Answer:
$ 30
Step-by-step explanation:
Let x be the cost of tie ( in dollars ),
∵ The shirt costs $21 more than the tie,
So, the cost of shirt = x + 21
Thus, the cost of a tie and a shirt = x + x + 21 = 2x + 21,
According to the question,
2x + 21 = 57
2x = 57 - 21
2x = 36
x = 18
Hence, the cost of the shirt = 18 + 12 = $ 30
The problem is solved using Polya's four-step problem-solving process. By setting up two equations based on the problem, we determine that the tie costs $18 and the shirt costs $39 which is confirmed by substitution into the original problem statement.
Explanation:According to Polya's four-step problem solving strategy, we first need to understand the problem. We know that a shirt and tie cost $57 together, and the shirt costs $21 more than the tie.
Step two of Polya's strategy involves devising a plan. In this case, we can write two expressions to represent the cost of the two items: S (the cost of the shirt) and T (the cost of the tie). The total cost (S+T) equals $57. We also know that S (the cost of the shirt) is T (the cost of the tie) plus $21.
For step three, we carry out the plan. We can substitute S from the second expression into the first expression: (T + $21) + T = $57. Solving for T gives us T = $18. Hence, the tie costs $18.
Finally, for step four, we review our answer. We can plug T back into the second expression to get S = T + $21 = $18 + $21 = $39. So, the shirt costs $39, which sounds reasonable given that the shirt is supposed to be more expensive than the tie.
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Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured parallel to a line
(x + 2)/3 = (2y + 3)/4 = (3z + 4)/5
Answer:
The distance is:
[tex]\displaystyle\frac{3\sqrt{142}}{10}[/tex]
Step-by-step explanation:
We re-write the equation of the line in the format:
[tex]\displaystyle\frac{x+2}{3}=\frac{y+\frac{3}{2}}{2}=\frac{z+\frac{4}{3}}{\frac{5}{3}} [/tex]
Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.
In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:
[tex]\displaystyle\vec{v}=\left< 3, 2, \frac{5}{3}\right> [/tex]
Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:
[tex]x=-2+3t\\y=3+2t\\\displaystyle z=-4+\frac{5}{3}t[/tex]
We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:
[tex]\displaystyle x+y+z=3\to -2+3t+3+2t-4+\frac{5}{3}t=3[/tex]
Then we solve that equation for t, to get:
[tex]\displaystyle \frac{20}{3}t-3=3\to t=\frac{9}{10}[/tex]
Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:
[tex]\displaystyle x=-2+3\left(\frac{9}{10}\right)=\frac{7}{10}\\\displaystyle y=3+2\left(\frac{9}{10}\right)=\frac{24}{5} \\\displaystyle z=-4+\frac{5}{3}\left(\frac{9}{10}\right)=-\frac{5}{2}[/tex]
Then to find the distance we just use the distance formula:
[tex]\displaystyle d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}[/tex]
So we get:
[tex]\displaystyle d=\sqrt{\left(-2-\frac{7}{10}\right)^2+\left(3-\frac{24}{5}\right)^2+\left(-4 +\frac{5}{2}\right)^2}=\frac{3\sqrt{142}}{10}[/tex]
Twenty girls (ages 9-10) competed in the 50-meter freestyle event at a local swim meet. The mean time was 43.70 seconds with a standard deviation of 8.07 seconds. The median time was 40.15 with an IQR of 4.98 seconds. Without looking at a graphical display, what shape would you expect the distribution of swim times to have?
The distribution of swim times from the data given would most likely be right-skewed, as the mean is larger than the median and the Interquartile Range (IQR) suggests the data is concentrated towards the middle.
Explanation:From the given data about the 50-meter freestyle event, one can deduce probable distribution shape of the swim times. Notably, the mean of 43.70 seconds significantly exceeds the median of 40.15 seconds. This fact suggests a possible right skewed distribution, with longer swim times occurring less frequently but affecting the mean more strongly due to their higher values. It's called right-skewed because the 'tail' of the distribution curve extends more towards the right.
We can also examine the Interquartile Range (IQR), which measures spread in the middle 50% of the data. This is found by subtracting the lower quartile (first 25% of data) from the upper quartile (last 25% of data). An IQR of 4.98 seconds signifies much of the data is bunched in the middle of the distribution rather than at the ends, reinforcing the notion of a skewed distribution.
Thus, without a graphical representation, the swim times would be expected to exhibit a right-skewed distribution, presenting a positive skewness in the data.
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The expected shape of the distribution of swim times would be right-skewed.
To determine the expected shape of the distribution, we compare the mean and median of the swim times:
- The mean time is 43.70 seconds, which is greater than the median time of 40.15 seconds.
- The standard deviation is 8.07 seconds, which is relatively large compared to the mean, indicating a wide spread of times.
- The interquartile range (IQR) is 4.98 seconds, which is relatively small compared to the standard deviation, suggesting that the middle 50% of the data is more tightly clustered.
In a perfectly symmetric distribution, the mean and median would be equal. However, when the mean is greater than the median, it suggests that there are some outliers or a longer tail on the right side of the distribution, pulling the mean up. The relatively large standard deviation in comparison to the IQR reinforces this idea, as it indicates there are some times that are significantly higher than the majority of the times, which are more closely packed around the median.
Describe the differences between a histogram and a stem-and-leaf display. Check All That Apply A stem-and-leaf display describes the individual observations. A stem-and-leaf display describes the individual observations. A histogram describes the individual observations. A histogram describes the individual observations. A histogram has slightly more information than a stem-and-leaf. A histogram has slightly more information than a stem-and-leaf. A stem-and-leaf display has slightly more information than a histogram.
Answer:
Step-by-step explanation:
A steam and leaf plot is the arrangement of numerical data into different groups with place value. For eg, 17,20,21 is shown as
stem leaf
1 7
2 0,1
A histogram is a bar chart that described frequency distribution.
A stem and leaf plot displays more information than a histogram.
Hence we have the correct answers are:
A stem-and-leaf display describes the individual observations.
A stem-and-leaf display has slightly more information than a histogram.
A stem-and-leaf display provides detailed individual data points and their distribution, while a histogram offers aggregated data into bins, showing the overall data distribution without individual details.
The differences between a histogram and a stem-and-leaf display are significant in how they present data. A stem-and-leaf display retains the individual data values and is beneficial for small datasets, showing the exact values and the frequency of data for each "stem" which provides a clear view of the distribution shape. On the contrary, a histogram groups data into contiguous bins, providing a visual representation of data distribution, showing the spread and most frequent values but without detailing individual data points. Therefore, a stem-and-leaf display has slightly more information than a histogram because it describes individual observations, unlike a histogram that aggregates data into bins.
How many rows of 10 make 50
Answer:
5 rows.
Step-by-step explanation:
Imagine having 10 in each row. If you had 5 rows that means you have 5 groups of 10.
Answer:
Step-by-step explanation:
10 goes into 50, 5 times. I know this because if you multiply 10x5 it gives you 50!
On a safari, a team of naturalists sets out toward a research station located 8.9 km away in a direction 42° north of east. After traveling in a straight line for 2.1 km, they stop and discover that they have been traveling 21° north of east, because their guide misread his compass. What is the direction (relative to due east) of the displacement vector now required to bring the team to the research station?
Answer:
27.19°
Step-by-step explanation:
According to the picture attached, we can find the distance between the two vectors using cosine law
[tex]a^{2} =b^{2} +c^{2} -2ab*cosA\\a=\sqrt{b^{2} +c^{2} -2ab*cosA} \\\\a=\sqrt{2.1^{2} +8.9^{2} -2(2.1)(8.9)*cos21}\\a=6.98\\\\[/tex]
Then we can get C angle by applying one more time cosine law between a and b
[tex]c^{2} =a^{2} +b^{2} -2ab*cosC\\\\c^{2} -a^{2} -b^{2}= -2ab*cosC\\\\\frac{c^{2} -a^{2} -b^{2}}{-2ab}=cosC\\ \\CosC=\frac{8.9^{2} -6.98^{2} -2.1^{2}}{-2*6.98*2.1}\\ \\CosC=-0.89\\\\ArcCos(-0.89)=C\\\\C=152.81[/tex]
We can see that the C angle is complement of the angle we are looking for, so we take away 180 degrees to get the answer
[tex]180=C+?\\\\180-C=?\\\\180-152.81=C\\\\27.19=C[/tex]
27.19 degrees is our answer!
Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, set x3 and solve for x1 and x2. x1-3x3 =-5 3x1 X2 2x34 2x1 + 2x2 + x3 = 7 Need Help? Read It Talk to a Tutor Submit Answer Save Progress Practice Another Version 1 points LarLinAlg8 1.2.033 Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, x2, and x3 in terms of the parameter t.) My Notes Ask Your Teach 2x1+ 4x1-3x2 + 7x3 = 2 8x1 - 9x2 15x3 12 3x33 (x1, x2, x3) -
Therefore, the solution to the system of equations is:
x=0
y=-3t+4
z=t
We can solve the system of equations using Gaussian elimination with back-substitution. Here's how:
Steps to solve:
1. Eliminate x from the second and fourth equations:
x+y+3z=4
0=0 (2x+5y+15z=20)-(x+2y+6z=8)
3y+9z=12
-x+2y+6z=8
2. Eliminate y from the fourth equation:
x+y+3z=4
0=0
3y+9z=12
3y+9z=12 (3y+9z=12)-(3y+9z=12)
0=0
3. Since the last equation is always true, we can ignore it.
4. Solve the remaining equations:
x+y+3z=4
0=0
3y+9z=12
From the second equation, we know that y=-3z+4. Substituting this into the first equation, we get:
x+(-3z+4)+3z=4
x+4=4
x=0
Now that we know x=0, we can substitute it back into the third equation to solve for z:
3(-3z+4)+9z=12
-9z+12+9z=12
12=12
This equation is always true, so there are infinitely many solutions. We can express x, y, and z in terms of the parameter t as follows:
x=0
y=-3z+4
z=t
Complete Question:
Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, y, and z in terms of the parameter t.)
3x + 3y + 9z = 12
x + y + 3z = 4
2x + 5y + 15z = 20
-x + 2y + 6z = 8
(x, y, z) =
martha kept track of her hot dog sales. of every 5 hotdogs sold , 4 had mustard. what percent had mustard?
Answer:
80 %
Step-by-step explanation:
Hi there!
To find the percent of hot dogs with mustard we must divide the number of hotdogs with mustard by the number of total hotdogs, and multiply this number by 100:
[tex]P = \frac{N_{withMustard}}{N_{total}}*100= 100*(4/5) = 80[/tex]
Greetings!
The numbers 2, 4, 6, and 8 are a set of four consecutive even numbers. Suppose the sum of five consecutive numbers is 320. What is the smallest of the five numbers?
The smallest of five consecutive numbers, whose sum equals 320, is 62. This is determined by setting up an equation where the sum of these numbers equals 320, then solving for the smallest number 'n'.
Explanation:The subject at hand involves understanding patterns within consecutive numbers (numbers that follow each other in order, without gaps). In the given example of four consecutive even numbers 2, 4, 6 and 8, we see that the difference between them is constantly 2.
When it comes to the sum of five consecutive numbers equating to 320, let's presume the first (and smallest) number is 'n'. Therefore, the consecutive numbers would be n, (n+1), (n+2), (n+3) and (n+4). Their sum ought to total 320, so we write the expression n + (n+1) + (n+2) + (n+3) + (n+4) = 320. By simplifying, we receive 5n+10 = 320.
Further simplifying, we subtract 10 from both sides to afford: 5n = 310. Divide 310 by 5 to isolate 'n', which results in 'n' equals 62. Consequently, the smallest of the five consecutive numbers is 62.
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(a) Find all points where the function f(z) = (x^2+y^2-2y)+i(2x-2xy) is differentiable, and compute the derivative at those points.
Answer:
The given function is differentiable at y = 1.
At y = 1, f'(z) = 0
Step-by-step explanation:
As per the given question,
[tex]f(z)\ = (x^{2}+y^{2}-2y)+i(2x - 2xy)[/tex]
Let z = x + i y
Suppose,
[tex]u(x,y) = x^{2}+y^{2}-2y[/tex]
[tex]v(x,y) = 2x - 2xy[/tex]
On computing the partial derivatives of u and v as:
[tex]u'_{x} =2x[/tex]
[tex]u'_{y}=2y -2[/tex]
And
[tex]v'_{x} =2-2y[/tex]
[tex]v'_{y}=-2x[/tex]
According to the Cauchy-Riemann equations
[tex]u'_{x} =v'_{y} \ \ \ \ \ \ \ and\ \ \ \ \ \ u'_{y} = -v'_{x}[/tex]
Now,
[tex](u'_{x} =2x) \neq (v'_{y}=-2x)[/tex]
[tex](u'_{y}=2y -2) \ = \ (- v'_{x} =-(2-2y) =2y-2)[/tex]
Therefore,
[tex]u'_{y}=- v'_{x}[/tex] holds only.
This means,
2y - 2 = 0
⇒ y = 1
Therefore f(z) has a chance of being differentiable only at y =1.
Now we can compute the derivative
[tex]f'(z)=\frac{1}{2}[(u'_{x}+iv'_{x})-i(u'_{y}+iv'_{y})][/tex]
[tex]f'(z) =\frac{1}{2}[(2x+i(2-2y))-i(2y-2+i(-2x))][/tex]
[tex]f'(z) = i(2-2y)[/tex]
At y = 1
f'(z) = 0
Hence, the required derivative at y = 1 , f'(z) = 0
Show that the given curve c(t) is a flow line of the given velocity vector field F(x, y, z).
c(t) = (2 sin(t), 2 cos(t), 9et); F(x, y, z) = (y, −x, z)
c'(t) = ?
F(c(t)) = ?
Answer:
a) [tex]c'(t) = (2 Cos(t), -2 Sin(t), 9e^t) [/tex]
b) [tex]c'(t) = (2 Cos(t), -2 Sin(t), 9e^t) [/tex]
Step-by-step explanation:
We are given in the question:
[tex]c(t) = (2 Sin(t), 2 Cos(t), 9e^t)[/tex]
F(x,y,z) = (y, -x, z)
a) [tex]c'(t) [/tex]
We differentiate with respect to t.
[tex]c'(t) = (2 Cos(t), -2 Sin(t), 9e^t) [/tex]
b) F(c(t))
This is a composite function.
[tex]F(c(t)) = F(2 Sin(t), 2 Cos(t), 9e^t)[/tex]
[tex]= (2 Cos(t), -2 Sin(t), 9e^t)[/tex]
List all element of the following sets
a. { 1/n ∣ n ∈ { 3 , 4 , 5 , 6 } }
b. {x∈Z ∣ x=x+1}
c. {n∈P ∣ n is a factor of 24 }
Answer:
a) The elements are [tex]\frac{1}{3},\frac{1}{4},\frac{1}{5},\frac{1}{6}[/tex]
b) The elements are (-∞ ...-1,0,1,2,..∞).
c) The elements are 2 and 3.
Step-by-step explanation:
To find : List all element of the following sets ?
Solution :
a) [tex]\{\frac{1}{n}| n\in \{ 3 , 4 , 5 , 6 \} \}[/tex]
Here, The function is [tex]f(n)=\frac{1}{n}[/tex]
Where, [tex]n\in \{ 3 , 4 , 5 , 6 \}[/tex]
Substituting the values to get elements,
[tex]f(3)=\frac{1}{3}[/tex]
[tex]f(4)=\frac{1}{4}[/tex]
[tex]f(5)=\frac{1}{5}[/tex]
[tex]f(6)=\frac{1}{6}[/tex]
The elements are [tex]\frac{1}{3},\frac{1}{4},\frac{1}{5},\frac{1}{6}[/tex]
b) [tex]\{x\in \mathbb{Z} | x=x+1\}[/tex]
Here, The function is [tex]f(x)=x+1[/tex]
Where, [tex]x\in \mathbb{Z}[/tex] i.e. integers (..,-2,-1,0,1,2,..)
For x=-2
[tex]f(-2)=-2+1=-1[/tex]
For x=-1
[tex]f(-1)=-1+1=0[/tex]
For x=0
[tex]f(0)=0+1=1[/tex]
For x=1
[tex]f(1)=1+1=2[/tex]
For x=2
[tex]f(2)=2+1=3[/tex]
The elements are (-∞ ...-1,0,1,2,..∞).
c) [tex]\{n\in \mathbb{P}| \text{n is a factor of 24}\}[/tex]
Here, The function is n is a factor of 24.
Where, n is a prime number
Factors of 24 are 1,2,3,4,6,8,12,24.
The prime factor are 2,3.
The elements are 2 and 3.
On three examinations, you have grades of 85, 78, and 84. There is still a final examination, which counts as one grade In order to get an A your average must be at least 90. If you get 100 on the final, what is your numerical average? (Type an integer or a decimal)
Answer:
The average of the provided grades are 86.75
Step-by-step explanation:
Consider the provided information.
On three examinations, you have grades of 85, 78, and 84. In order to get an A your average must be at least 90.
In the last exam you get 100 marks now calculate the average by using the formula:
[tex]\frac{\text{Sum of observations}}{\text{Number of observations}}[/tex]
[tex]\frac{85+78+84+100}{5}[/tex]
[tex]\frac{347}{5}[/tex]
[tex]86.75[/tex]
86.75 is less than 90 so you will not get A.
The average of the provided grades are 86.75
Show that if a, b e Z, then a^2 - 4b =/ 2
Step-by-step explanation:
Proposition If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex], then [tex]a^{2}-4b \neq2[/tex]
You can prove this proposition by contradiction, you assume that the statement is not true, and then show that the consequences of this are not possible.
Suppose the proposition If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex], then [tex]a^{2}-4b \neq2[/tex] is false. Thus there exist integers If a, b [tex]\in[/tex] [tex]\mathbb{Z}[/tex] for which [tex]a^{2}-4b=2[/tex]
From this equation you get [tex]a^{2}=4b+2=2(2b+1)[/tex] so [tex]a^{2}[/tex] is even. Since [tex]a^{2}[/tex] is even, a is even, this means [tex]a=2d[/tex] for some integer d. Next put [tex]a=2d[/tex] into [tex]a^{2}-4b=2[/tex]. You get [tex] (2d)^{2}-4b=2[/tex] so [tex]4(d)^{2}-4b=2[/tex]. Dividing by 2, you get [tex]2(d)^{2}-2b=1[/tex]. Therefore [tex]2((d)^{2}-b)=1 [/tex], and since [tex](d)^{2}-b[/tex] [tex]\in[/tex] [tex]\mathbb{Z}[/tex], it follows that 1 is even.
And that is the contradiction because 1 is not even. In other words, we were wrong to assume the proposition was false. Thus the proposition is true.
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
This sequence has generating function
[tex]F(x)=\displaystyle\sum_{k\ge0}k^3x^k[/tex]
(if we include [tex]k=0[/tex] for a moment)
Recall that for [tex]|x|<1[/tex], we have
[tex]\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k[/tex]
Take the derivative to get
[tex]\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k[/tex]
[tex]\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k[/tex]
Take the derivative again:
[tex]\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k[/tex]
[tex]\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k[/tex]
Take the derivative one more time:
[tex]\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k[/tex]
[tex]\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k[/tex]
so we have
[tex]\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}[/tex]
Find the error with this proof and explain how it mat be corrected in order to clearly prove the equation.
Prove that if m is an odd integer, then m2 is odd.
Proposed proof: Assume m is an odd integer. By definition of odd integer, m=2k+1, for some integer k.
This means that (2k + 1)^2 = 4k^2 + 1, so m is odd.
Answer:
Step-by-step explanation:
It is true that for any given odd integer, square of that integer will also be odd.
i.e if [tex]m[/tex] is and odd integer then [tex]m^{2}[/tex] is also odd.
In the given proof the expansion for [tex](2k + 1)^{2}[/tex] is incorrect.
By definition we know,
[tex](a+b)^{2} = a^{2} + b^{2} + 2ab[/tex]
∴ [tex](2k + 1)^{2} = (2k)^{2} + 1^{2} + 2(2k)(1)\\(2k + 1)^{2} = 4k^{2} + 1 + 4k[/tex]
Now, we know [tex]4k^{2}[/tex] and [tex]4k[/tex] will be even values
∴[tex]4k^{2} + 1 + 4k[/tex] will be odd
hence [tex](2k + 1)^{2}[/tex] will be odd, which means [tex]m^{2}[/tex] will be odd.
The error in the proof is in the expansion of the square of an odd integer. The correct expansion is 4k² + 4k + 1, and adding 1 to an even number 4k² + 4k results in an odd number, proving that m² is odd when m is an odd integer.
The proposed proof has a mistake in expanding the square of an odd integer. The correct expansion of (2k + 1)² is 4k² + 4k + 1, not 4k² + 1 as stated in the proof. To correct the proof:
Assume that m is an odd integer.By definition, m can be written as 2k + 1, where k is an integer.Squaring m yields (2k + 1)² = 4k² + 4k + 1.The expression 4k² + 4k is clearly even since it's divisible by 2.Adding 1 to an even number results in an odd number. Hence, m² is odd.Proof by Contradiction : Show that √ 2 is irrational.
Answer:
[tex]\sqrt2[/tex] is irrational
Step-by-step explanation:
Let us assume that [tex]\sqrt2[/tex] is rational. Thus, it can be expressed in the form of fraction [tex]\frac{x}{y}[/tex], where x and y are co-prime to each other.
[tex]\sqrt2[/tex] = [tex]\frac{x}{y}[/tex]
Squaring both sides,
[tex]2 = \frac{x^2}{y^2}[/tex]
Now, it is clear that x is an even number. So, let us substitute x = 2u
Thus,
[tex]2 = \frac{(2u)^2}{y^2}\\y^2 = 2u^2[/tex]
Thus, [tex]y^2[/tex]is even, which follows the fact that y is also an even number. But this is a contradiction as x and y have a common factor that is 2 but we assumed that the fraction [tex]\frac{x}{y}[/tex] was in lowest form.
Hence, [tex]\sqrt2[/tex] is not a rational number. But [tex]\sqrt2[/tex] is a an irrational number.
Two fair dice are tossed, and the up face on each die is recorded. Find the probability of observing each of the following events. Answer in fraction form or decimal approximation with 4 decimal places: A:{A:{ A 5 does not appear on either die }} B:{B:{ The difference of the numbers is 2 }} C:{C:{ The sum of the numbers is 10 or more }
Step-by-step explanation:
When two dies are tossed, possible outcomes are (1,1) (1,2) ,(1,3) (1,4), (1,5) (1,6),(2,1) (2,2) (2,3) (2,4) (2,5) (2,6), (3,1)(3,2)(3,3)(3,4),(3,5)(3,6)(4,1) (4,2),(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
so the total sample space =36
From de possible outcome, probability of getting a die that five does not appear on either side is given by total outcome of not getting five from either side/sample space
=30/36 = 5/6
And also probability of getting the difference of numbers to be 2 are (3,1)(4,2) (5,3) (6,4) =4outcomes
the probability of getting a difference of 2 is given by outcome/sample space 4/36 = 1/9
probability of getting the summation of two numbers to be equal to or greater than ten are; Outcome/sample space.
the outcome are (4,6) (5,5) (5,6)(6,4)(6,5)and (6,6)= 6outcomes
=6/36 =1/12.
The probabilities for the three events are approximately 0.6944, 0.2222, and 0.1667 respectively. These figures were achieved by comparing the number of favorable outcomes to the total number of outcomes when rolling two dice.
Explanation:The subject of this question is probability which involves using numbers for calculation. When you roll two dice, there are 36 possible outcomes.
Event A: The probability that a 5 does not appear on either die can be calculated by subtracting the outcomes where one or both dice show five (11 outcomes) from total outcomes. So the probability is (36-11)/36, or around 0.6944 as a decimal approximation.Event B: The difference of the numbers is 2 happens in 8 cases (3 and 1, 4 and 2, 5 and 3, 6 and 4, 1 and 3, 2 and 4, 3 and 5, 4 and 6). So the probability is 8/36, which simplifies to 2/9 or around 0.2222 in decimal approximation.Event C: The sum of the numbers is 10 or more happens in 6 cases (5 and 5, 6 and 4, 4 and 6, 6 and 5, 5 and 6, 6 and 6). So the probability is 6/36, which simplifies to 1/6 or around 0.1667 in decimal approximation.
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Write a differential equation whose only solution is the trivial solution y = 0. Explain your reasoning
Answer:
[tex]2e^{y'}y=0[/tex]
Step-by-step explanation:
The solution for this differential equation [tex]2e^{y'}y=0[/tex] have to be the trivial solution y=0. Because the function [tex]e^{x}[/tex] always have values different of zero, then the only option is the trivial solution y=0.
Prove the following statement.
The square of any odd integer has the form 8m+1 for some integer m.
As per the question,
Let a be any positive integer and b = 4.
According to Euclid division lemma , a = 4q + r
where 0 ≤ r < b.
Thus,
r = 0, 1, 2, 3
Since, a is an odd integer, and
The only valid value of r = 1 and 3
So a = 4q + 1 or 4q + 3
Case 1 :- When a = 4q + 1
On squaring both sides, we get
a² = (4q + 1)²
= 16q² + 8q + 1
= 8(2q² + q) + 1
= 8m + 1 , where m = 2q² + q
Case 2 :- when a = 4q + 3
On squaring both sides, we get
a² = (4q + 3)²
= 16q² + 24q + 9
= 8 (2q² + 3q + 1) + 1
= 8m +1, where m = 2q² + 3q +1
Now,
We can see that at every odd values of r, square of a is in the form of 8m +1.
Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.
Hence , it is clear that square of an odd positive is in form of 8m +1
3.2.19 Statistics students conducted a test to see if people could taste the difference between Coke and Pepsi. They fill two cups with Coke and a third with Pepsi. They then asked their subjects which tasted different than the other two. Of the 64 people they tested, 22 were able to correctly identify which of the three cups of colas tasted different. Determine a 95% theory-based confidence interval for the population proportion that can correctly identify the cola that is different? What is the margin of error from your interval from part (a)?
The confidence interval for population mean is given by :-
[tex]\hat{p}\pm E[/tex], where [tex]\hat{p}[/tex] is sample proportion and E is the margin of error .
[tex]E=z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]
Given : Significance level : [tex]\alpha:1-0.95=0.05[/tex]
Sample size : n= 64
Critical value : [tex]z_{\alpha/2}=1.96[/tex]
Sample proportion: [tex]\hat{p}=\dfrac{22}{64}\approx0.344[/tex]
[tex]E=(1.96)\sqrt{\dfrac{0.344(1-0.344)}{64}}\approx0.1164[/tex]
Hence, the margin of error = 0.1164
Now, the 95% theory-based confidence interval for the population proportion will be :
[tex]0.344\pm0.1164\\\\=(0.344-0.1164,\ 0.344+0.1164)=(0.2276,\ 0.4604)[/tex]
Hence, the 99% confidence interval is [tex](0.2276,\ 0.4604)[/tex]
When constructing a 95% theory-based confidence interval for the proportion of people that can correctly identify the different cola, the interval ranges from about 0.225 to 0.463. The margin of error is approximately 0.118.
Explanation:This question pertains to a theory-based confidence interval for the population proportion. In this case, the proportion (p) is the number of people who correctly identified the different cola, which is 22 out of 64, or 0.34375. First, we need to calculate the standard error (SE), which is the square root of [ p(1-p) / n ], where n is the sample size. So, SE = sqrt[ 0.34375(1-0.34375) / 64 ] ≈ 0.0602.
The 95% confidence interval can be calculated as p ± Z * SE, where Z is the Z-score from the standard normal distribution corresponding to the desired level of confidence. For a 95% confidence interval, Z = 1.96. Plug the values into the equation gives us the interval [0.34375 - 1.96(0.0602), 0.34375 + 1.96(0.0602)] which is approximately [0.225, 0.463].
The margin of error is the difference between the endpoint of the interval and the sample proportion, which can be calculated as Z*SE. So the margin of error = 1.96(0.0602) ≈ 0.118.
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Using a formula estimate the body surface area of a person whose height is 5 feet and who weighs 120 pounds.
A.
1.52 m2
B.
0.32 m2
C.
1.13 m2
D.
55.9 m2
Answer:
(A) 1.52 m²
Step-by-step explanation:
As per the given data of the question,
Height of a person = 5 feet
As we know that 1 feet = 30.48 cm
∴ Height = 152.4 cm
Weight of a person = 120 pounds
And we know that 1 pound = 0.453592 kg
∴ Weight = 54.4311 kg
The Mosteller formula to calculate body surface area (BSA):
[tex]BSA(m^{2})=\sqrt{\frac{Height (cm)\times Weight(kg)}{3600}}[/tex]
Therefore,
[tex]BSA=\sqrt{\frac{Height (cm)\times Weight(kg)}{3600}}[/tex]
[tex]BSA=\sqrt{\frac{152.4\times 54.4311}{3600}}[/tex]
[tex]BSA= 1.517 m^{2} = 1.52 m^{2}[/tex]
Hence, the body surface area of a person = 1.52 m²
Therefore, option (A) is the correct option.
What is the probability of selecting an ace of diamonds from a deck of cards?
5/52
1/52
4/52
1/13
Mr Barkley has a box of books. He says the number of books in the box is divisible by 2,3,4,5 and 6. How many books could be in the box? Add another factor so there is only one possible solution.
Answer:
The number of books in the box is 60.
Step-by-step explanation:
Since it is given that the number of books in the box is divisible by 2,3,4,5 and 6.
So, the number of books in the box is multiple of these numbers.
Thus we have to find Least Common Multiple (L.C.M.) of these number
L.C.M. of (2,3,4,5,6) = 60
Thus the number of books in the box is multiples of 60 i.e. 60, 120, 180, 240,... etc.
The other factor that can we add in statement so there is only one possible solution is: "The number of books in the box is smallest number divisible by 2,3,4,5 and 6".
Answer:
The number is 60
Step-by-step explanation:
So the first way to solve this would be to multiply the greatest numbers in the sequence, you have 5 and 6, the result is 30, since 30 is not divisible by 4 you need to find the next number that is divisible by 5 and 6, that would be 60, since 60 is divisible by 4, then that is the answer, 60 is the first number that is divisible by 2, 3, 4, 5, and 6.
In the equation g = 312 ÷ α , the variable g can be described best as the 1. number of degrees that a skateboarder turns when making α rotations. 2. total number of groups, g, with α students each that can be made if there are 312 students to be grouped. 3. weight of a bag containing α grapefruits if each piece of fruit weighs 312 grams. 4. total number of goats that can graze on 312 acres if each acre can feed α goats. 5. number of grams of fuel, g, needed to raise the temperature of a solution, α, to a temperature of 312◦F.
Answer:
5) True. G is the Number of grams of fuel, g, needed to raise the temperature of a solution, α, to a temperature of 312◦F.
Step-by-step explanation:
Hi!
Let's examine better this equation: [tex]g=\frac{312}{a}[/tex]
What we have here 312 is a dependent variable, and it is inversely proportional to a. The more a increases the more g decreases.
1) Number of degrees that a skateboarder turns when making "α" rotations
[tex]g=\frac{312}{a}[/tex]
1 rotation ----------- 312°
2 rotation ----------- 156°
Here we have a problem. The skateboarder must necessarily and randomly turn 312°, and its fractions. But in a circle, the rotation cannot follow this pattern.
False
2) The total number of groups, g, with "α" students each that can be made if there are 312 students to be grouped.
[tex]g=\frac{312}{a}[/tex]
1 group --------------- 312 students
2 groups ------------ 156 students
5 groups -------------62.4 students
Even though 312 is divisible for 1,2,3,4 it is not for 5,7,9, and the group is a countable, natural category.
False
3) Weight of a bag containing "α" grapefruits if each piece of fruit weighs 312 grams
[tex]g=\frac{312}{a}[/tex]
g=1 bag with 1 grapefruit-------------- 312 g
g=1 bag with 2 grapefruits ---------- 156 g
That doesn't make sense, since for this description. The best should be g=312a and not g=312/a.
False
4) The total number of goats that can graze on 312 acres if each acre can feed "α" goats.
Since there's a relation
1 acre can feed ----------------- 1 goat
312 acres can feed ----------------g
g= 312/1 = 312 acres can feed 1 goat (1 acre for 1 goat)
g=312/2= since 312 acres can feed 156 goats (1 acre for 2 goats)
g =312/3 = 312 acres can feed 104 (1 acre for 3 goats)
Clearly, this function g=312/a does not describe this since the ratio is not the same, as long as we bring more goats to graze on those 312 acres.
False
5) Number of grams of fuel, g, needed to raise the temperature of a solution, α, to a temperature of 312◦F
g= number of grams of a fuel
a= initial temperature of a solution
g=312/a
Let's pick a=100 F initial temperature
g=312/100
g=3.12 grams
Let's now pick 200F as our initial temperature.
g=312/200 g=1.56 grams of solution
The more heat needed to raise, the more fuel necessary. Then True
Show that Z2[i] = {a + bi | a,b € Z2} is not a field
Step-by-step explanation:
On a field every element different from 0 should have a multiplicative inverse. Let's check that in Z2[i] not ALL nonzero elements have multiplicative inverses.
Z2 is made of two elements: 0 and 1, and so Z2[i] is made of four elements: 0+0i,0+1i, 1+0i, 1+1i (which we can simplify from now on as 0, i, 1, 1+i respectively). Now, let's check that the element 1+i doesn't have a multiplicative inverse (we can do this by showing that no matter what we multiply it by, we're not getting 1, which is the multiplicative identity)
[tex](1+i)\cdot 0 = 0[/tex] (which is NOT 1)
[tex](1+i)\cdot i = i+i^2=i-1=1+i[/tex] (which is NOT 1) (remember -1 and 1 are the same in Z2)
[tex](1+i)\cdot 1 = 1+i[/tex] (which is NOT 1)
[tex](1+i)\cdot (1+i) = 1+i+i+i^2=1+2i-1=0+0i=0[/tex] (which is NOT 1) (remember 2 is the same as 0 in Z2)
Therefore the element 1+i doesn't have a multiplicative inverse, and so Z2[i] cannot be a field.
a cell phone tower that is 150 ft tall sits on a mountain that
is 1200 ft above sea level. what is the angle of depression from
the top of the tower to a cell user 5 miles away and 400 ft above
sea level?
Answer:
angle of elevation will be [tex]2.14^o.[/tex]
Step-by-step explanation:
Given,
height of tower = 150 ft
height of tower = 1200 ft
So, total height of peak of tower = 1200 + 150
= 1350 ft
distance of user from cell tower = 5 miles
= 5 x 5280 feet
= 26,400 feet
Since the height of user from sea level = 400 ft
so, height of peak of tower with respect to user = 1350 - 400 ft
= 950 ft
If the angle of depression is assumed as [tex]\theta[/tex], then we can write
[tex]tan\theta\ =\ \dfrac{\textrm{height of peak of tower w.r.t user}}{\textrm{distance of user from tower}}[/tex]
[tex]=>\ tan\theta\ =\ \dfrac{950}{26400}[/tex]
[tex]=>\ tan\theta\ =\ 0.374[/tex]
[tex]=>\ \theta\ =\ 2.14^o[/tex]
So, the angle of elevation will be [tex]2.14^o.[/tex]
Purchase likelihood 18 dash 34 35 dash 44 45 dash 54 55 plus Total More likely 223 373 384 404 1384 Less likely 26 7 26 13 72 Neither more nor less likely 285 210 169 113 777 Total 534 590 579 530 2233 (a) What is the probability that a randomly selected individual is 35 to 44 years of age, given the individual is neither more nor less likely to buy a product emphasized as "Made in our country"? The probability is approximately 0.270 0.270. (Round to three decimal places as needed.) (b) What is the probability that a randomly selected individual is neither more nor less likely to buy a product emphasized as "Made in our country," given the individual is 35 to 44 years of age? The probability is approximately nothing. (Round to three decimal places as needed.)
Answer:
(a) 0.270 . . . . as you know
(b) 0.356
Step-by-step explanation:
(a) p(35-44 | neither) = (35-44 & neither)/(neither total) = 210/777 ≈ 0.270
__
(b) p(neither | 35-44) = (neither & 35-44)/(35-44 total) = 210/590 ≈ 0.356
A lawyer researched the average number of years served by 45 different justices on the Supreme Court. The average number of years served was 13.8 years with a standard deviation of 7.3 years. What is the 95% confidence interval estimate for the average number of years served by all Supreme Court justices? Place your limits, rounded to 1 decimal place, in the blanks. Place you lower limit in the first blank.
Answer: [tex]11.7<\mu<15.9[/tex]
Step-by-step explanation:
Given : Significance level : [tex]\alpha:1-0.95=0.05[/tex]
Sample size : n=45
Critical value : [tex]z_{\alpha/2}=1.96[/tex]
Sample mean : [tex]\overline{x}=13.8\text{ years}[/tex]
Standard deviation : [tex]\sigma=7.3\text{ years}[/tex]
The confidence interval for population mean is given by :-
[tex]\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=13.8\pm(1.96)\dfrac{7.3}{\sqrt{45}}\\\\\approx13.8\pm2.1\\\\=(13.8-2.1,\ 13.8-2.1)=(11.7,\ 15.9)[/tex]
Hence, the 95% confidence interval estimate for the average number of years served by all Supreme Court justices is [tex]11.7<\mu<15.9[/tex]
Find the period and amplitude of the function. y-2sin 6x Give the exact values, not decimal approximations. Period: 2 Amplitude:
Answer:
Amplitude=2
Period=[tex]\frac{\pi}{3}[/tex]
Step-by-step explanation:
We are given that [tex]y=2sin6x[/tex]
We have to find the value of period and amplitude of the given function
We know that [tex]y=a sin(bx+c)+d [/tex]
Where a= Amplitude of function
Period of sin function =[tex]\frac{2\pi}{\mid b \mid}[/tex]
Comparing with the given function
Amplitude=2
Period=[tex]\frac{2\pi}{6}=\frac{\pi}{3}[/tex]
Hence, period of given function=[tex]\frac{\pi}{3}[/tex]
Amplitude=2
Company A charges $331.35 per week for a compact car with unlimited miles. Company B charges $175 per week plus $0.53 per mile, for the same car. How many miles must be driven in a week so that company A is a better deal than company B?
Answer:
Company A is a better deal than Company B for the number of miles greater than 295 miles
Step-by-step explanation:
Let
y ----> the charge per week in dollars
x ----> the number of miles
we have
Company A
[tex]y=331.35[/tex] -----> equation A
Company B
[tex]y=0.53x+175[/tex] -----> equation B
Solve the system by substitution
Equate equation A and equation B and solve for x
[tex]331.35=0.53x+175[/tex]
[tex]0.53x=331.35-175\\0.53x=156.35\\x=295\ mi[/tex]
For x=295 miles the charge in Company A and Company B is the same
therefore
Company A is a better deal than Company B for the number of miles greater than 295 miles