Answers
when Rate = K [A]^x * [B]^z
So to get the rate we have to get X & Z
first, we choose two value of [A] which [A] changed and [B] still constant
that appears in trial 1 & 3 SO, we will use Rate 1 & rate 3 and [A1] &[A3] and we can neglect [B] as it is constant:
Rate3/Rate1 = ([A3]/[A1])^x
0.0852/0.0213 = (0.62/0.31)^x
4 = 2^x ∴ X = 2
- second, we have to choose two value of [B] which [B] changed and [A] still constant and that appears in trail 1&2, we will use the rate 1 &2 and [B1] & [ B2] and we can neglect [A] as it is constant:
Rate 2 / Rate 1 = ([B2]/[B1])^z
0.0213/0.0213 = (0.68/0.34)^z
1 = 2^z ∴ Z= zero
SO Rate1 = K [A]^2[B]^0
0.0213 = K * (0.31)^2 *1
∴ K = 0.222 m^-1.S^-1
Related Questions
The solubility of KNO3(s) in water increases as the..
a. Pressure on the solution decreases
b. Temperature of the solution increases
c. pressure on the solution increases
d. Temperature of the solution decreases
Answers
Temperature determines the kinetic energy of the water molecule. Higher temperature will cause the molecule to moves faster and the compound (KNO3) could break solute molecule easier make it become more soluble. A higher pressure will increase the solubility of a gas, not solid
TRUE of FALSE
During the process of cellular respiration, water becomes oxygen.
Answers
Answer:
False.
Explanation:
Hello,
During cellular respiration, glucose reacts with oxygen to produce carbon dioxide, water and energy based on:
[tex]C_6H_{12}O_6+6O_2-->6CO_2+6H_2O+Energy[/tex]
Best regards.
The R-COOH compound behaves as an _____. acid base alcohol ester
Answers
Answer: Option (a) is the correct answer.
Explanation:
An organic compound that contains "-COOH" as the function group is known as carboxylic compound.
A carboxylic compound is an acid as it dissociates to give hydrogen ion.
[tex]R-COOH \rightarrow R-COO^{-} + H^{+}[/tex]
Whereas a compound with functional group "-OH" is known as alcohol.
And, a compound with general formula RCOOR' is known as an ester.
Thus, we can conclude that the R-COOH compound behaves as an acid.
Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of solution?
Use mc006-1.jpg.
0.333 M
0.751 M
1.50 M
3.00 M
Answers
[tex]the \: answer \: is \: 3 \: molar[/tex]
the solution is as follows
[tex]moles \: of \: NaCl \: in \: the \: solution[/tex]
=
[tex]give \: mass \: of \: sodium \: chloride \\ - - - - - - - - - - - - - - - - \\ molecular \: mass \: of \: sodium \: chloride \: [/tex]
=
[tex] \: \: 87.75 \\ - - - - \\ \: \: 58.44[/tex]
[tex] = \: 1.501 \: moles[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: moles \: of \: solute \\ Molarity \: = \: \: \: \: \: - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: volume \: of \: solution(litrs)[/tex]
[tex]applying \: the \: formulae \: [/tex]
converting ml to litres
1.501/(500/1000)
1.501 X 2
3 M
Hope it helps
Answer: D on Edge :)
Explanation:
Given that the vapor pressure of water is 17.54 torr at 20 °c, calculate the vapor-pressure lowering of aqueous solutions that are 1.80 m in (a) sucrose, c12h22o11, and (b) sodium chloride. assume 100% dissociation for electrolytes.
Answers
1)
b(solution) = 1,80 m = 1,80 mol/kg..
If we use 1000 g of water to make solution:
m(H₂O) =
1000 g ÷ 1000 g/kg = 1 kg.
n(sucrose - C₁₂O₂₂O₁₁) = b(solution) · m(H₂O).
n(C₁₂O₂₂O₁₁) =
1,8 mol/kg · 1 kg.
n(C₁₂O₂₂O₁₁) =
1,8 mol.
n(H₂O)
= 1000 g ÷ 18 g/mol.
n(H₂O)
= 55,55 mol.
Mole fraction of solvent = 55,55 mol ÷
(55,55 mol + 1,8 mol) = 0,968.
Raoult's Law: p(solution) = mole fraction of solvent · p(solvent).
p(solution) = 0,968 · 17,54 torr = 16,99 torr.
Δp = 17,54 torr - 16,87 torr = 0,55 torr.
2) b(solution) = 1,80 m = 1,80 mol/kg..
If we use 1000 g of water to make solution:
m(H₂O) =
1000 g ÷ 1000 g/kg = 1 kg.
n(NaCl) = b(solution) · m(H₂O).
n(NaCl) = 1,8 mol/kg · 1 kg.
n(NaCl) = 1,8 mol.
n(H₂O) =
1000 g ÷ 18 g/mol.
n(H₂O) =
55,55 mol.
i(NaCl) = 2; Van 't Hoff factor. Because dissociate on one
cation and one anions.
Mole fraction of solvent = 55,55 mol ÷ (55,55 mol + 1,8 mol · 2) = 0,94.
Raoult's Law: p(solution) = mole fraction of
solvent · p(solvent)
p(solution) = 0,94 · 17,54 torr = 16,47 torr.
Δp = 17,54 torr - 16,47 torr = 1,06 torr.
The vapor-pressure lowering for a sucrose solution is 31.572 torr and for a sodium chloride solution is 63.144 torr, both computed using the colligative property of vapor pressure lowering.
Explanation:To calculate the vapor-pressure lowering, we'll use the formula for the colligative property of vapor pressure lowering: ΔP = P0 * i * m. Here, ΔP is the vapor pressure lowering, P0 is the vapor pressure of the pure solvent, i is the van 't Hoff factor (the number of particles the solute splits into), and m is the molality of the solution.
(a) For sucrose, we consider it to be nonvolatile and non-ionizing. The van 't Hoff factor is 1 (because sucrose does not dissociate into ions). So, ΔP = 17.54 torr * 1 * 1.80 m = 31.572 torr.
(b) For sodium chloride, assuming 100% dissociation, it splits into two ions (Na+ and Cl-). So, the van 't Hoff factor is 2. Therefore, ΔP = 17.54 torr * 2 * 1.80 m = 63.144 torr.
Remember, a larger number of solute particles will greater lower the vapor pressure of the solvent.
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List four greenhouse gases in the atmosphere. For each gas, describe its prevalence in the atmosphere, its natural sources, its human-induced sources, and how its concentration in the atmosphere might be changing.
Answers
The answer/answers: The four main greenhouse gases that support the natural greenhouse effect are:
H2O (water vapor)
CO2 (carbon dioxide)
CH4 (methane)
and
NO (nitrous oxide)
These greenhouse gas traps heat from the sun
Hopes this Helps u :D
The primary greenhouse gases are carbon dioxide, methane, nitrous oxide, and water vapor. They are naturally produced through processes like respiration, decomposition, and evaporation, but levels have been significantly increased due to human activities such as farming, waste treatment, and the burning of fossil fuels.
Explanation:The four main greenhouse gases are carbon dioxide, methane, nitrous oxide, and water vapor. Carbon dioxide, the most prevalent GHG, is naturally released through processes like respiration and volcano eruptions, but human activities like fossil fuel combustion have significantly increased their levels. Methane, though less plentiful, is incredibly potent. It occurs naturally in marshes and other wet environments and is also produced by human agriculture and waste treatment processes. Nitrous oxide, less common still, is released naturally by bacteria, but human sources include fertilizers and industrial activities. Lastly, water vapor, the most abundant GHG, is released through evaporation and plant transpiration, and its levels are also indirectly impacted by human GHG emissions as the warmer the atmosphere, the more water vapor it can hold.
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PLEASE HELP ME BABES AND ASAP PLEASE!!
What special structures are needed for green plants?
A.chloroplasts and chlorophyll
B. stems and roots
C. cotyledon and embryo
D. flowers and spores
What happens during the light reaction of photosynthesis?
A.Water molecules combine to make food.
B.Air and water create energy for a plant.
C.Carbon dioxide is combined with glucose.
D. Water molecules split apart.
Answers
A.chloroplasts and chlorophyll
What happens during the light reaction of photosynthesis?
D. Water molecules split apart. (Not 100%)
What is the change in oxidation number of sulfur when the dithionite anion, s2o42−, is converted to so2 in an oxidation-reduction reaction? does each sulfur atom gain or lose electrons in the reaction? is sulfur oxidized or reduced in the reaction?
Answers
2 · x + 4 ·(-2) = -2.
2x = +6.
x = +3; oxidation number of sulfur.
In sulfur(IV) oxide (SO₂), sulfur has oxidation number +4, because oxygen is again -2 and compound has neutral charge:
x + 2 · (-2) = 0.
x = +4.
Change in sulfur is from +3 to +4.
Sulfur atoms lose electrons in the reaction. Sulfur is oxidized in the reaction, because his oxidation number raise from +3 to +4.
What is the maximum mass of sugar that could be dissolved in 1.3 l of water?
Answers
The solubility of sugar in water in room temperature is 204 g/100 ml.
Make proportion, if 204 grams of sugar dissolve in 100 ml of water, than how much dissolve in 1300 ml of water:
204 g : 100 ml = m(sugar) : 1300 ml.
m(sugar) = 204 g · 1300 ml ÷ 100 ml.
m(sugar) = 2652 g ÷ 1000 g/kg = 2,652 kg.
A certain gas is present in a 12.0 L cylinder at 4.0 atm pressure. If the pressure is increased to 8.0 atm the volume of the gas decreases to 6.0 L . Find the two constants ki, the initial value of k, and kf, the final value of k, to verify whether the gas obeys Boyle’s law by entering the numerical values for ki and kf in the space provided.
Answers
1) To find the initial Boyle's constant [tex]k_{i}[/tex]
2) To find the final Boyle's constant [tex]k_{f}[/tex]
3) To verify whether gas is obeying Boyle's law or not
Given data:
The initial volume of the cylinder(in litres) = [tex]V_{i}[/tex] = 12.0 L
The initial pressure(in atmospheric pressure) = [tex]P_{i}[/tex] = 4.0 atm
The final pressure(in atmospheric pressure) = [tex]P_{f}[/tex] = 8.0 atm
The final volume of the cylinder(in litres) = [tex]V_{f}[/tex] = 6.0 L
First you need to know what Boyle's law is:
Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.
The Mathematical form of Boyle's law is:
[tex]P = \frac{k}{V} [/tex]
Where,
P = Pressure
V = Volume of the gas
k = Boyle's constant
Now let's solve aforementioned parts one by one:
1.
The initial volume of the cylinder(in litres) = [tex]V_{i}[/tex] = 12.0 L
The initial pressure(in atmospheric pressure) = [tex]P_{i}[/tex] = 4.0 atm
The Boyle's constant = [tex]k_{i}[/tex] = ?
According to the Boyle's law,
[tex]P_{i} = \frac{k_{i}}{V_{i}} [/tex]
=> [tex]k_{i}[/tex] = [tex]P_{i}V_{i}[/tex]
Plug-in the values in the above equation, you would get:
[tex]k_{i}[/tex] = 4.0 * 12.0 = 48
Ans-1) [tex]k_{i}[/tex] = 48
2.
The final pressure(in atmospheric pressure) = [tex]P_{f}[/tex] = 8.0 atm
The final volume of the cylinder(in litres) = [tex]V_{f}[/tex] = 6.0 L
The Boyle's constant = [tex]k_{f}[/tex] = ?
According to the Boyle's law,
[tex]P_{f} = \frac{k_{f}}{V_{f}} [/tex]
=> [tex]k_{f}[/tex] = [tex]P_{f}V_{f}[/tex]
Plug-in the values in the above equation, you would get:
[tex]k_{f}[/tex] = 8.0 * 6.0 = 48
Ans-2) [tex]k_{f}[/tex] = 48
3.
In order to verify Boyle's law, the initial Boyle's constant should be EQUAL to the final Boyle's constant, meaning:
[tex]k_{i}[/tex] = [tex]k_{f}[/tex]
Since,
[tex]k_{i}[/tex] = 48
[tex]k_{f}[/tex] = 48
Therefore,
48=48.
Ans-3) Hence proved: The gas IS obeying the Boyle's law.
-i
The initial value of constant [tex]{{\text{k}}_1}[/tex] is 48.0 atmL and the final value of constant [tex]{{\text{k}}_2}[/tex] is 48.0 atmL. This proves that Boyle's lawis obeyed by gas.
Further explanation:
Boyle’s law:
It is an experimental gas law that describes the relationship between pressure and volume of the gas. According to Boyle's law, the volume of the gas is inversely proportional to the pressure of the system, provided that the temperature and the number of moles of gas remain constant.
If the temperature and number of moles of gas are constant then the equation (1) will become as follows:
[tex]{\text{PV}} = {\text{k}}[/tex] ……(2)
Here, k is a constant.
Or it can also be expressed as follows:
[tex]{{\text{P}}_1}{{\text{V}}_1} = {{\text{P}}_2}{{\text{V}}_2}[/tex] ……(3)
Here,
[tex]{{\text{P}}_1}[/tex] is the initial pressure.
[tex]{{\text{P}}_2}[/tex] is the final pressure.
[tex]{{\text{V}}_1}[/tex] is the initial volume.
[tex]{{\text{V}}_2}[/tex] is the final volume.
Boyle'slaw for the initial condition of gas can be written as,
[tex]{{\text{P}}_1}{{\text{V}}_1}={{\text{k}}_1}[/tex] …… (4)
Substitute 4.0 atm for [tex]{{\text{P}}_1}[/tex] and 12.0 L for [tex]{{\text{V}}_1}[/tex] in equation (4).
[tex]\begin{aligned}\left( {4.0{\text{ atm}}}\right)\left({12.0{\text{ L}}}\right)&= {{\text{k}}_1}\hfill\\48.0{\text{ atm}}\cdot{\text{L}}&= {{\text{k}}_1}\hfill\\\end{aligned}[/tex]
Boyle's law for the final condition of gas can be written as,
[tex]{{\text{P}}_2}{{\text{V}}_2} = {{\text{k}}_2}[/tex] …… (5)
Substitute 8.0 atm for [tex]{{\text{P}}_2}[/tex] and 6.0 L for [tex]{{\text{V}}_2}[/tex] in equation (5).
[tex]\begin{aligned}\left( {8.0{\text{ atm}}}\right)\left({6.0{\text{ L}}}\right)&={{\text{k}}_2}\hfill\\48.0{\text{ atm}}\cdot{\text{L}}&={{\text{k}}_2}\hfill\\ \end{aligned}[/tex]
Since the value of [tex]{{\text{k}}_1}[/tex] and [tex]{{\text{k}}_2}[/tex] is equal in both cases thus this gives,
[tex]{{\text{P}}_1}{{\text{V}}_1} = {{\text{P}}_2}{{\text{V}}_2}[/tex]
Hence, it is proved that Boyle's law is obeyed by the given gas.
Learn more:
1. Law of conservation of matter states: https://brainly.com/question/2190120
2. Calculation of volume of gas: https://brainly.com/question/3636135
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Ideal gas of equation
Keywords: Boyle's law, volume, temperature, pressure, volume pressure relationship, constant temperature, relationship, V inversely proportional to P, ideal gas, ideal gas equation number of mole and moles.
Draw the major product(s) of electrophilic chlorination of p-cyanobenzoic acid.
Answers
For the sake of the question, we will assume that the reaction is allowed to take place. Therefore, each group will be trying to direct the to different meta-positions. The nitrile group is a much stronger withdrawing group, therefore, it will be the major directing group and the chloro will substitute in the position that is meta- to the nitrile, and ortho- to the carboxylic acid. The minor product would be the meta-position relative to the carboxylic acid. The reaction scheme provided shows the potential products of this reaction.
Helium has the lowest boiling point of any substance, at 4.2 k. part a what is this temperature in âc?
Answers
The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273,15: T(°C) = T(K) - 273.15.
T(He) = 4,2 K.
T(He) = 4,2 K - 273,15.
T(He) = -268,95°C.
The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm pressure.
The temperatur e of Helium in °C = -268.8 °
Further explanationTemperature is one of the principal quantities that shows the degree of heat or cold from an object / space
Temperature is used as a guide to the level of heat energy from objects
Temperature measures thermal energy
The temperature of an object also depends on the kinetic energy of the object's molecules
Temperature cannot be measured by the surface of the hand because it is not accurate but can be measured by a thermometer. Temperature units include Celsius, Fahrenheit, Reamur or Kelvin
Boiling point and freezing point of Temperature units;
1. CelsiusBoiling point : 100 °C
Freezing point: 0 °C
2. ReamurBoiling point : 80 °R
Freezing point: 0 °R
3. FahrenheitBoiling point : 212 °F
Freezing point: 32 °F
4. KelvinBoiling point : 373 °K
Freezing point: 273 °K
Whereas the temperature conversion is
°F = (9/5) °C + 32
°R = (4/5) °C
°K = °C + 273
°C = 5/9 (°F-32)
°R = 4/9 (°F-32)
°K = 5/9 (°F-32) + 273
°C = °K - 273
°R = 4/5 (°K-273)
°F = 9/5 (°K-273) + 32
°C = (5/4) °R
°F = (9/4) °R + 32
°K = °C + 273
°K = (5/4) °R + 273
Helium at 4.2 K, then the temperature in C :
C = K - 273
C = 4.2 - 273
C = -268.8 C
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relationships among temperature, heat, and thermal energy.
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If two protons and two neutrons are added to the nucleus of a carbon atom, what nucleus does it become?
Answers
if the theoretical yield of RX is 56.0 g , what is the percent yield ?
Answers
Let
x------------------- > actual yield
y------------------- > theoretical yield
z------------------- > percent yield
we have that
z=x/y
we know
x=47 g
y=56 g
therefore
z=47/56=0.839 ---------------- > 83.9%
the answer is the option C 83.9%
A sample of potassium chlorate (15.0 g) is dissolved in 201 g of water at 70 °c with precautions taken to avoid evaporation of any water. the solution is cooled to 30.0 °c and no precipitate is observed. this solution is __________.
a.hydrated
Answers
Solubility of potassium chlorate on 70°C is approximately 30 grams in 100 grams of water.
Solubility of potassium chlorate on 70°C is approximately 10 grams in 100 grams of water.
So if dissolve 15 g of potassium chlorate in 201 g of water, there is less salt than it solubility and solution is unsaturated.
The potassium chlorate remains fully dissolved in the water even when the temperature is lowered, thus the solution is considered to be saturated.
Explanation:The potassium chlorate in the question is fully dissolved in water at a certain temperature (70°C) and it stays in solution even when the temperature is lowered to 30°C. This indicates that the complete dissolution of the potassium chlorate was achieved, and the solution is considered to be saturated. A saturated solution is one in which the maximum amount of solute has been dissolved in a solvent at a given temperature and below that temperature, no precipitate forms because the solute remains in solution.
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if the theoretical yield of RX is 56.0 g , what is it’s percent yield ?b
Answers
the theoretical yield = 56.0 g
actual yield = 47.0 g
percent yield = actual yield / theoretical yield x 100 %
percent yield = 47.0 / 56.0 x 100% = 83.9 %
percent yield = 83.9 %
Let
x------------------- > actual yield
y------------------- > theoretical yield
z------------------- > percent yield
we have that
z=x/y
we know
x=47 g
y=56 g
therefore
z=47/56=0.839 ---------------- > 83.9\%
the answer is the option C 83.9\%
What is the relationship between an observation and an inference?
A. An observation is fact, but an inference is only opinion.
B. An observation can be proven or disproven, but an inference cannot.
C. An inference is an attempted explanation based on observations.
D. An inference is based on fact, but an observation is based on experimentation.
Answers
In the Scientific Method, you make a hypothesis (or inference) based on observations or questions to make from the world around you. An observation is not a fact, nor is an inference an opinion.
The best answer is: "C" An inference is an attempted explanation based on observations.
I hope this helps!
~kaikers
Final answer:
An inference is an explanation based on observations which are facts or data collected through sensory experience or scientific measurement. Observations can lead to inferences, where logic and knowledge are applied to the observed facts to draw conclusions.
Explanation:
The relationship between an observation and an inference is that an inference is an attempted explanation based on observations. An observation is the act of noting and recording something with instruments and measuring devices, whereas an inference is the conclusion reached using logic and knowledge after the observation. While observations are the direct results of experiments consciously made to determine facts, inferences are the reasoned conclusions or interpretations of what the observations mean. In the context of the student's question, observations are regarded as facts established through sensory experience or scientific measurement, and inferences are logical conclusions drawn from these observations.
In which circumstance is the transition state more similar to the products of the reaction?
Answers
hoped it helped !!
He main reasons why ch4 has a higher vapor pressure at a given temperature when compared to ch3cl is that
Answers
CH4 exhibits weaker London dispersion forces while CH3Cl has stronger dipole-dipole interactions due to its polar C-Cl bond, resulting in CH4 having a higher vapor pressure at the same temperature than CH3Cl.
Explanation:The main reason why CH4 has a higher vapor pressure at a given temperature when compared to CH3Cl is primarily due to the differences in the types and strengths of their intermolecular forces (IMFs). Methane (CH4) only exhibits London dispersion forces, which are the weakest type of IMFs because it is a non-polar molecule.
On the other hand, chloromethane (CH3Cl) exhibits both London dispersion forces and dipole-dipole interactions due to the presence of a polar C-Cl bond. This dipole-dipole interaction in CH3Cl is stronger than the dispersion forces in CH4, leading to stronger intermolecular attractions in CH3Cl and, consequently, a lower vapor pressure at the same temperature.
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d = 1.114 g/ml; = 62.07 g/mol) and water (d = 1.00 g/ml) at 20°c. the density of the mixture is 1.070 g/ml. express the concentration of ethylene glycol as:
Answers
Formula: % v/v = [volume solute / volume solution] * 100
Just to make it easy take a base of 50 volume parts of ethylen glycol and 50 volume parts of water to make 100 volumes of mixture (this assumpion will be valid for all the questions):
% v/v =[ 50 ml ethyleneglycol] / [100 ml mixture] * 100 = 50%
Answer: 50% v/v
b) Mass percent
% m/m = [mass ethylene glycol / mass solution] * 100
mass ethylene glycol = 50 ml * 1.114 g/ ml = 55.7 g
mass of mixture = 100 ml * 1.07 g/ml = 107 g
% m/m = [55.7 / 107 g] * 100 = 52.06 %
Answer: 52.06%
c) Molarity
M = number of moles of solute / liters of solution
number of moles of solute = mass in grams / molar mass
number of moles of ehtylene glycol = 55.7 g / 62.07 g/mol = 0.8974 mol
liters of solution = 0.1 liter
M = 0.8974 mol / 0.1 liter = 8.974 M
Answer: 8.974 M
d) Molality
m = number of moles of solute / kg of solvent
number of moles of ethylen glycol = 0.8974 mol
mass of water = 50 ml * 1 g/ml = 50 g = 0.05 kg
m = 0.8974 mol / 0.05 kg = 17.95 m
Answer: 17.95 m
e) mole fraction
mole fraction = [number of moles of solute] / [number of moles of mixture] * 100
number of moles of ethylen glycol = 0.8974 mol
number of moles of water = 50 g / 18.01 g /mol = 2.776 mol
mole fraction = 0.8974 mol / [0.8974 mol + 2.776 mol] = 0.244
Answer: 0.244
The concentration of ethylene glycol in the antifreeze mixture can be calculated by determining the mole fraction. First, find the moles of ethylene glycol and water, then use the mole fraction to find the concentration. The final concentration of ethylene glycol is 0.0179 mol/kg.
Explanation:To calculate the concentration of ethylene glycol in the antifreeze mixture, we'll first need to find the mole fraction, which involves calculating the molar amounts of both ethylene glycol and water.
Since 1ml of each liquid is used, we have 1.114g of ethylene glycol and 1.00g of water. The molar mass of ethylene glycol is 62.07 g/mol, so 1.114g / 62.07 g/mol = 0.0179 moles of ethylene glycol. The molar mass of water is 18.02 g/mol, so 1.00g / 18.02 g/mol = 0.0555 moles of water.
The mole fraction (X) of a substance is the number of moles of that substance divided by the total number of moles of all substances in the solution. So, X_ethylene glycol = 0.0179 / (0.0179 + 0.0555) = 0.244.
Finally, to express concentration of ethylene glycol as molality, we use the formula molality = moles of solute/kg of solvent. Hence, molality = 0.0179 moles/1g = 0.0179 mol/kg.
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which rock future is the line running between points A and B most likely to be?
A)
rock
B)
strata still
C)
dice
D)
fault
Answers
Answer:
On plato this would be D a fault line
Explanation:
Which of the following is an example of how science can solve social problems? It can stop excessive rain from occurring. It can identify the sources of polluted water. It can control the time and day when cyclones happen. It can reduce the frequency of severe weather conditions.
Answers
Answer: It can identify the sources of polluted water.
Scientific innovations and researches have been proved to be beneficial in solving the day to day social problems such as household practices such as cooking, washing of cloth, industrialization and conservation of the environment.
It can identify the sources of polluted water is the correct example of how science can solve social problems. The source of pollution can be identified by tracing back it's origin and application of filters and purifiers can help in controlling the pollution.
An example of how science can solve social problems is : ( B ) It can Identify the sources of polluted water
Scientific innovationsSeveral scientific innovations have made the identification and resolution of certain problems easier and one of such is the ability to Identify the dangers and sources of pollution.
Certain natural conditions such as excessive rain, cyclones and severe weather conditions can be identified but not stopped because they occur naturally.
Hence an example of how science can solve social problems is It can identify the sources of polluted water.
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A first-order reaction has a half-life of 29.2 s . how long does it take for the concentration of the reactant in the reaction to fall to one-sixteenth of its initial value?
Answers
Answer is: it takes 116,8 seconds to fall to one-sixteenth of its initial value
The half-life for the chemical reaction is 29,2 s and is
independent of initial concentration.
c₀
- initial concentration the reactant.
c - concentration of the reactant remaining at time.
t = 29,2 s.
First calculate the rate constant k:
k = 0,693 ÷ t = 0,693 ÷ 29,2 s = 0,0237 1/s.
ln(c/c₀) = -k·t₁.
ln(1/16 ÷ 1) = -0,0237 1/s ·
t₁.
t₁ = 116,8 s.
What is the main reason for processing coal ore?
A) To increase heating value
B) To remove inorganic material
C) To eliminate pollution of groundwater
D) To recover other valuable minerals from the ore
Answers
It is A because to increase heating value removing other materials from coal increases its effectiveness as an energy source, making the coal more valuable. It also reduces transportation costs.
A compound decomposes by a first-order process. if 25.0% of the compound decomposes in 60.0 minutes, the half-life of the compound is _________.
a. 65 minutes
b. 198 minutes
c. 120 minutes
d. 145 minutes
e. 180 minutes
Answers
Half-life is the time needed for a radioactive to decay half of its weight. The formula to find the half-life would be:
Nt= N0 (1/2)^ t/h
Nt= the final mass
N0= the initial mass
t= time passed
h= half-life
If 25.0% of the compound decomposes that means the final mass would be 75% of initial mass. Then the half-live for the compound would be:
Nt= N0 (1/2)^ t/h
75%= 100% * (1/2)^ (60min/h)
3/4= 1/2^(60min/h)
log2 3/4 = log2 1/2^(60min/h)
0.41503749928 = -60min/h
h= -60 min / 0.41503749928= 144.6min
How much chalcopyrite had to be mined to produce 100 pennies if reaction 1 had a percent yield of 68.00 % and all other reaction steps had yield of 100%?
Answers
Answer:
[tex]m_{CuFeS_2}=1273.8gCuFeS_2[/tex]
Explanation:
Hello,
In this case, the set of chemical reactions are shown below:
(1) 2 CuFeS₂ + 3 O₂ ----> 2 CuS + 2 FeO + 2 SO₂
(2) 2 FeO + SiO₂ ----> 2 FeSiO₃
(3) 2 CuS ----> Cu₂S + S
(4) Cu₂S + S + O₂ ----> 2 Cu + 2 SO₂
In such a way, the pennies are assumed to be 100% copper, and each penny has about 3.0 g of copper, so based on the 4th reaction, we compute moles of Cu₂S and pass through until the 1st reaction as shown below:
[tex]n_{Cu_2S}=100pennies*\frac{3.0gCu}{1penny}*\frac{1molCu}{63.5gCu}*\frac{1molCu}{2molCu} \\n_{Cu_2S}=2.36molCu_2S[/tex]
Now, from the 3rd reaction we compute the moles of CuS:
[tex]n_{CuS}=2.36molCu_2S*\frac{2molCuS}{1molCu_2S}=4.72molCuS[/tex]
2nd reaction is needless, so we proceed to compute CuS's theoretical amount since the 4.72 mol of CuS are said to be actually obtained (real amount) as shown below:
[tex]n_{CuS}^{theoretical}=\frac{n_{CuS}^{real}}{Y}=\frac{4.72molCuS}{0.68} \\n_{CuS}^{theoretical}=6.94molCuS[/tex]
Now, we develop the shown-below stoichiometric relationship between CuS and the chalcopyrite to compute the required amount to be mined in grams, for example
[tex]m_{CuFeS_2}=6.94molCuS*\frac{2molCuFeS_2}{2molCuS}*\frac{183.54gmolCuFeS_2}{1molCuFeS_2} \\m_{CuFeS_2}=1273.8gCuFeS_2[/tex]
Best regards.
Consider the first-order reaction shown here. the yellow spheres in the pictures to the right represent the reactant,
a. the blue spheres represent the product,
b. a → b (a) what is the rate constant of the reaction? s−1 (b) how many a (yellow) and b (blue) molecules are present at t = 20 s? yellow molecules blue molecules (b) how many a (yellow) and b (blue) molecules are present at t = 30 s? yellow molecules blue molecules
Answers
K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B
So when after 10 s and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069
The amount of A (the reactants) after N half lives = Ao / 2^n
b) so no.of yellow spheres after 20 s (2 half-lives) = 16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14
The reaction demonstrates exponential decay with a rate constant (\(K\)) of approximately 0.069. After 20 seconds, 4 yellow spheres remain, and after 30 seconds, only 2 yellow spheres persist.
In this scenario, the rate constant (K) for the reaction is determined by using the formula [tex]\(K = \frac{\log 2}{t_{1/2}}\),[/tex] where [tex]\(t_{1/2}\)[/tex] represents the half-life of the reaction. The experiment involves two jars labeled at different times (t = 0 and t = 10\, containing yellow spheres (representing reactants A) and blue spheres (representing products B).
Given that, after 10 seconds, the number of yellow spheres decreases from 16 to 8, indicating one half-life [tex](\(t_{1/2} = 10[/tex] seconds), K is calculated as [tex]\(K = \frac{\log 2}{10} \approx 0.069\).[/tex]
a) **Calculation of \(K\):**
[tex]\[ K = \frac{\log 2}{10} = 0.069 \][/tex]
b) **After 20 seconds (2 half-lives):**
[tex]\[ \text{Yellow spheres} = \frac{16}{2^2} = 4, \quad \text{Blue spheres} = 16 - 4 = 12 \][/tex]
c) **After 30 seconds (3 half-lives):**
[tex]\[ \text{Yellow spheres} = \frac{16}{2^3} = 2, \quad \text{Blue spheres} = 16 - 2 = 14 \][/tex]
The trend indicates that, with time, the yellow spheres (representing reactants) exhibit exponential decay, while the blue spheres (representing products) increase correspondingly.
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Why is butyl iodide preferred over butyl chloride in a williamson ether synthesis?
Answers
Also, Williamson synthesis is carried out at relatively high temperatures, around 50ºC-100º C. Ethyl iodide has a boiling point of 72.2ºC, so it will be in the liquid phase. Ethyl chloride has a boiling point of 12.3ºC so it will be in the gaseous phase, which is undesirable for this.
Final answer:
Butyl iodide is used in Williamson ether synthesis due to iodide ion being a better leaving group than chloride, facilitating the formation of ethers more selectively and efficiently.
Explanation:
Butyl iodide is preferred over butyl chloride in a Williamson ether synthesis because of its ease in undergoing nucleophilic substitution due to the Iodide ion (I-) being a better leaving group than the Chloride ion (Cl-).
The Iodide ion is larger and more polarizable compared to chloride, which means the carbon-iodine bond can be more easily broken during the reaction, facilitating the formation of the ether product.
Additionally, iodide is a weaker base than chloride, which reduces the chance of side reactions such as elimination, leading to a more selective and efficient ether synthesis.
What bonds to cytosine (C) in DNA.
Answers
Which of the following correctly describes voltage difference?
Answers
The best description of voltage is: Difference in potential energy per unit charge when measured between two points.
The correct answer is option C.
Voltage, often referred to as electric potential difference or electric potential, is a fundamental concept in electricity and represents the electric potential energy per unit charge between two points in an electric field. It is typically measured in volts (V).
Here's an explanation of why the other options are not accurate:
a. Amount of charge stored by a battery: Voltage is related to the potential energy difference, not the amount of charge stored.
b. Amount of power stored by a battery: Voltage is not a measure of power; it's a measure of electric potential.
d. Amount of potential energy at a given location: This option is somewhat close but lacks the specific reference to the difference in potential energy between two points, which is essential for voltage.
e. Difference in charge between two points: Voltage is not a measure of the difference in charge but rather the difference in potential energy per unit charge.
In summary, voltage is a measure of the potential energy difference per unit charge between two points in an electric field. It is crucial for understanding how electrical circuits work and plays a fundamental role in electricity and electronics making option C the correct answer.
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The question probable may be:
Which of the following best describes voltage?
a. Amount of charge stored by a battery
b. Amount of power stored by a battery
c. Difference in potential energy per unit charge when measured between two points
d. Amount of potential energy at a given location
e. Difference in charge between two points