Use the order of operations to simplify this expression 4 + 0.8 x 1.5 - 3

In six seconds,a total of 3 waves crash onto the shore of the beach .

The distance between each wave crest on the water is 8 meters.

Wave length is the length between two wave crests that is the distance between two wave crests.

We know distance between each wave crest is 8 meters

Total of 3 wave crests, the distance between first and second wave crest is 8 meters

the distance between second and third wave crest is 8 meters

So wave length = 8+8 = 16 meters

Answer:

The correct option is:  B. 9

Step-by-step explanation:

The number of tennis balls, [tex]P(n)[/tex] , in [tex]n[/tex] layers of the square pyramid is given by:   [tex]P(n)=P(n-1)+n^2[/tex]

As the stack of the tennis balls is in shape of a square pyramid, that means in the top layer, there will be one ball. So,  [tex]P(1)= 1[/tex]

Now, if [tex]n=2,[/tex] then [tex]P(2)= P(2-1)+(2)^2 = P(1)+4=1+4=5[/tex]

If  [tex]n=3,[/tex] then [tex]P(3)=P(3-1)+(3)^2=P(2)+9=5+9=14[/tex]

If  [tex]n=4,[/tex] then [tex]P(4)=P(4-1)+(4)^2 = P(3)+16=14+16=30[/tex]

That means, the number of tennis balls from the top layer will be:  1, 5, 14, 30, .......

So, the number of tennis balls that Coach Kunal could not have is 9.

the correct answer is b.9

The first thing we must do for this case is to define variables: x: number of tickets sold before the tournament. y: number of tickets sold at the door. The system of equations that adapts to this situation is given by: x + y = 820 x-y = 80 Answer: The correct options are: option 2 option 3 option 5

Answer:

The correct options are:

option 2

option 3

option 5

Step-by-step explanation:

To round 74.58 to the nearest tenth, look at the digit in the hundredth place (8) and round up the digit in the tenths place (5) by adding 1 to get 74.6.

To round 74.58 to the nearest tenth,

We have to look at the digit in the hundredth place, which is 8.

The rule for rounding to the nearest tenth is to look at the digit in the hundredth place.

If it is 5 or greater, you round up the digit in the tenths place by adding 1. If it is less than 5,

Simply drop the digit in the hundredths place and leave the digit in the tenths place as it is.

In this case,

The digit in the hundredths place is 8, which is greater than 5.

Therefore, we must round up the digit in the tenths place, which is 5, by adding 1 to get 6.

Thus, 74.58 rounded to the nearest tenth is 74.6.

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we are given

[tex](-3+5i)^2[/tex]

we can expand it

[tex](-3+5i)^2=(-3+5i)(-3+5i)[/tex]

now, we can FOIL it

[tex](-3+5i)^2=-3\times -3-3\times 5i+5i\times -3+5i\times 5i[/tex]

now, we can simplify it

[tex](-3+5i)^2=9-15i-15i+25i^2[/tex]

we know that

[tex]i^2=-1[/tex]

so, we can plug it

[tex](-3+5i)^2=9-30i+25(-1)[/tex]

[tex](-3+5i)^2=9-30i-25[/tex]

[tex](-3+5i)^2=-16-30i[/tex]..............Answer

Answer: Choice A)

x^2 + (x+2)^2 = (x+4)^2

========================================

Consecutive even integers are whole numbers that are as close as possible and they are also even as well. One example of having 3 of them is {2, 4, 6}. Another example is {4,6,8} and another example is {6,8,10}. You start with any even integer you want, then count up by 2 each time to get the next values.

In general, if x is your first even number, then x+2 is the next number up. Eg: x = 10 so x+2 = 10+2 = 12. Then after that, x+4 is the third number (if x = 10, x+4 = 10+4 = 14)

a = x is the side length of the shorter leg

b = x+2 is the side length of the longer leg

c = x+4 is the side length of the hypotenuse

Use the pythagorean theorem to get

a^2 + b^2 = c^2

x^2 + (x+2)^2 = (x+4)^2

To solve the quadratic equation 48x^2 + 44x = 60, one can rearrange it to the standard form, use the quadratic formula, attempt factoring if it is factorable, or multiply by a common factor to simplify. The most common method is the quadratic formula which provides a systematic way to find the solutions.

To solve the equation 48x^2 + 44x = 60, we can use several methods that are commonly used to solve quadratic equations. First, we need to rearrange the equation into the standard quadratic form, which is ax^2 + bx + c = 0. By subtracting 60 from both sides of the equation, we get 48x^2 + 44x - 60 = 0.

One way to solve for x is by using the quadratic formula, which is x = (-b ± √(b^2 - 4ac))/(2a), where a, b, and c are coefficients from the quadratic equation ax^2 + bx + c = 0. In this situation, a = 48, b = 44, and c = -60. By plugging these values into the quadratic formula, we can find the two possible solutions for x.

Alternatively, we can try to factor the quadratic if it can be expressed as a product of two binomials. In some cases, like when the quadratic is a perfect square or can be easily factored, this is a simpler solution. However, if factoring is complicated or not apparent, the quadratic formula can always be used as a reliable method.

Additionally, if the equation has coefficients that are not integers or are difficult to work with, we can multiply both sides by a common factor to simplify the equation into a more manageable form with integer coefficients, after which we can proceed to use the quadratic formula or factor the quadratic, if possible.

The correct expression to find solutions is [tex]\(4(4x + 3)(3x - 5)\)[/tex], as it correctly factors the given quadratic equation.

To find the solutions to the given quadratic equation [tex]\(48x^2 + 44x = 60\)[/tex], we can use factoring. The equation needs to be rearranged to set it equal to zero:

[tex]\[48x^2 + 44x - 60 = 0\][/tex]

Now, we can factor the quadratic expression. The correct factorization is:

[tex]\[4(4x + 3)(3x - 5)\][/tex]

To verify this, distribute the factors:

[tex]\[4(4x + 3)(3x - 5) = 48x^2 + 36x - 60x - 45\][/tex]

Combine like terms:

[tex]\[48x^2 - 24x - 45\][/tex]

This matches the original quadratic expression, confirming the correct factorization.

Therefore, the correct expression that could be used to find the solutions to the given equation is [tex]\(4(4x + 3)(3x - 5)\)[/tex].

Complete Question:

The sequence of 3 letters "a,b,c" is repeating.

[tex]40=3\cdot13+\boxed{1}[/tex]

So it will be the letter at the 1st position, which is a.

Answer:

The answer is A

Step-by-step explanation:

(the product of one-fourth and a number plus seven)

An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is D, the product of one-fourth and a number plus seven.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

2x + 3 is an example of a variable mathematical expression. Every variable must have a coefficient, which is a number multiplied by the variable. The coefficient of x in the formula 2x + 3 is the number 2, and it signifies 2 times x plus 3.

The given algebraic expression 1/4d+7 can be represented as a phrase as the product of one-fourth and a number plus seven.

Hence, the phrase that represents the algebraic expression 1/4d+7 is the product of one-fourth and a number plus seven.

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Answer:

Only options a ,b,d have the same solution as [tex]\frac{3}{5}x +\frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x[/tex]

Step-by-step explanation:

Given:

An equation:  [tex]\frac{3}{5}x +\frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x[/tex]    ....[1]

Like terms states that contain the same variables raised to the same power.

Combine like terms on left hand side in equation [1] we get,

[tex]\frac{3}{5}x+x +\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x[/tex]

[tex]\frac{8}{5}x +\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x[/tex]

we get option (a) as the same solution.

Using LCM(Least Common ) to change each fraction to make their denominators the same as the least common denominator

Taking LCM both sides in Equation (1) ,

[tex]\frac{3}{5}x +\frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x[/tex]

As LCM(3,5)=15 and LCM(2,5)=10 we have,

[tex]\frac{9x+10+15x}{15}= \frac{5-2x}{10}[/tex]

On simplifying we get,

[tex]10(9x+10+15x)= 15(5-2x)[/tex]=

Dividing both sides by 5 we get,

[tex]\frac{10(9x+10+15x)}{5} =\frac{15(5-2x)}{5}[/tex]

On simplify:

[tex]2(9x+10+15x)=3(5-2x)[/tex]

∴ [tex]18x+20+30x=15-6x[/tex]

which is same solution as given in option (b).

Now,

Use Additive Property of Equality states that allows one to add the same quantity to both sides of an equation.

Further, using the above property add 6x both sides  in  [tex]18x+20+30x=15-6x[/tex] we get,

[tex]18x+20+30x+6x=15-6x+6x[/tex]

On simplifying we get,

[tex]18x+20+30x+6x=15[/tex]

Subtract 20 from both the sides we get,

[tex]18x+20+30x+6x-20=15-20[/tex]

Simplify:

[tex]18x+30x+6x=-5[/tex]

or, [tex]24x+30x=-5[/tex] which is same solution  as given in option(d)

But, options c and e equation doesn't have same solution as [tex]\frac{3}{5}x +\frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x[/tex]

The Answer Is 196

                            Hope It Helps Mark Me The Brainlyest

Answer:

it should be c 14 to the power 2

Step-by-step explanation:

-24n2+31 if im correct!

Answer:

[tex]-24n^2 + 31[/tex]

Step-by-step explanation:

[tex]7 - 3[(n^3 + 8n) divide (-n) + 9n^2][/tex]

To simplify it we use order of operation PEMDAS

Parenthesis , exponents , multiply, divide, add and subtract

[tex]7 - 3[(n^3+ 8n) divide (-n) + 9n^2][/tex]

LEts start with parenthesis (divide by -n)

[tex]7 - 3[-n^2-8+ 9n^2][/tex]

Now we simplify the parenthesis by combining like terms

[tex]7 - 3[-8+8n^2][/tex]

multiply by -3

[tex]7+24 -24n^2[/tex]

[tex]-24n^2 + 31[/tex]

For this case we have the following:

So:

[tex]x ^ 2 + x^{\frac{1}{2} }+ x + 6[/tex] is not a polynomial

Answer:

Option B

The expression which is not a polynomial is:

            B)   [tex]x^2+x^{\dfrac{1}{2}}+x+6[/tex]

We know that the general form of a polynomial expression is given by:

[tex]P(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+......+a_2x^2+a_1x+a_0[/tex]

i.e. P(x) is a polynomial of degree n  , where n belongs to natural numbers and [tex]a_i's[/tex] belong to the real numbers.

and [tex]a_n\neq 0[/tex]

A)

[tex]\dfrac{3}{x^{-1}}+\dfrac{3}{2}[/tex]

which could also be written by:

[tex]3x+\dfrac{3}{2}[/tex]

Hence, this expression is a polynomial expression.

Option: a is incorrect.

B)

[tex]x^2+x^{\dfrac{1}{2}}+x+6[/tex]

Since in the second term the power of x does not belong to the set of natural numbers.

Hence, option: b is not a polynomial expression.

Hence, the correct answer is option: b

C)

[tex]x^3-9[/tex]

Since, the expression matches the definition of the polynomial expression.

Hence, option: c is incorrect.

D)

[tex]\sqrt{16x^4}[/tex]

This could also be written as:

[tex]=4x^2[/tex]

Hence, it is a polynomial expression.

Hence, option: d is incorrect.

5 x 10^2

= 5 x 100

= 500

Alright, so to solve this we have to use P.E.M.D.A.S. There are no parenthesis, so we move on to exponents. 10^2. Well, we know that 10 multiplied by 10 is 100. So the new equation is 5 multiplied by 100. The answer is 500.

This question i know. It is C

For this one, the best way to answer is to use the question and it will guide us to the answer.

First, you can eliminate two choices:

the problem states that a number minus ten and nine

so you can eliminate B and D because it is 10 minus a number.  In math, you can be picky and take the question exactly.

Then, look at the last part, "when decreased by seven."  So now look between A and C and see which one is decreasing by 7.  Based on that C would be your answer

C) 9(x-10) -7 = 50

Hope this helps!

Answer:

 Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

Explanation:

 Marks received by Marta in four tests =  86, 84, 97 and 89

 Let mark received in fifth test be x

 We have average of five test is more than or equal to 90

 So we have

    [tex]\frac{86+84+97+89+x}{5} \geq 90\\ \\ 86+84+97+89+x\geq 450\\ \\ x\geq 94[/tex]

 So Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

The lowest grade she can receive on her fifth and final test to achieve an average of 90 or higher is 94.

Marta hopes to have a test average of at least 90 by the end of the marking period. Her grades on the first four tests have been 86, 84, 97 and 89. To find the lowest grade she can receive on her fifth and final test to achieve an average of 90 or higher, we can use the formula:

Average = (Sum of all grades) / Total number of grades

Let x be the lowest grade she can receive on her fifth test. We can set up the equation:

(86 + 84 + 97 + 89 + x) / 5 = 90

Now we can solve for x:

86 + 84 + 97 + 89 + x = 90 * 5

356 + x = 450

x = 450 - 356

x = 94

Therefore, the lowest grade Marta can receive on her fifth and final test and still have a test average of 90 or higher is 94.

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Answer: 275 Miles

Step-by-step explanation: 55 x 5 = 275

Answer:

275 Miles

Step-by-step explanation:

55 mph * 5hours= 275 Miles

Answer:

P = 15/20 = 3/4

Step-by-step explanation:

20 minutes - 5 minutes = 15 minutes.

The probability of waiting at least 5 minutes = 15/20 = 3/4 = 75%

-3x+9 = -3(2x+3) + 3(x-4)+1

distribute

-3x+9 =-6x-9+3x-12+1

add like terms

-3x+9= -3x-20

add 3x to each side

9 = -20

there are no solutions because 9 does not equal -20

Answer:

Step-by-step explanation:

The formula for area of a square is A=s^2

Taking the square root of each side

sqrt(A) =s

sqrt(36)=s

6yds =s

The length of each side of the square is 6 yards.

2.53 is then answer .... im pretty sure

Answer:

  Hank's pickup need 3 gallons of gas to travel 54 miles.

Explanation:

   Hank's pickup can travel 72 miles on 4 gallons of gas

   Miles travel by  Hank's pickup with 1 gallon of gas = 72/4 = 18 miles.

  We need to find gallons of gas required for Hank's pickup to travel 54 miles.

  Gallons of gas required =  Miles need to travel/ Miles travel with 1 gallon of gas

                                        = 54/18 = 3 gallons of gas.

 So Hank's pickup need 3 gallons of gas to travel 54 miles.

Step 1: reflected across the line y=x

Step 2: reflected across the x axix

Since all 3 shapes are still the same size and shape:

Because the transformations are both rigid , the pre-image and image are congruent

To calculate the total value of Eve's stamps, multiply the number of stamps (24) by the value of each stamp ($24.75), resulting in a total value of $594.00.

The question involves calculating the total value of stamps using multiplication. Eve has 24 stamps, each valued at $24.75. To find the total value, we multiply the number of stamps by the value of each stamp.

Here is the calculation:

Therefore, the total value of Eve's stamps is $594.00.