What happens to the magnitude of the charge on each plate of a capacitor if the potential difference between the conductors is doubled?

Answer:

The sun

Explanation:

somewhere between 99.8 and 99.9 percent. The rest is split between the planets and their satellites, and the comets and asteroids and the dust and gas surrounding our star.

Answer:

Because of the strong interaction of photons with matter,neutrinos rarely interact with matter

Explanation:

In the core of the sun,nuclear fusion which is a nuclear reaction,produces the photons and neutrinos,for photons to emerge from the sun's core it passes through denser particles colliding and losing energy as it moves at such it can take it up to a million years to emerge from the sun core.Unlike the neutrinos that has more easier path,with little or no collission.

Photons take a long time to exit the sun due to repeated absorption and re-emission by atoms, resulting in a slow, zigzag path. On the other hand, neutrinos, which interact weakly with matter, can pass straight through the sun rapidly, taking just a bit over 2 seconds.

The reason why photons take much longer than neutrinos to emerge from the sun is due to their interactions with atoms inside the sun's dense core. When photons, which are energy particles produced by nuclear reactions, try to exit the sun, they end up getting absorbed or scattered by atoms, resulting in their paths being zigzag or random. This absorption and reemission process significantly slows down their journey, causing it to take between an estimated 100,000 to 1,000,000 years for them to reach the surface.

On the other hand, neutrinos, another type of particle produced by nuclear reactions, interact minimally with matter. This weak interaction enables them to pass straight through the sun's interior, reaching its surface in a little over 2 seconds. While photons eventually give up enough energy to become visible light that we see as sunlight, neutrinos escape the sun and radiate into space almost immediately after they're created.

https://brainly.com/question/33944307

#SPJ12

Answer:

He has 5,609,404 J of potential energy

Explanation:

P.E. = M*G*H

65 * 9.8^2 * 8800

The potential energy of the climber weighing 65 kg at a height of 8800 m is 5.6 × 10⁶ Joules.

Potential energy of a body is generated by virtue of its position. It is the form of energy stored in an object when it is stationary. When the body stopes its motion, its kinetic energy converts to potential energy.

The potential energy is related to the mass and height of the object from the ground and to the acceleration due to gravity g, by the expression,

PE = m g h.

Given that, mass of the climber = 65 Kg

Height of the mountain = 8800 m

g = 9.8 m/s²

Thus, PE = 65 kg × 8800 m × 9.8 m/s² = 5.6 × 10⁶ Joules.

Therefore, the potential energy of the climber will be 5.6 × 10⁶ Joules.

To find more on potential energy, refer here:

https://brainly.com/question/24284560

#SPJ3

Answer:

Te =  23.4 °C

Explanation:

Given:-

- The mass of iron horseshoe, m = 1.50 kg

- The initial temperature of horseshoe, Ti_h = 550°C

- The specific heat capacity of iron, ci = 448 J/kgC

- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

- The specific heat capacity of water, cw = 4186 J/kgC

Find:-

What is the final temperature of the water–horseshoe system?

Solution:-

- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

                             m*ci*( Ti_h - Te) = M*cw*( Te - Ti_w )

- Solve for (Te):

                             m*ci*( Ti_h ) + M*cw*( Ti_w ) = Te* (m*ci + M*cw )

                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

Answer:

Final temperature = 23.4 °C

Explanation:

The idea here is that the heat lost by the metal will be equal to the heat gained by the water.

In order to be able to calculate the final temperature of the iron + water system, we need to know the specific heats of water and iron which are;

C_water = 4.18 J/g°C

C_iron = 0.45 J/g°C

The formula to determine the determine the amount of heat lost or gained is given by;

q = m•c•ΔT

q = heat lost or gained

m = the mass of the sample

c = specific heat of the substance

ΔT = the change in temperature, defined as final temperature minus initial temperature

Now, -q_water = q_iron

The negative sign is used here because heat lost carries a negative sign. Let's say that the final temperature of the iron + water system will be T_f

Thus, we can say that the changes in temperature for the iron and for the water will be;

ΔT_iron = T_f − 550 °C

and ΔT_water = T_f − 20 °C

This means that we will now have;

−m_iron•c_iron•ΔT_iron = m_water•c_water•ΔT_water

This now gives us ;

−m_iron•c_iron•(T_f − 550°C) = m_water•c_water•(T_f − 20°C) - - - - (eq1)

Notice that the specific heats for these two substances is given per gram. This means that you will have to

Mass of iron = 1.5 kg = 1500g

Mass of water = 25 kg = 25000 g

Plugging the relevant values into eq(1),we have;

−(1500g)•(0.45 J/g°C)•(T_f − 550°C) = (25000 g)•(4.18 J/g°C)•(T_f − 20°C)

Multiplying out to get;

-675(T_f − 550) = 104,500(T_f − 20)

-675T_f + 371,250 = 104,500T_f - 2090000

371,250 + 2090000 = 104,500T_f + 675T_f

2461250 = 105175T_f

T_f = 2461250/105175 = 23.4 °C

Answer:

Explanation:

Given that,

Small piston Hydraulic piston has an area

A1 = 0.01m²

If the force applied is 250N is applied to the small piston at an area of 0.05 m²

Then,

F2 = 250 N and A2 = 0.05m²

Then, applying pascal principle,

Pressure at small area = pressure are bigger area

P1 = P2

F1 / A1 = F2 / A2

F1 / 0.01 = 250 / 0.05

F1 / 0.01 = 5000

Cross multiply

F1 = 5000 × 0.01

F1 = 50 N

Answer:

50N

Explanation:

Pressure = Force/Area

Where P1 = P2

F1/A1 = F2/A2

Given that F1 =? A1 = 0.01m^2

F2= 250N A2= 0.05m^2

F1/0.01m^2 = 250N/0.05m^2

F1 × 0.05= 0.01 × 250

F1 = 0.01×250/0.05

F1 = 2.5/0.05

F1 = 50N

1) 0.00257 A

2) [tex]1.6\cdot 10^{17}[/tex] electrons

3) 0.00512 A

Explanation:

1)

A current is defined as the flow of charge through a conductor.

The intensity of current is calculated as:

[tex]I=\frac{q}{t}[/tex] (1)

where

q is the amount of charge passing through a certain point in the conductor

t is the time interval during which this charge passes

In the wire in this problem we have:

[tex]q=9.0 mC=0.009 C[/tex] is the charge

[tex]t=3.5 s[/tex] is the time elapsed

Therefore, the current in the wire is:

[tex]I=\frac{0.009}{3.5}=0.00257 A[/tex]

2)

To find the total charge passing through a given point of the wire in a certain time, we re-arrange eq. (1):

[tex]q=It[/tex]

where

I is the current

t is the time interval we are considering

In this problem we have:

I = 0.00257 A is the current in the wire

t = 10.0 s is the time we are considering

Therefore, the charge is:

[tex]q=(0.00257)(10.0)=0.0257 C[/tex]

We know that this charge q consists of N electrons, so we can write

[tex]q=Ne[/tex]

where

[tex]e=1.6\cdot 10^{-19}C[/tex] is the charge of one electron

Solving for N, we find:

[tex]N=\frac{q}{e}=\frac{0.0257}{1.6\cdot 10^{-19}}=1.6\cdot 10^{17}[/tex]

3)

In this problem, we are told that the number of charges that pass through the cross-sectional area during the given time interval doubles, so we have:

[tex]N'=2N=2(1.6\cdot 10^{17})=3.2\cdot 10^{17}[/tex]

Therefore, the total charge through the point in the wire in a time of

t = 10.0 s

will be

[tex]q'=N'e=(3.2\cdot 10^{17})(1.6\cdot 10^{-19})=0.0512 C[/tex]

And so, the current in this case will be

[tex]I'=\frac{q'}{t}=\frac{0.0512}{10.0}=0.00512 A[/tex]

And we see that this current is twice the current we had in part 1), because the current is proportional to the number of charge carriers.

The charges are  [tex]0.00257\ A[/tex],  [tex]1.6 \times 10^{17}[/tex] electrons, and [tex]0.00512 \ A[/tex], and their further calculation can be defined as follows:

For part 1:

A movement of energy via a conductor is known as just a current.

This current's strength is computed as:

[tex]I=\frac{q}{t}.....(1)[/tex]

wherein q is the quantity of charge travelling through a specific location in the conductor, and t denotes a time interval during which this charge flows.

In the this problem, we have the following wire:

[tex]\to q=9.0 \ m C=0.009\ C[/tex] charges  

Time elapsed [tex]t=3.5 \ s[/tex]

current wire:

[tex]\to I=\frac{0.009}{3.5}= 0.00257 \ A[/tex]

For part 2:

You re-arrange eq. (1) to obtain that total charge passing through a particular location of the wire inside a given time.

[tex]\to q=It\\\\[/tex]

where

current =I

interval time =t

[tex]I = 0.00257\ A[/tex]  current in the wire

[tex]t = 10.0\ s[/tex]

Calculating the charge:

[tex]\to q=(0.00257) (10.0) =0.02575\ C[/tex]

We assume there are N electrons in this test charge, thus we can write

[tex]q=Ne\\\\[/tex]

where

Calculating the charge in one electron

[tex]e=1.6 \times 10^{-19}\ C[/tex]

Solving for N:

[tex]\to N=\frac{q}{e}=\frac{0.0257}{1.6\times 10^{-19}}=1.6 \times 10^{17}\\\\[/tex]

For point 3:

A number of charges which it pass through the cross-sectional area during the given time interval doubles in this issue, so we have:

[tex]\to N'=2N=2(1.6 \times 10^{17})=3.2\times 10^{17}\\\\[/tex]

As a result, the complete charge passed through the wire point in a period of

[tex]t = 10.0\ s\\\\[/tex]

[tex]\to q'=N'e=(3.2\times 10^{17})(1.6\times 10^{-19})=0.0512\ C\\\\[/tex]

So, in this scenario, the current will be

[tex]\to I'=\frac{q'}{t}=\frac{0.0512}{10.0}=0.00512\ A\\\\[/tex]

Because the current is proportional to the number of charge carriers, we can see that this current is twice as large as the current we had in part 1.

Find out more about the total charge here:

brainly.com/question/26142659

Answer:

In disagreement

Explanation:

Fluorescence can be defined as the phenomenon by which an object emits visible light when placed in front of ultraviolet light. In fluorescence, the absorbed light increases the energy band of the electrons, causing them to go into a more excited state. The electrons, before they release the absorbed energy in the form of light, lose a part of the energy due to the vibration of the molecules. When they return to their initial state, the electrons will emit light.

While microwaves are electromagnetic waves whose frequency is high, and are used for the transmission of high-speed telegraphic signals and for the communication of satellites and do not emit light.

Sample Response: I disagree with her because many substances show fluorescence under ultraviolet light, not microwaves.

edge

Answer:It is not possibly

Explanation:

Yes, it is possible to study single atoms using techniques like ultrafast laser spectroscopy and devices like the scanning tunneling electron microscope, which allow for detailed observations of individual atomic behavior and theoretical modeling.

It is indeed possible to study just one atom. Advanced experimental techniques, such as ultrafast laser spectroscopy and devices like the scanning tunneling electron microscope, have made observations of individual atoms feasible. These methods provide a profound understanding of atomic behavior and properties. Theoretical approaches, which include molecular dynamics calculations, offer insights by numerically solving Newton's equations of motion, thus allowing us to peek into the microscopic world.

This computational approach acts as a bridge toward grasping the complex interactions within systems containing a relatively large number of particles, approaching macroscopic behavior. Furthermore, the derivation of energy levels for electrons within atomic structures showcases the depth of study that individual atoms can be subjected to, advancing our comprehension of nuclear and electronic properties.

Answer:

Image is real and inverted

Explanation:

The ray diagram representing the situation is shown in attachment.

In this problem, we have a convex lens, which is curved outward at its centre; the rays of light reaching the lens parallel to the principal axis are refracted into the focal point of the lens.

Therefore, in order to build the ray diagram of this situation and draw the image, we proceed as follows:

1) First, we draw a ray of light parallel to the principal axis and going from the tip of the object towards the lens, then this ray is refracted towards the focal point on the other side

2) Then, we draw another ray of light going from the tip of the object towards the centre of the lens and continuing on the other side of the lens

The intersection point of rays 1) and 2) gives the position of the tip of the image.

Looking at the attached figure, we see that the image is:

- Real, because it is produced on the other side of the lens

- Inverted, as it is upside down

When the rays are drawn so here the Image should be considered as real and inverted.

Since it is the convex lens that curved outward at the center. Here the rays of light should be reached the lens that parallels to the principal axis also it should be refracted into the focal point of the lens.

Also, the first ray of light should be drawn, then the other ray of light should be gone from the tip of the object. It should be real since it is generated on the other side of the lens. And, it should be inverted since it is upside down.

Learn more about ray here; https://brainly.com/question/12449404?referrer=searchResults

Answer:

a) [tex]k = 200.016\,\frac{N}{m}[/tex], b) [tex]m = 1.389\,kg[/tex], c) [tex]f = 0.524\,hz[/tex]

Explanation:

a) The maximum speed of the oscillating block-spring system is:

[tex]v_{max} = \omega \cdot A[/tex]

The angular frequency is:

[tex]\omega = \frac{v_{max}}{A}[/tex]

[tex]\omega = \frac{1.2\,\frac{m}{s} }{0.1\,m}[/tex]

[tex]\omega = 12\,\frac{rad}{s}[/tex]

The mass of the system is:

[tex]E = \frac{1}{2}\cdot m\cdot v_{max}^{2}[/tex]

[tex]m = \frac{2\cdot E}{v_{max}^{2}}[/tex]

[tex]m = \frac{2\cdot (1\,J)}{(1.2\,\frac{m}{s} )^{2}}[/tex]

[tex]m = 1.389\,kg[/tex]

The spring constant is:

[tex]\omega = \sqrt{\frac{k}{m} }[/tex]

[tex]k = \omega^{2}\cdot m[/tex]

[tex]k = (12\,\frac{rad}{s} )^{2}\cdot (1.389\,kg)[/tex]

[tex]k = 200.016\,\frac{N}{m}[/tex]

b) The mass is:

[tex]m = 1.389\,kg[/tex]

c) The frequency of oscillation is:

[tex]\omega = 2\pi\cdot f[/tex]

[tex]f = \frac{2\pi}{\omega}[/tex]

[tex]f = \frac{2\pi}{12\,\frac{rad}{s} }[/tex]

[tex]f = 0.524\,hz[/tex]

Answer:

a) F = 20 N

b) m = 1.39 kg

c) f = 1.909 Hz

Explanation:

Given

E = 1 J

A = 0.1 m

vmax = 1.2 m/s

a) F = ?

b) m = ?

c) f = ?

Solution

a) We apply the equation

E = 0.5*k*A²

then

k = 2*E/A²

k = 2*1 J/(0.1 m)²

k = 200 N/m

then we use the equation

F = kA

F = (200 N/m)(0.1 m)

F = 20 N

b) We use the formula

E = K + U

if U = 0 J

then

E = K = 0.5*m*v²

⇒  m = 2*K/v²

m = 2*1 J/(1.2 m/s)²

m = 1.39 kg

c) we apply the equation

f = (1/2π)√(k/m)

then

f = (1/2π)√(200 N/m/1.39 kg)

f = 1.909 Hz

Answer:

Although the speed changes and wavelength changes, the frequency of the light will be constant. The frequency, wavelength, and speed are related by: The change in speed that occurs when light passes from one medium to another is responsible for the bending of light, or refraction, that takes place at an interface.

Explanation:

Answer:

[tex]\omega = 0.016\,\frac{rad}{s}[/tex]

Explanation:

The rotation rate of the man is:

[tex]\omega = \frac{v}{R}[/tex]

[tex]\omega = \frac{0.80\,\frac{m}{s} }{5\,m}[/tex]

[tex]\omega = 0.16\,\frac{rad}{s}[/tex]

The resultant rotation rate of the system is computed from the Principle of Angular Momentum Conservation:

[tex](90\,kg)\cdot (5\,m)^{2}\cdot (0.16\,\frac{rad}{s} ) = [(90\,kg)\cdot (5\,m)^{2}+20000\,kg\cdot m^{2}]\cdot \omega[/tex]

The final angular speed is:

[tex]\omega = 0.016\,\frac{rad}{s}[/tex]

Using the principle of conservation of angular momentum, the person's movement imparts an angular velocity of 0.018 rad/s to the disk.

To solve this problem, we'll need to use the principle of conservation of angular momentum, which states that the total angular momentum before an event must equal the total angular momentum after the event if no external torques act on the system.

Given Data:

First, calculate the person's moment of inertia relative to the center of the disk:

Initial angular momentum of the person (since they are initially stationary) is 0.

When the person starts moving, they contribute angular momentum relative to the axis:

Since the merry-go-round was initially stationary, its initial angular momentum L(disk-initial) is 0.

By conservation of angular momentum, the total angular momentum before must equal the total angular momentum after:

Solving for the angular velocity ω of the disk:

Hence, the disk will rotate with an angular velocity of 0.018 rad/s in the direction opposite to the person’s motion due to the conservation of angular momentum.

Answer:

ALMA is a trans-formative radio telescope that can study cosmic light that straddles the boundary between radio and infrared. Most objects in the Universe emit this kind of energy, so the ability to detect it has been a driver for astronomers for decades.

Explanation:

Answer:

the location of dust and gases in space

places where stars will be born

Explanation:

The voltage released because the charges in the current dropped electric potential energy; this energy loss occured due to the resistance of the metal strips.

Explanation:

Answer:

Both technicians A and B

Explanation:

Both trailer sway control, hill assist and hill descent controls are additional featires that enhance stability of electronics and their control systems. Majorly, these features track and reduce skidding in electronics, therfore, enhancing electronic system stability. During the process, these newly added features help to automatically apply brakes and direct the sytem where the controller wants to take it.

The type of movement used as an input includes gliding, angular, rotational, or special movement. These movements refer to instances like bone surfaces moving past each other, changes in the angle between joint bones, rotation of a bone around its own axis, and specific non-classifiable movements.

The type of movement used as an input varies depending on the situation and mechanism in question. In the broader sense, common types of movement used as inputs include: gliding, angular, rotational, or special movement.

Gliding movements occur as flat bone surfaces move past each other, such as the joints of the carpal and tarsal bones. Angular movements change the angle between bones of a joint, observed in actions like flexion and extension. Rotational movements result in the rotation of a bone around its own axis, while special movements that don't fit into the previous categories involve specific movements, like inversion, eversion, protraction, retraction, elevation, depression, dorsiflexion, plantar flexion, supination, pronation, or opposition.

https://brainly.com/question/30060370

#SPJ3

The solution with 10 grams of sugar per liter is hypertonic to the one with 5 grams of sugar per liter. Comparatively, the solution with 45 grams of sugar in 100 mL of water is much more hypertonic than both. The cup with more sugar has less water compared to the cup with less sugar due to the displacement of water by sugar.

When comparing two sugar solutions with different amounts of sugar but the same volume of water, the solution with more sugar is considered hypertonic, and the one with less sugar is hypotonic. In the given scenario, a student created two solutions by dissolving different amounts of sugar in equal volumes of water. The first solution with 5 grams of sugar is hypotonic compared to the second solution, which has 10 grams of sugar in the same volume of water (1 liter), making the second solution hypertonic to the first.

To further illustrate this with a different example, if you have 100 mL of water and add 45 grams of sugar, you will have a more concentrated (hypertonic) solution compared to a solution where you add a lesser amount of sugar to the same volume of water. This is because the hypertonic solution has a greater solute concentration. Comparatively, the solution with lesser sugar concentration, in this case, 5 grams per liter, would be hypotonic to the one with higher sugar concentration, which is 10 grams per liter or even more substantially to the one with 45 grams in 100 mL.

Therefore, when the volume is the same, the cup with the larger amount of sugar has less water due to the space taken by the sugar, and vice versa. This scenario is another way to understand the concept of hypertonic and hypotonic solutions based on solute concentration and the displacement of the solvent (water) by the solute (sugar).

Answer:

Red Dwarf

Explanation:

Answer:

Thermometer

Explanation:

Hence the name Thermo meaning heat.

Refrigerators and air conditioners use heat transfer, requiring a work input, to move thermal energy from cooler to warmer spaces. They absorb thermal energy from the cooler area, transfer it to a hotter reservoir while discharging heat back into the environment. These are essentially heat engines run backward, not in strict reverse.

Contrary to what may seem natural, appliances like refrigerators and air conditioners utilize a concept known as heat transfer to move thermal energy from a cooler space to a warmer one. This process requires a work input, typically provided by a motor or cooling substance.

The process occurs in stages. Firstly, the appliance absorbs thermal energy (denoted as Qc) from the cooler area. Secondly, this energy is transferred to a hotter reservoir, simultaneously discharging thermal energy (Qh) back into the warmer environment. The work input (W) is crucial here as it aids in moving the energy from the cool to the warm region, thereby keeping the cooler region at a lower temperature.

Finally, it's important to remember that these systems don't exactly run in reverse. Instead, they are essentially heat engines run backward, implying that while they perform opposite functions, they don't strictly follow a reversed process of a heat engine.

https://brainly.com/question/13433948

#SPJ3

Answer:

Distance traveled during this acceleration will be 6950 m

Explanation:

Wear have given maximum speed tat will be equal to final speed of the car        v = 278 m/sec

Constant acceleration [tex]a=5.56m/sec^2[/tex]

As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec

From third equation of motion [tex]v^2=u^2+2as[/tex]

Putting all values in equation

[tex]278^2=0^2+2\times 5.56\times s[/tex]

s = 6950 m

So distance traveled during this acceleration will be 6950 m

Answer:

Speed of the car around the circular path will be 12 m/sec

Explanation:

We have given mass of the car m = 1500 kg

Radius of the curve r = 45 m

Centripetal acceleration of the car [tex]a=3.2m/sec^2[/tex]

We have to find the speed of the car

We know that centripetal acceleration is given by [tex]a=\frac{v^2}{r}[/tex], here v is car speed along the circular path and r is radius of the curve

So [tex]3.2=\frac{v^2}{45}[/tex]

[tex]v^2=144[/tex]

v = 12 m/sec

So speed of the car around the circular path will be 12 m/sec

The car's speed as it travels around the curve is 12m/sec.

Given that,

Based on the above information, the calculation is as follows:

[tex]3.2 = v^2 \div 45\\\\v^2 = 144[/tex]

v = 12

Learn more: brainly.com/question/16911495

i need help toExplanation:

Answer:

B Is the Answer

Explanation: Trust me it is :P

In relation to the electromagnetic spectrum,wavelength is defined as a distance between peak of waves. It goes on decreasing from moving left to right in the electromagnetic spectrum as the energy increases.

The electromagnetic spectrum consists of  radiation  which consists of waves made up of the  electromagnetic field which are capable of propogating through space and carry the radiant electromagnetic energy.

The radiation are composed of electromagnetic waves which are synchronized oscillations of electric and magnetic fields . They are created due to change which is periodic in electric as well as magnetic fields.

In vacuum ,all the electromagnetic waves travel at the same speed that is with the speed of air.

Learn more about electromagnetic spectrum ,here:

https://brainly.com/question/15576247

#SPJ5

Answer:

Parked truck

Fast feather

fast baseball

slow car

fast car

Answer:

Net Force= -7.8N

Explanation:

fist start by solving the weight of the ball, this means the force pushing the ball down and the mass of the ball combined. we know that the force acting on the ball is gravity. the force of gravity is equivalent to 9.8m/s^2

weight formula w=mg. w= weight m= mass g= gravity

w=1kg(9.8m/^2)

w=9.8kg.m/s^2

w=9.8N

Simply add the two forces together to get the net force. The weight 9.8N is negative since it is directed downwards, while the air resistance 2N is positive since it is directed upwards.

Fnet= -9.8N+2N

Fnet= -7.8N

A 1-kg ball falling to the earth experiences a gravitational force of 9.8 N. With air resistance of 2 N, the net force acting on the body is 7.8 N.

The net force acting on a 1-kg ball falling due to gravity can be calculated by using Newton's second law. The gravitational force (weight) is equal to the mass times the gravity acceleration on Earth's surface. Thus, it is 1 kg times 9.8 m/s^2, which equals 9.8 N. However, the object encounters air resistance of 2 N, therefore, the net force on the object would be the gravitational force minus the air resistance: 9.8 N - 2 N = 7.8 N.

https://brainly.com/question/33730566

#SPJ11

Answer:

4.8 m

Explanation:

A mirror is a reflecting surface on which rays of light are reflected. Reflection occurs when a ray of light bounces off a surface, coming back into the original medium.

There exists two types of mirrors:

- Flat mirrors: they consist of a flat surface

- Curved mirrors: they consist of curved surfaces. They are further divided into convex mirrors and concave mirrors.

For a flat mirror, the image produced from the mirror is always:

- Virtual (on the other side of the mirror)

- Of the same size as the object

- Laterally inverted

- Upright (same orientation as the object)

Moreover, the image produced by a flat mirror is at the  same distance from the mirror as the object.

So in this case, since the person is 2.4 m from the mirror, then the image is produced 2.4 m from the mirror (but on the other side).

This means that the total distance between you and your image in the mirror is:

d = 2.4 + 2.4 = 4.8 m

Therefore, the focus of the camera must be adjusted to be at 4.8 m.

Answer:

Explanation:

GIVEN

Force (F) = 8 N

Distance (d) = 2.5 metres

Work done = ?

WE know we have the formula

work done = F * d

Work done = 8 * 2.5

                   = 20 Joule

Hope it helps :)

Work is measured in Joule.  The work done by the given chair is 20 J.

Work:

It is defined as the amount change in the energy. It is the product of force applied and displacement due to force.

Formula for work,

W = F x d

Where,

F - Force applied = 8 N  

d - Distance = 2.5 meters  

W - Work done = ?

Put the values in the formula,

[tex]\bold {W = 8\times 2.5 }\\\\\bold {W = 20\ J}[/tex]

Therefore, the work done by the given chair is 20 J.

To know more about work,

https://brainly.com/question/19604436