The correct answer is D. 1.13 x 10^22 atoms are present in 0.378 g of neon. Avogadro's number (6.022 x 10^23) gives the ratio of representative particles per mole of substance. For every mole of substance, there are 6.022 x 10^23 representative particles present. Since 0.378 g of neon is less than one mole of neon, the answer should be less than Avogadro's number, which makes option D a logical answer.
Further Explanation:
To get the number of atoms present in 0.378 g of neon the following steps must be done:
Convert the mass of neon into moles.Use Avogadro's number to get the number of atoms present in the given moles of neon.STEP 1: Convert 0.378 g of Neon to moles of Neon
[tex]moles \ of \ neon \ = 0.378 \ g \ Ne (\frac{1 \ mol \ Ne}{20.1797 \ g \ Ne})\\\\\boxed {moles \ of \ Ne \ = 0.018732 \ mol}[/tex]
STEP 2: Use Avogadro's number to calculate the number of atoms of Ne
[tex]no. \ of \ atoms \ Ne \ = 0.018732 \ mol \ Ne \ (\frac{6.022 \ x \ 10^{23} \ Ne \ atoms}{1 \ mol \ Ne})\\\\ no. \ of \ atoms \ Ne \ = 1.128 \ x \ 10^{22} \ atoms[/tex]
Since the given, 0.378 g has 3 significant figures, the final answer must also have 3 significant figures. Therefore,
[tex]\boxed {no. \ of \ atoms \ Ne \ = 1.13 \ x \ 10^{22} \ atoms}[/tex]
A. 6.02 x 10^23 atoms is FALSE because the given amount of neon is less than one mole. Hence, the number of atoms cannot be equal to Avogadro's number.
B. 1.187 x 10^-2 atoms is FALSE because atoms are very very small particles. It will require a large number of atoms to make up something that is measurable like a 0.378 g sample of neon. Having less than 1 atom to make up this much sample is not logical.
C. 2.28 x 10^23 atoms is FALSE because this much atoms make up 0.3781 mol of Neon but the given is 0.378 grams not moles of Ne.
D. 1.13 x 10^22 atoms is TRUE because the value is less than 6.022 x 10^23 which is logical since the sample is less than 1 mole.
Learn More
Learn more about Avogadro's Number https://brainly.com/question/12972204Learn more about mole conversion https://brainly.com/question/12979299?source=aid8145232Learn more about Inert Gases https://brainly.com/question/7581131?source=aid8145177Keywords: Avogadro's Number, Mole Conversion, Atoms
Final answer:
To find the number of atoms of neon in 0.378g, we divide the mass by the atomic mass of neon to find the number of moles, then multiply by Avogadro's number. The result is approximately 1.13 × 10²² atoms. So the correct answer is option d.
Explanation:
To determine how many atoms of neon are in 0.378g of neon, first, we need to use Avogadro's number, which is 6.022 × 10²³ atoms per mole. This number helps us to convert between the number of atoms and the number of moles. Neon has an atomic mass of approximately 20.18 g/mol. Therefore, we can calculate the number of moles of neon in 0.378g by using the formula:
moles of Neon = mass (g) / atomic mass (g/mol)
moles of Neon = 0.378g / 20.18g/mol
moles of Neon = 0.0187286 mol
Now, we convert this number into atoms using Avogadro's number:
number of atoms = moles of Neon × Avogadro's number
number of atoms = 0.0187286 mol × 6.022 × 10²³ atoms/mol
number of atoms ≈ 1.13 × 10²² atoms
So the answer is (d) 1.13 × 10²² atoms of neon in 0.378g of neon.
Study the image
Which type of clouds are shown?
cirrocumulus
cumulonimbus
cumulus
stratus
Answer:
The correct answer is Cirrocumulus.
Explanation:
Cirrocumulus : Clouds forming broken layer of small fleecy clouds at higher altitudes.
Cumulonimbus : Clouds forming a towering mass with flat base with flat base at lower altitude
Cumulus : Cloud forming rounded masses heaped or stacked on each other above a flat base , fairly at lower altitudes.
Stratus : Clouds forming continuous horizontal gray sheet, usually during rain or snow.
The given image corresponds to description given as Cirrocumulus.
Answer: A
Explanation:
Based on the image, which color will refract the most when passing through a prism?
orange
yellow
green
Answer:
green
Explanation:
Answer:
The answer is Green
Explanation:
I've just answered this on usatestprep.
which containe the most moles: water, aluminum, salt, baking soda
Moles are the number of particles in a given weight. So unless you state the amount of water, aluminum, salt, and baking soda no one can not consider which contain the most moles.
How does the concentration of reactants affect the rate of a reaction
Answer:
B
Explanation:
If the concentration is increased, there are more particles to collide with each other, increasing the rate of the reaction.
The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.
What rate of reaction?The reaction rate refers to how quickly the concentration of such a particular reactant as well as product changes during a chemical reaction.
What is concentration?The abundance of an ingredient divided by the volume of a combination is called concentration. Mass concentration, molar concentration, number concentration, as well as volume concentration are all examples of mathematical descriptions.
The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.
Therefore, the correct answer will be option B
To know more about rate of reaction.
https://brainly.com/question/8592296
#SPJ2
A chemical factory is making soda ash (NA2CO3) from sodium bicarbonate. The production manager calculates they will make 80 tons of soda ash in the next 8 hour shift. At the end of the shift they weigh the produced soda ash at 74.3 tons. What was their percent yield?
Answer:
[tex]\boxed{\text{ 93 \%}}[/tex]
Explanation:
[tex]\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}[/tex]
Data:
[tex]\begin{array}{rcr}\text{Actual yield} & = & \text{74.3 T}\\\text{Theoretical yield} & = & \text{80 T}\\\end{array}[/tex]
Calculation:
[tex]\text{\% yield} = \dfrac{\text{74.3 T}}{\text {80 T}} \times\text{100 \%} = \textbf{93 \%}}\\\\\text{The percent yield was } \boxed{\textbf{93 \%}}[/tex]
HELPPP ME WITH SICENCE PLZZZZZZ
The group of symbols and numbers that shows the types and numbers of atoms that make up a compound is a _________________.
Answer:
molecules
Explanation:
molecules because the summer like atoms and Sciences sciency to be honest
6. How to calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes?
Answer:
Approximately 0.074 grams.
Explanation:
Look up the relative atomic mass of copper on a modern periodic table: [tex]\rm 63.546[/tex]. Look up the Faraday's Constant: [tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex]. This constant gives the amount of electrical charge on each mole of electrons.How does the electroplating works for copper? Copper exists as copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] in the copper(II) nitrate [tex]\rm Cu{(NO_3)}_2[/tex] solution. It takes two moles of electrons to reduce one mole of copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] to metallic copper [tex]\rm Cu[/tex].
[tex]\rm Cu^{2+}\;(aq) + 2\;e^{-} \to Cu\;(s)[/tex]. (Reduction half of the ionic equation.)
What are the steps for finding the mass of copper that has been deposited.Start by finding the charge on the electrons that have been supplied to this electrochemical cell. After that,
Find the number of moles of electrons that have been supplied based on the charge supplied; Find the number of moles of copper that have been reduced based on the number of moles of electrons supplied; andFind the mass of copper based on the number of moles of copper atoms reduced.What's the charge [tex]Q[/tex] on the electrons supplied to this electrochemical cell?For a constant direct current [tex]I[/tex], the charge [tex]Q[/tex] that has been delivered in time [tex]t[/tex] is equal to
[tex]Q = I \cdot t[/tex].
In case
[tex]I[/tex] is in Amperes [tex]\mathrm{A}[/tex] and[tex]t[/tex] is in seconds [tex]\mathrm{s}[/tex],[tex]Q[/tex] will be in Coulombs [tex]\mathrm{C}[/tex] (which is the same as [tex]\mathrm{A\cdot s}[/tex].)
For this electrochemical cell,
[tex]Q = I\cdot t = \rm 0.75\;A \times 300\;s = 225\;C[/tex].
How many moles of electrons were supplied to this electrochemical cell?The Faraday's Constant gives the size of charge (in Coulombs) on one mole of electrons.
[tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex].
[tex]\displaystyle n(\mathrm{e^{-}}) = \frac{Q}{F} = \rm \frac{225\;C}{96485.33212\;C\cdot mol^{-1}}\approx 0.00233196\;mol[/tex].
How many moles of copper atoms have been deposited?Assume that copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] are in excess. Refer to the reduction half-equation, it takes two moles of electrons to deposit one mole of metallic copper.
[tex]\displaystyle \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \frac{1}{2}[/tex].
[tex]n(\mathrm{e^{-}})=\rm 0.00233196\;mol[/tex]. As a result,
[tex]\displaystyle n(\mathrm{Cu}) = n(\mathrm{e^{-}})\cdot \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \rm 0.00233196\;mol\times \frac{1}{2} = 0.00116598\; mol[/tex].
What's the mass of that many copper atoms?The Relative atomic mass of copper is [tex]63.546[/tex].
[tex]\begin{aligned}m(\mathrm{Cu})& = n(\mathrm{Cu}) \cdot M(\mathrm{Cu})\\& = \rm 0.00116598\; mol\times 63.546\; g\cdot mol^{-1}\\&\rm \approx 0.074\;g\end{aligned}[/tex].
Final answer:
The mass of copper that can be plated from a 1.0 M Cu(NO3)2 solution using 0.75 A for 5 minutes is calculated by converting the charge passed to moles of electrons, determining the moles of copper, and then converting it to mass, resulting in approximately 0.0740 grams.
Explanation:
To calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes, we apply Faraday's laws of electrolysis and use the molar mass of copper.
Firstly, calculate the total charge passed through the solution using the formula Q = It, where Q is the charge in Coulombs, I is the current in Amperes, and t is the time in seconds. For 0.75 A over 5.0 minutes (or 300 seconds), we obtain Q = (0.75 A) × (300 s) = 225 Coulombs.
Next, convert the charge to moles of electrons using the charge of one mole of electrons, known as Faraday's constant (approximately 96485 C/mol). Thus, moles of electrons = 225 C / 96485 C/mol ≈ 0.00233 mol.
Since the copper plating involves Cu2+ ions gaining two electrons to become copper atoms (Cu2+ + 2e− → Cu), the moles of copper plated will be half the moles of electrons. So, 0.00233 mol / 2 = 0.001165 mol of copper.
Finally, calculate the mass of copper by multiplying the moles of copper by its molar mass (63.55 g/mol for Cu). Thus, mass of copper = 0.001165 mol × 63.55 g/mol ≈ 0.0740 g.
Therefore, the mass of copper that can be plated out using these conditions is approximately 0.0740 grams.
What amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4.18 J/g°C.
Answer:
Explanation:
Heat = m*c * deltat
m = 20 grams
c = 4.19 J/g*C
deltaT = 30 - 10 = 20
Heat = 20 * 4.19 * 20
Heat = 1676 joules or 1.7 kJ depending on what you need.
Answer:
The correct answer for plato/edmentum is C). 1700 joules
what type of bond is SF6
Sulfur hexafluoride or SF6 is an inorganic, greenhouse gas. It is non-flammable, odorless, and colorless, and is an excellent insulator. It is a hypervalent octahedral molecule that has been an interesting topic of conversation among chemistry enthusiasts.
Hope this helps:)
SF₆ has six covalent bonds created by sp³ d² hybridization of the sulfur atom, forming a symmetrical octahedral structure with low reactivity.
The type of bond in SF₆ (sulfur hexafluoride) is a covalent bond. Specifically, the sulfur atom undergoes sp³ d² hybridization, allowing it to form six equivalent bonding pairs with the fluorine atoms. These bonds exhibit both sigma (σ) and pi (π) characteristics, as the S-F bond length is short, which is consistent with π-bonding in addition to σ-bonding.
This indicates that there are no lone pairs of electrons on the sulfur atom. The geometry displayed by SF₆ is highly symmetrical, forming an octahedron where all bond lengths and angles are identical, making it a nonpolar molecule with high symmetry and low reactivity. SF₆ is resistant to chemical attack and exhibits inert characteristics, which makes it useful in applications such as a spark suppressor.
What is an electrochemical cell?
A. Two electrodes separated by an electrolyte that can generate an electrical current.
B. A chemical that, when an electrical current is passed through it, releases a large amount of energy.
C. A biological cell, such as a bacterium, that can generate an electrical current.
D. An electrical circuit formed from chemicals in a solid state rather than metals or metalloids.
A. Two electrodes separated by an electrolyte that can generate an electrical current.
Answer:
Two electrodes separated by an electrolyte that can generate an electrical current.
Explanation:
Answer via Educere/ Founder's Education
which one of the following ions would be negatively charged with a charge of -2?
10 electrons, 8 protons
18 electrons, 16 neutrons
0 electrons, 2 protons
6 electrons, 8 protons
Answer:
10 electrons 8 protons
Explanation:
p +8 - e10- equals -2
Metallic sodium reacts vigorously with liquid bromine in the following reaction:
if 1 kg of Na is brought into contact with 3 kg of liquid bromine. Presuming that the reaction is quantitative and proceeds to completion, determine the limiting reagent and the quantity of NaBr formed. Determine the amount of excess reagent remaining after the reaction is complete.
First we look at the chemical reaction:
2 Na + Br₂ → 2 NaBr
number of moles = mass / molecular weight
mass = number of moles × molecular weight
number of moles of Na = 1000 / 23 = 43.48 moles
number of moles of Br₂ = 3000 / 160 = 18.75 moles
from the reaction:
if 2 moles of Na are reacting with 1 mole of Br₂
then X moles of Na are reacting with 18.75 moles of Br₂
X = (18.75 × 2) / 1 = 37.5 moles of Na
The limiting reactant is bromine Br₂.
After the reaction is complete you remain with Na as excess reagent.
moles of Na = 43.48 - 37.5 = 5.98 moles
mass of Na = 5.98 × 23 = 137.54 g
if reacting 1 mole of Br₂ produces 2 moles of NaBr
then reacting 18.75 moles of Br₂ produces Y moles of NaBr
Y = (18.75 × 2) / 1 = 37.5 moles of NaBr
mass of NaBr = 37.5 × 103 = 3862.5 g
Answer:
Explanation:
Given parameters:
Mass of Na = 1kg = 1000g
Mass of Br = 3kg = 3000g
Unkown:
Limiting reagent =?
Amount of excess reagent = ?
Quantity of NaBr formed = ?
Solution
The reaction equation can be expressed as:
2Na + Br₂ → 2NaBr
To find the limiting reagent
The limiting reagent is the reagent that is in short supply and it determines the amount of products that can be formed in the reaction.
To find the limiting the reagent, we establish a mole relationship between the reactants. We then check their stoichoimetric expression to see the one in excess and the limiting reagent.
Number of moles of Na = [tex]\frac{mass of Na}{molar mass of Na}[/tex]
molar mass is expressed as g/mol and the Na should also be in grams
Number of moles = [tex]\frac{1000}{23}[/tex] = 43.48mol
Number of moles of Br₂ = [tex]\frac{mass}{molar mass}[/tex]
Number of moles = [tex]\frac{3000}{2x80}[/tex] = 18.75mol
From the balanced reaction equation:
2 mole of Na combines with 1 mole of Br₂
43.48mole of Na would require 43.48/2 mole = 21.74mole of Br₂ to react with.
But the given amount of Br we have is 18.75mole.
Therefore, the reagent in short supply is Bromine. It is the limiting reagent
Quantity of NaBr formed
To find the quantity of NaBr formed, we use the known reagent which is the limiting one to determine its number of moles and eventually the mass. The limiting reagent determines the extent of the reaction.
From the stoichiometric equation:
1 mole of Br₂ will produce 2 mole of NaBr
19.23 mole Br₂ would now yield (18.75 x2)= 37.5mole of NaBr
Mass of NaBr = number of moles of NaBr x molar mass of NaBr
Molar mass of NaBr = 23 + 80 = 103g/mol
Mass of NaBr = 37.5 x 103 = 3862.5g = 3.86Kg
Amount of excess reagent remaining after the complete reaction:
The amount of excess reagent would be derived from the reagent that occurs in excess which is Na:
1 mole of Br₂ reacts with 2 moles of Na
18.75mole of Br₂ will require 2x 18.75 = 37.5mole of Na
Excess mole of Na = (43.48 - 37.5)mole = 5.98mole
Mass of excess Na = number of moles of excess Na x molar mass of Na
Mass of excess Na = 5.98 x 23
Mass of excess Na = 137.54g or 0.14g
Write the equation sulfur dioxide reacts with oxygen to form sulfur trioxide.
Answer:
2SO2 + 02 ====>2SO3
Explanation:
SO2 + O2 ===> SO3
The only thing you can do is balance the oxygens that are on the sulfurs. When you do that the oxygen (O2) can make the difference.
SO2 + O2 ===> 2SO3
Bring the oxygen on the right up to 6. When you do that, the sulfurs are out of balance. So balance the sulfurs.
2SO2 + 02 ====>2SO3
Your equation is now balanced. The trick is not to leave the number of oxygens on the right as an odd number. When you fix that problem, the equation will balance easily.
Species S O
Left 2 2+4=6
Right 2 2*3 =6
Balanced.
What happens when a gas becomes ionized?
A. Deposition Occurs
B. Sublimation Occurs
C. It becomes a liquid
D. A plasma is formed
Answer:
A. Deposition Occurs
Explanation:
When a gas becomes ionized, deposition occurs.
Answer: Option (D) is the correct answer.
Explanation:
A plasma is defined as the state of matter in which gas exists in hot ionized formed that has similar number of positively charged ions and negatively charged electrons.
Whereas deposition is the change from gaseous to liquid or solid state in which particles come closer to each other.
Sublimation means direct conversion of solid into gaseous phase without undergoing liquid phase.
Thus, we can conclude that when a gas becomes ionized then a plasma is formed.
3.4000*10^-6 + 5.7000*10^-3
Answer:
0.0057034 or 5.7034 * 10^-3
Baking soda is mixed with water, and no bubbles are produced. When baking soda is mixed with vinegar, it bubbles and foams rapidly.
What chemical property of baking soda is shown in this scenario?
flammability
color change
reactivity
boiling point
Answer:
Reactivity
Explanation:
The scenario shows that baking soda is reactive enough to produce bubbles with vinegar but not enough to do so in pure water.
Flammability, color change, and boiling point are all wrong. The scenario says nothing about these properties.
Answer:
Reactivity (Znk Elite Answerer is right)
Explanation:
I just took a test and I got it right. Even if the question says select all that apply there is only 1 answer and it is reactivity
A gas is most likely to exist at which of the following conditions?
A) High temperatures and high pressures
B) High temperatures and low pressures
C) Low temperatures and high pressures
D) Low temperatures and low pressures
Answer:
B. High temp and low pressure
Explanation:
I got an A on my chem final :) Got this right.
Answer:
A gas is most likely to exist at B) High temperatures and low pressures
Explanation:
Ideal gas behaviour is likely to be at high temperature and low pressure .
The causes of deviations from ideal behaviour may be due to the following two assumptions of kinetic theory of gases.
The volume occupied by gas molecules is negligibly small as compared to the volume occupied by the gas.
The forces of attraction between gas molecules are negligible.
Deviation occur for real gases with a minor difference from that of an Ideal gas.
When real gases are at low pressures and high temperatures they behave close enough to ideal gases
Determine the freezing point of a 0.51 molal
solution of benzoic acid in chloroform. Chloroform
has a freezing point of -63.5°C and a freezing
point depression constant of 4.70°C.kg/mol.
What is the freezing point of this solution?
°C
Answer:
-65.897°C.
Explanation:
Adding solute to water causes depression of the boiling point.The depression in freezing point (ΔTf) can be calculated using the relation: ΔTf = Kf.m,where, ΔTf is the depression in freezing point of chloroform solution.
Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).
m is the molality of the solution (m = 0.51 m).
∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.
∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.
Answer:
-65.9 and 100.9
Explanation:
Hope this helps
100 g of 20% salt solution is mixed with 200g of 10% salt solution. Find out the concentration of the resulting solution.
Explanation:
The total mass is:
100 g + 200 g
= 300 g
The mass of salt is:
0.20 (100 g) + 0.10 (200 g)
= 20 g + 20 g
= 40 g
So the concentration is:
40 g / 300 g
≈ 13.33%
Round as needed.
Imagine if during the cathode ray experiment, the size of the particles of the ray was the same as the size of the atom forming the cathode. Which other model or scientific observation would have also been supported?
This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.
This would support Bohr's prediction about electrons moving in orbits having specific energy.
This would support Bohr's prediction about electrons being randomly scattered around the nucleus in the atom.
This would support Dalton's postulates that proposed that atoms combine in fixed whole number ratios to form compounds.
Answer:
This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.
Explanation:
Experiment using the gas discharge tube by J.J Thomson led to the discovery of cathode rays which are now known as electrons.
Primarily, Thomson's experiment led to the discovery of cathode rays, electrons, as subatomic particles.
If the size of the atoms observed at the cathode is the same as that of the rays,we can conclude that the particles of the rays are the simplest form of matter we can have. This would suggest that the atom is indeed the smallest indivisible particle of a matter according to Dalton.
Answer:
This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.
Explanation:
Dalton proposed that all matter is made up of atoms. Atoms are indivisible. But Thompson’s cathode ray experiment proved that the cathode rays are made up of negatively charged particles which were deflected by both electric and magnetic field. This caused Thompson to propose the Plum and Pudding model of the atom.
Which polygon is a base of the triangular prism?
Answer:
a triangle
Explanation:
the name "triangular prism" has triangle in it, just like "rectangular prism" which has a rectangle as a base
Answer:
It’s actually DFG
Explanation:
DFBA
all arenius acid are also bronsted lowry but all arrhenius base are not bronsted lowry base.
Answer:
False
Explanation:
All Arrhenius acids and bases are also Bronsted-Lowry acids and bases.
An Arrhenius base is a compound that dissociates to form hydroxide ions in water.
NaOH(s) → Na^+(aq) +OH^-(aq)
A Bronsted-Lowry base is a proton acceptor.
NaOH is a Bronsted-Lowry base because the hydroxide on can accept a proton from HCl to form water.
Thus, all Arrhenius bases are Bronsted-Lowry bases.
Lemonade is an example of a compound because the particles retain their original chemical properties and identity.
true or false
Answer:
False
Explanation:
Compounds are chemically combined
lemonade is not
If the squeezed lemonade is made by squeezing lemons to extract the juice and mixing it with water and sugar, it would be a homogenous mixture.
If it contains a pulp than it would be heterogeneous
Round off the measurement to three significant figures 12.17º C
The temperature 12.17º C rounded to three significant figures is 12.2º C, taking into account the fourth figure which is a 7. This causes an upward rounding due to the rule of significant figures.
To round off the temperature of 12.17º C to three significant figures, we look at the fourth figure which is a 7. Since 7 is greater than 5, we round the third significant figure up, which results in a rounded temperature of 12.2º C.
In the context of rounding based on significant figures, the temperature value is often dependent on the least precise measurement in a data set or calculation. As an example, if we had another measurement of 13.7 kg, which is to the 0.1 decimal place, any resultant calculation would need to be rounded to the tenths place for consistency, giving us a hypothetical final answer of 15.2 kg, to match the precision of 13.7 kg.
What are the only things that can change in a valid experiment?
An sample of water with a mass of 123.00 kg is heated from 25 C to 97 C. If the specific heat of water is 1 J-1 kg K-1 then how much energy is required?
Answer:
8856joules
Explanation:
Energy= MC. ©
energy = 123.00*1*(97-25)
energy =8856joules//
Answer: The amount of energy required will be 8856 Joules.
Explanation:
To calculate the amount of heat absorbed, we use the equation:
[tex]Q=mc\Delta T[/tex]
where,
Q = heat absorbed or released
m = Mass of the substance = 123 kg
c = specific heat capacity of water = [tex]1J/kg.K[/tex]
[tex]\Delta T[/tex] = change in temperature = [tex](97-25)^oC=72^oC=72K[/tex] (change remains the same)
Putting values in above equation, we get:
[tex]Q=123kg\times 1J/kg.K\times 72K\\\\Q=8856J[/tex]
Hence, the amount of energy required will be 8856 Joules.
Water has a slight negative charge around its oxygen atom, and a slight positive charge around its hydrogen atoms Which type of solvent is water?
A) Saturated
B) no polar
C) polar
D) unsaturated
Answer:
Polar
Explanation:
water is a polar solvent since they can ionize into positive (H+) and negative ions (OH-). they can dissociate into negatively and positively charged poles
Which equation is used to help form the combined gas law?
Answer:
The ideal gas equation
Explanation:
The ideal gas equation is derived from the combination of three gas laws:
Boyle's lawCharles's law Avogadro's law.The ideal gas law is expressed mathematically as: PV=nRT where:
P is pressure
V is volume
n is the number of moles
R is the ideal gas law
T is temperature.
To obtain the combined gas law, we assume that n=1 and this gives:
[tex]\frac{PV}{T}[/tex] = R
Therefore:
[tex]\frac{P_{1} V_{1} }{T_{1} }[/tex] = [tex]\frac{P_{2} V_{2} }{T_{2} }[/tex]
where are the first repost of new scientific discoveries published A.) Internet Sites B.) Magazines C.) encyclopedias D.) Scientific journals
Answer:
D
Explanation:
Most if not all fields of research will post their results for others to test and find data to make sure their experiment is theoretically correct.
Scientific journals are the first repost of new scientific discoveries published. Hence, option D is correct.
What is Scientific journals?Scientific papers are also called journal articles, A scientific journal is the best medium for disseminating and popularizing scientific information in the form of accomplishments, discoveries, and research findings.
In order to publish this kind of work, they are typically published in a periodical called a journal.
Thus, option D is correct.
For more details about Scientific journals, click here:
https://brainly.com/question/17587049
#SPJ2
Which of the following equations is balanced correctly and has the correct products for the reactants RbNO3 and BeF2?
3RbNO3 + 3BeF2 → Be(NO3)3 + 3RbF, because Be increases in charge from 2+ to 3+ when it is replaced
2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be keeps a 2+ charge throughout the reaction
RbNO3 + BeF2 → BeNO3 + RbF2, because Be keeps a 1+ charge throughout the reaction
2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be increases in charge from 1+ to 2+ when it is replaced
Answer:
2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction
Explanation:
2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction
Rb is a +1 cation, NO3 is a -1 anion, Be is a +2 cation and F is a -1 anion.
In writing an ionic compound the charge of the cation becomes the subscript of the anion and the charge of the anion becomes the subscript of the cation.
So the ionic compound formed between Be2+ and F- is BeF2. The ionic compound formed between Be2+ and NO3- is Be(NO₃)₂.
As there are two NO₃ on the product side it is balanced by writing a 2 coefficient before RbNO₃ on the reactant side.
And as there are two F on the reactant side it is balanced by writing a 2 coefficient before RbF on the product side.
Answer:
2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be keeps a 2+ charge throughout the reaction