Valence electrons are: O a. Electrons that have been lost in an atom O b. Electrons in the nucleus of an atom O c. electrons in the outer-most shell of an atom O d. electrons in the inner-most shell of an atom

Answer : The correct option is, (C) NH₃ + H⁺

Explanation:

Hydrolysis : It is defined as the chemical reaction in which the breakdown of compound takes place due to reaction with water.

As per question:

First ammonium chloride completely dissociates into ion.

[tex]NH_4Cl(aq)\rightarrow NH_4^+(aq)+Cl^-(aq)[/tex]

Now ammonium ion react with water to give ammonia and hydronium or hydrogen ion.

The balanced hydrolysis reaction will be:

[tex]NH_4^++H_2O\rightarrow NH_3+H_3O^+[/tex]

Hence, the correct option is, (C) NH₃ + H⁺

Final answer:

The correct response to the products of hydrolysis of NH4Cl is  'NH3 + H+', because, during hydrolysis, NH4Cl separates into NH4+ and Cl- ions, with NH4+ reacting with water to form ammonia (NH3) and hydronium ions (H3O+). So the correct option is  C.

Explanation:

The question asks which response gives the products of hydrolysis of NH4Cl. During hydrolysis, water is involved in breaking down a compound. In the case of NH4Cl, when it is dissolved in water, it separates into NH4+ ions and Cl− ions. The Chloride ion (Cl−) does not hydrolyze as it's the conjugate base of a strong acid (HCl) and has no significant basicity. On the other hand, the Ammonium ion (NH4+) is the conjugate acid of a weak base (NH3), and it will hydrolyze in water. The NH4+ accepts a hydroxide ion (OH−) from water, forming NH3 and H3O+ (hydronium ion). Therefore, the hydrolysis of NH4Cl will result in ammonia (NH3) and hydronium ions (H3O+).

Option C is the correct response: NH3 + H+. When NH4Cl hydrolyzes, it forms ammonia (NH3) and hydronium ions (H3O+), not hydrochloric acid (HCl). The correct formula of the products reflects the ammonia and hydronium ions formed.

Answer:

The density of carbon dioxide is 1,86 g/L

Explanation:

The global reaction is:

2 HCl (aq)+ CaCO₃ (s) → CaCl₂(aq)+ H₂O(l)+ CO₂(g)

To obtain density it is necessary to obtain calcium carbonate moles -with molar mass of CaCo₃ = 100,09 g/mol- that are the same than CO₂ moles. Then, this moles must be converted to grams -CO₂ weights 44,01 g/mol- and, with the given liters (225 L) will be possible to know density, thus:

1004,0g × 95,0% = 953,8 g of CaCO₃

953,8 g of CaCO₃ ×[tex]\frac{1 mol}{100,09 g}[/tex] =

9,53 CaCO₃ moles ≡ CO₂ moles

9,53 CO₂ moles ×[tex]\frac{44,01 g}{1 mol}[/tex] = 419,4 g of CO₂

Thus, density of Carbon dioxide is:

[tex]\frac{419,4 g}{225 L}[/tex] = 1,86 g/L

I hope it helps!

Final answer:

To find the density of carbon dioxide, first calculate the mass of calcium carbonate used. Next, use the molar mass of CaCO3 to calculate the number of moles. Finally, calculate the density of CO2 using the mass and volume.

Explanation:

To find the density of carbon dioxide, we need to calculate the mass of carbon dioxide produced. From the given information, we know that a 1004.0g sample of calcium carbonate that is 95.0% pure gives 2.25L of CO2 at STP when reacted with an excess of hydrochloric acid. First, we calculate the mass of calcium carbonate used:

Mass of CaCO3 = 1004.0g * 0.95 = 954.8g

Next, we use the molar mass of CaCO3 (100.09 g/mol) to calculate the number of moles:

Moles of CaCO3 = 954.8g / 100.09 g/mol = 9.537 mol

According to the balanced chemical equation:

CaCO3 + 2HCl -> CaCl2 + CO2 + H2O

1 mole of CaCO3 produces 1 mole of CO2. Therefore, the number of moles of CO2 produced is also 9.537 mol.

Finally, we can calculate the density of CO2:

Density = Mass / Volume

Density = 9.537 mol * 44.01 g/mol / 2.25 L = 188.70 g/L

Explanation:

White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.

The chemical reaction is given as:

[tex]AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)[/tex]

When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.

Final answer:

The chemical equation for the dissolution of AgCl precipitate with the addition of ammonia is [tex]AgCl(s) + 2NH_3(aq) < = > Ag(NH_3)_2+(aq) + Cl-(aq).[/tex] Ammonia interacts with [tex]Ag^+[/tex] to form a complex ion, increasing the solubility of AgCl significantly.

Explanation:

The dissolution of AgCl precipitate upon the addition of NH3(aq) is described by the following chemical equation:

[tex]AgCl(s) + 2NH_3(aq) \ < = > Ag(NH_3)_2+(aq) + Cl−(aq)[/tex]

When ammonia (NH3) is added to a solution containing AgCl, it reacts with the [tex]Ag^+[/tex] ions to form the complex ion [tex]Ag(NH_3)_2^+[/tex]. This acts to decrease the concentration of [tex]Ag^+[/tex] ions in solution. According to Le Chatelier's principle, the solubility of AgCl will increase to re-establish equilibrium, which leads to the dissolution of the AgCl precipitate.

The net effect of adding ammonia is a significant increase in the solubility of AgCl, as indicated by a change in the equilibrium constant from 1.8 x [tex]10^-10[/tex] in pure water to 3.0 x [tex]10^3[/tex] in the presence of dissolved ammonia.

Answer:

4 × 10⁶ sec

Explanation:

The distance between the earth and the moon = 384,400 km

The speed of the peregrine falcon = 350 km/hr

Considering,

Distance = Speed × Time

So,

Time = Distance / Speed = 384,400 km / 350 km/hr = 1098.28571 hrs

Also,

1 hr = 3600 sec

So,

1098.28571 hrs = 3600 × 1098.28571 s ≅ 4 × 10⁶ sec

Thus time taken by peregrine falcon if falcon fly to the moon = 4 × 10⁶ sec

It would take the peregrine falcon approximately 3,953,044 seconds to fly to the moon at a speed of 350 km/hr.

If the peregrine falcon can travel up to 350 km/hr in a dive, let's calculate how long it would take for the falcon to fly to the moon at this speed. The average distance from Earth to the moon is approximately 384,400 km.

To find the time it would take, we can use the formula:

Time = Distance/Speed

So, Time = 384,400 km / 350 km/hr = 1098.29 hours.

Converting hours to seconds, we have:

Time = 1098.29 hours x 60 minutes x 60 seconds = 3,953,044 seconds.

Therefore, it would take the peregrine falcon approximately 3,953,044 seconds to fly to the moon at a speed of 350 km/hr.

Answer:

On the basis of ownership, distribution, durabilities.

Explanation:

Answer:

pH = 2.56

Explanation:

The Henderson-Hasselbalch equation relates the pH to the Ka and ratio of the conjugate acid-base pair as follows:

pH = pKa + log([A⁻]/[HA]) = -log(Ka) + log([A⁻]/[HA])

Substituting in the value gives:

pH = -log(1.77 x 10⁻⁴) + log((0.0065M) / (0.10M))

pH = 2.56

The pH of a 0.10 M formic acid and 0.0065 M formate solution can be calculated using the Henderson-Hasselbalch equation and a given Ka for formic acid of 1.77 x 10-4. The resulting pH is approximately 3.04.

In order to find the pH of a solution consisting of a weak acid (formic acid, HCOOH) and its conjugate base (formate, HCOO-), you'd use the Henderson-Hasselbalch equation, which is pH = pKa + log([A-]/[HA]), where [A-] is the molarity of the conjugate base (here, formate, 0.0065 M) and [HA] is the molarity of the weak acid (here, formic acid, 0.10 M). The pKa is found by taking the negative logarithm of the Ka value, so pKa = -log(Ka) = -log(1.77 x 10-4) = 3.75.

Using these values in the Henderson-Hasselbalch equation: pH = 3.75 + log(0.0065/0.10) this results in a pH of approximately 3.04

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Answer:

Coal is a traditionally used source of energy, there are main four types of ranks for coal. Here the rank of a coal means to a natural process called Coalification, which takes place during a plant is buried and changes to a harder, and denser material and become even more rich in carbon contents.

Anthracite is know to have the highest ranked coal, it contains highest percent of fixed carbon and lowest percent of volatile material.

Answer:

[tex]1.64x10^-^1^7 J[/tex]

Explanation:

Due to you know the velocity of the electron, the only thing that you need to do is used the Newtonian kinetic energy formula.  The kinetic energy is defined as the work needed by motion body of a given mass to accelerate from rest to its know velocity:

[tex]KE=1/2mv^2=[kg*(m/s)^2]=[J][/tex]

[tex]m_e_- =9.1093835x10^-^3^1 kg [/tex]

[tex]KE=9.11x10^-^3^1 kg*(6.00x10^6 m/s)^2=1.64x10^-^1^7 J[/tex]

Answer:

Explanation:

four carbon atoms ------ atoms ------------nucleus of an atom------------electron

Atoms are the smallest indivisible particle in any substances. But atoms are also made up of other tiny particles which are subatomic in sizes. These particles are protons, neutrons and electrons.

Protons and neutrons are called the nucleons of an atoms. They are massive particles found in the nucleus of an atom. The nucleus is a very small area but very dense.

Electrons are negatively charged subatomic particles. The bulk of the volume of the atom is occupied by electrons orbiting the nucleus.

Together, the electrons and the nucleons makes up the subatomic particles in an atom.

The kinetic energy acquired by the electron in a hydrogen atom when it absorbs a light radiation can be calculated using E = hf, where E is the energy of the radiation and f is the frequency of the radiation.

When an electron in a hydrogen atom absorbs a light radiation, it gains kinetic energy. To calculate the energy gained, we can use the equation E = hf, where E is the energy of the radiation, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of the radiation. In this case, the energy of the radiation is given as 1.08 x 10^-7 J.

Since the electron absorbs the radiation, we know that the energy gained will be equal to the energy of the radiation. Therefore, the kinetic energy acquired by the electron in the hydrogen atom is 1.08 x 10^-7 J.

Explanation:

At low temperatures (below the glass transition temperature) crystalline polymers are rigid like glass. This happens because all the polymer chains are perfectly arranged, all the polymer is in the crystalline form. On the other hand, when the temperature raises, upper the glass transition temperature, some polymer chains start to get loose and form some amorphous regions in between the crystalline regions of the polymer. This condition makes the polymer more flexible.

Answer:

The organism died 35900 years ago

Explanation:

Plug-in all the values in the above equation:

[tex]0.013=(\frac{1}{2})^{\frac{t}{5730years}}[/tex]

So, t = 35900 years

Hence the organism died 35900 years ago

Answer:

Hydrogen bonding

Explanation:

As a rule of thumb, "likes dissolve like", meaning polar solutes dissolve in polar solvents and nonpolar solutes in nonpolar solvents. In this case, water is polar (dipolar moment = 1.85 Debye) dissolves methanol which is also polar (dipolar moment = 1.69 Debye). Besides being dipoles, both molecules have atoms of Hydrogen with a covalent bond to more electronegative atoms of Oxygen. When this happens, stronger dipole-dipole interactions appear known as Hydrogen bonding. There is an electrostatic attraction between H (positive charge density) and O (negative charge density).

Answer :

(a) The rate of reaction is, second order reaction.

(b) The rate of reaction is, zero order reaction.

Explanation :

Rate of reaction : It is defined as the rate of change in concentration of reactant or product with respect to time.

Order of reaction : It is defined as the sum of the exponents or powers to which the molar concentration in the rate law equation are raised to express the observed rate of reaction.

The order of reaction depends on the power of reactant concentration.

(a) The given rate expression is,

[tex]Rate=k[NO_2]^2[/tex]

From this expression we conclude that the power of concentration of reactant [tex]NO_2[/tex] is 2.  

That means it is a second order reaction.

(b) The given rate expression is,

[tex]Rate=k[/tex]

From this expression we conclude that the rate of reaction is equal to rate constant.

That means it is a zero order reaction.

Answer: The [tex]\Delta S^o[/tex] of the reaction is [tex]-579JK^{-1}[/tex]

Explanation:

Entropy change of the reaction is defined as the difference between the total entropy change of the products and the total entropy change of the reactants.

The equation representing entropy change of the reaction follows:

[tex]\Delta S_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}][/tex]

For the given chemical equation:

[tex]4NH_3(g)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(l)[/tex]

We are given:

[tex]\Delta S^o_{NH_3}=192Jmol^{-1}K^{-1}\\\Delta S^o_{O_2}=205.1Jmol^{-1}K^{-1}\\\Delta S^o_{N_2}=192Jmol^{-1}K^{-1}\\\Delta S^o_{H_2O}=70Jmol^{-1}K^{-1}[/tex]

Putting values in above equation, we get:

[tex]\Delta S^o_{rxn}=[(6\times \Delta S^o_{H_2O})+(2\times \Delta S^o_{N_2})]-[(4\times \Delta S^o_{NH_3})+(3\times \Delta S^o_{O_2})][/tex]

[tex]\Delta S^o_{rxn}=[(6\times 70)+(2\times 192)]-[(4\times 192)+(3\times 205.1)]=-579JK^{-1}[/tex]

Hence, the [tex]\Delta S^o[/tex] of the reaction is [tex]-579JK^{-1}[/tex]

Answer : The mass of combustion products formed are 134 lbs.

Explanation :

The balanced chemical reaction will be:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Given :

Mass of [tex]C_3H_8[/tex] = 29 lbs = 13154.2 g

conversion used : 1 lbs = 453.592 g

Molar mass of [tex]C_3H_8[/tex] = 44 g/mole

First we have to calculate the moles of [tex]C_3H_8[/tex].

[tex]\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{13154.2g}{44g/mole}=298.9moles[/tex]

Now we have to calculate the moles of [tex]CO_2[/tex] and [tex]H_2O[/tex].

From the balanced chemical reaction we conclude that,

As, 1 mole of [tex]C_3H_8[/tex] react to give 3 moles of [tex]CO_2[/tex]

So, 298.9 mole of [tex]C_3H_8[/tex] react to give [tex]298.9\times 3=896.7[/tex] moles of [tex]CO_2[/tex]

and,

As, 1 mole of [tex]C_3H_8[/tex] react to give 4 moles of [tex]H_2O[/tex]

So, 298.9 mole of [tex]C_3H_8[/tex] react to give [tex]298.9\times 4=1195.6[/tex] moles of [tex]H_2O[/tex]

Now we have to calculate the mass of [tex]CO_2[/tex] and [tex]H_2O[/tex].

Molar mass of [tex]CO_2[/tex] = 44 g/mole

Molar mass of [tex]H_2O[/tex] = 18 g/mole

[tex]\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass }CO_2[/tex]

[tex]\text{Mass of }CO_2=896.7mole\times 44g/mole=39454.8g=86.98lbs[/tex]

and,

[tex]\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass }H_2O[/tex]

[tex]\text{Mass of }H_2O=1195.6mole\times 18g/mole=21520.8g=47.44lbs[/tex]

The total mass of products = Mass of [tex]CO_2[/tex] + Mass of [tex]H_2O[/tex]

The total mass of products = 86.98 + 47.44 = 134.42 ≈ 134 lbs

Therefore, the mass of combustion products formed are 134 lbs.

Answer:

Their antibody is composed by subunits that have molecular weights of 50 kD and 25 kD, and each of these subunits has one Cys residue at least.

Explanation:

Their antibody is composed by subunits that are conected by an S-S bond that takes place in their Cys residue. When the antibody is treated with a reducing agent, these S-S bond are reduced to S-H, thus the subunits are no longer connected to each other.

The original antibody weights 150 kD, as seen in Lane 1. And the combination of these subunits are seen in Lane 2: this means there is not only one subunit of 50 kD and one of 25 kD. Rather, these subunits are repeated in the antibody, in a way such that their combined weight add ups to 150 kD (for instance 2 subunits of 50 kD and 2 subunits of 25 kD).

Final answer:

Based on SDS-PAGE analysis, investigators can conclude that the antibody under study is a multimeric protein made of polypeptide chains with molecular weights of 50 kD and 25 kD, held together by disulfide bonds that were reduced by mercaptoethanol.

Explanation:

Investigators utilized SDS-PAGE to analyze the purity of an antibody preparation. Upon electrophoresis, Lane 1, which contained untreated antibody sample, showed a single band at 150 kD. However, Lane 2, with antibody treated with mercaptoethanol, exhibited two distinct bands at molecular weights of 50 kD and 25 kD. The presence of these two bands in Lane 2, which was absent in Lane 1, indicates that the antibody molecule was originally composed of multiple polypeptide chains held together by disulfide bonds. Mercaptoethanol reduced these disulfide bonds, allowing the constituent polypeptide chains to be separated under electrophoretic conditions and revealing the true subunit composition of the antibody. Therefore, the investigators can conclude that the antibody is a multimeric protein, likely composed of two 50 kD chains and at least one 25 kD chain that were originally connected by disulfide bonds.

Answer:

-2.3 ºC

Explanation:

Kf (benzene) = 5.12 ° C kg mol – 1

1st - We calculate the moles of condensed gas using the ideal gas equation:

n = PV / (RT)

P = 748/760 = 0.984 atm

T = 270 + 273.15 = 543.15 K

V = 4 L

R = 0.082 atm.L / mol.K

n = (0.984atm * 4L) / (0.082atm.L / K.mol * 543.15K) = 0.088 mol

Then, you calculate the molality of the solution:

m = n / kg solvent

m = 0.088 mol / 0.058 kg = 1.52mol / kg

Then you calculate the decrease in freezing point (DT)

DT = m * Kf

DT = 1.52 * 5.12 = 7.8 ° C

Knowing that the freezing point of pure benzene is 5.5 ºC, we calculate the freezing point of the solution:

T = 5.5 - 7.8 = -2.3 ºC

To obtain 50.0 g of methyl acetate, the student should measure out 53.5 cm³, using the density of methyl acetate which is 0.934 g/cm³.

To calculate the volume of methyl acetate the student should pour out using its density, the formula density = mass/volume can be rearranged to volume = mass/density. Given that the density of methyl acetate is 0.934 g/cm³, and the student needs 50.0 g of methyl acetate, the volume can be calculated as follows:

volume = mass/density

volume = 50.0 g / 0.934 g/cm³

volume = 53.533 g/cm³

The student should measure out 53.5 cm³ of methyl acetate to obtain 50.0 g, rounding to 3 significant digits.

Answer:

[tex](\rho*Q)/(\mu*h)[/tex]

Explanation:

First, we need to establish the unit of each variable:  

To eliminate [tex]m^3[/tex] we need to multiply Q by [tex]\rho[/tex]. Then to eliminate kg we divide [tex]\rho[/tex] by [tex]\mu[/tex]. Finally, multiply [tex]\mu[/tex] by h we can let the constant dimensionless.

Answer:

Lithium iodide, sodium fluoride and potassium iodide are more likely to undergo dissolution in water.

Explanation:

Water is a polar substance, which means that it will be a good solvent for other polar substances and salts.

LiI, NaF and KI are all salts that easily dissociate in water to produce ions. The ions will be surrounded by water molecules (solvatation) due to electrostatic interactions.

Heptane and octane are both non-polar substances that have no significant charges to interact with water molecules. Therefore, this substances will not dissolve in water.

Final answer:

Lithium iodide, sodium fluoride, and potassium iodide are ionic compounds that are most likely to dissolve in water, a polar solvent. Nonpolar substances like heptane and octane are less likely to dissolve in water.

Explanation:

When considering the solubility of substances in water, we must account for the polarity of both the solute and the solvent. Water is a polar solvent, which means it can easily dissolve other polar compounds and ionic compounds due to its ability to form ion-dipole interactions. Considering the substances provided, lithium iodide (LiI), sodium fluoride (NaF), and potassium iodide (KI) are ionic compounds and are most likely to undergo dissolution in water.

On the other hand, heptane ([tex]C_{7} H_{16}[/tex]) and octane ([tex]C_{8} H_{18}[/tex]) are hydrocarbons, which are nonpolar substances. Nonpolar substances do not dissolve well in polar solvents like water, thus making these substances less likely to dissolve in water. Instead, they would be more soluble in nonpolar solvents such as hexane or other hydrocarbons.

The molar heat of vaporization of substance X can be determined using the Clausius-Clapeyron equation. The molar heat of vaporization of substance X is -61.78 kJ/mol.

The molar heat of vaporization of substance X can be determined using the Clausius-Clapeyron equation. The equation is given by:

ln(P₂/P₁) = -(ΔHvap/R)((1/T₂) - (1/T₁))

We can solve for ΔHvap by substituting the values given: P₁ = 100 mm Hg, T₁ = 1080 °C (or 1353 K), P₂ = 600 mm Hg, and T₂ = 1220 °C (or 1493 K).

ln(600/100) = -(ΔHvap/8.314)((1/1493) - (1/1353))

Solving for ΔHvap gives us a value of -61.78 kJ/mol. Therefore, the molar heat of vaporization of substance X is -61.78 kJ/mol.

Answer:

The advantage of using building information modeling (BIM) are as follows:

1.Model based cost estimation

2. Preconstruction project visualization

3.Safe construction site

4. Improve scheduling

5.Improve coordination and clash detection

6.Reduced mitigated risk and cost

7.Improve prefabrication

8.Better collaboration and communication

9. Strong facility management

10.Improve sequencing

Answer:

[tex]Q=\frac {[Fe^{2+}]^2[Zn^{2+}]}{[Fe^{3+}]^2}[/tex]

Explanation:

The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at  particular point in the time.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The conecntration of the liquid and the gaseous species does not change and thus is not written in the expression.

Thus, for the reaction:

[tex]2Fe^{3+}_{(aq)}+Zn_{(s)}\rightleftharpoons 2Fe^{2+}_{(aq)}+Zn^{2+}_{(aq)}[/tex]

The expression is:

[tex]Q=\frac {[Fe^{2+}]^2[Zn^{2+}]}{[Fe^{3+}]^2}[/tex]

Answer:

3-D shape of molecule and adjacent carbon atoms and their orientation.

Explanation:

Stereochemistry involves study of relative spatial positioning or arrangement of atoms which form structure of the molecules.

Stereochemistry studies focuses on the stereoisomers, which are the species which have same molecular formula but the sequence of the bonded atoms is different in the 3-D space of the atoms.

Thus,

Molecule's stereochemistry tells the 3-D shape of molecule and adjacent carbon atoms and their orientation.

Stereochemistry provides information about the three-dimensional structure of a molecule, including the arrangement of atoms and their spatial orientation.

Stereochemistry is the study of the relative arrangement of atoms in molecules and their manipulation. It provides information about the three-dimensional structure of a molecule, including the arrangement of atoms and the spatial orientation of these atoms. By showing a molecule's stereochemistry, we can understand its shape, bonding patterns, and how it interacts with other molecules.

A molecule's stereochemistry can be represented using various models, such as ball-and-stick models, wedge-and-dash representations, or space-filling models. These models help visualize the three-dimensional structure of a molecule and show the arrangement of atoms in space.

Answer: This element has +2 charge on it.

Explanation:

An ion is formed when an atom looses or gains electrons.

Magnesium is the 12th element of the periodic table having electronic configuration of [tex]1s^22s^22p^63s^2[/tex]

This element will loose 2 electrons to attain stable electronic configuration and leads to the formation of a cation having formula [tex]Mg^{2+}[/tex]

Hence, this element has +2 charge on it.

Answer:

The molecular weight of the acid is 60.05 g/mol

Explanation:

Let's state the balanced chemical equation to represent the neutralization reaction:

NaOH + HAc → NaAc + H2O

where HAc is the representation of the monoprotic acid. As we can see, the relationship between the base and the acid is 1:1, that is 1 mole of NaOH reacts with 1 mole of the monoprotic acid HAc. So, let's calculate the moles of NaOH that where present in the 88.81 mL aliquot used to neutralize the acid:

1000 mL ---- 0.75 moles of NaOH

88.81 mL --- x = (88.81 mL × 0.75 moles)/1000 mL = 0.0666075 moles NaOH

As we stated before, 1 mole of NaOH will react with 1 mole of HAc, so 0.0666075 moles of NaOH will reacted with 0.0666075 moles of the acid. Having said that, because we already know the mass of the acid, we are able to determine the molecular weight of it:

0.0666075 moles of HAc ---- 4.00 g

1 mole of HAc ---- x = (1 mole × 4.00 g)/0.0666075 moles = 60.05 g/mole

The concentration of a 0.0075 umol of zinc oxalate in a 450 mL solution is 1.67 x [tex]10^{-8[/tex] mol/L or 0.0000000167 M.

To calculate the concentration of the zinc oxalate solution, we first convert the given quantity of zinc oxalate from umol to mol.

Converting 0.0075 umol to mol gives us 0.0075 x  [tex]10^{-6[/tex]  mol, which is 7.5 x [tex]10^{-9[/tex] mol.

Molarity is defined as the number of moles of solute per liter of solution.

So, we also need to convert 450 mL to liters, giving us 0.45L.

The concentration (C) is then calculated by dividing the number of moles (n) by the volume (V) in liters.

So, the molarity of the zinc oxalate solution can be calculated as follows: C = n/V = 7.5 x  [tex]10^{-9[/tex]  mol / 0.45L which equals 1.67 x  [tex]10^{-8[/tex]  mol/L, or 0.0000000167 M.

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Explanation:

Length of trash cans = l = 4 feet

Breadth of trash cans =  b = 4 feet

Height of trash cans =  h = 30 inches = 2.5 feet

1 inches = 0.0833333 feet

Capacity of trash can = Volume of the rectangular trash can = V

V = l × b × h

[tex]V=4 feet\times 4 feet \times  2.5 feet= 40 feet^3[/tex]

a) [tex]1 feet^3=7.48052 gallons[/tex]

[tex]V=40 feet^3=40\times 7.48052 gallons=299.221 gallons[/tex]

b) Density of water at 4°C = 1 kg /L

1 metric tonne of water = 264.17 gallons of water

[tex]V=299.221 gallons=\frac{299.221}{264.17}[/tex] metric tonne of water

[tex]V=1.1327[/tex]  metric tonne of water

Answer: The mass of chlorine gas is 4.54 grams.

Explanation:

To calculate the mass of the gas, we use the equation given by ideal gas equation:

[tex]PV=nRT[/tex]

Or,

[tex]PV=\frac{m}{M}RT[/tex]

where,

P = pressure of the gas = 98.7 kPa

V = Volume of gas = 3.34 L

m = given mass of chlorine gas = ?

M = Molar mass of chlorine gas = 35.45 g/mol

R = Gas constant = [tex]8.31\text{ L kPa }mol^{-1}K^{-1}[/tex]

T = Temperature of the gas = [tex]37^oC=[37+273]=310K[/tex]

Putting values in above equation, we get:

[tex]98.7kPa\times 3.34L=\frac{m}{35.45g/mol}\times 8.31\text{ L kPa }mol^{-1}K^{-1}\times 310K\\\\m=4.54g[/tex]

Hence, the mass of chlorine gas is 4.54 grams.