The dissolved particles in a solution containing a molecular solute are the molecules of the solute themselves. When a molecular solute dissolves, its molecules distribute uniformly within the solvent, forming a homogeneous mixture at the molecular level. However, ionic solutes dissociate into individual cations and anions.
Explanation:The dissolved particles in a solution containing a molecular solute like sugar (C12H22O11) would be molecules. In chemistry, a solution can be thought of as a mixture that is homogeneous at the molecular level. In these solutions, one component (the solvent) is usually present in a significantly larger concentration. Other components (solutes), are present in relatively lesser amounts. When a covalent solid like sugar dissolves in water, its molecules become uniformly distributed among the molecules of water creating an aquaeous solution.
However, not all solutions result in dissolved molecules. Solutions that include ionic compounds like sodium chloride (NaCl) will separate into individual cations and anions when dissolved in water. In contrast to molecular substances, ionic type compounds will break apart into separate ions. Hence, it's crucial to understand the type of solute in your solution.
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In location B, what can you conclude about the sediments carried in the river?
They can form a delta, because the river location B leads into the Gulf of Mexico.
Why do some metals lose their shine over time but not gold ?
Some metals lose their shine because of corrosion, a galvanic process involving oxidation by substances like oxygen.
The reason some metals lose their shine over time is due to a process known as corrosion, which is a galvanic process that leads to the deterioration of metals through oxidation. Metals like iron rust and silver tarnish when exposed to air because of their reaction with oxygen, forming oxides on the surface. However, gold does not corrode easily due to its resistance to oxidation by common substances.
Aluminum, although reactive, forms an aluminum oxide coating that protects it from further corrosion, while copper reacts with carbon dioxide to form a green patina that serves as a protective layer. Precious metals such as gold and platinum, known for their corrosion resistance and durability, defy normal oxidation and maintain their luster over time. They are impervious to most elements and can be corroded by only a few special fluids.
how do you explain why the addition of silver nitrate to the Fe/SCN equilibrium had an effect on the equilibrium, even though neither silver ion nor nitrate ion is written as part of the equilibrium reaction?
Final answer:
Adding silver nitrate to the Fe/SCN equilibrium introduces a common ion, Ag+, which reacts with SCN- to form a precipitate, reducing SCN- concentration and shifting the equilibrium to compensate, thus affecting the system.
Explanation:
The addition of silver nitrate to the Fe/SCN equilibrium affects the equilibrium even though silver ion or nitrate ion isn't part of the equilibrium reaction because it leads to the formation of a precipitate, AgSCN, thus reducing the concentration of free SCN− in the solution.
This is an example of the common ion effect, where the addition of a common ion shifts the position of equilibrium according to Le Chatelier's Principle. As AgSCN is removed from the solution, the equilibrium shifts to the left to restore balance, decreasing the concentration of Fe(SCN)2+ and lightening the color of the solution.
Adding silver nitrate to the Fe/SCN equilibrium affects the equilibrium by removing SCN− ions through precipitation, causing a shift in the equilibrium to the left. This results in a lower concentration of Fe[tex](SCN)^2^+[/tex] and a lighter solution color.
When silver nitrate is added to the Fe/SCN equilibrium, it affects the equilibrium even though neither silver ion nor nitrate ion is directly part of the equilibrium reaction. This is because silver ion (Ag+) reacts with thiocyanate ion (SCN−) to form a precipitate of AgSCN: [tex]Ag^+ _(_a_q_)[/tex] + [tex]SCN^-_(_a_q_)[/tex] = AgSCN (s)
This reaction removes SCN− ions from the solution, thereby reducing its concentration. According to Le Chatelier's principle, the equilibrium will shift to counteract this decrease by shifting to the left, thus decreasing the concentration of Fe(SCN[tex])^2^+[/tex] and causing the solution to become lighter in color.
Which bond in the acetic acid molecule is the most polar?
The most polar bond in acetic acid is [tex]\boxed{{\text{O - H bond}}}[/tex].
Further explanation:
Electronegativity:
The tendency of an atom to attract the shared electrons in the bond towards itself is known as electronegativity. The more electronegative atom will more attract the bonding electrons towards itself than the less electronegative one.
Higher the electronegativity value of the element more will be its tendency to accept an electron towards itself.
A polar bond is defined as a covalent bond between two atoms where the electrons that form the bond are unequally distributed. This is reason for the positive charge at one end and the negative charge at other end.
The bond or the molecular polarities are related to the electronegativity of the atoms or the molecules. The polarity of a bond is given by the difference in electronegativity between the two atoms that form polar bond
The factors on which the polarity of bonds depends are as follows:
1) Relative electronegativity of participating atoms:
Since the bond polarity involves pulling of electrons towards itself, hence a more electronegative element will be able to attract the electrons more towards it. As a result, the electrons will definitely move towards the more electronegative element.
2) The spatial arrangement of various bonds in the atom:
The shared pair of electrons also experience pulling force from the other bonded and non-bonded pair of electrons. This results in different bond polarities between same participating atoms that are present in different molecules. For example, bond polarity of O-H bond in a water molecule and acetic acid molecule is different. This is due to the different spatial arrangements of various bonds in the molecule.
Acetic acid also called as ethanoic acid is a colorless organic compound. It consists of methyl group that is bonded to carboxyl group.
The structure of acetic acid is attached in the image.
In acetic acid, two oxygen atoms are present in which one oxygen atom is double-bonded to carbon atom, and another one is single bonded to the carbon atom. Also, oxygen is bonded to hydrogen.
As oxygen is electronegative, the two oxygen atoms draw electron density away from the O-H bond and make the bond polar. Also, the electronegativity difference between oxygen and hydrogen is high due to which electrons are attracted towards oxygen and make the bond most polar.
Hence, in acetic acid O-H bond is most polar.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Organic compounds
Keywords: acetic acid, polar bond, polarity, electronegativity, O-H bond, CH3COOH, and carboxylic group.
Final answer:
The O-H bond in acetic acid is the most polar due to a large difference in electronegativity between oxygen and hydrogen.
Explanation:
The bond in the acetic acid molecule CH3COOH that is the most polar is the O-H bond. This polarization is due to the difference in electronegativity between oxygen (3.5) and hydrogen (2.1), which is 1.4 according to the Pauling scale. This significant difference leads to a highly polar covalent bond, meaning the electrons are more attracted to the oxygen atom, giving it a partial negative charge and the hydrogen a partial positive charge.
If a translucent blue copper sulfate solution is mixed with another solution and changes to a translucent lighter blue color does that mean a physical change occurred or a chemical change?
A solution made by dissolving 14.2g of sucrose in 100g water exhibits a freezing point depression of 0.77 degrees. Calculate the molar mass of sucrose
Final answer:
To find the molar mass of sucrose based on the freezing point depression, we first determine the molality of the solution from the observed freezing point depression and the freezing point depression constant of water. Then we calculate the number of moles of sucrose and finally divide the mass of sucrose dissolving by the number of moles to obtain the molar mass, which is 343.0 g/mol.
Explanation:
To calculate the molar mass of sucrose using freezing point depression, we utilize the formula ΔTf = i * Kf * m, where ΔTf is the change in freezing point, i is the van't Hoff factor (for sucrose, i = 1 since sucrose does not dissociate into ions), Kf is the freezing point depression constant for the solvent (water in this case), and m is the molality of the solution.
First, we need to determine the molality (m) of the sucrose solution. The freezing point depression observed is 0.77 degrees Celsius, and the freezing point depression constant (Kf) for water is 1.86 K/kg/mol. The molality is calculated using the observed ΔTf and Kf:
m = ΔTf / (Kf * i)
m = 0.77°C / (1.86°C*kg/mol)
m = 0.414 mol/kg
Now, convert the mass of the water to kilograms:
100g water = 0.1kg water
Next, calculate the number of moles of sucrose using the molality and mass of solvent:
n (moles of sucrose) = molality * mass of water (in kg)
n = 0.414 mol/kg * 0.1 kg
n = 0.0414 mol
Finally, calculate the molar mass of sucrose (M) by dividing the mass of sucrose used by the number of moles:
M = mass of sucrose / number of moles
M = 14.2g / 0.0414 mol
M = 343.0 g/mol
Therefore, the molar mass of sucrose is 343.0 g/mol.
Calculate the boiling point of water if the atmospheric pressure is 630 mmhg
The boiling point of water can be calculated by the equation:
Where:
P = Pressure in mm Hg
Po = Atmospheric pressure in mm Hg
ΔH= heat of vaporization in kJ/mol
R = Ideal Gas Constant (J/mol-K)
To = normal boiling point in Kelvin
T = boiling point of water (K)
Our known values are:
P = 630 mm Hg
Po = 760 mm Hg
ΔH = 40.66 kJ/mol = 40.66×1000 =40660
R = 8.314 J mol⁻¹ K ⁻¹
To = 373 K
Putting these values in the equation,
[tex] ln \frac{P_{0}}{P}= \frac{\Delta H}{R}(\frac{1}{T}-\frac{1}{T_{0}})[/tex]
[tex] ln \frac{760}{630}= \frac{40660}{8.314}(\frac{1}{T}-\frac{1}{373})[/tex]
Solving the equation will give:
T=370K
so, the boiling point of water is 370 K.
In an acid-base neutralization reaction 43.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution. what is the concentration of the h2so4 solution?'
Answer: The concentration of sulfuric acid is 0.219 M
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is KOH.
We are given:
[tex]n_1=2\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=43.74mL[/tex]
Putting values in above equation, we get:
[tex]2\times M_1\times 50.00=1\times 0.500\times 43.74\\\\M_1=\frac{1\times 0.500\times 43.74}{2\times 50.00}=0.219M[/tex]
Hence, the concentration of sulfuric acid is 0.219 M
Phosphoric acid has 3 pka values, which are 2.1, 6.9, and 12.4. draw the protonated form of phosphoric acid associated with the reaction whose pka value is 12.4. draw only one resonance form. do not draw lone electron pairs.
The ph of 0.015 m hno2 (nitrous acid) aqueous solution was measured to be 2.63. what is the value of pka of nitrous acid?
How many moles of copper are 4.57 x 1013 atoms of copper?
Taking into account the definition of avogadro's number, 7.59×10⁻¹¹ moles of copper are 4.57×10¹³ atoms of copper.
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of copper, then 4.57×10¹³ atoms are contained in how many moles of copper?
amount of moles of copper= (4.57×10¹³ atoms × 1 mole)÷ 6.023×10²³ atoms
amount of moles of copper= 7.59×10⁻¹¹ moles
Finally, 7.59×10⁻¹¹ moles of copper are 4.57×10¹³ atoms of copper.
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https://brainly.com/question/11907018?referrer=searchResultshttps://brainly.com/question/1445383?referrer=searchResultshttps://brainly.com/question/1528951?referrer=searchResultsFundamentally, how are ΔHrxnand ΔHfdifferent?Which part of the experiment demonstrated the change inenthalpy per mole of a reaction?
Final answer:
The difference between ΔHrxn and ΔHf lies in their application; ΔHrxn measures the energy change in a reaction, while ΔHf pertains to the formation of a compound from its elements. The change in enthalpy per mole of a reaction is demonstrated experimentally through methods like calorimetry, which measures temperature changes.
Explanation:
Fundamentally, ΔHrxn and ΔHf differ in their application within thermodynamics. ΔHrxn, or the enthalpy change for a reaction, measures the overall energy change when reactants turn into products under constant pressure. This encompasses the total heat absorbed or released, calculated as the difference between the enthalpy of products and reactants. In contrast, ΔHf, or the standard enthalpy of formation, is the enthalpy change accompanying the formation of 1 mole of a substance from its elements in their most stable states, under standard conditions (1 bar, 298.15 K).
The part of the experiment that demonstrates the change in enthalpy per mole of a reaction typically involves measuring the temperature change of the surroundings or the system itself during a chemical reaction. This temperature change, coupled with the specific heat capacity of the system and the number of moles of reactants or products, allows us to calculate the enthalpy change. Therefore, experimental methods such as calorimetry can directly measure the enthalpy changes, providing insights into whether a reaction is endothermic or exothermic based on the ΔH values calculated.
What is the term for a solid that forms when two solutions are mixed? a precipitate a gas a suspension a solution
the term for a solid when two solutions are mixed is a percipitate
The vapor pressure of water at 25.0°c is 23.8 torr. determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.0 g of water to change the vapor pressure to 22.8 torr.42.a solution is prepared from 53.8 g of a nonvolatile, nondissociating solute and 85.0 g of water. the vapor pressure of the solution at 60°c is 132 torr. the vapor pressure of water at 60°c is 150. torr. what is the molar mass of the solute?ans:epts:1dif:difficultref:11.4chemistry | general chemistry | solutions | colligative properties | vapor pressure of a solution | vapor pressure loweringmsc: quantitative43.an ideal solution is formed from a mixture of the nonvolatile solute urea, co(nh2)2, and methanol, ch3oh. the vapor pressure of pure methanol at 20°c is 89 mmhg. if 4.4 g of urea is mixed with 39.9 g of methanol, calculate the vapor pressure of the methanol solution.a) 4.9 mmhgb)80 mmhgc)74 mmhgd) 15 mmhge)84 mmhg44.a salt solution sits in an open beaker. assuming constant temperature and pressure, the vapor pressure of the solution
Sodium carbonate (Na2CO3) reacts with acetic acid (CH3COOH) to form sodium acetate (NaCH3COO), carbon dioxide (CO2), and water (H2O). A chemist carries out this reaction in a bomb calorimeter. The reaction causes the temperature of a bomb calorimeter to decrease by 0.985 K. The calorimeter has a mass of 1.500 kg and a specific heat of 2.52 J/g•K. What is the heat of reaction for this system?
The heat of reaction for this system can be calculated using the formula: Heat of reaction = mass of the calorimeter x specific heat of the calorimeter x change in temperature.
Explanation:The heat of the reaction for this system can be calculated using the formula:
Heat of reaction = mass of the calorimeter x specific heat of the calorimeter x change in temperature.
Plugging in the given values:
mass of the calorimeter = 1.500 kgspecific heat of the calorimeter = 2.52 J/g•K (converting to kg: 2.52 J/g•K / 1000 g = 0.00252 J/kg•K)change in temperature = 0.985 KUsing the formula, we can calculate:
Heat of reaction = 1.500 kg x 0.00252 J/kg•K x 0.985 K = 0.0037072 J
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When 1,000 joules of coal is burned it only produces 500 joules of electricity. What happened to the other 500 joules of energy?
The missing 500 joules of energy when burning 1,000 joules of coal are lost to inefficiencies in the energy conversion process, including factors like heat loss.
When 1,000 joules of coal is burned and only 500 joules of electricity is produced, the missing 500 joules of energy are lost primarily due to inefficiencies in the energy conversion process. This is a result of the Second Law of Thermodynamics, which states that when energy is transformed or transferred, part of it assumes a form that cannot be used to do work (often manifested as heat). In the context of a coal-fired power station, the energy undergoes several conversions: chemical energy from the coal is converted to thermal energy (heat), which is then converted to mechanical energy (turbines spinning), and finally converted to electrical energy.
The lost 500 joules of energy in the process are dissipated as heat into the environment, sound, and other forms of energy that are not useful in generating electricity. This comes from the inefficiency of the power plant, where some of the energy is unavoidably lost due to factors like friction, heat loss through conduction, convection, and radiation, and other resistive processes within the power generation system. Therefore, the efficiency of the power station is around 50% as it is only able to convert half of the energy content of the coal into electricity. Ex. In the case provided, a coal power plant with 1,000 joules of input energy from burning coal and an output of 500 joules of electrical energy would have an efficiency of 50%. This percentage is a simplified representation of many real-world power stations' efficiency, which tends to be around 30%-40%. It is also important to note that efforts to increase the efficiency of power stations can lead to more sustainable energy practices by reducing both waste energy output into the environment, which has ecological consequences, and the amount of coal required, which affects the release of CO2 emissions.
The picture below shows two galaxies.

Which of these statements best describes a similarity between the two galaxies? (2 points)
Both have spiral arms.
Both revolve around a single point.
Both are formed by gravitational forces.
Both change their shape from time to time
Answer:
Both are formed by gravitational forces.
Explanation:
I took the test!!
Enter a balanced equation for the reaction of Na2S and CdSO4.
Answer: [tex]Na_2S+CdSO_4\rightarrow Cd_2S+Na_2SO_4[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
Double displacement reaction is one in which exchange of ions take place.
The balanced chemical reaction will be:
[tex]Na_2S+CdSO_4\rightarrow Cd_2S+Na_2SO_4[/tex]
An aqueous solution of glucose behaves as an aldehyde because ________.
Question 1 (10 points) Question 1 Unsaved
How much heat is needed to raise 0.30grams of Aluminum from 30 Celcius to 150 Celcius?
(Use 0.9J/gC for the specific heat of Aluminum)
Question 1 options:
120J
32.4J
0.9J
100J
The equation from which heat can be calculated is represented as:
q=mc\Delta T
Where, q=Heat (J)
m=mass of aluminium(g)
Delta T=Change in temperature(⁰C)
c=specific heat (J/g ⁰C)
Here ,
m=mass of aluminium(g)=0.3 g
Delta T=Change in temperature(⁰C)=150-30⁰C=120⁰C
c=0.9J/gC
Putting all the values in the above equation,
q=mc\Delta T
q=0.3×0.9×120
q=32.4 J
So, heat required will be 32.4 J.
which is a substance that could be found in air, water or soil that is harmful to humans or animals?
a.) fossil fuel
b.) pollutant
c.) smog
d.) carbon dioxide
Answer:
Pollutant
Explanation:
took test
There are two steps in the extraction of copper metal from chalcocite, a copper ore. in the first step, copper(i) sulfide and oxygen react to form copper(i) oxide and sulfur dioxide: (s) (g) (s) (g) in the second step, copper(i) oxide and carbon react to form copper and carbon monoxide:
The net chemical equation is 2 [tex]Cu_2S[/tex] (s) + 3 [tex]O_2[/tex] (g) + 2 C (s) → 4 Cu (s) + 2 [tex]SO_2[/tex] (g) + 2 CO (g).
The net chemical equation for the production of copper from copper(I) sulfide, oxygen, and carbon involves a two-step process: oxidation of copper(I) sulfide with oxygen followed by reduction of copper(I) oxide with carbon, yielding copper metal, sulfur dioxide, and carbon monoxide.
The extraction of copper from its ore involves a two-step process. The first step is the oxidation of copper(I) sulfide (chalcocite) with oxygen to form copper(I) oxide and sulfur dioxide. The second step is the reduction of copper(I) oxide with carbon to obtain copper metal and carbon monoxide.
Step 1: Oxidation of Copper(I) Sulfide
2 [tex]Cu_2S[/tex] (s) + 3 [tex]O_2[/tex] (g) → 2 [tex]Cu_2O[/tex] (s) + 2 [tex]SO_2[/tex] (g)
Step 2: Reduction of Copper(I) Oxide
2 [tex]Cu_2O[/tex] (s) + 2 C (s) → 4 Cu (s) + 2 CO (g)
By adding the balanced equations from both steps together and eliminating the intermediate product, copper(I) oxide, which appears on both sides, we get the net chemical equation for the production of copper:
Net Chemical Equation
2 [tex]Cu_2S[/tex] (s) + 3 [tex]O_2[/tex] (g) + 2 C (s) → 4 Cu (s) + 2 [tex]SO_2[/tex] (g) + 2 CO (g)
The question is:
There are two steps in the extraction of copper metal from chalcocite, a copper ore. In the first step, copper(I) sulfide and oxygen react to form copper(I) oxide and sulfur dioxide. In the second step, copper(I) oxide and carbon react to form copper and carbon monoxide.
Write the net chemical equation for the production of copper from copper(I) sulfide, oxygen and carbon. Be sure your equation is balanced.
Which statement best compare how coal is formed to the way natural gas and oil are formed
How does a turbine work to produce energy for electricity
Final answer:
Coal is formed from plant matter, while oil and natural gas are derived from marine organisms. A turbine produces electricity by spinning its blades with energy from different sources, transferring this motion to a generator.
Explanation:
The correct statement that compares the formation of coal to the way natural gas and oil are formed is: Coal results from the compressed remains of plant matter. Both oil and natural gas are compressed remains of marine organisms. So the correct answer is B. Coal, oil, and natural gas are all fossil fuels, but they form from different types of organic matter and under varying conditions of heat and pressure.
Coal is typically found as coal seams within rock layers and is formed from ancient swamp vegetation, whereas oil and natural gas originated from microorganisms in prehistoric water bodies and are often found together due to their similar formation processes.
A turbine works to produce energy for electricity by harnessing energy from various sources, such as the wind, water flow, or steam generated from the combustion of fossil fuels, to spin its blades. This motion is transferred to a generator, which converts the kinetic energy into electrical energy. The correct answer that describes this process is A: Energy from sources such as wind or from burning fossil fuels is used to spin the blades of the turbine. The turbine then powers a generator which produces electricity.
Genes help determine a person's traits or characteristics. scientific investigations into genes have helped scientists solve major societal issues. which issue would most likely benefit from these investigations?
A. treating inherited diseases
B. improving nutrition
C. preventing food borne illness
D. accessing clean drinking water
Answer:
The correct answer is option A, that is, treating inherited diseases.
Explanation:
Genetic testing comprises testing the DNA, that is, the chemical database, which conducts instructions for the functions of the body. Investigation of genes can demonstrate modifications in the genes, which may lead to a disease or illness.
If someone is exhibiting signs of a disease, which may be a result of genetic modifications, also known as mutated genes. Then in such cases, the examination of genes can show if one is exhibiting a suspected disorder. For example, genetic testing may be done to confirm a diagnosis of Huntington's disease or cystic fibrosis.
Suppose that a catalyst lowers the activation barrier of a reaction from 125 kj/mol to 57 kj/mol . by what factor would you expect the reaction rate to increase at 25 âc? (assume that the frequency factors for the catalyzed and uncatalyzed reactions are identical.)
Factor would you expect the reaction rate to increase at 25 C is [tex]1.8*10^{12}[/tex]
Explanation:Suppose that a catalyst lowers the activation barrier of a reaction from 125 kj/mol to 57 kj/mol . Assume that the frequency factors for the catalyzed and uncatalyzed reactions are identical: by what factor would you expect the reaction rate to increase at 25 C?
Catalysis is process of increasing the chemical reaction rate by adding a substance known as catalyst. Reaction rate is the speed at which a chemical reaction proceeds. Activation energy is the energy which must be provided to a chemical or nuclear system with potential reactants to result in chemical reaction, nuclear reaction, etc
The rates of reaction question in Kelvin [tex]25 C = 273 + 25 = 298 K[/tex]
The rate constants under catalysed and non‐catalysed conditions:
Catalysed: [tex]k_{cat} = A e^{\frac{-Ea(cat)}{RT} } = A e^{\frac{‐55000}{(8.314 x 298)}} = A e^{-22.2}[/tex]
Uncatalysed: [tex]k_{uncat} = A e^{\frac{-Ea(uncat)}{RT} } = A e^{\frac{‐125000}{8.314* 298} } = A e^{-50.4}[/tex]
Ratio of catalysed to uncatalysed reaction rates is
[tex]\frac{k_{cat}}{k_{uncat}} = \frac{Ae^{-22.2}}{Ae^{-50.4}}[/tex]
The A values are the same for both processes, therefore [tex]\frac{A}{A} = 1[/tex]
[tex]\frac{k_{cat}}{k_{uncat}} =\frac{e^_{-22.2}}{e^{-50.4}} = 1.8 * 10^{12}[/tex]
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The factor by which reaction rate is more in the presence of catalyst as compared to uncatalysed reaction is 1.8 × 10¹².
What is Arrhenius equation?From the Arrhenius equation, we can calculate the effect of chnage in the activation energy as well as of temperature on the rate of the reaction.
Arrhenius equation will be represented as:
[tex]k = Ae^{-Ea/RT}[/tex], where
k = rate constant
A = frequency factor = 1 (given)
Ea = activation energy
R = universal gas constant = 8.314 J/ mol.K
T = temperature = 25 degree celsius = 298 K
Rate of reaction in the presence of catalyst will be calculated as:Activation energy = 57 kJ/mol = 57000 J/mol
[tex]k1 = e^{-57000/8.314\times 298}[/tex] = [tex]e^{-22} \\[/tex]
Rate of reaction in the absence of catalyst will be calculated as:Activation eneregy = 125 kJ/mol = 125000 J/mol
[tex]k2 = e^{-125000/8.314\times 298}[/tex] = [tex]e^{-50.4}[/tex]
Ratio of both the rates will be :
k1/k2 = [tex]e^{-22} \\[/tex] / [tex]e^{-50.4}[/tex] = 1.8 × 10¹²
Hence, the rate is 1.8 × 10¹² times more.
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Epirical formula of P4O10
When vapors of a flammable or combustible liquid are mixed with air in the proportions in the presence of a source of ignition, rapid combustion or an explosion can occur. The proper proportion is called the _______________. A. Boiling range B. Flammable or explosive range C. Flash point
Answer: Option (B) is the correct answer.
Explanation:
When vapors of a flammable or combustible liquid are mixed together with air in the presence of a source of ignition in proportions rapid combustion or an explosion can occur. The proper proportion is called the flammable or explosive range.
Boiling range is defined as the range of temperature which is involved distillation of oil from the starting time to the time till it evaporates.
The lowest temperature at which an ignitable mixture can be formed from a liquid in air near its surface.
As shown in table 15.2, kp for the equilibrium n21g2 + 3 h21g2 δ 2 nh31g2 is 4.51 * 10-5 at 450 °c. for each of the mixtures listed here, indicate whether the mixture is at equilibrium at 450 °c. if it is not at equilibrium, indicate the direction (toward product or toward reactants) in which the mixture must shift to achieve equilibrium. (a) 98 atm nh3, 45 atm n2, 55 atm h2 (b) 57 atm nh3, 143 atm n2, no h2 (c) 13 atm nh3, 27 atm n2, 82 atm h2
A) The direction in which the mixture must shift to achieve equilibrium is;
Left Direction
B) The direction in which the mixture must shift to achieve equilibrium is;
Left Direction
C) The direction in which the mixture must shift to achieve equilibrium is;
Right Direction
Chemical Equilibrium Equations
We are given the balanced equation reaction at equilibrium as;
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
We are given;
Kp value at equilibrium = 4.51 × 10⁻⁵
A) Formula to find Kp in an equilibrium equation is;
Kp = [P(Product)]ⁿ/[P(Reactant 1)]ⁿ * [P(Reactant 2)]ⁿ
Where;
n is the coefficient attached to the respective product or reactant
P is the pressure
At 98 atm of NH₃, 45 atm N₂, 55 atm H₂
Thus;
Kp = [P(NH3)]²/ [P(N₂)] × [P(H2)]³
Kp = 98²/(45 × 55³)
Kp = 1.28 × 10⁻³
This calculated Kp value is greater than the given Kp value at equilibrium and thus the mixture is not equilibrium but it will shift to the left direction towards the reactants to achieve equilibrium.
B) At 57 atm NH₃, 143 atm N₂, No H₂
Thus;
Kp = [P(NH₃)]²/ [P(N₂)]
Kp = 57²/143
Kp = 22.7
This calculated Kp value is greater than the given Kp value at equilibrium and thus the mixture is not equilibrium but it will shift to the left direction towards the reactants to achieve equilibrium.
c) At 13 atm NH₃, 27 atm N2, 82 atm H₂
Thus;
Kp = [P(NH₃)]²/ [P(N₂)] × [P(H₂)]³
Kp = 13²/(27 × 82³)
Kp = 1.14 × 10⁻⁵
This calculated Kp value is less than the given Kp value at equilibrium and thus the mixture is not equilibrium but it will shift to the right direction towards the product to achieve equilibrium.
Read more about Chemical Equilibrium Reactions at; https://brainly.com/question/4289021
what kind of electrochemical cell might likely be used for a task such a electroplating?
Write the equilibrium constant expression for this reaction: h2so4 (aq) → 2h+ (aq) + so−24 (aq)
Answer:
[tex]Keq =\frac{[H+]^{2} [SO4^{2-}]^{2} }{[H2SO4]}[/tex]
Explanation:
The equilibrium constant K is a parameter that relates the concentration of products to that of the reactants at equilibrium and under a given temperature.
Consider a hypothetical reaction:
xA + yB ↔ zC
where A and B are the reactants ; C is the product
x and y are the coefficients of the reactants; z is the product coefficient
The equilibrium constant is given as:
[tex]Keq = \frac{[C]^{z} }{[A]^{x}[B]^{y}}[/tex]
The given reaction is:
[tex]H2SO4(aq)\rightleftharpoons 2H+(aq)+ SO_{4}^{2-}(aq)[/tex]
[tex]Keq =\frac{[H+]^{2} [SO4^{2-}]^{2}}{[H2SO4]}[/tex]