Answer: The correct answer is : Hues
Explanation: The spectrum is made up of three primary light colors that are red, green and blue. For three secondary colors that are yellow, cyan and magenta. For six tertiary colors that are orange, lemon green, turquoise, light blue, violet and teal. The spectrum does not contain all the colors that human eyes and the brain can distinguish, for example magenta, pink and coffee are not in the visible spectrum because the mixing of several wavelengths, mainly dark reds, is required .
The visible spectrum includes the colors red, orange, yellow, green, blue, indigo, and violet, with specific wavelengths assigned to each. These colors are often observed in a rainbow. While indigo is sometimes included, the main colors are typically red, orange, yellow, green, blue, and violet.
The visible spectrum of light consists of colors that are produced by visible light of specific wavelengths. The primary colors that we see in a rainbow and that can be produced by narrow bands of wavelengths include:
Red (620 to 750 nm), Orange (590 to 620 nm), Yellow (570 to 590 nm), Green (495 to 570 nm), Blue (450 to 495 nm), Indigo (approx. 445 to 450 nm), Violet (380 to 445 nm). In total, these are the main colors of the visible light spectrum.
Which type of modulation is applied to radio-controlled toys?
Answer:
Pulse modulation
Explanation:
Remote control toys use the radiations that lie in the range of infrared for their working. The frequency of these infrared radiations is 36-46 kilo Hertz.
The signals we give to the toys through remote control are actually given in the form of bits of data which are then modulated with the any desired carrier frequency. Therefore, the data we are sending is in the form of pulses and the pulses' duration determines that whether the signal will be read as OFF (0) or ON (1). This modulation is pulse modulation which is an effective method to lower the power value delivered by a signal by cutting the signal into smaller parts.
Similarly there are some other kinds of modulations used in some other purposes like frequency and amplitude modulation for signals transmission video and music.
Hope it helps!
Answer:
pulse
Explanation:
If the magnitude of the electrostatic force felt by a charge is three times that from another charge, but their charges are the same, then the electric field strength of this charge is _____ the strength of the other charge.
three times
nine times
one-third
one-ninth
Answer:
three times
Explanation:
F=Eq
3F=3Eq
Answer:
three times
Explanation:
The relation between the force and the electrostatic field is given by
F = q E
where, F be the force , q be the charge and E be the strength of electrostatic field.
Here the charge is q
F = q E .... (1)
Now the charge remains same but the force three times, let E' be the electrostatic field strength.
3F = q E' .... (2)
Divide equation (2) by equation (1)
E' / E = 3F / F
E' = 3 E
A _________ is a satellite or other spacecraft designed to explore space and transmit data back to Earth.
Answer:
Space Probe
Explanation:
It is actually a type of satellite to explore space considering the useful dimensions for discoveries and observations that are useful for existence of life. It collects data and returns back to the base with records that are purpose of flight.
The Voyager is a designed robotic spacecraft as a part of space technology to explore space and sends data to Earth.
Explanation:
The voyager has been designed as an integral part of the space program known as the VOYAGER, which explores space. This program has been launched into the space by the NASA.
The satellite has been communicating and sending various space informational data to the space information base positioned in NASA known by the name of DEEP SPACE NETWORK. This program was launched in the year of 1977.
Which agency helps with disaster response
Answer:
AMURT
Explanation:
BUT THERE ARE MANY OTHERS LIKE THE AMERICAN RED CROSS ETC
Answer: Mercy corps
answered this on another dudes comment thread but still, give me brainliest please!
Starting from rest on a frictionless floor you move 160 kg crate accelerated by a net force of 60N applied for 4s. Enter units for acceleration as m/s^2.
What is the acceleration of the crate from Newton’s 2nd law?
If it starts from rest, how far does it travel in time of 4 s?
How much work is done by the 60N net force?
What is the velocity of the crate at the end of 4s?
What is the kinetic energy of the crate at this time?
1. Acceleration: [tex]0.375 m/s^2[/tex]
Newton's second law states that the net force on an object is equal to the product between the object's mass and its acceleration:
F = ma
where
F is the net force
m is the mass
a is the acceleration
For the crate in this problem we have
F = 60 N
m = 160 kg
Re-arranging the equation, we can find the acceleration of the crate:
[tex]a=\frac{F}{m}=\frac{60 N}{160 kg}=0.375 m/s^2[/tex]
2. Distance: 3 m
For this problem we can use the following SUVAT equation:
[tex]S=ut+\frac{1}{2}at^2[/tex]
where
S is the distance travelled by the crate
u = 0 is the initial velocity, since it starts from rest
t = 4 s is the time elapsed
[tex]a=0.375 m/s^2[/tex] is the acceleration
Substituting all numbers into the equation,
[tex]S=0+\frac{1}{2}(0.375)(4)^2=3 m[/tex]
3. Work done: 180 J
The work done by a force, assuming that the force is parallel to the displacement of the object, is given by
W = F d
where
W is the work done
F is the magnitude of the force
d is the displacement
Here we have
F = 60 N
d = 3 m
So the work done is
[tex]W=(60 N)(3 m)=180 J[/tex]
4. Final velocity: 1.5 m/s
The final velocity of the crate can be found by using the following SUVAT equation:
[tex]v^2 = u^2 +2ad[/tex]
where here
u = 0 is the initial velocity
[tex]a=0.375 m/s^2[/tex] is the acceleration
d = 3 m is the distance covered
Substituting all the numbers that we have, we found:
[tex]v=\sqrt{u^2 +2ad}=\sqrt{0^2+2(0.375)(3)}=1.5 m/s[/tex]
5. Kinetic energy: 180 J
The kinetic energy of an object is given by
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the object
v is the velocity
Here we have
m = 160 kg is the mass of the crate
v = 1.5 m/s is its final velocity
So the kinetic energy of the crate is
[tex]K=\frac{1}{2}(160)(1.5)^2=180 J[/tex]
Gravity is the force that keeps us on the Earth. It pulls us towards the center of the Earth. If you were to move from the surface of the Earth to a point higher up, away from the Earth, what type of energy would be gained? A. Chemical potential energy B. Gravitational potential energy C. Gravitational kinetic energy D. Kinetic potential energy
Explanation:
The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field.
That is why this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.
In the case of the Earth, in which the gravitational field is considered constant, the value of the gravitational potential energy [tex]U_{p}[/tex] will be:
[tex]U_{p}=mgh[/tex]
Where [tex]m[/tex] is the mass of the object, [tex]g[/tex] the acceleration due gravity and [tex]h[/tex] the height of the object.
As we can see, the value of [tex]U_{p}[/tex] is directly proportional to the height.
If the specific heat of water is 1.0 calorie/gram°C, how many calories are required to raise 500 grams of water 10.0°C?
510 cal
5,000 cal
50 cal
501 cal
Answer:
5,000 cal
Explanation:
q = m C ΔT
where q is heat, m is mass, C is specific heat, and ΔT is change in temperature.
q = (500 g) (1.0 cal/g/°C) (10.0°C)
q = 5,000 cal
Sierra did 500 J of work to move her couch. If she exerts 250 N of force on the couch, how far did she move it?
Answer:
2 m
Explanation:
Work = force × distance
500 J = 250 N × d
d = 2 m
She moved the couch 2 meters.
Which factors affect gravitational force? Check all that apply.
composition of the objects
distance between the objects
masses of the objects
volume of the objects
weights of the objects
Intro
Done
Answer:
distance between the objects
masses of the objects
Explanation:
Gravitational force is a force of attraction that pulls two objects with masses together.
To best understand the concept of gravitational force, newton's law of universal gravitation provides a good insight. The law states that "every object in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".
From the law, we see that gravitational force is dependent on the masses of the object and their distances.
Answer:
B. distance between the objects
C. masses of the objects
a weight lifter performed 200 J of work lifting a weight in 2 seconds. what was his power
Answer:
100 Watts
Explanation:
Power is work per time.
P = W / t
P = 200 J / 2 s
P = 100 W
Answer: 100 Watts
Explanation:
Chris is about to do an experiment to measure the density of water at several temperatures. His teacher has him prepare and sign a safety contract before beginning the experiment.
Which item is most likely part of the safety contract?
The safety contract will include basic lab safety guidelines such as:
Remove all flammable materials from the work station. Avoid leaving the heating set-up unattended. Fold long sleeves, tie back long hair, remove all accessories that may catch on fire. Wear proper lab attire.Avoid horse-playing in the lab.Report any injuries to the teacher, no matter how minor, as soon as possible. Avoid working alone inside the lab. Make sure you are aware of the location of the safety equipment and features of the lab especially the first aid kit, fire exit, fire blanket, and fire extinguisher.Follow instructions carefully.Dispose materials properly.Report any faulty equipment as soon as possible.Avoid touching hot surfaces with bare hands. Wash all used glassware.Keep workstation clean and tidy to avoid accidents.Avoid eating and drinking inside the lab.Put away unnecessary things. Only materials needed for the investigation must be on the workstation.Further Explanation:
In his safety contract, Chris will find statements that has him agreeing that he will behave appropriately inside the lab especially since they will be working with an open fire (Bunsen burner) or a heating equipment (hot plate) to change the temperature of the water. Proper behavior and basic expectation inside a lab are in the items listed above.
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Answer:
th
Explanation:
a bike can climb the inclined road at uniform speed of 72 km/hr by applying force 500N what will be the power applied by the bike ?
Answer:
10 kW
Explanation:
First convert km/hr to m/s.
72 km/hr × (1000 m / km) × (1 hr / 3600 s) = 20 m/s
The power is:
P = Fv
P = (500 N) (20 m/s)
P = 10000 W
P = 10 kW
The power applied by the bike is 10 kW.
The power applied by the bike climbing the inclined road at a constant speed with a force of 500 N is calculated as 10000 watts or 10 kW using the formula Power = Force x Velocity.
The problem at hand involves calculating the power applied by a bike when it ascends an inclined road at a uniform speed while applying a force. To find the power, we need to use the formula for power in the context of mechanical systems, which is Power (P) = Force (F) × Velocity (v). Here, force is given as 500 N and the velocity can be converted from 72 km/hr to meters per second (m/s) by multiplying it with (1000 m/km) / (3600 s/hr), which gives us 20 m/s.
Therefore, the power applied by the bike is P = 500 N × 20 m/s = 10000 watts or 10 kW.
This is the instantaneous power delivered by the force that the bike exerts on the road to overcome resistant forces like friction and air resistance while moving uphill. It's important to note that the power can change if any of the variables, such as speed or the force, change.
10. A worker covers a distance of 40 km from his house to his place of
work, and 10 km towards his house back. Then the displacement
covered by the worker in the whole trip is
The displacement covered by the worker in the whole trip is 30km.
The easiest way to solve this problem is using the displacement equation:
Δx = x₂ - x₁
A worker covers a distance of 40 km from his house to his place of
work, and 10 km towards his house back. So:
Δx = x₂ - x₁ = 40km - 10km = 30km
Since displacement is a vector quantity, the displacement of the worker from the data is 30Km.
What is displacement?Displacement refers to distance covered in a specific direction. Hence, unlike distance, we include direction in our discussion of displacement.
As such, displacement is a vector quantity therefore, the displacement of the worker is obtained from 40 Km - 10 Km = 30Km.
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A particle of mass, m = 3.0kg movers with a uniform velocity, v = (5m/s)I +(3m/s)j. At the time, t, the particle passes through the point r = (2m)i - (3m)j from the origin. Calculate the magnitude and direction of the angular momentum about the origin at time t. (Angular momentum is given by L= mv x R
Answer:
The magnitude is 63 kg m²/s, and the direction is -k.
Explanation:
Plug the values into the equation:
L = m v×r
L = (3.0 kg) (<5 i + 3j> m/s × <2i − 3j> m)
Take the cross product. The cross product of two dimensional vectors is:
<v₁ i + v₂ j> × <r₁ i + r₂ j> = <(v₁ r₂ − v₂ r₁) k>
Therefore:
L = (3.0 kg) <((5)(-3) − (3)(2)) k m²/s>
L = (3.0 kg) <-21 k m²/s>
Multiply:
L = <-63 k kg m²/s>
The magnitude is 63 kg m²/s, and the direction is -k.
2 Points
What was a Democratic Party argument against the building of transportation
systems by the federal government?
O
A. The plan would result in the loss of farming jobs.
O
B. The plan would result in the loss of city jobs.
O
C. The plan would result in domination of the country by special
interests.
O
D. Only state governments could afford the large costs of the plan.
S
Answer:
The plan would result in domination of the country by special interests. - C.
A student drives her car at 54.0 km/h along a level (horizontal) curve. The combined mass of the car is 1250 kg. If the
curve has a radius of 70.0 m, what centripetal force must be supplied by friction to keep the car from skidding?
Answer:
4020 N
Explanation:
First convert km/h to m/s.
54.0 km/h × (1000 m / km) × (1 h / 3600 s) = 15.0 m/s
Sum of the forces in the radial direction:
∑F = ma
F = m v² / r
F = (1250 kg) (15.0 m/s)² / 70.0 m
F ≈ 4020 N
A baseball is launched straight up (vertically) next to a tall building with an initial velocity of 30.0 m/s[up]. The ball continues upward to a stop, and then falls until caught by a player leaning out of a window 14.0 m above the ground. How long is the ball in the air before the player catches it?
Answer:
5.61 seconds
Explanation:
Given:
y₀ = 0 m
y = 14.0 m
v₀ = 30.0 m/s
a = -9.8 m/s²
Find: t
y = y₀ + v₀ t + ½ at²
14 = 0 + 30t − 4.9t²
4.9t² − 30t + 14 = 0
Solve with quadratic formula:
t = [ -b ± √(b² − 4ac) ] / 2a
t = [ 30 ± √(900 − 274.4) ] / 9.8
t = 0.509, 5.61
t = 0.509 is the time when the ball first reaches the height of 14.0 meters on the way up. t = 5.61 is the time when the ball reaches the height of 14.0 meters on the way down.
Since we know the ball reaches its maximum height and begins falling again, we want the second time. t = 5.61 seconds.
the period and freqency of a wave are inversely related true or false
Answer: false
Explanation: the longer the period, the less thef= frequency
Answer:
True
Explanation:
As frequency increases, period decreases, and vice versa.
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A satellite with a mass of 5.6 E 5 kg is orbiting the Earth in a circular path. Determine the satellite's velocity if it is orbiting at a distance of 6.8 E 5 m above the Earth's surface. Earth's mass = 5.98 E 24 kg; Earth's radius = 6.357 E 6 m.
6,800 m/s
7,200 m/s
7,500 m/s
7,900 m/s
Answer:
7500 m/s
Explanation:
Centripetal acceleration = gravity
v² / r = GM / r²
v = √(GM / r)
Given:
G = 6.67×10⁻¹¹ m³/kg/s²
M = 5.98×10²⁴ kg
r = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m
v = √(6.67×10⁻¹¹ (5.98×10²⁴) / (7.037×10⁶))
v = 7500
The orbital velocity is 7500 m/s.
The orbital velocity is 7500 m/s.
What is orbital velocity ?Orbital velocity is defined as the minimum velocity a body must maintain to stay in orbit.
Given
h = 6.8 E 5 m = 6.8 * [tex]10^{5}[/tex] m
mass of satellite = 5.6 * [tex]10^{5}[/tex] kg
Earth's mass : m(e) = 5.98 E 24 kg
Earth's radius ; R(e) = 6.357 E 6 m
orbital velocity :v(orbiting ) = [tex]\sqrt{Gm(e) / R(e) + h}[/tex]
R(e) + h = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m
v = √(6.67×10⁻¹¹ * (5.98×10²⁴)) / (7.037×10⁶))
v = 7500 m/s
The orbital velocity is 7500 m/s.
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12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolley
travelling in the same direction at 1.5m/s. Find their common
velocity. Assume that there is no external unbalanced force
working in the horizontal direction.
Answer:
4 m/s
Explanation:
Momentum is conserved.
m₁ v₁ + m₂ v₂ = (m₁ + m₂) v
(50)(5) + (20)(1.5) = (50 + 20) v
v = 4
The final velocity is 4 m/s.
3. A nail salon has looked up the melting and boiling point of alcohol (ethyl). This means there's enough energy to change the state of matter. This change where a switches states is known as the
A. freezing point.
B. critical temperature.
C. fusion point.
D. condensation point.
Explanation:
critacal temperature
if the ball rises with a force of 150 N, what pressure did the patient apply to his side of the tube?
The following formula relates applied force to pressure:
P = F/A
P is the pressure, F is the applied force, and A is the area over which the force is applied.
Unfortunately we cannot calculate the pressure if we don't know the area of contact between the ball and the tube.
11. If a bar magnet's neutral region is broken in two, what will most likely occur?
Answer:
When the neutral point of a magnet is broken into two each part gains polarity opposite to each other. This is because the broken parts of this magnet become a complete magnet as the Original magnet with complete poles N and S.
When the neutral region of a bar magnet is broken into two, the broken two parts of the magnet becomes a whole magnet in itself, that is from one magnet, two new magnets are formed.
Explanation:
The neutral region exists in the mid of the magnet as the magnet is only polarized at the end on whole. Thereby the broken pieces on its ends acquires the polarity on the two end sides.
This occurs in both the broken parts. With the acquirement of the polarity, one side becomes the North Pole and the other side becomes the South pole. Therefore, the broken bar magnets becomes a magnet in itself.
A force of 32.5N stretches a spring of 0.500cm. What force will stretch a similar spring 1.60 cm?
Answer:
104 N
Explanation:
Calculate the spring stiffness:
F = kx
32.5 N = k (0.500 cm)
k = 65 N/cm
Find the force for the new length:
F = kx
F = (65 N/cm) (1.60 cm)
F = 104 N
You have 13.0 gallons of gasoline. How many liters is this? (1 gallon equals
about 3.79 L.)
Answer:
I believe the answer is C
Explanation:
For this case we must make a conversion, we have as data that:
1 gallon is equivalent to 3.79 liters
By making a rule of three we have:
1 gallon ------------> 3.79 L
13 gallons --------> x
Where "x" represents the equivalent in liters:
[tex]x = \frac {13 * 3.79} {1}\\x = 49.27[/tex]
So, we have 49.27 liters of gasoline.
Answer:
Option C
3.
A traffic light is suspended by two cables. What
should be the angle between the cables (0) so that the
tension in each cable will be equal to the weight of the
traffic signal light (W=T, = T)?
Answer:
120°
Explanation:
Draw a free body diagram. There are three forces acting on the traffic light. Two tension forces acting along the cables, and weight.
The tension forces have an angle θ between them. That means each tension force forms an angle of θ/2 with respect to the vertical. So the y component of each tension force is:
Ty = T cos (θ/2)
Sum of the forces in the y direction:
∑F = ma
Ty + Ty − W = 0
2 Ty = W
Substituting:
2 T cos (θ/2) = W
If W = T, then:
2 W cos (θ/2) = W
2 cos (θ/2) = 1
cos (θ/2) = 1/2
θ/2 = 60°
θ = 120°
The angle between the cables Ф so that the tension in each cable will be equal to the weight of the traffic signal light is 120°
Let
Ф = the angle between the cables.T = the tension in cable 1, T' = the tension in cable 2 and W = the weight of the traffic lightNow, the angle between the tension and the vertical is α = Ф/2.
Net force on vertical force on traffic lightThe net force vertical force on the traffic light is F = Tcosα + T'cosα - W
Since the traffic light is in equilibrium, we have that F = 0
So, F = Tcosα + T'cosα - W
Tcosα + T'cosα - W = 0
Tcosα + T'cosα = W
Now, since the tension in each cable equals the weight of the traffic light, T = T' = W.
So, Tcosα + T'cosα = W
Wcosα + Wcosα = W
2Wcosα = W
cosα = W/2W
cosα = 1/2
α = cos⁻¹(1/2)
α = 60°
Angle between the cablesSince α = Ф/2
Ф = 2α
Ф = 2(60°)
Ф = 120°
So, the angle between the cables Ф so that the tension in each cable will be equal to the weight of the traffic signal light is 120°
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the initial velocityof a particle along x axis is u at t=0 x=0 and its acceleration is given by a =2x then whats the correct equation for v^2= u^2 +2as
Answer:
v² = u² + 2x²
Explanation:
v² = u² + 2as is only valid for constant acceleration. Here, the acceleration is a function of position. We can find the function of velocity by integrating. Acceleration is the derivative of velocity with respect to time:
a = 2x
dv/dt = 2x
Apply chain rule:
dv/dt = dx/dt × dv/dx
dv/dt = v × dv/dx
Therefore:
v dv/dx = 2x
Separate the variables and integrate:
v dv = 2x dx
½ v² |ᵤᵛ = x² |₀ˣ
½ (v² − u²) = x²
v² − u² = 2x²
v² = u² + 2x²
Why is Earth considered to be an inner planet?
A- It is located between the sun and the Kuiper Belt.
B- It is located between the sun and the main asteroid belt.
C- It is the closest planet to the main asteroid belt.
D- It is the closest planet to the sun.
Earth is considered an inner planet because it lies between the Sun and the main asteroid belt, along with the other terrestrial planets Mercury, Venus, and Mars.
Explanation:Earth is considered to be an inner planet because it is located between the sun and the main asteroid belt. This asteroid belt is the region of the solar system between the orbits of Mars and Jupiter, where most asteroids are found. Earth, along with Mercury, Venus, and Mars, falls into the category of terrestrial or inner planets, which are closer to the Sun and primarily composed of rock and metal with solid surfaces that have geological features.
Correct answer to the student's question: B- It is located between the sun and the main asteroid belt.
How much momentum will a dumb-bell of mass 10 kg transfer
to the floor if it falls from a height of 80 cm? Take its downward
acceleration to be 10 m s–2 .
We want to find how much momentum the dumbbell has at the moment it strikes the floor. Let's use this kinematics equation:
Vf² = Vi² + 2ad
Vf is the final velocity of the dumbbell, Vi is its initial velocity, a is its acceleration, and d is the height of its fall.
Given values:
Vi = 0m/s (dumbbell starts falling from rest)
a = 10m/s² (we'll treat downward motion as positive, this doesn't affect the result as long as we keep this in mind)
d = 80×10⁻²m
Plug in the values and solve for Vf:
Vf² = 2(10)(80×10⁻²)
Vf = ±4m/s
Reject the negative root.
Vf = 4m/s
The momentum of the dumbbell is given by:
p = mv
p is its momentum, m is its mass, and v is its velocity.
Given values:
m = 10kg
v = 4m/s (from previous calculation)
Plug in the values and solve for p:
p = 10(4)
p = 40kg×m/s
By using the equations of motion and momentum, it can be determined that a 10 kg d.umbbell falling from a height of 80 cm will transfer 40 kg m/s of momentum to the floor.
Explanation:The subject of this question is Physics, particularly dealing with the concept of momentum. To find out how much momentum a d.umbbell will transfer to the floor, we first need to calculate its velocity right before it hits the ground. This can be calculated using the equation of motion: v² = u² + 2gh, where u (initial velocity) is 0 (because it starts from rest), g (gravity) is 10 m/s², and h (height) is 0.8m (80cm).
Using the given values in the equation, the velocity v comes out to be √(2*10*0.8) = √16 = 4 m/s. The momentum is then calculated using the formula p=mv, where p represents momentum, m is mass, and v is velocity. Substituting the mass (10 kg) and the velocity (4 m/s), we find out that the momentum transferred to the floor is 40 kg m/s. Therefore, a d.umbbell of mass 10 kg falling from a height of 80 cm transfers 40 kg m/s momentum to the floor.
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how far does a car go in 30 seconds at a speed of 29 m/s?
Answer:
870 metres
Explanation:
Speed = Distance/Time
Distance = Speed x Time
Distance = 29 x 30
= 870 metres