in a 1:1 ratio, as Sodium is a metal with a +1 charge and Iodine is a non-metal with a -1 charge.
Explanation:The compound formed between sodium and iodine based on their positions in the periodic table is Sodium Iodide. In the periodic table, sodium is a metal (from Group 1: alkali metals) and iodine is a non-metal (from Group 17: halogens). When a metal and a non-metal combine, they typically form ionic compounds. Sodium, with a charge of +1, and iodine, with a charge of -1, combine in a 1:1 ratio to form Sodium Iodide, which has the chemical formula NaI.
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Cyanide poisoning can occur when compounds such as sodium cyanide dissociate in water to produce cyanide ions. what is the formula for sodium cyanide?
Answers
The fromula for sodium cyanide is NaCn.
The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to form its conjugate, and the other half still remains unreacted. if 0.500 moles of a monoprotic weak acid (ka = 5.0 × 10-5) is titrated with naoh, what is the ph of the solution at the half-equivalence point?
Answers
Chemical reaction: HA + NaOH → NaA + H₂O.
n₀(HA) = 0,500 mol.
Ka = 5,0·10⁻⁵.
Half of the analyte has reacted, so n(HA) = 0,5 mol ÷ 2 = 0,25 mol.
From chemical reaction: n(HA) : n(NaOH) = 1 : 1.
n(NaOH) = n(NaA) = 0,25 mol.
pH = pKa + log(n(NaA)/n(HA).
pH = -log(5,0·10⁻⁵) + log (0,25 mol/0,25 mol).
pH = 4,30.
When NaOH is added to water, the hydroxide concentration increases. What can you conclude about NaOH?
Answers
Answer:
NaOH dissociates into ions.
Explanation:
Hydroxide is one of the ions that compose NaOH, therefore the NaOH must dissociate into its constituent ions:
NaOH ⇒ Na⁺ + OH⁻
Which of these is an element?
A. Oxygen
B. Sodium Chloride
C. Water
D. Air
Answers
An "element" is a substance that is made entirely of one type of atom. Out of the four given options, A. Oxygen is considered an element, because it just can't be broken down farther. As for the other options, Sodium Chloride and water are both compounds, not elements. Air is a mixture.
Formaldehyde, h2c=o, is known to all biologists because of its usefulness as a tissue preservative. pure formaldehyde trimerizes to give trioxane, c3h6o3, which, surprisingly enough, has no carbonyl groups. only one monobromo derivative (c3h5bro3) of trioxane is possible. propose a structure for trioxane.
Answers
Please find the attached which illustrate the trimerize of the formaldehyde (HCHO) to form trioxane (C3H6O3)
The average rate of consumption of br− is 1.86×10−4 m/s over the first two minutes. what is the average rate of formation of br2 during the same time interval?
Answers
5Br(aq)+BrO3(aq)+6H(aq)= 3Br2(aq)+3H2O(l)
when the average rate of consumption of Br = 1.86x10^-4 m/s
So from the reaction equation
5Br → 3Br2 when we measure the average rate of formation (X) during the same interval So,
∴ 1.86x10^-4/5 = X / 3
∴X = 1.1 x 10^-4 m/s
∴the average rate of formation of Br2 = 1.1x10^-4 m/s
The average rate of formation of Br₂ during the first two minutes is 1.12×10⁻⁴ M/s.
This was calculated using the stoichiometric relationship between Br⁻ and Br₂ in the given reaction. The rate of formation is obtained by multiplying the rate of disappearance of Br⁻ by the stoichiometric ratio (3/5).
The chemical reaction in question is:
5Br⁻(aq) + BrO₃⁻(aq) + 6H⁺ (aq) → 3Br₂(aq) + 3H₂O(l)
Given that the average rate of consumption of Br⁻ (bromide ions) is 1.86×10⁻⁴ M/s, we need to determine the average rate of formation of Br₂ (bromine) during the same time interval.
This reaction shows that for every 5 moles of Br− consumed, 3 moles of Br₂ are produced. Therefore, the rate of formation of Br₂ will be:
Rate of Br₂ formation = (3/5) × Rate of Br⁻ consumption
Using the given rate of Br− consumption:
Rate of Br₂ formation = (3/5) × 1.86×10⁻⁴ M/s = 1.12×10⁻⁴ M/s
Thus, the average rate of formation of Br₂ during the first two minutes is 1.12×10⁻⁴ M/s.
Lewis structure for SiOS
Answers
with Si as the central atom
Number of valence electrons around each of the atoms
Si - 4
S - 6
O - 6
total number of valence electrons - 16
the number of lone pairs - 16/2 = 8
1 pair is shared between O and Si and 1 pair shared between Si and S
8-2 = 6 pairs are remaining
if we add 3 pairs each to O and Si as lone pairs their octets are complete however Si has an incomplete octet
then we convert the single bond between to O and Si to a double bond and bond between Si and S also to a double bond. By doing so the number of lone pairs around S and O are reduced to 2 lone pairs
. . . .
: O = Si = S :
Here we go!
Explanation:
Write the complete ionic equation and the Net ionic equation for: K2C2O4(aq)+Pb(OH)2(aq) -> 2KOH(aq)+PbC2O4(s)
Answers
K₂C₂O₄(aq)+Pb(OH)₂(aq) → 2KOH(aq) + PbC₂O₄(s).
Ionic equation:
2K⁺(aq) + C₂O₄²⁻(aq) + Pb²⁺(aq) + 2OH⁻(aq) → 2K⁺(aq) +2OH⁻(aq)+PbC₂O₄(s)
Net ionic eqation:
C₂O₄²⁻(aq) + Pb²⁺(aq) → PbC₂O₄(s).
s is solid, do not dissolve in water, potassiom hydroxide is trong base and dissolves in water.
The complete ionic equation for the reaction of K2C2O4(aq) with Pb(OH)2(aq) includes all ions present. The net ionic equation simplifies to Pb2+(aq) + C2O42-(aq) → PbC2O4(s).
When solutions of potassium oxalate (K2C2O4) and lead(II) hydroxide (Pb(OH)2) are mixed, a double displacement reaction occurs, forming potassium hydroxide (KOH) and lead(II) oxalate (PbC2O4), where lead(II) oxalate is an insoluble precipitate.
The complete ionic equation for the reaction is:
2 K+ (aq) + C2O42- (aq) + Pb2+ (aq) + 2 OH- (aq) → 2 K+ (aq) + 2 OH- (aq) + PbC2O4 (s)
By cancelling out the spectator ions, we can write the net ionic equation:
Pb2+ (aq) + C2O42- (aq) + 2 OH- (aq) → PbC2O4 (s) + 2 OH- (aq)
However, we can cancel out the common ions further to simplify:
Pb2+ (aq) + C2O42- (aq) → PbC2O4 (s)
Calculate the mass of aluminum in 250 g of Al(C2H3O2)3
Answers
A 14.01 g sample of n2 reacts with 3.02 g of h2 to form ammonia (nh3). if ammonia is the only product, what mass of ammonia is formed? 17.01 g 1.10 g 14.01 g 3.02 g 23.07 g
Answers
Chemical reaction: 3H₂ + N₂ → 2NH₃.
m(N₂) = 14,01 g.
n(N₂) = m(N₂) ÷ M(N₂).
n(N₂) = 14,01 g ÷ 28,02.
n(N₂) = 0,5 mol.
m(H₂) = 3,02 g.
n(H₂) = 3,02 g ÷ 2,01 g/mol.
n(H₂) = 1,5 mol.
From chemical reaction: n(N₂) : n(H₂) = 1 : 3.
From chemical reaction: n(N₂) : n(NH₃) = 1 : 2.
n(NH₃) = 2 · 0,5 mol = 1 mol.
m(NH₃) = 1 mol · 17 g/mol.
m(NH₃) = 17 g.
Final answer:
The mass of ammonia formed when 14.01 g of N2 reacts with 3.02 g of H2 is the sum of the reactant masses, which equals 17.03 g of NH3.
Explanation:
The question involves a chemical reaction where nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). The balanced equation for the formation of ammonia is:
N2(g) + 3H2(g) → 2NH3(g).
In the scenario provided, 14.01 g of N2 reacts with 3.02 g of H2. Given the stoichiometry of the reaction and the law of conservation of mass, the mass of the reactants equals the mass of the product. Therefore, if you start with 14.01 g of N2 and 3.02 g of H2, the mass of ammonia formed would be the sum of the masses of nitrogen and hydrogen, which is 17.03 g NH3.
An example of kinetic energy continuously being changed to potential energy and back again might be -
f electric charges moving in a straight path
g a train moving down a track
h a plate sitting on the edge of a table
j a girl swinging on a swing
Answers
hope this helps<3
A solution was prepared by dissolving 25.0 g of kcl in 225 g of water. calculate the mass percent of kcl in the solution.
Answers
The mass percent of KCl mass would be: 25g/ 250g= 10%
Final answer:
The mass percent of KCl in the solution is calculated by dividing the mass of KCl by the total mass of the solution and then multiplying by 100%, resulting in a mass percent of 10%.
Explanation:
To calculate the mass percent of KCl in the solution, you can use the formula: (mass of solute ÷ mass of solution) × 100%. First, calculate the mass of the solution by adding the mass of KCl and the mass of water. In this case, it would be 25.0 g of KCl + 225 g of water, which equals 250.0 g of solution.
Now, take the mass of KCl (25.0 g) and divide it by the mass of the solution (250.0 g). Multiply the result by 100% to get the mass percent of KCl in the solution.
So, the calculation is (25.0 g ÷ 250.0 g) × 100% which equals 10%. Therefore, the mass percent of KCl in the solution is 10%.
calculate the percent of lead in Pb (Co3)2
Answers
M(Pb(CO3)2) = Ar(Pb) + 2xAr(C) + 6xAr(O) = 207.2 + 2x12 + 6x16= 327.2 g/mol
M(Pb) = 207.2 g/mol
From the date above we can set the following ratio:
M(Pb(CO3)2) : M(Pb) = 100% : x
327.2 : 207.2 = 100 :x
x = 63.33% of Pb there is in Pb(Co3)2
The percent of lead in Pb(CO3)2 is calculated by dividing the molar mass of the lead by the molar mass of the entire compound and then multiplying by 100, resulting in 63.31% lead content.
Explanation:To calculate the percent of lead in Pb(CO3)2, first, we need to determine the molar mass of the compound. The molar mass of lead (Pb) is 207.2 u, and the molar mass of carbonate (CO3) is 60.01 u (with 3 oxygens at 16.0 u each plus one carbon at 12.01 u).
The molar mass of the lead carbonate compound is:
Lead (Pb): 207.2 uCarbonate (CO3): 2 x (12.01 u + 3 x 16.0 u) = 2 x 60.01 u = 120.02 uAdding these together, the molar mass of Pb(CO3)2 is 207.2 u + 120.02 u = 327.22 u.
To find the percent of lead in the compound, divide the molar mass of lead by the total molar mass of the compound and multiply by 100:
Percent of lead = (207.2 u / 327.22 u) x 100 = 63.31%
Therefore, the percent of lead in lead carbonate is 63.31%.
I need help on all of these
Answers
Chemical reaction: 2Cl₂ + Sn → SnCl₄.
n(Cl₂) = 2,85 mol.
From chemical reaction: n(Cl₂) : n(SnCl₄) = 2 : 1.
n(SnCl₄) = n(Cl₂) ÷ 2.
n(SnCl₄) = 2,85 mol ÷ 2.
n(SnCl₄) = 1,425 mol.
n - amount of substance.
2) Answer is: mass of lithium is 128,04 grams.
Chemical reaction: 6Li + N₂ → 2Li₃N.
m(N₂) = 86,1 g.
n(N₂) = m(N₂) ÷ M(N₂).
n(N₂) = 86,1 g ÷ 28 g/mol.
n(N₂) = 3,075 mol.
From chemical reaction: n(N₂) : n(Li) = 1 : 6.
n(Li) = 6 · 3,075 mol.
n(Li) = 18,45 mol.
m(Li) = 18,45 mol · 6,94 g/mol.
m(Li) = 128,04 g.
3) Answer is: 69,77 grams of oxygen can be produced.
Chemical reaction: 2Cr(ClO₃)₃ → 2CrCl₃ + 9O₂.
m(Cr(ClO₃)₃) = 146,5 g.
n(Cr(ClO₃)₃) = m(Cr(ClO₃)₃) ÷ M(Cr(ClO₃)₃).
n(Cr(ClO₃)₃) = 146,5 g ÷ 302,35 g/mol.
n(Cr(ClO₃)₃) = 0,48 mol.
From chemical reaction: n(Cr(ClO₃)₃) : n(O₂) = 2 : 9.
n(O₂) = 2,18 mol.
m(O₂) = 2,18 mol · 32 g/mol.
m(O₂) = 69,77 g.
4) Answer is: volume of hydrogen is 97,47 dm³.
Chemical reaction: 2Al + 6H₂O → 2Al(OH)₃ + 3H₂.
m(Al) = 78,33 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 78,33 g ÷ 27 g/mol.
n(Al) = 2,9 mol.
From chemical reaction: n(Al) : n(H₂) = 2 : 3.
n(H₂) = 2,9 mol · 3 ÷ 2.
n(H₂) = 4,35 mol.
V(H₂) = n(H₂) · Vm.
V(H₂) = 4,35 mol · 22,4 dm³/mol.
V(H₂) = 97,47 dm³ (L).
Vm - molar volume.
5) Answer is: there is 5,47·10²⁴ atoms of copper.
Chemical reaction: 6Cu + N₂ → 2Cu₃N.
V(N₂) = 33,9 L.
n(N₂) = V(N₂) ÷ Vm.
n(N₂) = 33,9 L ÷ 22,4 L/mol.
n(N₂) = 1,513 mol.
From chemical reaction: n(N₂) : n(Cu) = 1 : 6.
n(Cu) = 6 · 1,513 mol.
n(Cu) = 9,08 mol.
N(Cu) = n(Cu) · Na.
N(Cu) = 9,08 mol · 6,022·10²³ 1/mol.
N(Cu) = 5,47·10²⁴.
Na - Avogadro number.
Kia is doing an experiment in science lab. She is given a beaker containing 100 g of liquid. The beaker has markings on the side for measuring volume. The water comes up to the 100 mL mark. Kia puts the liquid on a hot plate by mistake. By the time she realizes the mistake, half of her liquid has evaporated.
Kia still needs 100 g of liquid for her experiment. To find out how much liquid she has to replace, she needs to re-weigh her liquid. However, the balance she used before is now broken. The teacher tells Kia that she can tell how much water is left by looking. The water now comes up to the 50 mL mark.
How much mass does Kia's remaining water have?
Answers
density=mass/volume
density= 100g/ 100ml= 1g/ml
If the water now comes up to the 50 mL mark, then the weight would be:
density = mass/volume
mass = volume * density
mass = 50ml * (1g/ml)= 50g
The correct answer is 50g.
Describe how the law of conservation of energy is demonstrated in this laboratory activity.
Answers
Law of conservation of energy can be evidenced by the total heat energy of reaction and mechanical energy of dynamic system. And the energy transfer into mass during a nuclear reaction.
What is law of conservation of mass?According to energy conservation law, energy can neither be created nor be destroyed. Therefore, the total energy in a system is conserved.
However, energy can be transformed from one form to the other such as conversion of electrical energy to chemical energy, electrical energy to mechanical energy etc.
The sum of kinetic energy and potential energy is called mechanical energy. If kinetic energy of a body increases, its potential energy decreases. Thus, total mechanical energy is constant.
This can be well explained by ,measuring the kinetic and potential energy of the a moving pendulum when it is at rest and on motion.
Similarly in chemical reactions, the total heat energy will be constant and if we take the nuclear reactions, where the energy of the product side and reactant side will be equal.
To find more about energy conservation, refer the link below:
https://brainly.com/question/2137260
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Using the given data, calculate the rate constant of this reaction.
Answers
when Rate = K [A]^x * [B]^z
So to get the rate we have to get X & Z
first, we choose two value of [A] which [A] changed and [B] still constant
that appears in trial 1 & 3 SO, we will use Rate 1 & rate 3 and [A1] &[A3] and we can neglect [B] as it is constant:
Rate3/Rate1 = ([A3]/[A1])^x
0.0852/0.0213 = (0.62/0.31)^x
4 = 2^x ∴ X = 2
- second, we have to choose two value of [B] which [B] changed and [A] still constant and that appears in trail 1&2, we will use the rate 1 &2 and [B1] & [ B2] and we can neglect [A] as it is constant:
Rate 2 / Rate 1 = ([B2]/[B1])^z
0.0213/0.0213 = (0.68/0.34)^z
1 = 2^z ∴ Z= zero
SO Rate1 = K [A]^2[B]^0
0.0213 = K * (0.31)^2 *1
∴ K = 0.222 m^-1.S^-1