Answer:
C. Approx. Two thirds of the water is in the ICF compartment
Explanation:
The body cells are bathed in fluids internally and externally. The water inside the cells make up about 42% of the total body weight and is called the intracellular fluid (ICF). The rest of the fluid outside the cells is called extracellular fluid (ECF) and is separated from the intracellular fluid by a semipermeable membrane that surrounds the cell, and only allows fluid to flow in and out of the cells, but prevents unwanted molecules or materials from getting in.
A rifle fires a 1.06 x 10-2-kg pellet straight upward, because the pellet rests on a compressed spring that is released when the trigger is pulled. The spring has a negligible mass and is compressed by 6.61 x 10-2 m from its unstrained length. The pellet rises to a maximum height of 6.26 m above its position on the compressed spring. Ignoring air resistance, determine the spring constant.
Answer:
k = 2.65 10² N / m
Explanation:
As the pellets shoot up we can use energy conservation
Starting point. Compressed spring rifle
Em₀ = Ke = ½ k x²
Final point. Highest point of the path
[tex]Em_{f}[/tex] = U = m g y
Energy is conserved
Em₀ = Em_{f}
½ k x² = m g y
k = 2 m g y / x²
Let's calculate
k = 2 1.06 10⁻² 9.8 6.26 / (6.61 10⁻²)²
k = 2.65 10² N / m
If there is 8 g of a substance before a physical change, how much will there be afterwards?
0g
4g
8g
16g
According to the law of conversion of mass, the mass of a closed system is neither made or taken away in a physical change. It is the same for a chemical change as well.
Therefore, the mass of the substance remains 8g.
Best of Luck!
The specialized capillary bed responsible for the pressure that drives filtration is the
Answer: GLOMERULUS
Explanation:
The specialized capillary bed responsible for the pressure that drives filtration is the
GLOMERULUS.
The kidney is an organ responsible for the excretion of nitrogenous wastes from the human body and osmoregulation of the blood and body fluids. The structure which is responsible for formation of urine is the nephron( kidney tubule). The GLOMERULUS are found within the Bowman's capsule of the nephrons. It is made up of specialised bundle of capillary beds which are the only capillary beds that are not surrounded by interstitial fluid in the body. In the glomerulus, blood pressure is high because an arteriole enters and exists the capillary beds which is responsible for the pressure that drives filtration.
The glomerulus, a specialized capillary bed in the kidney nephrons, creates pressure driving filtration, a process important for maintaining body homeostasis.
Explanation:The specialized capillary bed responsible for the pressure that drives filtration is the glomerulus. This structure, located within the nephrons of the kidney, creates a pressure high enough to force substances such as water, glucose, and electrolytes out of the blood and into the nephron tubule, beginning the process of urine formation. The glomerular filtration process is an essential part of maintaining bodily homeostasis, i.e., keeping a stable internal environment in the body.
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Technician A says that with a properly operating air-conditioning system, the inlet to the compressor should be cold and the outlet from the compressor hot. Technician B says that the condenser should be hot and the evaporator cold. Which technician is correct?
Answer:
Only technician A is correct
Explanation:
Analysis of technician A's statements
The refrigeration cycle contains four major components: the compressor, condenser, expansion device, and evaporator. Refrigerant remains piped between these four components and is contained in the refrigerant loop.
The refrigerant begins as a cool vapor and heads to the first component:
1. the compressor
It forces the refrigerant through the system. In the process of being compressed the cool, gaseous refrigerant is turned to a very hot and high-pressure vapor.
Analysis of technician B's statement
The condenser’s job is to cool the refrigerant so that it turns from a gas into a liquid, or condenses. This happens when warm outdoor air is blown across the condenser coil that is filled with hot, gaseous refrigerant.
The evaporator is responsible for cooling the air going to the space by boiling (evaporating) the refrigerant flowing through it. This happens when warm air is blown across the evaporator as cold refrigerant moves through the evaporator coil. Heat transfers from the air to the refrigerant, which cools the air directly before it is vented to the space.
Three fire hoses are connected to a fire hydrant. Each hose has a radius of 0.017 m. Water enters the hydrant through an underground pipe of radius 0.088 m. In this pipe the water has a speed of 2.7 m/s. (a) How many kilograms of water are poured onto a fire in one hour by all three hoses
Answer:
2.36 x 10^5 kg
Explanation:
radius of hose, r = 0.017 m
radius of underground pipe, R = 0.088 m
number of hoses, n = 3
velocity of water in underground pipe, V = 2.7 m/s
Let v is the velocity of water in each hose.
According to the equation of continuity
A x V = n x a x v
π R² x V = n x π x r² x v
0.088 x 0.088 x 2.7 = 3 x 0.017 x 0.017 x v
v = 24.12 m/s
(a) Amount of water poured onto a fire in one hour by all the three hoses
= n x a x v x density of water x time
= 3 x 3.14 x 0.017 x 0.017 x 24.12 x 1000 x 3600
= 2.36 x 10^5 kg
Thus, the amount of water poured onto the fire in one hour is 2.36 x 10^5 kg.
a) Using the principles of fluid dynamics, specifically the continuity equation, we found that the velocity of water in the hoses is 2.02 m/s. The volume flow rate in the hoses is 0.0055 m³/s. Therefore, the mass of water poured onto a fire in one hour by all three hoses is 19800000 kg.
Explanation:a) To answer this question, we need to apply the principles of fluid dynamics, specifically the concept of continuity equation which states that the mass flow rate (the mass of water passing through a given spot per unit time) through a pipe system is constant.
First, let's calculate the cross sectional area of the hydrant pipe (A1) which is πr² = π(0.088m)² ≈ 0.0243 m².
Then, calculate the area of one fire hose (A2) which is π(0.017m)² ≈ 0.000907 m².
Since there are three hoses, the total area for the three hoses (A3) is 3 * A2 ≈ 0.00272 m².
Then, we apply the continuity equation, which is
A1v1=A3v3. We can solve for v3 (the velocity of the water in the hoses), v3 = A1v1/A3 ≈ 2.02 m/s.
To find the mass of water delivered in one hour, we first find the volume flow rate in the hoses,
Q= A3v3 = 0.00272 m² * 2.02 m/s ≈ 0.0055 m³/s.
The volume of water in one hour is Q * 3600s = 19800 m³.
Then, since water has a density (ρ) of 1000 kg/m³, the mass (m) of the water is ρ*volume which equals
19800 * 1000 kg = 19800000 kg.
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Label the parts that make up the human heart. Drag the items on the left to the correct location on the right.
A 1.0 m long piece of coaxial cable has a wire with a radius of 1.1 mm and a concentric conductor with inner radius 1.3 mm. The area between the cable and the conductor is filled with a dielectric. If the voltage drop across the capacitor is 6000 V when the line charge density is 8.8 μC/m, find the value of the dielectric constant. (k = 1/4πε₀ = 8.99 × 109 N · m²/C²)A) 4.8
B) 5.3
C) 4.4
D) 5.7
Answer:
C) 4.4
Explanation:
The potential of a cylindrical capacitor is given by the formula:
[tex]V=\frac{2kq}{L\epsilon}ln(\frac{a}{b})\\\\\epsilon=\frac{2kq}{LV}ln(\frac{a}{b})[/tex]
where:
k : Coulomb Constant
L : length of the capacitor
a : outer radius
b : inner radius
V : potential
By replacing we obtain:
[tex]\epsilon=\frac{2(8.89*10^{9}N/m^2C^2)(8.8*10^{-6}C)}{(1m)(6000V)}ln(\frac{1.3mm}{1.1mm})=4.35[/tex]
Hence, the answer is C) 4.4 (4.35 is approximately 4.4)
hope this helps!!
A radio wave of frequency on the order of 105 Hz is used to carry a sound wave with a frequency on the order of 103 Hz. Is the wavelength of this radio wave on the order of (a) kilometers, (b) meters, (c) centimeters, (d) micrometers
Given that,
Frequency of radio wave is from f = 10⁵ Hz and f' = 10³ Hz
We need to find the wavelength of radio wave. The speed of a wave is given by formula as follows :
If f = 10⁵ Hz
[tex]v=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{10^5}\\\\\lambda=3000\ m[/tex]
or
[tex]\lambda=3\ km[/tex]
If f' = 10³ Hz
[tex]v=f\lambda\\\\\lambda'=\dfrac{c}{f'}\\\\\lambda'=\dfrac{3\times 10^8}{10^3}\\\\\lambda'=300000\ m[/tex]
or
[tex]\lambda'=300\ km[/tex]
So, the wavelength of this radio wave on the order of kilometres.
The wavelength of this radio wave is on the order of meters.
Explanation:The wavelength of a radio wave can be calculated using the formula: wavelength = speed of light / frequency. In this case, the given frequency of the radio wave is on the order of 10^5 Hz. To compare it with the lowest audible sound waves with a frequency of 20 Hz, we can use the formula again. Taking the speed of sound in air at 20 °C as 343 m/s, we can calculate the wavelength of the lowest audible sound waves. By comparing the wavelengths of the two waves, we can determine the order of magnitude of the wavelength of the radio wave.
Let's calculate the wavelengths:
Wavelength of radio wave = speed of light / frequency = (3 x 10^8 m/s) / (10^5 Hz) = 3000 m
Wavelength of lowest audible sound wave = speed of sound / frequency = (343 m/s) / (20 Hz) = 17.15 m
Comparing the two wavelengths, we can see that the wavelength of the radio wave is on the order of meters.
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a man lift a load of 20kg through a height of 4m in 10sec . calculate the workdone
Answer:
The answer to your question is Work = 784.8 Joules
Explanation:
Data
mass = 20 kg
height = 4 m
time = 10 s
Mechanic work is defined as the force applied to a body so it moves a distance.
Formula
Work = force x distance
Process
1.- Calculate the force
Force = mass x gravity
-Substitution
Force = 20 x 9.81
-Result
Force = 196.2 N
2.- Calculate the Work
Work = 196.2 x 4
-Result
Work = 784.8 Joules
Changing the direction of current flow, will or will not affect the strength of an electromagnet? Pick one: Will or Will Not
Answer:
Will not.
Explanation:
just got the question correct.
Answer:
will not .
Explanation:
An object that completes 100 vibrations in 5 seconds has a period of
Answer:
The answer of the question is None.
Answer:
Period is 1/20 of a second.
Explanation:
Frequency is 20 vibrations per second. Period and frequency are reciprocals (period = 1/f). Period is 1/20 of a second.
A balloon is rising vertically above a level, straight road at a constant rate of 4 ft divided by sec4 ft/sec. Just when the balloon is 7272 ft above the ground, a bicycle moving at a constant rate of 1212 ft divided by secft/sec passes under it. How fast is the distance s (t )s(t) between the bicycle and balloon increasing 66 seconds later?
Answer:
12.27 ft/s
Explanation:
At 72 ft above the ground, the balloons height increases at a rate of 4ft/s. For 66s, vertical distance moved, y = 4ft/s × 66 s = 264 ft. When the balloon is at 72 ft above the ground, just below it, the bicycle which moves at a rate of 12 ft/s in 66 s, covers a horizontal distance, x = 12ft/s 66 = 792 ft.
The distance between the bicycle and the balloon 66 s later is given by
s = √(x² + (y + 72)²) = √(792² + (264 + 72)²) = √(792² + 336²) = √740160 ft = 860.33 ft
From calculus
The rate of change of the distance between the balloon and bicycle s is obtained by differentiating s with respect to t. So,
ds/dt = (1/s)(xdx/dt + ydy/dt)
dx/dt = 12 ft/s, x = 792 ft, dy/dt = 4 ft/s, y = 264 ft, s = 860.33. These are the values of the variables at t = 66 s.
So, substituting these values into ds/dt, we have
ds/dt = (1/860.33)(792 ft × 12 ft/s + 264 ft × 4ft/s) = (1/860.33)(9504 + 1056) = 10560/860.33 = 12.27 ft/s
An electron is moving in a circular orbit in a uniform magnetic field. Is the kinetic energy of the electron changing?
Answer:
kinetic energy does not change
Explanation:
you can use the formula for the kinetic energy of the electron and for the radius of the trajectory of an electron in a uniform magnetic field:
[tex]E_k=\frac{1}{2}m_ev^2\\\\r=\frac{m_e v}{qB}[/tex]
me: mass of the electron
B: magnetic field
q: charge of the electron
r: radius
By doing v the subject of the formula and replace it in the expression for the kinetic energy you obtain:
[tex]v=\frac{rqB}{m_e}\\\\E_k=\frac{1}{2}m_e(\frac{rqB}{m_e})^2=\frac{r^2q^2B^2}{2m_e}[/tex]
as youcan see, all parameters r, q, B and me are constant.
hence, the kinetic energy does not change
A 65kg teacher (including the parachute) is skydiving! As the parachute opens, the system experiences a 1200N drag.
How many forces are acting on the system?
What is the magnitude of the net force on the system?
What is the magnitude of the system's acceleration?
Describe the system's speed:
1) 2 Forces
2) 563 N, upward
3) [tex]8.66 m/s^2[/tex], upward
4) Speed is decreasing
Explanation:
1)
There are two forces acting on teacher during his skydiving:
- The force of gravity (also known as weight), acting downward (towards the Earth's centre), of magnitude
[tex]W=mg[/tex]
where
m is the mass of the teacher
g is the acceleration due to gravity
- The air resistance, of magnitude R = 1200 N, acting upward (air resistance always acts in the direction opposite to the direction of motion)
There are no other forces, therefore the correct answer is:
2 Forces
2)
The net force on the system is given by the vector resultant of the two forces described in part 1). Since the two forces act along the same line but in opposite directions, the net force will be equal to the difference between the two forces, so:
[tex]F_{net}=W-R=mg-R[/tex]
where we have chosen downward as positive direction, and where
m = 65 kg is the mass of the teacher
[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity
R = 1200 N is the air drag
Therefore, the net force on the teacher is
[tex]F_{net}=(65)(9.8)-1200=-563 N[/tex]
And the negative sign means that the direction of the net force is upward.
3)
The acceleration of the system can be found by using Newton's second law of motion, which can be written as
[tex]a=\frac{F_{net}}{m}[/tex]
where
a is the acceleration
[tex]F_{net}[/tex] is the net force
m is the mass of the teacher
Here we have
[tex]F_{net}=-563 N[/tex]
m = 65 kg
Therefore, the acceleration is
[tex]a=\frac{-563}{65}=-8.66 m/s^2[/tex]
And the negative sign indicates that the direction of the acceleration is opposite to the motion (so, upward).
4)
From part 3), we observed that:
- The motion of the teacher is downward (he is moving downward)
- However, the direction of his acceleration is upward
This means that the velocity and the acceleration of the system have opposite directions.
As we know, the velocity of an accelerating system can be written as
[tex]v=u+at[/tex]
where
v is the velocity after time t
u is the initial velocity
a is the acceleration
Since a is negative, we see that [tex]at<0[/tex], so [tex]v<u[/tex]: this means that the velocity of the teacher is decreasing with time, so, the teacher is slowing down, and therefore his speed is decreasing.
(a) Two forces are acting on the system.
(b) The magnitude of net force on the system is 592.4 N.
(c) The magnitude of the acceleration is 9.11 m/s².
(d) The speed of the system decreases with time
The given parameters;
mass of the teacher, m = 65 kgdrag force on the teacher, [tex]F_f[/tex] = 1200 NThe forces acting on the teacher are downward force due to the teachers weight and drag force acting upward opposing the downward motion.
The magnitude of net force on the system is calculated as follows;
[tex]F_{net}= W - F_f\\\\F_{net}= (65 \times 9.8) - (1200)\\\\F_{net} = -592.4 \ N[/tex]
The magnitude of the acceleration is calculated as follows;
[tex]a = \frac{-592.4}{65} \\\\a = -9.11 \ m/s^2\\\\|a| = 9.11 \ m/s^2[/tex]
The speed of the system is calculated as follows;
[tex]v= u + at\\\\v= 0 + (-9.11)t\\\\v = -9.11t[/tex]
The speed of the system decreases with time.
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What must be included when describing the displacement of an object?
Answer:
Measurement and Direction
Explanation:
Displacement is a vector quantity because it has magnitude (the measure o displacement)
Answer:
Measurement and direction.
Explanation:
What is true in every balanced chemical equation?
A. Mass has to be conserved.
B. The reaction does not give off any energy.
C. All coefficients have to be an even number.
D. Atoms are created when products are formed.
Answer:
B
Explanation:
How long will it take a force of 2.5 N to bring a 0.25-kg object to rest if it was moving at 1.4 m/s?
Tt will take approximately 0.14 seconds for the force of 2.5 N to bring the 0.25 kg object to rest from an initial velocity of 1.4 m/s
The question involves the application of Newton's second law of motion and the concepts of force, mass, acceleration, and time to bring an object to rest. Given a 0.25-kg object moving at 1.4 m/s, and a force of 2.5 N acting on it, we can first determine the acceleration using Newton's second law, F=ma, which gives us an acceleration of 10 m/s2. Next, we use the kinematic equation v = u + at (where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time) to find the time. Since the object comes to rest, v = 0 m/s, solving the equation for t gives us a time of 0.14 seconds to bring the object to rest.
A horizontal 826 N merry-go-round of radius 1.17 m is started from rest by a constant horizontal force of 57.8 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-goround after 3.47 s. The acceleration of gravity is 9.8 m/s 2 . Assume the merry-go-round is a solid cylinder. Answer in units of J. 028 10.0
Answer:
The kinetic energy of the merry-go-round is [tex]\bf{475.47~J}[/tex].
Explanation:
Given:
Weight of the merry-go-round, [tex]W_{g} = 826~N[/tex]
Radius of the merry-go-round, [tex]r = 1.17~m[/tex]
the force on the merry-go-round, [tex]F = 57.8~N[/tex]
Acceleration due to gravity, [tex]g= 9.8~m.s^{-2}[/tex]
Time given, [tex]t=3.47~s[/tex]
Mass of the merry-go-round is given by
[tex]m &=& \dfrac{W_{g}}{g}\\~~~~&=& \dfrac{826~N}{9.8~m.s^{-2}}\\~~~~&=& 84.29~Kg[/tex]
Moment of inertial of the merry-go-round is given by
[tex]I &=& \dfrac{1}{2}mr^{2}\\~~~&=& \dfrac{1}{2}(84.29~Kg)(1.17~m)^{2}\\~~~&=& 57.69~Kg.m^{2}[/tex]
Torque on the merry-go-round is given by
[tex]\tau &=& F.r\\~~~&=& (57.8~N)(1.17~m)\\~~~&=& 67.63~N.m[/tex]
The angular acceleration is given by
[tex]\alpha &=& \dfrac{\tau}{I}\\~~~&=& \dfrac{67.63~N.m}{57.69~Kg.m^{2}}\\~~~&=& 1.17~rad.s^{-2}[/tex]
The angular velocity is given by
[tex]\omega &=& \alpha.t\\~~~&=& (1.17~rad.s^{-2})(3.47~s)\\~~~&=& 4.06~rad.s^{-1}[/tex]
The kinetic energy of the merry-go-round is given by
[tex]E &=& \dfrac{1}{2}I\omega^{2}\\~~~&=&\dfrac{1}{2}(57.69~Kg.m^{2})(4.06~rad.s^{-1})^{2}\\~~~&=& 475.47~J[/tex]
A team of engineering students is testing their newly designed 200 kg raft in the pool where the diving team practices. The raft must hold a 730 kg steel cube with edges of length 45.0 cm without sinking. Assume the density of water in the pool is 1000 kg/m3.
The students use a crane to gently place the cube on the raft but accidentally place it off center. The cube remains on the raft for a few moments and then the raft tilts, causing the cube to slide off and sink to the bottom of the pool. The raft remains floating in the pool. In a coherent paragraph-length response, indicate whether the water level in the pool when the cube is on the bottom of the pool is higher than, lower than, or the same as when the cube is on the raft, and explain your reasoning. For both cases, assume that there is no motion of the water.
Answer:
The water level rises more when the cube is located above the raft before submerging.
Explanation:
These kinds of problems are based on the principle of Archimedes, who says that by immersing a body in a volume of water, the initial water level will be increased, raising the water level. That is, the height in the container with water will rise in level. The difference between the new volume and the initial volume of the water will be the volume of the submerged body.
Now we have two moments when the steel cube is held by the raft and when it is at the bottom of the pool.
When the cube is at the bottom of the water we know that the volume will increase, and we can calculate this volume using the volume of the cube.
Vc = 0.45*0.45*0.45 = 0.0911 [m^3]
Now when a body floats it is because a balance is established in the densities, the density of the body and the density of the water.
[tex]Ro_{H2O}=R_{c+r}\\where:\\Ro_{H2O}= water density = 1000 [kg/m^3]\\Ro_{c+r}= combined density cube + raft [kg/m^3][/tex]
Density is given by:
Ro = m/V
where:
m= mass [kg]
V = volume [m^3]
The buoyancy force can be calculated using the following equation:
[tex]F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3][/tex]
Vs > Vc, What it means is that the combined volume of the raft and the cube is greater than that of the cube at the bottom of the pool. Therefore the water level rises more when the cube is located above the raft before submerging.
A village maintains a large tank with an open top, containing water for emergencies. The water can drain from the tank through a hose of diameter 6.60 cm. The hose ends with a nozzle of diameter 2.20 cm. A rubber stopper is inserted into the nozzle. The water level in the tank is kept 7.50 m above the nozzle. (a) Calculate the friction force exerted on the stopper by the nozzle. (b) The stopper is removed. What mass of water flows from the nozzle in 2.00 h
Answer:
(A) Frictional force will be equal to 27.92 N
(B) Mass is equal to 33120 kg
Explanation:
(A) Diameter of nozzle d = 2.20 cm
So radius [tex]r=\frac{d}{2}=\frac{2.20}{2}=1.10cm[/tex]
eight h = 7.5 m
Density of water [tex]\rho =1000kg/m^3[/tex]
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Pressure on the rubber stopper
[tex]P=\rho hg[/tex]
[tex]p=1000\times 7.5\times 9.8=73500Pa[/tex]
Area of cross section [tex]A=\pi r^2[/tex]
[tex]A=3.14\times 0.01^2=3.799\times 10^{-4}m^2[/tex]
So force [tex]F=PA[/tex]
[tex]F=73500\times 3.799\times 10^{-4}=27.92N[/tex]
(B) Speed of the water through nozzle
[tex]v=\sqrt{2gh}[/tex]
[tex]=\sqrt{2\times 9.8\times 7.5}=12.12m/sec[/tex]
Volume of water flow
[tex]V=vA=12.12\times 3.799\times 10^{-4}=0.0046m^3/sec[/tex]
Mass of water flow per sec
[tex]m=\rho V=1000\times 0.0046=4.6kg[/tex]
Total time t = 2 hour = 2×3600 = 7200 sec
So total mass flow
[tex]m=4.6\times 7200=33120kg[/tex]
To calculate the friction force exerted on the stopper by the nozzle, use Bernoulli's equation for fluid flow. To calculate the mass of water that flows from the nozzle, use the equation Q = A * V.
Explanation:To calculate the friction force exerted on the stopper by the nozzle, we can use Bernoulli's equation for fluid flow. The pressure at the top of the tank is atmospheric pressure, and the pressure at the nozzle is also atmospheric pressure. The friction force can be calculated by the equation F = P * A, where P is the pressure difference and A is the cross-sectional area of the stopper.
First, calculate the pressure difference between the top of the tank and the nozzle using the equation P = ρ * g * h, where ρ is the density of water, g is the acceleration due to gravity, and h is the height difference.Next, calculate the cross-sectional area of the stopper using the equation A = π * (r^2), where r is the radius of the stopper.Finally, multiply the pressure difference by the cross-sectional area to calculate the friction force exerted on the stopper.To calculate the mass of water that flows from the nozzle in 2.00 hours, we can use the equation Q = A * V, where Q is the volumetric flow rate, A is the cross-sectional area of the nozzle, and V is the velocity of the water.
First, calculate the cross-sectional area of the nozzle using the equation A = π * (r^2), where r is the radius of the nozzle.Next, calculate the volumetric flow rate using the equation Q = A * V.Finally, multiply the volumetric flow rate by the time to calculate the mass of water that flows from the nozzle in 2.00 hours.Learn more about Fluid Flow here:https://brainly.com/question/34457794
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A spring is compressed by 50 cm from it's equilibrium length by an unattached block of mass 5.0 kg (the spring constant is 400 N/m). The box is released from rest, slides along a friction-less surface for a time, and then ascends a ramp of length 10 m, which is inclined at an angle of 20 degrees above the horizontal. What is the maximum distance that the box travels up the ramp?
Answer:
L = 2.98 m
Explanation:
In this exercise we are told that there is no friction, so we can use energy conservation
Starting point. Compressed spring
Em₀ = Ke = ½ k x²
Final point. At the highest point of the ramp
[tex]Em_{f}[/tex] = U = mg h
As there is no friction the energy is conserved
Emo = Em_{f}
½ k x² = mg h
h = ½ k x² / mg
h = ½ 400 0.50² / (5.0 9.8)
h = 1.02 m
This is the height that the body reaches, to calculate the distance traveled on the ramp let's use trigonometry
sin θ = h / L
L = h / sin θ
L = 1.02 / sin 20
L = 2.98 m
A thermometer reading 10 degrees C is brought into a room with a constant temperature of 38 degrees Upper C. (a) If the thermometer reads 14 degrees C after 4 minutes, what will it read after being in the room for 6 minutes?
Answer:
Explanation:
We shall apply Newton's laws of cooling .
dT / dt = k ( T₁ - T₂ )
dT is change in temperature in time dt , k is constant , T₁ and T₂ are temperature of cold object and hot surrounding respectively.
For the first case of 4 minutes
(14 - 10)/ 4 = k [(14+10) /2 - 38 ] , T₁ = (14+10) /2 , the average temperature
1 = - 26 k
Using the formula for next two minutes
T-14 / 2 = k [(14+T) /2 - 38 ]
T-14 / 2 = 1/26[ 38 - (14+T) /2 ]
T / 2 - 7 = 1.46 - .27 - T / 52
T/2 + T/52 = 7 + 1.46 - .27
= .52 T = 8.19
T = 15.75 degree
Carbonic anhydrase (CA) has a 25000-fold higher activity (kcat =106 s-1) than orotidine monophosphate decarboxylase (OMPD) (kcat =40 s-1). However, OMPD provides more than a 1010 higher rate acceleration than CA. Explain how this is possible.
Answer:
Answer in explanation
Explanation:
In this question, we will be providing an explanation as to why OPMD provides more than 10^10 higher rate acceleration than CA
we proceed as follows;
Kcat is a measure of the catalytic activity of an enzyme indicating how many reactions a molecule of enzyme can catalyze per second. But Michaelis constant, Km also plays role during rate acceleration. The kcat/Km ratio is useful for comparing the activities of different enzymes. It is also possible to assess the efficiency of an enzyme by measuring its catalytic proficiency.
This value is equal to the rate constants for a reaction in the presence of the enzyme (kcat/Km) divided by the rate constant for the same reaction in the absence of the enzyme (kn). an enzyme with rapid binding might evolve a mechanism that favored a faster reaction.
An electric field around the OMPD active site enhances the rate of formation of the ES complex. Electrostatic effects allow OMPD to bind and remove OMPD much faster than expected from random collisions of enzyme and substrate.
According to the diagram, which pair could both be north poles?
The given diagram of the magnet shows attraction which occurs between opposite poles therefore, A and C could both be the north poles. Thus, the correct option is C.
What is a magnet?A magnet is a material or an object which produces a magnetic field around itself. The magnetic field of this magnet is invisible however it is responsible for the most notable property of a magnet which is a force that is responsible for pulling on other ferromagnetic materials, such as iron, steel, nickel, cobalt, etc. towards it and attracts or repels other magnets as well.
Some important properties of magnet include a magnet has two poles which are north pole and south pole, magnets attract ferromagnetic materials, the similar poles of two magnets repel each other, whereas the opposite poles of two magnets attract each other. A magnet hung up in the air always comes to rest facing the north-south direction. The poles of a magnet are arranged in pairs.
Therefore, the correct option is C.
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IIn traveling to the Moon, astronauts aboard the Apollo spacecraft put the spacecraft into a slow rotation to distribute the Sun's energy evenly (so one side would not become too hot). At the start of their trip, they accelerated from no rotation to 1.0 revolution every minute during a 12-min time interval. Think of the spacecraft as a cylinder with a diameter of 8.5 m rotating about its cylindrical axis. Determine the angular acceleration, and the radial and tangential components of the linear acceleration of a point on the skin of the ship 6.0 min after it started this acceleration.
The spacecraft had an angular acceleration of 0.00873 rad/s². At 6 minutes into the flight, a point on the skin of the spacecraft had a radial (centripetal) acceleration of 0.01167 m/s² and a tangential acceleration of 0.0371 m/s².
Explanation:First, let's find the angular acceleration which is the rate of change of angular velocity. The spacecraft went from 0 to 1 revolution per minute in 12 minutes. This is an angular acceleration (α) of 1 rev/min/12 min = 1/12 rev/min². However, we generally measure angular acceleration in rad/s², not rev/min². We know that 1 revolution = 2π rad and 1 min = 60 s, so we can convert our units to get α = ((1/12 rev/min²) x (2π rad/rev) x (1 min/60 s)²) = 0.00873 rad/s².
Next, we find the radial (centripetal) and tangential components of linear acceleration at 6 minutes. At 6 minutes, the angular velocity (ω) is (α x t) = ((1/12 rev/min) x 6 min) = 0.5 rev/min. Convert this to rad/s: ω = ((0.5 rev/min) x (2π rad/rev) x (1 min/60 s)) = 0.05236 rad/s. Now, the radial or centripetal acceleration (a_r) is given by (ω² x r) and the tangential acceleration (a_t) is given by (α x r), where r is the radius of the spacecraft, which is half of the diameter or 8.5 m / 2 = 4.25 m. We can plug the numbers in to get: a_r = (ω² x r) = (0.05236 rad/s)² x 4.25 m = 0.01167 m/s² and a_t = α x r = 0.00873 rad/s² x 4.25 m = 0.0371 m/s². So, the radial acceleration is 0.01167 m/s² and the tangential acceleration is 0.0371 m/s².
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A long string carries a wave; a 7.00-m segment of the string contains five complete wavelengths and has a mass of 180 g. The string vibrates sinusoidally with a frequency of 55.0 Hz and a peak-to-valley displacement of 20.0 cm. (The "peak-to-valley" distance is the vertical distance from the farthest positive position to the farthest negative position.)(a) Write the function that describes this wave traveling in the positive x direction. (Use the following as necessary: x and t. x is in meters and t is in seconds.)y =
Answer:
y = 0.1sin(4.5x - 345.6t)
Explanation:
Parameters given:
Length of 5 wavelengths = 7 m
Length of one wavelength, λ = 7/5 = 1.4 m
Frequency of wave, f = 55 Hz
Peak to Valley displacement = 20 cm = 0.2 m
Amplitude is half of the Peak to Valley displacement = 0.1 m
The wave function of a wave traveling in the positive x direction is given generally as:
y = Asin(kx - wt)
Where A = amplitude
k = Wave factor = 2π/λ
x = displacement on the x axis
w = angular frequency = 2πf
t = time taken
=> Wave factor, k = 2π/λ = 2π/(1.4) = 4.5 m^(-1)
=> Angular frequency, w = 2πf = 2π * 55 = 345.6 Hz
Therefore, inserting all the necessary parameters, we get that the wave function is:
y = 0.1sin(4.5x - 345.6t)
A solution that contains the maximum amount of solute for a given amount of solvent at a particular temperature is called
Answer:
saturated solution is the correct answer.
Explanation:
A saturated solution is a chemical solution, comprised of solute and solvent and in which no more further solute can dissolve in the solvent.A saturated solution contains the highest concentration of solute dissolved in a solvent.factors affecting the saturation solution are: the solution's temperature and pressure and also chemical composition of the substance addAn example of a saturated solution is carbonated water.a force sets an object in motion. when the force is multiplied by the time of its application we call the quantity impulse which changes the momentum of that object. what do we call the quantity force x (times) distance, and what quantity can this change?
Answer:
Work done
Explanation:
Impulse of an object is given by the product of force and time. It is also equal to the change on momentum of an object. The quantity that is given by the product of force and distance is called work done by an object.Work done also depends on the angle between force and displacement.The work done on an object is given as the product of force and distance traveled by the object.
What is impulse?Impulse is the force applied to an object for a certain period of time
J = Ft (Ns)
The change in the momentum of an object is equal to the impulse experienced by the object.
The work done on an object is given as the product of force and distance traveled by the object.
W = Fd (J)
The work done on an object causes change in the position of the object.
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A sphere of radius R has total charge Q. The volume charge density (C/m3) within the sphere is rho(r)=C/r2, where C is a constant to be determined. Part A The charge within a small volume dV is dq=rhodV. The integral of rhodV over the entire volume of the sphere is the total charge Q. Use this fact to determine the constant C in terms of Q and R. Hint: Let dV be a spherical shell of radius r and thickness dr. What is the volume of such a shell? Express your answer in terms of the variables Q and R.
Answer: C = Q/4πR
Explanation:
Volume(V) of a sphere = 4πr^3
Charge within a small volume 'dV' is given by:
dq = ρ(r)dV
ρ(r) = C/r^2
Volume(V) of a sphere = 4/3(πr^3)
dV/dr = (4/3)×3πr^2
dV = 4πr^2dr
Therefore,
dq = ρ(r)dV ; dq =ρ(r)4πr^2dr
dq = C/r^2[4πr^2dr]
dq = 4Cπdr
FOR TOTAL CHANGE 'Q', we integrate dq
∫dq = ∫4Cπdr at r = R and r = 0
∫4Cπdr = 4Cπr
Q = 4Cπ(R - 0)
Q = 4CπR - 0
Q = 4CπR
C = Q/4πR
The value of C in terms of Q and R is [Q/4πR]
Consider heat transfer between two identical hot solid bodies and the air surrounding them. The first solid is being cooled by a fan while the second one is allowed to cool naturally. For which solid is the lumped system analysis more likely to be applicable? Why?
Answer:
The solution to the question above is explained below:
Explanation:
For which solid is the lumped system analysis more likely to be applicable?
Answer
The lumped system analysis is more likely to be applicable for the body cooled naturally.
Question :Why?
Answer
Biot number is proportional to the convection heat transfer coefficient, and it is proportional to the air velocity. When Biot no is less than 0.1 in the case of natural convection, then lumped analysis can be applied.
Further explanations:
Heat is a form of energy.
Heat transfer describes the flow of heat across the boundary of a system due to temperature differences and the subsequent temperature distribution and changes. There are three different ways the heat can transfer: conduction, convection, or radiation.
Heat transfer analysis which utilizes this idealization is known as the lumped system analysis.
The Biot number is a criterion dimensionless quantity used in heat transfer calculations which gives a direct indication of the relative importance of conduction and convection in determining the temperature history of a body being heated or cooled by convection at its surface. In heat transfer analysis, some bodies are observed to behave like a "lump" whose entire body temperature remains essentially uniform at all times during a heat transfer process.
Conduction is the transfer of energy in the form of heat or electricity from one atom to another within an object and conduction of heat occurs when molecules increase in temperature.
Convection is a transfer of heat by the movement of a fluid. Convection occurs within liquids and gases between areas of different temperature.
Final answer:
The lumped system analysis is more applicable to the solid cooled naturally because natural convection is slower, allowing the solid's temperature to equalize, which suits the assumptions of lumped system analysis better than the enhanced convection caused by a fan.
Explanation:
The lumped system analysis is more likely to be applicable to the solid that is being cooled naturally rather than the one with a fan. The reason for this is that the use of a fan increases the flow of air over the surface, enhancing convection and therefore increasing the rate of heat transfer. This forced convection reduces the likelihood that the temperature gradient within the solid will remain uniform, which is a key assumption of lumped system analysis – that the object's temperature is spatially uniform and can be modeled as a lumped capacitance.
In contrast, when cooling occurs naturally, the heat transfer is driven by natural convection, which tends to be slower as it relies on the thermal expansion of the fluid around the solid due to the heat transfer from the solid. The slower rate of heat transfer allows the temperature within the solid to equalize more readily, making lumped system analysis a more appropriate simplification for predicting the thermal response of the solid.