What did the early plants add to the atmosphere and why was that important? What else did they create?

Answers

Answer 1
Oxygen is the thing they added to the otmosphere
Answer 2

early plants added oxygen to the atmosphere. They did this by photosynthesis process by absorbing the carbon dioxide from the atmosphere and giving away oxygen in return.

This was important because life is not possible without oxygen present in the atmosphere.

They consumed the carbon dioxide from the atmosphere and reduced the temperature of the planet also.


Related Questions

Which of these statements would best explain the problem encountered with nuclear waste disposal?

Answers

A) The isotopes have a long half-life and only remain radioactive for a long time period. 

Answer: A

Explanation:

The potential energy due to the strong interaction, between two quarks or a quarkantiquark pair, goes something like v (r) = −α/r + βr, where α and β are positive constants. is there any point rv where the potential energy goes to zero? is there any point

Answers

Given that 
V= x/r + Br.
If V=0 Then -x/r + Br = 0
→ -x + br²/r = 0
→Br² - x = 0
r² = x/B
r² = +₋ √x/B
Force = dv/dr = d/dr [ -x/r +Br]
F = -[ -x/-r² + B]
= [B +x/r²]
a,B are positive.
r² is constant and it can never be negative.
∴ [ B + x/r²] is a positive value.
V = 0 at r = ⁺₋√x/B for the value of r.

When light propagates from a material with a given index of refraction into a material with a smaller index of refraction, the speed of the light vie?

Answers

When light moves from a material with a higher index of refraction to one with a lower value, the speed of light increases, potentially causing the light to refract. The index of refraction ratio determines the extent of this change in speed.

When light travels from a material with a higher index of refraction to one with a lower index of refraction, the speed of light in the material increases. The index of refraction, denoted as n, is defined by the ratio n = c/v, where c is the speed of light in a vacuum (approximately 3.0 * 10⁻⁸ m/s), and v is the observed speed of light in the material.

Since the index of refraction for a vacuum is exactly 1 (because the speed of light in a vacuum is c), and since n is always greater than or equal to 1, when light enters a material with a smaller n, it means that v must increase."

For example, when light moves from water (where it travels slower due to a higher n) into air (with a smaller n), the light speeds up. This change in speed can cause the light to bend or refract. The extent to which this bending occurs depends on the difference in the indices of refraction between the two materials.

A calorie is the measurement of ____ required to raise a 1 gram of water 1 degree celsius.

Answers

Calorie is a unit of energy, it is used above all in the area of health to measure the energy content of food.
 
Therefore the statement must be completed in the following way:


A calorie is the measure of heat required to raise 1 gram of water 1 centigrade.

Acceleration is best defined as the rate of change of ________ of an object.

Answers

Acceleration is best defined as the rate of change of ________ of an object.            ANSWER: velocity!

Answer:

Velocity

Explanation:

Remember that acceleration is given by the next formula:

Acceleration: Vf-Vo/Time

Where Vf final velocity and Vo is initial velocity, so acceleration of an object is best defined as the change in velocity the an object experiences in a certain period of time, it is often described in M/s^2 and those are the units in the international system.

The lengthening of a transmitted signal's wavelength and/or a decrease in its frequency, which indicates that the object is moving away from the observer, is called the

Answers

Both the effects (lengthening of the transmitted signal's wavelength and decrease in its frequency) indicates that the object is moving away from the observer, and this phenomenon is called Doppler effect.

In fact, when the object is moving away from the observer, the relative distance between two consecutive crests of the wave emitted by the object increases to the observer eyes, since he's moving away. This means that the wavelength appears larger, and since the frequency is inversely proportional to the wavelength, the frequency appears smaller.

The red shift... Hope it helps!

Which property of light remains unchanged when it enters a different medium?

Answers

The FREQUENCY of light remains unchanged once it leaves the source.

frequency  d is the anwsewr



Why are conductors and insulators both required to construct the electrical wiring in our home

Answers

Conductors are materials with many free electrons, so they allow electrical current to flow through them. Therefore, conductors are required in order to bring electricity to every room of the house.

Insulators, instead, are materials with few or no free electrons, so electrical currents do not flow through them. In the electrical wiring of the houses, they are used in order to isolate the conductive elements of the wire from other conductive materials (in fact, if the conductive elements touch other conductive elements of the house, part of the current would be dissipated)

Calculate the absolute pressure at the bottom of a freshwater lake at a point whose depth is 27.8 m. assume the density of the water is 1.00 103 kg/m3 and the air above is at a pressure of 101.3 kpa.

Answers

The relative pressure at the bottom of the lake is given by
[tex]p_r = \rho g h[/tex]
where
[tex]\rho[/tex] is the water density
g is the gravitational acceleration
h is the depth at which the pressure is measured

At the bottom of the lake, h=27.8 m, so the relative pressure is
[tex]p_r = (1\cdot 10^3 kg/m^3)(9.81 m/s^2)(27.8 m)=2.72 \cdot 10^5 Pa[/tex]

To find the absolute pressure, we must add the atmospheric pressure, [tex]p_a[/tex], to this value:
[tex]p=p_r + p_a =2.72 \cdot 10^5 Pa + 1.013 \cdot 10^5 Pa =3.74 \cdot 10^5 Pa[/tex]

Jupiter _____.

may have prevented asteroids from forming a planet
has a large gravitational field which can capture small comets
is responsible for creating most known meteors and meteoroids
releases radiation which warms comets and creates a comet tail

Answers

It's a because i chose this and got it right

Answer:

Jupiter may have prevented asteroids from forming a planet

Explanation:

How can medical assistant use the knowledge of the nervous systems to care for the patient with Parkinson’s and other neurological disorders

Answers

Having a wide knowledge of the nervous system and the of how the brain’s different parts collaborate to organize all our movements, senses thoughts, and emotions enable the medical assistants to handle the cognitive and behavioral complications in the patient. It helps them to deal with wounds and falls since the nervous disorder generally affects cognition and movement. Having a wide knowledge of how the nerve impulses are transmitted from the nervous system to the brain, when it is then converted into feelings such as pleasure, pain, cold or hot, the medical assistant will be able to take response immediately on the patient prior they start complaining of sensory indications, such as discomfort, irritating, and unresponsiveness.

If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific heat capacity of the metal?

Answers

The amount of heat needed to increase the temperature of a substance by [tex]\Delta T[/tex] is given by
[tex]Q= mC_s \Delta T[/tex]
where m is the mass of the substance, Cs is its specific heat capacity and [tex]\Delta T[/tex] is the increase of temperature.

If we re-arrange the formula, we get
[tex]C_s = \frac{Q}{m \Delta T} [/tex]
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
[tex]C_s = \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C [/tex]

sorry i don't know the answer i'm really sorry

a 10.0 kg ball falling at 10.0 m/s hits a mattress and comes to a complete stop in 1 s. what force does the mattress exert to stop the ball

Answers

Using Newton's second law;

F = ma, where m = mass, a = acceleration or deceleration

a = Δv/t = (v-u)/t, but v= 0, u = 10 m/s, t = 1.
Then,
a = (0-10)1 = -10 m/s^2

Substituting;
F = ma = 10*-10 = -100 N

The  mattress exerts 100 N to stop the ball.

The polar ice caps of mars is believed to consist mostly of

Answers

Solid Carbon Dioxide

A boat is moving at 3 m/s and increases its speed at 2 m/s2. How fast is it moving after it travels 10 m from the point it begins to speed up?

Answers

The boat is moving by uniformly accelerated motion, with initial speed 
[tex]v_i = 3 m/s[/tex]
constant acceleration of
[tex]a=2 m/s^2[/tex]
and it covers a distance of
[tex]S=10 m[/tex]

So we can use the following relationship to find the final speed, [tex]v_f[/tex]:
[tex]v_f^2 - v_i^2 = 2aS[/tex]
[tex]v_f = \sqrt{v_i^2 + 2aS}= \sqrt{(3 m/s)^2 +2(2 m/s^2)(10 m)} = 7m/s [/tex]

A relatively long lived excited state of an atom has a lifetime of 2.05 ms. what is the minimum uncertainty (in ev) in its energy?

Answers

We can solve the exercise by using Heisenberg's principle. In its energy-time version, Heisenberg principle states that the product between the uncertainty on the energy and on the time is larger than:
[tex]\Delta E \Delta t \ \textgreater \ \frac{h}{4 \pi} [/tex] (1)
where [tex]\Delta E, \Delta t[/tex] are the uncertainties on the energy and on the time, and h is the Planck constant.

The lifetime of the particle is 2.05 ms, so we can assume the maximum uncertainty on the time corresponds to the lifetime itself:
[tex]\Delta t = 2.05 ms = 2.05 \cdot 10^{-3} s[/tex]
And so the minimum uncertainty on the energy can be found by using (1):
[tex]\Delta E \ \textgreater \ \frac{h}{4 \pi \Delta t}= \frac{6.6 \cdot 10^{-34} Js}{4 \pi (2.05 \cdot 10^{-3} s)}= 2.56 \cdot 10^{-32} J[/tex]

Keeping in mind that [tex]1 eV = 1.6 \cdot 10^{-19}J[/tex], we can convert the energy uncertainty into electronvolts:
[tex]\Delta E = 2.56 \cdot 10^{-32} J : 1,6 \cdot 10^{-19} J/eV = 1,6 \cdot 10^{-13} eV[/tex]


What is the wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v? express your answer in terms of λ0, c, and v?

Answers

When an electromagnetic wave moves from a medium to another medium, its frequency remains constant. In this problem, we have light (which is an electromagnetic wave) moving from air to glass (or vice-versa), so we can write
[tex]f_0 = f[/tex] (1)
where [tex]f_0[/tex] is the frequency of the light in air, while f is the frequency in glass.

Using the relationship between frequency, wavelenght and speed of a wave, we have
[tex]f= \frac{v}{\lambda} [/tex]
where v is the speed of light in glass and [tex]\lambda[/tex] the wavelength in glass, and
[tex]f_0 = \frac{c}{\lambda_0} [/tex]
where c is the speed of light in air and [tex]\lambda_0[/tex] the wavelength in air. Using these two relationships, we can rewrite eq.(1) as
[tex] \frac{c}{\lambda_0}= \frac{v}{\lambda} [/tex]
and by re-arranging it, we find
[tex]\lambda= \frac{v}{c} \lambda_0 [/tex]

The wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v will be

[tex]\lambda=\dfrac{v}{c}\lambda_o[/tex]

What is wavelength?

The wavelength of any wave is defined as the distance between two max adjacent amplitudes, or the distance between two successive troughs or crest.

When an electromagnetic wave moves from a medium to another medium, its frequency remains constant. In this problem, we have light (which is an electromagnetic wave) moving from air to glass (or vice-versa), so we can write

[tex]f_o=f(1)[/tex] (1)

where  is the frequency of the light in air, while f is the frequency in glass.

Using the relationship between frequency, wavelenght and speed of a wave, we have

[tex]f=\dfrac{v}{\lambda}[/tex]

where v is the speed of light in glass and  the wavelength in glass, and

[tex]f_o=\dfrac{c}{\lambda_o}[/tex]

where c is the speed of light in air and  the wavelength in air. Using these two relationships, we can rewrite eq.(1) as

[tex]\dfrac{c}{\lambda_o}=\dfrac{v}{\lambda}[/tex]

and by re-arranging it, we find

[tex]\lambda=\dfrac{v}{c} \lambda_o[/tex]

Hence the wavelength λ of light in glass, if its wavelength in air is λ0, its speed in air is c, and its speed in the glass is v will be

[tex]\lambda=\dfrac{v}{c}\lambda_o[/tex]

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A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the lowest frequency associated with this portion of the spectrum? (c 3.00 108 m/s)

Answers

The lowest and highest wavelengths of this part of the electromagnetic spectrum are:
[tex]\lambda_1 = 200 nm=200 \cdot 10^{-9} m[/tex]
[tex]\lambda_2 = 400 nm = 400 \cdot 10^{-9} m[/tex]

We can calculate the corresponding frequencies by using:
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light. If we use this equation, we find:
[tex]f_1 = \frac{c}{\lambda_1}= \frac{3 \cdot 10^8 m/s}{200 \cdot 10^9 m} =1.5 \cdot 10^{15}Hz[/tex]
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{400 \cdot 10^9 m} =7.5 \cdot 10^{14}Hz[/tex]
Therefore, the lowest frequency associated with this portion of the spectrum is 
[tex]f_2 = 7.5 \cdot 10^{14} Hz[/tex]

A 5.3 kg cat and a 2.5 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. how far to the left of the pivot must a 3.7 kg cat stand to keep the seesaw balanced?

Answers

Moment about the pivot must be equal for the seesaw to balance. Initially, the first cat and the bowl are at 2 m from the pivot.

The moment due to cat = 5.3*2 = 10.6 kg.m
The moment due to bowl = 2.5*2 = 5 kg.m
The unbalanced moment = 10.6 - 5 = 5.6 kg.m

Therefore, the 3.7 kg cat should stand at a distance x from the pivot in left to balance the 5.6 kg.m.
That is,
3.7*x = 5.6 => x = 5.6/3.7 = 1.5134 m to the left (on the side of the bowl)
Final answer:

To keep the seesaw balanced, the 3.7 kg cat must stand 2.06 meters to the left of the pivot.

Explanation:

To keep the seesaw balanced, the torques (rotational forces) on both sides of the pivot must be equal. The torque is given by the product of the mass and the distance from the pivot. In this case, the 5.3 kg cat and the 2.5 kg bowl of tuna fish create a torque on one side, while the 3.7 kg cat creates a torque on the other side. Let's denote the distance from the pivot to the 5.3 kg cat as x:

Torque on one side = 5.3 kg * x

Torque on the other side = 2.5 kg * 1.5 m + 3.7 kg * (4 m - x)

Setting these two torques equal to each other and solving for x:

5.3 kg * x = 2.5 kg * 1.5 m + 3.7 kg * (4 m - x)

Simplifying the equation:

5.3x = 3.75 + 14.8 - 3.7x

9x = 18.55

x = 2.06 meters

Therefore, the 3.7 kg cat must stand 2.06 meters to the left of the pivot to keep the seesaw balanced.

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Allison wants to calculate the speed of a sound wave. Which formula should she use?
distance traveled / amplitude
number of wavelengths / amplitude
number of wavelengths / time
distance traveled / time

Answers

the true answer is distance traveled / time
because the speed of propagation of sound wave formula is the quotient of the distance traveled by a sound shaking by the time required on arrival. on edguinuity 

Answer:

Option 4th is correct

distance traveled / time

Explanation:

Allison wants to calculate the speed of a sound wave.

The speed of the sound wave is the distance traveled divided by the time.

[tex]v = \dfrac{d}{t}[/tex]

Where, v = speed of sound

d = distance

t= time

Therefore, The formula should she use is, distance traveled / time

A crate of mass 5 kg slides along a horizontal surface with coefficient of kinetic friction of 0.3. the force is pulled by a rope that makes an angle of 30o above the horizontal. the tension in the rope is 150 n. what is the power supplied by the rope to the crate at an instant where the box is moving at a speed of 3 m/s in the direction the rope is pulling it?

Answers

See attachment file below.
The power is 412W
(I'm not so sure of the answer. Can u please confirm it! Thank you.)


Hope it helped!

What waves shown on the electromagnetic spectrum disturb the medium it passes through at answer?

Answers

Electromagnetic waves do not require material medium for propagation. Radiowaves have the longest wavelength but the least frequency. 
Gamma ray has the shortest wavelength but the highest frequency. 

The gamma rays and x-rays due to their high frequency, they can disturb the medium they pass through. They have high energy that can cause damage to the matter the come across.  

What method of forecasting uses the effects of past weather conditions as part of its forecasting method

Answers

Analog method is the answer :)

the method is analog forecasting method

analog forecasting method uses the past weather data and compares it with the existing one to forecast. it is a complex method since it involves remembering previous data for whether that can be triggered by a specific event.

How many significant digits are in the measurement 50.003010 nm?

Answers

Answer:

Significant digits = 8

Explanation:

Significant digits in a number which is more than 1 and if the number if having decimal in it then as per the rule all the digits present in the number must be significant digit

for an example we will say

1.00 = 3 significant figures

so in this way for all such kind of numbers we have to count all digits in it

so here given number is more than 1 and it contains the decimal in it

so we will say

50.003010 nm = 8 significant figures

Answer:

There are 15 significant digits

Explanation:

50.00301 nm = 0.0000000500301

Counting the figures makes it 15

What is the wavelength of a photon whose energy is twice that of a photon with a 622 nm wavelength?

Answers

The frequency of the [tex]\lambda_2 = 622 nm = 622 \cdot 10^{-9} m[/tex] wavelength photon is given by
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{622 \cdot 10^{-9} m}=4.82 \cdot 10^{14} Hz [/tex]
where c is the speed of light.

The energy of this photon is
[tex]E_2=hf_2 = (6.6 \cdot 10^{-34}Js)(4.82 \cdot 10^{14}Hz)=3.18 \cdot 10^{-19} J[/tex]
where h is the Planck constant.

The energy of the first photon is twice that of the second photon, so
[tex]E_1 = 2 E_2 = 2 \cdot 3.18 \cdot 10^{-19}J =6.36 \cdot 10^{-19} J[/tex]

And so now by using again the relationship betwen energy and frequency, we can find the frequency of the first photon:
[tex]f_1 = \frac{E_1}{h}= \frac{6.36 \cdot 10^{-19} J}{6.6 \cdot 10^{-34}Js}=9.64 \cdot 10^{14}Hz [/tex]

and its wavelength is
[tex]\lambda_1 = \frac{c}{f_1}= \frac{3 \cdot 10^8 m/s}{9.64 \cdot 10^{14}Hz} =3.11 \cdot 10^{-7}m = 311 nm [/tex]
So, we see that the wavelength of the first photon is exactly half of the wavelength of the second photon (622 nm).

A magnetic field of 0.55 g is directed straight down, perpendicular to the plane of a circular coil of wire that is made up of 550 turns and has a radius of 20 cm. 1) if the coil is stretched, in a time of 35 ms, to a radius of 50 cm, calculate the emf induced in the coil during the process.

Answers

The emf induced in the coil is given by Faraday-Neumann-Lenz law:
[tex]\epsilon = - \frac{\Delta \Phi}{\Delta t} [/tex]
where 
[tex]\Delta \Phi[/tex] is the variation of magnetic flux through the coil
[tex]\Delta t[/tex] is the time interval

The magnetic field intensity is
[tex]B=0.55 G \cdot (1 \cdot 10^{-4} T/G) = 0.55 \cdot 10^{-4} T[/tex]

Since the magnetic field strength is constant, the variation of flux through the coil is given by
[tex]\Delta \Phi = N B \Delta A[/tex] (1)
where N=550 is the number of turns, while [tex]\Delta A[/tex] is the variation of area of the coil. We can re-write (1) as 
[tex]\Delta \Phi = NB (\pi r_1^2 - \pi r_2^2)=(550)(0.55 \cdot 10^{-4} T)(\pi (0.20m)^2-\pi (0.50m)^2) =[/tex]
[tex]=-0.020 Wb[/tex]

The time interval is [tex]\Delta t=35 ms=0.035 s[/tex], therefore the induced emf is
[tex]\epsilon = - \frac{\delta \Phi}{\Delta t}=- \frac{-0.020 Wb}{0.035 s}=0.57 V [/tex]

with a bar magnet where are the lines of force closest together

Answers

At the tip of either of the magnets poles

Answer: at the tips of the magnet

Explanation: charges are more at the tip of a substance so likewise for a magnet

Two astronauts are playing catch with a ball in space. The first astronaut throws the ball; and A) the ball moves, but the astronaut doesn’t. B) the ball moves, and so does the astronaut. C) the ball doesn’t move, but the astronaut does. D) the ball doesn’t move, and neither does the astronaut.

Answers

B) the ball moves, and so does the astronaut.

 Two astronauts are playing catch with a ball in space. The first astronaut throws the ball, and the ball moves, and so does the astronaut because of the action-reaction law. When the ball goes forward, the astronaut goes backward.

plz give me the brainliest

Two astronauts are playing catch with a ball in the space. One astronaut throws the ball, then the ball moves, and so does the astronaut. Hence, option B is correct.

What is Newton's third law?

Newton's third law states that if two bodies meet, they exert forces on each other that are comparable in size and directed in the opposite direction.

Action and reaction law is another name for the third law. This law is critical in understanding issues involving static equilibrium, in which all the forces are in balance, but it also holds true for entities moving uniformly or quickly.

A game of catch is being played in space by two astronauts. A ball is thrown by the first astronaut, and thanks to the action-reaction rule, both the ball and the astronaut move. The astronaut is forced to move backwards as the ball advances.

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I need help finding the answer:
When a guitar string plays the note "A", the string vibrates at 440 Hz. What is the period of the vibration?

Answers

The formula applicable:

Period, T = 1/f --- Where T = period (s), and f = frequency (Hz).

Substituting by use of the values of frequency given in the current scenario,

T = 1/440 = 2.27*10^-3 seconds
Final answer:

The period of the guitar string's vibration when it plays the note 'A' is approximately 0.00227 seconds.

Explanation:

In physics, the period of vibration refers to the time it takes for a single complete cycle of vibration to occur. It is usually represented by the symbol T and is measured in seconds. To find the period of the guitar string's vibration, you can use the formula T = 1/f, where f is the frequency of the vibration.

In this case, the frequency of the guitar string playing the note 'A' is given as 440 Hz. So, the period can be calculated as T = 1/440 = 0.00227 seconds.

Therefore, the period of the guitar string's vibration when it plays the note 'A' is approximately 0.00227 seconds.

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A parallel circuit has two 8.0-ohm resistors and a power source of 9.0 volts. If a 12.5-ohm resistor is added to the circuit in parallel, how will the current be affected and what value will it have?

Answers

The initial equivalent resistance of the circuit is
[tex] \frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}= \frac{1}{8 \Omega}+ \frac{1}{8 \Omega} = \frac{1}{4 \Omega} [/tex]
which means 
[tex]R_{eq}= 4 \Omega[/tex]
Therefore the initial current in the circuit is
[tex]I= \frac{V}{R}= \frac{9 V}{4 \Omega}=2.25 A [/tex]

When the new resistor of [tex]12.5 \Omega[/tex] is added to the circuit in parallel, the new equivalent resistance of the circuit is
[tex] \frac{1}{R_{eq}} = \frac{1}{8 \Omega} + \frac{1}{8 \Omega}+ \frac{1}{12.5 \Omega}= 0.33 \Omega^{-1}[/tex]
from which we find
[tex]R_{eq}=3 \Omega[/tex]
This means that the equivalent resistance of the circuit has decreased, and the new current is
[tex]I= \frac{V}{R_{eq}}= \frac{9 V}{3 \Omega}=3 A [/tex]
which means that the current in the circuit has increased.

Answer:

1/R1 + 1/R2 + ... = 1/Re

So...

1/17.2 + 1/22.4 = 1/Re

0.1021 = 1/Re

Re = 9.792 Ohms

Now use the Voltage equation V = IR

6 = I * 9.792

I = 6/9.792 = 0.613 Amps.Pato 0.61

Explanation:

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