What are the magnitude and direction of the force the pitcher exerts on the ball? (enter your magnitude to at least one decimal place.)?

Answer:

Decreases

Explanation:

Coulomb found that the electric force between two point charges is inversely proportional to the square of the distance that separates them. Therefore, in this case, when the distance increases the repulsion force decreases and when the distance decreases the repulsion force increases.

(a) What is its resistance? Express your answer to two significant figures and include the appropriate units."

(b) How much charge passes through it in 11 min ? Express your answer to two significant figures and include the appropriate units.

Solution

(a) We can calculate the resistance by using Ohm's law:

[tex]\Delta V= I R[/tex]

Since we know that [tex]\Delta V=120 V[/tex] and [tex]I=14.5 A[/tex], we can find R:

[tex]R= \frac{\Delta V}{I} = \frac{120 V}{14.5 A}=8.3 \Omega [/tex]

(b) The current is equal to the quantity of charge by unit of time:

[tex]I= \frac{Q}{t} [/tex]

In our problem, t=11min=660 s, so we can calculate the charge passed through the hair dryer:

[tex]Q=It=14.5 A \cdot 660 s = 9570 C[/tex]

Answer: It has a range of visible and invisible forms of radiation.

Explanation:

Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light i.e [tex]2.998\times 10^8ms^{-1}[/tex]

The electromagnetic radiations consist of radio waves, microwaves, infrared ,Visible , ultraviolet, X rays and gamma rays arranged in order of increasing frequency and decreasing wavelengths.

Only visible light is visible to naked eyes.

The relationship between wavelength and frequency of the wave follows the equation:

[tex]\nu=\frac{c}{\lambda}[/tex]

where,

[tex]\nu[/tex] = frequency of the wave

c = speed of light  

[tex]\lambda [/tex] = wavelength of the wave

From the above relation, it is visible that wavelength and frequency follow inverse relation. For increase in wavelength, the value of frequency decreases and vice-versa.

Answer: Static friction, sliding fiction, fluid fiction, and rolling friction

Explanation: static friction (friction that acts upon unmoving objects), sliding fiction (friction that occurs between two objects sliding past each other), fluid friction (is the force that resists motion when fluid is involved)and the last one is rolling friction (the force between a rolling object and a surface).

The velocity of the oscillating particle at [tex]t=0.4\,{\text{s}}[/tex]  is [tex]\boxed{1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex]  or [tex]\boxed{1.5\times{{10}^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .

Further Explanation:

The position of the oscillating mass is given by:

[tex]x\left(t\right)=\left({2.0\,{\text{cm}}}\right)\cos\left({10t}\right)[/tex]

Here, [tex]x\left(t\right)[/tex]  is the position of the particle at time [tex]t[/tex]  during the oscillation.

The velocity of the oscillating particle is defined as the rate of change of the position of the body. Thus, it can be expressed as the first derivative of the position of the body while it is oscillating.

The velocity of the particle can be expressed as:

[tex]\boxed{v=\frac{{dx\left(t\right)}}{{dt}}}[/tex]

Substitute the equation of the position in above expression.

[tex]\begin{aligned}v&=\frac{d}{{dt}}\left({\left({2.0\,{\text{cm}}}\right)\cos\left({10t}\right)}\right)\\&=-\left({2.0\,{\text{cm}}}\right)\sin\left({10t}\right)\\\end{aligned}[/tex]

Now, we are to obtain the velocity of the oscillating particle at time [tex]t=0.4\,{\text{s}}[/tex] . So, substitute [tex]0.4[/tex]  for  [tex]t[/tex] in above equation of velocity.

[tex]\begin{aligned}v&=-\left({2.0\,{\text{cm}}}\right)\sin\left({10\times0.4\,{\text{rad}}}\right)\\&=-2.0\times\left({-0.75}\right)\\&=1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]

The velocity of the oscillating particle in [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] while it oscillates is given as:

[tex]\begin{aligned}v&=1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\left({\frac{{1\,{\text{m}}}}{{100\,{\text{cm}}}}}\right)\\&=1.5\times{10^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]

Thus, the velocity of the oscillating particle at [tex]t=0.4\,{\text{s}}[/tex]  is [tex]\boxed{1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] or [tex]\boxed{1.5\times{{10}^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .

Learn More:

1. The position of a 2.75×105n training helicopter under test is given by r⃗ =(0.020m/s3)t3i^+(2.2m/s)tj^−(0.060m/s2)t2k^ https://brainly.com/question/6125929

2. Which of the following are units for expressing rotational velocity, commonly denoted by  https://brainly.com/question/2887706

3. A sound wave is described by d(y,t)=(0.0200mm)× sin[(8.96rad/m)y+(3140rad/s)t https://brainly.com/question/3619541  

Answer Details:

Grade: College

Subject: Physics

Chapter: Oscillation

Keywords:

Position, 55g particle9t, oscillating mass, velocity at, t=0.40 s, position of particle, rate of change of position, x(t)=(2.0 cm)cos(10t).

The correct answer is B) Nitrogen and oxygen

Explanation:

The atmosphere refers to the gaseous layer that covers a body such as a planet. The composition of the atmosphere varies according to the planet or body and therefore the elements found on it are different. In the case of our planet, the atmosphere is mainly composed of nitrogen and oxygen as these are 99% of the atmosphere, while other elements such as carbon dioxide represent the 1% missing. Also, the atmosphere is divided into different layers according to heigh this includes the troposphere, stratosphere, among others. Thus, 99 percent of the Earth's atmosphere is made up only of nitrogen and oxygen.

Answer : The purpose of the zigzag line on the periodic table is to separates the metal from the non-metal.

Explanation :

Metalloids : These are the elements that shows both the property of metals and non-metals.

For example : Boron, silicon, germanium, arsenic, antimony, tellurium, polonium and astatine are the metalloids.

Metalloids separates the metals from the non-metals.

The zigzag line on the periodic table represent the metalloids.

Non-metals are found to the right side of the zigzag line that gains electrons to attain stability.

Metals are found to the left side of the zigzag line that loses electrons to attain stability.

Hence, the purpose of the zigzag line on the periodic table is to separates the metal from the non-metal.

Final answer:

The minimum constant acceleration required for an aircraft to become airborne after a takeoff run of 277 meters is [tex]2.25 m/s^2[/tex] when converting the liftoff speed from km/h to m/s and applying the kinematic equation.

Explanation:

To determine the minimum constant acceleration required for an aircraft to become airborne after a takeoff run of 277 meters, we can use the kinematic equation:

[tex]$$ v^2 = u^2 + 2as $$[/tex]

Where:

v is the final velocity (liftoff speed), which needs to be converted from 127 km/h to m/s.

u is the initial velocity, which is 0 m/s since the aircraft starts from rest.

a is the acceleration, which we are trying to find.

s is the displacement, which is the distance of the takeoff run (277 m).

First, we convert the liftoff speed to m/s:

[tex]$$ 127 km/hr \times \frac{1000 m}{1 km} \times \frac{1 h}{3600 s} = 35.28 m/s $$[/tex]

Now we can use the kinematic equation to solve for a:

[tex]$$ 35.28^2 = 0^2 + 2a \times 277 $$ $$ a = \frac{35.28^2}{2 \times 277} = \frac{1244.6784}{554} = 2.2465 \frac{m}{s^2} $$[/tex]

The minimum constant acceleration required for the aircraft to be airborne is [tex]2.25 m/s^2[/tex] (rounded to two decimal places).

Final answer:

In physics, the maximum static frictional force equals the coefficient of static friction times the normal force. Once the crate starts slipping, the force of kinetic friction applies, and acceleration can be calculated using Newton's second law of motion.

Explanation:

The question involves concepts from Physics, specifically dealing with static friction and Newton's second law of motion. The maximum force that can be exerted on a wooden crate without moving it is equal to the maximum static frictional force. This force can be found by multiplying the coefficient of static friction (μ) between the wooden crate and the wood floor by the normal force, which, in this case, is equal to the gravitational force acting on the crate (mass × acceleration due to gravity, g).

If the static frictional force is overcome and the crate begins to slide, and assuming the applied force remains constant, we switch to dealing with kinetic friction. The magnitude of kinetic friction is usually lower than static friction. To find the acceleration of the crate once it starts moving, you would subtract the kinetic friction force from the applied force and then divide by the crate's mass, according to Newton's second law (F = ma).

For example, consider the question (a) What is the maximum force you can exert horizontally on a 120-kg wooden crate without moving it? The answer would be the product of the coefficient of static friction and the normal force, which equals the weight of the crate. If given (for example, μ=0.5), the calculation would be 588 N. For part (b), if the creates starts to slip, we then use Newton's second law to determine the magnitude of the crate's acceleration, which would be the net force divided by the crate's mass, resulting in an acceleration of 1.96 m/s².

Final answer:

Isabel is using her implicit procedural memory, a form of long-term memory responsible for automatic skills, to recall how to use a manual stick shift after primarily driving an automatic car.

Explanation:

Isabel is utilizing her implicit procedural memory to recall how to shift gears in a stick shift car after having driven an automatic vehicle for many years. Procedural memory is a form of long-term memory that enables people to perform tasks without conscious awareness of the learned skills, such as riding a bike, typing on a keyboard, or driving. In this case, Isabel's ability to revert to using a manual stick shift despite the extended use of an automatic car illustrates the durability and automaticity of procedural memory.

Final answer:

The current is 1.01 x 10^-11 A and 5.4 x 10^7 Na+ ions flow in 0.86 s.

Explanation:

In order to find the current, we can use Ohm's Law which states that current (I) is equal to the potential difference (V) divided by the resistance (R). So, the current can be calculated as:

I = V / R

Substituting the given values:
I = (69 mV) / (6.8 × 109 Ω)

I = 1.01 × 10-11 A

For part (b), we need to find the number of Na+ ions (q = +e) that flow in 0.86 s. We can use the equation:

q = I × t

Substituting the known values:
q = (1.01 × 10-11 A) × (0.86 s)

q = 8.7 × 10-12 C

Since 1 Na+ ion has a charge of +e, where e is the elementary charge (1.6 × 10-19 C), we can calculate the number of ions:

Number of ions = q / e = (8.7 × 10-12 C) / (1.6 × 10-19 C)

Number of ions = 5.4 × 107 Na+ ions

In a parallel circuit, the brightness of the remaining bulbs isn't affected when one bulb goes bad or is disconnected. This is because each bulb has its own path to the voltage source, and neither the voltage nor the redistributed current through each bulb is affected by the removal of one bulb. Contrarily, in a series circuit, all bulbs would go dark.

In a parallel circuit with several identical light bulbs of equal resistance, when one bulb goes bad or is disconnected, it doesn't affect the brightness of the other bulbs. This is because in a parallel circuit, each bulb has its own separate path to the voltage source. Therefore, the removal of one path (the bad or disconnected bulb) doesn't affect the potential difference or voltage across the other bulbs.

Let's take the two primary variables determining the brightness of a bulb - the voltage and current. In a parallel circuit, the voltage across each bulb remains the same, regardless of whether a bulb is removed or not. On the other hand, current, though different for each bulb depending on its resistance, isn't affected by the removal of one bulb because the total current just gets redistributed through the remaining paths, maintaining the original brightness of the other bulbs.

In contrast, if this were a series circuit, the scenario would be different. In a series circuit, the removal or failure of one bulb would disrupt the entire circuit (since there's only one path for the current to flow), causing all other bulbs to go dark.

https://brainly.com/question/11409042

#SPJ3

Answer:

15 m/s

Explanation:

Answer:

Its C

Explanation:

thank me later

Eddie's initial velocity as he left the ramp is calculated as 28.61 m/s

This physics problem involves two-dimensional motion or projectile motion. We can solve it by using the principles of conservation of energy and kinematics. The final horizontal velocity (vxf) can be calculated using the final velocity (v) and the angle (θ) below the horizontal through the formula vxf = v * cos(θ), which in this case gives us 33 * cos(30°) = 28.6 m/s. Since there's no horizontal acceleration involved in Eddie's jump, the initial horizontal velocity (vxi) equals the final horizontal velocity (vxf), hence vxi = 28.6 m/s.

Now, we can use the horizontal displacement (Δx) and vxi to calculate the total time of flight using the formula Δx = vxi * t, so the time of flight (t) = Δx / vxi = 72.1 m / 28.6 m/s = 2.52 s. Finally, using the time of flight, final vertical velocity (vyf), and the acceleration due to gravity (g), we can find the initial vertical velocity (vyi) using the formula vyf = vyi + g * t. Substituting the given values, we get - 33 * sin(30) = vyi - 9.8 * 2.52, which gives us vyi = -1.1 m/s.

As the last step, we find the magnitude of the initial velocity from the resultant of its vertical and horizontal components using the Pythagorean theorem: vi = sqrt[(vxi^2) + (vyi^2)], which comes out to be sqrt[(28.6^2) + (-1.1^2)] = 28.61 m/s.

https://brainly.com/question/35479651

#SPJ2

The absolute pressure at a depth of 15.0m below the surface of the ocean is 150975 Pa.

To calculate the absolute pressure at a depth of 15.0m below the surface of the ocean, we need to consider the pressure due to the weight of the water column above that point.

The pressure due to the weight of a fluid is given by the equation P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.

Substituting the given values, we have P = (1025 kg/m3) × (9.8 m/s2) × (15.0m) = 150975 Pa.

Therefore, the absolute pressure at a depth of 15.0m below the surface of the ocean is 150975 Pa.

Answer: B) Iron rusts in water.

Explanation:

Physical property is defined as the property of a substance which becomes evident during physical changes. Example: Melting point  , electrical conductivity, malleability,

Chemical property is defined as the property of a substance which becomes evident during chemical changes. Example: Reactivity with other substances

Rust is hydrated ferric oxide [tex](Fe_2O_3.xH_2O[/tex].

[tex]Fe\rightarrow Fe^{2+}+2e^-[/tex]

Corrosion of iron is called as rusting. Rust is hydrated ferric oxide [tex](Fe_2O_3.xH_2O[/tex].

[tex]Fe\righatarrow Fe^{2+}+2e^-[/tex]

[tex]O_2+4H^++4e^-\rightarrow 2H_2O[/tex]

[tex]4Fe^{2+}+O_2+4H_2O\rightarrow 2Fe_2O_3+8H^+[/tex]

Thus rusting of iron is a chemical property.

Answer: B) Iron rusts in water.