Explanation:
Given that,
(a) Frequency, [tex]f_1=4\times 10^{19}\ Hz[/tex]
All electromagnetic wave moves with the speed of light. It is given by :
[tex]c=f\lambda[/tex]
[tex]\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{4\times 10^{19}}\\\\\lambda_1=7.5\times 10^{-12}[/tex]
(b) Frequency, [tex]f_2=5.5\times 10^{1=9}\ Hz[/tex]
All electromagnetic wave moves with the speed of light. It is given by :
[tex]c=f\lambda[/tex]
[tex]\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{5.5\times 10^{9}}\\\\\lambda_2=0.054\ m[/tex]
Hence, this is the required solution.
A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the particle between t=0.00 seconds and t=5.00 seconds. find the speed v of the particle at t=5.00 seconds?
Answer:
43 m/s
Explanation:
Mass, m = 5 kg
Force, F(t) = 6t² - 4t + 3
To find the speed, we first need to get the acceleration, a.
Force is the product of mass and acceleration. It is given as:
F = ma
Therefore, acceleration is:
a(t) = F(t)/m
a(t) = (6t² - 4t + 3) / 5
a(t) = 1.2t² - 0.8t + 0.6
Acceleration is the differentiation of velocity with respect to time, t. Therefore, to get velocity, v, we integrate a(t):
a(t) = dv(t) / dt
=> v(t) = (1.2/3)t³ - (0.8/2)t² + 0.6t
v(t) = 0.4t³ - 0.4t² + 0.6t
Therefore, at time t = 5secs, velocity is:
v(5) = 0.4 * (5³) - 0.4 * (5²) + 0.6 * 5
v(5) = 50 - 10 + 3
v(5) = 43 m/s
The velocity at time, t = 5 secs is 43 m/s
The incoming infrared radiation from the Sun as it travels towards Earth is _____. mostly reflected back out into space mostly absorbed and transmitted toward Earth's surface equally absorbed and reflected completely blocked and reflected by the upper atmosphere
Answer:
Mostly absorbed and transmitted toward Earth's surface
Explanation:
Infrared radiation from the sun reaches the Earth's surface and warms the Earth's surface. It emits some infrared radiation, some absorbed by gases such as carbon dioxide in the atmosphere. This is known as the greenhouse effect. and If it don't, radiation from the earth is powerful enough to burn the skin.
so correct answer is Mostly absorbed and transmitted toward Earth's surface
Answer:
mostly absorbed and transmitted toward Earth's surface
Explanation:
Degeneracy pressure stops the crush of gravity in all the following except
Answer:
A very massive main- sequence star
Explanation:
Degeneracy pressure refers to pressure expend by dense material , which is composed of fermions, which is an example of electrons in a white dwarf star. According to Pauli exclusion principle, which states that no two fermions can exist in the same quantum state, actually give details about the pressure.
When there is stellar masses that is less than about 1.44 of that of solar masses, there will be gravitational fall in the energy , and the energy will not be sufficient to produce the neutrons of a neutron star, therefore, the fall is abstruptly stopped through the electron degeneracy to form white dwarfs.this result to the creation of an effective pressure that further prevents gravitational fall.
If an electronin an electron beam experiences a downward force of 2.0x10^-14N while traveling in a magnetic field of 8.3x10^-2T west, what is the direction and the magnitude of the velocity?
Answer:
Explanation:
Given that,
Force is downward I.e negative y-axis
F = -2 × 10^-14 •j N
Magnetic field is westward, +x direction
B = 8.3 × 10^-2 •i T
Charge of an electron
q = 1.6 × 10^-19C
Velocity and it direction?
Force in a magnetic field is given as
F = q(V×B)
Angle between V and B is 270, check attachment
The cross product of velocity and magnetic field
F =qVB•Sin270
2 × 10^-14 = 1.6 × 10^-19 × V × 8.3 × 10^-2
Then,
v = 2 × 10^-14 / (1.6 × 10^-19 × 8.3 × 10^-2)
v = 1.51 × 10^6 m/s
Direction of the force
Let x be the direction of v
-F•j = v•x × B•i
From cross product
We know that
i×j = k, j×i = -k
j×k =i, k×j = -i
k×i = j, i×k = -j OR -k×i = -j
Comparing -k×i = -j to given problem
We notice that
-F•j = q ( -V•k × B×i)
So, the direction of V is negative z- direction
V = -1.51 × 10^6 •k m/s
What is the equivalent resistance in this circuit?
Ω
What is the current in this circuit?
A
Answer:
6.0?
Explanation:
What is the current in this circuit?
A
Hold on, our servers are swamped. Wait for your answer to fully load.
Answer:
The first one is 15.
The second one is 3.0.
Explanation:
You add up all the sides accept the voltage. 2+3+4+6= 15
For the second one you divide the voltage by all the resisters. 45/15=3
A force F acts in the forward direction on a cart of mass m. A friction force ff opposes this motion. Part A Use Newton's second law and express the acceleration of the cart. Express your answer in terms of the variables F, f, and m.
The acceleration of the cart can be calculated using the equation a = (F - f) / m, where F is the applied force, f is the friction force, and m is the mass of the cart.
Explanation:The acceleration of the cart can be expressed using Newton's second law, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Therefore, the acceleration (a) of the cart can be calculated using the equation:
a = (F - f) / m
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El vector a tiene componented ax= 2.70 cm, ay=2.25 cm; y el vector b tiene componentes bx= 0.30 cm, by= 1.75 cm. Calcular las componentes de la resultante a+b
Answer:
Explanation:
Given that,
A vector A has x component to be 2.7cm and y component to be 2.25cm
Then,
A = 2.7•i + 2.25•j
A vector B has x component of 0.30cm and y component of 1.75cm
B = 0.3•i + 1.75•j
So, we want to find A+B
Addition of vectors
Generally
(a•i + b•j) + (c•i + d•j) = (a+c)•i +(b+d)•j
Vectors are added component wise.
So,
A + B = (2.7•i + 2.25•j) + (0.3•i + 1.75•j)
A + B = (2.7 + 0.3)•i + (2.25 + 1.75)•j
A + B = 3•i + 4•j
We can also find it magnitude and direction
Generally,
A = a•i + b•j
|A| = √(a²+b²)
<A = arctan(b/a)
So,
|A+B| = √(3²+4²) = √9+16 = √25
|A+B| = 5
And it's direction
< = arctan(y/x)
< = arctan(4/3)
< = 53.13°
why hot air balloon rises up in air n large ships Floyd in water
Answer:
Hot air is less dense than cool air; the heated air causes the balloon to rise simply because it is lighter than an equal volume of cold air.So hot air balloon rises up in air.
Large ships float in water as their density is lesser than the water so.
Why do you think the combined wave is more powerful than either the transverse or longitudinal wave with the same amplitude
Answer:
Explanation:
The combined wave only end up been more powerful than the Longitudinal wave. This means, the transverse wave is more powerful than the combined wave. In transverse wave, the oscillation is perpendicular to the direction of the wave, while in longitudinal wave, the motion of the movement of the object is parallel to the movement of the wave. And in combined wave, the movement of the medium is in a circular manner,
On a merry-go-round, animals at the edge are located 4 times farther from the axis of rotation than the animals near the center. The animals near the center has a rotational speed of 3 RPM and a tangential speed of 2 m/sec.
What is the rotational speed of the animals near the edge?
a 3 RPM
b 12 RPM
c 2 RPM
d 6 RPM
Answer:
12 RPM
Explanation:
I would calculate the distance from the edge to the center, and then multiple that by 3RPM with 2 m/sec
A block of mass = 4.00 kg is supported by a spring scale with unit of measure of Newtons. This spring scale is attached to top of an elevator. The elevator accelerates upward with a = 3.00 m/sec2. What is the reading on the spring scale to 3 significant figures?
Answer:
118 N
Explanation:
Given mass of the block, m = 4.00kg.
The acceleration of the elevator, a = 3.0 m/s^2.
As elevotar attaced with spring scale and accelerating upward
(block and elevator), so total force
[tex]F_N-mg=ma[/tex]
Here, mg is the weight of the block downward direction.
or
[tex]F_N=ma+mg=m(g+a)[/tex]
substitute the given value, we get
[tex]F_N=4kg(9.8m/s^2+3m/s^2)[/tex]
= 117.6 N = 118 N.
Thus, the reading on the spring scale to 3 significant figures is 118 N.
Will water flow more easily through a wide pipe or a narrow pipe? Will current flow more easily through a thick wire or a thin wire?
Answer:
Explained below.
Explanation:
The water will flow more easily through a wide pipe, because as we know that if the diameter of the pipe is wider than the flow of water will be more.
And same case will be applied with the electric current, if the is wire thicker then the flow of the current will be more easy and the charge will also flow easily.
The starting conditions of an oscillator are characterized by the
Answer:
The phase constant
Explanation:
The phase constant tells how much a signal is shifted along the x-axis. A phase constant of ϕ means that each value of the signal happens ϕ amount of time earlier. If the signal has a beginning, then a phase constant of ϕ means the signal occurs that much sooner.
The starting conditions of an oscillator are characterized by the phase constant. Option B is correct.
Phase Constant:
This represents the number of oscillation per cycle of wave. It is denoted by [tex]\bold {\phi}[/tex]. It is also known as Propagation constant. The phase constant can be calculated using the formula.
[tex]\bold {\phi = \dfrac {2\pi }{\lambda}}[/tex]
Where, lambda is wavelength.
Frequency is the number of waves passing from a point per unit time.Amplitude is the height of the wave from its mid point.Therefore, option B is correct. The starting conditions of an oscillator are characterized by the phase constant.
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How does atmospheric pressure affect the boiling point of a liquid
Answer:
The atmospheric pressure and boiling point are directly proportional
Increasing atmospheric pressure increases the boiling point also
Explanation:
The atmosphere contain molecules that are in constant motion. They exert a downward force on a liquid’s surface. The higher the air pressure, the harder it is for the liquid to evaporate. Therefore, the boiling point of a solvent or liquid is affected by the atmospheric pressure and boiling point is raised.
A liquid in a high pressure environment boils at a higher temperature.
When placed in a lower pressure environment it boils at a lower temperature.
A bat locates insects by emitting 25.3 kHz ultrasonic chirps and then listening for echoes from insects flying around it. Humans can hear sounds with frequencies up to 20 kHz. How fast would a bat have to fly and in which direction (positive away from and negative towards a stationary human listener) in order for a person to hear these chirps
Answer:
Speed at which the bat have to fly is 90.895 m/s away from the human (listener) in positive direction.
Explanation:
Given:
Frequency of the bat that is source here, [tex]f_S[/tex] = 25.3 kHz = 25.3 * 10^3 Hz
Frequency of the listener (human), [tex]f_L[/tex] = 20 kHz = 20*10^3 Hz
We have to identify how fast the bat have to fly in order for a person to hear these chirps .
Let the velocity of bat that is source is "Vs" and "Vs" = "Vbat".
Doppler effects formulae :
When the source is receding (moving away) [tex]f_L=(\frac{V+V_L}{V+V_S}) f_S[/tex] When the source is approaching [tex]f_L=(\frac{V+V_L}{V-V_S}) f_S[/tex] Speed of sound in [tex]V_S =433.895-343[/tex]the air (medium), [tex]V = 343\ ms^-^1[/tex]Using the above formula and considering that the bat is moving away so that the human can listen the chirps also [tex]V_L=0[/tex] as listener is stationary.
⇒ [tex]f_L=(\frac{V+V_L}{V+V_S}) f_S[/tex] ⇒ [tex]f_L=(\frac{V+0}{V+V_S}) f_S[/tex]
Re-arranging in terms of Vs.
⇒ [tex]V+V_S =\frac{V\times f_S}{f_L}[/tex]
⇒ [tex]V_S =\frac{V\times f_S}{f_L}-V[/tex]
⇒ [tex]V_S =\frac{343\times 25.3\times 10^3}{20\times 10^3}-343[/tex]
⇒ [tex]V_S=90.895[/tex] m/s
The speed at which the bat have to fly is 90.895 m/s away from the human (listener) in positive direction.
In an adiabatic process oxygen gas in a container is compressed along a path that can be described by the following pressure p, in atm, as a function of volume V, in liters: p = p0 V-6/5. Here p0 is a constant of units atm⋅L6/5. show answer Incorrect Answer 50% Part (a) Write an expression for the work W done on the gas when the gas is compressed from a volume Vi to a volume Vf.
The work done on the gas during an adiabatic compression process is calculated by integrating the pressure as a function of volume from the initial volume to the final volume. In this case, the integral ∫from V(i) to V(f) p₀ V^(-6/5) dV provides the value for the work done.
Explanation:In an adiabatic process, the work done W on the gas when it's compressed from a volume V(i) to a volume V(f) can be calculated by integrating the pressure-volume equation over the given volume range.
Given the pressure equation p = p₀ V^(-6/5), the work done on the gas (W) can be computed by the integral formula for work: W = ∫p dV = ∫from Vi to Vf p₀ V^(-6/5) dV. Evaluating this integral gives the work done on the gas during the compression process in the adiabatic process.
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During a redox reaction the molecule that gains an electron is
In a redox (reduction-oxidation) reaction, the molecule that gains an electron is reduced. Reduction and oxidation always occur together in such reactions. Reduced molecules often act as energy carriers in metabolic pathways.
Explanation:During a redox (reduction-oxidation) reaction, the molecule that gains an electron is referred to as being reduced. This process is accompanied by an energy transfer. When a molecule loses an electron (a process termed as oxidation), energy is released; this energy and the electron are then transferred to another molecule, resulting in reduction of that molecule. These two processes, oxidation and reduction, always occur together in a redox reaction.
For example, considering a metabolic pathway involving Nicotinamide adenine dinucleotide (NAD+), when it accepts a hydride ion (H-) from a hydrogen atom, it gets reduced to form NADH. Here, NAD+ is the molecule that gets reduced in this redox reaction.
In summary, in redox reactions, the molecule that gains an electron and is reduced can act as an energy carrier, an important function in metabolism, facilitating the controlled transfer of energy within the cell. The concepts of oxidation and reduction are integral to understanding energy extraction and utilization in cells.
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The top and bottom surfaces of a metal block each have an area of A = 0.030 m 2, and the height of the block is d = 0.11 m. At the top surface of the block, a force F1 is applied to the right, while at the bottom surface of the block, a force F2 is applied to the left, causing a shear in the metal block. If F1 = F2 = 30 ⨯ 106 N and the displacement between the two edges due to the shear is 1.12 10-3 m, what is the shear modulus of the metal
Answer:
Shear modulus is equal to [tex]9.82\times 10^{10}N/m^2[/tex]
Explanation:
We have given area [tex]A=0.030m^2[/tex]
Force is given [tex]F_1=F_2=30\times 10^6N[/tex]
Height of the block d = 0.11 m
Change in height of the block [tex]\Delta d=1.12\times 10^{-3}m[/tex]
Stress is given by
[tex]stress=\frac{force}{area}[/tex]
[tex]stress=\frac{30\times 10^6}{0.030}=10^9N/m^2[/tex]
Strain is equal to
[tex]strain=\frac{\Delta d}{d}[/tex]
[tex]strain=\frac{1.12\times 10^{-3}}{0.11}=10.18\times 10^{-3}[/tex]
Shear modulus is equal to
Shear modulus [tex]=\frac{stress}{strain}[/tex]
[tex]=\frac{10^9}{10.18\times 10^{-3}}=9.82\times 10^{10}N/m^2[/tex]
A sound wave (a periodic longitudinal wave) from a loudspeaker travels from air into water. The frequency of the wave does not change, because the loudspeaker producing the sound determines the frequency. The speed of sound in air is 343 m/s, whereas the speed in fresh water is 1482 m/s. When the sound wave enters the water, does its wavelength increase, decrease, or remain the same
Answer:
When the sound wave enters the water its wavelength increase.
Explanation:
Given:
Speed of sound in air [tex]v = 343 \frac{m}{s}[/tex]
Speed of sound in fresh water [tex]v' = 1482 \frac{m}{s}[/tex]
We know that when wave travel into one medium to another medium frequency doesn't change.
Velocity is given by,
[tex]v = f \lambda[/tex]
In above equation frequency is constant,
So when sound wave enters the water wavelength increase because speed sound is increase in water as compare to air.
Therefore, when the sound wave enters the water its wavelength increase.
A form of charge designated as negative positive or neutral is called
Answer:
Electrical charge
Explanation:
Electrical Charge is a form of charge, designated negative, positive, or neutral (without charge) that is found on the subatomic particles that make up all atoms
Suppose you are 3.3km away from a rifle range where someone is practicing shooting. How long would it take you to hear the sound of a shot fired by him?
Can you guys answer quickly, its urgent.
Answer:9.5 seconds(approx.)
Explanation:time=distance/speed
here,
distance=3.3 km= 3300 m
standard speed of sound=344 m/s
so, time=3300/344
time=9.5(approx.)
Final answer:
It would take approximately 9.71 seconds for the sound of a shot to travel 3.3 km and reach you, using the speed of sound of 340 m/s.
Explanation:
To calculate how long it would take for you to hear the sound of a shot fired from 3.3 km away, we need to use the speed of sound. In general, the speed of sound is approximately 340 meters per second (m/s) at sea level under normal conditions. Therefore, we can use the formula:
Time = Distance / Speed of Sound.
Now we simply plugin the values to get:
Time = 3300 meters / 340 m/s = 9.71 seconds
Therefore, it would take approximately 9.71 seconds for the sound of the shot to travel 3.3 km and reach you.
Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 1515 grams and velocity of 77 centimeters per second has a kinetic energy of 147147 ergs. Find the kinetic energy for a mass of 1010 grams and velocity of 99 centimeters per second?
Answer:
The second kinetic energy is 162 J.
Explanation:
Given that,
Mass, [tex]m_1=15\ g[/tex]
Velocity, [tex]v_1=7\ cm/s[/tex]
Kinetic energy, [tex]K_1=147\ ergs[/tex]
Mass, [tex]m_2=10\ g[/tex]
Velocity, [tex]v_2=9\ cm/s[/tex]
We need to find kinetic energy [tex]K_2[/tex]. Kinetic energy is given by :
[tex]K=\dfrac{1}{2}mv^2[/tex]
So,
[tex]\dfrac{K_1}{K_2}=\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}\\\\K_2=\dfrac{K_1}{\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}}\\\\K_2=\dfrac{147}{\dfrac{15}{10}\times \dfrac{7^2}{9^2}}\\\\K_2=162\ J[/tex]
So, the second kinetic energy is 162 J.
The electric power consumed by a circuit with one light bulb is 24 W. The voltage of the battery is 3 V. What is the current in the circuit?
Answer:
8 ampere
Explanation:
P= V x I
so
I = P/V
I= 24 /3
I = 8 A
During which phase of the moon may a lunar eclipse occur?
Answer: New moon
Explanation: A solar eclipse is only possible during a new moon phase
Write down the (real) electric and magnetic fields for a monochromatic plane wave of amplitude E0 , frequency w, and phase angle zero that is (a) traveling in the negative x direction and polarized in the z direction; (b) traveling in the direction from the origin to the point (1, 1, 1), with polarization parallel to the xz plane. In each case, sketch the wave, and give the explicit Cartesian components ofk and ii.
Answer:
a) the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis
b) the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)
Explanation:
a) the polarization the determined wave oscillates the electric field, which is the z axis
As the wave travels on the negative x-axis and the magnetic field is perpendicular, this field goes on the positive y-axis
the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis
be) in the case of a polarization in the xi plane the magnetic field must go in the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)
A uniform horizontal beam 4.0 m long and weighing 200 N is attached to the wall by a pin connection that allows the beam to rotate. It is supported by a cable that makes an Angle of 53 degrees with the horizontal. If the person of weight 350 N stands 1.50 m from the wall. Find the magnitude of the tension T in the cable. (Show your workout instead of giving the final answer).
The magnitude of the tension T in the cable is approximately 468.164 N.
To find the tension T in the cable supporting the beam, we can analyze the forces acting on the beam in equilibrium.
First, let's consider the forces acting on the beam:
1. The weight of the beam, acting downward at its center (2.0 m from the wall).
2. The tension T in the cable, acting upward and at an angle of 53 degrees with the horizontal.
3. The reaction force at the pin connection, acting horizontally to the left.
4. The vertical force exerted by the person standing on the beam, which contributes to the vertical component of the tension in the cable.
The beam is in equilibrium, so the sum of the torques about any point must be zero. Let's take moments about the pin connection at the wall.
Clockwise torques:
- Weight of the beam: [tex]\(200 \, \text{N} \times 2.0 \, \text{m}\)[/tex]
- Vertical component of the tension: [tex]\(T \times \cos(53^\circ) \times 1.5 \, \text{m}\)[/tex]
Counterclockwise torques:
- Tension in the cable: [tex]\(T \times \sin(53^\circ) \times 1.5 \, \text{m}\)[/tex]
- Vertical force exerted by the person: [tex]\(350 \, \text{N} \times 1.5 \, \text{m}\)[/tex]
Since the beam is in equilibrium, these torques must balance:
[tex]\[ 200 \, \text{N} \times 2.0 \, \text{m} + T \times \cos(53^\circ) \times 1.5 \, \text{m} = T \times \sin(53^\circ) \times 1.5 \, \text{m} + 350 \, \text{N} \times 1.5 \, \text{m} \][/tex]
Now, we can solve for T:
[tex]\[ 400 \, \text{N} + T \times \cos(53^\circ) \times 1.5 \, \text{m} = T \times \sin(53^\circ) \times 1.5 \, \text{m} + 525 \, \text{N} \][/tex]
[tex]\[ 400 \, \text{N} = T \times \sin(53^\circ) \times 1.5 \, \text{m} - T \times \cos(53^\circ) \times 1.5 \, \text{m} + 525 \, \text{N} \][/tex]
[tex]\[ 400 \, \text{N} = T \times (\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m} + 525 \, \text{N} \][/tex]
[tex]\[ T \times (\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m} = 125 \, \text{N} \][/tex]
[tex]\[ T = \frac{125 \, \text{N}}{(\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m}} \][/tex]
Now, we can calculate T:
[tex]\[ T = \frac{125 \, \text{N}}{(\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T = \frac{125 \, \text{N}}{(\sin(53^\circ) - \cos(53^\circ)) \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T \approx \frac{125 \, \text{N}}{(0.7986 - 0.6206) \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T \approx \frac{125 \, \text{N}}{0.178 \times 1.5 \, \text{m}} \][/tex]
[tex]\[ T \approx \frac{125 \, \text{N}}{0.267 \, \text{m}} \][/tex]
[tex]\[ T \approx 468.164 \, \text{N} \][/tex]
So, the magnitude of the tension T in the cable is approximately 468.164 N.
Compute the quantity of heat released by 25.0 g of steam initially at 100.0oC, when it is cooled to 34.0°C and by 25.0 g of water initially at 100.0 oC, when it is cooled to 34.0°C.
Answer:
For steam, heat released E = 15.26KJ
For water, heat released E2 = 6.91KJ
Explanation:
Given;
Mass(steam) ms = 25g
Mass (water) mw = 25g
Change in temperature of both steam and water ∆T = 100-34= 66°C
Specific heat of water C = 4.186 J/g.°C
Specific Latent heat L = 334J/g
For steam;
Heat released E = msL + msC∆T
E = (25×334) + (25×4.186×66)
E = 15256.9J
E = 15.26KJ
For water;
Heat released E2 = mwC∆T
E2 = 25×4.186×66
E2 = 6906.9J
E2 = 6.91KJ
Identify which type of natural selection is described in each case below.
Results in the evolution of the species:
Results in new species:
Favors traits at the two extremes:
No increase in diversity:
One extreme trait is favored:
Diversity decreases:
Diversity increases:
Answer:
1.) A
2.) B
3.) B
4.) A
5.) A
6.) C
7.) B
Explanation:
Answer:
A directional selection
B disruptive selection
B disruptive selection
A directional selection
A directional selection
C stabilizing selection
B disruptive selection
Explanation:
A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 290 N applied to its edge causes the wheel to have an angular acceleration of 0.814 rad/s2.What is the mass of the wheel?
Answer:
The mass of the wheel is 2159.045 kg
Explanation:
Given:
Radius [tex]r = 0.330[/tex]
m
Force [tex]F = 290[/tex] N
Angular acceleration [tex]\alpha = 0.814 \frac{rad}{s^{2} }[/tex]
From the formula of torque,
Γ [tex]= I\alpha[/tex] (1)
Γ [tex]= rF[/tex] (2)
[tex]rF = I \alpha[/tex]
Find momentum of inertia [tex]I[/tex] from above equation,
[tex]I = \frac{rF}{\alpha }[/tex]
[tex]I = \frac{0.330 \times 290}{0.814}[/tex]
[tex]I = 117.56[/tex] [tex]Kg. m^{2}[/tex]
Find the momentum inertia of disk,
[tex]I = \frac{1}{2} Mr^{2}[/tex]
[tex]M = \frac{2I}{r^{2} }[/tex]
[tex]M = \frac{2 \times 117.56}{(0.330)^{2} }[/tex]
[tex]M = 2159.045[/tex] Kg
Therefore, the mass of the wheel is 2159.045 kg
Sound waves are converted into mechanical movements by the
Answer:
a.auditory ossicles
b.oval window
c.Round window
d.tympanic membrane
Answer is tympanic membrane
Explanation:
The tympanic membrane otherwise called the ear drum is a membrane shaped like a cone,it connects the outside to the inner ear,it serves to convert vibration from air into fluid membrane vibration a good example of mechanical waves for onwatd transmission into the cochlea of the inner ear through the oval window
Sound waves are converted into mechanical movements by the ear, specifically through structures in the middle and inner ear. The eardrum, ossicles, and cochlea play significant roles in this process, with the final conversion to electrical signals occurring in the cochlea.
Explanation:Sound waves are converted into mechanical movements by the ear, specifically the structures within the middle and inner ear.
When sound waves enter the ear, they strike the eardrum or tympanic membrane in the middle ear, causing it to vibrate. These vibrations are then transferred to three tiny bones in the middle ear called the ossicles, consisting of the malleus, incus, and stapes. The vibrations move these bones, with the stapes pushing into the oval window of the cochlea in the inner ear.
The cochlea is filled with fluid and lined with tiny hair-like structures called stereocilia. The mechanical movement from the ossicles creates waves in this fluid, which cause the stereocilia to move. This movement is converted into electrical signals that the brain interprets as sound.
Learn more about Sound conversion in ear here:https://brainly.com/question/32551108
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